I'm not sure how to do both of them

**Disclaimer** Hi there! I am not fully sure what [ T ] represents. From the answer that I got [ 38π / 3 ], it does not match any one of them, so I choose none of the above. If there's a specific meaning of [ T ] and I am incorrect, please let me know and I will modify my answer.

Answer: None of above

Step-by-step explanation:

Given formula

S = r θ

Given information

radius = 19 ft

Angle = 2π / 3

Substitute values into the formula

S = r θ

S = (19) (2π / 3)

Simplify by multiplication

[tex]\Large\boxed{S=\frac{38\pi}{3} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

The correct statements about the solids are:

To find which statements are correct:

Congruent base: This is used to indicate that the triangles' bases are the same and that they have the same shape.

The volume of the first triangle is: [tex]2x^{2} h[/tex]

The volume of the second triangle is: [tex]x^{2} h[/tex]

Therefore, the correct statements about the solids are:

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The complete question is given below:
One rectangular solid with a square base has twice the height of another rectangular solid with a square base with the same side length. Which statements about the two rectangular solids are true? Check all that apply.

A) The bases are congruent.

B) The solids are similar.

C) The ratio of the volumes of the first solid to the second solid is 8:1.

D)The volume of the first solid is twice as much as the volume of the second solid.

E) If the dimensions of the second solid are x by x by h, the first solid has 4xh more

surface area than the second solid.

Answer:

b 19.2

Step-by-step explanation:

a = [tex]\pi[/tex][tex]r^{2}[/tex] for a circle.  We do not want to find the area for a whole circle.  We only want to find the area for part of a circle.  a hole circle is 360 degrees.

a = [tex]\frac{88}{360}[/tex][tex]\pi[/tex][tex]r^{2}[/tex]

a = [tex]\frac{88}{360}[/tex][tex]\pi[/tex]([tex]5^{2}[/tex])

a = 19.2 rounded.

The area of the sector of circle is b. 19.20 square meter.

The space enclosed by the sector of circle is called area of the sector of circle.Mathematically,

Area of the sector of circle, A = θ/360πr²

where θ is the angle of the arc and r is the radius of the circle.

Now it is given that,

radius of the circle, r = 5m

Angle of arc, θ = 88°

Therefore, area ofsector of circle A = θ/360πr²

Put the values,

A = 88/360 π 5²

Solving the equation we get

A = 19.20 square meter.

Hence,the area of the sector of circle is b. 19.20 square meter.

So  the correct answer is b.) 19.20 square meter.

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The number of additional days she wants to rent the car for the two specials are equivalent is 5 days.

Compact car:

y = 50 + 6x

Another special:

y = 40 + 8x

let

x = number of additional days

50 + 6x = 40 + 8x

50 - 40 = 8x - 6x

10 = 2x

x = 10/2

x = 5 days

Therefore, the number of additional days she wants to rent the car for, the two specials are equivalent is 5 days.

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The solution to the system of equations is x = 1, y = 10 and z = 4

The system of equations is given as:

3x +2y +4z = 11

2x -y +3z = 4

5x -3y +5z = -1

Multiply the second equation by 2

So, we have

4x - 2y + 6z = 8

Add this equation to the first equation

3x + 4x + 2y - 2y + 4z + 6z = 11 + 8

Evaluate the like terms

7x + 10z = 19

Multiply the second equation by 3

So, we have

6x - 3y + 9z = 12

Subtract this equation from the third equation

6x - 5x - 3y + 3y + 9z - 5z = 12 + 1

Evaluate the like terms

x + 4z = 13

Make x the subject

x = 13 - 4z

Substitute x = 13 - 4z in 7x + 10z = 19

7(13 - 4z) + 10z = 19

Expand

91 - 28z + 10z = 19

Evaluate the like terms

-18z = -72

Divide

z = 4

Substitute z = 4 in x = 13 - 4z

x = 13 - 4 * 4

Evaluate

x = 1

We have:

2x -y +3z = 4

This gives

2(1) - y + 3 * 4 = 4

Evaluate

2 - y + 12 = 4

This gives

y = 10

Hence, the solution to the system of equations is x = 1, y = 10 and z = 4

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The median value is 63 and Lower quartile range is 48 and Interquartile range is 80.

According to the given statement

we have given data set and we have to find the five number summary.

So, For this purpose,

the given data set is:

48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80

Firstly we have to find the upper quartile means median for it.

So, Median = n /2

median = 12/2

median = 6th term.

So, Upper quartile range for this data set is 63.

And

Lower quartile for data set is the lower value of the data set.

So, That's why

Lower quartile range for this data set is 48.

And now, we have to find the Interquartile range

so, Interquartile range means maximum value of data.

So, That's why

Interquartile range of this data is 80.

So, The median value is 63 and Lower quartile range is 48 and Interquartile range is 80.

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Answer:

A.

Sample 1 mean: 6.375

Sample 2 mean: 6.375

Sample 3 mean: 6.625

B.

Range of sample means: 0.25

C.

The first and last boxes should be checked, as they are true.

Step-by-step explanation:

To calculate the mean you must add all of the numbers together and then divide the sum by the quantity of numbers. Ex: 3+7+8+3+7+9+6+8 = 51.

51/8 = 6.375.

The first five terms of the sequence with the given nth term are 1, 3/2, 3/2, 9/8, 27/40.

In this question,

The nth term of the sequence is [tex]a_n=\frac{3^{(n-1)} }{n!}[/tex]

Now substitute the values of n = 1,2,3,4,5

For n = 1,

⇒ [tex]a_1=\frac{3^{(1-1)} }{1!}[/tex]

⇒ [tex]a_1=\frac{3^{0} }{1}[/tex]

⇒ a₁ = 1

For n = 2,

⇒ [tex]a_2=\frac{3^{(2-1)} }{2!}[/tex]

⇒ [tex]a_2=\frac{3^{(1)} }{(1)(2)}[/tex]

⇒ [tex]a_2=\frac{3}{2}[/tex]

For n = 3,

⇒ [tex]a_3=\frac{3^{(3-1)} }{3!}[/tex]

⇒ [tex]a_3=\frac{3^{(2)} }{(1)(2)(3)}[/tex]

⇒ [tex]a_3=\frac{9}{6}[/tex]

⇒ [tex]a_3=\frac{3}{2}[/tex]

For n = 4,

⇒ [tex]a_4=\frac{3^{(4-1)} }{4!}[/tex]

⇒ [tex]a_4=\frac{3^{(3)} }{(1)(2)(3)(4)}[/tex]

⇒ [tex]a_4=\frac{27}{24}[/tex]

⇒ [tex]a_4=\frac{9}{8}[/tex]

For n = 5,

⇒ [tex]a_5=\frac{3^{(5-1)} }{5!}[/tex]

⇒ [tex]a_5=\frac{3^{(4)} }{(1)(2)(3)(4)(5)}[/tex]

⇒ [tex]a_5=\frac{81}{120}[/tex]

⇒ [tex]a_5=\frac{27}{40}[/tex]

Hence we can conclude that the first five terms of the sequence with the given nth term are 1, 3/2, 3/2, 9/8, 27/40.

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Answer:

Resistance

Step-by-step explanation:

The first five terms of the given arithmetic sequence are:

54, 45, 36, 27, 18 (First option)

The arithmetic sequence is given as follows,

f(n) = f(n-1) - 9 ............ (1)

Also, f(1) = 54 .............. (2)

Now, for finding the first five term of this arithmetic sequence, we will substitute n as 1, 2, 3, 4, and 5 one by one. Using the above formula for the arithmetic sequence, we can deduce the first five terms.

f(1) is the first term of the sequence which is already provided as 54.

Now, putting n=2 in equation (1), we get,

f(2) = f(2-1) - 9

f(2) = f(1) - 9

Substitute f(1) = 54 from equation (2)

⇒ f(2) = 54 - 9

f(2) = 45

To find the third term of the arithmetic sequence, put n = 3 in equation (1)

f(3) = f(3-1) - 9

f(3) = f(2) - 9

⇒ f(3) = 45 - 9

f(3) = 36

Similarly, we can find the fourth and fifth terms of the arithmetic sequence by substituting n = 4 and n = 5 respectively.

∴ f(4) = f(3) - 9

⇒ f(4) = 36 - 9

f(4) = 27

Likewise, f(5) = f(4) - 9

⇒f(5) = 27 - 9

f(5) = 18

Thus, using the recursive formula, the first five terms of the arithmetic sequence are deduced to be:

54, 45, 36, 27, 18

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The tangential speed of the satellite above the Earth's surface is [tex]7.588 * 10^{3} m/s[/tex].

The tangential speed of a satellite at the given radius and time is calculated as follows:

[tex]v=\frac{2\pi *(150*10^{3}+6371*10^{3} }{90*60} \\v=7.588*10^{3} m/s[/tex]

Therefore, the tangential speed of the satellite above the Earth's surface is [tex]7.588 * 10^{3} m/s[/tex].

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The correct question is shown below:
Consider formula A to be v = and formula B to be v2 = G. Write the letter of the appropriate formula to use in each scenario. Determine the tangential speed of the moon given the mass of Earth and the distance from Earth to the moon. Determine the tangential speed of a satellite that takes 90 minutes to complete an orbit 150 km above Earth’s surface.

Answer: first box is B

second box is A

Explanation:

right on edge as of 2022

The solution accurate to equation within [tex]10^{-2}[/tex] for [tex]x^{4}-2x^{3} -4x^{2} +4x+4=0[/tex] lies in [0,2].  

Given the equation  [tex]x^{4}-2x^{3} -4x^{2} +4x+4=0[/tex] and range is  [tex]10^{-2}[/tex].

We are required to find the interval in which the solution lies.

The attached table shows the iterations. At each step, the interval containing the root is bisected and the function value at the mid point of the interval is found. The sign of its relative to the signs of the function values at the ends of the interval tell which half interval contains the root. The process is repeated until the interval width is less than [tex]10^{-2}[/tex].

Interval:[0,2], signs [+,-],mid point:1, sign at midpoint +.

[1,2]                                                       3/2

[1,3/2]                                                    5/4

The rest is in the attachment. The listed table values are the successive interval mid points.

The final midpoint is 181/128=1.411406.

This solution is within 0.0002 of the actual root.      

Hence the solution accurate to equation within [tex]10^{-2}[/tex] for [tex]x^{4}-2x^{3} -4x^{2} +4x+4=0[/tex] lies in [0,2].

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Answer:

Option 2

Step-by-step explanation:

Using the quadrstic formula,

[tex]\tan \theta=\frac{-2 \pm \sqrt{2^2 - 4(\sqrt{3})(-\sqrt{3})}}{2\sqrt{3}} \\ \\ =\frac{-2 \pm 4}{2\sqrt{3}} \\ \\ =\frac{-1 \pm 2}{\sqrt{3}} \\ \\ = -\sqrt{3}, \frac{1}{\sqrt{3}}[/tex]

Case 1

[tex]\tan \theta=-\sqrt{3} \implies \theta=\frac{2\pi}{3}, \frac{5\pi}{3}[/tex]

Case 2

[tex]\tan \theta=\frac{1}{\sqrt{3}} \implies \theta=\frac{\pi}{6}, \frac{7\pi}{6}[/tex]

Answer:

its the 4th one i think

Step-by-step explanation:

The missing length of given right triangle is equal to 1500.

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean  Theorem.

The Pythagorean Theorem says: [tex]hypotenuse^2=(leg_1)^2+(leg_2)^2[/tex] . And the main trigonometric ratios are: sin (x),  cos (x) and tan (x) , where:

[tex]sin(x)=\frac{opposite\ side}{hypotenuse} \\ \\ cos(x)=\frac{adjacent\ side}{hypotenuse} \\ \\ tan (x)= \frac{opposite\ side}{adjacent\ side}[/tex]

There is another important property, where h²=m*n. See the attached image.

From the previous informations presented, you can solve the given question.

Thus, if h²=m*n. You can write:

h²=900*1600

[tex]h=\sqrt{1440000}\\ \\ h=1200[/tex]

If h=1200, you can find x from Pythagorean  Theorem.

x²=1200²+900²

x²=1440000+810000

x²=2250000

x=[tex]\sqrt{2250000}[/tex]

x=1500

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Just me:

? I will just explain what I understand

Answer:

(Think hard) If you cut a snake in half you get 1/2 but if you cut it into 4's 1/5

I tried.

The predicted value (in dollars) for maintenance expenses when a truck is 7 years old is $626.3.

In this question,

The equation for least regression line to this data set is

y' = 76.82x + 88.56 ------- (1)

Number of years, x = 7

The general form of equation for least regression line is

y' = a + bx

where y is the dependent variable, x is the independent variable, a is the intercept of regression line and b is the slope of regression line.

The predicted value (in dollars) for maintenance expenses when a truck is 7 years old can be calculated as

y' = 76.82x + 88.56

Substitute the value of x in the above equation, we get

y' = 76.82(7) + 88.56

y' = 537.74 + 88.56

y' = 626.3

Hence we can conclude that the predicted value (in dollars) for maintenance expenses when a truck is 7 years old is $626.3.

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The value of r = 9.078.

pv = nrt. The factor “r” in the ideal gas law equation is known as the “gas constant”. r = [tex]\frac{pv}{nt}[/tex]. The pressure times the volume of a gas divided by the number of moles and temperature of the gas is always equal to a constant number.

so the student weights out .0422 grams of the magnesium metal so from here we can calculate that more's, the magnesium that he used, that is the mass of the magnesium over the more mass, which is .024422 over 24 point. That's equal to about .001758. More so also, it says the magnesium metal is react with excessive hydrochloric acid and produce hydrogen gas. A sample of the hydrogen gas is collected over water in a meter at 22 cecr, the volume of clictic gas is 43.9 and mastic pressure. Is that so using the experimental and collected data calculated are in the percent error? So we know the magnesium react with hydrochloride. The reaction ratio is 1 to 2 and we produce 1. More is the hydrogen and 1. More is magnesium chloride. So from this equatium we know that more of the hydrogen that would be produced in this case is equal to the mass of the magnesium here, that's his .001758 more and set way. There's among hydrogen. The temperature is 32 (degree celcius) which we need to convert the unit into kelvin, so it's actually about field 5.15 kelvin and tells you. The volume of the gas is 43.9 in ml, which is .0439 liter and tells you the pressure of the gas is about 832 millimeter. Mercury, which is a 2 times 13332 plus ca, that's equal to about 110922.24 par. So in this case we know p v = n r t.

r = [tex]\frac{pv}{nt}[/tex]

So p = 110922.24. V = 0.0439 , n = 0.001758 t =  305.15. So let's just do the calculations here.

In this case you will find r=?

Here it's about 9.078.

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The correct student's t- distribution requires knowing the degrees of freedom. The degrees of freedom are there for a sample of size n is B) n-1.

Distribution is described as the technique of having items to consumers. An instance of distribution is rice being shipped from Asia to the USA. The frequency of occurrence or quantity of lifestyles.

Distribution manner to spread the product for the duration of the market such that a big quantity of humans should purchase it. Distribution involves doing the following matters. An amazing delivery machine to take the goods into one-of-a-kind geographical regions.

Distribution is one of the four elements of the advertising and marketing mix. Distribution is the method of creating a service or product available for the consumer or enterprise user who needs it. this may be executed without delay through the manufacturer or service company or the usage of indirect channels with vendors or intermediaries.

Disclaimer: The question is incomplete. Please read below to find the missing content.

Question: To select the correct Student's t-distribution requires knowing the degrees of freedom. How many degrees of freedom are there for a sample of size n?

A) n

B) n-1

C) n+1

D) [X - μ / (s / n)]

The degrees of freedom depends on the number of parameters you are estimating.

8=

i-1

In student t distribution we estimate the population mean through sample mean and population standard deviation through sample standard deviation

So here both parameters depend on the sample mean i.e. we just calculate from a sample of size n so

Degrees of freedom for students t distribution is B) n-1

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[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: (h - g)(x) [/tex]

[tex]\qquad \sf  \dashrightarrow \: h(x) - g(x) [/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + 2x - 6 - (2 {x}^{2} + 3x - 9)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + 2x - 6 - 2 {x}^{2} - 3x + 9[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} - 2 {x}^{2} + 2x - 3x - 6 + 9[/tex]

[tex]\qquad \sf  \dashrightarrow \: - {x}^{2} - x + 3[/tex]

For, (h - g)(2.1), put x = 2.1

[tex]\qquad \sf  \dashrightarrow \: - {(2.1)}^{2} - (2.1) + 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 4.41 - 2.1 + 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 6.51 + 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 3.51[/tex]

Answer:x=5

Step-by-step explanation: 73+73+6x+4=180

150+6x=180

6x=30

x=5

Answer:

The graph of g(x) has a y-intercept at (0,0) and a slope of -2.

Answer: 4/10, 6/15, 8/20

Hope this helps!

Answer:

y = 8x+7

Step-by-step explanation:

firstly reduce the equation to an arithmetic series starting from the 0th term so:
7, 15, 23, 31, 39....

Secondly, identify the common difference: 8
we now know that the answer must contain 8x

Thirdly, form the equation 8x + c = y where y is a constant. Afterwards insert the values of any given x and y so:
8*0 + c = 7
c = 7
Thusly we now know that the series and thus equation is 8x+7 = y

Answer:

y = 8x + 7

Step-by-step explanation:

the equation of a linear function in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2-y_{1} } }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (1,15) and (x₂, y₂ ) = (2, 23) ← 2 ordered pairs from the table

m = [tex]\frac{23-15}{2-1}[/tex] = [tex]\frac{8}{1}[/tex] = 8

the ordered pair (0, 7 ) indicates c = 7

y = 8x + 7 ← equation of linear function

The Option A is correct. The Numbers of Miles Driven for A Truck That Cost a Total Of $42.50 To Rent for One Day $25m + 0.35m = $42.50

According to the statement

we have given that the  Rental Truck Is Company Charges $25 Per Day Plus A Fee Of $0.35 For Every Mile (m) Driven. and a Truck That Cost A Total Of $42.50 To Rent For One Day.

And we have to find the equation for this.

So, for given purpose,

we know that the A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

And from the given values the equation formed that the

In the equation the charges per mile is added to the original charges is equal to the total charges per day.

So, The equation become

$25m + 0.35m = $42.50

And by this equation we represent the all given conditions related charges.

So, The Option A is correct. The Numbers of Miles Driven for A Truck That Cost a Total Of $42.50 To Rent for One Day $25m + 0.35m = $42.50

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The difference in mail handled between 195 and 1965 is -5.4 x 10

The data on the pieces of mail handled by the United States Postal Service is written in scientific notation. Scientific notation is used to compress larger numbers into smaller numbers.

In order to write a number in scientific notation, the number is written as a decimal number, between 1 and 10 and multiplied by a power of 10. For example, 1 x 10² is equivalent to 100

Difference in mail handled = mail handled in 1995 - mail handled in 1965

(1.8 x [tex]10^{11}[/tex]) - (7.2 x [tex]10^{10}[/tex])

(1.8 - 7.2)  x [tex]10^{11 - 10}[/tex]

-5.4 x 10

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Step-by-step explanation:

x = 7

y = 5

[tex] = {x}^{2} + {y}^{2} [/tex]

[tex] = (7 {)}^{2} + (5 {)}^{2} [/tex]

= 7 × 7 + 5 × 5

[tex] = 49 + 25 [/tex]

[tex] = 74[/tex]

Hey there!

x^2 + y^2

= 7^2 + 5^2

= 7 * 7 + 5 * 5

= 49 + 25

= 74

Therefore, your answer should be: 74

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

PQ = 10 units

Step-by-step explanation:

to find where the lines cross the x- axis let y = 0 and solve for x , that is

2x + 8 = 0 ( subtract 8 from both sides )

2x = - 8 ( divide both sides by 2 )

x = - 4 ← point P

and

2x - 12 = 0 ( add 12 to both sides )

2x = 12 ( divide both sides by 2 )

x = 6 ← point Q

the lines cross the x- axis at x = - 4 and x = 6

using the absolute value of the difference , then

PQ = | - 4 - 6 | = | - 10 | = 10 units

or

PQ = | 6 - (- 4) | = | 6 + 4 | = | 10 | = 10 units

Answer: [tex]\Huge\boxed{Distance=10~units}[/tex]

Step-by-step explanation:

Given expression

y = 2x + 8

Substitute 0 for the y value to find the x value

This is the definition of x-intercepts

(0) = 2x + 8

Subtract 8 on both sides

0 - 8 = 2x + 8 - 8

-8 = 2x

Divide 2 on both sides

-8 / 2 = 2x / 2

x = -4

[tex]\large\boxed{P~(-4,0)}[/tex]

Given expression

y = 2x - 12

Substitute 0 for the y value to find the x value

(0) = 2x - 12

Add 12 on both sides

0 + 12 = 2x - 12 + 12

12 = 2x

Divide 2 on both sides

12 / 2 = 2x / 2

x = 6

[tex]\large\boxed{Q~(6,0)}[/tex]

Given information

[tex](x_1,~y_1)=(-4,~0)[/tex]

[tex](x_2,~y_2)=(6,~0)[/tex]

Substitute values into the distance formula

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]Distance=\sqrt{(6-(-4))^2+(0-0)^2}[/tex]

Simplify values in the parenthesis

[tex]Distance=\sqrt{(10)^2+(0)^2}[/tex]

Simplify values in the radical sign

[tex]Distance=\sqrt{100}[/tex]

[tex]\Huge\boxed{Distance=10~units}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

y = 3x + 6

Step-by-step explanation:

We are given a line.

We know this line is parallel to the line y=3x+2, and passes through (1, 9).
We want find the equation of this line.

Parallel lines have the same slopes.

So, let's find the slope of y=3x+2.

The line is written the format y=mx+b, where m is the slope and b is the value of y at the y intercept.

As 3 is in the place of where m (the slope) is, the slope of the line is 3.

It is also the slope of the line parallel to it.

We should write the equation of the line parallel y=3x+2 in slope-intercept form as well, however, before we do that, we can write the line in point-slope form, and then convert it to slope-intercept form.

Point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1,y_1)[/tex] is a point.

We can substitute 3 as m in the formula, as we know that is the slope of the line

[tex]y-y_1=3(x-x_1)[/tex]

Recall that we were given the point (1, 9), which also belongs to (it passes through) the line.

Therefore, we can use its values in the formula.

Substitute 1 as [tex]x_1[/tex] and 9 as [tex]y_1[/tex].

y - 9 = 3(x-1)

We can now convert the equation into slope intercept form.

Notice how y is by itself in slope-intercept form; this means we'll need to solve the equation for y.

Start by distributing 3 to both x and -1.

y - 9 = 3x - 3

Now add 9 to both sides.

y = 3x + 6