having trouble with this

The maximum possible area would have a length of 24 feet and width of 12 feet.

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.

Let x represent the length and y represent the width, hence:

Since beth has 48 ft fencing and cover 3 sides, hence:

x + 2y = 48  

x = 48 - 2y     (1)

Also:

Area (A) = xy

A = (48 - 2y)y

A = 48y - 2y²

The maximum area is at A' = 0, hence:

A' = 48 - 4y

48 - 4y = 0

y = 12 feet

x = 48 - 2(12) = 24

The maximum possible area would have a length of 24 feet and width of 12 feet.

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Answer:

T tof = 2 ( v 0 sin θ 0 ) g . T tof = 2 ( v 0 sin θ 0 ) g . This is the time of flight for a projectile both launched and impacting on a flat horizontal surface.

Answer:

Yup Yup

Step-by-step explanation:

yessah

Inequalities help us to compare two unequal expressions. The given inequality x<8 can be written in the interval notation as x=(-∞,8).

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

Continuous sets of real numbers can be represented using interval notation by the numbers that bound them. When written, intervals resemble ordered pairs in several ways. They do not, however, intend to indicate any particular location. Instead, they serve as a concise approach to expressing an inequality or a set of inequalities.

The given inequality x<8 can be written in the interval notation as,

x = (-∞,8)

Hence, The given inequality x<8 can be written in the interval notation as x=(-∞,8).

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Answer:

1/2

Step-by-step explanation:

Assume the coin is a fair coin.

Since we already know that the first 9 tosses were heads, the probability of 9 straight heads in the first 9 tosses is 1.

It all depends on the last toss. There is an equal probability of heads and tails in a single toss of a fair coin.

p(heads) = 1/2

p(10 heads) = 1/2

Ok so the answer is 1/2

a linear combination can be:

(a + b)*(4x + 15y) = a*12 + b*15

Here we have the system of equations:

(2/3)*x + (5/2)*y = 15

4x + 15y = 12

To solve the system of equations, we first need to isolate one of the variables in one of the equations, I will isolate x on the second equation.

4x = 12 - 15y

x = (12 - 15y)/4

Now we can replace that in the other equation:

(2/3)*x + (5/2)*y = 15

(2/3)* (12 - 15y)/4 + (5/2)*y = 15

Now we can solve that for y.

2 - (10/4)*y + (5/2)*y = 15

2 = 15

That is a false equation, then we conclude that the system of linear equations has no solutions.

This means that the two lines are parallel lines, then a linear combination can be:

(a + b)*(4x + 15y) = a*12 + b*15

Where a and b are two real numbers.

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Answer:Your answer is

There are no solutions.

Step-by-step explanation:Brainliest Please?

Concluding, the equations that do not accurately represent the data in the scatter plot are B, C, and D.

By looking at the scatter plot, we can see that as we read from left to right, the number of shoes sold (y variable) decreases.

Then the linear fit must have a negative slope, from that, we can discard options B and C.

Now, we also can see that the line starts almost at y = 70.

If you look at the option D, you can see that the constant term of that line is -70, so we can also discard that option.

Concluding, the equations that do not accurately represent the data in the scatter plot are B, C, and D.

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a. log₈8 = 1

b. log₇6/5

c. log₉3¹

1. log₈ 2 * 4 would produce an integer

= log₈8 = 1

The output is an integer

2. log₇6/5 would give us an irrational number

= log₇1.2

This would give us an irrational number

3. log₉3¹ would give us a rational number

= log₉9^[tex]^\frac{1}{2}[/tex] = 1/2 log⁹9

= 1/2

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Answer:

Step-by-step explanation:

X-INTERCEPT

Plug y=0 into the equation and solve the resulting equation −6x=−7 for x.

The x-intercept:

[tex]\left(\frac{7}{6},0\right)\approx \left(1.16666666666667,0\right)[/tex]

Y-INTERCEPT

Plug x=0 into the equation and solve the resulting equation 3y=−7 for y.

The y-intercept:

[tex]\left(0, - \frac{7}{3}\right)\approx \left(0,-2.33333333333333\right)[/tex]

Answer:

[tex]x[/tex]-intercept = ([tex]-\frac{7}{6}[/tex]  , 0)

[tex]y[/tex]-intercept = (0 , [tex]-\frac{7}{3}[/tex])

Step-by-step explanation:

[tex]6x + 3y = -7[/tex]

• The x-intercept is the point at which the line crosses the x-axis, that is, where y = 0.

∴ [tex]6x + 3(0) = -7[/tex]

⇒ [tex]6x = -7[/tex]

⇒ [tex]x = \bf -\frac{7}{6}[/tex]

∴ The x-intercept is at the point ([tex]-\frac{7}{6}[/tex] , 0).

• Similarly, the y-intercept is the point at which the line crosses the y-axis, that is, where x = 0.

∴ [tex]6(0) + 3y = -7[/tex]

⇒ [tex]3y = -7[/tex]

⇒ [tex]y = \bf - \frac{7}{3}[/tex]

∴ The y-intercept is at the point (0 , [tex]-\frac{7}{3}[/tex]).

The probability that a class of 50 has an average midterm mark that is less than 75 is value=0

Average is the mathematics mean, and is calculated by means of adding a group of numbers and then dividing with the aid of the count of these numbers. for instance, the average of 2, three, three, five, 7, and 10 is 30 divided with the aid of 6, that is five.

The common is described as the implied value that is identical to the ratio of the sum of the number of a given set of values to the whole wide variety of values gift within the set.

There are three primary sorts of common: imply, median, and mode. each of those techniques works slightly differently and frequency effects in barely specific regular values. The suggestion is the maximum normally used average. To get the suggested fee, you add up all of the values and divide this total by using the number of values.

The probability that a class of 50 has an average midterm mark that is less than 75

n = 50

P(<75)=P(Z<75)

P(Z<75−786√50)

P(Z<−3.5355)

We will look for the value in the StandardNormal able. We will get the value=0

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-5x - 5 = 3x + 19

---Move the x's to one side

-5x - 3x - 5 = 3x - 3x + 19

-8x - 5 = 19

---Isolate the -8x by removing the -5 from the left side

-8x - 5 + 5 = 19 + 5

-8x = 24

---Divide both sides by -8 to get x by itself

x = -3

Hope this helps!

-5x-5= 3x+19

= > -5x-3x= 19+5

= > -8x= 24

= >-x=24/8

= >x= -3

Answer:

(-6,4)

Step-by-step explanation:

You started at (-4,2)  The first number in the ordered pair moves the number left and right and the second number moved the point up and down.

We are first told to move the point 2 units to the left.  -4 is my left right number.  If I am at -4 and I go to unites to the left, I will be at -6.  My new point is now (-6,2).  Next we are told to go up 2.  The 2 number in my ordered pair tells me that I am 2 above the x axis.  Now I am going to go two more units up.  I am now at 4, so my new ordered pair after the translation is (-6,4)

coordinates of the point (−4, 2) after a translation 2 units left and 2 units up would be (-6, 4).

What is Translation ?

"Translation" moves points the same distance along lines that are parallel to each other.

Translation involves the initial object called the pre-image and the final object called the image. As you can see in the picture above, the rust-colored item represents the pre-image, and the blue item represents the image. Because of the arrow, we can tell the direction in which the image was moved. For other images, you may receive instructions on which image is the pre-image, or you may be asked to find the pre-image from the image.

Reflection, on the other hand, moves points along a specified line in such a way that the line bisects each line segment connecting corresponding pre-image points and image points

We are asked to find the coordinates of the points (-4,2) after a translation 2 units left and 2 units up.

We know that translating a point to the left by 'a' units means we need to subtract 'a' units from x-coordinate of the point.

Translation to 2 units left:

(-4,2) → (-4-2, 2)  → (-6, 2)

We know that translating a point to upwards by 'a' units means we need to add 'a' units to y-coordinate of the point.

Translation to 2 units up:

(-6, 2) → (-6, 2+2) → (-6, 4)

Therefore, coordinates of the point (−4, 2) after a translation 2 units left and 2 units up would be (-6, 4).

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The source of the force in the gas sample is; The force is composed of the sum of the collisions only between the gas molecules and the container

We are given that;

Pressure = Force /Area

Now, for any gas sample, force is defined as basically the force exerted by the gas molecules when they strike the surface and bounce back inside the container where they are located.

Now, from the definition above we can conclude that the source of the force in the gas sample will be The force is composed of the sum of the collisions only between the gas molecules and the container

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The equations exist [tex]$y =-(x+2)^2+1[/tex] and [tex]y =4x+9[/tex] then the value of

x = -6, x = -2 and y = -15, y = 1.

[tex]y =4x+9[/tex] ?

The given equations are [tex]$y =-(x+2)^2+1[/tex] and [tex]y =4x+9[/tex]

[tex]$-\left(x\:+\:2\right)^2\:+\:1\:=\:4x\:+\:9[/tex]

[tex]$-x^{2}-4 x-3=4 x+9[/tex]

Subtract 9 from both sides, we get

[tex]$-x^{2}-4 x-3-9=4 x+9-9[/tex]

Simplifying the equation, we get

[tex]$-x^{2}-4 x-12=4 x[/tex]

Subtract 4x from both sides

[tex]$-x^{2}-4 x-12-4 x=4 x-4 x[/tex]

[tex]$-x^{2}-8 x-12=0[/tex]

Solve with the quadratic formula

[tex]$x_{1,2}=\frac{-(-8) \pm \sqrt{(-8)^{2}-4(-1)(-12)}}{2(-1)}[/tex]

[tex]$\sqrt{(-8)^{2}-4(-1)(-12)}=4[/tex]

[tex]$x_{1,2}=\frac{-(-8) \pm 4}{2(-1)}[/tex]

Separate the solutions

[tex]$x_{1}=\frac{-(-8)+4}{2(-1)}, x_{2}=\frac{-(-8)-4}{2(-1)}[/tex]

[tex]$x=\frac{-(-8)+4}{2(-1)}=-6[/tex]

[tex]$x=\frac{-(-8)-4}{2(-1)}= \quad-2[/tex]

The solutions to the quadratic equation are x = -6, x = -2

From the above equation [tex]y =4x+9[/tex],

substitute the value of x, then we get

Put, x = -6 then y = 4(-6) + 9 = -15

Put, x = -2 then y = 4(-2) + 9 = 1

The system of equations exists (–2, 1) and (–6, –15).

Therefore, the correct answer is (–2, 1) and (–6, –15).

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Answer:

(–2, 1) and (–6, –15)

Step-by-step explanation:

flvs testing (i am not completely sure btw)

just substitute that into a last equations (seperatly if you understand=== -2 and 1 as x and y; -6 and -15 as x and y)

[tex]let \: the \: number \: be \: denoted \: by \: p \\ five \: times \: a \: number = 5p \\ square\: of \: a \: number = p {}^{2} [/tex]

[tex] \gamma - p {}^{2} = 5p - p {}^{2} [/tex]

39 number is the secret code as the unlock code for the safe.

According to the statement

we have given that  a some numbers as a code and we have to find the correct code after applying the given conditions.

So, For this purpose

The given number set is

5 17 29 22 11 26 27 35 39 41

So,

A. One condition : It is an odd number

so, the number set become

5 17 29 11 27 35 39 41

And

B. Second condition : It is greater than 20

so, the number set become

29 27 35 39 41

And

C. Third condition : It is smaller than 40

so, the number set become

29 27 35 39

And

D. Fourth condition : It is not a prime number

so, the number set become

27 35 39

And

E. Fifth condition : It has 13 as one of its factors

so, the number set become

39.

So, 39 number is the secret code as the unlock code for the safe.

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The perimeter of the triangle is 56.4 units.

The perimeter of the triangle can be found as follows:

The perimeter of a figure is the sum of the whole sides. Therefore, the perimeter of a triangle is the sum of the three sides.

perimeter of a triangle = x + y + z

where

Therefore,

perimeter of the triangle = 19.8 + (9.8 + 8.4) + (8.4 + (19.8 - 9.8))

perimeter of the triangle = 19.8 + 18.2 + 18.4

perimeter of the triangle = 56.4

perimeter of the triangle = 56.4 units

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Answer:

Angle symbol

Angle ACB

Angle ACE

Angle DCE

Answer:subtraction

Step-by-step explanation: to find out how many fewer tickets were sold on Sunday you would need to subtract 34012 by 29879. The solution would be how many fewer tickets were sold on Sunday compared to Saturday.

The algebraic solution to the situation is as follows:

x + y = 750

10x + 6y = 6860

The number of adult and student are 590 and 160 respectively.

One adult ticket for a school play costs 10 dollars and one student ticket costs 6 dollars.

One evening,750 people attended the play and the total receipts were 6860.

Therefore,

let

x = number of adult ticket

y = number of student tickets

Therefore,

x + y = 750

10x + 6y = 6860

10x + 10y = 7500

10x + 6y = 6860

4y = 640

y = 640 / 4

y = 160

Hence,

x  = 750 - y

x = 750 - 160

x = 590

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Based on the bearings of the direction and the distances given, the distance of point B from A is 1.62 km.  Point C's distance from A is 5.92 km east and 2.16 km south.

To find the distance from point B to point A, the Cos function should be used.

Point A's distance from B can be found as:

= Cos (143 - 90) x distance from point A

= Cos (53°) x 2.7

= 1.62 km

The distance of C from A eastward is:

= 1.62 + 4.3

= 5.92 km

As C is southward from point A, the function to be used is the Sin function.

The distance southward of c from A is:

= Sin(53°) x 2.7

= 2.16 km

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Answer:

Step-by-step explanation:

The matching of exponential functions to table values involves matching both initial values and rate of growth. The value of a geometric series can be calculated from its formula, or can be shown by a calculator or spreadsheet.

The starting values of the two sequences are different, as are all of the starting values of the answer choices. Matching starting values is sufficient to identify which sum goes with which player.

The series ...

  [tex]\displaystyle S=\sum_{k=1}^n{AB^{k-1}}[/tex]

gives the sum of a geometric sequence with first term A and common ratio B.

The first term of Erica's series is A=30. The ratio is B=42/30 = 1.4.

The first term of Marquis's series is 50. The ratio is B=75/50 = 1.5.

Using these values in the series formula, the total score after n rounds will be ...

  [tex]\displaystyle \text{Erica:}\quad \sum_{k=1}^n{30(1.4)^{k-1}}\qquad\text{matches Row 3}\\\\\text{Marquis:}\quad \sum_{k=1}^n{50(1.5)^{k-1}}\qquad\text{matches Row 2}[/tex]

The explicit expression for these sums is ...

  [tex]S=A\dfrac{B^n-1}{B-1}[/tex]

Then the total scores after 6 rounds are ...

  Erica: 30(1.4^6 -1)/0.4 = 489.7152

  Marquis: 50(1.5^6 -1)/0.5 = 1039.0625 . . . . . matches row 4

Then the required table gets filled in ...

__

Additional comment

The values in the attached table are total scores after each round. One must subtract the previous round's total to find the points scored in a given round.

The purpose of showing totals is to permit matching the value seen in Row 4 of the table.

Answer:

Step-by-step explanation:

Comment

The first thing you should notice once you have read it, is there is a plus sign required. That means you are likely to get a binomial (two different things that won't reduce or combined).

So what you get is

18*g + 5

Notice where the place sign is. It is between 18g and 5. The result cannot be simplified any further.

Answer

18g + 5

Answer:

g(1) = 1

Step-by-step explanation:

Since 1 ≠ -2  and  1 ≠ -1

Then we must use the expression:

g(x) = x³ - x² + 1  ,to calculate g(1).

Therefore

g(1) = (1)³ - (1)² + 1

     = 1 - 1 + 1

     = 0 + 1

     = 1

By applying inverse of a matrix, we find that the solution of the system of linear equations is (x, y) = (5/7, - 2/7).

In linear algebra, systems of linear equations with a unique solution can be represented by the following expression:

[tex]\vec A \cdot \vec x = \vec B[/tex]      (1)

Where:

The solution of such systems is defined by:

[tex]\vec x = \vec A^{-1}\cdot \vec B[/tex]

[tex]\vec x = \frac{1}{\det(\vec A)}\cdot adj\left(\vec A\right) \cdot \vec B[/tex], where [tex]\det \left(\vec A\right) \ne 0[/tex].

Where:

For the case of [tex]\vec A \in \mathbb{R}_{2\times 2}[/tex], the inverse of [tex]\vec A[/tex] is:

[tex]\vec A^{-1} = \frac{1}{\det \left(\vec A\right)} \cdot \left[\begin{array}{cc}a_{22}&-a_{12}\\-a_{21}&a_{11}\end{array}\right][/tex]     (2)

If we know that [tex]\vec A = \left[\begin{array}{cc}3&4\\5&2\end{array}\right][/tex] and [tex]\vec B = \left[\begin{array}{cc}1\\3\end{array}\right][/tex], then the solution of the system of linear equations is:

[tex]\vec A^{-1}= \frac{1}{(3)\cdot (2) - (5) \cdot (4)}\cdot \left[\begin{array}{cc}2&-4\\-5&3\end{array}\right][/tex]

[tex]\vec A^{-1} = -\frac{1}{14}\cdot \left[\begin{array}{cc}2&-4\\-5&3\end{array}\right][/tex]

[tex]\vec A^{-1} = \left[\begin{array}{cc}-\frac{1}{7} &\frac{2}{7} \\\frac{5}{14} &-\frac{3}{14} \end{array}\right][/tex]

[tex]\vec x = \left[\begin{array}{cc}-\frac{1}{7} &\frac{2}{7} \\\frac{5}{14} &-\frac{3}{14} \end{array}\right] \cdot \left[\begin{array}{cc}1\\3\end{array}\right][/tex]

[tex]\vec x = \left[\begin{array}{cc}\frac{5}{7} \\-\frac{2}{7} \end{array}\right][/tex]

By applying inverse of a matrix, we find that the solution of the system of linear equations is (x, y) = (5/7, - 2/7).

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The factored form of a - b is [tex]\left(5-3 p^{4}\right)\left(25+15 p^{4}+9 p^{8}\right)[/tex].

A monomial is an expression that is the product of constant and non-negative integer powers of x, like [tex]3x^{2}[/tex]..

A monomial is expressed as a product of two or more other monomials when it is factored.

Here,

a = 125

[tex]$b=27 p^{12}$[/tex]

To find: a - b

a - b = 125 - [tex]27 p^{12}$[/tex]

a - b =  [tex]5^{3}-\left(3 p^{4}\right)^{3}$[/tex]

We know that,

[tex]$x^{3}-y^{3}=(x-y)\left(x^{2}+x y+y^{2}\right)$[/tex]

Finding the factored form of a - b using this method:

[tex]$a - b=\left(5-3 p^{4}\right)\left(5^{2}+5\left(3 p^{4}\right)+\left(3 p^{4}\right)^{2}\right)$[/tex]

[tex]$a-b=\left(5-3 p^{4}\right)\left(25+15 p^{4}+9 p^{8}\right)$[/tex]

So, factored form of a - b is [tex]$\left(5-3 p^{4}\right)\left(25+15 p^{4}+9 p^{8}\right)$[/tex].

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Answer:

She used 9 tiles which are 3 cm long

Step-by-step explanation:

cuz 3x9=27 and yea

Answer:

b) It is false

Based on the amount of money that Jerl had and then the amount that she put away, the possible values of the number of dollars in the original pile of money was ( 200, 440).

The amount that was above $200 that she found can be x which means that the greater side of the inequality is:

= 200 + x

She then gave away $80:

= 120 + x

She gave away 1/3 of the money so the amount left is:

= 2/3 x (120 + x)

The lesser side of the inequality:

(x + 2) - 200 = x

So then:

((120 + x) x 2) / 3 > x

240 + 2x > 3x

240 > x

x < 240

The interval that shows the possible values of the original pile of money is therefore:

( 200, 440)

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8 Guidelines for Critically Evaluating a Statistical Study

1. Identify the Goal, Population, and Type of Study

2. Consider the Source

3. Examine the Sampling Method

4. Look for Problems in Defining or Measuring the Variables of

Interest

5. Watch Out for Confounding Variables

6. Consider the Setting and Wording of Any Survey

7. Check That Results Are Fairly Represented in Graphics or

Concluding Statements

8. Stand Back and Consider the Conclusions

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