Answer:
No.
Explanation:
HI is more polar than HF
An ion of a single pure element always has an oxication number of
A. magnitude equal to its atomic number
OB. 1
OC.0
OD. None of these
Answer:
C. zero 0
Explanation:
single elements will always possess an oxication number of zero
What is the oxidation number of chlorine in KClO3?
Group of answer choices
A. +5
B. +1
C. -5
D. -1
The oxidation number of chlorine in KClO3 is +5 (option A).
How to calculate oxidation number?The oxidation number of an element is the hypothetical charge of an atom within a molecule.
The oxidation number of an element like chlorine in a compound like Pottasium chlorate can be calculated as follows:
The oxidation number of the elements in KClO3 is as follows:
K = +1Cl = xO = -21 + x - 2(3) = 0
x - 5 = 0
x = +5
Therefore, the oxidation number of chlorine in KClO3 is +5.
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Suppose you need to prepare 136.9 mL of a 0.315 M aqueous solution of NaCl.
What mass, in grams, of NaCl do you need to use to make the solution?
Answer:
2.52 g NaCl
Explanation:
(Step 1)
To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:
Molarity = moles / volume (L)
After you convert mL to L, you can plug the given values into the equation and simplify to find moles.
136.9 mL / 1,000 = 0.1369 L
Molarity = moles / volume
0.315 M = moles / 0.1369 L
0.0431 = moles
(Step 2)
Now, you can use the molar mass to convert moles to grams.
Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol
Molar Mass (NaCl): 58.443 g/mol
0.0431 moles NaCl 58.443 g
------------------------------ x ------------------- = 2.52 g NaCl
1 mole
URGENT
A chemical equilibrium between gaseous reactants and products is shown.
N2(g) + 3H2(g) ⇌ 2NH3(g)
How will the reaction be affected if the pressure on the system is increased?
It will shift toward the reactant side as there is lower pressure on the reactant side.
It will shift toward the product side as there is higher pressure on the product side.
It will shift toward the reactant side as there are a greater number of moles of gas on the reactant side.
It will shift toward the product side as there are a fewer number of moles of gas on the product side.
Answer:
Explanation:
Discussion
When Pressure increases equilibrium shifts to the side with the smallest number of moles. But which side is that?
N2(g) + 3H2(g) ⇌ 2NH3(g)
The left side has 1 mol of nitrogen (N2) and 3 moles of Hydrogen = 4 mols
on the left side.
The right side has 2 mols of NH3 = 2 mols on the right.
Conclusion: You tell the number of mols by the Balance numbers to the left of each chemical in an equation.
Since the left side N2 + 3H2 = 4 mols, the equilibrium does NOT shift left.
2NH3 is only two mols.
The equilibrium shifts Right
Answer
D
Quick explanation please i'm having trouble
Two different atoms have nine protons each and the same mass. However, one is neutral while the other has a negative charge. Describe what each atomic structure could be, listing the possible number and location of all subatomic particles.
In many regions of the world, humans rely on underground water supplies called aquifers for fresh water. The amount of water an aquifer can store depends in part on the porosity of the rock or sediment in which the water is stored. Porosity is a measure of the amount of liquid that can be stored in a material and is related to the amount of empty space that exists between individual rock or sediment particles. A group of civil engineers wants to determine whether the porosity of surface soil affects aquifer recharge rates-the ability of aquifers to refill with water. The engineers conduct the following study to determine the porosity of the surface soil at various locations. The results of the study will then be compared with the recharge rates of the aquifer each location supplies with water. 1. Collect one 200-milliliter (mL) sample of soil from each of three locations. 2. Place each soil sample in a beaker. 3. Add 200 mL of water to each sample and allow the water to saturate the soil. 4. Measure the amount of standing water in each beaker (amount of water the soil did not absorb). 5. Determine the amount of water in the soil sample by subtracting the amount of standing water from 200 mL. 6. Divide the amount of water in the soil sample by 200 mL and multiply by 100 to determine the percent porosity of the soil. Which change to the experimental design would improve the reliability of the engineers' measurements?
The change to the experimental design that would improve the reliability of the engineers' measurements is C. testing single samples from more than three locations
What is an experimental design?It should be noted that experimental design is the process of carrying out research in an objective as well as a controlled fashion in order for precision to be maximized and specific conclusions can be drawn from the hypothesis statement.
Based on the information, the locations selected are only three. Also, an area must have more types of soil with variable porosity. Hence, the collection of more soil samples may provide more accurate results than collecting soil samples from only three regions.
Therefore, change to the experimental design that would improve the reliability of the engineers' measurements is the testing single samples from more than three locations.
In conclusion, the correct option is C.
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Complete question:
Which change to the experimental design would improve the reliability of the engineers' measurements?
A. using a liquid other than water to determine porosity
B. using flasks instead of beakers
C. testing single samples from more than three locations
D. testing more samples from each location
A sample of a gas (15.0 mol) at 2.0 atm is expanded at constant temperature from 5 L to 19.5 L. calculate the final pressure.
Answer:
.512 ATM
Explanation:
P1V1 = P2V2
2 * 5 = P2 * 19.5
P2 = .512 ATM
What is the mass of a 5.00cm3 piece of copper having a density of 8.96g/cm3
Answer:
44.8 grams
Explanation:
The density exists as a ratio comparing the mass of a piece of copper per 1 cm³. Since you have been given a new volume, you can set up a proportion to find the new mass.
[tex]\frac{8.96 grams}{1.00 cm^3} =\frac{?grams}{5.00cm^3}[/tex] <----- Proportion
[tex]44.8 = (1.00cm^3)(?grams)[/tex] <----- Cross-multiply
[tex]44.8= ?grams[/tex] <----- Divide both sides by 1.00
what is s for silicon tetrachloride Sicl4?
S denotes the ''number of shared electron pairs by an atom'', Hence, Silicon transmits its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ .It is also known as covalency
What is silicon tetrachloride used for?
Silicon Tetrachloride is a transparent, colorless, fuming liquid with an irritating odor. It is used to create Silicon-containing chemicals and in chemical analysis. determine potentially hazardous frontages.
How is silicon tetrachloride produced?Silicon tetrachloride is designed by the chlorination of various silicon compounds such as ferrosilicon, silicon carbide, or mixtures of silicon dioxide and carbon. The ferrosilicon route is most familiar. In the laboratory, SiCl 4 can be prepared by dining silicon with chlorine on 600 °C (1,112 °F): Si + 2 Cl 2 → SiCl.
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us
Let's say that you were asked to find the
molecular formula for a compound given its
empirical formula, CH₂O, and the compound's
molar mass.
The first step in solving such a problem is to
calculate the molar mass for the empirical
formula. What is the molar mass of CH₂O?
(C=12.01 amu, H=1.008 amu, O=16.00 amu)
[?] g/mol CH₂0
1
Answer:
Molar mass = 30.026 g/mol
Explanation:
Let Molar mass be mm
mm of CH2O = 12.01 + 2(1.008) + 16.00
= 12.01 + 2.016 + 16.00 = 30.026 g/mol
28. What mass
0.120M HCI?
of Na₂CO3 (Molar Mass = 106.0 g/mol) is required to react completely with 21.6 mL of.
Mass of [tex]$\mathrm{Na}{2} \mathrm{CO} 3$[/tex] required [tex]$=0.55 \mathrm{~g}$[/tex]
What is meant by molar mass?The mass of one mole of a sample is its molar mass. Add the atomic masses (atomic weights) of all the atoms in the molecule to obtain the molar mass. Using the mass listed in the Periodic Table or atomic weights table, determine the atomic mass for each element.The total mass of all the atoms that make up a mole of a specific molecule, measured in grams, is known as the molar mass or molecular weight. The measurement is made in grams per mole.Molar mass is a crucial factor to consider while planning an experiment. The molar mass enables you to calculate the quantity you should weigh on your scale if you are testing theories involving precise amounts of a substance. Take a look at an experiment that needs 2 moles of pure carbon as an illustration.The mass 0.120M HCI:
Moles of [tex]$\mathrm{HCl}$[/tex]reacted [tex]$=0.120 \times 21.6 / 1000=0.00260$[/tex]
according to balanced reaction, [tex]$\mathrm{HCl}$ and $\mathrm{Na} 2 \mathrm{CO} 3$[/tex] reacts in [tex]$2: 1$[/tex] the ratio
moles of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.00260 \times 2=0.00520$[/tex]
convert moles to mass
mass [tex]$=$[/tex]moles [tex]$\times$[/tex]molar mass
mass [tex]$=0.00520 \times 106.0$[/tex]
mass [tex]$=0.55 \mathrm{~g}$[/tex]
mass of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.55 \mathrm{~g}$[/tex]
Mass 0.120M HC is [tex]$=0.55 \mathrm{~g}$[/tex]
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How to calculate the exact molarity of phosphoric acid using the first equivalence point with the use of Diprotic and Triprotic Ka's?
As we know that the equivalency point of moles of added base will be equal to the moles of original acid, this allows to determine the number of moles of original acid.
How do you find the concentration at the first equivalence point?At the equivalency point the moles of added base will be equal to the moles of original acid, this allows the determination of the number of moles of original acid. This can be combined with the original volume of the analyte solution in order to determine its concentration.
So we can conclude that at the equivalence point the moles of added base will be equal to the moles of original acid, this allows the determination of the number of moles of original acid.
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A solution of dextrose contains 25.0 g solute in 250.0 g water. How should the percentage by mass of dextrose in this solution be calculated?
Answer:
9.10% dextrose
Explanation:
To find the mass percent, you need to use the following equation:
mass (g) of solute
Mass Percent = --------------------------------- x 100%
mass (g) of solution
You can plug the given values into the equation and solve to find the mass percent of dextrose. But first, you need to calculate the mass of the solution.
Mass (solute): 25.0 g
Mass (solution): 250.0 g + 25.0 g = 275 g
25.0 grams
Mass Percent = ------------------------ x 100%
275 grams
Mass Percent = 0.0909 x 100%
Mass Percent = 9.10%
A solution of dextrose contains 25.0 g solute in 250.0 g water. 9.10% is the percentage by mass of dextrose in this solution.
A component's concentration in a combination or compound can be expressed as a mass percent, also known as a weight percent. It shows how much of the total mass of the solution or mixture is made up of the solute's (component's) mass. In chemistry, mass percent is frequently employed and stated as a percentage.
Mass Percent = mass (g) of solute/ mass (g) of solution x 100%
Mass (solute): 25.0 g
Mass (solution): 250.0 g + 25.0 g = 275 g
Mass Percent =25.0 grams / 275 grams x 100%
Mass Percent = 0.0909 x 100%
Mass Percent = 9.10%
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4 Fe(s) + 3 02(g)
--> 2 Fe₂O3(s)
1. What is the oxidation state of iron (Fe) in the reactant Fe(s)?
2. What is the oxidation state of oxygen (O) in the reactant O2(g)?
3. What is the oxidation state of iron (Fe) in the product Fe2O3(s)?
4. What is the oxidation state of oxygen (O) in the product Fe2O3(s)?
5. In this reaction, iron is... (oxidized or reduced?)
6. In this reaction, oxygen is... (oxidized or reduced?)
7. What was the oxidizing agent in this reaction: Fe(s) or O2(g)?
The oxidation number of reactant Fe is 0 while the oxidation number of iron in the product is +3
What s a redox reaction?The term redox reaction implies a reaction in which there is an increase in the oxidation number of a specie and the decrease in the oxidation number of another specie.
Now we have the answers as follows;
1) The oxidation number of reactant Fe is 0
2) The oxidation number of reactant oxygen is 0
3) The oxidation number of iron in the product is +3
4) The oxidation number of oxygen in the product is -2
5). Iron is oxidized in the reaction
6) Oxygen is reduced in the reaction
7) The oxidizing agent in this case is the oxygen atom
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In the reaction:
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
How does the equilibrium shift if the HCl concentration is increased?
Group of answer choices
A. To the reactants
B. No change will occur
C. To the products
D. The equilibrium will initially shift but eventually be uneffected.
The equilibrium shift if the HCl concentration is increased to the product.
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
What is effect of concentration on equilibrium?If the concentration of a substance is changed, then the equilibrium will shift in such a way that it minimise the effect of change which occur. If we increase the concentration of a reactant, then the equilibrium will shift to minimize the changes in the direction of the reaction which uses the reactants, so that the reactant concentration decreases.
Factor affecting concentration of reactionThe temperature: As we increasing the temperature, the average speed of the reactant molecules also increases. As many molecules move faster, the large number of molecules moving fast enough to react increases, make the faster formation of products.pressure and concentration of the system are the factors which affect equilibrium.Thus, we concluded that with increase in the concentration of reactant equilibrium shift forward.
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Lab Data
Mass of magnesium (g)
Moles of magnesium (mol)
Temperature of water (°C)
Temperature of water (K)
Vapor pressure of water (mmHg)
Barometric pressure (mmHg)
Observations
Volume of hydrogen gas collected (mL)
Volume of hydrogen gas collected (L)
Pressure of hydrogen gas (mmHg)
Pressure of hydrogen gas (atm)
Moles of hydrogen gas produced (mol)
Ideal das constant (L-atm-mol-K)
0.218
-X
ES
V
LAB DATA SH
OLONCE
Answer:
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If I(to study),I(to pass)the exams
If I study, I will pass the exams.
please answer the question so i can make sure I got them right! thank you :)
pH = pKa + log [conj.base]/[acid]
Let the concentration of the conjugate base = x
=> The concentration of the acid is also x (As the acid concentration is equivalent to that of the conjugate base)
for CH₃COOH=0.50 M and CH₃COO=0,25 M
pH = pKa + log [salt]/[acid]
pKa = -log Ka = -log 1.8x10-5 = 4.74
pH = 4.74 + log (0.50 M/1.0 M) = 4.74 + log 0.5 = 4.74 + (-0.3)
pH = 4.74 - 0.3
pH = 4.44
For0.20 M Na2CO3
pH=−log[H+]
=−log (1.54×10−12)
=11.8
for HNO₂
Kb = 2.17X10^-11 = x^2 / 0.148
x = [OH-] = 1.79X10^-6
pOH = 5.747
pH = 14.000 - pOH = 8.253
for HPO₄³⁻
= [HPO₄³⁻] [PO₄³⁻] [H +]/×10⁻³
=[PO₄³⁻]5.464×10⁻¹⁸
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The two compounds that are the correct enol tautomers of 2-butnone are the structures shown in Option B.
What is Keto Enol Tautomerism?Isomerism is a situation in which two compounds have the same molecular formula but do not have the same structural formula. This occurs because the atoms in the molecule are arranged differently in space. One of the types of isomerism that we have is the Keto Enol Tautomerism. The Keto Enol Tautomerism occurs between the Keto and the enol forms of a compound via the movement of electrons. It is common in ketone compounds.
In this case, we can see that the compound 2-butanone can give rise to two enol compounds that have the same molecular formula as the 2-butanone.
The two compounds that are the correct enol tautomers of 2-butnone are the structures shown in Option B.
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How many molecules in 5.68 g of ozone (O3)
Answer:
[tex]\boxed{\sf no.\ of \ molecules = 7.13 \times 10^{22} \ molecules}[/tex]
Explanation:
Given data::Mass in g = m = 5.68 g
Molar mass = M = (16)3 = 48 g/mol
Avogadro's number = [tex]N_A[/tex] = 6.023 × 10²³
Required:No. of molecules = ?
Formula:[tex]\displaystyle no.\ of \ molecules = \frac{m}{M} \times N_A[/tex]
Solution:Put the givens in the above formula
[tex]\displaystyle no. \ of \ molecules =\frac{5.68}{48} \times 6.023 \times 10^{23}\\\\no. \ of\ molecules = 0.12 \times 6.023 \times 10^{23}\\\\no. \ of \ molecules = 0.713\times 10^{23}\\\\no.\ of \ molecules = 7.13 \times 10^{22} \ molecules\\\\\rule[225]{225}{2}[/tex]
select the common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous
The common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.
What are hazardous statements?Hazardous statements are those words or phrases that are labelled against chemicals which shows the degree of how dangerous the chemical are.
The common words that are used as hazardous statements which shows that a chemical is dangerous include the following:
Danger,Caution andWarning.Therefore, the common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.
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In the chemical reaction:
Cu + 2AgNO3 → 2Ag + Cu(NO3)2
What is the limiting reactant if you start with 1.8 moles of copper and 2.0 moles of silver nitrate?
Group of answer choices
A. copper (II) nitrate
B. copper
C. silver
D. silver nitrate
Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.
Reaction stoichiometryIn first place, the balanced reaction is:
Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Cu: 1 moleAgNO₃: 2 molesAg: 2 molesCu(NO₃)₂: 1 moleLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?
[tex]amount of moles of AgNO_{3} =\frac{1.8 moles of Cux2 moles of AgNO_{3} }{1 mole of Cu}[/tex]
amount of moles of AgNO₃= 3.6 moles
But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.
SummaryIn summary, AgNO₃ will be the limiting reagent.
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Need the answer pretttty pleaseeeeee
Answer:
B.) their electrons are assigned to the s and p orbitals only
Explanation:
Once you get to the fourth row on the periodic table, the transition metals are introduced. The transition metals are located in the d-block and their electrons fill up d orbitals. When an element in the p-block (the right side of the table) is in one of these rows, the d-block has to fill up first.
Perform the following mathematical operation and report the answer to the appropriate number of significant figures. 5.4-4.21
Answer:
1.2 ( two significant digits)
Explanation:
5.4 - 4.21 answer should only have the the number of significant digits as the number in the equation with the least number of significant digits... in this case 5.4 is only two significant digits....so the answer should only have two significant digits
5.4 - 4.21 = 1.19 round to two digits = 1.2
At a certain temperature the reaction
CO2(g) + H2(g) ↔ CO(g) + H2O(g) has Kc = 2.50.
If 2.00 mol of carbon dioxide and 1.5 mol of hydrogen are placed in a 5.00 L vessel and equilibrium is established, what will be the concentration of carbon monoxide?
The concentration of carbon monoxide at equilibrium is 0.209 M.
Concentration of each gasCO2 = 2 mol/5 L = 0.4
H2 = 1.5 mol/5L = 0.3
ICE tableCreate ICE table as shown below
CO2(g) + H2(g) ↔ CO(g) + H2O(g)
I 0.4 0.3 0 0
C - x - x x x
E 0.4 - x 0.3 - x x x
Kc = [CO][H₂O] / [CO₂][H₂]
2.5 = (x²)/(0.4 - x)(0.3 - x)
x² = 2.5(0.4 - x)(0.3 - x)
x² = 2.5(0.12 - 0.7x + x²)
x² = 0.3 - 1.75x + 2.5x²
0 = 1.5x² - 1.75x + 0.3
solve the quadratic equation using formula method;
x = 0.209
Thus, the concentration of carbon monoxide at equilibrium is 0.209 M.
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In a perfect world, reactions can never go above 100% yield. However in reality you will sometimes get above 100% yield. Why?
Group of answer choices
A. Excess water and Impurities
B. Impurities Only
C. Excess Water Only
D. You can never have above 100% yield under any circumstance.
Answer:
You can never have above 100% yield under any circumstance
To solve such this we must know the concept of chemical reaction. Therefore, the correct option is option D that is you can never have above 100% yield under any circumstance.
What is chemical reaction?Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.
You can never have above 100% yield under any circumstance for any chemical reactions. Option D is the correct options among all the given options.
Therefore, the correct option is option D that is you can never have above 100% yield under any circumstance.
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The symbol X in the following equation, 23/11 Na + 1/1H → 23/12 Mg + X, is a/an
Answer:
X = ¹₀n
Explanation:
The mass number is the total amount of neutrons and protons in the element. The atomic number is the total protons in the element. The mass number is the superscript and the atomic number is the subscript. The mass and atomic numbers must be balanced on both sides of the equation. The element can be identified by the atomic number.
In the event that we have an atomic number of zero, there is no element this represents, so the letter "n" should be used.
²³₁₁Na + ¹₁H → ²³₁₂Mg + X
Mass Number:
Reactants = Products
23 + 1 = 23 + ?
24 = 23 + ?
1 = ?
Atomic Number:
Reactants = Products
11 + 1 = 12 + ?
12 = 12 + ?
0 = ?
The complete equation is:
²³₁₁Na + ¹₁H → ²³₁₂Mg + ¹₀n
The following reaction: HF(aq) <--> H+(aq) + F-(aq) has an equilbirum constant (K) value of 7.2 x 10-4. This means that the reaction proceeds essentially to completion.
Group of answer choices
True
False
Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.
What is the equilibrium constant?In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.
On the other hand, when we have a case that the equilibrium constant is small and is not so large, then the reaction does not proceed essentially to completion.
Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.
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What is the oxidation state of oxygen (O) in the reactant O2(g)?
Answer:0
Explanation:
Since oxygen gas i.e., diatomic oxygen exists in the atmosphere in the free state, hence the oxidation state of each atom will be 0
Need the answer pretttty pleaseeeeee
Answer:
The answer would be D.
Explanation:
Whenever one has many of the same correlating numbers within in a pattern, the rest tend to follow. With the information I was given and not the actual plotting, that would be my answer.