15. Find the young modulus of a brass rod of diameter 25mm and of length 250mm which is
subjected to a tensile load of 50KN when the extension of the rod is equal to 0.3mm.

The times interest earned ratio for 20Y8 and 20Y9 are 11 and 12.6 respectively.

The change in the times interest earned ratio is favorable.

According to the question,

In 20Y8 and 20Y9, Averill Products Inc. disclosed the following on its income statement:

For 20Y9,

Interest expense= $440,000

Income before income tax expense= $5,544,000

Times interest earned ratio= 5544000/440000 = 12.6

For 20Y8,

Interest expense=$400,000

Income before income tax expense=$4,400,000

Times interest earned ratio= 4400000/400000 =11

As the times interest earned ratio for 20Y9 is greater than that for 20Y8,the change in the times interest earned ratio is favorable.

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The chances that NEITHER of these two selected people were born after the year 2000 is 0.36

The given parameters are:

Year = 2000

Proportion of people born after 2000, p = 40%

Sample size = 2

The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:

P = (1- p)^2

Substitute the known values in the above equation

P = (1 - 40%)^2

Evaluate the exponent

P = 0.36

Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36

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The set of natural numbers greater than or equal to 6 will be 6, 7, 8, 9, 10, ....

It should be noted that the first information is about the set of natural numbers greater than or equal to 6. Therefore, they will be 6 and above.

It should be noted that the descriptive form simply states in words the elements that are in a set. It is the verbal description of the elements in the set. It is the determination of the elements that belong to a set and those that doesn't.

Also, the way that a set is described is known as the roster form. In this case, the contents of a set can be described by listing the elements that are in the set which are separated by a comma inside the bracket.

Also, the roster form: (5, 7, 9, 11) indicates odd natural numbers. The numbers that are given are odd.

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Answer:

[tex]y=-2x+1[/tex]

Step-by-step explanation:

Looking at the line can ensure that the slope is negative

The rise/run is 4/-2, ten the slope is:

[tex]s=\frac{-4}{2} =-2[/tex]

b intercept is 1

The equation:

[tex]y=-2x+1[/tex]

Hope this helps

The local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.

Given a graph of a function.

We are required to find:

A)Local minimum over the interval [-3,-1],

B) Local maximum over the interval [-1,0],

C) Local minimum over the interval [0,3].

We know that local maximum is a point after which the value of function starts decreasing and the local minimum is a point after which the value of function starts increasing.

When we see the graph from x=-3 to x=-1 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at x=-2 and y=0, so the value of local minimum will be 0.

When we see the graph from x=-1 to x=0 we can find that the highest point is where the value of f(x) is maximum and after which the graph is decreasing is at  y=4.39, so the value of local maximum will be 4.39.

When we see the graph from x=0 to x=3 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at  y=-32, so the value of local minimum will be -32.

Hence the local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.

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By using an online graphing calculator, the overall equation represented by this scenario is plotted in the image attached below.

Based on the information provided about this company with respect to its delivery and total number of miles to be covered, we would assign variables as follows:

Next, we would translate the word problem into an algebraic equation by using an inequality:

y > x/2 - 3

Also, we would determine the intercepts as follows:

When x = 0, we have;

y = 0/2 - 3

y = -3.

y-intercept = (0, -3).

For the x-intercept, we have:

When y = 0, we have;

0 = x/2 - 3

x/2 = 3

x = 6.

x-intercept = (6, 0).

By using an online graphing calculator, the overall equation represented by this scenario is plotted in the image attached below.

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Answer:

c

Step-by-step explanation:

c is the answer

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

When we expand a function, everything must be multiplied out evenly.

      [tex](x+6)*(x+6)\\=x*x +x*6+6*x+6*6\\=x^2 + 6x + 6x+36\\x^2 +12x+36[/tex]

Answer: x² + 12x + 36

Hope that helps!

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Polynomials are mathematical expressions made up of many terms.

To simplify the polynomial to the maximum, all like terms must be grouped together and rearranged from highest to lowest power.

Distribute

Combining like terms.

Answer:

C. Subtract 4 from both sides.

Step-by-step explanation:

You need the equation in the form x² + ax + b = 0 to then either try factoring or use the quadratic formula.

In order to achieve that, you need to first:

Subtract 4 from both sides.

The z-score for a data value of 19 if the mean of a set of data is 37 and the standard deviation is 8.6 is -2.09

From the question, the given parameters about the distribution are

Mean value of the set of data = 37

Standard deviation value of the set of data = 8.6

The actual data value = 19

The z-score of the data value is calculated using the following formula

z = (x - mean value)/standard deviation

Substitute the given parameters in the above equation

z = (19 - 37)/8.6

Evaluate the difference of 19 and 37

z = -18/8.6

Evaluate the quotient of -18 and 8.6

z = -2.09

Hence, the z-score for a data value of 19 if the mean of a set of data is 37 and the standard deviation is 8.6 is -2.09

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Answer:

-2s-18 is the simplified answer

Step-by-step explanation:

s-3(s+6)

distributive property

s-3s-18

-2s-18

The given statement that, decimal, fraction, and percent can all represent the same values is True.

Verification of the True Statement:

The ratio of two numbers results in a fraction which are often rational numbers (often integers). As an illustration, 11/59 is a fraction. Typically, absolute values for fractions should be larger than 0 and less than 1. A mixed fraction equivalent to 1 3/4 is 7/4.

A fraction stated in tenths are known as a decimal (or tenths of tenths, etc.). The decimal equivalent of one fourth, or 1/4 as a fraction, is 0.25 (which equals 25/100). (Remember that 1/100 is just a tenth of a tenth.)

Percentage (percent) is a decimal fraction multiplied by 100. Therefore, 0.25 is equivalent to 25 percent, for instance. The ratio of two numbers results in fractions, which are often rational numbers (often integers).

Let us take a number 3/5, this is a fraction.

Now, if we further divide, 3 by 5, we will get 0.6

This 0.6 is a decimal number, but it still represents the number 3/5

Similarly, it is equivalent to 60 percent which again represent the fraction 3/5 or decimal 0.6.

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Answer:

6

Step-by-step explanation:

[tex]\frac{DC}{4}=\frac{12}{8} \\ \\ DC=6[/tex]

Answer:

55

Step-by-step explanation:

[tex]\sqrt{3018+\sqrt{36+\sqrt{169} } }[/tex]

= [tex]\sqrt{3018+\sqrt{36+13} }[/tex]

= [tex]\sqrt{3018+\sqrt{49} }[/tex]

= [tex]\sqrt{3018+7}[/tex]

= [tex]\sqrt{3025}[/tex]

= 55

The value of x in (1/6)/2 = x/3 is 1

The equation is given as

(1/6)/2 = x/3

Cross multiply in the above equation

x * 2 = (1/6) * 3

This gives

x * 2 = 1/2

Cross multiply

x = 2 * 1/2

This gives

x = 1

Hence, the value of x in (1/6)/2 = x/3 is 1

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Answer:

See below

Step-by-step explanation:

Assuming the interest is compounded annually

x * (1 + .10)^5 = 1.61051  x

  your final amount will be  1.61051 times bigger than the initial deposit

In order to calculate the confidence Interval, what we need is the t distribution. The population mean number of visits is 11.667 and 19.9928 visits. 95 percent contains true mean while the other 5 does not.

We have n = 12

df = n- 1 = 11

a. To compute the confidence interval use a t distribution.

The mean = fx/n

= 15.83

level of significance = 0.05

standard deviation = 6.555

t α/2, df = 2.20

standard error  = 6.555 / √ 12 = 1.8922

margin of error , = 2.2 * 1.8922 = 4.1628

barx - E = 15.83 - 4.1628 = 11.6672

barx + E = 15.83 + 4.1628 = 19.9928

With 95% confidence the population mean number of visits  is between 11.667 and 19.9928 visits.

c. About 95 percent of these confidence intervals will contain true mean.

about __5__percent will not contain the true population

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Answer:

No, she is wrong

Step-by-step explanation:

[tex]\frac{60}{36} = \frac{5}{3}[/tex] {Simplification}

[tex]\frac{5}{3} \neq \frac{1}{6}[/tex]

Answer:i got 329

Step-by-step explanation:

Answer:(5-1)(7-1)

Step-by-step explanation:

We have give 4 numbers that are 1,1,5,7. we have to apply operations on it to make it 24.

» ( 7 - 1) × (5 - 1)

» (6) × (4)

» 24

Here's our answer..!!

The stages to utilize to construct a frequency distribution table utilizing Sturge's approximation are as follows:

The steps to create a frequency distribution table utilizing Sturge's approximation exist as follows;

Step 1: Estimate the range of the data:

This exists simply by finding the difference between the biggest and the least values.

Step 2: Decide on the inaccurate number of classes in which the provided data exist to be grouped. The formula for this is;

K = 1 + 3.322logN

where; K= Number of classes

logN = Logarithm of the whole number of observations.

Step 3: Specify the approximate class interval size:

This exists acquired by splitting the range of data by the number of classes and exists symbolized by h class interval size.

Step 4: Find the starting point:

The lower class limit should take care of the least value in the raw data.

Step 5: Determine the remaining class boundaries:

When you have reached the lowest class boundary, then you can count the class interval size to the lower class boundary to obtain the upper-class boundary.

Step 6: Circulate the data into separate classes.

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Answer:

43 degrees

Step-by-step explanation:

First, notice that we can draw a right triangle to represent this situation. The vertical leg of the triangle corresponds to the tower, and the horizontal leg corresponds to the shadow. The height of the tower, 114, is OPPOSITE, and the length of the shadow, 121, is ADJACENT to the angle of elevation to the top of the tower. Remember SOH CAH TOA, we can use TAN to find the angle since we know the values of O and A.

TAN(x) = O/A

TAN(x) = 114/121

x = ARCTAN(114/121)

x = 43

792 different sets of 7 colors can be chosen.

Remember that if we have a set of N elements, the number of different sets of K elements that we can make out of these N elements is given by:

C(N, K) = N!/(N - K)!*K!

In this case, we have 12 distinct colors and we want to select 7, so we have:

N = 12

K = 7

Replacing that we get:

C(12, 7) = 12!/(12 - 7)!*7! = 12*11*10*9*8/(5*4*3*2*1) = 792

792 different sets of 7 colors can be chosen.

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the correct option is:

"The distance from the origin to point A is equal to the radius of circle P. Therefore, point A lies on circle P."

A circle is defined as the set of equidistant points to a given point which is the center of the circle.

That distance to the center is called the radius.

Here, the center is at the point (0, 0), also called the origin, so if the distance between the point A and the origin, then point A lies on top of the circle P.

From that, we conclude that the correct option is:

"The distance from the origin to point A is equal to the radius of circle P. Therefore, point A lies on circle P."

That is the only proof that we can (and should) use to prove that a point lies on a circle.

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Answer:

The distance from the origin to point A is equal to the radius of circle P. Therefore, point A lies on circle P."

Step-by-step explanation:

I did the test

[tex]number \: of \: performances = 9 \\ note = \\ one \: insists \: on \: being \: last \\ number \: of \: flexible \: performances = 9 - 1 = 8 \\ \\ c( \gamma ) = 8P8 \times 1 \\ c( \gamma ) = 8! \\ c( \gamma ) = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \\ c( \gamma ) = 40320 \: ways[/tex]

Answer:

Step-by-step explanation:

Comment and Answer

This is a very well laid out proof. It would good for you to see how carefully this this proof has been set up.

Step Three says

DE = DF ÷ 2

The problem is that at least 2 of the choices will work. I think the best reason is that it is the definition of bisect. The previous statement says in language what  statement three says in algebraic notation. So statement 2 is the given statement. Statement 3 tells us that DE is 1/2 DF because it is bisected.

Answer A

Using a calculator, the critical value for the t-distribution with a confidence level c=0.80 and sample size n=29 is of Tc = 1.3125.

It is found using a calculator, with two inputs, which are given by:

In this problem, the inputs are given as follows:

Hence, using a calculator, the critical value for the t-distribution with a confidence level c=0.80 and sample size n=29 is of Tc = 1.3125.

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The number of points of intersection between the rectangle and hexagon is = 4

The point of intersection between two or more lines is where the lines met at a particular plane. The point of intersection an equally be referred to as the vertex.

A rectangle is a quadrilateral because it's made up of four sides of which the two sides which are opposite, are equal and parallel.

A triangle is a polygon that is made up of three lines that meet to form edges and angles.

A hexagon is a polygon that is made up of six sides and six angles.

From the attached image, the rectangle which has four sides, made an intersection with the hexagon at four points which are marked with an asterisk.

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Answer:

2

Step-by-step explanation:

Answer: A

Step-by-step explanation: Because it can be simplified twice.

a) The factor form of the polynomial is f(x) = 4 · (x - 3) · (x + 5 / 4).

b) The values of the x-intercepts of the graph of f(x) are represented by the roots found in part a).

c) The function has a minimum and grows in the + y direction.

d) Marking the two x-intercepts, second, generating a line perpendicular to the x-axis that passes the midpoint of the line segment generated by the two intercepts and estimate the location of the vertex and, finally, creating a parabola with a minimum and growing in the + y direction by matching the points.

In this problem we have a quadratic function in standard form, that is, an equation of the form f(x) = a · x² + b · x + c, where a, b and c are real coefficients. a) First, we need to complete the square and find the roots to determine the factorized form:

4 · x² - 7 · x - 15 = 0

4 · [x² - (7 / 4) · x - (15 / 4)] = 0

x² - (7 / 4) · x - (15 / 4) = 0

x² - 2 · (7 / 8) · x - (15 / 4) + (289 / 64) = 289 / 64

x² - 2 · (7 / 8) · x + 49 / 64 = 289 / 64

(x - 7 / 8)² = 289 / 64

x - 7 / 8 = ± 17 / 8

x = 7 / 8 ± 17 / 8

Then, the factor form of the polynomial is f(x) = 4 · (x - 3) · (x + 5 / 4).

b) The values of the x-intercepts of the graph of f(x) are represented by the roots found in part a).

c) The end behavior of the graph is inferred from the lead coefficient. A positive coeffcient , which is the case of the function, indicates that vertex of the polynomial is a minimum and parabola grows in the + y direction.

d) In accordance with algebra, we can generate a quadratic equation by knowing three distinct points on Cartesian plane.

First, mark the two x-intercepts, second, generate a line perpendicular to the x-axis that passes the midpoint of the line segment generated by the two intercepts and, finally, generate a parabola with a minimum and growing in the + y direction.

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Answer: 1, 2, 5, 10

Step-by-step explanation:

1 x 30 = 30

1 x 20 = 20

2 x 15 = 30

2 x 10 = 20

5 x 6 = 30

5 x 4 = 20

10 x 3 = 30

10 x 2 = 20