Sn^2+ + Br2 ---> Sn^4+ + 2Br^- is referred to as a non-spontaneous redox reaction.
What is a Non spontaneous reaction?This type of reaction doesn't favor the formation of the product and must be endothermic.
In the reaction above under the given conditions, ΔG is positive and it is intended to form Sn(s) and Br(l) through the reduction of tin cation to make bromine liquid and tin solid. This therefore points to the direction of the reaction being non-spontaneous one.
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Find the number of moles of the following substances 210 grams of NaHCO3
The number of moles of 210 grams of NaHCO₃ is 2.5 moles.
How to find the Number of moles ?To calculate the number of moles use the formula
Number of moles = [tex]\frac{\text{Given Mass}}{\text{Molar Mass}}[/tex]
Mass of NaHCO₃ = 210 g
Now we have to find the Molar mass of NaHCO₃
= Atomic mass of Na + Atomic mass of H + Atomic mass of C + 3 (Atomic mass of O)
= 23 + 1 + 12 + 3 (16)
= 36 + 48
= 84 g/mol
Now put the value in above formula we get
Number of moles = [tex]\frac{\text{Given Mass}}{\text{Molar Mass}}[/tex]
= [tex]\frac{210\ g}{84\ g/mol}[/tex]
= 2.5 moles
Thus from the above conclusion we can say that The number of moles of 210 grams of NaHCO₃ is 2.5 moles.
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Which of the following aqueous solutions are good buffer systems?
(Select all that apply.)
a. 0.22 M acetic acid + 0.15 M potassium acetate
b. 0.27 M nitric acid + 0.16 M potassium nitrate
c. 0.29 M ammonium nitrate + 0.32 M ammonia
d. 0.20 M calcium hydroxide + 0.23 M calcium chloride
e. 0.31 M hydrofluoric acid + 0.22 M potassium fluoride
The following aqueous solutions represents good buffer systems:
0.22 M acetic acid + 0.15 M potassium acetate0.29 M ammonium nitrate + 0.32 M ammonia What is a buffer?A buffer is a solution used to stabilize the pH (acidity) of a liquid.
A good buffer system is generally known to contain close or equal concentrations of a weak acid and its conjugate base.
Based on the above explanation, the following represents a good buffer system as they are between their weak acid and conjugate base:
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what is mb for CH3NH2….
Answer:
A.) [tex]K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}[/tex]
Explanation:
The general Kb expression is:
[tex]K_b = \frac{[HA][OH^-]}{[A^-]}[/tex]
In this equation
-----> Kb = equilibrium constant
-----> [HA] = acid
-----> [A⁻] = base
Since liquids are not included in equilibrium expressions, H₂O should not be present. The products are in the numerator while the reactant are in the denominator. In this reaction, CH₃NH₂ is acting as a base and CH₃NH₃⁺ is acting as an acid.
As such, the expression is:
[tex]K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}[/tex]
How many moles of Hydrogen gas will be produced if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid given the following balanced chemical reaction:
Mg + 2HCl → MgCl2 + H2
Group of answer choices
A. 1.25 moles
B. 5.0 Moles
C. 7.5 moles
D. 2.5 moles
Answer:
D.) 2.5 moles
Explanation:
To find the moles of H₂, you need to multiply the given value by the mole-to-mole ratio. This ratio consists of the coefficients in front of the relevant molecules. It is important to arrange the ratio in a way that allows for the cancellation of units.
1 Mg + 2 HCl -----> MgCl₂ + 1 H₂
^ ^
2.5 moles Mg 1 moles H₂
----------------------- x --------------------- = 2.5 moles H₂
1 mole Mg
round off each of the following numbers to two significant figure 0.436 and 9.000
Answer:
0.436 ⇒ 0.44
9.000 ⇒ 9.0
Concept:
Significant figures are where each of the digits of a number are used to express it to the required degree of accuracy, starting from the first nonzero digit.
Therefore, in the context of this question, two significant figure means that two digits of numbers are kept, from left to right, starting from the first nonzero digit.
Solve:
PART I: Rounding 0.4360.436 has 3 significant digits in total starting from left to right
Thus, the last digit should be rounded up / down
Since the last digit is 6, it is greater than 5, so it should be rounded up.
Therefore, a rounded 0.436 is [tex]\Large\boxed{0.44}[/tex]
PART II: Rounding 9.0009.000 has 4 significant digits in total starting from left to right
Thus, the last two digits should be rounded up / down
Since the last two digits are 0, it is less than 5, so it should be rounded up (or remained).
Therefore, a rounded 9.000 is [tex]\Large\boxed{9.0}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
A sample of nitrogen gas has a volume of 3.0 L at 25 degrees Celsius and 720 torr. What would the volume be at STP? (Hint: This is a combined gas law question).
Answer:
2.60 L
Explanation:
To find the new volume, you need to use the Combined Gas Law:
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure. volume, and temperature.
At STP, the pressure is 1.0 atm and the temperature is 273 K. Before you can plug the values into the equation, you need to convert pressure from torr to atm and the temperature from Celsius to Kelvin.
P₁ = 720 torr / 760 = 0.947 atm P₂ = 1.0 atm
V₁ = 3.0 L V₂ = ? L
T₁ = 25 °C + 273 = 298 K T₂ = 273 K
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex] <----- Combined Gas Law
[tex]\frac{(0.947atm)(3.0L)}{298K}=\frac{(1.0atm)V_2}{273K}[/tex] <----- Insert values
[tex]\frac{2.84}{298K}=\frac{(1.0atm)V_2}{273K}[/tex] <----- Multiply 0.947 and 3.0
[tex]0.00954=\frac{(1.0atm)V_2}{273K}[/tex] <----- Simplify left side
[tex]2.60={(1.0atm)V_2}[/tex] <----- Multiply both sides by 273
[tex]2.60L=V_2[/tex] <----- Divide both sides by 1.0
<
A 83.5 g sample of a nonelectrolyte is dissolved in 291.7 g of water.
The solution is determined to have a boiling point of 102.3 °C. What is
the molar mass of the compound? (Kb for water is 0.510 °C/m).
The molar mass of the compound is = 1.42g/ mol
Calculation of compound molar mass∆Tb = kB × molarity
∆Tb = 102.3°C
Kb = 0.510 °C/m
Molarity= electrolyte mass × water solubility/ Mw× mass of water.
That is,
102.3°C= 0.51× 83.5×1000/Mw × 291.7
Make Mw the subject of formula,
Therefore,
Mw = 0.51 × 83.5×1000/ 102.3 × 291.7
Mw= 42,585/29,840.91
Mw= 1.42g/mol
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How many grams of water will be produced if you start with 4.0 grams of hydrogen and an excess of oxygen given the following balanced chemical equation?
2H2 + O2 → 2H2O
Group of answer choices
A. 32.0 grams
B. 36.0 grams
C. 54.0 grams
D. 18.0 grams
Answer:
B.) 36.0 grams
Explanation:
To find the mass of water, you need to (1) convert grams H₂ to moles (using the molar mass), then (2) convert moles H₂ to moles H₂O (using mole-to-mole ratio from reaction coefficients), and then (3) convert moles H₂O to grams (using the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units.
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
2 H₂ + O₂ -----> 2 H₂O
^ ^
4.0 g H₂ 1 mole 2 moles H₂O 18.014 g
--------------- x ---------------- x ------------------------ x --------------- = 36 g H₂O
2.016 g 2 moles H₂ 1 mole
If a reactant is oxidized another reactant must be
Group of answer choices
A. oxidized
B. consumed
C. reacted
D. reduced
If a reactant is oxidized, another reactant must be reduced (option D).
What is redox reaction?Redox reaction also known as oxidation-reduction reaction relates to any reaction in which oxidation and reduction occur simultaneously.
This means that in a redox reaction, electrons are lost and gained at the same time.
The substance that loses electrons in a redox reaction is called reducing agent while the substance that gains electrons in a redox reaction is called oxidizing agent.
Therefore, if a reactant is oxidized, another reactant must be reduced.
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What is the [OH-] if the [H3O+] is 1 x 10 -10?
The answer is [OH⁻] = 1 x 10⁻⁴.
[OH⁻] = H₂O ÷ [H₃O⁺]
[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻¹⁰
[OH⁻] = 10⁻⁴
What is the identity of a metal that has a mass of 27.0 g and a volume of 10.0 cm3?
Group of answer choices
A. Gold
B. Aluminum
C. Lead
D. Copper
The identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium. That is option B.
What is molar mass?Molar mass is defined as the mass in grams of one mole of an element. This is measured in grams/mole of that substance.
The metal that is 27.0 g and a volume of 10.0 cm3 is aluminium because aluminium is 27 times heavier than 1/12th of the mass of carbon-12 atom.
Therefore, the identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium.
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Question 5 categorizing things involves assigning items to categories. identifying themes takes those categories a step further, grouping them into broader themes or classifications.
This exercise is related to the subject of Structured Thinking. See the definition of structured thinking below.
What is structured thinking?The process of developing a structured framework to address an unstructured situation is known as structured thinking.
Structured thinking is a strategy of problem-solving that entails breaking a huge problem into smaller ones in order to tackle the larger problem more quickly and effectively.
Categorizing things and identifying themes are two subjects under structured thinking.
What does Categorizing things involve?To categorize anything requires:
putting things into categoriesgiving goods a grade.identifying the differences between things.What does Identifying themes involve?Identifying themes entails:
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What is the coefficient and the formula 3Zn(NO3)2 represent ?
Nitrogen atoms:
I thought it was 8 but it’s wrong
The answer is 6 nitrogen atoms.
The given chemical formula is : 3Zn(NO₃)₂
Let's find the number of nitrogen atoms by opening the bracket.
3ZnN₂O₆Zn₃N₆O₁₈Hence, there are 6 nitrogen atoms.
Draw clearly the structural formulas of the given compounds. (a) 3-methyl heptane
See the attached image.
help me please with this question as soon as possible
0.5376 g is the minimum mass of sodium sulfite that we should add.
What is Molarity ?Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I unit of Molarity is molar (M) or mol/L.
The conversion sequence is
mL solution → L solution → mol → g
[tex]80\ mL \times \frac{1\ L}{1000\ mL} \times \frac{0.04\ \text{mol Calcium nitrate solution}}{L} \times \frac{168\ \text{Calcium nitrate solution}}{\text{mol Calcium nitrate solution}}[/tex]
= 0.5376 g
Thus from the above conclusion we can say that 0.5376 g is the minimum mass of sodium sulfite that we should add.
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How many atoms in 56.4 g of platinum (Pt)
56.4 g of platinum will contain 1.7417 x [tex]10^{23}[/tex] atoms
Number of atoms in substancesAccording to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^{23}[/tex] atoms of the substance.
The problem is we don't know how many moles of platinum that are present in 56.4 g. Thus, the first thing is to calculate the number of moles of platinum present in 56.4 g of the substance.
This can be achieved by using the formula, mole = mass/molar mass. Keep in mind that the molar weight of platinum is 195 g/mol.
Therefore,
Mole of 56.4 g of platinum = 56.4/195 = 0.2892 moles
If,
1 mole of any substance = 6.022 x [tex]10^{23}[/tex] atoms
Then,
0.2892 moles of platinum = 0.2892 x 6.022 x [tex]10^{23}[/tex] atoms = 1.7417 x [tex]10^{23}[/tex] atoms
In other words, 56.4 g of platinum will contain 1.7417 x [tex]10^{23}[/tex] atoms 1.7417 x [tex]10^{23}[/tex] atoms of the metal.
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Which pair shares the same empirical formula? (4 points)
C2H4 and C6H6
C6H6 and C3H3
CH2 and C6H6
CH and C2H4
Considering the definition of empirical and molecular formula, the pair C₆H₆ and C₃H₃ shares the same empirical formula.
Empirical formulaThe empirical formula is the simplest expression to represent a chemical compound, and indicates the elements that are present and the minimum proportion in whole numbers between its atoms. This formula is also known as the “minimum formula”.
That is, the empirical formula is the expression of the simplest ratio between the atoms of a chemical compound and indicates the different elements that make up the molecule and the relationship between them. But it does not indicate the actual formula of the compound.
Molecular formulaThe molecular formula is the actual formula of the molecule, it tells us the types of atoms and the number of each type that participate in the formation of the molecule.
Same empirical formula in this caseIn this case, the pair C₆H₆ and C₃H₃ shares the same empirical formula. In the first case, the ratio of carbon atoms to hydrogen atoms is 6:6 or 1:1, while in the second case said ratio is 3:3 or 1:1. Therefore, the relationship is the same, so they have the same empirical formula.
In summary, the pair C₆H₆ and C₃H₃ shares the same empirical formula.
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a reaction is 50% complete in 2 hours and 75% complete in 4 hours.
what is the order of this reaction ?
Answer:
the half life of reaction is 2 hours which is consist half life of consist in the first order reaction has the order reaction is one
can you help with this please?
Answer:
A.) 2,4,5-trimethylhexan-2-ol
B.) 6-bromo-3-ethylhexan-2-one
C.) 3-isoproyl-4-propyloctan-1-al
Explanation:
A.) Since there is an alcohol (-OH) group in the molecule, the name should have the ending -ol. Since the alcohol is on the 2nd carbon, there should be a 2 in front of the -ol. The longest carbon chain contains 6 single-bonded carbons, making this a hexane. There are 3 methyl (-CH₃) groups on the 2nd, 4th, and 5th carbons.
Therefore, the IUPAC name is: 2,4,5-trimethylhexan-2-ol
B.) Since there is a ketone (C=O) group in the molecule, the name should have the ending -one. Since the ketone takes priority, it is on the 2nd carbon. As such, there should be a 2 in front of the -one. The longest carbon chain contains 6 single-bonded carbons, making this a hexane. There is an ethyl (-CH₂CH₃) group on the 3rd carbon and a bromo (-Br) group on the 6th carbon.
Therefore, the IUPAC name is: 6-bromo-3-ethylhexan-2-one
C.) Since there is an aldehyde (HC=O) group in the molecule, the name should have the ending -al. Since the aldehyde is on the 1st carbon, you can add a 1 before the -al (technically not necessary). The longest carbon chain contains 8 single-bonded carbons, making this an octane. There is an isopropyl (-CHCH₃CH₃) group on the 3rd carbon and a propyl (-CH₂CH₂CH₃) on the 4th carbon.
Therefore, the IUPAC name is: 3-isoproyl-4-propyloctan-1-al (or 3-isoproyl-4-propyloctanal)
environmental conditions of the ocean
The environmental conditions of the ocean are:
Light availabilityOxygen levelsWater movementSalinityDensity and pH.What are the environmental impacts on the ocean?In our oceans, there are known to be a lot of environmental conditions that are known to often affect the growth, survival and also the productivity of marine organisms. These are the ones listed above.
Note that the increased concentration of chemicals, e.g. nitrogen and phosphorus is one that can be harmful to marine life.
Hence, The environmental conditions of the ocean are:
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given the a+b=c what is the reaction given
The generic reaction a + b = c, represents a synthesis or combination reaction, which is a kind of chemical reaction.
What is a synthesis reaction?A synthesis, or combination reaction, is a kind of reaction in which two substances combine to form a bigger molecule.
The generic reaction is:
a + b = c
Some common synthesis reactions are:
Two elements combine to form a compound.Fe + S = FeS
One element and one compound combine to form a compound.O₂ + 2 SO₂ = 2 SO₃
Two compounds combine to form another compound.CaO + CO₂ = CaCO₃
In all the examples above, we can verify that the substances (elements or compounds) combine with each other to form another substance (product).
The generic reaction a + b = c, represents a synthesis or combination reaction, which is a kind of chemical reaction.
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A student who prefers to study by recalling personal examples that connect to what is being learned, makes lists of ways to use skills in
real scenarios (like at work), and starts a discussion with another student to talk about a topic most likely prefers which learning style?
Oa. Visual
O b. Auditory
O c. Reading Writing
Od. Kinesthetic
B. A student who prefers to study by recalling personal examples that connect to what is being learned, makes lists of ways to use skills in real scenarios (like at work), and starts a discussion with another student to talk about a topic most likely prefers Auditory.
What is Auditory learning style?
Auditory learning style is a method of learning that involves listening.
Auditory learning means that a student learns most effectively by listening.
In Auditory learning style, students would prefer listening to a lecture over reading a textbook, or hearing the instructions for a project instead of figuring it out hands-on.
Thus, a student who prefers to study by recalling personal examples that connect to what is being learned, makes lists of ways to use skills in real scenarios (like at work), and starts a discussion with another student to talk about a topic most likely prefers Auditory.
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The combustion of 296 g of propane (C₃H₈) produces 713 g of carbon dioxide. [C₃H₈ + 5O₂ --> 3CO₂ + 4H₂O; C = 12.01 g/mol, H = 1.01 g/mol, O = 16.0 g/mol]
What is the percent yield?
80.5%
124%
0.805%
41.50%
Answer:
80.5%
Explanation:
The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.
To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
(Steps 1 - 3)
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)
Molar Mass (C₃H₈): 44.11 g/mol
Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)
Molar Mass (CO₂): 44.01 g/mol
1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
296 g C₃H₈ 1 mole 3 moles CO₂ 44.01 g
------------------- x ---------------- x ---------------------- x ---------------- = 886 g CO₂
44.11 g 1 mole C₃H₈ 1 mole
(Step 4)
Actual Yield
Percent Yield = ------------------------------ x 100%
Theoretical Yield
713 g CO₂
Percent Yield = ---------------------- x 100%
886 g CO₂
Percent Yield = 80.5%
If an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom what wavelength of light is emitted?
Group of answer choices
A. 122 nm
B. 1024 nm
C. 97 nm
D. 103 nm
The wavelength is obtained as 122 nm. Option A
What is the wavelength?We know that from the Bohr model of the atom, an electron can move from a higher energy level to a lower energy level or from a lower energy level to a higher energy level. This is the idea of energy quantization as put forward by Neill Bohr.
The wavelength can be obtained by the use of the formula;
1/λ = RH(1/n^2initial - 1/n^2 final)
λ = wavelength of the emitted light
RH = Rydberg's constant
n intial = initial energy level
nfinal = final energy level
Thus;
1/λ = 1.09 * 10^7(1/1^2 - 1/2^2)
1/λ = 1.09 * 10^7( 1 - 0.25)
λ = 122 nm
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=> The approximate mss of an electron is 1/10²⁷ g , Calculate the uncertainty in its velocity if the uncertainty in its position were of the order of 1/10¹¹ m ( h = 6.6 × 1/10³⁴ kg m² per sec ) ..
Answer:
Δx(m.Δv)=h/4π
here ,
Δv = uncertainty in velocity
10−11×10−27×Δv=6.626×10−34/4×22/7
=5.25×103ms−1
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
According to Heisenberg's uncertainty principle :
[tex]\qquad \sf \dashrightarrow \: \Delta x \Delta p \geqslant \cfrac{h}{4 \pi} [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta x \cdot m \Delta v \geqslant \cfrac{h}{4 \pi}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{h}{4 \pi \cdot m \Delta x}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 \times 10 {}^{ - 34} }{4 \pi \cdot 10 {}^{ - 27} \times 10 {}^{ - 3} \times 10 {}^{ - 11} }[/tex]
[tex] \textsf{ [ we took } [/tex][tex]{ {10}^{-3} } [/tex][tex] \textsf{because mass of electron is} [/tex][tex] \textsf{ given in grams that need to be converted into kg ]} [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \pi } \times \cfrac{10 {}^{ - 34} } {10 {}^{ (- 27 - 3 - 11)} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times \cfrac{10 {}^{ - 34} } {10 {}^{ - 41} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{12.56 } \times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant0.525\times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant5.25\times {10 {}^{ 6}} \:\:m/s[/tex]
complete the following table and calculate the decrease in the freezing point of water when 1 mol glycerol (CH3OH-CHOH-CH2OH), NaCI or Na2CO3 is dissolved in 1.00 kg of water
The decrease in the freezing point of the solution is −1.86oC.
What is the decrease in the freezing point?Now we know that the freezing point depression of a solid is a colligative property of the solution.
Thus we have that;
ΔT = K m i
ΔT = freezing point depression
K = freezing constant
m = molality of the solution
i = Van't Hoff factor
Thus;
molality = 1 mol/1 Kg = 1 m
ΔT = −1.86oC/m * 1 m * 1
ΔT =−1.86oC
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What is one thing people can do to reduce the amount of carbon in the
atmosphere?
A. Drive longer distances.
B. Plant more trees.
C. Burn more fossil fuels.
D. Use more electricity.
Answer:
B
Explanation:
Planting trees sequesters CO2
all of the other choices produce more CO2 in the atmosphere
will BeCO3 Hydrolyze in aqueous medium?. If so how?... very urgent..
Answer:
BeCO3 will hydrolyze in an aqueous medium, yielding a basic solution.
Explanation:
In accord with the rules of salt hydrolysis, the cation [tex]Be^{2+}[/tex] can hydrolyze. The anion [tex]CO_{3} ^{2-}[/tex] can also hydrolyze, given that the resulting conjugate acid is weak.
Given that both ions hydrolyze, the Ka (acid ionization constant) and Kb (Base ionization constant) of each reactant (or product [that is, the conjugate acid and base for each ion]) must be compared.
Using the web (hopefully some sort of reference table has been provided to you):
Ka (for Be^2+) = [tex]3 * 10^{-7}[/tex]
Kb (for CO3^2-) = [tex]\frac{Kw (water)}{Ka (HCO3)}[/tex]
= [tex]\frac{1*10^{-14}}{4.7*10^{-11}}[/tex]
= [tex]2.1 * 10^{-4}[/tex]
The Kb > Ka, so the solution will be basic.
Hope this helps! My apologies if this answer is incorrect, I have not done this type of problem in a while.
How many grams of chromium(II) nitrate, , must be dissolved to prepare 500. mL of a 0.188 M aqueous solution of the salt?
22.37 g of chromium(II) nitrate, must be dissolved to prepare 500. mL of a 0.188 M aqueous solution of the salt.
According to the definition, the molar concentration of a substance in a solution is the ratio of the number of the moles to the volume of the solution:
c=n/V.
The number of the moles is related to the mass with the molar mass:
n=m/M;
m=n·M.
Thus, given the volume of the solution of chromium(II) nitrate, its concentration and molar mass is 238.011 g/mol we can calculate the mass of chromium(II) nitrate needed for the preparation :
∴ Cr(NO₃)₃ = cVM
= 0.188 M × 0.5 L × 238.011 g/mol
= 22.37 g
Therefore, 22.37 g of chromium(II) nitrate, must be dissolved to prepare 500. mL of a 0.188 M aqueous solution of the salt.
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100.0 mL of a 0.695 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution?
Answer:
0.116 M
Explanation:
(Step 1)
Calculate the amount of moles using the molarity ratio.
100.0 mL / 1,000 = 0.1000 L
Molarity = moles / volume
0.695 M = moles / 0.1000 L
0.0695 = moles
(Step 2)
Calculate the new molarity using the moles and new volume.
500.0 mL / 1,000 = 0.5000 L
Molarity = moles / volume
Molarity = 0.0695 moles / (0.1000 L + 0.5000 L)
Molarity = 0.0695 moles / (0.6000 L)
Molarity = 0.116 M