Assume that thermometer readings are normally distributed with a mean of 0 C and a standard deviation of 1.00 C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.)
Between 1.50 and 2.25
1. Choose the correct graph
2.the probability of getting a reading between 1.50 and 2.25
The probability of getting a reading between 1.50 and 2.25 is; 0.00546
How to find the probability from z-score?We are given the following information in the question:
Mean; μ = 0 °C
Standard Deviation; σ = 1 °C
We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.
Formula for z-score is;
z = (x' - μ)/σ
P(Between 1.50 degrees and 2.25 degrees) is expressed as;
P(1.5 ≤ x ≤ 2.25)
= P((1.5 - 0)/1 ≤ z ≤ (2.25 - 0)/1))
= P(z ≤ 2.25) - P(z < 1.5)
= 0.0546 = 5.46%
The graph that correctly describes this is the first graph
Read more about Z-score Probability at; https://brainly.com/question/25638875
#SPJ1
Name the rule for this sequence.
27, 21, 15, 9, 3,...
A) divide the previous term by 0.06
B) divide the previous term by 0.6
C) add 6 from the previous term
D) subtract 6 from the previous term
Answer:
D) subtract 6 from the previous term
Step-by-step explanation:
27-6=21, 21-6=15, 15-6=9, and 9-6=3
A data set contains three points, and two of the residuals are 7 and -3. What 7
is the third residual?
The data set in discuss which contains three points and two of the residuals are 7 and -3 would have its third residual as; -4.
What is the third residual if the data set characterized as having 2 of its three residuals to be; 7 and -3?According.tinthe task content, the data set in discuss has three points and consequently should have three residuals.
Additionally, two of the three residuals have been given and on this note, it follows that the third residual must have a value such that the algebraic sum of all residuals is 0.
Hence, we have; -3 + 7 +x = 0;
x = 3-7 = 4.
Ultimately, the third residual is; -4.
Read more on residuals in a data set;
https://brainly.com/question/27733055
#SPJ1
What are the domain and range of g of x equals the square root of the quantity x plus 4?
It is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).
What are the domain and range of a function?The domain of a function is the set of values that can be plugged into it. This set contains the x values in a function like f(x). A function's range is the set of values that the function can take. This is the set of values that the function returns after we enter an x value.To find the domain and range:
The given function in the problem is: [tex]g(x)=\sqrt{x+4}[/tex]Because the square root function does not exist for negative numbers, the domain is denoted by: [tex]x+4[/tex] ≥ [tex]0[/tex] → [tex]x[/tex] ≥ [tex]-4[/tex]Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).The range of the square root function is [tex]x[/tex] ≥ [tex]0[/tex], which remains the same as there are no vertical translations.Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).
Know more about the range here:
https://brainly.com/question/26098895
#SPJ4
The complete question is given below:
What are the domain and range of g of x equals the square root of the quantity x plus 4?
(A) D: [4, ∞) and R: [0, ∞)
(B) D: (–4, ∞) and R: (–∞, 0)
(C) D: [–4, ∞) and R: [0, ∞)
(D) D: (4, ∞) and R: (–∞, 0)
1. 3k − 8 = 7
2. 8b + 9 = −15
3. 8 = 3x − 13
4. 6p + 22 = 4
5. 84 = 51 + 11c
Add 8 to both sides.
3k = 7 + 8Add 7 and 8 to get 15.
3k = 15Divide both sides by 3.
k = 15 / 3Divide 15 by 3 to get 5.
k=5 ===> Answer===> Exercise 28b + 9 = −15
Subtract 9 from both sides.
8b= −15 − 9Subtract 9 from −15 to get −24.
8b = −24Divide both sides by 8.
b = -24 / 3Divide −24 entre 8 para obtener −3.
b=−3 ===> Answer===> Exercise 38 = 3x − 13
Swap the sides so that all the terms of the variables are on the left side.
3x −13 = 8Add 13 to both sides.
3x = 8 + 13Add 8 and 13 to get 21.
3x = 21Divide both sides by 3.
x = 21 / 3Divide 21 by 3 to get 7.
x = 7 ===> Answer===> Exercise 46p + 22 = 4
Subtract 22 from both sides.
6p = 4 − 22Subtract 22 from 4 to get −18.
6p = −18Divide both sides by 6.
p = -18 / 6Divide −18 entre 6 para obtener −3.
p = −3 ===> Answer===> Excercise 584 = 51 + 11c
Swap the sides so that all the terms of the variables are on the left side.
51 + 11c = 84Subtract 51 from both sides.
11c = 84 − 51Subtract 51 from 84 to get 33.
11c = 33Divide both sides by 11.
c = 33 / 11Divide 33 by 11 to get 3.
c = 3 ===> AnswerSolution 1 :-
>> 3k - 8 = 7
>> 3k = 7 + 8
>> 3k = 15
>> k = 15 / 3
>> k = 5
Solution 2 :-
>> 8b + 9 = -15
>> 8b = -15 - 9
>> 8b = -24
>> b = -24 / 8
>> b = -3
Solution 3 :-
>> 8 = 3x - 13
>> 3x = 13 + 8
>> 3x = 21
>> x = 21 / 3
>> x = 7
Solution 4 :-
>> 6p + 22 = 4
>> 6p = 4 - 22
>> 6p = -18
>> p = -18 / 6
>> p = -3
Solution 5 :-
>> 84 = 51 + 11c
>> 11c = 84 - 51
>> 11c = 33
>> c = 33 / 11
>> c = 3
An athlete trains for 80 min each day for as many days as possible. Write an equation that relates the number of days d that the athlete spends training when the athlete trains for 400min.
80d = 400 is the equation that relates the number of days d that an athlete spends training when the athlete trains for 400 min given that athlete trains for 80 min each day for as many days as possible. This can be obtained by converting the given statements into algebraic equation.
Find the required equation for the given question:Here in the question it is given that,
Athlete trains for 80 min each day,that is each day the athlete spends 80 min.
We have to assume the variable d the number of days the athlete spends training.Finally we have to find an equation that relates the number of days d that the athlete spends training when the athlete trains for 400 min.So we can write that,
400 min is the time spent by the athlete
400 min = number of days × time spent by the athlete in one day
400 min = d × 80
⇒ 80d = 400
Hence 80d = 400 is the equation that relates the number of days d that an athlete spends training when the athlete trains for 400 min given that athlete trains for 80 min each day for as many days as possible.
Learn more about algebraic equation here:
brainly.com/question/953809
#SPJ1
Factor the polynomial completely
10³ -25r² - 12r + 30
1 + 7x = 5x + 25 solve for X
Answer:
x = 12
Step-by-step explanation:
1 + 7x = 5x + 25 ( subtract 5x from both sides )
1 + 2x = 25 ( subtract 1 from both sides )
2x = 24 ( divide both sides by 2 )
x = 12
Answer:
12
Step-by-step explanation:
Start by subtracting both sides by 5x:
[tex]1+7x-5x=25\\1+2x=25[/tex]
Subtract 1 from both sides
[tex]2x=24[/tex]
Divide both sides by 2
[tex]x=12[/tex]
Check[tex]1+7(12)=5(12)+25\\1+84=60+25\\85=85[/tex]
Therefore x = 12
Determine the area between the curves by integrating over the x-axis or y-axis.
x=y^2
x=-|y|+12
When [tex]y\ge0[/tex] (above and on the [tex]x[/tex]-axis), we have [tex]|y|=y[/tex]. The parabola [tex]x=y^2[/tex] intersects with [tex]x=-|y|+12[/tex] in this region when
[tex]y^2 = -y + 12 \implies y^2 + y - 12 = (y-3)(y+4) = 0 \implies y=3[/tex]
On the other hand, when [tex]y<0[/tex] (below the [tex]x[/tex]-axis, we have [tex]|y|=-y[/tex], and so the curves intersect when
[tex]y^2 = -(-y) + 12 \implies y^2 - y - 12 = (y - 4)(y+3) = 0 \implies y=-3[/tex]
The area between the curves is then given by the definite integral,
[tex]\displaystyle \int_{-3}^3 (-|y| + 12) - y^2 \, dy[/tex]
The integrand is symmetric about the [tex]x[/tex]-axis, so the integral is equivalent to
[tex]\displaystyle 2\int_0^3 12 - y - y^2 \, dy = 2 \left(12y - \frac{y^2}2 - \frac{y^3}3\right)\bigg|_0^3 = \boxed{45}[/tex]
I dont know this one
Answer:
10, 8
Step-by-step explanation:
l + w = 18
l*w = 80
8 and 10 works
Aakash has a fever. His body temperature during the day was 99.2°F. By evening, his body temperature has increased by 3.4°F.
His body temperature in the evening is
°F.
His body temperature in the evening is 102.6 °F
How to determine his body temperature?The given parameters are:
Temperature in the morning = 99.2°F.
Temperature increase = 3.4°F.
His body temperature in the evening is calculated as:
New = Temperature in the morning + Temperature increase
So, we have
New = 99.2°F + 3.4°F
Evaluate the sum
New = 102.6 °F
Hence, his body temperature in the evening is 102.6 °F
Read more about addition at:
https://brainly.com/question/11562149
#SPJ1
To calculate the height of a tower Mary measures the angle of elevation from a point A, to be
10. She then walks 100m directly towards the tower, and finds the angle of elevation from the
new point B to be 20°. What is the height of the tower to the nearest tenth of a metre?
If Mary measures the angle of elevation from a point A, to be 10°. She then walks 100m directly towards the tower, and finds the angle of elevation from the new point B to be 20°, the height of the tower comes out to be 37 meters.
Given Information and Formula Used:
The angle of elevation of the tower from point A (a in figure) = 10°
The angle of elevation of the tower from point B (b in figure) = 20°
The distance AB (ab n figure) = 100m
In right triangle adc, tan 10° = cd / ad ....... (1)
In right triangle bdc, tan 20° = cd / bd ......... (2)
Here, cd is the height of the tower.
Let the distance bd be x, then the ad = x + 100
Substituting this value of of ad in equation (1), we get,
tan 10° = cd / (x+100)
x+100 = cd / tan 10°
x+100 = cd / 0.18
x+100 = 5.6 cd ....... (3)
From equation (2),
tan 20° = cd / x
x = cd / tan 20°
x = cd / 0.34
x = 2.9 cd
Putting this value of x in equation (3), we obtain the height cd (or CD) as,
2.9 cd + 100 = 5.6 cd
(5.6 - 2.9)cd = 100
2.7cd = 100
cd = 100/2.7
cd ≈ 37m (To the nearest tenth of a meter)
Therefore, the height of the tower is calculated to be 37 meters.
Learn more on height here:
https://brainly.com/question/10724305
#SPJ1
The model of a trinomial is shown.
An algebra tile configuration. 0 tiles are in the Factor 1 spot and 0 tiles are in the Factor 2 spot. 24 tiles are in the Product spot: 1 is labeled + x squared, 7 are labeled negative x, the 2 tiles below + x squared are labeled + x, and the 14 tiles below the negative x tiles are labeled negative.
What are the factors of the trinomial? Select two options.
x – 14
x + 7
x – 7
x – 2
x + 2
The factors of the trinomial are:
x – 7x + 2Options C and E
This is further explained below.
What is trinomial?Generally, A trinomial is a kind of polynomial that is used in basic mathematics. It is composed of three components, also known as monomials.
In conclusion, The following expressions are the components of the trinomial: x - 7, x + 2
Read more about trinomial
https://brainly.com/question/8985142
#SPJ1
For a sample of n = 36 that has a sample variance of 1,296, what is the estimated standard error for the sample? 6 37 36 6. 9
The estimated standard error for the sample is 6
Given,
Sample size, n = 36
Sample variance, [tex]s^{2}[/tex] = 1296
Standard deviation, s = √1296
= 36
Standard error, SE = [tex]\frac{s}{\sqrt{n} }[/tex]
= [tex]\frac{36}{\sqrt{36} }[/tex]
= [tex]\frac{36}{6}[/tex]
= 6
Concept
Sample size is the number of participants or observations included in a study. It is denoted by ‘n’Sample variance is a measure of the degree to which the numbers in a list are spread out. It is denoted by '[tex]s^{2}[/tex]'Standard deviation is a measure of how dispersed the data is in relation to the mean. It is denoted by ‘s’Learn more about standard deviation here:https://brainly.com/question/13905583
#SPJ4
6;15; x; 45;....... is a quadratic number pattern (sequence). Determine the value of x.
Solving a system of equations, we conclude that the value of x is 28.
How to determine the value of x?
Here we have the quadratic number pattern:
6, 15, x, 45, ...
First, we have that:
15 - 6 = 9
So 9 is the first difference.
Then we will have:
x = 15 + 9 + a
(where a is the second difference, constant of the sequence).
And:
45 = x + 9 + a + a
Then we have a system of equations:
x = 15 + 9 + a
45 = x + 9 + a + a
We can isolate a on the first equation:
a = x - 24
We can replace that in the other equation:
45 = x + 9 + 2a
45 = x + 9 + 2*(x - 24)
Now we can solve that for x:
45 - 9 = x + 2*(x - 24)
36 = 3x - 48
36 + 48 = 3x
84 = 3x
84/3 = x = 28
The value of x is 28.
If you want to learn more about systems of equations:
https://brainly.com/question/13729904
#SPJ1
Can someone help me with these two problems and show work please !!
Answer:
13. Two real solutions.
14. No real solutions.
Step-by-step explanation:
Given quadratic equations:
13. [tex]x^2+7x+10=0[/tex]
14. [tex]4x^2-3x+4=0[/tex]
[tex]{\large \textsf{Quadratic Formula: }} x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\ \Bigg{\|}\ \textsf{when }ax^2+bx+c=0[/tex]
What is the discriminant?
The discriminant (Δ) is b² - 4ac, which is under the square root in the quadratic formula. It is used to determine the number of real solutions (roots) of a quadratic:
When b² - 4ac > 0, the quadratic has two real solutions.When b² - 4ac = 0, the quadratic has one real solution.When b² - 4ac < 0, the quadratic has no real (complex) solutions.13. x² + 7x + 10 = 0
[tex]\implies a=\textsf{1},b=\textsf{7},c=\textsf{10}[/tex]
Find the discriminant value.
[tex]\implies \Delta = b^2 - 4ac[/tex]
[tex]\implies \Delta=(7)^2 - 4(1)(10)[/tex]
[tex]\implies \Delta=49 - 40[/tex]
[tex]\implies \Delta=9[/tex]
As [tex]9[/tex] > 0, this quadratic has two real solutions.
14. 4x² - 3x + 4 = 0
[tex]\implies a=\textsf{4},b=\textsf{-3},c=\textsf{4}[/tex]
Find the discriminant value.
[tex]\implies \Delta = b^2 - 4ac[/tex]
[tex]\implies \Delta = (-3)^2 - 4(4)(4)[/tex]
[tex]\implies \Delta = 9 - 64[/tex]
[tex]\implies \Delta = -55[/tex]
As [tex]-55[/tex] < 0, this quadratic has no real solutions.
Learn more about quadratic equations here:
brainly.com/question/28063094
brainly.com/question/27638369
20 points and I will mark brainlyist to the first right answer.
Answer:
Step-by-step explanation:
Movie A: 267 students
Movie B: 217 students
Movie C: 233 students
Movie D: 183 students
PLEASE HELP IM STUCK
Answer:
y=1
Step-by-step explanation:
Since you already found x,
We will only be needing one equation to find y..
I will take equation two: 3(2)+2y=8
Step Two: 6+2y=8 (then you minus 6 on each side)
Step Three: 2y=2 (divide)
y=1
In the expression (ax+b)*(cx^2+dx+e), find two set of values of a,b,c,d and e so that the coefficient of x^3and x terms after expansion are 4and 10 respectively.
Answer:
2, 0, 2, 3, 5
1, 2, 4, 0, 5
Step-by-step explanation:
(ax + b)(cx² + dx + e)
acx³ + adx² + aex + bcx² + bdx + be
2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0
4x³ + 6x² + 10x
a = 2
b = 0
c = 2
d = 3
e = 5
1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10
4x³ + 8x² + 10x + 10
a = 1
b = 2
c = 4
d = 0
e = 5
Find the missing length indicated.
The missing length indicated on the right triangle is 120 units
How to determine the missing length?To start with:
The missing length in the right triangle can be represented with the variable x
Next, we have the following equivalent ratio from the given triangle
64 : x = x : 289 - 64
Express the ratio as a fraction
64/x = x/(289 - 64)
Evaluate the difference on the right-hand side
64/x = x/225
Cross multiply in the above equation
x * x = 64 * 225
This gives
x^2 = 64 * 225
Take the square root of x^2 (do not approximate)
x = 64 * 225
Take the square root of 64 and 225 (do not approximate)
x = 64 * 225
Evaluate the product of 8 and 5
x = 120
Based on the given parameters, the missing length indicated on the right triangle is 120 units
Read more about right triangles at:
https://brainly.com/question/2437195
#SPJ1
Find the value of x. Degrees in an arc!! pls help i need this to study for my test!! pls show work thank you so much :)
Considering the angle of the arc, it is found that the value of x is of x = 12º.
What is the angle of the arc?It is twice the inside angle.
In this problem, the angle of the arc is of 102º, hence the inside angle is of 51º, which means that we can solve for x as follows:
4x + 3 = 51
4x = 48
x = 12º.
More can be learned about the angle of an arc at https://brainly.com/question/2005046
#SPJ1
A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet saturn. you could determine a 100–pound earthling's weight on saturn using the proportion: a. startfraction 15 over 4 endfraction = startfraction b over 100 endfraction c. startfraction 4 over 15 endfraction = startfraction 100 over b endfraction b. startfraction 15 over 4 endfraction = 100 over b endfraction d. either a or c
100–pound earthling's weight on Saturn using the proportion is (B)
15/4 = 100/x.
What is proportion?The size, number, or quantity of one object or group of things in comparison to another thing or group of things In our class, the ratio of guys to girls is two to one (2:1).To find the 100–pound earthling's weight on Saturn using the proportion:
Weight of ball on Earth = 15 poundsWeight of ball on Saturn= 4 poundsLet 100 pounds of earthling weight on Saturn be x pounds.Thus, the proportion is 15:4 = 100:x15/4 = 100/xTherefore, 100–a pound earthling's weight on Saturn using the proportion is (B) 15/4 = 100/x.
Know more about proportions here:
https://brainly.com/question/19994681
#SPJ4
The correct question is given below:
A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet Saturn. you could determine a 100–pound earthling's weight on Saturn using the proportion:
a. start fraction 15 over 4 end fraction = start fraction x over 100 end fraction
b. startfraction 15 over 4 endfraction = 100 over x endfraction
c. startfraction 4 over 15 endfraction = startfraction 100 over x endfraction
d. either a or c
julianna wrote -16+ x = -8 on the board.Do not solve.Tell how you would simplify julianna's expression?
Answer:
x = 8
Step-by-step explanation:
→ Add 16 to both sides
x = 8
The correct solution for the given expression [tex]-16+x = -8 \\[/tex] is [tex]x[/tex] is equal to [tex]8[/tex].
Given expression:
[tex]-16+x =- 8 \\[/tex]
To solve for [tex]x[/tex], Rearrange the equation or isolate [tex]x[/tex] terms on one side of the expression.
Add [tex]8[/tex] on both side of the equation:
[tex]-16+x+8=-8+8[/tex]
Simplify:
[tex]x-8 = 0[/tex]
Isolate [tex]x[/tex] on one side:
[tex]x= 8[/tex]
The correct value of [tex]x[/tex] is [tex]8[/tex].
Lear more about simplification here:
https://brainly.com/question/24295244
#SPJ3
Match each quadratic equation with its solution set. 2x2 − 32 = 0 4x2 − 100 = 0 x2 − 55 = 9 x2 − 140 = -19 2x2 − 18 = 0
Correct match for the quadratic equation are:
A. {-4, 4}
B. {-5, 5}
C. {-8, 8}
D. {-11, 11}
E. {3,-3}
What is a quadratic equation ?An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.
According to the given Information:First equation:2x² - 32 = 0
Adding thirty-two to both sides of the equation:
2x² = 32
Dividing between two on both sides of the equation:
x² = 322
x² = 16
Applying square root to eliminate the exponent:
x = ±√16
x = ±4
Second equation:4x² - 100 = 0
Adding hundred to both sides of the equation:
4x² = 100
Dividing between four on both sides of the equation:
x² = 100/4
x² = 25
Applying square root to eliminate the exponent:
x = ±√25
x = ±5
Third equation:x² - 55 = 9
Adding fifty-five to both sides of the equation:
x² = 9 + 55
x² = 64
Applying square root to eliminate the exponent:
x = ±√64
x = ±8
Fourth equation:x² - 140 = -19
Adding one- fourty to both sides of the equation:
x² = -19 + 140
x² = 121
Applying square root to eliminate the exponent:
x = ±√121
x = ±11
Fifth equation:2x² - 18 = 0
Adding eighteen to both sides of the equation:
2x² = 18
Dividing between two on both sides of the equation:
x² = 182
x² = 9
Applying square root to eliminate the exponent:
x = ±√9
x = ±3
Correct match for the quadratic equation are: A. {-4, 4},B. {-5, 5},
C. {-8, 8},D. {-11, 11},E. {3,-3}
To know more about quadratic equation visit:
https://brainly.com/question/1863222
#SPJ4
I understand that the question you are looking for is:
Match each quadratic equation with its solution set.
A. 2x2 - 32 = 0 {-8, 8}
B. 4x2 - 100 = 0 {-4, 4}
C. x2 - 55 = 9 {-5, 5}
D. x2 - 140 = -19 {-11, 11}
E. 2x2 - 18 = 0 {3,-3}
Which point lies on the line described by the equation below? y+4=4(x-3
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies \begin{array}{llll} y+4=4(x-3)\implies y-(\stackrel{y_1}{-4})=\stackrel{m}{4}(x-\stackrel{x_1}{3})\\\\ ~\hfill (\stackrel{x_1}{3}~~,~~\stackrel{y_1}{-4}) \end{array}[/tex]
If a card is drawn from a deck, find the probability of getting these results:
a. a 6 and a spade
b. a black king
c. a red card and a 7
d. a diamond or a heart
e. a black card
Answer:
Below in bold,
Step-by-step explanation:
a. There's is only one card that fits this description so
Probability = 1/52.
b. There are 2 black Kings so
Probability = 2/52 = 1/26.
c. There are 2 of these - 7 of diamonds and 7 of hearts
so
Probability = 2/52 = 1/26.
d. There 13 diamonds and 13 hearts so
Probability = 26/52 = 1/2.
e. There 26 black cards
Probability = 26/52 = 1/2.
The real solutions to the quadratic -x² - 2x+5=0 are:
2± √√29
2
-1±-√6
No real solutions.
None of the choices are correct.
Answer:
No real solutions.
Step-by-step explanation:
To solve this, we need to use Quadratic Formula.
Quadratic Formula:
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ [/tex]
in the form of:
[tex]a {x}^{2} + bx + c[/tex]
Given information from the question, we can deduce:
a = -1
b = -2
c = 5
Let's substitute these values into the formula.
[tex]x = \frac{ - ( - 2) + - \sqrt{ {( - 2)}^{2} - 4( - 1)( -5)} }{2( - 1)} \\ = no \: real \: solutions[/tex]
if you punch these into the calculator.
math related pls help
Answer:
(a) (f +g)(x) = √(x-2) +√(x)
Step-by-step explanation:
The sum of two functions is the sum of their definitions.
Application(f +g)(x) = f(x) +g(x)
(f +g)(x) = √(x -2) +√(x)
Note: the radicals can only be combined if they can be reduced to a form that has the same expression under the radical. Here, that is not the case, so there is no way to simplify the sum.
PLS HELP IM STUCK PLS
Answer:
-4
Step-by-step explanation:
We are going to substitute 0 in for x and solve for y.
-2(0)+ 8y = -32 Anything times zero is zero
0 + 8 y = -32 Anything plus zero is itself.
8y = -32 Divide both sides by 8
y = -4
In the regular pentagon below, if AP = 4 m and BC = 10 m, find it's area.
First symmetrically cut the pentagon to get 5 pieces. (So that you will get the idea that this polygon is divided into 5 triangles)
Then find the area of one of the triangles:
Area of Triangle = [tex]\frac{1}{2} bh[/tex]
A = [tex]\frac{1}{2}[/tex] × 4 × 10
A = 20 m²
To find the area of the whole pentagon shape:
A = 20 × 5 = 100 m²
Hope it helps!