Taking into account the definition of dilution, moles of solute (option C) is the only thing about the solution that does NOT change.
DilutionWhen it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeSummaryIn summary, moles of solute (option C) is the only thing about the solution that does NOT change.
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Consider this reaction: 6 CO2 + 6 H2O + light equation C6H12O6 + 6 O2 If there were 2.38 x 102 g of H2O, 18.6 moles of CO2, and plenty of light, which reactant would be the limiting reactant?
H₂O would be the limiting reactant.
Balanced chemical equation:
6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂
The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).
Given
No. of moles of CO₂ = 18.6
Mass of H₂O = 2.38 × 10² g = 238g
No. of moles of H₂O = Given mass/ Molar mass
= 238 / 18 = 13.22 moles
Moles of H₂O = 13.22
According to the balanced chemical equation
6 moles of CO₂ react with 6 moles of H₂O
So the reactant that has less number of moles will be consumed first.
As the No. of moles of H₂O < No. of moles of CO₂
So, H₂O is the limiting reactant with 13.22 moles.
Hence, H₂O would be the limiting reactant.
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What volume, in liters, of 0.023 M NH4NO3 solution can be made using 25 g NH4NO3
The molar mass of NH4NO3 is 80.043 g/mol
Answer:
14 L
Explanation:
To find the volume, you need to (1) convert grams to moles (via molar mass) and then (2) calculate the volume (via molarity equation). The final answer should have 2 sig figs to match the sig figs of the given values.
(Step 1)
Molar Mass (NH₄NO₃): 80.043 g/mol
25 grams NH₄NO₃ 1 mole
------------------------------- x ------------------------- = 0.312 moles NH₄NO₃
80.043 grams
(Step 2)
Molarity = moles / volume
0.023 M = 0.312 moles / volume <----- Insert values
(0.023 M) x volume = 0.312 moles <----- Multiply both sides by volume
volume = 14 L <----- Divide both sides by 0.023
Volume, in liters, of 0.023 M NH₄NO₃ solution can be made using 25 g NH₄NO₃ are 13.47L.
What is Molarity?Molarity of a given solution is known as the total number of moles of solute per litre of the solution. A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.
Molarity = (No. of moles of solute ÷ Volume of solution in liters)
The unit of molarity is mol L⁻¹.
Molarity is temperature dependent because as temperature changes, volume of the solution also changes.
No. of moles of solute = Mass / Molar mass
No. of moles of solute = 0.31
Hence,
Volume of solution in liters = No. of moles of solute ÷ molarity
= 13.47 litres
Therefore, Volume, in liters, of 0.023 M NH₄NO₃ solution can be made using 25 g NH₄NO₃ are 13.47L.
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Given similar concentrations, the stronger acid corresponds to the lower pH. Comment on the relative strengths of the acids H3PO4, H2PO4^– and H2PO4^2–
Answer:
H3PO4 is stronger than H2PO4- because
H3PO4 dissociation constant is 6.9×10^-3
H2PO4^- dissociation constant is 6.2×10^-8
The volume of a gas at 0 degrees Celsius is 100 L. If the volume of the gas is increased to 200 L at a constant temperature, what is the new temperature of the gas in Kelvin?
The new temperature of the gas in Kelvin, given the data from the question is 273 °C
Data obtained from the questionFrom the question given above, the following data were obtained:
Initial volume (V₁) = 100 LInitial temperature (T₁) = 0 °C = 0 + 273 = 273 KPressure = ConstantNew volume (V₂) = 200 LNew temperature (T₂) =? How to determine the new temperatureThe new temperature of the gas can be obtained by using the Charles' law equation as illustrated below:
V₁ / T₁ = V₂ / T₂
100 / 273 = 200 / T₂
Cross multiply
100 × T₂ = 273 × 200
Divide both side by 100
T₂ = (273 × 200) / 100
T₂ = 546 K
Subtract 273 to obtain answer in °C
T₂ = 546 – 273 K
T₂ = 273 °C
Thus, new temperature of the gas is 273 °C
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What is the oxidation number of nitrogen in nitrogen gas?
Group of answer choices
A. -2
B. -1
C. -3
D. 0
HELP NOW pls will give points due soon
Sorry for the sloppy writing I tried my best.
If you can't read the words in my photo it says
Evaporation
condensation precipitation and runoff
definition of these words
evaporation: The process of turning liquid into vapor
Condensation:water which collects as droplets on a cold surface when humid air is in contact with
Precipitation: the action or process of precipitating a substance from a solution
runoff: liquid, especially water or rainwater, that flows off or drains away
I hope this is helpful
Sincerely- Your Brainly Bestfriend
Consider the following reaction at 298K.
I2 (s) + H2 (g) 2 I- (aq) + 2 H+ (aq)
Which of the following statements are correct?
From the forgoing, we can conclude that the the correct statements are;
n = 2 mol of electronsK < 1What are the redox reaction?The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;
E°cell = 0.0592/n log K
E°cell = cell potential
n = number of electrons
K = equilibrium constant
E°cell = -0.403 - 0.535 = -0.938 V
n = 2 electrons
Thus;
-0.938 = 0.0592/2 logK
-0.938 * 2/ 0.0592 = log K
K = 2 * 10^-31
Also;
ΔG = - nFE°cell
ΔG = - (2 * 96500 * -0.938)
ΔG = 181kJ/mol
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In the reaction between CO and Fe3O4 , the theoretical yield in an experiment is calculated to be 47.2 g Fe.
When a chemistry student carries out the experiment, their actual yield is 34.1 g Fe.
Calculate the percent yield (% yield) of Fe
Answer:
Explanation:
34.1 / 47.2 x 100% = 0.07%
The percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.
How to calculate percent yield?The percent yield is the percent ratio of the weight of the product obtained to the theoretical yield.
The percent yield can be calculated by dividing the experimental yield by the theoretical yield and multiplying the result by 100 then express the final answer in %.
According to this question, the experimental yield is 34.1g and the theoretical yield is 47.2g. The percent yield can be calculated as follows:
Percent yield = 34.1/47.2 × 100
Percent yield = 72.25%
Therefore, the percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.
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If the value for ΔS is postive, and the value for ΔH is negative, thr reaction will be
Group of answer choices
A. spontaneous at high temperatures.
B. spontaneous at all temperatures.
C. spontaneous at low temperatures.
D. Δnot spontaneous at all temperatures.
It follows that the reaction is spontaneous at high temperatures Option A.
What is ΔS ?The term ΔS is referred to as the change in the entropy of the system. Now recall that entropy is defined as the degree of disorderliness in a system. If a system is highly disorderly then it means that it has a high entropy. Also, ΔH has to do with the heat change that accompanies a reaction.
We know that both the entropy and the heat change can both either be positive or negative. Now we know that the equation ΔG = ΔH - TΔS can be used to ascertain whether or not a reaction will be spontaneous. If the result is negative, then the reaction will be spontaneous.
As such, when then it follows that the reaction is spontaneous at high temperatures Option A.
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Oliver and Mike put some ice into a container and heat it .
Answer:
See below
Explanation:
From the graph: initial temp = -10 ° C
melting occurs at 0 ° C (constant temp process)
at '2' the ice is melting.....going from a solid to a liquid at a constant temperature
Which Inorganic Substance has a melting point of -101°C and a boiling point of -35°C?
Group of answer choices
A. Chlorine
B. Hydrogen
C. Hydrogen Sulfide
D. Hydrogen Chloride
The inorganic substance that has a melting point of -101°C and a boiling point of -35°C is chlorine (option A).
What is melting and boiling point?Melting point is the temperature at which the solid and liquid phases of a substance are in equilibrium.
On the other hand, the boiling point is the temperature at which a liquid boils, with the vapor pressure equal to the given external pressure.
Chemical elements and compounds have specific boiling and melting points that distinguishes them chemically.
The following are the melting and boiling point of the given compound and elements respectively;
Chlorine - -101°C and -35°CHydrogen: -259.2°C and -252.9 °CHydrogen sulfide: -85.5 °C and -60°CHydrogen chloride: -114.2 °C and - 85°CTherefore, the inorganic substance that has a melting point of -101°C and a boiling point of -35°C is chlorine.
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perform the following operation and express the answer in scientific notation 6x10^2 / 8x10^12
Answer:
7.5 x 10 ^-11
Explanation:
6/8 = .75
10^2 / 10^12 = 10^ (2-12) = 10^(-10)
so far .75 x 10^-10
which is 7.5 x 10^-11