Most towns use a water tower to store water and provide pressure in the pipes that deliver water to customers. The figure below shows a spherical water tank that holds 5.80 105 kg of water when full. Note that the tank is vented to the atmosphere at the top and that the pipe delivering water to customer Smith is a height h = 3.75 m above the level of the pipe delivering water to customer Jones. Determine the gauge pressure of the water at the faucet of each house when the tank if full.
There is a spherical water-filled chamber with a vent on top and underneath it is a pipe 18 m long that leads down to the ground. At ground level a horizontal pipe connects the faucet in the Jones house to the water supply. The faucet in the Smith house is connected to the water supply with a pipe at a height h above ground level.
(a) Jones house
Pa

(b) Smith house
Pa

Answers

Answer 1

The effective height of the water for Smith's house will be 24.61m.

How to calculate the height?

Based on the information given, the volume of the water in sphere will be:

= 4/3πr³ = (5.80 × 10^5)/1000

= 4.18r³ = 580

r³ = 138.7

r = 5.18m

The effective height of the water will be:

= 18.0 + 2(5.18)

= 28.36

The gauge pressure at Faucet of Jones house will be:

= pgh

= 1000(9.8)(28.36)

= 277.9kPa

The effective height of the water for Smith's house will be:

= 18.0 + 2(5.18) - 3.75

= 24.61m

The gauge pressure at Faucet of Jones house will be:

= 1000 × 9.8 × 24.61

= 241.2kPa

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Related Questions

Particles that are __________ can transfer heat energy as they vibrate.
A. The same size
B. The same color
C. Very close together
D. Very far apart

Answers

Answer is C. Very close together

Reason
Conduction is the process where heat energy is transmitted through collisions or direct contact between atoms or molecules that are close together.

Explain the mechanism by which an open fracture could result in shock.

Answers

Answer:

an open fracture contains some sort of water which if it comes in contact with electrons could result to a shock

Is it possible for an object to be in equilibrium (no net force), if only one force is acting on it ?

Answers

No

An object cannot be in equilibrium if only one force is acting upon it as there is no way for the net force to be canceled out unless there is at least one other force (so 2+ total) acting upon the object.

An object is thrown upward with initial velocity of 30m/s at angle of 30 degree to the horizontal. calculate the components of the initial velocity.​

Answers

Answer:

Vo (vertical) = Vo sin 30 = 30 m/s / 2 = 15 m/s

Vo (horizontal) = Vo cos 30 = .866 30 m/s = 26 m/s

In thicker materials the particles can move more easily, therefore the resistance has to ____________.
A. Increase
B. Decrease
C. Stay the same
D. Not enough info

Answers

In thicker materials the particles can move more easily, therefore the resistance has to decrease.

Hence Option (b) is correct.

Resistivity, which is sometimes represented by the Greek letter rho, is quantitatively equal to a specimen's resistance R times its cross-sectional area A times its length.

ρ = R × A/ l

R = ρ × l/ A

It means the Resistance of the material is inversely proportional to the area of the material.

As the area of the material increases, the resistance decreases and vice versa.

Hence, In thicker particles, there is a greater area available and that's why resistance has to decrease so that particles can move more easily.

Hence, Option (b) is correct.

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density of a substance ratio​

Answers

Answer:

Density of a substance is the ratio of mass of the substance to its volume.

Answer:

Density of a substance is the ratio of mass of the substance to its volume.

A car with a mass of 1000 kg accelerates from 0 to 90 km/h in 10 seconds. a) What is its acceleration? b) What is the net force on the car?

Answers

Answer:

v

f=90km/h=25m/s

v_{_{i}}=0v

i=0

t=10\;\mathrm{s}t=10s

m=1000\;\mathrm{kg}m=1000kg

The acceleration of the car is 2.5 m/s². The net force acting on the car is 2500 Newtons (N). The correct answers are  2.5 m/s², 2500 Newtons (N).

Given:

Mass of the car (m) = 1000 kg

Acceleration (a) = 2.5 m/s²

a) The acceleration of the car is:

Acceleration (a) = Change in velocity / Time taken

Final velocity (v(f)) = 90 × 0.27778  = 25 m/s

Acceleration (a) = (Final velocity - Initial velocity) / Time taken

Acceleration (a) = (25 - 0 ) / 10

Acceleration (a) = 2.5 m/s²

Therefore, The acceleration of the car is 2.5 m/s².

b) Newton's second law of motion:

F = m × a

F = 1000 × 2.5

F = 2500 N

The net force acting on the car is 2500 Newtons (N).

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Consider the ballistic pendulum collision. The projectile, of mass m, is fired into a large block of mass M. (Figure 1)
a) Derive a formula for the fraction of the magnitude of kinetic energy lost
Express your answer in terms of the variables m and M .
b)Evaluate the fraction for m = 18.0 g and M = 380 g .
Express your answer using three significant figures.

Answers

The fraction of the magnitude of the kinetic energy lost is [tex]\frac{(change) KE }{KE} = 1 - \frac{m}{m + M }[/tex]. = 0.955.

using the law of conservation of momentum,

[tex]mv=(m+M)V[/tex]

[tex]V= m ( \frac{1}{M+m} ) v\\[/tex]

kinetic energy lost,

Δ[tex]KE=KE_{i} -KE_{f}[/tex]

(see image )

now, for the other part

the fraction of the kinetic energy lost,

ΔKE/ KE = [tex]1- m (\frac{1}{m+M} )[/tex]

ΔKE/ KE = [tex]1 - 18 ( \frac{1}{18 + 380 } )[/tex]

ΔKE/ KE = 0.955.

what is kinetic energy ?

The energy that an object has as a result of motion is known as kinetic energy. It is stated as the effort needed to transfer a bulk body from rest to the given velocity. The body holds onto the kinetic energy it gained during its acceleration until its speed changes.

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Using the Left Hand Rule, if motion is down and the current is toward you, which way is the field?

Answers

In the left-hand rule, the field is represented by the forefinger and it is perpendicular to the motion.

Fleming’s Left-Hand Rule:

A force perpendicular to the field's direction and the direction of the current flow is experienced by a current-carrying conductor when it is exposed to an external magnetic field. According to Fleming's Left Hand Rule, if the thumb, forefinger, and middle finger are arranged in a straight line on the left hand, the thumb will point in the direction of the force experienced by the conductor, and the forefinger will point in the direction of the magnetic field, and the middle finger will point in the direction of the electric current. This rule is employed to determine the magnetic force's direction within an electric motor.

Fleming’s Left-Hand Rule are essential rules applicable in magnetism and electromagnetism. They were created by John Ambrose Fleming in the late 19th century as an easy method of determining the direction of motion in an electric motor.

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Circle the anomalous result in the table below. An anomaly is a piece of data that doesn't
fit in with the rest of the data.
1. Concentration of
sucrose (M)
0.25
0.5
1
1.5
2
2. Change in mass of piece of potato (g)
Group B's
Group A's
measurements
0.02
0.05
0.12
0.17
0.21
3. measurements
0.03
0.05
2.3
0.14
0.2
Average?





Pls help I need to get this done really soon otherwise I will get a detention for two hours after school with my least fave teacher plss it’s for a test!!!!!!

Answers

Answer:

Explanation:

yes

What climate zone are you in temperatures are always very warm Where is this zone located on Earth

Answers

Answer:

Warm weather may be found in the tropical zone since the sun's heat is concentrated in regions close to the equator. At 23.5 degrees north of the equator and 23.5 degrees south of the equator, this area is nearly in the middle of the world. It has a monthly average temperature of 18 degrees Celsius or higher.

Explanation:

When a 6kg block is placed on a vertical spring, the spring is compressed by 20cm. How much work is required to compress the spring by an additional 10CM​

Answers

Answer:

Mass of block = 6kg

wright = 6 × g = 60 N using g = 10 m/s^2 .

compression= 0.20m

spring constant =( weight / compression) =( 60/0.20) = 300 N/m .

Work done in compressing 0.20 m =( 1/2 × 300 × 0.20 × 0.20)= 6 joule.

Additional compression = 0.10 m

total compression = 0.20+ 0.10= 0.30 m.

Total work done = ( 1/2 × 300 × 0.30× 0.30) = 13.5 joule.

Hence work done in compressing from 0.20 m to 0.30 m will be = ( 13.5 - 6) = 7.5 joule.

Note :- work done in compressing a spring having spring constant K N/m by x m is equal to 1/2× (K) × X^ 2 .

progress of science has not caused any ill effect true or false?​

Answers

False due to certain experiments and materials that are now used / were used such as plastic

How does the suns energy affect the climate of an area

Answers

Answer:

the earth receives the suns energy as radiation which is able to travel without the need of matter from point A to point B and this radiation is also in the form of heat.

Explanation:

Sun's energy fall on the earth in form of radiation and heats up the atmosphere and produces unequal heating due to its spherical nature and impacts climate of different areas.

The Sun is the only source of energy for the Earth's climate system. Fundamental to atmospheric composition is the warming of the atmosphere caused by solar radiation, which also causes global wind patterns and aids in the development of clouds, storms, and rainfall.

When the sun is at its maximum (peak in sunspots, prominences, and flares), it produces more ultraviolet (UV) radiation. More ozone is produced as a result of UV light, warming the stratosphere. The lower atmosphere and Earth's surface warm slightly as a result of the increased solar radiation.

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I = 30A and R = 30; what is V?



A. 900v
B.90v
C.10v
D.0.1v

Answers

Answer:

[tex]V = 900\; {\rm V}[/tex] for a resistor where [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex].

Explanation:

By Ohm's Law, if the electric resistance of a resistor is [tex]R[/tex] and the current going through that resistor is [tex]I[/tex], the voltage across that resistor would be [tex]V = I\, R[/tex].

Note that electric resistance is typically measured in Ohms, where [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex].

Given that [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex] for the resistor in this question, apply the formula [tex]V = I\, R[/tex] to find the voltage [tex]V[/tex] across this resistor:

[tex]\begin{aligned} V &= I\, R \\ &= 30\; {\rm A} \times 30\; {\rm \Omega} \\ &= 30\; {\rm A} \times 30\; {\rm V \cdot A^{-1}} \\ &= 900\; {\rm V} \end{aligned}[/tex].

1. What type of waves can only travel through a medium?

Answers

Answer:

A mechanical wave can only travel through a medium.

i. Which of the following formula gives definition of relative density? d d B. A. C. d water at 4°C d d mercury at 4°C D. d water at 40°C d d alcohol at 4°C​

Answers

Answer:

water at 4°c that's abnormal stage of water

A bead of mass 15g is sliding on a wire. It has a speed of 2.0m/s at A, and it stops as it reaches the point C. The length of the wire from A to C is 250cm. How large an average friction force opposed the motion of the bead?

Answers

Answer:

.12 N

Explanation:

Velocity goes from 2 m/s    to   0  m/s   so average velocity = 1 m/s

.250 m / 1 m/s  =  .25 second to stop

change in velocity / change in time = accel

  2 m/s / .25 sec =  8 m/s^2

F = ma

  = .015 kg *  8 m/s^2  = .12 N

4 Four objects are stiuated along the y axis as follow: a 20 kg object is at +3 m, a 3 kg object is at +2.5 m, a 2.5 kg object is at origin, and a 4 kg object is at -5 m. What is the center of mass of these objects?​

Answers

Answer: 1.348 meters

Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point  c . Adding the four moments together, we get:

(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0

6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0

11.5c=15.50

c=  1.348 metres

The center of mass is on the y axis at  y  = 1.348 metres.

A 5 Ω and a 5 Ω resistor are in parallel. What is their total resistance?
A. 10 Ω
B. 2.5 Ω
C. 25 Ω
D. 5 Ω

Answers

Answer:

B. 2.5 Ω

Explanation:

[tex]\frac{1}{5} +\frac{1}{5}=0.4[/tex]

Put a one on top of the 0.4

[tex]\frac{1}{0.4} =2.5[/tex]

what is barometer ???​

Answers

Answer:

an instrument measuring atmospheric pressure, used especially in forecasting the weather and determining altitude.

Explanation:

hope it helps ya

Why does Usain bolt run?

Answers

Answer:

because he's fast and speedy

Explanation:

a ball bearing x is dropped vertically downwards,from the edge of a table and it takes 0.5seconds to hit the floor. Another bearing y leaves from the edge of the table horizontally with a velocity of 5m/s . Find:.
a)the time taken for bearing y to reach the table?
b)the horizontal distance traveled by y before hitting the floor
c)the height of the table top above the floor level

Answers

Answer:

See below

Explanation:

A) bearing y reaches the FLOOR in the same amount of time   .5 seconds  since there is no initial vertical velocity component

B.  in .5 seconds y will travel     5 m/s * .5 s = 2.5 meters horizontally

C.  d = 1/2 a t^2

         = 1/2 (9.81)(.5^2) = 1.23 m table height

(a) Bearing y takes 0.2 seconds to reach the table. (b) Bearing y travels 1 meter horizontally before hitting the floor. (c)  The height of the table top above the floor level is 1.225 meters.

a) Time is taken for bearing y to reach the table:

For a horizontal motion, the equation to calculate time is:

Time (t) = Distance (d) ÷ Velocity (v)

Time (t) = Width of the table / Velocity of y

t = 1  / 5

t = 0.2 sec

So, bearing y takes 0.2 seconds to reach the table.

b) Horizontal distance traveled by bearing y before hitting the floor:

Distance (d) = Velocity (v) × Time (t)

d = 5 × 0.2

d = 1 m

So, Bearing y travels 1 meter horizontally before hitting the floor.

c) The height of the table top above the floor level:

h = (1/2) × g × t²

h = (1/2) × 9.8 × (0.5)²

h = (1/2) × 9.8 × 0.25

h = 1.225 m

So, the height of the table top above the floor level is 1.225 meters.

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A simple pendulum suspended in a rocket ship has a period [tex]T_{0}[/tex]. Assume that the rocket ship is near the earth in a uniform gravitational field.
True or false:
1. If the ship moves upward with a constant velocity, the period increases.
2. If the length of the pendulum is doubled, the new period will be: square root of 2 times [tex]T_{0}[/tex].
3. If the ship accelerates upward, the period increases.
4. If the ship accelerates downward at 9.81 [tex]m/s^{2}[/tex], the pendulum will no longer oscillate.
5. If the mass of the pendulum is halved, the period decreases.

Answers

(1) If the ship moves upward with a constant velocity, the period increases, false.

(2) If the length of the pendulum is doubled, the new period will be: square root of 2 times T₀. true.

(3) If the ship accelerates upward, the period increases, true.

(4) If the ship accelerates downward at 9.81 m/s² , the pendulum will no longer oscillate, false.

(5) If the mass of the pendulum is halved, the period decreases, false.

Period of a simple pendulum

The period of a simple pendulum is given as;

T = 2π√(L/g)    ------- (1)

where;

L is length of the pendulumg is acceleration due to gravity

When the ship moves upward with a constant velocity, the period will not change.

When the length of the pendulum is doubled

T ∝√L

when, L = 2L₀

T = T₀√2

Thus, if the length of the pendulum is doubled, the new period will be: square root of 2 times T₀.

when ship accelerates upward

t = √2h/g

when the height increases, time or period increases

when mass of the pendulum is halved

T = √I/mgd

where;

m is mass of the pendulum

when the mass is halved, the period increases.

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is power and voltage the same thing yes or no ​

Answers

No because voltage is the difference in electric potential between two points. Current is just the rate of flow of electric charge

Is there any change in mass of substance after it changes its state? Explain with an example​

Answers

Answer:

No

Explanation:

When a substance changes its state , there will not be any change in the mass of substance . For example , if we change 100 grams of water (liquid) to ice(solid) , the mass of ice will be same i.e., 100 grams . This shows there is no change in the mass even if a substance changes its state.

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Suppose you need your silicon circuit element to run continuously for 3 minutes before it shuts off long enough to cool back down to its initial temperature. If the circuit element can withstand a temperature change of 5.1 ∘C without being damaged, what is the maximum rate at which energy can be added to the circuit element?

Answers

The maximum rate at which energy can be added to the circuit element mathematically given as

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

What is the maximum rate at which energy can be added to the circuit element?

Generally, the equation for P is  mathematically given as

[tex]P=\ln s \frac{\Delta T}{\Delta t}[/tex]

Therefore

[tex]Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}[/tex]

[tex]\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}[/tex]

[tex]\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}[/tex]

Max temp Change

[tex]MaxT=5.6^{\circ} \mathrm{C}[/tex]

[tex]\text { time }=3 \times 60[/tex]

t=180s

In conclusion, Max Energy Rate

[tex]MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}[/tex]

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

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Glucose solution is administered to a patient in a hospital. The density of the solution is 1.308 kg/l. If the blood pressure in the vein is 35.7 mmHg, then what is the minimum necessary height of the IV bag above the position of the needle?

Answers

The minimum necessary height of the IV bag above the position of the needle is 0.37 m.

Minimum necessary height

The minimum necessary height of the IV bag above the position of the needle is calculated as follows;

P = ρgh

where;

ρ is density = 1.308 kg/L = 1308 kg/m³g is acceleration due to gravity = 9.8 m/s²p is pressure = 35.7 mmHg = 4759.609 Pah is height, (m) = ?

Substitute the given parameters and solve for minimum height

h = P/ρg

h = (4759.609) / (9.8 x 1308)

h = 0.37 m

Thus, the minimum necessary height of the IV bag above the position of the needle is 0.37 m.

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If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical speed be after having fallen a vertical distance of 50.8m if you neglect air resistance over that distance?

Answers

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

Time of motion of the girl

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

v is initial vertical velocity = 0t is time of motiong is acceleration due to gravity

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

Final vertical velocity of the skydiver

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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is a pot plant a closed system?​

Answers

Answer:

No because a pot plant system must interact with its surroundings (air, water, etc) and these are not closed systems.

Only if the pot plant were completely enclosed, say in a large glass jar would the system be closed.

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