In a combustion chamber, ethane (c2h6) is burned at a rate of 9 kg/h with air that enters the combustion chamber at a rate of 176 kg/h. determine the percentage of excess air used during this process

The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.

a) Velocity of car A (Va) = 20m/s

Velocity of car B (Vb) = -6m/s

To find the Relative Velocity, we should apply the formula as,

Relative Velocity of car A and car B = Vab

Vab = Va - Vb

Vab = 20 - (-6)

Vab = 20+6

Vab = 26m/s

b). if Velocity of car A = Velocity of car B

Va = Vb

In this case,

Relative Velocity = Vab

Vab = Va - Vb

(since Va = Vb)

Vab = 0m/s

Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.

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Partial pressure of helium gas in the tank is 162.24 atm.

Partial Pressure:

A partial pressure is the imaginary pressure that a gas would have if it were to occupy the complete volume of the initial mixture by itself at the same temperature. Each gas in a mixture of gases has a partial pressure.

Explanation:

Total pressure in Heloix (P) = 208 atm

The mole fraction of an individual gas component in an ideal gas mixture can be expressed in terms of the component's partial pressure or the moles of the component

Mole fraction of oxygen (X₀) = 0.220

The sum of the mole fractions of all the components present must equal 1.

Mole fraction of helium (Xₐ) = 1-(X₀) = 1- 0.220= 0.78

According to Dalton's law of partial pressure.

Partial pressure of an individual gas component in an ideal gas can be obtained using this expression:

Partial pressure of oxygen gas in Heloix: P*X₀ = 208 * 0.22 = 45.76 atm

Partial pressure of helium gas in Heloix: P*Xₐ = 208 * 0.78 = 162.24 atm

Partial pressure of helium gas is 162.24 atm.

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Answer:

6molO2 3/2O22Fe=4,5024molFe .

Explanation:

You have to start with the balanced chemical equation. Iron is just Fe. Oxygen in nature is found as an O2 molecule.

2Fe(s)+3/2O2(g) Fe2O3(s)

If you check the balance. There are two Fe on both sides of the equation and three O on both sides, so it’s balanced.

Now use the stoichiometric ratios (the coefficients of the balanced chemical equation) to convert 6 mol of oxygen to iron.

6molO2 3/2O22Fe=4.5024molFe .

These coefficients can be used as conversion factors when it comes to substance moles.

Some of you may insist that a balanced chemical reaction must have whole numbers. This is not really necessary. The reaction I wrote above is a named type of reaction, called Fe2O3 formation. In this type of reaction, there must be a mole of product so that it requires that sometimes there are fractional numbers for the coefficients in the reagents.

But, just for the argument, let’s rebalance the equation for integer coefficients only.

4Fe(s)+3O2(g) 2Fe2O3(s)

We are now using the coefficients as conversion factors, as we have done before.

Taking into account the definition of molarity, the molarity of the solution is 8 M.

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

In this case, you know:

Replacing in the definition of molarity:

[tex]Molarity=\frac{2 moles}{0.250 L}[/tex]

Solving:

Molarity= 8 [tex]\frac{moles}{liter}[/tex]= 8 M

Finally, the molarity of the solution is 8 M.

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The lead (Pb) in the lead storage battery act as an anode

What is Voltaic Cell?

A voltaic cell or galvanic cell is an electrochemical cell that uses chemical reactions to produce electrical energy.

Parts of voltaic cell

In lead storage battery, the following reactions occur:

At anode:

[tex]Pb(s) + H_2SO_{4} + H_2O(l) \rightarrow2e^- + PbSO_{4} (s) + H_3O^+(aq)[/tex]

At Cathode:

[tex]PbO_2(s) + H_2SO_4(aq) + 3H_3O+(aq) + 2e^- \rightarrow PbSO_4(s) + 5H_2O(l)[/tex]

Overall reaction:

[tex]Pb(s) + PbO_2(s) + 2H_2SO_4 (aq.) \rightarrow PbSO_4(s) + 2H_2O(l)[/tex]

Hence, Pb acts as an anode and [tex]PbO_2[/tex] as a cathode.

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Answer:

sublimation because it's has changed from solid to gaseous

Answer:

67° C   increase

Explanation:

235 gm   *   4.186 J /g-C  *    x     =  66 000 J          x = degree change C°

x = 67 degrees C

A precipitation reaction exists in which dissolved substances react to create one (or more) solid products.

A precipitation reaction exists in which dissolved substances react to create one (or more) solid products. Many reactions of this kind concern the exchange of ions between ionic compounds in an aqueous solution and exist sometimes directed as double displacement, double replacement, or metathesis reactions.

A precipitation reaction exists as a chemical reaction happening in an aqueous solution where two ionic bonds integrate, resulting in the construction of an insoluble salt which is named precipitates.

Some examples exist reactions between calcium chloride (CaCl2) and potassium hydroxide(KOH), which result in the appearance of calcium hydroxide which stands as an insoluble salt. The reaction between silver nitrate (AgNO3) and sodium chloride (NaCl), results in the construction of silver chloride (AgCl) exists an insoluble salt.

In an aqueous solution, precipitation stands the procedure of converting a dissolved substance into an insoluble solid from a super-saturated solution. The solid formed exists named the precipitate.

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It is Cobalt(II)chloride dihydrate. The value of x is 2.

First, we have to determine the mass of H₂O that was evaporated upon heating which will be = 2.00g - 1.56 g

                                 = 0.435 g

So,

CoCl₂ + x.H₂O → CoCl₂.xH₂O

Molecular mass of CoCl₂ = 129.839 g/mol

Molecular mass of H₂O = 18 g/mol

Weight of sample after heating = 1.565 g

Weight of H₂O evaporated = 0.435 g

Hence,

           [tex]18x = \frac{129.839X0.435}{1.565} \\x = \frac{55.48}{28.17} \\x = 1.9[/tex]

           x ≈ 2

So, it is Cobalt(II)chloride dihydrate.

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Electrical resistivity is the measure of the material that can resist the electrical charge. The resistance of the copper wire at 80°C will be 146.43 Ω. Thus, option E is correct.

Electrical resistance is defined as the opposing force that counteracts the electrical charge flow in the material. It is expressed in the terms of the ohms (Ω).

Resistance is calculated as,

R₈₀ = R₀(1 + αΔT)

Given,

Temperature coefficient of resistance (α) = 0.0068 °C⁻¹

ΔT = 60°C

Resistance of a wire (R₀) at 20° C = 104 Ω

Resistance of a wire (R₈₀) at 80°C =?

Substituting values above:

R₈₀ = (104 )[1 + (0.0068)(60)]

R₈₀ = 146.43 Ω

Therefore, option E. 146.43 Ω is the resistance of the copper wire at 80°C.

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Your question is incomplete, but most probably your full question was, The temperature coefficient of resistivity for copper is 0.0068 °C⁻¹. If a copper wire has a resistance of 104 Ω at 20°C, what is its resistance at 80°C?

In an acid-base neutralization reaction, the equilibrium reaction would be between a weak base and its conjugate strong base. So, this must be the basis of the volume of added base.

pH is used to measure whether the substance is acidic, basic or neutral and the range is 0 - 14.

Neutralization reaction is a chemical reaction in which an acid and a base react quantitatively with together.

Neutralization reaction equation:

Acid + Base → Salt + Water

Thus from the above conclusion we can say that In an acid-base neutralization reaction, the equilibrium reaction would be between a weak base and its conjugate strong base. So, this must be the basis of the volume of added base.

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Urine color is the most effective method for measuring hydration status before and after exercise

Urine color is yellow color from a pigment called urochrome or urobilin. Darker pee contains less fluid, whereas lighter urine is more diluted. Dehydration may be indicated by very black urine. Don't worry if your urine doesn't match the color scheme.

Normal urine color is a pale yellow, however light amber is also acceptable. If your pee appears dark amber, you may be dehydrated and should drink additional water to compensate. Urine naturally contains yellow pigments known as urobilin or urochrome. The darker the pee, the more concentrated it is. Dehydration is the most common cause of dark urine color

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Mendeleev positioned elements in the periodic table in increasing order of their atomic numbers, such that elements having identical chemical properties and characteristics plunge into the same group.

What is Mendeleev's periodic table called?

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1. I think r0b a bank would be such a rush. Imagine r0b a bank, driving a souped up getaway vehicle, and then successfully escaping with loads of cash...., that would be such an adrenaline rush.

2. Nationwide animal release. Just ninja into pounds and shelters and set them all free. It'd get to the point that they'd have to get armed guards. Soon wild packs of pugs and Chihuahuas roam freely claiming their territory against man.

3. Putting glitter bombs in mailboxes. Not sending but personally taping it in there so it goes off when opened.

The descriptive term that is applied to the type of diene represented by 1,5-octadiene is isolated diene. The correct option is C.

Diene is a compound that contains two or more double bonds, usually  carbon bonds, which are separated by a single bond. They are covalent compounds. Alkene units are surely present in these compounds, whose quantity is two.

1,5-octadiene is a polymer of diene, which are generally elastomers, and they made of vulcanized rubber. They are isolated diene.

Thus, the correct option is C) Isolated diene.

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The question is incomplete. The complete question is given below:

A) Conjugated diene.

B) Cumulated diene.

C) Isolated diene.

D) Alkynyl diene.

E) None of the above.

When using ion-selective electrodes, to compensate for a complex or unknown matrix, the  standard addition method can be used to determine the analyte concentration. Option D

Analytical chemistry is a science that deal with the measurement and detection of the accurate amount of a substance. Analytical chemistry plays a large role in environmental management as it helps in the determination of the levels of contaminants in a sample.

An ion selective electrode is used in analytical chemistry to measure the amount of a target ion by converting its activity into a measurable electrical signal.

Hence, when using ion-selective electrodes, to compensate for a complex or unknown matrix, the  standard addition method can be used to determine the analyte concentration.

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Final temperature of the solution formed is 50.93ºC

As we know,

heat = mass x specific heat x change in temperature

q = mC∆T

where, m = 111 g water

             C = 4.184 J/g/deg

             ∆T = ?

To find heat we need to first find moles Libr used in this reaction:

21.4 g Libr x 1 mole/86.84 g = 0.246 moles

Therefore,

q = 0.246 moles x (-48.8) kJ/mol = -12.00 kJ = -12000 J (since it is negative, this indicates an exothermic reaction, so temperature of solution will increase).

-12000 J = (111g)(4.184 J/g/deg)(∆T)

∆T = -25.83 degrees

Final temperature = 25.1º - (-25.83º) = 50.93ºC

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Considering the definition of pH, the hydronium ion concentration [H₃O⁺] of the solution is  1×10⁻³ M.

pH is the Hydrogen Potential. It is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:

pH= - log [H⁺]= -log [H₃O⁺]

The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.

In this case, being pH= 3, you can replace this value in the definition of pH:

3= -log [H₃O⁺]

Solving:

[H₃O⁺]= 10⁻³ M

[H₃O⁺]= 1×10⁻³ M

Finally, the hydronium ion concentration [H₃O⁺] of the solution is  1×10⁻³ M.

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The highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given as ,

The mechanism of solvolysis of tert-butyl iodide follow nucleophilic substitution reaction . The nucleophilc substitution reaction are two types one unimolecular and second bimolecular  nucleophilc substitution .

The mechanism of solvolysis of tert-butyl iodide follows unimolecular nucleophilic substitution reaction in which carbocation is the intermediate which as a transition state of it. The carbocation formed by  solvolysis of tert-butyl iodide is 3° carbocation or tertiary carbocation which is most stable. The methanol as neutral nucleophile and oxygen of methanol  attack at carbocation intermediate.

Therefore , the highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given .

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Answer:

D. carbohydrate, blue-purple

Explanation:

Carbohydrates are one of many types of macronutrients found in certain foods and drink. For example, sugars, starches, and fibers are carbohydrates.

When starch is present, using an iodine solution will turn it blue-black or purple. If starch is NOT present, it will stay orange or yellow. The reason starch reacts with iodine is due to the amylose present in starch. Iodine is not soluble in water, so it's dissolved along with potassium iodide that forms a triiodide molecule. That then enters the helical structure of amylose and changes its color.

Answer:The particles move faster, and their average kinetic energy decreases.

Explanation:

Answer:

A

Explanation:

Isotopes are atoms of the same element with the same number of protons and electrons but different numbers of neutrons.

Isotopes can also be defined as atoms of the same element with the same atomic number but different mass numbers e.g isotopes of chlorine, oxygen and so on.Oxygen for instance has three isotopes with the same atomic number,8 and different mass numbers,16,17 and 18.

Platinum has a face-centered cubic crystal structure and a density of 21.5 g/cm^3. The radius of the platinum atom is 139pm.

The radius of the platinum atom can be found by the relation of density and radius of atom.

Platinum has a face-centered cubic (fcc) crystal structure which means that 4 atoms are present in each structure.

Hence no. of atoms, Z=4

The radius of atom can be found out by substitution in the below formula:

Relation of density and radius of atom:

Density, d = Z × M / Nₐ × a³    

∴ where, Z is the no. of atoms = 4                

M is the Molecular mass of platinum = 195 g/mol    

 N is the Avogadro's number = 6 × 10²³ / mol                

 a is the radius of the atom = ?                

d is the density = 21.5 g/cm³

⇒ a³ = Z × M / Nₐ × d

⇒ a³ = 4 × 195 / 6 × 10²³ ×  21.5

⇒ a = 139 × 10⁻¹²m

a = 139pm

Hence, the radius of the platinum atom is 139pm.

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The answer is 139pm

The relationship between density and radius of an atom may be used to calculate the radius of a platinum atom.

Platinum has a face-centred cubic (fcc) crystal structure, which implies that each structure has four atoms.

As a result, the number of atoms is Z=4.

Substitution in the following formula yields the radius of an atom:

Atomic density and radius relationship:

Density,[tex]$d=Z \times M / N_{a} \times a^{3}$[/tex]

[tex]$\therefore$[/tex] where, Z is the no. of atoms =4

[tex]$\mathrm{M}$[/tex] is the Molecular mass of platinum [tex]$=195 \mathrm{~g} / \mathrm{mol}$[/tex]

[tex]$\mathrm{N}$[/tex]is the Avogadro's number [tex]$=6 \times 10^{23} / \mathrm{mol}$[/tex]

a is the radius of the atom = ?

[tex]$\mathrm{d}$[/tex] is the density [tex]$=21.5 \mathrm{~g} / \mathrm{cm}^{3}$[/tex]

[tex]$$\begin{aligned}&\Rightarrow a^{3}=Z \times M / N_{a} \times d \\&\Rightarrow a^{3}=4 \times 195 / 6 \times 10^{23} \times 21.5 \\&\Rightarrow a=139 \times 10^{-12} m \\&a=139 p m\end{aligned}$$[/tex]

What is platinum atom?

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The partner that is used along with benzaldehyde is acetophenone to yield  1,3-Diphenylprop-2-en-1-one.

In adol condensation, aldehydes or ketones having α - H atoms undergo condensation in the presence of a dilute alkali to form β - hydroxy aldehydes or ketones.

Under mixed or crossed adol condensation,

undergoes condensation in the presence of dilute alkali to form a mixture of β - hydroxy aldehyde or ketone.

The following reaction takes place:

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Mixed aldol condensations involving benzaldehyde yield typically a single product. draw the structure of the partner that was used to synthesize this molecule:

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There is  200 milliosmolarity of a 0. 2 m glucose solution, assuming that the atoms in a glucose molecule are held together by covalent bonds .

Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution. Dilution is a process of decreasing the concentration of a solution by adding a number of solvents

Calculation ,

The molarity of the glucose = 0.2 M

the mili means [tex]10^{-3}[/tex] of any unit.

So , the 1mM =  1 × [tex]10^{-3}[/tex] M

So ,  0.2 M  =  0.2/ [tex]10^{-3}[/tex] M = 0.2 × [tex]10^{3}[/tex] = 200 mM

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The equation described by the kb value is 5.21 x [tex]10^-^3[/tex].

The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.

Assuming  PO₄³⁻ (the phosphate anion).

PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻

Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]

We can find the [OH⁻] from the pH of 12.70.

pH + pOH = 14

14.0 - 12.7 = 1.3 = pOH

[OH] = 1x[tex]10^-^1^.^3[/tex]

[OH-] = 5.0x[tex]10^-^2[/tex] M

[HPO₄²⁻] = 5.0x[tex]10^-^2[/tex] M

Kb = (5.0x[tex]10^-^2[/tex])2 / 0.48

     = 2.5x[tex]10^-^3[/tex] / 0.48

Kb = 5.21 x [tex]10^-^3[/tex]

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The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.

Calculation,

Given data,

Mass of the ice = 10 g

Temperature of ice =  0. 0°C

Heat required at this stage = mas of the ice ×latent heat of fusion of ice

Heat required at this stage = 10 g×80 = 800 cal  

Heat required for this = mass of the ice×rise in temperature×specific heat of water

Heat required for this  = 10 g×100× 1 = 1000 cal

Heat required for this = Mass of water× latent heat

Heat required for this  = 10g ×536 =5360 cal

Total energy or heat required = sum of all heat = 800 +1000+ 5360  = 7160 cal

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The molarity of the solution is 0.43 M

What is molar concentration or molarity?

Calculation of molarity:

Initially, we must change grams of hydrogen chloride into moles.

Moles of solute per L of solution are known as molarity.

                        M = n/v

where, M=molar concentration,

n = moles of solute,

v= litres of solution

We must divide by the molecular mass to go from grams to moles.

5.20 g of HCl * (1 mole/36.46 g of HCl) = 1.14 moles of HCl

3.0 L x 0.143 moles = 0.429 M HCl ≈ 0.43 M HCl

Therefore it is concluded from the above solution that the molarity of the solution is 0.43 M HCl.

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Answer:

sorry i don't know this question of answer

The amount of charge required to reduce Zn²⁺ to Zn is 1585.26 coulomb.

The process that has been equipped with the use of electric current to break the chemical compound and deposited at the constituent electrodes is termed as electrolysis.

The reaction of reduction of Zn can be given as:

Zn²⁺ + 2e⁻ → Zn (s)

Molar mass of Zn = 65.39 g

The equivalent of Zn²⁺ has been:

Equivalent = atomic mass/equivalent weight

Equivalent Zn²⁺ = 65.39/32.69

Equivalent Zn²⁺ = 2 mol

1 equivalent = 1 F charge used

2 mol equivalent = 2 F charge used

Charge in coulomb can be given as:

1 Faraday = 96500 coulomb

2 F = 96500 * 2 coulomb

2 F = 1,93,000 coulomb

The moles of Zn to be deposited is:

Moles = weight /molar weight

Moles = 0.5371 g/ 65.39 g/mol

Moles = 0.00821 mol

Therefore, the charge used for the deposition of 0.00821 mol is:

Charge = 0.00821 * 1,93,000 coulomb

Charge = 1585.26 coulomb

1585.26 coulomb charge was used to reduce the Zn²⁺ to Zn.

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