Answers
By the quotient rule for differentiation,
[tex]\displaystyle h'(x) = \dfrac{g(x)f'(x) - f(x)g'(x)}{g(x)^2}[/tex]
According to the plots of [tex]f[/tex] and [tex]g[/tex], we have [tex]f(3)=2[/tex] and [tex]g(3)=3[/tex].
On the interval [2, 4], [tex]f[/tex] is a line through the points (2, 5) and (4, -1), and hence has slope (-1 - 5)/(4 - 2) = -3, so [tex]f'(3)=-3[/tex]. We can similarly find [tex]g'(3)=2[/tex].
Then
[tex]h'(3) = \dfrac{3\cdot(-3)-2\cdot2}{3^2} = \boxed{-\dfrac{13}9}[/tex]
Related Questions
An object is launched directly in the air at a speed of 64 feet per second from a platform located 16 feet above the ground. The position of the object can be modeled using the function f(t)=−16t2+64t+16, where t is the time in seconds and f(t) is the height, in feet, of the object. What is the maximum height, in feet, that the object will reach?
Answers
Considering the vertex of the quadratic equation, the maximum height that the object will reach is of 80 feet.
What is the vertex of a quadratic equation?A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
[tex]x_v = -\frac{b}{2a}[/tex][tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]Considering the coefficient a, we have that:
If a < 0, the vertex is a maximum point.If a > 0, the vertex is a minimum point.In this problem, the equation is:
f(t) = -16t² + 64t + 16.
Hence the coefficients are:
a = -16, b = 64, c = 16.
The maximum value is found as follows:
[tex]y_v = -\frac{64^2 - 4(-16)(16)}{4(-16)} = 80[/tex]
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what is 11- 2 to the 3rd power
Answers
Answer:
See below
Step-by-step explanation:
Question is unclear
could be (11-2)^3 = 9^3 = 729
could be 11 - 2^3 = 11 - 8 = 3 Pick the one you want !
Find the area of the trapezoid 19 12.6 29.2 14.5
Answers
Answer:
303.66 in²
Option 4 is the correct answer
Service Department Charges and Activity Bases
Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.
CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:
• The sector has 5,200 employees, of whom 25% are office employees.
• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.
• One hundred percent of the employees with a computer also have an e-mail account.
• The average number of help desk calls for October was 1.5 calls per individual with a computer.
• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.
a. Determine the service charge rate for the four CCS service categories for October.
CCS Service Category Service Charge Rate
Help desk $fill in the blank 1
Per call
Network center $fill in the blank 3
Per device monitored
Electronic mail $fill in the blank 5
Per user or e-mail account
Smartphone support $fill in the blank 7
Per smartphone issued
b. Determine the charges to the COMM sector for the four CCS service categories for October.
October charges to the COMM sector
Help desk charge $fill in the blank 9
Network center charge $fill in the blank 10
Electronic mail charge $fill in the blank 11
Smartphone support charge $fill in the blank 12
Feedback Area
Feedback
a
Answers
The answers to the question are:
50751014a. How to determine the service charge rate for the month of OctoberThis is the number of calls for the help desk
160000/3200 = 50per call
network center
735000/9800
= 75 per device that was monitored
Electronic mail
100000/10000 =
10 for the mail account
For smart phone support
124600/8900
= 14 per phone extension
b. Charges to the COMM sectorfor helpdesk
5200 * 0.25 * 0.96 *1.5 calls * $50
= 93600
For network center
(5200 * 0.25 * 0.96) + 600] x 75
= 138600
For Electronic mail
5200 * 0.25 * 0.96 * 10 per email account
= 12480
Smart support charge
5200 * 0.25 * 14 = 18200
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Earlier in this course, you explored Euclidean geometry, which is the study of flat space. This approach follows the teachings of Euclid, in which he describes the relationships between points, lines, and planes without any numerical measurement. You saw evidence of Euclidean geometry inside several proofs and geometric constructions.
In contrast, the focus of this unit is understanding geometry using positions of points in a Cartesian coordinate system. The study of the relationship between algebra and geometry was pioneered by the French mathematician and philosopher René Descartes. In fact, the Cartesian coordinate system is named after him. The study of geometry that uses coordinates in this manner is called analytical geometry.
It’s clear that this course teaches a combination of analytical and Euclidean geometry. Based on your experiences so far, which approach to geometry do you prefer? Why? Which approach is easier to extend beyond two dimensions? What are some situations in which one approach to geometry would prove more beneficial than the other? Describe the situation and why you think analytical or Euclidean geometry is more applicable.
Answers
The Elements can be defined as a mathematical treatise which comprises 13 books that are attributed to the ancient Greek mathematician who lived in Alexandria, Ptolemaic Egypt c. 300 BC and called Euclid.
Basically, the Elements is a collection of the following geometric knowledge and observations:
DefinitionsPostulatesPropositionsMathematical proofs of the propositions.Based on my experiences so far, an approach to geometry which I prefer is Euclidean geometry because it's much easier than analytical geometry. Also, an approach that is easier to extend beyond two-dimensions is Euclidean geometry because it can be extended to three-dimension.
A situation in which one approach to geometry would prove to be more beneficial than the other is when dealing with flat surfaces. In Euclidean geometry, a correspondence can be established between geometric curves and algebraic equations.
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Use the fact 0.09=1/11 to write 0.27 as a fraction
Answers
0.27 / 0.09 = 3
So
0.09 * 3 = 0.27
Substitute 0.09 with 1/11
1/11 * 3 = 3/11
Someone please help with this question asap!
Answers
Answer:
Side b is the longest because the longer side always lie opposite the bigger angle. Angle B is the biggest angle, and since side b is opposite angle B, side b is the longest.
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
The side opposite to the largest angle is the longest side of a triangle.
[tex] \qquad \large \sf {Conclusion} : [/tex]
hence, we can conclude that the longest side is b
( since it's opposite angle is the largest, i.e 91° )
it took a 3D priner 10528 minutes to print 87 percent of a 3D print job. At this rate of speed how much time will take for the print to
reach 100 percent completion?
Answers
The time it would take for the print to reach 100 percent completion is 12,101 minutes 9 seconds.
What is time it would take to reach 100%?The mathematical operations that would be used to determine the required value are division and multiplication. Division is the process of grouping a number into equal parts using another number. The sign used to denote division is ÷. Multiplication is the process of determining the product of two or more numbers. The sign used to denote multiplication is ÷.
Other mathematical operations that are used to solve problems include addition and subtraction.
Time it would take to reach 100% completion = (minutes it takes to print 87% of the words x 100%) / 87%
Time it would take to reach 100% completion = (10,528 x 1) / 0.87 =
10.528 / 0.87
= 12,101. 15
= 12,101+ (0.15 x 60)
= 12,101 minutes 9 seconds
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What is the measure of this line?
Answers
Answer:
2 and 1/16th inch
Step-by-step explanation:
the half inch mark would be 2 and 1/2 and you know half of half is 1/4 so the best answer is A.
us
Find a formula for the nth term in this
arithmetic sequence:
a₁ = 7, a2 = 4, a3 = 1, a4 = -2, ...
an = [? ]n +
Answers
The formula for the nth term of the arithmetic sequence is [-3]n+10
What is the nth term of an arithmetic sequence?
⇒ The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
Calculation:
It is given that the given sequence is an arithmetic sequence.
First term a1 = 7
Second term a2 = 4
Common difference d = 4-7
⇒ d=3
From the general formula,
an = a1 + (n - 1)d
On substituting,
an = 7+ (n-1)(-3)
an = 7-3n+3
an = -3n+10
⇒ Thus the general formula for the nth term of the arithmetic sequence is -3n+10
an= [-3]n+10
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Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of so that the following is true.
P(-0.78≤Z≤c)=0.7657
Answers
For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166
How to find the p-value from 2 z-scores?We want to find the p-value between 2 z-scores expressed as;
P(-0.78 < z < c) = 0.7657
To solve this, we will solve it as;
0/7657= 1 - [P(z < -0.78) + P(z > c)]
From normal distribution table, we have that;
P(z < -0.78) = 0.217695
Thus;
0.7657 = 1 - (0.217695 + c)
c = 1 - 0.7657 - 0.217695
c = 0.0166
Thus, For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166
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Need all 3 done, please help (:
Answers
(8) The algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.
(9) The minimum number of shares needed to achieve the required profit is 1223, using the algebraic expression 2.25x ≥ 2750, where x is the number of shares.
(10) The number of books needed to be sold for the novelist to make a profit of $10,000 is 4350, using the algebraic expression 5000 + 1.1495x ≥ 10000, where x is the number of books sold,
(8) Weekly target for Ms. Reed is $350.
The cost of each unit she sells is $22.
We assume the number of units she sold to be x.
Thus, the total sales done by Ms. Reed is $22x.
For her to remain employed, her total sales should exceed her target, which can be shown as an algebraic expression: 22x ≥ 350.
Thus, the algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.
(9) Profit on each share is $2.
The additional profit is $0.25.
Thus, the total profit on each share is $2 + $0.25 = $2.25.
The required profit by the customer is $2750.
We assume the number of shares needed to be x.
Thus, the total profit made by the customer is $2.25x.
For the customer to make the required profit, we can write the algebraic expression, 2.25x ≥ 2750.
To solve this, we divide both sides by 2.25 to get:
2.25x/2.25 ≥ 2750/2.25,
or, x ≥ 1222.22.
Thus, the minimum number of shares needed to achieve the required profit is 1223.
(10) Default contract of Book Maker publisher is $5000 and 5% royalty.
The cost of the book, for which the novelist has got the contract is $22.99.
We assume the number of books sold to be x.
The royalty share on each book given to the novelist is 5% of $22.99, or, $ 5/100 * 2299/100 = $ 11495/10000 = $1.1495.
Thus, the royalty received on x number of books = $1.1495*x = $1.1495x.
Thus, the total profit to the novelist = (5000 + 1.1495x).
Since the novelist wants to make a minimum profit of $10000, we can show it as the algebraic expression:
5000 + 1.1495x ≥ 10000.
To solve this, we go as follows:
5000 + 1.1495 ≥ 10000,
or, 1.1495x ≥ 10000 - 5000,
or, 1.1495x ≥ 5000,
or, x ≥ 5000/1.1495,
or, x ≥ 4349.717.
Approximating, we get x ≥ 4350.
Thus, 4350 books need to be sold to achieve the wanted profit.
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The composite figure is made up of a parallelogram and a rectangle. Find the
area.
A. 88 sq. units
B. 64 sq. units
C. 24 sq. units
D. 120 sq. units
Answers
Answer:
A
Step-by-step explanation:
The parallelogram is the length times the height. The height is 8 and the length is 12 - 2 - 2 or 8.
8x8 = 64
The small rectangle is 12 x 2 or 24
64 + 24 = 88
Find the range of y=7x-34/x-5
Answers
Answer:
Option A
Here you go.
Hope this help!!
Good luck!!
Horizontal asymptote
y=7x/x=7The range is
(-oo,oo)-{7}Or
R-{7}Option A
y=3x-2
y=-2x+8 solve this equation
Answers
Answer:
x = 2
Step-by-step explanation:
3x - 2 = - 2x + 8
→ Add 2x on both sides
5x - 2 = 8
→ Add 2 on both sides
5x = 10
→ Divide both sides by
x = 2
Answer:
x = 2, y = 4 (2,4)
Step-by-step explanation:
Put both the equation in ax + by = c
-3x + y = -2
2x + y = 8
Find x:
Multiply 8 times 1, -2 by 1, 2 times 1, and -3 by 1
8 - (-) 2/2 - (-) 3 = x
10/5
x = 2
Plug x back into equation:
-3(2)+y = -2
y = 4
IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each
Answers
Answer:
22.34021442
Step-by-step explanation:
22.34021442
divide 5 by 6 and 5/6 into a repeating decimal
Answers
_
Answer: 0.83
Step-by-step explanation:
5/6 = 0.8333...
_
0.8333... = 0.83
Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.
f(x)= (3x-4)(-6x-5)
quadratic function
quadratic term: −18x2
linear term: 39x
constant term: –20
quadratic function
quadratic term: −12x2
linear term: −42x
constant term: –20
linear function
linear term: 39x
constant term: –20
linear function
linear term: −18x2
constant term: –20
Answers
The given function is quadratic. The quadratic term is -18x², the linear term is 39x, and the constant term is -20. So, first option is correct.
What is a quadratic function?A function in which the highest degree of the variable is 2, then that function is said to be a quadratic function.
The general form of a quadratic function is ax² + bx + c. Where the terms are:
ax² - quadratic term;
bx - linear term;
c - constant term;
What is a linear function?A function in which the highest degree of the variable is 1, then that function is said to be a linear function.
The general form of a linear function is ax + c. Where the terms are:
ax - linear term;
c - constant term;
Expanding the given function:The given function is f(x) = (3x - 4)(-6x + 5)
Expanding the given function,
f(x) = (3x)(-6x) + (3x)(5) + (-4)(-6x) + (-4)(5)
= -18x² + 15x + 24x - 20
= -18x² + 39x - 20
Since the highest degree of the variable x in the obtained function is 2, it is a quadratic function.
The terms in the obtained quadratic function are:
quadratic term: -18x²
linear term: 39x
constant term: -20
Therefore, the first option is correct.
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Disclaimer: The question has a mistake in the function. The corrected question is here.
Question: Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.
f(x)= (3x - 4)(-6x + 5)
In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y
Answers
The values of X and Y are 30 and 11 respectively
How to determine the values of X and Y?The figure that represents the complete question is added as an attachment
The given parameters are:
DH = X +3
HF = 3Y
GH = 2X -5
HE = 5Y
From the attached parallelogram, we have:
DH = HF
GH = HE
Substitute the known values in the above equation
X + 3 = 3Y
2X - 5 = 5Y
Make X the subject in X + 3 = 3Y
X = 3Y - 3
Substitute X = 3Y - 3 in 2X - 5 = 5Y
2(3Y - 3) - 5 = 5Y
Expand
6Y - 6 - 5 = 5Y
Evaluate the like terms
Y = 11
Substitute Y = 11 in X = 3Y - 3
X = 3*11 - 3
Evaluate
X = 30
Hence, the values of X and Y are 30 and 11 respectively
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For a certain company, the cost function for producing x items is C(x)=50x+100 and the revenue function for selling x items is R(x)=−0.5(x−100)2+5,000 . The maximum capacity of the company is 120 items.
The profit function P(x) is the revenue function R(x) (how much it takes in) minus the cost function C(x) (how much it spends). In economic models, one typically assumes that a company wants to maximize its profit, or at least make a profit!
Answers to some of the questions are given below so that you can check your work.
Assuming that the company sells all that it produces, what is the profit function?
P(x)=
Answers
Assuming that the company sells all that it produces, The profit function is: P(x)=-x^/2+50x -100 or P(x)=-0.5x²+50x -100.
Profit functionProfit = R-C = -(x-100)^2/2 +5000 - 50x -100 =
-(x^2 -200x +10000)/2 -50x +4900 =
-x^2/2 +100x -5000 +5000 -50x +4900
Collect like terms
-x^/2+50x -100
Hence,
Profit function = P(x)=-0.5x²+50x -100
Maximum profit generating output can be determine by taking the derivative and setting it equal to zero
R-C = -x^2/2 + 50x -100
R'-C' = -x + 50 =0
P(0)x = 50
Maximum profit can be determine by substituting x=50 into the original profit equation, R-C
P(50) =-(1/2)(50)^2 +50(50) -100
P(50)= -1250 + 2500 -100
P(50) = $1150 profit
P(120) =-(1/2)(120)^2 +50(120) -100
P(120)= -3600 + 6000 -100
P(120) = $2300 profit
Therefore the profit function is: P(x)=-x^/2+50x -100 or P(x)=-0.5x²+50x -100.
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Write an equation that expresses the following relationship.
varies directly with the square of and inversely with
In your equation, use as the constant of proportionality.
Answers
The equation become u = k p^2 / d.
According to the statement
we have given that some conditions for the equations and we have t make the equation from the given equations.
So, For this purpose, we have given that
The equation in which u is varies directly with the square of p and inversely with d and use the k as the constant of proportionality.
So, From all these above the equation will become is
u = k p^2 / d
In latex form the equation write as :
[tex]u = \frac{kp^{2}}{d}[/tex]
In this equation all the given conditions are applicable.
So, The equation become u = k p^2 / d
Disclaimer: This question was incomplete. Please find the full content below.
Question:
Write an equation that expresses the following relationship. u varies directly with the square of p and inversely with d In your equation, use k as the constant of proportionality.
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6. Find the mean, median, and mode of the set of
numbers: 6, 7, 11, 5, 8, 7, 4, 13, 11, 2.
Answers
Answer:
Mean 7.4
Median 7
Mode 7, 11
Step-by-step explanation:
Let me know if this is correct!
Answer: 7.4, 7, 7 and 11
Step-by-step explanation:
The mean is the sum of all the numbers divided by the number of numbers. In this case, there are 10 numbers.
[tex]Mean=\frac{6+7+11+5+8+7+4+13+11+2}{10}=\frac{74}{10}=7.4[/tex]
The median is the number (or the average of the two numbers) in the middle of the set when it is ordered in ascending order. Let's first order it from least to greatest.
[tex]2,4,5,6,7,7,8,11,11,13[/tex]
The two middle numbers are 7 and 7. The median is the mean of these two numbers.
[tex]Median=\frac{7+7}{2}=\frac{14}{2}=7[/tex]
The mode is the number that is most repeated number in the set. The numbers 7 and 11 are repeated twice. Hence, the modes are 7 and 11.
WILL GIVE BRAINLIEST
Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.
1) 50 mph
2) 70 mph
3) x mph
4) (x+10)mph
5) (x-5)mph
Answers
The length of the trip at a distance of 300 miles and the given times are
6 hours30/7 hours300/x hours300/x + 10 hours300/x - 5 hoursHow to determine the length of the trip?The distance is given as:
d = 300
The formula is represented as:
d = r * t
Make t the subject
t = d/r
Substitute 300 for d
t = 300/r
When r = 50 mph,
t = 300/50
Evaluate
t = 60
When r= 70 mph, we have
t = 300/70
Evaluate
t = 30/7
When r = x, we have
t = 300/x
When r = x + 10, we have
t = 300/x + 10
When r = x - 5, we have
t = 300/x - 5
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Complete question
A train traveled 300 miles. How long did the trip take if the train was traveling at a rate of:
Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.
he polynomial of degree 5, P ( x ) has leading coefficient 1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of multiplicity 1 at x = − 1 Find a possible formula for P ( x ) .
f]
Answers
The possible formula for the polynomial in discuss whose roots are described as; having roots of multiplicity 2 at x = 3 and x = 0 , and a root of multiplicity 1 at x = − 1 is; P(x) = x^5 -5x⁴-6x³+18x².
What is the polynomial in discuss whose roots and leading coefficient are as discussed?The polynomial which is as described in the task content whose roots are as given can be written in its factorised form as follows;
P(x) = (x-3) (x-3) (x) (x) (x+1)
The expanded form is therefore;
P(x) = x^5 - 5x⁴- 6x³+ 18x².
Therefore, the polynomial having roots of multiplicity 2 at x = 3 and x = 0 , and a root of multiplicity 1 at x = − 1 is P(x) = x^5 - 5x⁴- 6x³+ 18x².
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Find the slope and reduce.
P=(-8, 3) Q=(-6, 2)
Slope
Answers
Answer:
[tex]-\frac{1}{2}[/tex]
Step-by-step explanation:
Slope/Gradient = [tex]\frac{y1-y2}{x1-x2}[/tex]
P = (-8 , 3) (x1, y1)
Q = (-6 , 2) (x2, y2)
Slope = [tex]\frac{3-2}{-8-(-6)}[/tex] =[tex]\frac{1}{-8+6}[/tex] = [tex]\frac{1}{-2}[/tex] = [tex]-\frac{1}{2}[/tex]
Answer:
-1/2
Step-by-step explanation:
The formula for the slope is (change in y)/(change in x) or Rise/Run.
The change in y for the two points is: 3 --> 2 which is -1
The change in x for the two points is: -8 --> -6 which is +2
If we input these numbers in the slope equation, we end up with -1/2.
Since we cannot simplify -1/2 further, that is our final answer.
Please help me quick. I don’t understand please give me the answer
Answers
Answer:
m = -2
Step-by-step explanation:
to find the answer you must put rise over run
rise is (y2 - y1) and run is (x2 - x1)
lets use the bottom two points for thisd
y2 is 0 and y1 is 2
x2 is 1 and x1 is 0
0 - 2 = -2
1 - 0 = 1
-2/1 = -2
that is the slope
The following information is available for Brownstone Products Company for the month of July:
Actual Master Budget
Units 3,500 4,000
Sales revenue $ 54,300 $ 60,000
Variable manufacturing costs 10,000 16,000
Fixed manufacturing costs 13,000 14,000
Variable selling and administrative expenses 6,500 8,000
Fixed selling and administrative expenses 8,000 9,100
Required:
1. What was the master budget variance for July? Was this variance favorable or unfavorable?
2. Compute the July sales volume variance and the flexible-budget variance for the month, both in terms of contribution margin and in terms of operating income.
4. Prepare pro-forma budgets for activities within its relevant range of operations. Prepare a flexible budget for each of the following two output levels:
a. 3,560 units.
b. 3,980 units.
Answers
1. The master budget variance for July was $3,900, and this variance was favorable.
2. The July sales volume variances in terms of contribution margin and operating income are $2,800 F and $3,900 F, respectively.
3. The July flexible-budget variances in terms of contribution margin and operating income are $5,550 F and $6,650 F, respectively.
4. Flexible budgets for the following output levels are:
3,560 units 3,980 units
Sales revenue $53,400 $59,700
Variable manufacturing costs 14,240 15,920
Fixed manufacturing costs 12,460 13,930
Variable selling and
administrative expenses 7,120 7,960
Fixed selling and
administrative expenses 9,100 9,100
Operating Income $10,480 $12,790
Data and Calculations:Actual Master Budget Per Unit Variance
Units 3,500 4,000 500 U
Sales revenue $ 54,300 $ 60,000 $15.00 $ 5,700 U
Variable manufacturing costs 10,000 16,000 4.00 6,000 F
Fixed manufacturing costs 13,000 14,000 3.50 1,000 F
Variable selling and
administrative expenses 6,500 8,000 2.00 1,500 F
Contribution margin $24,800 $22,000 $2,800 F
Fixed selling and
administrative expenses 8,000 9,100 1,100 F
Total costs $37,500 $47,100
Operating income $16,800 $12,900 $3,900 F
Sales volume variance:
Revenue per unit $15.51 $15.00 $0.51 F
Flexible-budget:Actual Master Budget Variance
Units 3,500 3,500 U
Sales revenue $ 54,300 $ 52,500 $ 1,800 F
Variable manufacturing costs 10,000 14,000 4,000 F
Fixed manufacturing costs 13,000 12,250 750 U
Variable selling and
administrative expenses 6,500 7,000 500 F
Contribution margin $24,800 $19,250 $5,550 F
Fixed selling and
administrative expenses 8,000 9,100 1,100 F
Operating income $16,800 $10,150 $6,650 F
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Which set of ordered pairs represents a function?
{(-6,-4), (1, -7), (-4, 3), (-4, 8)}
{(-8, -3), (-8, 9), (9, 6), (1, -4)}
{(4,1), (-6, 6), (5,-2), (-4,1)}
{(-3, 6), (-1,0), (-8, 1), (-8, -3)}
Answers
Answer:
{(4,1), (-6, 6), (5,-2), (-4,1)} set of ordered pairs represents a function.
Step-by-step explanation:
Because every element or component of domain has unique image in co-domain.
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three hens lay 3 eggs any 3 days. in how many days will 3n hens lay at this rate 9nk eggs? please i need answer fast!!! will give brainliest!
Answers
If three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.
Number of days that three hens lay 9 eggsGiven:
3 hens lay 3 eggs in 3 days
First step is to determine the number of egg one hen lay in 3 days
1 hen in 3 days lays 3/3
1 hen in 3 days lays=1 egg
Second step is to determine the number of egg 3 hens lay 1 day
1 hen in 1 day lays 1/3 egg
3 hens in 1day lay=(1×3)/3
3 hens in 1day lay=1 egg
Third step is to determine the number of eggs 3 hens lay in 9 days
3 hens in 9 days lay=(1×9)
3 hens in 9 days lay=9 eggs
Therefore assuming three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.
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Suppose each edge of the cube shown in the figure is 10 inches long. Find the sine and cosine of the angle formed by diagonals DE and DG.
Answers
Check the picture below.
[tex]sin(EDG )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{10\sqrt{3}}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{sin(EDG )=\cfrac{\sqrt{3}}{\sqrt{3^2}}\implies sin(EDG )=\cfrac{\sqrt{3}}{3}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]cos(EDG )=\cfrac{\stackrel{adjacent}{10\sqrt{2}}}{\underset{hypotenuse}{10\sqrt{3}}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{cos(EDG )=\cfrac{\sqrt{6}}{\sqrt{3^2}}\implies cos(EDG )=\cfrac{\sqrt{6}}{3}}[/tex]