Taking into account the Henry's Law, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.
Henry's LawA change in pressure does not appreciably influence the solubility of solids or liquids or liquids in liquids; however, that of gases in solvents increases when the partial pressure of the gases increases. The solubility of a gas depends on pressure and temperature.
In this way, Henry's Law describes the effect of pressure on the solubility of gases. This law states that the solubility of a gas in contact with the surface of a liquid at a given temperature is directly proportional to the partial pressure of said gas on the liquid.
Mathematically, Henry's law is expressed as:
C=k×P
Where:
P is the partial pressure of the gas.C is the concentration of the gas.k is Henry's constant, which depends on the nature of the gas, the temperature, and the liquid.At 2 different partial pressure values, the Henry's law is expressed as:
[tex]\frac{C1}{C2} =\frac{P1}{P2}[/tex]
Quantity of carbon dioxideIn this case, you know:
C₁ = [tex]\frac{1.240 g}{1.01 L}[/tex] =1.228 [tex]\frac{g}{L}[/tex]C₂ = ?P₁ = 755 mm HgP₂ = 790 mm HgReplacing in Henry's Law:
[tex]\frac{1.228\frac{g}{L} }{C2} =\frac{755 mmHg}{790mmHg}[/tex]
Solving:
[tex]1.228\frac{g}{L} =\frac{755 mmHg}{790mmHg}xC2[/tex]
C2= [tex]\frac{1.228\frac{g}{L} }{\frac{755 mmHg}{790mmHg}}[/tex]
C2= 1.285 [tex]\frac{g}{L}[/tex]
Then, the concentration of carbon dioxide at 790 mmHg is 1.285 g/L. But you have 1.01 L of water. So the amount of gas dissolved can be calculated as 1.01 L×1.285 g/L = 1.297 g
Finally, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.
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What is one thing people can do to reduce the amount of carbon in the
atmosphere?
A. Drive longer distances.
B. Plant more trees.
C. Burn more fossil fuels.
D. Use more electricity.
Answer:
B
Explanation:
Planting trees sequesters CO2
all of the other choices produce more CO2 in the atmosphere
What is the coefficient and the formula 3Zn(NO3)2 represent ?
Nitrogen atoms:
I thought it was 8 but it’s wrong
The answer is 6 nitrogen atoms.
The given chemical formula is : 3Zn(NO₃)₂
Let's find the number of nitrogen atoms by opening the bracket.
3ZnN₂O₆Zn₃N₆O₁₈Hence, there are 6 nitrogen atoms.
As the water freezes in the ice tray, will its mass change? Please explain.
No, the mass does not change.
Freezing is a change in physical state, not a chemical reaction. No matter is added or taken away.
As water transitions to ice, no molecules are lost; it is boiling so it is not turning into a gas. There is a very, very small amount of mass lost in the form of energy as the water loses it's heat, but this amount of mass is so insignificant it practically can't be measured. In other words, it's negligible.
The combustion of 296 g of propane (C₃H₈) produces 713 g of carbon dioxide. [C₃H₈ + 5O₂ --> 3CO₂ + 4H₂O; C = 12.01 g/mol, H = 1.01 g/mol, O = 16.0 g/mol]
What is the percent yield?
80.5%
124%
0.805%
41.50%
Answer:
80.5%
Explanation:
The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.
To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
(Steps 1 - 3)
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)
Molar Mass (C₃H₈): 44.11 g/mol
Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)
Molar Mass (CO₂): 44.01 g/mol
1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
296 g C₃H₈ 1 mole 3 moles CO₂ 44.01 g
------------------- x ---------------- x ---------------------- x ---------------- = 886 g CO₂
44.11 g 1 mole C₃H₈ 1 mole
(Step 4)
Actual Yield
Percent Yield = ------------------------------ x 100%
Theoretical Yield
713 g CO₂
Percent Yield = ---------------------- x 100%
886 g CO₂
Percent Yield = 80.5%
Mercury-197 has a half-life of 3 days. Starting
with 300 grams, how much remains in 3
weeks? (Round to two places)
Answer:
2.34 gms left
Explanation:
3 weeks = 21 days = 7 half lives
300 * (1/2)^7 = 2.34 gms
Which element has an electron configuration of 1s22s22p63s23p3 ?
Group of answer choices
A. Silicon
B. Nitrogen
C. Arsenic
D. Phosphorus
Answer:
D. phosphorusExplanation:
Greetings !
The electronic configuration 1s²,2s²,2p⁶,3s²,3p³ represents phosphorus with atomic number 15.
The electron configuration 1s², 2s², 2p⁶, 3s², 3p³ corresponds to the element phosphorus. The first two shells are full, with 2 electrons in each shell. The third shell has 2 electrons in the 3s subshell and 3 electrons in the 3p subshell. Hence option D is correct.
Phosphorus is a chemical element with the symbol P and atomic number 15. It belongs to Group 15 (or Group V) of the periodic table, which is also known as the nitrogen group. Here are some key features and characteristics of phosphorus:
Phosphorus is a non-metal, and at room temperature, it exists in several allotropes. The most common forms are white phosphorus, red phosphorus, and black phosphorus.
White phosphorus is a highly reactive and toxic waxy solid, while red phosphorus is less reactive and is often used in safety matches. Black phosphorus is a semiconductor material with interesting electronic properties.
Therefore option D) phosphorous is correct.
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=> The approximate mss of an electron is 1/10²⁷ g , Calculate the uncertainty in its velocity if the uncertainty in its position were of the order of 1/10¹¹ m ( h = 6.6 × 1/10³⁴ kg m² per sec ) ..
Answer:
Δx(m.Δv)=h/4π
here ,
Δv = uncertainty in velocity
10−11×10−27×Δv=6.626×10−34/4×22/7
=5.25×103ms−1
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
According to Heisenberg's uncertainty principle :
[tex]\qquad \sf \dashrightarrow \: \Delta x \Delta p \geqslant \cfrac{h}{4 \pi} [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta x \cdot m \Delta v \geqslant \cfrac{h}{4 \pi}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{h}{4 \pi \cdot m \Delta x}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 \times 10 {}^{ - 34} }{4 \pi \cdot 10 {}^{ - 27} \times 10 {}^{ - 3} \times 10 {}^{ - 11} }[/tex]
[tex] \textsf{ [ we took } [/tex][tex]{ {10}^{-3} } [/tex][tex] \textsf{because mass of electron is} [/tex][tex] \textsf{ given in grams that need to be converted into kg ]} [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \pi } \times \cfrac{10 {}^{ - 34} } {10 {}^{ (- 27 - 3 - 11)} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times \cfrac{10 {}^{ - 34} } {10 {}^{ - 41} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{12.56 } \times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant0.525\times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant5.25\times {10 {}^{ 6}} \:\:m/s[/tex]
a reaction is 50% complete in 2 hours and 75% complete in 4 hours.
what is the order of this reaction ?
Answer:
the half life of reaction is 2 hours which is consist half life of consist in the first order reaction has the order reaction is one
Use a periodic table to help you answer these questions if needed.
How many valance electrons does aluminum have? 3
How many valance electrons does sulfur have? 6
What type of bond will these two elements form? ionic
The top three are correct but not sure on bottom questions of number of atoms Can you answer the question below.
How many aluminum atoms will you need? How many sulfur atoms will you need?
Answer:
2 Al and 3 S
Explanation:
Al2S3 so 2 Al and 3 S
Why is it important to dispose of waste chemicals in collection vessels, instead of pouring them down the
drain?
Explanation:
Reasons why you should not dispose of chemicals down drains
Pipes, especially older pipes, can leak at connections or where they have been damaged. Often large pipes, like storm water pipes or really large sewage mains, are made out of concrete so at places where two pipes meet, there can be minor leaks. It’s not a big deal when it’s just a little bit of storm water leaking, but if chemicals are also in this water, you’ve just given them a direct path to contaminating drinking water! Also, some of Indianapolis’s infrastructure is very old, and pipes used to be made out of things like bricks and hollowed out trees which will also leak.
Disposing of chemicals down drains can damage your plumbing which can be expensive to repair and also allow those chemicals a direct path into the groundwater.
Improperly disposing of chemicals at your site can lead to environmental contamination of your site which can be time consuming and expensive to clean up.
Solve this organic transformation....use - Br2,CCl4,KOH,CH3OH,Hg+2,diluted H2SO4, PCC,HBr,Mg,Dry ether,Na,H2,Pd,quinoline
Organic transformation sequential equation using catalysts will be as follows:
2CH3-CH2-O => (alc. KOH) => CH2=CH2 + KCl + H2O => (Br2/CCl4) => CH2Br-CH2Br + Zn
CH2Br-CH2Br + Zn => (HBr /Pd) => CH2=CH2+ZnBr2
As can be visualized from above organic transformation equation, conversion of dry ether in presence of alkaline potassium hydroxide results in formation of unstable ethene. This dry unsaturated compound of ethene is stabilized by reaction that happens in presence of bromine or calcium tetrachloride as the catalyst which results in formation of ethylene bromide which in presence of highly efficient palladium as catalyst results in formation of stable ethene as byproduct. Thereby with formation of stable compound of ethylene, it releases zinc bromide as byproduct resulting completion of reaction equation. This stable product ethene is a double bonded carbon structure that is chemically extremely flammable and has planar structure.
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what is oxidized and what is reduced
C2H4 + 2O2 → 2CO + 2H2O
C2H4 + 3O2 → 2CO2 + 2H2O
C2H4 is oxidized and O2 is reduced in both reactions.
What is oxidation/reduction?Oxidation is defined in several ways. Some of the definitions are:
The addition of oxygen or removal of hydrogenIncrease in the oxidation number of atomsAddition of electronegative or the removal of electropositive elementsReduction, on the other hand, is defined as:
Removal of oxygen or addition of hydrogenDecrease in the oxidation number of atomsAddition of electropositive elements or the removal of electronegative elements.In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.
The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.
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What is the [OH-] if the [H3O+] is 1 x 10 -10?
The answer is [OH⁻] = 1 x 10⁻⁴.
[OH⁻] = H₂O ÷ [H₃O⁺]
[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻¹⁰
[OH⁻] = 10⁻⁴
Heating up a reaction does which of the following:
Group of answer choices
A. Increases the number of collisions as well as the strength of the collision
B. Increases the strength of the collisions only.
C. Increases the number of collisions only.
D. No effect is found on the reaction by increasing the temperature.
Heating up a reaction does increase the number of collision only.
Hence, Option C is correct answer.
What is Collision Theory ?According to the collision theory, the reaction take place when the collision occur and molecules having sufficient energy or threshold energy for collision.
The collision of molecules depend on the kinetic energy of molecules. Greater the kinetic energy greater the number of molecules collide. Lesser the kinetic energy lesser will be collision.
How temperature affect the collision theory ?With an increase in temperature, there is an increase in energy that can be converted into activation energy in a collision, and that will increase the reaction rate. A decrease in temperature would have the opposite effect. With an increase in temperature, there is an increase in the number of collision.
Thus from the above conclusion we can say that Heating up a reaction does increase the number of collision only.
Hence, Option C is correct answer.
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At STP, 1 mole of gas has a molar volume of 22.4 L. What is the density (g/L) of oxygen at STP?
(Hint: find mass using PV=nRT) and find Density using d=m/v
find the solubility of agcl in a 0.1M solution of cucl2.
ksp = 1.8x10^-10
The solubility of AgCl is 18 × [tex]10^-^1^0[/tex] in a 0.1M solution of CuCl₂.
The amount of a substance that can dissolve completely in a solvent at a specific temperature is known as its solubility. A saturated solution is one such example.
The maximum number of moles per liter of solution can be dissolved before the solution becomes saturated.
The equilibrium in the saturated solution will be as :
[tex]AgCl[/tex] ⇄ [tex]Ag ^+ + Cl ^-[/tex]
[tex]a[/tex] [tex]a[/tex] [tex]a[/tex]
[tex]CuCl_2[/tex] ⇄ [tex]Cu^2^+ + Cl^-[/tex]
[tex]0.1[/tex] [tex]0.1[/tex] [tex]0.1[/tex]
Ksp = [tex]1.8[/tex] × [tex]10^ -^1^0[/tex]
The solubility product constant: Ksp is the equilibrium constant for the dissolving of an ionic compound in water. Ksp is a function of temperature.
[tex]ksp AgCl = [ Ag ^+ ] [ Cl^-]\\[/tex]
[tex]= a[/tex]×[tex][ a + 0.1][/tex]
[tex]= a^2 + 0.1a[/tex]
[tex]a^2[/tex] is very small, so it is neglected.
ksp AgCl = 0.1a
[tex]1.8[/tex] × [tex]10^ -^1^0[/tex] = 0.1a
a = 18 × [tex]10^-^1^0[/tex]
Therefore, the solubility of AgCl is 18 × [tex]10^-^1^0[/tex].
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Convert the following measurement
The correct answer would be 0.034 g/L.
Unit conversionWhat we are trying to do here is to convert from milligram to gram and from deciliter to liter.
First, let's do the milligram to gram conversion.
1 mg = 0.001 g
Therefore,
3.4 mg = 3.4 x 0.001 = 0.0034 g
In order to convert from deciliter to liter.
1 deciliter = 0.1 L
Thus, 3.4 mg/dL = 0.0034g/0.1 L = 0.034 g/L
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which three directions in the drawing below are most likely to result in a warmer earth?
The directions that are likely to result in a warmer earth are the directions 3, 5 and 6.
What is global warming?The term global warming has to do with the gradual rise in the temperature of the earth as a result of the re-radiation of infrared rays back to the earth. We know that greenhouse gases are able to trap the infrared rays from the sun and reradiate same to the surface of the earth and this ultimately leads to a warmer earth.
As such, if we look at the image closely, we can see that there is a reradiation of the rays to the earth in the directions 3, 5 and 6. It then follows that the directions that are likely to result in a warmer earth are the directions 3, 5 and 6.
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#44) Draw the complete chemical equation for the hydrohalogenation reaction of 1-
pentene by HBr. You must show the structures in your reaction; you may NOT use
molecular formulas!
Hydrohalogenation Reaction:
The substitution of hydrogen and halide levels across a double bond takes place. The halide group is connected to the carbon with more substituents. The product will affect by the presence of peroxide
What is the hydrohalogenation reply with example?
Ethene is a symmetrical alkene having two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon particles on either side of the double bond.
What is the hydrohalogenation reaction with example?Ethene is a symmetrical alkene including two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon atoms on either flank of the double bond.
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Given the reaction:
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution:
Group of answer choices
A. No changes in color occur
B. The solution turns darker red
C. The solution becomes colorless
D. The solution becomes more yellow
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution the solution turns darker red
While precipitating out Fe3+ (as Fe(OH)3) or SCN- (as AgSCN) will push the equilibrium to the left, consuming the complex and reducing color intensity, the addition of Fe3+ or SCN- will push the equilibrium to the right, creating more complex and intensifying the color.
The pace of reaction rises as Fe3+ levels rise. The concentration of SCN reduces as the rate rises.
The FeSCN2+ complex, which is created when iron(III) and thiocyanate ions react, displays an extremely strong blood red color (or orange in diluted solution), making it simple to detect and quantify using spectrophotometry.
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If a chemical reaction produces 20.0 grams of product, but by stoichiometry it is supposed to have 25.0 grams of product; what is the percent yield of the reaction?
Group of answer choices
A. 125%
B. 75%
C. 20%
D. 80%
Answer:
d
Explanation:
d
Most of the heat that’s melting the ice comes from the foil. That’s because metals are good conductors of heat. Heat from the surroundings flows into the foil and then from the foil into the ice. Draw arrows to show the amount and direction of heat transfer between the foil and the ice.
the rate of cooling decreases
Urgent!!!
A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the calorimeter is 32.0 °C. Determine the specific heat of the metal. Show your work by listing various steps, and explain how the law of conservation of energy applies to this situation.
The specific heat of the metal, given the data from the question is 0.60 J/gºC
Data obtained from the questionThe following data were obtained from the question:
Mass of metal (M) = 74 gTemperature of metal (T) = 94 °CMass of water (Mᵥᵥ) = 120 g Temperature of water (Tᵥᵥ) = 26.5 °C Equilibrium temperature (Tₑ) = 32 °C Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC Specific heat capacity of metal (C) =? How to determine the specific heat capacity of the metalThe specific heat capacity of the sample of gold can be obtained as follow:
According to the law of conservation of energy, we have:
Heat loss = Heat gain
MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)
74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)
C × 4588 = 2761.44
Divide both side by 4588
C = 2761.44 / 4588
C = 0.60 J/gºC
Thus, the specific heat capacity of the metal is 0.60 J/gºC
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Line p has an equation of y= – 8x+6. Line q, which is perpendicular to line p, includes the point (2, – 2). What is the equation of line q?
The equation of line q is determined as y = ¹/₈x - ⁹/₄.
What is slope?The slope of a line is the change in y axis to change in x axis.
Slope of line Py = – 8x + 6
from general line equation, y = mx + c
where;
m is slopem = - 8
Slope of line qm₂ = -1/m
m₂ = -1/-8
m₂ = 1/8
Equation of line q(y - y₁) / (x - x₁) = m₂
(y + 2)/(x - 2) = 1/8
y + 2 = ¹/₈(x - 2)
y + 2 = ¹/₈x - ¹/₄
y = ¹/₈x - ⁹/₄
Thus, the equation of line q is determined as y = ¹/₈x - ⁹/₄.
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Which of the following is NOT an example of a colligative property?
Group of answer choices
A. Salt is added to ice to make homemade ice cream.
B. Salt is added to roads before a snow storm.
C.Antifreeze is added to a radiator of a car.
D. Salt water dehydrates someone that drinks it.
Salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).
What are Colligative Properties?Colligative Properties make reference to physical properties associated with solute concentration instead of its intrinsical characteristics.
Some examples of colligative properties include boiling state, vapour pressure, and osmotic pressure due to the presence of ionic particles.
In conclusion, salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).
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what is the purpose of adding concentrated phosphoric acid to the reaction mixture in the synthesis of aspirin
Concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.
What is the phosphoric acid?Phosphoric acid is an inorganic acid with the molecular H₃PO₄.
Its a triprotic acid which means that one molecule of the acid produces 3 molecules of hydrogen ions.
Phosphoric acid is important for many laboratory as well as industrial uses. It can be serve as buffer in living organisms.
It also used in the synthesis of aspirin.
The synthesis of aspirin requires an acidic environment. Therefore, concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.
In conclusion, Phosphoric acid ensures an acidic environment in the synthesis of aspirin.
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What volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid?
The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L
Data obtained from the questionFrom the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 15.7 MVolume of diluted solution (V₂) = 12 L Molarity of diluted solution (M₂) = 0.156 M Volume of stock solution needed (V₁) = ?How to determine the volume of the stock solution needed
The volume of the stock solution needed can be obtained by using the dilution formula as shown below:
M₁V₁ = M₂V₂
15.7 × V₁ = 0.156 × 12
15.7 × V₁ = 1.872
Divide both side by 15.7
V₁ = 1.872 / 15.7
V₁ = 0.12 L
Thus, the volume of the stock solution needed to prepare the solution is 0.12 L
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Which of the following could be
considered an example of physical
contamination?
a. Pesticide contamination in food
b. Copper leeching into food during the
cooking process
c. A bandage falling into a prepared dish
d. Sanitizer getting onto a food product during
preparation
A bandage falling into a prepared dish could be considered an example of physical contamination.
Physical contamination occurs when a physical object enters food at some level of the manufacturing or preparation procedure. Physical objects in meals may be a choking hazard and regularly introduce biological contaminants as well.
It may arise at any stage of food delivery and preparation. Physical contamination can reason critical damage to the consumer, which includes broken teeth or choking. Varieties of contaminants that can be found in food include jewelry, hair, plastic, bones, stones, pest bodies, and material.
Chemical contamination takes place while food is infected through chemical compounds. Some of the reasons for chemical contamination are cleansing merchandise or pesticides and herbicides from unwashed fruit and vegetables. Examples of chemical contaminants are commercial chemical substances and agricultural chemicals.
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What volume of a 0.550 M solution of potassium hydroxide (KOH) can be made with 19.9 g of potassium hydroxide?
Answer:
0.645 L
Explanation:
To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.
(Step 1)
Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol
Molar Mass (KOH): 56.104 g/mol
19.9 grams KOH 1 mole
-------------------------- x ----------------------- = 0.355 moles KOH
56.014 grams
(Step 2)
Molarity = moles / volume <----- Molarity ratio
0.550 M = 0.355 moles / volume <----- Insert values
(0.550 M) x volume = 0.355 moles <----- Multiply both sides by volume
volume = 0.645 L <----- Divide both sides by 0.550
what is the acid dissociation constant of an monoprotic acid if a concentration of 0.3M solution has a pH of 3?
The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
What is the acid dissociation constant?The acid dissociation constant (Ka) is the equilibrium constant for an acid dissociation reaction.
Let's consider the acid dissociation of a generic weak acid.
HA(aq) = H⁺(aq) + A⁻(aq)
Step 1. Calculate [H⁺].The pH of the solution is 3.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -3 = 1 × 10⁻³ M
Step 2. Calculate the acid dissociation constant (Ka).The concentration of the acid (Ca) is 0.3 M. For a weak monoprotic acid, we can calculate the acid dissociation constant using the following expression.
[H⁺] = √(Ca × Ka)
Ka = [H⁺]² / Ca
Ka = (1 × 10⁻³)² / 0.3 = 3 × 10⁻⁶
The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
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