In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0 represents the worst possible life and 10 represents the best possible life. The responses were normally​ distributed, with a mean of 5.2 and a standard deviation of 2.5. Answer parts ​(a)–​(d) below.

[tex]x^3[/tex] is strictly increasing on [0, 5], so

[tex]\max\{x^3 \mid 0\le x\le5\} = 5^3 = 125[/tex]

and

[tex]\min\{x^3 \mid 0 \le x\le5\} = 0^3 = 0[/tex]

so the integral is bounded between

[tex]\displaystyle \boxed{0} \le \int_0^5x^3\,dx \le \boxed{125}[/tex]

Answer: C, E

Step-by-step explanation:

These are polynomials by the definition of a polynomial.

July Aug. Sept. Oct. Nov. Dec. Receipts $500 $550 $700 $850 $795 $715 Expenses $490 $550 $600 $795 $ $650 Net Cash Flow $ $0 $ $55 $45 $ Cumulative Balance $10 $ $110 $ $210 $275 the missing values are 750, 10, 100, 65, 10, 165

This is further explained below.

Generally, The term "cumulative balance" refers to the total amount of money left over at the end of a fiscal year after all surplus amounts have been subtracted from deficit amounts. If there is a negative amount in the Cumulative Balance at the conclusion of a fiscal year, then that balance will be carried forward and used as the opening balance for the next fiscal year.

The term "cumulative account" refers to the total amount of an employee's account under a defined contribution plan (for an unaggregated plan) or the total amount of an employee's account under all defined contribution plans included in an Aggregation Group (for aggregated plans), both of which are determined as of the most recent plan valuation date within the most recent 12-month period that ends on the...

In conclusion, for the following data  July Aug. Sept. Oct. Nov. Dec. Receipts $500 $550 $700 $850 $795 $715 Expenses $490 $550 $600 $795 $ $650 Net Cash Flow $ $0 $ $55 $45 $ Cumulative Balance $10 $ $110 $ $210 $275 the missing values are 750, 10, 100, 65, 10, 165

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The value of the given expression is approximate equal to 1.021 × 10⁴ OR 10207.8

From the question, we are to determine the value of the given expression

The given expression is

10 to the 4th times the square root of 1.042

That is,

10⁴ × √1.042

The expression can be evaluated as shown below

10⁴ × √1.042

= 10⁴ × 1.02078

= 1.02078 × 10⁴

≈ 1.021 × 10⁴

OR

= 1.02078 × 10⁴ = 10207.8

Hence, the value of the given expression is approximate equal to 1.021 × 10⁴ OR 10207.8

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The speed of the plane will be 875km/h and the speed of the wind will be 125km/h.

It should be noted that the speed is calculated as:

= Distance/Time

Based on the information, the DC10 airplane travels 3000 km with a tailwind in 3 hr. It travels 3000 km with a headwind in 4 hr.

Therefore, (v + w) = 3000/3

v + w = 1000 .... I

(v - w) = 3000/4

v - w = 750 .... ii

We'll then add both equations together. Therefore, the speed of the plane will be 875km/h and the speed of the wind will be 125km/h.

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Answer:

[tex]u = x^{7} +8[/tex]     [tex]du = 7x^{6} dx[/tex]   result is [tex]\frac{1}{7} \sqrt[4]{u}[/tex]

Step-by-step explanation:

The slope of the curve described by the equation at the given point (0,1) as in the task content is; 4.

According to the task content, it follows that the slope of the curve can be determined by means of implicit differentiation as follows;

y⁵+ x³ = y² + 12x

5y⁴(dy/dx) -2y(dy/dx) = 12 - 3x²

(dy/dx) = (12 -3x²)/(5y⁴-2y)

Hence, since the slope corresponds at the point given; (0, 1); we have;

(dy/dx) = (12 -3(0)²)/(5(1)⁴-2(1))

dy/dx = 12/3 = 4.

Hence, slope, m = 4.

Consequent to the mathematical computation above, it can then be concluded that the slope of the curve, the line tangent to the curve at the given point is; 4.

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The answer is no.

Always remember when converting from percent to decimal, divide by 100%.

Hence, the student's thinking is not correct.

Answer:

no

Step-by-step explanation:

0.3 = 30% not 3%

to change a percentage to a decimal fraction, divide by 100

3% = [tex]\frac{3}{100}[/tex] = 0.03

Considering the given function, it is found that:

Since the changes for each 5 second interval are not the same, the ball is not traveling at a constant speed.

The function is:

d = 5t².

Hence:

Since the changes for each 5 second interval are not the same, the ball is not traveling at a constant speed.

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The value of the median, lower and upper quartile

The minimum value = 10

The maximum value = 38

The median is the value that is found in the center of the data when it is ordered from lowest to highest. In the event that there is no value that precisely corresponds to the center, the value will be determined by taking the average of the values that are located on each side of the middle.

10  11  12  15  19  24  27  29  33  38

Median = 21.5

The intermediate value of the data that is located to the left of the median is known as the lower quartile.

10  11  12  15  19

lower quartile = 12

The intermediate value of the data that is located to the right of the median is known as the upper quartile.

24  27  29  33  38

upper quartile = 29

In conclusion, the 5 number summary is 10, 12, 21.5, 29, 38 → A

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Answer: minimum 10 first quartile 11.5 median 12.5 third quartile 16 maximum 20

Step-by-step explanation:

Solving a system of equations we will see that Hari has 800 and Ram has 600.

Let's define the variables:

We know that:

(2/3)*R = (1/2)*H

We also know that in total they have 1400, then:

R + H = 1400.

So we have the system of equations:

(2/3)*R = (1/2)*H

R + H = 1400.

In the first equation we can isolate R.

R = (3/2)*(1/2)*H = (3/4)*H

Now we can replace that in the other equation:

(3/4)*H + H  =1400

H*(7/4) = 1400

H = (4/7)*1400 = 800

So Hari has 800, and:

R + H = 1400

R = 1400 - H = 1400 - 800 = 600

Hari has 800 and Ram has 600.

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The two positive numbers whose difference is 9 and whose product is 2950 are 50 and 59

As a general rule, it should be noted that positive numbers are numbers that have their value greater than 0

So, we start by representing the two positive numbers with x and y.

So, we have the following equations

x - y = 9

xy = 2950

Make x the subject in the first equation x - y = 9

x = y + 9

Substitute y + 9 for x in the second equation

(y + 9) * y = 2950

Expand the equation

y^2 + 9y - 2950 = 0

Using a graphing tool, we  have the solution of the above equation to be

y = 50

Recall that:

x = 9 + y

So, we have:

x = 9 + 50

Evaluate

x = 59

Hence, the two positive numbers whose difference is 9 and whose product is 2950 are 50 and 59

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A line segment can be defined as the part of a line in a geometric figure such as a parallelogram, that is bounded by two (2) distinct points and it typically has a fixed length.

In Geometry, a line segment can be measured by using the following measuring instruments:

A parallelogram refers to a geometrical figure (shape) and it can be defined as a type of quadrilateral and two-dimensional geometrical figure that has two (2) equal and parallel opposite sides.

Based on the previous experiment conducted in question 5, 6 and 7, we can logically conclude that the opposite sides of quadrilateral ABCD have the same (equal) slopes, which implies that the opposite sides are parallel. Hence, quadrilateral ABCD is simply a parallelogram by definition.

In this context, yes I would you reach the same conclusion that I reached in question 7 because the line segments that I drew represent the diagonals of a parallelogram.

Therefore, if the point of intersection of the diagonals divide each diagonal in half, then, the quadrilateral belonging to these diagonals forms a parallelogram.

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Answer: no real solution

Thus, the function has no x- intercept

Step-by-step explanation:

Answer:

22

Step-by-step explanation:

Answer: B: (1-5x²)³, all real numbers

Step-by-step explanation:

The notation [tex]f\circ g(x)[/tex] is called function composition, which is where you pass one function in as the value of another function. In other words, [tex]\( f\circ g(x)=f(g(x)) \)[/tex].

Since we have the values for f(x) and g(x), let's plug them in.

[tex]f(g(x))\\f(1-5x^2)\\(1-5x^2)^3[/tex]

Hence, the best answer choice is B, as all real numbers would work and it is the cube of 1 - 5x².

6,800 to get a total interest of Rs 6,800 and keep the balance for 3 years.

How long should she keep the remaining amount to get a total interest of Rs 6,800 from the beginning:

The rate of 8% p.a. in her saving account.

20,000 at 8% interest for 2 years:

= 20,000*2*8/100

= 3200

5000 was withdrawn after 2 years and earned interest.

After 2 years, the new principal:

= 20000- 5000

=15000

She needs to get interested of 6800–3200 =3600 for the next N years.

N= 100* I /PR

= 100*3600/(15000*8)

=3

6,800 to get a total interest of Rs 6,800 and keep the balance for 3 years.

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Sajina should keep the remaining amount for 3 years to get a total interest of Rs 6,800 from the beginning.

For the principal [tex]P[/tex] and the rate of interest [tex]r\%[/tex] per annum, the total interest after [tex]t[/tex] years is given by the formula: [tex]I=\dfrac{Prt}{100}[/tex].

Given that Sajina deposited Rs 20,000 at the rate of 8% p.a. in her savings account.

So, [tex]P=20,000[/tex] and [tex]r=8[/tex].

Thus, after t=2 years the total interest would be

[tex]I=\dfrac{Prt}{100}\\\Longrightarrow I=\dfrac{20000\times 8\times 2}{100}\\\therefore I=3200[/tex]

So, the total interest after 2 years would be Rs 3,200.

Given that Sajina withdrew Rs 5,000 and the total interest of 2 years.

So, the new principal will be [tex]P'=20,000-5,000=\test{Rs}\hspace{1mm}15,000[/tex].

The total interest she wanted to gain is Rs 6,800. She had already gained Rs 3,200.

so, the remaining interest [tex]I'=6,800-3,200=\text{Rs}\hspace{1mm}3,600[/tex].

Let the required time be [tex]t'[/tex] years after how many years she got a total interest of Rs 6,800 from the beginning.

For principal [tex]P'=15,000[/tex], rate of interest [tex]r=8\%[/tex]; the total interest after [tex]t'[/tex] years would be [tex]I'=\dfrac{P'rt'}{100}=\dfrac{15000\times 8\times t'}{100}=1200t'[/tex]. But given that [tex]I'=3600[/tex].

So, we must have

[tex]1200t'=3600\\\Longrightarrow t'=\dfrac{3600}{1200}\\\therefore t'=3[/tex]

Therefore, Sajina should keep the remaining amount for 3 years to get a total interest of Rs 6,800 from the beginning.

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[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

For two lines to be parallel, there should be angles that follow some specific properties that is usually observed with parallel lines.

We can clearly see that :

[tex] \qquad❖ \: \sf \: \angle7 \cong \angle16[/tex]

( by Alternate interior angle pair )

[tex] \qquad \large \sf {Conclusion} : [/tex]

Lines l and m are parallel to each other.

The statement that "σ(n) < 2n holds true for all n of the form n = p²" has been proved.

Let p be any prime number, and let σ(n) be the sum of all positive divisors of the integer n.

As p is a prime number, and 2 is the smallest prime number, so, p[tex]\geq[/tex]2

So, the positive divisors of the integer n are: 1,p,p².

As σ(n) represents the sum of all positive divisors of the integer n.

σ(n)=1+p+p²

In order to prove that σ(n) < 2n,for all n of the form n = p².

1+p+p²<2p²

p²-p-1>0

It is know that, p[tex]\geq[/tex]2.

So, p²-p-1[tex]\geq[/tex]1

Thus, σ(n) < 2n holds true for all n of the form n = p².

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Answer:

Fufusyyigywngd, hdj4snwhsjtc

Bahr Ltd flu not ld6wlw

Answer:[tex]\Large\boxed{(2+\sqrt{2},~2-\sqrt{x} )~~and~~ (2-\sqrt{2},~2+\sqrt{x} )}[/tex]

Step-by-step explanation:

Given the system of equations

[tex]1)~xy=2[/tex]

[tex]2)~x+y=4[/tex]

Divide x on both sides of the 1) equation

[tex]xy=2[/tex]

[tex]xy\div x=2\div x[/tex]

[tex]y=\dfrac{2}{x}[/tex]

Current system

[tex]1)~y=\dfrac{2}{x}[/tex]

[tex]2)~x+y=4[/tex]

Substitute the 1) equation into the 2) equation

[tex]x+(\dfrac{2}{x} )=4[/tex]

Multiply x on both sides

[tex]x\times x+\dfrac{2}{x}\times x=4\times x[/tex]

[tex]x^2+2=4x[/tex]

Subtract 4x on both sides

[tex]x^2+2-4x=4x-4x[/tex]

[tex]x^2-4x+2=0[/tex]

Use the quadratic formula to solve for the x value

[tex]x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(1)(2)} }{2(1)}[/tex]

[tex]x=2\pm\sqrt{2}[/tex]

Substitute the x value into one of the equations to find the y value

[tex]xy=2[/tex]

[tex](2+\sqrt{2} )y=2[/tex]

[tex]y=2-\sqrt{2}[/tex]

[tex]OR[/tex]

[tex]xy=2[/tex]

[tex](2-\sqrt{2} )y=2[/tex]

[tex]y=2+\sqrt{2}[/tex]

Therefore, the points of intersection are

[tex]\Large\boxed{(2+\sqrt{2},~2-\sqrt{x} )~~and~~ (2-\sqrt{2},~2+\sqrt{x} )}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

(2 - [tex]\sqrt{2}[/tex] , 2 + [tex]\sqrt{2}[/tex] ) and (2 + [tex]\sqrt{2}[/tex], 2 - [tex]\sqrt{2}[/tex] )

Step-by-step explanation:

xy = 2 → (1)

x + y = 4 ( subtract x from both sides )

y = 4 - x → (2)

substitute y = 4 - x into (1)

x(4 - x) = 2

4x - x² = 2 ( multiply through by - 1 )

x² - 4x = - 2

using the method of completing the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 2)x + 4 = - 2 + 4

(x - 2)² = 2 ( take square root of both sides )

x - 2 = ± [tex]\sqrt{2}[/tex] ( add 2 to both sides )

x = 2 ± [tex]\sqrt{2}[/tex] , that is

x = 2 - [tex]\sqrt{2}[/tex] , x = 2 + [tex]\sqrt{2}[/tex]

substitute these values of x into (2) for corresponding values of y

x = 2 - [tex]\sqrt{2}[/tex] , then

y = 4 - (2 - [tex]\sqrt{2}[/tex])

  = 4 - 2 + [tex]\sqrt{2}[/tex]

  = 2 + [tex]\sqrt{2}[/tex] ⇒ (2 - [tex]\sqrt{2}[/tex] , 2 + [tex]\sqrt{2}[/tex] ) ← 1 point of intersection

x = 2 + [tex]\sqrt{2}[/tex] , then

y = 4 - (2 + [tex]\sqrt{2}[/tex] )

   = 4 - 2 - [tex]\sqrt{2}[/tex]

   = 2 - [tex]\sqrt{2}[/tex] ⇒ (2 + [tex]\sqrt{2}[/tex] , 2 - [tex]\sqrt{2}[/tex] ) ← 2nd point of intersection

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

En esta pregunta debemos encontrar el volumen remanente entre el espacio de una caja cúbica y una esfera introducida en el elemento anterior. El volumen remanente es igual a sustraer el volumen de la pelota del volumen de la caja.

Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:

Cubo

V = l³

V = (4 cm)³

V = 64 cm³

Esfera

V' = (4π / 3) · R³

V' = (4π / 3) · (2 cm)³

V' ≈ 33.5103 cm³

Segundo, determinamos la diferencia de volumen entre los dos elementos:

V'' = V - V'

V'' = 64 cm³ - 33.5103 cm³

V'' = 30.4897 cm³

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

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1. To determine the better option between a 10% off coupon versus a $10 off coupon, it is necessary to determine the coupon price.

2. On the other hand, the $10 off coupon becomes better when the coupon price is less than $100.

3. The 10% off coupon and the $10 off coupon do not give the same amount of discount unless the coupon or list price is $100 in both situations.

A discount is a monetary reduction in the cost of a good or service offered to customers to increase trade.

Offering discounts enhances sales but not profitability.  So, there is a trade-off that must be considered properly.

Ordinarily, if the coupon price is more than $100, the 10% off coupon becomes better than the $10 off coupon.

For instance, if the coupon price is $110, the 10% off coupon will yield a discount amount of $11 ($110 x 10%), which is more than $10.

For instance, if the coupon price is $99, the discount amount will be $9.90, which is less than $10.

Thus, a 10% off coupon and a $10 off coupon do not offer the same discount amount unless the list price is $100, no more, no less.

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Compare the discounts you would receive with a 10% off coupon versus a $10 off coupon.

Answer: −2(