jake made some tarts. He sold 3/5 of them and gave 1/4 of the remainder to his friends. If he had 150 tarts left, how many did he sell?
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Answer:

C

Step-by-step explanation:

the answer is c

The identity of  sin²Ф + cos²Ф  = 1 is verified below

Trigonometry ratio can be evaluated by following the laid down rules with the the use of table and calculator

Given that tan Ф =  1/√5

Where Tan Ф = Opposite / adjacent

We can calculate the hypotenuse by using Pythagoras theorem

Hyp² = 1² + (√5)²

Hyp² = 1 + 5

Hyp = √6

sin Ф = opp / hyp

sin Ф = 1/√6

sin²Ф = 1/6

cos Ф = adj / hyp

cosФ = √5 / √6

cos²Ф = 5/6

sin²Ф + cos²Ф =  1/6 + 5/6

sin²Ф + cos²Ф  = 6/6

sin²Ф + cos²Ф  = 1

Therefore, the identity of  sin²Ф + cos²Ф  = 1 is verified.

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Step-by-step explanation:

Monday has 6 different letters.

and we have therefore 6 positions to put letters.

so, for the first position we have 6 choices.

for the second position the 5 choices, and so on.

that makes all together

6! = 6×5×4×3×2×1 = 720

ways to arrange the letters.

if the arrangements must not begin with M, we are taking one choice away for the 1st position.

we can express that as all the ways with only 5 choices for the first position, or as the total number of possibilities minus the ones that start with M.

1.

5×5×4×3×2×1 = 600

2.

6! - 1×5! = 720 - 120 = 600

now, for the possibilities that start with M but do not end with Y.

that is the same as demanding that the second position does not have a Y.

so, the first position has only one choice, and the second position has one choice less :

1×4×4×3×2×1 = 96

We conclude that 375 portions can be sold.

We know that 500 portions have been ordered, but only 5/6 of that was delivered, so the number of delivered portions is:

p = (5/6)*500 = 416.6

Which we can round to the next whole number, 417.

Now we know that 10% of these are given to the players and staff, then the number of portions that can be sold is the 90% of 417, which is:

N = 417*(90%/100%) = 417*0.9 = 375

We conclude that 375 portions can be sold.

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The rational equation with the desired asymptotes and intercepts is given by:

[tex]f(x) = \frac{-10(x^2 - 3x - 18)}{9(x^2 - 5x + 4)}[/tex]

The vertical asymptotes are related to the roots of the  denominator, hence:

[tex]f(x) = \frac{a}{(x - 4)(x - 1)} = \frac{a}{x^2 - 5x + 4}[/tex]

The x-intercepts are related to the numerator of the function, hence:

[tex]f(x) = \frac{a(x + 3)(x - 6)}{x^2 - 5x + 4} = a\frac{x^2 - 3x - 18}{x^2 - 5x + 4}[/tex]

The y-intercept is to find a, hence, when x = 0, y = 5, thus:

-18a/4 = 5

18a = -20

a = -10/9

Hence the function is:

[tex]f(x) = \frac{-10(x^2 - 3x - 18)}{9(x^2 - 5x + 4)}[/tex]

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It can be said that the total amount of fuel that was used by Michael when he was away to his friends was 12 gallons.

The question said that the tank was full before he left to his friends. This was after he checked the gauge of the gas tank.

The question says that the required quantity needed to fill up this tank is 24 gallon. Hence if it is full, then the total gallon it had before he made this trip was 24 gallon.

Then we are told that he went ahead to check the gauge when he finished and was at home. The quantity of fuel he had at this time was 1/2 of what was there.

This would be 1/2 * 24

12

Hence he made use of 12 gallons when he was away.

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Answer:

20

Step-by-step explanation:

u add 13+7 and that gives you 20, so if you subtract 20 and 7 that gives you 13

The quartiles of the data are: 60.5,64,66

Option(b) is correct.

The quartile divides the distribution into four groups and calculates the range of values above and below the mean.

A quartile separates the dataset into four categories by dividing the data into three points: the lowest, median, and upper quartiles.

Similar to how the median divides the data in half, with 50% of the measurements falling below it and 50% falling above it, the quartile divides the data into fourths, with 25% of the measurements falling below the lower quartile, 50% falling below the median, and 75% falling below the upper quartile.

The interquartile range, a measurement of variation around the median, is calculated using quartiles.

For the given data set: 58,60,60,61,62,64,64,64,66,70,72

Median = 64

Lower quartile = Median of the lower half = 60.5

Upper quartile = Median of the upper half = 66

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The probability that the person is a man or heavy smoker is 621 / 1124.

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0. The more likely the event is to happen, the closer the probability value would be to 1. The less likely it is for the event not to happen, the closer the probability value would be to zero.

The probability that the respondent is a man or heavy smoker can be determined by adding the probability that the respondent is a man and the probability that the respondent is a heavy smoker together.

The probability that the person is a man or heavy smoker = (number of men / total number of respondents) + (number of heavy smokers / total number of respondents)

(531 / 1124) + (90 / 1124) = 621 / 1124

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Answer:

Step-by-step explanation:

You worked 16 hours and 45 minutes

5 1/2 = 5 hours and 30 minutes

6 3/4 = 6 hours and 45 minutes

4 1/2 = 4 hours and 30 minutes

Add the hour and minutes.

5 hours 30 min + 4 hours 30 min = 10 hours

10 hours + 6 hours 45 min = 16 hours and 45 minutes

The graph of the parabola can be seen in the image below.

We need to find some points on the parabola, and then draw a curve that connects them.

On the graph you already have the x-intercepts, so you already have two points.

Now let's get another point which is the vertex.

For our parabola:

[tex]y = -x^2 + 10x - 24[/tex]

The vertex is at:

[tex]x = -10/(2*-1) = 5[/tex]

Evaluating in x = 5 we get:

[tex]y = -5^2 + 10*5 - 24 = 1[/tex]

So we also have the point (5, 1), now we can just connect the points and get the parabola:

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All values of x that satisfy 2x+2/x+7 >= 0 are represented as x >= -1

The inequality expression is given as:

2x+2/x+7 >= 0

Multiply both sides by x + y

2x+2 >= 0

Subtract 2 from both sides

2x > -2

Divide both sides by 2

x >= -1

Hence, all values of x that satisfy 2x+2/x+7 >= 0 are represented as x >= -1

See attachment for the number line of x >= -1

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The equation in term of p that models the above experience is:
2p + 10 = 0.8p + 20.

Any statement that models or captures the factors of a problem where in an equal sign is present to equate two of the factors or expressions therein is called an equation.

Total cost of baking p pizzas with brick oven = A =  p(cost of one pizza) + cost of baking = p(2) + 10 (in dollars).

Total cost of  baking p pizzas with electric oven = B =  p(cost of one pizza) + cost of baking = p(0.8) + 20 (in dollars).

B = A - 1 (as using electric oven saves $1 per day, as given)

Thus, we get:

2p + 10 = 0.8p + 20

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The initial membership fee for Club A is; $2.5.

The initial membership fee for Club B is; $3.

Hence, Club A has a lower initial membership fee.

It follows from the concepts of linear graphs that the interpretation of the initial membership fee is the y-intercept of the graphs given.

This is so because, it corresponds to the total cost at a point when the number of movies watched is; 0. That is, before any movie is watched.

Consequently, the graph calibrations (including the missing Club A graph) allow the determination of the initial membership fee (y-intercept) as declared above.

Ultimately, Club A has a lower initial membership fee.

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1) Given - This is given in the question.

2) Reflexive Property of Equality - Anything is equal to itself

3) Substitution Property of Equality - Due to the given, substituting 118° for m∠1 and 62° for m∠2 will not change the equality of the equation

4) Simplify - No need to explain as they have already given this

5) Definition of Supplementary Angles - Two angles are supplementary only when the sum of their measures is 180°.

6) Converse of Same-side Interior Angles Theorem - If there is a transversal intersecting two lines and the same-side interior angles formed are supplementary, then the lines are parallel.

1) Given - It is given in the question

2) Vertical Angles Theorem - Vertical angles have the same measure, making their angles congruent

3) Transitive Property of Congruence - Since it's given that [tex]\angle1\cong\angle3[/tex] and in step 2 we showed that [tex]\angle3\cong\angle4[/tex], we can say that [tex]\angle1\cong\angle4[/tex]

4) Transitive Property of Congruence - Since we proved that [tex]\angle1\cong\angle4[/tex] and it's given that [tex]\angle4\cong\angle5[/tex], we can say that [tex]\angle1\cong\angle5[/tex]

5) Converse of Alternate Interior Angles Theorem - If a transversal intersects two lines and the measures of alternate interior angles formed are equal, then the lines are parallel.

Step-by-step explanation:

A quadratic equation is a  equation with a degree of 2. Below are the 5 ways to solve a quadratic equation.

Using the z-distribution, the margin of error for the 95% confidence interval used to estimate the population proportion is 0.0683 = 6.83%.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

For this problem, the parameters are given as follows:

[tex]n = 198, \pi = \frac{80}{198} = 0.404[/tex]

Hence the margin of error is:

[tex]M = 1.96\sqrt{\frac{0.404(0.596)}{198}} = 0.0683[/tex]

The margin of error for the 95% confidence interval used to estimate the population proportion is 0.0683 = 6.83%.

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Since L₂ is twice as long as L₁, the length of L₁ should be 12' and 6 3/4".

First of all, we would convert the value of the overall length in feet to inches as follows:

1 feet = 12 inches

37 × 8 1/4 feet = X inches

Cross-multiplying, we have:

X = 1809/4 inches.

Since L₂ is twice as long as L₁, we have:

L₂ = 2L₁

Also, the overall length is given by:

T = 2L₁ + 2L₂

T = L₂ + 2L₂

T = 3L₂

1809/4 = 3L₂

L₂ = 1809/4 × 1/3

L₂ = 1809/12

L₂ = 150.75''

L₂ = 12' and 6 3/4".

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Using proportions, the billed amount for the month of June is:

D. $42.50

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The discount will be applied only for the second half of the month, from June 16 to June 30, hence instead of a discount of 30%, it will count as a discount of 15%, meaning that 85% of the bill will be paid, hence the amount paid will be of:

A = 0.85 x $50 = $42.50.

Hence option D is correct.

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We conclude that the starting average grade is 79.17%

There are 50 students, let's say that the grades are measured between 1% and 100%.

And the average grade of the 50 students is A.

We know that after it increased by 20%, the average of the grades is 95.

Then we just need to solve the percentage equation:

95 = A*(1 + 20%/100%) = A*(1.2)

95/1.2 = A = 79.17

We conclude that the starting average grade is 79.17%

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Answer:

75%

Step-by-step explanation:

You need to do the following equation: x+20≤95 and you will have the answer. (I am sorry if it is wrong but this is what my teacher told the answer was. I put this answer and got it correct.) Hope it helped. Have a nice day.

Answer:x2−7x−8=0

Tap to view steps...

Step-by-step explanation:

El volumen que queda entre la esfera y el cubo es:  30.49cm^3

El volumen sobrante será simplemente la diferencia entre el volumen del cubo y el volumen de la esfera.

Para el cubo que tiene una arista de 4cm, el volumen es:

V = (4cm)^3 = 64 cm^3

Para la esfera con un diametro de 4cm, el radio es:

R = 4cm/2 = 2cm

Y el volumen será:

V' = (4/3)*3.141592654*(2cm)^3 = 33.51 cm^3

El volumen que queda entre la esfera y el cubo es:

V - V' = 64 cm^3 - 33.51 cm^3 = 30.49cm^3

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The value of the function g(x) = x -3/2x + 1 for x = -1 is g(-1) = 4

The function is given as:

g(x) = x -3/2x + 1

The value is given as:

x = -1

Substitute the known values in the above equation

i.e. we substitute the -1 for x in the above equation

So, we have:

g(-1) = -1 -3/2(-1) + 1

Expand the bracket

g(-1) = -1 -3/-2 + 1

Evaluate the sum and the difference

g(-1) = -4/-1

Evaluate the quotient

g(-1) = 4

Hence, the value of the function g(x) = x -3/2x + 1 for x = -1 is g(-1) = 4

So, the complete parameters are:

g(x) = x -3/2x + 1

x = -1

g(-1) = 4

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Compute the first two derivative.

[tex]f(x) = x \sqrt{16 - x^2} = x (16 - x^2)^{1/2}[/tex]

[tex]f'(x) = x \dfrac{d}{dx} (16 - x^2)^{1/2} + (16 - x^2)^{1/2} \dfrac{d}{dx} x \\\\ ~~~~ = \dfrac x2 (16 - x^2)^{-1/2} \dfrac{d}{dx} (16-x^2) + (16 - x^2)^{1/2} \\\\ ~~~~ = \dfrac x2 (16 - x^2)^{-1/2} (-2x) + (16 - x^2)^{1/2} \\\\ ~~~~ = (16-x^2)^{-1/2} \left(-x^2 + (16 - x^2)\right) \\\\ ~~~~ = \dfrac{16 - 2x^2}{(16 - x^2)^{1/2}}[/tex]

[tex]f''(x) = \dfrac{(16-x^2)^{1/2} \frac d{dx} (16-2x^2) - (16-2x^2) \frac{d}{dx} (16-x^2)^{1/2}}{\left((16-x^2)^{1/2}\right)^2} \\\\ ~~~~ = \dfrac{(16-x^2)^{1/2} (-4x) - (8-x^2) (16 - x^2)^{-1/2} \frac{d}{dx} (16-x^2)}{16 - x^2} \\\\ ~~~~ = \dfrac{-4x (16-x^2) - (8-x^2) (-2x)}{(16 - x^2)^{3/2}} \\\\ ~~~~ = \dfrac{2x^3-48x}{(16 - x^2)^{3/2}}[/tex]

Take note of the domain of [tex]f(x)[/tex]. We must have [tex]16-x^2\ge0[/tex] for the square root to be defined, so

[tex]16 - x^2 \ge 0 \implies x^2 \le 16 \implies |x| \le 4[/tex]

and [tex]f(x)[/tex] exists only for [tex]-4 \le x \le 4[/tex].

Intercepts

Set [tex]x=0[/tex] to find the [tex]y[/tex]-intercepts. The only one is (0, 0), since

[tex]f(0) = 0 \sqrt{16-0^2} = 0[/tex]

The first intercept you listed is not a valid intercept. One or both coordinates must be 0.

Set [tex]f(x)=0[/tex] and solve for [tex]x[/tex] to find [tex]x[/tex]-intercepts. We already found (0, 0); there are two others at (-4, 0) and (4, 0).

[tex]f(x) = x \sqrt{16 - x^2} = 0 \\\\ x = 0 \text{ or } \sqrt{16 - x^2} = 0 \\\\ x = 0 \text{ or } 16 - x^2 = 0 \\\\ x = 0 \text{ or } x^2 = 16 \\\\ x = 0 \text{ or } x = \pm4[/tex]

The instructions say to list these in order from smallest to largest by [tex]x[/tex]-coordinate first, then by [tex]y[/tex]-coordinate. So the proper order of the intercepts would be (-4, 0), (0, 0), and (4, 0).

Relative minima/maxima

Find the critical points. We have [tex]f'(x) = 0[/tex] when

[tex]f'(x) = \dfrac{16 - 2x^2}{(16 - x^2)^{1/2}} = 0 \\\\ 16 - 2x^2 = 0 \\\\ x^2 = 8 \\\\ x = \pm2\sqrt2 \approx \pm 2.83[/tex]

and [tex]f'(x)[/tex] is undefined when

[tex](16 - x^2)^{1/2} = 0 \\\\ 16 - x^2 = 0 \\\\ x^2 = 16 \\\\ x = \pm4[/tex]

Check the sign of the second derivative at the first two critical points.

[tex]f''(-2\sqrt2) = 4 > 0 \implies \text{rel. min. at }  f(-2\sqrt2) = -8[/tex]

[tex]f''(2\sqrt2) = -4 < 0 \implies \text{rel. max. at } f(2\sqrt2) = 8[/tex]

For posterity, we should also check the value of [tex]f(x)[/tex] at the endpoints of the domain.

[tex]f(-4) = f(4) = 0[/tex]

So [tex]f(x)[/tex] has a relative minimum at (-2.83, -8) and a relative maximum at (2.83, 8).

Inflection points

We have [tex]f''(x) = 0[/tex] for

[tex]f''(x) = \dfrac{2x^3-48x}{(16 - x^2)^{3/2}} = 0 \\\\ 2x^3 - 48x = 0 \\\\ 2x (x^2 - 24) = 0 \\\\ 2x = 0 \text{ or } x^2 - 24 = 0 \\\\ x = 0 \text{ or } x = \pm2\sqrt6\approx\pm4.90[/tex]

The two non-zero solutions fall outside the domain, so the only inflection point is (0, 0).

a = amount invested at 5%

b = amount invested at 2%

now, we know the total invested by Mr Wilson was 20000, so whatever "a" and "b" might be, we know that a + b = 20000.

[tex]a + b = 20000\implies b = 20000-a \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{5\% of a}}{\left( \cfrac{5}{100} \right)a}\implies 0.05a~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)a}\implies \begin{array}{llll} 0.02b\\\\ \stackrel{substituting}{0.02(20000-a)} \end{array}[/tex]

now, we know the total of earned interest is 550 bucks, so then

[tex]0.05a~~ + ~~0.02(20000-a)~~ = ~~550\implies 0.05a+400-0.02a=550 \\\\\\ 0.03a+400=550\implies 0.03a=150\implies a=\cfrac{150}{0.03}\implies a=5000 \\\\\\ ~\hspace{24em}\stackrel{20000~~ - ~~5000}{b=15000}[/tex]

The amount add to the borrower's monthly payment is $313.33.

Given that lender requires PMI that is 0.8% of the loan amount of $470,000.

A loan's PMI, or personal mortgage insurance, is a type of mortgage insurance used by lenders when making traditional loans such as home loans. A PMI helps cover the loss to the lender (bank) if the borrower stops making monthly mortgage payments on their home loan. Therefore, the PMI can be described as a kind of risk mitigation tool for the bank when the borrower defaults on their EMIs (monthly mortgage payments). So, PMI for a borrower is an additional cost or payment for the borrower on top of his monthly payments i.e. EMI.

Thus, the additional amount of dollars that the borrower has to pay for the PMI on his loan along with his monthly mortgage payments

= Principal Loan amount × (PMI/12)

= $470,000 × (0.8%/12)

= $470,000 × (0.008/12)

= $470,000 × 0.0006666667

=$313.333349

Hence, the additional monthly payment for PMI where lender requires PMI that is 0.8% of the loan amount of $470,000 is $313.33.

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If the patio is as wide as the fire pit, and 5 feet long then area of backyard can be expressed as [tex]2x^{2}+16x+30[/tex].

Given that the patio is as wide as the fire pit, and 5 feet long.

We are required to form an equation which can describe the area of the backyard.

Equation is relationship between two or more variables that are expressed in equal to form. Equations of two variables look like ax+by=c. It may be linear equation, quadratic equation, cubic equation or many more depending on the powers of the variable.

If we see the figure carefully then we can find that the length of the backyard is 2x+6 and the breadth of the backyard is 5+x and backyard is in shape of rectangle.

Area of rectangle =Length *breadth

=(2x+6)*(5+x)

=30+10x+6x+2[tex]x^{2}[/tex].

Hence if the patio is as wide as the fire pit, and 5 feet long then area of backyard can be expressed as [tex]2x^{2}+16x+30[/tex].

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