Let F(x,y,z)=yzi+xzj+(xy+1)k be a vector field. (i) Find a potential ϕ(x,y,z) such that F=∇ϕ and ϕ(0,0,0)=2. Ans: xyz+z+2 (ii) Let C be a curve with parametrization r(t),0≤t≤2. Suppose, r(0)=(0,0,0),r(1)= (1,1,1) and r(2)=(2,2,2). Find ∫C​F⋅dr.

Answers

Answer 1

The potential ϕ(x,y,z) for the vector field F(x,y,z)=yzi+xzj+(xy+1)k is ϕ(x,y,z) = xyz+z+2.

To find the line integral ∫C​F⋅dr, we need to evaluate the dot product of F and dr along the curve C. Given that r(t) is the parametrization of C, we can express dr as dr = r'(t)dt.

Substituting the values of r(t) into F(x,y,z), we get F(r(t)) = (tz, t, t^2+1). Taking the dot product with dr = r'(t)dt, we have F(r(t))⋅dr = (tz, t, t^2+1)⋅(dx/dt, dy/dt, dz/dt)dt.

Now we substitute the values of r(t) and r'(t) into the dot product expression and integrate it over the given range of t, which is 0≤t≤2. This will give us the value of the line integral ∫C​F⋅dr.

Since the specific values of dx/dt, dy/dt, and dz/dt are not provided, we cannot calculate the exact value of the line integral without additional information.

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