Identify the classification of whipped cream. group of answer choices aerosol solid aerosol foam emulsion solid emulsion

The treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .

THF which is  tetrahydrofuran is reated with excess of HBr at 373 K .The product is 1,4-dibromobutane as a major organic product .

In the mechanism proton having positive charge is attack on electron rich oxygen and protonated it then bromine anion attack at adjacent carbon and break carbon - protonated  oxygen bond and in he final step the hydroxyl group is protonated and remove as a water with attack at bromine anion .

Therefore , on treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .

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3M

3M is the molarity of a koh solution if 200 ml of the solution contains 0. 6 moles KOH.

Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.

We know that,

Molarity = [tex]\frac{n*1000}{v}[/tex]

where,

n = moles of solute of KOH = 0.6

V= volume of solution in ml= 200 ml

Now on substituting the values in the molarity formula,

molarity = [tex]\frac{0.6*1000}{200}[/tex] = 3M/L

Therefore, molarity = 3M

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Answer:

3.0 moles Al₂O₃

Explanation:

We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.

4 Al + 3 O₂ -----> 2 Al₂O₃

6.0 moles Al            2 moles Al₂O₃
----------------------  x  -------------------------  =  3.0 moles Al₂O₃
                                    4 moles Al

4.0 moles O₂           2 moles Al₂O₃
----------------------  x  -------------------------  =  2.7 moles Al₂O₃
                                    3 moles O₂

As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.

However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.

Answer:

mass number = 18

Explanation:

The mass number is the total amount of protons and neutrons in an atom. Therefore, if there are 8 protons and 10 neutrons, the mass number is 18 (8 + 10 = 18).

Formic acid (ch2o2)  on reaction with water undergoes dissociation reaction.

Formic acid  is the acid released by ant when it bites which causes us irritation.

It's formula is CH2O2 or HCOOH. and pH is 3.75.

In the case of dehydration, one hydrogen atom in the water molecule joins the hydroxyl group in the trans formic acid to form a new water molecule, while the hydrogen bonded to carbon in the acid breaks off to regenerate a water molecule.

Formic acid dissociates in water according to the equation:

HCOOH (aq) + H2O (l) = H3O + (aq) + HCOO- (aq)

Formic acid is the simplest carboxylic acid, containing a single carbon. Occurs naturally in various sources including the venom of bee and ant stings, and is a useful organic synthetic reagent. Principally used as a preservative and antibacterial agent in livestock feed.

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Atomic or hybrid orbitals make up the sigma bond between c1 and c2 in ethane, ch3ch3 are one s orbital and 2 p orbital

Sigma bonds are the most powerful type of covalent chemical link. They are generated by atomic orbitals overlapping head-on. For diatomic molecules, sigma bonding is most readily explained using the language and tools of symmetry groups.

Chemical covalent bonds are sigma bonds and pi bonds. The overlap of atomic orbitals creates sigma and pi bonds. Sigma bonds are produced by overlapping from end to end, whereas Pi bonds are created when the lobe of one atomic orbital overlaps another.

Sigma bonding can be seen in the link between two hydrogen atoms. Sigma bonds are also formed between the sp3 orbitals of hybridized carbon and the s orbitals of hydrogen in methane.

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A mixture of three gases containing an equal number of moles of each gas has a total pressure of 12. 0 atm then partial pressure of each gas is 4 atm .

Calculation ,

According to Dalton law the total gas of the container is equal to the sum of partial pressure of each gas .

[tex]P_{t}[/tex] = [tex]P_{1}[/tex] +[tex]P_{2}[/tex]+ [tex]P_{3}[/tex]

Partial pressure = total pressure × mole fraction

mole of each gas is equal . So, mole fraction is also equal for each gas.

Let the number of  mole = x

mole fraction = x/3x =1/3

[tex]P_{1}[/tex] = 12. 0 atm/3 = 4 atm

[tex]P_{2}[/tex] = 12. 0 atm/3 = 4 atm

[tex]P_{3}[/tex] = 12. 0 atm/3 = 4 atm

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The formal charge in the central metal atom Nitrogen atom is O.

           Structure      O=N=f    formal charge on N = 0

Formal charge in a Lewis shape, for every atom, you need to count how many electrons. count number all of its lone pair electrons, and 1/2 of its bonding electrons. The difference among the atom's range of valence electrons and the range it owns is the formal rate

Nitrosyl fluoride is used as a solvent and as a fluorinating and nitrating agent in natural synthesis. It has additionally been proposed as an oxidizer in rocket propellants.

The guideline or method for assigning formal rate to atoms in Lewis systems is the subsequent: Formal fee = number of valence electrons - variety of lone-pair electrons + 1/2 range of bonding electrons.

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N3H is the correct answer.

N3H is the molecular formula of the smallest neutral compound of nitrogen and hydrogen.

an expression that lists the quantity and kind of atoms that make up a substance's molecules.

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Toluene compound reacts third fastest with fuming sulfuric acid.

The reaction is attached in figure -

What is toluene?

What is a toluene used for?

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The percentage of the original sample which would remain after 17.5 days according to the given half-life of the isotope is; 22.06%.

The given sample in discuss has a half life of; 8.02 days, this therefore indicates that after 17.5 days, the number of half-life periods completed is; 17.5/8.02 = 2.18 half-lifes.

Hence, the percentage of the original sample remaining after 17.5 days can be evaluated as follows;

N = 100% × (0.5)^2.18

N = 100 × 0.22

N = 22.06%.

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The oxygen consumption rate of a 200 kg seal is 10 ml/(g h). If it has oxygen stores of 2 liters, then minutes can it dive before running completely out of oxygen is 0.06min.

Oxygen is one of the most vital element of the organism which is required by almost all the cellular and for all metabolic activities to perform body function.

It is consumed by the respiratory system and passed ro each cell by circulatory system of the body.

Given,

Mass of seal = 200kg = 200000 g

Rate of oxygen consumption = 10 ml/gh

The volume of stored O2 = 2000mL

The time of consumption is calculated as

t = V/mr

t = 2000/200000×10

t = 0.001 hrs

In minutes

t = 0.06min.

Thus 0.06min is required to dive out the oxygen stores of 2 litre.

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Answer:

Explanation to the following:

Answer:

B.  4 Fe + 3 0₂---> 2 Fe₂O3        

Explanation:

(A) Ir + O₂--> IrO₂                                 No:  Ir is iridium

(B) 4 Fe + 3 0₂---> 2 Fe₂O3                Yes:  Fe is iron and O is oxygen,                  and the equation is balanced.

(C) I+ 0₂ ---> 10₂                                  No:  I is iodine

(D) 3 Ir + 0₂ -> 6 Ir₂03                         No:  I is iodine

The pH of blood if pco2 drops to 35.0 mmhg is 7.459

The pH of the blood can be calculated using the Henderson- Hasselbalch equation, it explains the relation between acid dissociation constant pKa and pH in biological and chemical systems.

pH = pK + log ( HCO3- / ( 0.03 * PCO2 ) )

pK is 6.1 for bicarbonate buffer system.

HCO3- = 24mm

PCO2  = 35.0 mmhg

pH = 6.1 + log ( 24 / 0.03 * 35.0 )

     = 6.1 + log ( 24 / 1.05 )

     = 6.1 + log 22.8571

     = 6.1 + 1.3590

     = 7.459

Hence, the pH of blood is 7.459

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The way to find the moles of CO2 in a pop are:

A mole is a measure of molecules that is equal to approximately 6.022x10^23 molecules. Using the ideal gas formula, one can find the number of moles of carbon dioxide in a container if you know the other needed parameters and conditions.

Based on the above, it should be noted that P is the pressure, V is the volume from, T is the temperature and R is a proportionality constant that is equal to 0.0821 L atm / K mol.

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The combination of properties would be expected to lead to the most viscous liquid include:

This is defined as the resistance of a liquid to flow and is characterized by its sticky nature.

This is as a result of the strong intermolecular forces which holds the atoms together and low temperature keeps them in shape thereby making it the most appropriate c hoice.

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Answer: 75.3%

Explanation:

Mg molar mass = 24

MgCl2 molar mass = 94

—> 94 x 10 / 24

29.5/1 x 24/94 x 10

= 29.5 x 24 / 94 x 10

since we are looking for percentage yield we multiply by 100

= 29.5 x 24 x 100 / 94 x 10 = 75.3%

The compound with the highest boiling point is [tex]CH_{3} CH_{2} OH[/tex] .

So, option C is correct one.

The boiling point depend two factors,

The boiling point of ether is less than alcohols because alcohol form hydrogen-bonding .The hydrogen bond is strongest bond. So, ethyl alcohol and methyl alcohol has more boiling point than dimethy ether.

The propane molecules have only van-der waals force of attraction, which is weakest force of attraction.So, propane has lowest boiling point.

The molecular mass of ethanol is greater than methaol. So, ethanol has higher boiling point.

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Answer:

compound(C) mixture(M)

Explanation:

COMPOUNDS MIXTURES

(C)In nature they are homogeneous. (M)They can be homogeneous as well as heterogeneous in nature.

(C)They have a definite melting and boiling point. (M)They do not have any definite melting or boiling point.

(C)Example: Baking soda, salt, etc.(M) Example: Salt and sand, sugar and water.

The polar water molecules attract the oppositely assessed polar areas of the sucrose molecules and pull them away, resulting in dissolving. Since the ions in salt and the molecules in sugar are very different, their solubilities tend to be additional.

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436 atoms of Pb 207 are left in the rock.

Alpha and beta decays are the mechanism through which uranium transforms into the lead. While 235U and its daughter nuclides only experience seven alpha and four beta decays, 238U and its daughter nuclides suffer eight alpha and six beta decays overall.

When there are too few neutrons in relation to protons, alpha decay occurs. There is the discharge of an alpha particle, which consists of two protons and two neutrons.

When there are more neutrons than protons, beta decay can happen. A high-speed electron is ejected from a proton that transforms spontaneously from a neutron.

Since gamma radiation is emitted as a wave rather than a particle, the atomic structure of an atom remains unaltered. Atomic fission is the primary cause of neutron emission. At one time, many neutrons can be released.

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Bombardment of uranium-238 nuclei by carbon-12 nuclei produces californium-246 and neutrons then the complete, balanced equation for this nuclear process is given a ,

[tex]^{238} _{92}U + ^{12} _{6} C[/tex] → [tex]^{246} _{98} Cf + 4^{1} _{0} n[/tex]

Nuclear fusion reactions are defined as the reaction in which, two or more lighter atoms combine to form a heavier atom. The number of atoms formed in this reaction decreases from the given atoms. The nuclear process is also nuclear fusion.

Example : Bombardment  of uranium-238 nuclei

Chain reactions are defined as the reaction in which the neutrons that are released in the previous fission reaction act as the starting material in the next reaction. Thus, this process continues to many reactions.

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

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Ka= 2.1106

The ka value of the acid will be:

Ka=2.1106

HA(aq)+OH−(aq)→A−(aq)+H2O(l)

You reach the halfway point when

[HA]=[A−]

It implies that

log([HA][A−])=log(1)=0

As a result, it can be claimed that at the half-equivalence point, the pH of the solution and the pKa of the weak acid are equivalent.

pH=pKa at the midpoint of equivalency.

The pKa is determined by the weak acid's acid dissociation constant, Ka. Ka=10pKa, as shown by the formula pKa=log(Ka).

When the two points are half equal, Ka=10pH will exist.

Put in your value to learn Ka=105.67=2.1106.

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Sodium(Na) is the limiting reagent.

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

[tex]2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}[/tex]

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

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Answer:

NH₄CN,  NH₄IO₃,  Fe(CN)₃,  Fe(IO₃)₃

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) NH₄CN

-----> NH₄⁺ and CN⁻

-----> +1 + (-1) = 0

2.) NH₄IO₃

-----> NH₄⁺ and IO₃⁻

-----> +1 + (-1) = 0

3.) Fe(CN)₃

-----> Fe³⁺ and CN⁻

-----> +3 + (-1) + (-1) + (-1) = 0

4.) Fe(IO₃)₃

-----> Fe³⁺ and IO₃⁻

-----> +3 + (-1) + (-1) + (-1) = 0

The surfaces of the cylinder block and cylinder head are interconnected to help cool the engine.

When an automobile engine is running, it generates a lot of heat and needs to be continuously cooled to prevent engine damage.

This is typically accomplished by pumping coolant liquid—often water combined with antifreeze solution—through unique cooling tubes. Air passing across cylinder casings with fins helps cool some engines.

The cylinder head and block of a water-cooled engine are interconnected by coolant channels. All of the channels come together to form a single exit at the top of the cylinder head.

Hot coolant is forced out of the engine and into the radiator, which serves as a type of heat exchanger, by a pump that is driven by a pulley and belt from the crankshaft.

Unwanted heat is transferred from the radiator into the air stream, after which the cooled liquid flows back into the channels after returning to an entrance at the bottom of the block.

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Answer:

K2O2 and KO2 is the answer

Answer:

C.) K₂O

Explanation:

Potassium (K) always forms the cation K⁺.

Oxygen (O) always forms the anion O²⁻.

The ionic compound these two ions form must have an overall charge of 0. However, the dissimilar charges on the ions do not cancel out (+1 + (-2) = -1). Therefore, you need to have two K⁺ ions in the compound to balance the charges (+1 +1 + (-2) = 0).

Which atomic model that shows the atomic structure is missing from this set?

Dalton’s model

In 1898, J. J. Thomson proposed the first of many atomic models to come as he made the proposition that the shape of an atom was like a sphere.

This refers to the way and manner an atom is arranged and the things that are contained in it.

Hence, we can see that an atom contains:

Therefore, the atomic model that shows the atomic structure is missing from this set is Dalton's model.

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The complete question is:

The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one important model is missing.

An image at left with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle.

Which atomic model is missing from this set?

Bohr’s model

Dalton’s model

Rutherford’s model

Thomson’s model

Answer: B.  schrodingers model

Explanation:

correct on edge

The mass percent composition of C in glycine is 31.66%.

The formula mass of a substance is defined as the sum of the atomic masses of constituent atoms in an ionic compound. This is generally used for ionic compounds which do not contain discrete molecules, but ions as their constituent units.

Given,

Formula mass of C2H5NO2 = Molar mass of C2H5NO2

Molar mass of C2H5NO2 = 75.08 g

Futher we know that the 75.08g of glycine contain 24 g of carbon,

then mass percent composition of C in glycine can be given as,

% C = (mass of carbon/ molar mass of glycine) ×100

%C = (24/ 75.8) × 100

= 31.66%

Thus, we find that the mass percent composition of C in glycine is 31.66%.

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