It would take 2 months for the membership of both clubs to be the same
What is an equation?An equation is an expression that shows the relationship between two numbers and variables.
The standard form of a linear equation is:
y = mx + b
Where m is the rate of change and b is the y intercept
Let y represent the total cost of dues over x months, hence given that:
y = 3x - 5 (1)
Also:
4x - 3y = 5
y = (4x - 5)/3 (2)
For the membership of both clubs to be the same:
3x - 5 = (4x - 5)/3
9x - 15 = 4x - 5
x = 2
It would take 2 months for the membership of both clubs to be the same
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Use theorem 9. 11 to determine the convergence or divergence of the p-series. 1 1 6 32 1 6 243 1 6 1024 1 6 3125. .
The given series is diverges according to the P Test.
According to the statement
we have given that the a series and we have to find that the those series is a converges or diverges.
So, For this purpose, we know that the
P-series test to say whether or not the series converges.
So, The given series is
[tex]1 + 1/\sqrt{32} + 1/\sqrt[3]{243 } + 1/\sqrt[4]{1024} + 1/\sqrt[5]{3125}[/tex]
And then
The value of P becomes P = 5/6 < 1 when we find it using the p series test.
Hence, the p-series diverges
Because according to the p series test, The series converges if, and only if, the power satisfies p>1.
And diverges if, and only if, the power satisfies p<1.
So, The given series is diverges according to the P Test.
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Disclaimer: This question was incomplete. Please find the full content below.
Question:
Use Theorem 9.11 to determine the convergence or divergence of the p-series. 1 + 1/32 squareroot + 1/243 squareroot 3 + 1/1024 squareroot 4 + 1/3125 squareroot 5.
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By using properties of right triangles and trigonometric functions, we conclude that the length of the side BC is 19 units.
How to find the length of a side in a system of three triangles
In this problem we can use trigonometric functions to determine the length of the side BC in three steps:
Step 1
BE = AB/tan 60°
BE = 19√2 /4
Step 2
BD = BE/cos 45°
BD = 19/2
Step 3
BC = BD/sin 30°
BC = 19
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PLS HELP ME WITH THIS
Answer:
The first option
Kindly award branliest
Can somebody solve this?
Answer:
MO = 12
PR = 3
Step-by-step explanation:
The perimeter of a triangle is calculated by adding all side lengths up:
The perimeter of triangle MNO is given as 48
The perimeter of triangle PQR is given as 12
The ratio is 1/4 (simplified ratio of 12/48)
we can write the following equation using this information:
[tex]\frac{x+2}{12x} = \frac{1}{4}[/tex]
cross multiply fractions
12x = 4x + 8
subtract 4x from both sides
8x = 8
divide both sides by 8
x = 1
Now to find the measure of side lengths in question we replace x with 1
for MO = 12x
12*1 = 12
for PR = x + 2
1 + 2 = 3
Point M is the midpoint of AB. Find BM.
since we know that M is the midpoint of the AB segment, that simply means that the two halves it makes are congruent, namely AM = BM.
[tex]\stackrel{AM}{4x+13}~~ = ~~\stackrel{BM}{3x+17}\implies x+13=17\implies x=4~\hfill \stackrel{3(4)~~ + ~~17}{BM=29}[/tex]
The required length of the side BM is 29.
What is algebra?Algebra is a study of mathematical expressions, in which numbers and quantities are represented in formulas and equations by letters and other universal symbols.
In the given question,
Point M is the midpoint of line AB.
AM = 4x + 13,
and BM = 3x + 17
To find the length of MB, use midpoint property.
Since, Point M is the midpoint of AB,
Therefore, AM = MB
4x + 13 = 3x + 17
4x - 3x = 17 - 13
x = 4
The length of MB = 3x + 17 = 3 × 4 + 17 = 12 + 17 = 29.
The length of MB, where M is midpoint of AB, is 29.
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Select the correct answer. What is the value of x in the equation ln (x + 6) – ln (2x – 1) = 1? A. -0.21 B. 0.74 C. 1.35 D. 1.97
Given the:
ln(x + 6) - ln(2x - 1) = 1
Using the logarithm rule:
ln a - ln b = ln (a/b)ln((x + 6) / (2x - 1)) = 1((x + 6) / (2x - 1)) = E ¹We know,
e1 = ²'⁷²((x + 6) / (2x - 1)) ≈ 2.72Simplifying we get,
(x + 6) = 2.72 (2x - 1)x + 6 = 2.72 (2x) - 2.72 (1)x + 6 = 5.44x - 2.728.72 = 4.44xBy cross multiplication we get,
x = 8.72 / 4.44x = 1.97Therefore, the value of x is 1.97.
The correct option in the exercise ln (x + 6) - ln (2x - 1) = 1 is alternative "D".
Write an expression to represent: 3 minus the quotient of x and 4
Answer:3 - x/4
Step-by-step explanation: quotient of x and 4 = x/4. 3 minus x/4 = 3 - x/4.
The expression representing the sentence is [tex]$3 -\frac{x}{4}[/tex].
We have a sentence - "3 minus the quotient of x and 4".
We have to determine the expression that represents the sentence.
Express the statement - "The difference of x and y is equal to an irrational number" in the form of expression.The expression representing the above statement is -
x - y = π.
According to the question, we have -
3 minus the quotient of x and 4.
Using the Division Algorithm -
x = 4q + r
Substituting r = 0 by introducing decimals in the quotient, we get -
q = [tex]$\frac{x}{4}[/tex]
Therefore -
[tex]$3 -\frac{x}{4}[/tex]
Hence, the expression representing the sentence is [tex]$3 -\frac{x}{4}[/tex].
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How would I describe this?
Answer:
That's a reflection in the x axis.
Step-by-step explanation:
Triangle C is the mirror image of B with the x axis acting as a mirror.
Aku minta tolong dengan ini
Answer:5
Step-by-step explanation:
321 123
The drama club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $8.50, and bags of cookies cost $4.50, and sales equaled $79.00 in total. There were 6 more bags of cookies than candy sold.
Find the number of bags of candy and cookies sold by the drama club. Show your work.
The bags of candy that was sold is 6
The bags of cookies that was sold is 10.
What are the linear equations that represent the question?$8.50c + $4.50o = 79 equation 1
o - c = 6
o = 6 + c equation 2
Where:
o = bags of cookies soldc = bags of candies sold How many bags of candy and cookies were sold?Substitute for o in equation 1 using equation 2
$8.50c + $4.50(6 + c) = 79
$8.50c + 27 + 4.50c = 79
$8.50c + 4.50c = 79 - 27
$13c = 52
c = 52 / 13
c = 4
Substitute for c in equation 2
0 = 6 + 4 = 10
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The graph of a quadratic function is represented by the table.
x f(x)
6 -2
7 4
8 6
9 4
10 -2
What is the equation of the function in vertex form?
Substitute numerical values for a, h, and k.
Big fraction
Parentheses
Vertical bars
Square root
Root
Superscript (Ctrl+Up)
Subscript (Ctrl+Down)
Plus sign
Minus sign
Middle dot
Multiplication sign
Equals sign
Less-than sign
Greater-than sign
Less-than or equal to
Greater-than or equal to
Pi
Alpha
Beta
Epsilon
Theta
Lambda
Mu
Rho
Phi
Sine
Cosine
Tangent
Arcsine
Arccosine
Arctangent
Cosecant
Secant
Cotangent
Logarithm
Logarithm to base n
Natural logarithm
Bar accent
Right left arrow with under script
Right arrow with under script
Angle
Triangle
Parallel to
Perpendicular
Approximately equal to
Tilde operator
Degree sign
Intersection
Union
Summation with under and over scripts
Matrix with square brackets
The equation of the function in vertex form exists f(x) = -2·(x - 8)² + 6.
What is the equation of the function in vertex form?The given values exist
x, f(x)
6, -2
7, 4
8, 6
9, 4
10, -2
The equation of the function in vertex form exists
f(x) = a(x - h)² + k
To estimate the values of a, h, and k,
When x = 6, f(x) = -2 then
-2 = a(6 - h)² + k
= (h²-12·h+36)·a + k.............(1)
When x = 7, f(x) = 4 then
4 = a( 7- h)² + k
= (h²-14·h+49)·a + k...........(2)
When x = 8, f(x) = 6
6 = a( 8- h)² + k ...........(3)
When x = 9, f(x) = 4.
4 = a( 9- h)² + k ..........(4)
When x = 10, f(x) = -2
-2 = a(10- h)² + k ...........(5)
Subtract equation (1) from (2)
4 - 2 = a( 7- h)² + k - (a(6 - h)² + k )
= 13·a - 2·a·h........(6)
Subtract equation (4) from (2)
a (9 - h)² + k - a( 7- h)² + k
32a -4ah = 0
Simplifying the equation, we get
4h = 32
h = 32/4 = 8
From equation (6) we have;
13·a - 2·a·8 = 6
-3a = 6
a = -2
From equation (1), we have;
-2 = -2 × ( 10- 8)² + k
-2 = -8 + k
k = 6
The value of k = 6.
The equation of the function in vertex form exists f(x) = -2·(x - 8)² + 6.
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PLEASE HELP W THIS MATH QUESTION. correct answers only please
The values of x are x₁ ≈ 4.8 and x₂ ≈ - 0.8.
What is the quadratic equation behind two circular sections of equal area?
Herein we have two circular sections of equal area, whose expressions are described by the following geometric equations:
Semicircle
A = 0.5π · x² (1)
Half Semicircle
A = 0.25π · (x + 2)² (2)
By equalizing (1) and (2):
0.5π · x² = 0.25π · (x + 2)²
2 · x² = (x + 2)²
2 · x² = x² + 4 · x + 4
x² - 4 · x - 4 = 0
x² - 4 · x + 4 = 8
(x - 2)² = 8
x - 2 = ±√8
x = 2 ± √8
x = 2 ± 2√2
x = 2 · (1 ± √2)
x = 2 · (1 ± 1.41)
x₁ = 2 · 2.41 ∨ x₂ = 2 · (- 0.41)
x₁ = 4.82 ∨ x₂ = - 0.82
The values of x are x₁ ≈ 4.8 and x₂ ≈ - 0.8.
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Aisha wants to paint the four walls of her living room.
Each wall is 2.4 m high and 5.2 m long.
One wall has a door of 2 m by 0.8 m.
Tins of paint cost £12 per 2 litre tin.
Each litre of paint can cover 12 m2 of wall.
There is an offer of: Buy 2 tins get the 3rd at half price.
How much will Aisha pay to paint her living room?
The total amount Aisha would pay to paint her room is $54.
What is the cost of painting the rooms?The first step is to determine the area of the walls. The walls have the shape of a rectangle. Thus, the formula for the area of a rectangle would be used to determine the area of the wall.
Area of the three walls without a door : 3 x (length x width)
3 x (2.4 x 5.2) = 37.44 m²
Area of the fourth wall with a door : area of the wall - area of the door
(2.4 x 5.2) - (2 x 0.8) = 10.88m²
Total area of the walls : area of the three walls + area of the wall with the door
10.88m² + 37.44 m² = 48.32 m²
The next step is to determine the number of tins that would be needed:
48.32 /12 = 4.03
5 tins would needed
Cost of the 5 tins: (4 x 12) + (0.5 x 12) = $54
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Find the explicit form of the arithmetic function of n if the first term is 3 and the common difference is -4 . Then find the seventh term.
The explicit function is (b) f(n) = -4(n - 1) + 3; the seventh term is -21
How to determine the explicit form?The given parameters are:
First term of the sequence, a = 3Common difference of the sequence, d = -4The explicit form is for an arithmetic function.
An arithmetic function has an explicit form represented as:
f(n) = a + (n -1) * d
Substitute the values of n and a in the above equation
f(n) = 3 + (n -1) * -4
Evaluate the product i.e. multiply -4 by (n - 1)
f(n) = 3 -4(n - 1)
Rewrite the equation as
f(n) = -4(n - 1) + 3
The seventh term is then calculated as:
f(n) = -4(n - 1) + 3
Substitute 7 for n in the above equation
f(7) = -4(7 - 1) + 3
Evaluate
f(7) = -21
Hence, the explicit function is (b) f(n) = -4(n - 1) + 3; the seventh term is -21
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Find the inequality represented by the graph.
The inequality of the graph is expressed as: y > 1/2x + 2.
How to Find the Inequality of a Graph?The graph given has a broken line and the shaded part is above the boundary line, therefore, we would use the sign, ">" in our inequality. The inequality would be expressed as y > mx + b.
Find the slope (m):
Slope (m) = rise/run = 1 units/2 units
m = 1/2
b = 2 (y-intercepts)
Substitute m = 1/2 and b = 2 into y > mx + b
y > 1/2x + 2.
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Solve the system of equations below using the substitution method. y = 3x − 1y = - 4x 6
Answer:
x = 1; y = 2
Step-by-step explanation:
y = 3x − 1
y = -4x + 6
In the first equation, y = 3x - 1.
Substitute 3x - 1 for y in the second equation.
3x - 1 = -4x + 6
7x = 7
x = 1
Substitute 1 for x in the first original equation.
y = 3x - 1
y = 3(1) - 1
y = 3 - 1
y = 2
Solution: x = 1; y = 2
its really confusing
Answer:
Step-by-step explanation:
6:1 i think
The ordered pair that is a solution of the equation y = | - 3x + 3 | is:
(r, 24)
(7,0)
(7, - 18)
( 7,18)
Answer:
The answer would be (7, 18)
Step-by-step explanation:
The answers simple,
in the equation y=|-3x+3|
x and y would be said like this (x,y). just like the answer choices
now in the first option, x is R, so i couldn't understand that. so I'm gonna skip that.
in the second one, (7,0) would no work as
0=|-3(7) + 3|
0=|-21+3|
0=|-18|
and since "|" is absolute value, meaning that instead of the number being negative or positive the number will just be translated into how much distance is from the number and 0, or just make the number positive.
lets continue,
0=18, so (7,0)
the second one, (7,-18)
-18=|-3(7)+3|
-18=|-18|
again, its absolute value so
-18=18, so it still doesn't work
the last one, (7,18)
18=|-3(7)+3|
18=|18|
18=18
so (7,18) would work.
Given that x=2y and 3y=5z. Find the ratio x:y:z hence or otherwise find the amount of money Ali got if Ali, Ben and Chris shared Kshs. 36000 in the ratio x:y:z respectively
Answers
The ratio x:y:z is 10:5:3
Ali got 20,000
===================================================
Explanation:
Let
x = amount Ali goty = amount Ben gotz = amount Chris gotThose amounts add to 36,000
x+y+z = 36,000
We're told that x = 2y, so let's replace x with 2y in the equation above to get these steps
x+y+z = 36,000
2y+y+z = 36,000
3y+z = 36,000
We're also told that 3y = 5z, so we can replace that previously mentioned 3y with 5z to end up with one variable, in which we can solve for like shown below.
3y+z = 36,000
5z+z = 36,000
6z = 36,000
z = (36,000)/6
z = 6,000
This tells us that Chris got 6,000
Use this to find y
3y = 5z
3y = 5*6,000
3y = 30,000
y = (30,000)/3
y = 10,000
Ben received 10,000
Lastly, determine x.
x = 2y
x = 2*10,000
x = 20,000 which is the amount Ali got.
The ratio x:y:z turns into 20,000:10,000:6,000 which fully simplifies to 10:5:3 after dividing all three parts by the GCF 2000. It might be tempting to try to reduce the 10:5 portion into 2:1, but we cannot divide by 5 since it's not a factor of that 3 at the end.
-------------------------
Check:
Ali + Ben + Chris = 20,000 + 10,000 + 6,000 = 36,000
which helps confirm the answer.
An oblique prism with a square base of edge length x units has a volume of x3 cubic units. which expression represents the height of the prism?x unitsx units2x unitsx units
The expression that represents the height of the oblique prism is: 1/2x.
What is the Volume of a Prism?
The volume of a prism is defined as the total space occupied by the three-dimensional object. Mathematically, it is defined as the product of the area of the base and the length.Prism Volume = base area × height of the prism
Given that the oblique prism has:
Volume = 1/2x³ cubic units
edge length = x units
Therefore,
base area = x²
Thus:
1/2x³ = (x²)(height)
Divide both sides by x²
1/2x³ ÷ x² = height
1/2x³ × 1/x² = height
x³/2 × 1/x² = height
height = x³/2x²
height = x/2
Therefore, the expression that represents the height of the oblique prism is: 1/2x.
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The complete question is -
An oblique prism with a square base of edge length x units has a volume of x3 cubic units. Which expression represents the height of the prism?
Solve the system u=3x-4y, v=x+4y for x and y in terms of u and v. then find the value of the jacobian
Eliminate [tex]y[/tex].
[tex]u + v = (3x - 4y) + (x + 4y) = 4x \implies x = \dfrac{u+v}4[/tex]
Eliminate [tex]x[/tex].
[tex]u - 3v = (3x - 4y) - 3 (x + 4y) = -16y \implies y = \dfrac{3v-u}{16}[/tex]
The Jacobian for this change of coordinates is
[tex]J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} \dfrac14 & \dfrac14 \\\\ -\dfrac1{16} & \dfrac3{16} \end{bmatrix}[/tex]
with determinant
[tex]\det(J) = \dfrac14\cdot\dfrac3{16} - \dfrac14\cdot\left(-\dfrac1{16}\right) = \dfrac1{16}[/tex]
Evaluate the following integral (Calculus 2) Please show step by step explanation!
Answer:
[tex]\displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=-4 \ln |x|+5 \ln|x-1|+\dfrac{3}{x-1}+\text{C}[/tex]
Step-by-step explanation:
Fundamental Theorem of Calculus
[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]
If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.
Given integral:
[tex]\displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x[/tex]
Factor the denominator:
[tex]\begin{aligned}\implies x^3-2x^2+x & = x(x^2-2x+1)\\& = x(x^2-x-x+1)\\& = x(x(x-1)-1(x-1))\\ & = x((x-1)(x-1))\\& = x(x-1)^2\end{aligned}[/tex]
[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int \dfrac{x^2-4}{x(x-1)^2}\:\:\text{d}x[/tex]
Take partial fractions of the given fraction by writing out the fraction as an identity:
[tex]\begin{aligned}\dfrac{x^2-4}{x(x-1)^2} & \equiv \dfrac{A}{x}+\dfrac{B}{(x-1)}+\dfrac{C}{(x-1)^2}\\\\ \implies \dfrac{x^2-4}{x(x-1)^2} & \equiv \dfrac{A(x-1)^2}{x(x-1)^2}+\dfrac{Bx(x-1)}{x(x-1)^2}+\dfrac{Cx}{x(x-1)^2}\\\\ \implies x^2-4 & \equiv A(x-1)^2+Bx(x-1)+Cx \end{aligned}[/tex]
Calculate the values of A and C using substitution:
[tex]\textsf{when }x=0 \implies -4=A(1)+B(0)+C(0) \implies A=-4[/tex]
[tex]\textsf{when }x=1 \implies -3=A(0)+B(0)+C(1) \implies C=-3[/tex]
Therefore:
[tex]\begin{aligned}\implies x^2-4 & \equiv -4(x-1)^2+Bx(x-1)-3x\\& \equiv -4(x^2-2x+1)+B(x^2-x)-3x\\& \equiv -4x^2+8x-4+Bx^2-Bx-3x\\& \equiv (B-4)x^2+(5-B)x-4\\\end{aligned}[/tex]
Compare constants to find B:
[tex]\implies 1=B-4 \implies B=5[/tex]
Substitute the found values of A, B and C:
[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-\dfrac{3}{(x-1)^2}\:\:\text{d}x[/tex]
[tex]\textsf{Apply exponent rule} \quad \dfrac{1}{a^n}=a^{-n}[/tex]
[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-3(x-1)^{-2}}\:\:\text{d}x[/tex]
[tex]\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int ax^n\:\text{d}x=a \int x^n \:\text{d}x$\end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating} $\dfrac{1}{x}$\\\\$\displaystyle \int \dfrac{1}{x}\:\text{d}x=\ln |x|+\text{C}$\end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating $ax^n$}\\\\$\displaystyle \int ax^n\:\text{d}x=\dfrac{ax^{n+1}}{n+1}+\text{C}$\end{minipage}}[/tex]
[tex]\begin{aligned}\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x & =\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-3(x-1)^{-2}}\:\:\text{d}x\\\\& = \displaystyle -4\int \dfrac{1}{x}\:\:\text{d}x+5\int \dfrac{1}{(x-1)}\:\:\text{d}x-3 \int (x-1)^{-2}}\:\:\text{d}x\\\\& = \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int (x-1)^{-2}}\:\:\text{d}x\end{aligned}[/tex]
Use Integration by Substitution:
[tex]\textsf{Let }u=(x-1) \implies \dfrac{\text{d}u}{\text{d}x}=1 \implies \text{d}x=\text{d}u}[/tex]
Therefore:
[tex]\implies \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int (x-1)^{-2}}\:\:\text{d}x[/tex]
[tex]\implies \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int u^{-2}}\:\:\text{d}u[/tex]
[tex]\implies -4 \ln |x|+5 \ln|x-1|-\dfrac{3}{-1}u^{-2+1}+\text{C}[/tex]
[tex]\implies -4 \ln |x|+5 \ln|x-1|+3u^{-1}+\text{C}[/tex]
[tex]\implies -4 \ln |x|+5 \ln|x-1|+\dfrac{3}{u}+\text{C}[/tex]
Substitute back in u = (x - 1):
[tex]\implies -4 \ln |x|+5 \ln|x-1|+\dfrac{3}{x-1}+\text{C}[/tex]
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Let startfraction cosine (2 x) over cosine (x) sine (x) endfraction = 0 where 0° ≤ x ≤ 180°. what are the possible values for x?
45° only the possible values for x.
What is the meaning of trigonometric ratio?
Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle.The given equation can be presented as follows;
[tex]\frac{cos (2 . x )}{cosine(x) + sin(x)} = 0[/tex]
We have that cos(2·x) = cos²(x) - sin²(x)
Also, we have, by the difference of two squares, the following relation;
cos²(x) - sin²(x) = (cos(x) - sin(x))(cos(x) + sin(x))
Therefore, the given equation can be written as follows;
[tex]\frac{cos (2 . x )}{cosine (x) + sin(x) } = \frac{(cos(x) - sin(x) * (cos(x) + sin(x)}{(cos(x) + sin(x))} = 0[/tex]
Crossing the common term, (cos(x) + sin(x)), in the numerator and the denominator, we have-
[tex]\frac{(cos(x) - sin (x) * (cos(x) + sin(x)}{(cos(x) + sin(x))} = cos (x) - sin(x) = 0[/tex]
From cos(x) - sin(x) = 0, we have;
Adding sin(x) to both sides of the equation
cos(x) - sin(x) + sin(x) = 0 + sin(x)
cos(x) = sin(x)
Therefore, the opposite leg and the adjacent leg of the right triangle formed with reference to the angle x are equal
∴ x = 90/2 = 45° only for 0° ≤ x ≤ 180°
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A star system with more than 2 but less than a million stars. which type of star system is pictured?
The star system is pictured is open cluster
What is Open cluster?A type of star cluster known as an open cluster is composed of up to a few thousand stars that are around the same age and originated from the same massive molecular cloud. Within the Milky Way galaxy, more than 1,100 open clusters have been found, and it is believed that there are many more.
What is solar system?The Sun and the things that circle it make up the gravitationally bound solar system. It was created 4.6 billion years ago when a massive interstellar molecular cloud collapsed because to gravity. The Sun is the system's primary mass source, while Jupiter is home to the majority of the system's leftover mass.
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I understand that the question you are looking for is :
| Will mark brainliest | Which type of star system is pictured? |
A. globular cluster
B. open cluster
C. binary
Answer:
B
Step-by-step explanation:
open cluster
Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 66 kmh faster than the other. If the two planes are 10,716 kilometers apart after 6 hours, what is the rate of each plane
Answer:
The rate of planes: 926 km/h and 860 km/h
=========================
GivenTwo planes travel in opposite directions,One plane travels 66 km/h faster than the other,The distance between the two planes after 6 hours is 10716 km.To findThe rate of of each planeSolution
The distance traveled by two planes in an hour is:
10716/6 = 1786 km/hLet the rate of one plane be x, then the other plane's rate is x - 66.
The sum of two rates is the distance traveled in one hour:
x + x - 66 = 17862x - 66 = 17862x = 1786 + 662x = 1852x = 1852/2x = 926So the rate of one plane is 926 km/h and of the other plane is:
926 - 66 = 860 km/h40 points please help
The athlete that has the shortest training ride is athlete A.
The athlete that has the shorter range is Athlete B.
The athlete that has the greater median is Athlete B.
The athlete that has the greater IQR is athlete A.
What are the summary statistics?A box plot is used to study the distribution and level of a set of scores. The box plot consists of two lines and a box. the two lines are known as whiskers. The first whisker represents the minimum number and the second whisker represents the maximum number. The difference between the whiskers is known as range.
Range of Athlete A = 36 - 13 = 13
Range of Athlete B = 30 - 19 = 11
Training ride of Athlete A = 16
Training ride of Athlete B = 21
On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile.
Median of Athlete A = 20
Median of Athlete B = 25
IQR of Athlete A = 30 - 16 = 14
IQR of Athlete B = 28 - 21 = 7
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really confused about b, how to get the position of w. Hope someone could help me.
Answer + Step-by-step explanation:
(a)
[tex]\overrightarrow{PQ} =a+\frac{3}{5} b[/tex]
(b)
we are given:
[tex]\left\vert \overrightarrow{RQ} \right\vert =\frac{3}{5} \left\vert \overrightarrow{OP} \right\vert[/tex]
Then
[tex]\left\vert \overrightarrow{WR} \right\vert =\frac{3}{5} \left\vert \overrightarrow{WO} \right\vert[/tex]
and we know that :
[tex]\overrightarrow{OW} = \overrightarrow{OR} + \overrightarrow{RW}[/tex]
Then
[tex]\overrightarrow{OW} = a +\frac{3}{5} \overrightarrow{OW}[/tex]
Then
[tex]\frac{2}{5} \overrightarrow{OW} = a[/tex]
Then
[tex]\overrightarrow{OW} = \frac{5}{2} a[/tex]
You decide that you want to purchase a Tesla SUV. You borrow \$95,000 for the purchase. You agree to repay the loan by paying equal monthly payments of \$1,200 until the balance is paid off. If you're being charged 6\% per year, compounded monthly, how long will it take you to pay off the loan?
Using compound interest and a graphing calculator, it is found that it will take about 15 years for the loan to be paid off.
What is compound interest?The amount of money earned, in compound interest, after t years, is given by:
[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]
In which:
A(t) is the amount of money after t years. P is the principal(the initial sum of money). r is the interest rate(as a decimal value). n is the number of times that interest is compounded per year.For this problem, the parameters are given as follows:
A(0) = 95000, r = 0.06, n = 12.
Hence the value of the loan after t years is:
[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]
[tex]A(t) = 95000\left(1 + \frac{0.06}{12}\right)^{12t}[/tex]
[tex]A(t) = 95000(1.005)^{12t}[/tex]
You have monthly payments of $1,200, hence the amount paid after t years is:
P(t) = 12 x 1,200t = 14400t
Then we have to solve for:
A(t) = P(t)
[tex]14400t = 95000(1.005)^{12t}[/tex]
Which is solved in the graph below, meaning that it will take about 15 years for the loan to be paid off.
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A line has a slope of -2/5 and passes through the point (10,7) . Write the equation of this line in point-slope form, slope-intercept form, and standard form.
i will give brainliest if you help
[tex](\stackrel{x_1}{10}~,~\stackrel{y_1}{7})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{-\cfrac{2}{5}}(x-\stackrel{x_1}{10})[/tex]
pls help solve math problem!!! lots of points