Answers
Answer:
[tex]\frac{x^2}{784}+\frac{y^2}{400}=1[/tex]
Step-by-step explanation:
Horizontal Major Axis:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}[/tex]
Vertical Major Axis:
[tex]\frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}+[/tex]
So these two expressions are essentially the same with the only difference being the location of "a" and "b". The length of the major axis will be "2a" and the length of the minor axis will be "2b". The way I remember this is because when you have the horizontal major axis the "a" value is in the denominator of the (x-h) and I think of "x" as a horizontal value, since it moves a point horizontally. When you have a vertical major axis the "a" value is in the denominator of (y-k) and I think of "x" as a vertical value, since it moves a point vertically.
So just by looking at the graph, you can easily determine that the eclipse has a horizontal major axis. This can be further proven, since the distance from the origin on the right side is 28, and the distance from the the top to the origin is only 20.
So you could set up an equation to solve for a, since 2a = length of major axis, but since we're given the two points, the "a" value is really just the length from the origin to the right/left side, and combining these together you get the value of 2a/major axis, but you don't have to do that. So by looking at the graph you'll see the distance from the origin to the right side is 28. This means "a=28"
You can do the same thing here for the "b" value, and since the top is 20 units away from the origin, "b = 20"
So now let's set up the equation:
[tex]\frac{x^2}{28^2} + \frac{y^2}{20^2}=1[/tex]
Square the values in the denominator
[tex]\frac{x^2}{784}+\frac{y^2}{400}=1[/tex]
Related Questions
Find the slope and reduce.
P=(2, 3) Q=(9, 7)
Slope =
Answers
Answer: 4/7
Step-by-step explanation:
Slope = Rise/Run = (7-3)/(9-2) = 4/7
Answer:
4/7
Step-by-step explanation:
The formula to find the slope is: (change in y)/(change in x)
Or also: Rise/Run
The change in y is: 3 --> 7 which is +4
The change in x is: 2 --> 9 which is +7
So the (change in y)/(change in x) will be 4/7.
Since 4/7 cannot be simplified further, that is our final answer.
Proofs 50 points for whole page ( serious answers only or report and 1 star )
Answers
1) Given - This is given in the question.
2) Reflexive Property of Equality - Anything is equal to itself
3) Substitution Property of Equality - Due to the given, substituting 118° for m∠1 and 62° for m∠2 will not change the equality of the equation
4) Simplify - No need to explain as they have already given this
5) Definition of Supplementary Angles - Two angles are supplementary only when the sum of their measures is 180°.
6) Converse of Same-side Interior Angles Theorem - If there is a transversal intersecting two lines and the same-side interior angles formed are supplementary, then the lines are parallel.
Question 2:1) Given - It is given in the question
2) Vertical Angles Theorem - Vertical angles have the same measure, making their angles congruent
3) Transitive Property of Congruence - Since it's given that [tex]\angle1\cong\angle3[/tex] and in step 2 we showed that [tex]\angle3\cong\angle4[/tex], we can say that [tex]\angle1\cong\angle4[/tex]
4) Transitive Property of Congruence - Since we proved that [tex]\angle1\cong\angle4[/tex] and it's given that [tex]\angle4\cong\angle5[/tex], we can say that [tex]\angle1\cong\angle5[/tex]
5) Converse of Alternate Interior Angles Theorem - If a transversal intersects two lines and the measures of alternate interior angles formed are equal, then the lines are parallel.
Sarah, Tony, and Megan are helping their parents plan the layout of the backyard. The patio is as wide as the fire pit, and 5 feet long. The pool is enlarged to yield the following layout:
Answers
If the patio is as wide as the fire pit, and 5 feet long then area of backyard can be expressed as [tex]2x^{2}+16x+30[/tex].
Given that the patio is as wide as the fire pit, and 5 feet long.
We are required to form an equation which can describe the area of the backyard.
Equation is relationship between two or more variables that are expressed in equal to form. Equations of two variables look like ax+by=c. It may be linear equation, quadratic equation, cubic equation or many more depending on the powers of the variable.
If we see the figure carefully then we can find that the length of the backyard is 2x+6 and the breadth of the backyard is 5+x and backyard is in shape of rectangle.
Area of rectangle =Length *breadth
=(2x+6)*(5+x)
=30+10x+6x+2[tex]x^{2}[/tex].
Hence if the patio is as wide as the fire pit, and 5 feet long then area of backyard can be expressed as [tex]2x^{2}+16x+30[/tex].
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In a sample of 198 observations, there were 80 positive outcomes. Find the margin of error for the 95% confidence interval used to estimate the population proportion.
Answers
Using the z-distribution, the margin of error for the 95% confidence interval used to estimate the population proportion is 0.0683 = 6.83%.
What is a confidence interval of proportions?
A confidence interval of proportions is given by:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
The margin of error is given by:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which:
[tex]\pi[/tex] is the sample proportion.z is the critical value.n is the sample size.In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.
For this problem, the parameters are given as follows:
[tex]n = 198, \pi = \frac{80}{198} = 0.404[/tex]
Hence the margin of error is:
[tex]M = 1.96\sqrt{\frac{0.404(0.596)}{198}} = 0.0683[/tex]
The margin of error for the 95% confidence interval used to estimate the population proportion is 0.0683 = 6.83%.
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What is the first term of the product of ( 4x 2 − x ) ( 6x 3 − x 4 + 3x ) when it is written in standard form?
Answers
Answer:x2−7x−8=0
Tap to view steps...
Step-by-step explanation:
. Last weekend, Michael
drove to his friend's house.
When he left, he noticed
that the fuel gauge in his
car indicated that his gas
tank was 4 full. When he
returned home, the fuel
gauge in his car indicated
that his gas tank was ½ full.
If the gas tank holds 24
gallons, how many gallons
did Michael use on his
drive?
Answers
It can be said that the total amount of fuel that was used by Michael when he was away to his friends was 12 gallons.
How to solve for the quantity.The question said that the tank was full before he left to his friends. This was after he checked the gauge of the gas tank.
The question says that the required quantity needed to fill up this tank is 24 gallon. Hence if it is full, then the total gallon it had before he made this trip was 24 gallon.
Then we are told that he went ahead to check the gauge when he finished and was at home. The quantity of fuel he had at this time was 1/2 of what was there.
This would be 1/2 * 24
12
Hence he made use of 12 gallons when he was away.
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What are the quartiles of the data
Answers
The quartiles of the data are: 60.5,64,66
Option(b) is correct.
The quartile divides the distribution into four groups and calculates the range of values above and below the mean.
A quartile separates the dataset into four categories by dividing the data into three points: the lowest, median, and upper quartiles.
Similar to how the median divides the data in half, with 50% of the measurements falling below it and 50% falling above it, the quartile divides the data into fourths, with 25% of the measurements falling below the lower quartile, 50% falling below the median, and 75% falling below the upper quartile.
The interquartile range, a measurement of variation around the median, is calculated using quartiles.
For the given data set: 58,60,60,61,62,64,64,64,66,70,72
Median = 64
Lower quartile = Median of the lower half = 60.5
Upper quartile = Median of the upper half = 66
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WILL GIVE BRAINLIEST
Given that two arcs of a circle are congruent, their measures are equal by the definition of congruence. Central angle
measures are equal to their intercepted arcs, so by the transitive property, the two central angle measures are equal. By
definition, the two angles are also congruent. Since all radii are congruent, the two triangles are congruent by SAS. Finally,
the intercepted chords are congruent by CPCTC.
Drag the statements to the positions that match the summary of Jeremy's proof.
Answers
m arc AC = m arc BD
mTriangle AOC =~ triangle BOD
(I apologize, my phone has no way to type the proper symbols, but I sincerely hope this helps)
Cual es el valor de x-7=13
Answers
Answer:
20
Step-by-step explanation:
u add 13+7 and that gives you 20, so if you subtract 20 and 7 that gives you 13
Please help, need for hw and cant find the fourth degreee
Answers
The quartic equation behind the graph is y = - 2 · x⁴ + 4 · x³ + 6 · x² - 8 · x - 8.
How to derive the expression for a quartic function
Quartic functions are fourth grade polynomials and according to the fundamental theorem of algebra, such kind of expressions have at least two real roots and at most four real roots. The graph of the picture shows a polynomial with two roots of multiplicity 2: x₁ = - 1, x₂ = 2.
y = a · (x + 1)² · (x - 2)² (1)
Where a is the leading coefficient.
If we know that (x, y) = (0, 4), then the leading coefficient of the polynomial is:
4 = a · (0 + 1) · (0 - 2)
4 = - 2 · a
a = - 2
Then, the quartic equation is equal to:
y = - 2 · (x + 1)² · (x - 2)²
y = - 2 · (x² + 2 · x + 1) · (x² - 4 · x + 4)
y = - 2 · [(x² + 2 · x + 1) · x² + (x² + 2 · x + 1) · (- 4 · x) + (x² + 2 · x + 1) · 4]
y = - 2 · (x⁴ + 2 · x³ + x² - 4 · x³ - 8 · x² - 4 · x + 4 · x² + 8 · x + 4)
y = - 2 · (x⁴ - 2 · x³ - 3 · x² + 4 · x + 4)
y = - 2 · x⁴ + 4 · x³ + 6 · x² - 8 · x - 8
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If Emery has $1,400 to invest at 5% per year compounded monthly, how long will it be before he has $2,400? If the compounding is
continuous, how long will it be? (Round your answers to three decimal places.)
Answers
Answer:
Step-by-step explanation:
(1400x14.5x5%) + 1400 =2415
Answer: 14.5 months
8. If one of the 1124 people is randomly selected, find the probability that the person is a man or heavy smoker. (a) 145 /281 (b) 617 /1124 (c) 1031 /1124 (d) 37 /1124
Answers
The probability that the person is a man or heavy smoker is 621 / 1124.
What is the probability?Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0. The more likely the event is to happen, the closer the probability value would be to 1. The less likely it is for the event not to happen, the closer the probability value would be to zero.
The probability that the respondent is a man or heavy smoker can be determined by adding the probability that the respondent is a man and the probability that the respondent is a heavy smoker together.
The probability that the person is a man or heavy smoker = (number of men / total number of respondents) + (number of heavy smokers / total number of respondents)
(531 / 1124) + (90 / 1124) = 621 / 1124
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The wall, shown above in Figure 105.1401, has an overall length that is 37’ and 8 1/4" . Three receptacle outlets are to be installed in this wall. L2 is twice as long as L1 . L1 should be _____' _____''.
Answers
Since L₂ is twice as long as L₁, the length of L₁ should be 12' and 6 3/4".
How to calculate the length (L₁)?First of all, we would convert the value of the overall length in feet to inches as follows:
1 feet = 12 inches
37 × 8 1/4 feet = X inches
Cross-multiplying, we have:
X = 1809/4 inches.
Since L₂ is twice as long as L₁, we have:
L₂ = 2L₁
Also, the overall length is given by:
T = 2L₁ + 2L₂
T = L₂ + 2L₂
T = 3L₂
1809/4 = 3L₂
L₂ = 1809/4 × 1/3
L₂ = 1809/12
L₂ = 150.75''
L₂ = 12' and 6 3/4".
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P: 2,012
1) El volumen de un cubo de arista 1 es Vc = 1³ y el
Volumen de una esfera de radior es
JE
V₁ = πr ²³ Entonces si en un cubo de arista 4cm
3
y se introduce una pelota de diametro 4 cm, al Calcular
aproximación con cuatro cifras decimales, por exceso.
Calcular el volumen que queda entre la esfera y el cubo.
(toma π =
3,141592654)
Answers
El volumen que queda entre la esfera y el cubo es: 30.49cm^3
¿Como calcular el volume sobrante?
El volumen sobrante será simplemente la diferencia entre el volumen del cubo y el volumen de la esfera.
Para el cubo que tiene una arista de 4cm, el volumen es:
V = (4cm)^3 = 64 cm^3
Para la esfera con un diametro de 4cm, el radio es:
R = 4cm/2 = 2cm
Y el volumen será:
V' = (4/3)*3.141592654*(2cm)^3 = 33.51 cm^3
El volumen que queda entre la esfera y el cubo es:
V - V' = 64 cm^3 - 33.51 cm^3 = 30.49cm^3
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I have to be at work at 4 am it takes 34 mins to walk to work from my house what time would i have to leave my house to be at work on time at 4 am
Answers
Answer:
3:26 to be on time!
Step-by-step explanation:
If you leave your house at 3:26 am and then walk 34 minutes it will be 4 am
once you get to work.
Mr. Wilson invested money in two accounts. His total investment was $20,000. If one account pays 5% in interest and the other pays 2% in interest, how much does he have in each account if he earned a total of $550 in interest in 1 year?
Answers
a = amount invested at 5%
b = amount invested at 2%
now, we know the total invested by Mr Wilson was 20000, so whatever "a" and "b" might be, we know that a + b = 20000.
[tex]a + b = 20000\implies b = 20000-a \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{5\% of a}}{\left( \cfrac{5}{100} \right)a}\implies 0.05a~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)a}\implies \begin{array}{llll} 0.02b\\\\ \stackrel{substituting}{0.02(20000-a)} \end{array}[/tex]
now, we know the total of earned interest is 550 bucks, so then
[tex]0.05a~~ + ~~0.02(20000-a)~~ = ~~550\implies 0.05a+400-0.02a=550 \\\\\\ 0.03a+400=550\implies 0.03a=150\implies a=\cfrac{150}{0.03}\implies a=5000 \\\\\\ ~\hspace{24em}\stackrel{20000~~ - ~~5000}{b=15000}[/tex]
Show all work to write the expression in simplified rational exponent form:
[tex]\sqrt[4]{17x^{2}}[/tex]
(Fourth root of 17 x squared)
Answers
Answer:
[tex](17x)^{\frac{2}{4}}[/tex]
Step-by-step explanation:
There's not much work to show for this problem, but I'll explain it for you
Use the exponent rule for roots to combine the 4 and the 2 like a fraction
2 on the top and 4 on the bottom
[tex](17x)^{\frac{2}{4} }[/tex]
That's it! Pretty easy
Good Luck!
pls mark brainliest
Divide. Write your answer in simplest form.
3/14 divided by 7/10???
Answers
Answer:
[tex]\frac{15}{49}[/tex]
Step-by-step explanation:
[tex]\frac{3}{14} /\frac{7}{10} =\frac{3}{14} *\frac{10}{7} = \frac{3}{7} *\frac{5}{7} =\frac{15}{49}[/tex]
Use the midpoint rule with the given value of n to approximate the integral. (Round your answer to four decimal places.)
16
0
sin
x
dx, n = 4
Answers
Split up [0, 16] into 4 equally-spaced subintervals of length [tex]\frac{16-0}4=4[/tex],
[0, 16] = [0, 4] U [4, 8] U [8, 12] U [12, 16]
with midpoints 2, 6, 10, and 14, respectively.
Then with the midpoint rule, we approximate the integral to be about
[tex]\displaystyle \int_0^{16} \sin(\sqrt x) \, dx \approx 4 \left(\sin(\sqrt2) + \sin(\sqrt6) + \sin(\sqrt{10}) + \sin(\sqrt{14})\right) \approx \boxed{4.1622}[/tex]
For the equation:
y=−x^2+10x−24, the x-intercepts are already given on the graph. Now, using the parabola tool, graph rest of the equation.
Answers
The graph of the parabola can be seen in the image below.
How to graph the parabola?
We need to find some points on the parabola, and then draw a curve that connects them.
On the graph you already have the x-intercepts, so you already have two points.
Now let's get another point which is the vertex.
For our parabola:
[tex]y = -x^2 + 10x - 24[/tex]
The vertex is at:
[tex]x = -10/(2*-1) = 5[/tex]
Evaluating in x = 5 we get:
[tex]y = -5^2 + 10*5 - 24 = 1[/tex]
So we also have the point (5, 1), now we can just connect the points and get the parabola:
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Help!
which of the following functions are graphed below
Answers
The first function is a quadratic or curve meaning x has an exponent. Since it’s to the left of an open circle, we use <
The second function is linear equation so x has no exponent. Since it’s to the right of a closed circle, we use greater than or equal to >/=
if tan theta = 1/√5 then verify the identity sin²theta + cos²theta = 1
Answers
The identity of sin²Ф + cos²Ф = 1 is verified below
How to evaluate Trigonometry Ratio ?Trigonometry ratio can be evaluated by following the laid down rules with the the use of table and calculator
Given that tan Ф = 1/√5
Where Tan Ф = Opposite / adjacent
We can calculate the hypotenuse by using Pythagoras theorem
Hyp² = 1² + (√5)²
Hyp² = 1 + 5
Hyp = √6
sin Ф = opp / hyp
sin Ф = 1/√6
sin²Ф = 1/6
cos Ф = adj / hyp
cosФ = √5 / √6
cos²Ф = 5/6
sin²Ф + cos²Ф = 1/6 + 5/6
sin²Ф + cos²Ф = 6/6
sin²Ф + cos²Ф = 1
Therefore, the identity of sin²Ф + cos²Ф = 1 is verified.
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Can I just get the answer for this I feel like it’s wrong.
Answers
The initial membership fee for Club A is; $2.5.
The initial membership fee for Club B is; $3.
Hence, Club A has a lower initial membership fee.
What is the initial membership fee for each Club?It follows from the concepts of linear graphs that the interpretation of the initial membership fee is the y-intercept of the graphs given.
This is so because, it corresponds to the total cost at a point when the number of movies watched is; 0. That is, before any movie is watched.
Consequently, the graph calibrations (including the missing Club A graph) allow the determination of the initial membership fee (y-intercept) as declared above.
Ultimately, Club A has a lower initial membership fee.
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last week you worked the following hours monday 5 1/2 wednesday 6 3/4 friday 4 1/2 how many hour did you work in all week
Answers
First, add 5 1/2 to 4 1/2. You get 9 2/2 which simplifies to 10. Next, add the 6 3/4 to 10. This gets you 16 3/4, your total for the week.
5 1/2 + 4 1/2 = 10
10 + 6 3/4 = 16 3/4
Answer:
Step-by-step explanation:
You worked 16 hours and 45 minutes
5 1/2 = 5 hours and 30 minutes
6 3/4 = 6 hours and 45 minutes
4 1/2 = 4 hours and 30 minutes
Add the hour and minutes.
5 hours 30 min + 4 hours 30 min = 10 hours
10 hours + 6 hours 45 min = 16 hours and 45 minutes
We will start with a string which is pulled tight enough to vibrate at 288 Hertz when
plucked. Let the length of the string be 1 unit. We can find additional nice sounding
notes by using a string of a smaller length with the same amount of tension. To find
the string lengths, we need to use fractions whose numerators are powers of 2 and
whose denominators are powers of 3 (which are larger than ½, but smaller than 1).
The first few fractions are given below. Determine the remaining fractions:
Answers
The series of fractions is 1, 2/3, 8/9, 16/27, 64/81, 128/243, 512/729, 2048/2187, 4096/6516, 16384/19683, 32768/59049, 131072/177147.
The string lengths are fractions whose numerators are powers of 2 and denominators are powers of 3, and the fractions are larger than 1/2 but smaller than 1.
Some powers of 2 are:
2⁰ = 1, 2¹ = 2, 2² = 4, 2³ = 8, 2⁴ = 16, 2⁵ = 32, 2⁶ = 64, 2⁷ = 128, 2⁸ = 256, 2⁹ = 512, 2¹⁰ = 1024, 2¹¹ = 2048, 2¹² = 4096, 2¹³ = 8192, 2¹⁴ = 16384, 2¹⁵ = 32768, 2¹⁶ = 65536, and 2¹⁷ = 131072.
Some powers of 3 are:
3⁰ = 1, 3¹ = 3, 3² = 9, 3³ = 27, 3⁴ = 81, 3⁵ = 243, 3⁶ = 729, 3⁷ = 2187, 2⁸ = 6561, 3⁹ = 19683, 3¹⁰ = 59049, and 3¹¹ = 177147.
The fractions, for which the numerator is a power of 2, the denominator is a power of 3, and the value is between 1/2 and 1 are:
2/3, 8/9, 16/27, 64/81, 128/243, 512/729, 2048/2187, 4096/6516, 16384/19683, 32768/59049, 131072/177147.
Thus, the series of fractions is 1, 2/3, 8/9, 16/27, 64/81, 128/243, 512/729, 2048/2187, 4096/6516, 16384/19683, 32768/59049, 131072/177147.
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Calculus HW , will someone please teach me how to do this problem. I'm struggling, thanks! 10 Points
Answers
Compute the first two derivative.
[tex]f(x) = x \sqrt{16 - x^2} = x (16 - x^2)^{1/2}[/tex]
[tex]f'(x) = x \dfrac{d}{dx} (16 - x^2)^{1/2} + (16 - x^2)^{1/2} \dfrac{d}{dx} x \\\\ ~~~~ = \dfrac x2 (16 - x^2)^{-1/2} \dfrac{d}{dx} (16-x^2) + (16 - x^2)^{1/2} \\\\ ~~~~ = \dfrac x2 (16 - x^2)^{-1/2} (-2x) + (16 - x^2)^{1/2} \\\\ ~~~~ = (16-x^2)^{-1/2} \left(-x^2 + (16 - x^2)\right) \\\\ ~~~~ = \dfrac{16 - 2x^2}{(16 - x^2)^{1/2}}[/tex]
[tex]f''(x) = \dfrac{(16-x^2)^{1/2} \frac d{dx} (16-2x^2) - (16-2x^2) \frac{d}{dx} (16-x^2)^{1/2}}{\left((16-x^2)^{1/2}\right)^2} \\\\ ~~~~ = \dfrac{(16-x^2)^{1/2} (-4x) - (8-x^2) (16 - x^2)^{-1/2} \frac{d}{dx} (16-x^2)}{16 - x^2} \\\\ ~~~~ = \dfrac{-4x (16-x^2) - (8-x^2) (-2x)}{(16 - x^2)^{3/2}} \\\\ ~~~~ = \dfrac{2x^3-48x}{(16 - x^2)^{3/2}}[/tex]
Take note of the domain of [tex]f(x)[/tex]. We must have [tex]16-x^2\ge0[/tex] for the square root to be defined, so
[tex]16 - x^2 \ge 0 \implies x^2 \le 16 \implies |x| \le 4[/tex]
and [tex]f(x)[/tex] exists only for [tex]-4 \le x \le 4[/tex].
Intercepts
Set [tex]x=0[/tex] to find the [tex]y[/tex]-intercepts. The only one is (0, 0), since
[tex]f(0) = 0 \sqrt{16-0^2} = 0[/tex]
The first intercept you listed is not a valid intercept. One or both coordinates must be 0.
Set [tex]f(x)=0[/tex] and solve for [tex]x[/tex] to find [tex]x[/tex]-intercepts. We already found (0, 0); there are two others at (-4, 0) and (4, 0).
[tex]f(x) = x \sqrt{16 - x^2} = 0 \\\\ x = 0 \text{ or } \sqrt{16 - x^2} = 0 \\\\ x = 0 \text{ or } 16 - x^2 = 0 \\\\ x = 0 \text{ or } x^2 = 16 \\\\ x = 0 \text{ or } x = \pm4[/tex]
The instructions say to list these in order from smallest to largest by [tex]x[/tex]-coordinate first, then by [tex]y[/tex]-coordinate. So the proper order of the intercepts would be (-4, 0), (0, 0), and (4, 0).
Relative minima/maxima
Find the critical points. We have [tex]f'(x) = 0[/tex] when
[tex]f'(x) = \dfrac{16 - 2x^2}{(16 - x^2)^{1/2}} = 0 \\\\ 16 - 2x^2 = 0 \\\\ x^2 = 8 \\\\ x = \pm2\sqrt2 \approx \pm 2.83[/tex]
and [tex]f'(x)[/tex] is undefined when
[tex](16 - x^2)^{1/2} = 0 \\\\ 16 - x^2 = 0 \\\\ x^2 = 16 \\\\ x = \pm4[/tex]
Check the sign of the second derivative at the first two critical points.
[tex]f''(-2\sqrt2) = 4 > 0 \implies \text{rel. min. at } f(-2\sqrt2) = -8[/tex]
[tex]f''(2\sqrt2) = -4 < 0 \implies \text{rel. max. at } f(2\sqrt2) = 8[/tex]
For posterity, we should also check the value of [tex]f(x)[/tex] at the endpoints of the domain.
[tex]f(-4) = f(4) = 0[/tex]
So [tex]f(x)[/tex] has a relative minimum at (-2.83, -8) and a relative maximum at (2.83, 8).
Inflection points
We have [tex]f''(x) = 0[/tex] for
[tex]f''(x) = \dfrac{2x^3-48x}{(16 - x^2)^{3/2}} = 0 \\\\ 2x^3 - 48x = 0 \\\\ 2x (x^2 - 24) = 0 \\\\ 2x = 0 \text{ or } x^2 - 24 = 0 \\\\ x = 0 \text{ or } x = \pm2\sqrt6\approx\pm4.90[/tex]
The two non-zero solutions fall outside the domain, so the only inflection point is (0, 0).
Dominique from "Dominique's Pizza" bakes p pizzas every day. Currently, it costs her $8 dollar sign, 8 per day to use the oven and $1.50 per pizza for the ingredients
Tomorrow, the price for the ingredients will increase from $1.50 per pizza to $2 per pizza. The oven costs will stay the same at $8 per day.
Dominique did some calculations and found that she should bake 8 more pizzas each day in order for the total expenses per pizza (including ingredient and shared oven costs) to remain the same.
Write an equation in terms of p to model the situation.
Answers
The equation in term of p that models the above experience is:
2p + 10 = 0.8p + 20.
What is an equation?
Any statement that models or captures the factors of a problem where in an equal sign is present to equate two of the factors or expressions therein is called an equation.
How do we form the above equation?Everyday pizza production is equal to p.Brick oven use fees are $10 per day.Ingredients for brick oven pizza cost $2 per pizza.$20 a day is the cost of using an electric oven.Pizzas baked in an electric oven cost $0.8 per pizza in ingredients.If an electric oven is used, the total cost of making a pizza falls by $1, including the cost of the ingredients.Total cost of baking p pizzas with brick oven = A = p(cost of one pizza) + cost of baking = p(2) + 10 (in dollars).
Total cost of baking p pizzas with electric oven = B = p(cost of one pizza) + cost of baking = p(0.8) + 20 (in dollars).
B = A - 1 (as using electric oven saves $1 per day, as given)
Thus, we get:
2p + 10 = 0.8p + 20
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500 portions of strawberries have been ordered for the tournament, but because of bad weather only
5
6
of the order has been delivered.
10% of those delivered are given to the players and staff.
How many portions of strawberries can be sold?
Answers
We conclude that 375 portions can be sold.
How many portions can be sold?
We know that 500 portions have been ordered, but only 5/6 of that was delivered, so the number of delivered portions is:
p = (5/6)*500 = 416.6
Which we can round to the next whole number, 417.
Now we know that 10% of these are given to the players and staff, then the number of portions that can be sold is the 90% of 417, which is:
N = 417*(90%/100%) = 417*0.9 = 375
We conclude that 375 portions can be sold.
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A customers monthly bill is $50 including taxes. You mom ’ll offer a 30% discount applicable towards the $50 on a monthly basis. The discount started being applied to his account on June 16. Therefore for the month of June the customer will receive a discount on a prorated basis on the monthly bill. The customers billing cycle begins on the first the month. What is the total billed amount for the month of June?
Answers
Using proportions, the billed amount for the month of June is:
D. $42.50
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
The discount will be applied only for the second half of the month, from June 16 to June 30, hence instead of a discount of 30%, it will count as a discount of 15%, meaning that 85% of the bill will be paid, hence the amount paid will be of:
A = 0.85 x $50 = $42.50.
Hence option D is correct.
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Graph on the number line all values of x that satisfy 2x+2/x+7 >= 0
Please help, if you help me I will give you a brainlist.
Answers
All values of x that satisfy 2x+2/x+7 >= 0 are represented as x >= -1
How to graph the inequality on a number line?The inequality expression is given as:
2x+2/x+7 >= 0
Multiply both sides by x + y
2x+2 >= 0
Subtract 2 from both sides
2x > -2
Divide both sides by 2
x >= -1
Hence, all values of x that satisfy 2x+2/x+7 >= 0 are represented as x >= -1
See attachment for the number line of x >= -1
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