The sky will appear in blue color at the sunset, if the sky of the planet scatters light of lower frequencies.
To find the answer, we have to know more about the scattering of light.
What is scattering of light?When light travels from one medium, like air or a glass of water, to another, scattering occurs. Part of the light is absorbed by the medium's particles, followed by subsequent radiation in a particular direction. The size of the scattered light's particles and its wavelength affect how intense it is.If the sky scatters a low frequency light, during sunset, this low frequency light will be totally absorbed by the atmospheric particles, and we can only be able to see the high frequency light.Thus, we can say that the sky will appear in blue color at the sunset, if the sky of the planet scatters light of lower frequencies.
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Why can rock avalanches move downslope at speeds exceeding 200 km/hr (125 mi/hr)?
Rock avalanches move downslope at speeds exceeding 200 km/hr (125 mi/hr) because when the soil expands and compresses, it lifts certain particles and drops them downslope a short distance.
Landslides are the common name for soil or rock avalanches. The most frequent type of avalanche, snowslides, can travel downhill more quickly than a skier. When an unstable snow mass detaches from a slope, a snow avalanche starts.
Rock avalanches are caused by the rapid breakup of initially intact, highly fast-moving rock masses during transportation. In mountainous areas, rock avalanches, which are unexpected rock slope failures marked by high velocities, lengthy runouts, and massive volumes, are among the most deadly and costly geological hazards.
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Use the same line to answer the questions
Q1. Use the number line above to calculate the distances and displacements for the paths listed. Don't forget to include the units.
Distance Displacement
From A to B to M to N
From C to A to G to D
From J to I to E to H
From F to B to K to F
Q2. For each of the paths from Q1, calculate the average speed and the average velocity if the path is traveled in 5.0 seconds. Don't forget to include the units. Use this Formula Reference Sheet (click this highlighted link for information) to remember the formulas you need.
Average velocity Average speed
From A to B to M to N
From C to A to G to D
From J to I to E to H
From F to B to K to F
(a) The distance From A to B to M to N is 22 m, the displacement is 22 m, the speed is 4.4 m/s and the average velocity is 4.4 m/s.
(b) The distance From C to A to G to D is 24 m, the displacement is 2 m, the speed is 4.8 m/s and the average velocity is 0.4 m/s.
(c) The distance From J to I to E to H is 16 m, the displacement is -2 m, the speed is 3.2 m/s and the average velocity is -0.4 m/s.
(d) The distance From F to B to K to F is 32 m, the displacement is 0 m, the speed is 6.4 m/s and the average velocity is 0 m/s.
Distance traveled by the objectThe distance traveled by the object is calculated as follows;
Distance From A to B to M to N
From A to B to M to N = 3 + 18 + 1 = 22
Distance From C to A to G to D
= 5 + 13 + 6
= 24
Distance From J to I to E to H
= 1 + 8 + 7
= 16
Distance from F to B to K to F
= 8 + 16 + 8
= 32
Displacement of the objectThe displacement of the object is calculated as follows;
displacement = final position - initial position
Displacement From A to B to M to N
= 11 - (-11)
= 22
Displacement from C to A to G to D
= D - C
= - 4 - (-6)
= 2
Displacement from J to I to E to H
= H - J
= 5 - 7
= - 2
Displacement From F to B to K to F
= F - F
= 0
Speed of the objectThe speed of the object is calculated as follows;
speed = total distance/total time
Speed of the object from A to B to M to N
= 22/5 = 4.4 m/s
Speed of the object from C to A to G to D
= 24/5
= 4.8 m/s
Speed of the object from J to I to E to H
= 16/5
= 3.2 m/s
Speed of the object from F to B to K to F
= 32/5
= 6.4 m/s
Average velocity of the objectThe average velocity of the object is calculated as follows;
Average velocity from A to B to M to N
= 22/5
= 4.4 m/s
Average velocity of the object from C to A to G to D
= 2/5
= 0.4 m/s
Average velocity of the object from J to I to E to H
= -2/5
= -0.4 m/s
Average velocity of the object from F to B to K to F
= 0
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Write an equation that expresses the first law of thermodynamics in terms of heat and work.
Answer:
Heat Input = Work Output (at 100% efficiency)
ΔQ = ΔW
(you cannot get something for nothing)
The law of conservation of momentum applies to a collision between two bodies since.
Answer:
The law of conservation of momentum applies to a collision between two bodies since Select one 0 a they exert forces on each other respectively inversely proportional to their masses 00 they exert forces on each other respectively proportional to their masses their accelerations are proportional to their masses they ...
Answer:
The law of conservation of momentum applies to a collision between two bodies since they exert equal and opposite forces on each other.
How is the law of conservation of momentum applied, in analyzing collisions?
Numerous final states are possible in collisions of elementary particles, but they are limited by the requirements of total energy and momentum conservation. It is necessary to utilize the relativistic formula for momentum and energy since high velocities are typically involved. These two laws provide two equations that may be used to determine which ultimate states are permitted by these two rules and which are not. For instance, it is conceivable to demonstrate that a photon cannot split into two gammas and that a second body, such as a nucleus, is required to satisfy both conservation principles. To forecast probabilities of various end stat configurations, a more thorough theoretical model of the collision is required.
Thank you,
Eddie
If a total force exerted by water in a container with a bottom area of 3 square meters is 900 newtons, what's the water pressure at the bottom of the container?
_______________
S=3 m²
F=900 N
_______________
p - ?
_______________
p=F/S=900 N / 3 m² = 300 Pa
Which method of measurement would be accurate but lack precision?
A. Measuring a volume of water by estimating the size of the
container
B. Measuring a volume of water using a graduated cylinder that can
be read to nearest mL
C. Measuring air temperature with a thermometer that has just been
taken out of hot water
D. Measuring air temperature with a thermometer that can be read to
the nearest degree and is calibrated to the correct temperature
Answer:
B
Explanation:
reading the volume of water in a graduated cylinder which can be read to the nearest mL is accurate, it lacks precision due to the bottom meniscus formed.
the bottom meniscus may cause a wrong reading due to refraction of light
If a particle with a charge of 2 coulombs moves through a potential difference of 12 volts, its change in kinetic energy will a have magnitude of__________.
The work done per unit charge is 24 joule
what is work done?
Measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
The potential difference across the two points is directly proportional to the work done per unit charge.
V=W/Q
where,
V=potential difference
W=work done
Q=charge
W=Q×V
given:
Q=2 coulomb
V=12 volt
W=2×12
W=24 joule
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A 26 kg bin is stationary on the driveway. The coefficient of static friction is 0.25. You pull on the bin with a force of 52 N [E] and your friend pulls with a force of 110 N [W]. Will the bin move? Explain your reasoning.
The bin will not move because the frictional force is greater than the net force acting on the bin.
What is the net force acting on the bin?The net force acting on the bin is obtained by subtracting the force acting on the Easterly direction from that acting in the Westerly direction.
Net force = 110 N - 52 N
Net force = 58 N
The frictional force acting on the bin is determined as well using the given formula:
Frictional force = coefficient of static friction * normal reaction
Norma reaction = 26 * 9.81
Normal reaction = 255.06 N
coefficient of static friction = 0.25
Frictional force = 0.25 * 255.06
Frictional force = 63.8 N
Since the frictional force is greater than the net force acting on the bin, the bin will not move.
In conclusion, the frictional force is the force that opposes relative between two objects at their surface of contact.
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If you apply 10.0 n of force to lift an object with a single, fixed pulley, then what is the resistive force?
Resistive force against 10.0 N of force to lift an object with a single, fixed pulley will be 10 N
Resistive force is a force, or the vector sum of numerous forces, whose direction is opposite to the motion of a body
A resistive force is one that inhibits or resists the motion of an object. It acts in a direction opposite to any motion or applied force that is trying to move the object. The most common resistive force is friction where an object is held back from sliding across a surface.
The force that the string (or similar) exerts on the object in these types of problems is called tension. Resistive Forces These include: Friction which is a force that prevents, or tries to prevent, the slipping or sliding of two surfaces in contact.
Hence , resistive force against 10.0 N of force to lift an object with a single, fixed pulley will be 10 N but in opposite direction to where pulley is been lifted .
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I NEED HELP ASAP
A green filter...
Select one:
a. transmits all other colors except green light.
b. reflects only green light.
c. absorbs only green light.
d. transmits only green light.
Answer:
ig d. transmits only green light.....
Select all the correct answers. which changes will increase the rate of reaction during combustion? decreasing the area of contact between the reactants adding more oxygen to the reaction removing heat from the reaction changing the reactants from solid form to powdered form lowering the exposure of the reactants to air
Adding more oxygen to the reaction and changing the reactants from solid form to powdered form will increase the rate of reaction during combustion.
What are factors on which rate of chemical reactions depend?The rate of a chemical reaction is affected by a number of factors, including temperature, the concentration of the reactants, the presence of a catalyst, and others.
The rate of a chemical reaction rises with temperature because more reactant and product particles will collide as a result of the higher temperature.By converting the reactants from a solid into a powder, more collisions between the reactant particles will occur, which will speed up the production of the products. Increasing the surface area of the reactants also increases the rate of reaction.The rate of reaction will grow when the concentration of the reactants, such as increasing the amount of oxygen in the reaction that is one of the reactants, increases.Learn more about rate of chemical reaction here:
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Consider the vector field. f(x, y, z) = xy2z2i x2yz2j x2y2zk (a) find the curl of the vector field?
Observe that the given vector field is a gradient field:
Let [tex]f(x,y,z)=\nabla g(x,y,z)[/tex], so that
[tex]\dfrac{\partial g}{\partial x} = x y^2 z^2[/tex]
[tex]\dfrac{\partial g}{\partial y} = x^2 y z^2[/tex]
[tex]\dfrac{\partial g}{\partial z} = x^2 y^2 z[/tex]
Integrating the first equation with respect to [tex]x[/tex], we get
[tex]g(x,y,z) = \dfrac12 x^2 y^2 z^2 + h(y,z)[/tex]
Differentiating this with respect to [tex]y[/tex] gives
[tex]\dfrac{\partial g}{\partial y} = x^2 y z^2 + \dfrac{\partial h}{\partial y} = x^2 y z^2 \\\\ \implies \dfrac{\partial h}{\partial y} = 0 \implies h(y,z) = i(z)[/tex]
Now differentiating [tex]g[/tex] with respect to [tex]z[/tex] gives
[tex]\dfrac{\partial g}{\partial z} = x^2 y^2 z + \dfrac{di}{dz} = x^2 y^2 z \\\\ \implies \dfrac{di}{dz} = 0 \implies i(z) = C[/tex]
Putting everything together, we find a scalar potential function whose gradient is [tex]f[/tex],
[tex]f(x,y,z) = \nabla \left(\dfrac12 x^2 y^2 z^2 + C\right)[/tex]
It follows that the curl of [tex]f[/tex] is 0 (i.e. the zero vector).
A grating has 470 lines/mm. how many orders of the visible wavelength 538 nm can it produce in addition to the m = 0 order?
Three complete orders on each side of the m=0 order can be produced in addition to the m=0 order.
The ruling separation is d=1/(470mm-1)
[tex] = 2.1 \times 10 {}^{ - 3}mm [/tex]
Diffraction lines occurs at an angle θ such that dsin=mλ,when λ is the wavelength and m is an integer.
Notice that for a given order,the line associated with a long wavelength is produced at a greater angle than the line associated with shorter wavelength.
we take λ to be the longest wavelength in the visible spectrum (538nm) and find the greatest integer value of m such that θ is less than 90°.
That is,find the greater integer value of m for which mλ<d.
since,d/λ
[tex] = 538 \times 10 {}^{ - 9} m/2.1 \times 10 {}^{ - 6} [/tex]
There are three complete orders on each side of the m=0 order.
The second and third orders overlap.
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A 0. 50 l sample of a gas has a mass of 11. 3 g at stp. what is the mass of 1. 00 mol of this gas? in other words, what is the molar mass (molecular weight)?
the molar mass of the given sample is 44.24kg.
To find the answer, we have to know about the concept of mole.
How to find the molar mass of the sample?Mole is the amount of substance that containing Avogadro number of particles.We can write the expression for mole as,[tex]mole,n=\frac{m}{M}[/tex]
where, m is the given mass and M is the molar mass.
Given that, the 0.5 mol of sample has a mass of 11.3g. Thus the molar mass will be,[tex]n=\frac{m}{M} \\M=\frac{n}{m}=\frac{0.5}{11.3*10^{-3}} =44.24kg[/tex]
The mass of 1 mole of given sample will be,[tex]m=n*M=1*44.24kg=44.24kg[/tex]
Thus, we can conclude that, the molar mass of the given sample is 44.24kg.
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Approximating the eye as a single thin lens 2. 70 cm from the retina, find the focal length of the eye when it is focused on an object at a distance of 265 cm?
The focal Length of the eye is 0.37cm.
The retina, which is always 2.70 cm away from the lens, serves as the image's primary imaging medium. Image distance is 2.70 cm as a result.
The object is located 265 cm away from the eye's lens.
Based on lens formula:
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{v}[/tex]
where the object distance is u, the image distance is v, and the focal length is f.
Consequently, u is 265.00 cm and v is 2.70 cm.
[tex]\frac{1}{f} = \frac{1}{265} + \frac{27}{10}[/tex]
[tex]\frac{1}{f} = \frac{7165}{2650}[/tex]
[tex]f = \frac{2650}{7165}[/tex]
f = 0.37
Thus, the focal length of the eye is 0.37cm.
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When adp and pi are added to the external medium and the vesicles are exposed to light, what will happen?
adp and pi are added to the external medium and the vesicles are exposed to light, The DNP will collapse the H+ gradient that ATP synthase uses to generate ATP.
ATP synthase is the enzyme that makes ATP molecules. It is a multi-part complex that straddles the inner membrane of mitochondria, the energy factories in cells. The enzyme complex interacts with fatty molecules in the mitochondrial inner membrane, creating a curvature that is required to produce ATP more efficiently.
ATP can be hydrolyzed to ADP and Pi by the addition of water, releasing energy. ADP can be "recharged" to form ATP by the addition of energy, combining with Pi in a process that releases a molecule of water.
The DNP will collapse the H+ gradient that ATP synthase uses to generate ATP. Each of the three respiratory enzyme complexes includes metal atoms that are tightly bound to the proteins.
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In hydraulic machine, how can you lift heavier load by using small magnitude of force?
Hello, yes it is possible to lift heavier load using small magnitude of force.
How? let's see.
Do you know on which principle does hydraulic machine work? Yes, it's Pascal's Principle. So in order to understand how hydraulic machine will lift heavier weight using small magnitude of force we will have to take a look at Pascal's law.
Pascal's law : It sates that in a closed container filled with fluid when pressure is applied to any point that intensity of pressure transfers in all direction equally.
Now look at diagram,
Consider the left piston as X and Right Piston as Y.
the area of piston X is small (A1) and applied force (F1) is also less and the resultant pressure is P.
[tex]P = \frac{F_1}{A_1}[/tex]
This same amount of pressure will be exerted at Piston Y having area (A2) and resultant output force (F2)
[tex]P = \frac{F_2}{A_2}[/tex]
So consider I have 5 N force and I have to lift a heavier rock weighing 50 N. take an example the area of Piston X is 1 m² & area of piston Y is 10 m²
So when I will apply 5 N force on piston X it will exert 50 N force on piston Y.
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differemces between liquid pressure and air pressure . give this answer is box
Answer:
The key difference between air pressure and liquid pressure is that air pressure allows the gaseous state of matter to be compressible, whereas liquid pressure makes a liquid incompressible.
Liquid pressure is the pressure that we can observe in a liquid. Air pressure is also known as atmospheric pressure, and it is the pressure as the force exerted by the collisions of particles in the air.
A 600-kg car makes a 90° turn. its speed before the turn is 21. 0 m/s and after the turn it is 24. 0 m/s. what is the magnitude of the change in the car's momentum during the turn?
The magnitude of the change in the car's momentum during the turn is
[tex] = 1.9 \times 10 {}^{3} kgm/s[/tex]
What is momentum?
Momentum can be defined as "mass in motion." All objects have mass,so if an object is moving, then it has momentum - it has its mass in motion.
Given:
V1=21m/s
V2=24m/s
m=600kg
To Find:
momentum
Now using Pythagoras theorem
[tex]f = ((600)(21)) {}^{2} + ((600)(24)) {}^{2} [/tex]
[tex]f = \sqrt{1.59 \times 10 {}^{8} + 2.07 \times 10 {}^{8} } [/tex]
[tex] = 1.9 \times 10 {}^{3} kgm/s[/tex]
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what is the value of boltzmann constant and where is it used?
Answer:
the value of the boltzman constant 8.61 73303 into 10 ratio by - 5 EV upon knev
A proton is placed in an electric field of intensity 800 n/c. what are the magnitude and direction of the acceleration of the proton due to this field? (e = 1. 60 × 10-19 c, mproton = 1. 67 × 10-27 kg)
The acceleration of the proton is 7.66*10^10m/s^2 in the direction of the electric field.
To find the answer, we have to know more about the electric field.
How to find the acceleration of the proton?We have the expression for electric field due to a accelerating particle as,[tex]E=\frac{F}{q}[/tex] , where q is the charge of the proton and F is the force.
We have the expression for force as,[tex]F=ma[/tex]
Combining both and rearranging, we get,[tex]ma=Eq\\\\a=\frac{Eq}{m} =\frac{800*1.60*10^{-19}}{1.67*10^{-27}} \\\\a=7.66*10^{10}m/s^2[/tex]
Thus, we can conclude that, the acceleration of the proton is 7.66*10^10m/s^2 in the direction of the electric field.
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While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at a constant speed of 2. 4 m/s relative to the surface of the walkway, you decide to try to determine the speed of the walkway itself. You watch the child run on the entire 18-m walkway in one direction, immediately turn around, and run back to his starting point. The entire trip takes a total elapsed time of 32 s. Given this information, what is the speed of the moving walkway relative to the airport terminal?.
Speed of walkway = 1.84 m/s
let x=speed of walkway
then (2.8+x)= speed of child moving in direction of walkway
then (2.8-x)= speed of child moving against direction of walkway
Travel time=distance/speed
travel time of child moving in direction of walkway=23/(2.8+x)
travel time of child moving in direction of walkway=23/(2.8-x)
total elapsed time given=29s
23/(2.8+x)+23/(2.8-x)=29
LCD=(2.8+x)(2.8-x)
23(2.8-x)+23(2.8+x)=29(2.8+x)(2.8-x)
23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)
23(2.8+2.8)/29=2.8^2-x^2
x^2=(2.8)^2-(23*5.6)/29)=3.4
x=sqrt(3.4)=1.84m/s
Speed of walkway = 1.84 m/s
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Fuel crises will occur in future because of a. over use of petroleum
b. use of solar energy
c. over use of bio-gas
d. use of hydro-energy
If you illuminate red paint with pure blue light, what color will that paint appear?
The red paint will appear no colour when it is illuminated with pure blue light.
Why does a red colour appear as red?When visible light of all wavelengths incident on a red coloured object, it absorbs all the wavelengths accept red colour.So it is reflected from its surface and makes the object red.What does happen when red coloured object is illuminated by pure blue light?As the pure blue light has no red coloured wavelength, so the object cannot reflect the red light wavelength. So we will get no reflection from the object.Thus, we can conclude that the red coloured object appears colourless as it is illustrated by pure blue light.
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When starting a foot race, a 89 kilogram sprinter exerts an average force of 518 newtons backward on the ground for 0.75 seconds. what is his final speed in meters/second at the end of this action?
The final speed of the sprinter is 4.8 m/s.
What is newtons second law of motion?According to the second law, the mass of the item or the net force acting on it both affect how quickly an object accelerates.
An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.
An object's acceleration increases as the amount of force exerted on it does.
A decreasing acceleration is caused by a rise in an object's mass.
Calculation of final velocity;
The sprinter exerts an average force of 518 newtons backward on the ground.
The taken by sprinter is 0.75 sec.
The wight of the sprinter is 89Kg.
According to Newton's second law
Force = mass×acceleration
F = m×a
a = F/m
a = 518/89
a = 6.4 m/sec²
Now, apply the equation of motion of straight line;
final velocity = initial velocity + acceleration×time
As, the sprinter starts from rest; initial velocity = 0.
Substitute all the values;
final velocity = 0 + 6.4×0.75
= 4.8 m/sec
Therefore, the final velocity of sprinter comes out to be 4.8 m/sec.
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When a solid is heated, it emits electromagnetic radiation known as ________________. an example of such radiation is the element of a stove top burning bright red.
Answer:
I think the answer is thermal radiation
Since nuclear fusion in the sun creates energy from matter, why doesn't it violate the law of conservation of energy?
Since nuclear fusion in the sun creates energy from matter, Einstein's formula E=mc² states that matter and energy are equal.
To find the answer, we have to know more about the nuclear fusion.
What is nuclear fusion?We are aware that the sun can achieve nuclear fusion by the fusion of hydrogen atoms. These atoms need to get closer to one another in order to fuse. Since both protons inside each nucleus are positively charged, they attempt to repel one another as they get closer to one another. If this issue cannot be solved, nuclear fusion in the sun cannot occur.Thus, we can conclude that, since nuclear fusion in the sun creates energy from matter, Einstein's formula E=mc² states that matter and energy are equal.
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What is the molar concentration of a 300.0 ml solution containing 5.00 g of nh3?
The molar concentration of a 300.0 ml solution containing 5.00 g of NH3 will be 0.98 mol/L
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
A mole is defined as the amount of a substance that contains exactly 6.02214076 X1023 elementary entities of the given substance. Thus, a mole of a substance is referred to as the mass of a substance containing the same number of fundamental units as atoms in exactly 12.000 g of 12C.
1 mol of NH3 has a mass of 17 g
Moles of NH3 = 5 g of NH3 * (1 mol of NH3 / 17 g of NH3)
= 0.294 mol of NH3
Litres of solution = 300 mL solution ×( 1 L solution/1000mL sol)
= 0.300 L of solution
Molarity = moles of solute / litres of solution
= 0.294 / 0.300 = 0.98 mol/L
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a man uses a 90 watt electric iron to press his clothes for an average of 4 hours a wpeek for five weeks if the cost of an electrical energy is acceptable per unit calculate the cost of energy for present
The cost of energy for pressing is 54 Kobo.
Units of electricity are measured in kilowatt-hours (kWh).
900-watt electric iron
Appliance usage = 4 hours a week for 5 weeks
The unit cost of electricity = 3 Kobo per kWh
Convert the wattage of the electric iron from watts to kilowatts.
1000 watts (W) = 1 kilowatt (kW)
⇒ 900 watts = 1 ÷ 1000 = 0.9 kilowatts
This means that the power consumption of the electric iron is 0.9 kW per hour of use.
Total hours spent pressing clothes:
= 4 hours per week for 5 weeks
= 4 × 5
= 20 hours
Total power consumption:
= number of kW × number of hours
= 0.9 × 20
= 18 kWh
To find the total cost, multiply the total kWh by the cost per kWh:
⇒ Cost = 18 × 3 = 54 Kobo
Therefore, the cost of energy is 54 Kobo
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The complete question is:
A man uses a 900-watt electric iron to press his clothes for an average of 4 hours a week for five weeks if the cost of electric energy is 3 Kobo per unit calculate the cost of electric energy for pressing.
. A rocket accelerates in a space at a rate of "1 g." The rocket exerts a force of 12,482 N. Later in flight the rocket exerts 46,458 N. What is the rockets new acceleration? What is the rocket's new acceleration in "g's?"
Explanation:
answer this question Do goods that have secondary packaging influence your purchasing decisions? Why/why not?
The new acceleration of the rocket is equal to 3.72 g.
What is acceleration?Acceleration can be demonstrated as the rate of change of velocity of a body with respect to time. The acceleration of a body can be defined as a vector quantity and can also be expressed as the second derivative of position w.r.t. time.
According to Newton's 2nd law of motion, the force acting on an object is equal to the multiplication of the mass of an object and acceleration.
F = ma
And, a = F/m
Therefore, the acceleration of a given body is inversely proportional to the body's mass.
Given, the new force exerted by the rocket, Fnew = 46,458 N
The old force exerted by the rocket, Fold = 12,482 N
The ratio of forces:
[tex]\displaystyle \frac{F_{new}}{F_{old}} =\frac{46458}{12482} = 3.72[/tex]
[tex]\displaystyle \frac{a_{new}}{a_{old}} = 3.72[/tex]
[tex]\displaystyle {a_{new}} = 3.72\times {a_{old}}[/tex]
[tex]\displaystyle {a_{new}} = 3.72\times g[/tex]
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