how to calculate voltage current and resistance in a circuit

Answers

Answer 1

Ohm’s Law is the most common method used to calculate voltage, current, and resistance in a circuit.

Ohm’s Law states that voltage (V) is equal to the product of current (I) and resistance

(R), or V = I x R.

Therefore, to calculate voltage, current, or resistance in a circuit using Ohm’s Law, the two other quantities must be known. For instance, if the current and resistance are known, the voltage can be calculated by multiplying the current by the resistance. Likewise, if voltage and resistance are known, the current can be calculated by dividing the voltage by the resistance. Finally, if voltage and current are known, resistance can be calculated by dividing the voltage by the current.

The power equation is another method used to calculate voltage, current, and resistance in a circuit. The power equation states that power (P) is equal to the product of voltage (V) and current (I), or P = V x I. Therefore, to calculate voltage, current, or resistance in a circuit using the power equation, two other quantities must be known. If voltage and current are known, power can be calculated by multiplying the voltage by the current. If power and voltage are known, current can be calculated by dividing the power by the voltage. Finally, if power and current are known, the voltage can be calculated by dividing the power by the current.

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Related Questions

Question 3 (1 point) On an assembly line, a robot is responsible for accelerating a piece of equipment from rest at 7.29 m/s^2
over a horizontal displacement of 140 m. How long does it take to complete this task? Your Answer: Answer units

Answers

It takes approximately 19.21 seconds for the robot to accelerate the equipment over a horizontal displacement of 140 m.

To determine the time it takes for the robot to accelerate the equipment, we can use the kinematic equation:

v² = u² + 2as

Where:

v is the final velocity

u is the initial velocity (which is 0 m/s since the equipment starts from rest)

a is the acceleration

s is the displacement

In this case, we need to solve for time (t). Rearranging the equation, we have:

t = (v - u) / a

Since the equipment starts from rest (u = 0 m/s), the equation simplifies to:

t = v / a

Substituting the given values:

t = 140 m / (7.29 m/s²)

Calculating:

t ≈ 19.21 seconds

Therefore, it takes approximately 19.21 seconds for the robot to accelerate the equipment over a horizontal displacement of 140 m.

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or a turning operation, a thrust force of 600 N and cutting force of 900 N are measured. The cutting speed is 2.5 m/sec, and the depth of cut is 2 mm. The tool rake angle is 12 deg and the cutting ratio r is 0.555. If Merchant theory applies, find the power consumed machining the material and the coefficient of friction between the chip and the tool. Use the graphical method.

Answers

In order to find out the power consumed machining the material and the coefficient of friction between the chip and the tool using graphical method with given conditions, we need to follow the steps given below.

Step 1: Calculate the cutting velocity vC:Given, cutting speed = 2.5 m/secDiameter of workpiece, D = 120 mmWe know that, cutting velocity vC = (πDN)/1000where, N = rotational speed in revolutions per minute= (1000 x cutting speed) / (πD)Putting the given values in the above formula,[tex]vC = (π x 120 x 1000 x 2.5) / (1000 x π)= 300 m/min , the cutting velocity vC is 300 m/min.[/tex]

Step 2: Calculate the chip thickness (h)The cutting ratio r is given asr = (t - h) / hwhere, t = depth of cut = 2 mmPutting the given values in the above formula,0.555 = (2 - h) / hh = (2 / 1.555)= 1.287 mm, the chip thickness h is 1.287 mm.

Step 3: Calculate the shear angle (φ):We know that, tan φ = (fcosα - tsinα) / (fsinα + tcosα)where, f = cutting force = 900 Nt = thrust force = 600 Nα = tool rake angle = 12° Putting the given values in the above formula,

[tex]tan φ = (900cos12 - 600sin12) / (900sin12 + 600cos12)= 0.2268, the shear angle φ is 12.56°.[/tex]

Step 4: Calculate the shear strain rate:Given, cutting speed = 2.5 m/sec Diameter of workpiece, D = 120 mmThe cutting velocity vC = 300 m/minChip thickness h = 1.287 mm We know that,γ = vC / (h x f) Putting the given values in the above formula,γ = (300 x 10^-3) / (1.287 x 900)= 0.2599 x 10^-3/sec  , the shear strain rate γ is 0.2599 x 10^-3/sec.

Step 5: Calculate the coefficient of friction:We know that,γ = (πD^2)/4 x V x k x cos φwhere, k = coefficient of friction Putting the given values in the above formula,k = γ / [(πD^2)/4 x V x cos φ] Putting the given values in the above formula,[tex]k = (0.2599 x 10^-3)/ [(π x 120^2)/4 x 300 x cos12.56]= 0.33,[/tex] the coefficient of friction is 0.33.

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What is the rotational inertia of a solid iron disk of mass 37.0 kg, with a thickness of 5.00 cm and radius of 19.0 cm, about an axis through its center and perpendicular to it? kg⋅m^2

Answers

The rotational inertia of a solid iron disk of mass 37.0 kg, with a thickness of 5.00 cm and radius of 19.0 cm, about an axis through its center and perpendicular to it is 0.6674 kg⋅m².

What is rotational inertia?

Rotational inertia is the resistance of a rotating object to any change in its rotational motion. The measurement of an object's rotational inertia is known as the moment of inertia. It is calculated by multiplying the mass of an object by the square of the distance from the axis of rotation to the object's center of mass.

Rotational inertia is important in many fields, including engineering, physics, and sports. Understanding the moment of inertia of an object allows for more efficient and accurate designs of various mechanical systems.

To find the rotational inertia of a solid iron disk about an axis through its center and perpendicular to it, we can use the formula for the rotational inertia of a solid disk:

I = (1/2) * m * r²

Where:

I is the rotational inertia (also known as the moment of inertia),

m is the mass of the disk, and

r is the radius of the disk.

In this case, the mass of the disk is given as 37.0 kg and the radius is 19.0 cm (which is 0.19 m).

Plugging these values into the formula, we have:

I = (1/2) * 37.0 kg * (0.19 m)²

Calculating this expression:

I = 0.5 * 37.0 kg * (0.19 m)²

I = 0.5 * 37.0 kg * 0.0361 m²

I = 0.5 * 1.3347 kg⋅m²

I ≈ 0.6674 kg⋅m²

Therefore, the rotational inertia of the solid iron disk about an axis through its center and perpendicular to it is approximately 0.6674 kg⋅m².

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A spaceship of mass 2.35×10^6 kg is to be accelerated to a speed of 0.850c. (a) What minimum amount of energy does this acceleration require from the spaceship's fuel, assuming perfect efficiency? 1 (b) How much fuel would it take to provide this much energy if all the rest energy of the fuel could be transformed to kinetic energy of the spaceship? kg

Answers

The minimum energy required to accelerate the spaceship to 0.850c is [tex]\(6.613 \times 10^{23}\) J.[/tex]Assuming perfect efficiency and all fuel rest energy transformed to kinetic energy, it would take [tex]\(2.35 \times 10^{-10}\)[/tex] kg of fuel to provide the required energy.

To calculate the minimum energy required to accelerate the spaceship, we can use Einstein's mass-energy equivalence principle, [tex]\(E = mc^2\)[/tex], where m is the mass and c is the speed of light.

[tex]\[ \text{Kinetic Energy} = E_f - E_i \][/tex]

Given values:

Mass of spaceship (m) = [tex]\(2.35 \times 10^6\)[/tex]kg

Speed of light (c) = [tex]\(3 \times 10^8\)[/tex] m/s

Final speed ([tex]\(v_f\)[/tex]) = [tex]\(0.850c\)[/tex]

Calculate the final energy ([tex]\(E_f\)[/tex]):

[tex]\[ E_f = mc^2 = (2.35 \times 10^6 \, \text{kg}) \times (3 \times 10^8 \, \text{m/s})^2 \\\\= 6.615 \times 10^{23} \, \text{J} \][/tex]

The initial energy ([tex]\(E_i\)[/tex]) is the rest energy of the spaceship, which can be calculated using the rest mass-energy equivalence:

[tex]\[ E_i = mc^2 \\\\= (2.35 \times 10^6 \, \text{kg}) \times (3 \times 10^8 \, \text{m/s})^2 \\\\= 2.115 \times 10^{17} \, \text{J} \][/tex]

Substitute the values to find the kinetic energy required:

[tex]\[ \text{Kinetic Energy} = E_f - E_i \\\\= (6.615 \times 10^{23} \, \text{J}) - (2.115 \times 10^{17} \, \text{J})\\\\ = 6.613 \times 10^{23} \, \text{J} \][/tex]

Part (b): Fuel Required

To find the amount of fuel required, we need to calculate the mass equivalent of the energy required using the mass-energy equivalence ([tex]\(E = mc^2\)[/tex]) and then divide it by the rest energy of the fuel:

[tex]\[ \text{Fuel Mass} = \dfrac{\text{Kinetic Energy}}{c^2} \][/tex]

[tex]\[ \text{Fuel Mass} = \dfrac{2.115 \times 10^{17} \, \text{J}}{(3 \times 10^8 \, \text{m/s})^2} \\\\= 2.35 \times 10^{-10} \, \text{kg} \][/tex]

Thus, it would take approximately [tex]\(2.35 \times 10^{-10}\)[/tex] kg of fuel to provide the energy required for the spaceship's acceleration.

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Discussion 14:
You are standing on the roadside when an ambulance is approaching you. Explain why the siren of an ambulance gets louder and high pitch as it moves toward you. Also, the sound gets softer and low pitch as it moves away from you. Integrate Doppler effect in your discussion. Elaborate your answer.

Answers

The siren of an ambulance appears louder and higher in pitch as it moves toward you due to the Doppler effect. This effect is caused by the relative motion between the source of sound (ambulance) and the observer (you), resulting in a change in perceived frequency. As the ambulance moves away, the sound becomes softer and lower in pitch.

The Doppler effect is the change in frequency or pitch of a sound wave due to the relative motion between the source of the sound and the observer. When the ambulance approaches you, its motion compresses the sound waves it emits, causing the wavelength to shorten and the frequency to increase. This increase in frequency makes the sound appear higher in pitch.

As the ambulance moves away from you, the sound waves are stretched out, resulting in a longer wavelength and a decrease in frequency. The decrease in frequency makes the sound appear lower in pitch.

The perceived change in loudness is related to the intensity of the sound waves. As the ambulance approaches, the sound waves are compressed, leading to a more concentrated and intense sound, which makes it appear louder. Conversely, as the ambulance moves away, the sound waves spread out, causing a decrease in intensity and perceived loudness.

Therefore, the combination of the Doppler effect and the change in intensity results in the siren of an ambulance appearing louder and higher in pitch as it approaches and softer and lower in pitch as it moves away from an observer.

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What is the medium for propagation of sound

Answers

The medium for propagation of sound refers to the substance through which sound waves can travel. Sound waves can propagate through various mediums, including gases, liquids, and solids.Sound waves require a medium to travel through, as they are a type of mechanical wave.

The medium through which sound waves travel can have an impact on the speed, direction, and intensity of the sound waves.

Gases: In gases, sound waves can travel through the movement of molecules. These molecules collide with each other, transferring kinetic energy and producing pressure waves that can be detected as sound.

Liquids: In liquids, sound waves can travel through the vibration of molecules. Liquids are more dense than gases, meaning that sound waves can travel faster through liquids. The vibration of molecules transfers energy, producing waves that can be detected as sound.

Solids: In solids, sound waves can travel through the movement of particles. Solids are the most dense medium for sound waves, allowing them to travel even faster than in liquids.

When sound waves move through a solid, the particles move back and forth in the direction of the wave, transmitting energy that produces sound waves.

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A golfer hits a shot to a green that is elevated 2.60 m above the point where the ball is struck. The ball leaves the club at a speed of 17.8 m/s at an angle of 52.0

above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands.

Answers

The horizontal component of the initial velocity of the ball is 17.8cos(52°) = 10.6m/s and the vertical component is 17.8sin(52°) = 14.0m/s.

When the ball reaches its maximum height, its vertical component of velocity is 0 (at the highest point, the ball has no more upward velocity), so using the formula

v = u + at,

where v is the final velocity,

u is the initial velocity,

a is the acceleration due to gravity and t is the time taken to reach the highest point of the ball's trajectory. We can find t as u = 14.0m/s,

a = -9.8m/s² (negative due to gravity), and

v = 0:0 = 14.0 + (-9.8)t=> t = 1.43 seconds

The time taken for the ball to reach the ground from its highest point is equal to the time it takes for the ball to reach that highest point.

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A system has a natural frequency of 50 Hz. Its initial displacement is .003 m and its initial velocity is 1.0 m/s. a. Express the motion as a cosine function x(t) = Acos(wnt + p). b. Express the motion as the sum of a cosine and sine function x(t) = A,cos(wnt) + A₂sin(wnt).

Answers

When the natural frequency of a system is 50 Hz, we know that: [tex]$$\omega_n = 2\pi f = 2\pi \times 50 = 100\pi \text{ rad/s}$$[/tex]

The expression for displacement of a mass on a spring is given by:

[tex]$$x(t) = A\cos (\omega_n t + \phi)$$[/tex]

where A and [tex]$\phi$[/tex] are constants determined by the initial conditions.

To find A and we use the initial conditions.

We know that at

t = 0,

displacement is 0.003m and velocity is 1.0m/s.

[tex]$$\begin{aligned} x(0) &= A\cos \phi = 0.003 \\ \frac{dx}{dt} \bigg|_{t=0} &= -\omega_n A\sin \phi = 1.0 \end{aligned}$$[/tex]

Dividing the second equation by the first, we get:

[tex]$$-\omega_n \tan \phi = \frac{1.0}{0.003}$$$$\tan \phi = - \frac{1}{300 \pi}$$[/tex]

which gives us .

Then we can use the first equation to get A,

which is the amplitude of the motion.

We can also express displacement as a sum of cosine and sine functions.

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A 0.050 kg yo-yo is swung in a vertical circle on the end of its 0.30 m long string at the slowest speed that the yo-yo can have. (8 marks)

a) What is this speed at the top of the circular path? Include a labelled free-body diagram with your answer.

b) What is this speed at the bottom of the circular path?

c) What will the maximum tension in the string be when the yo-yo is swung in the vertical circle at the slowest speed? Where will this maximum tension occur? Include a labelled free-body diagram with your answer.

Answers

a) The speed of the yo-yo at the top of the circular path is given by:

v² = gr [r + h]

Where, v = velocity

g = acceleration due to gravity

r = radius

h = height

Here, r = 0.30m (length of the string)

h = r

  = 0.30m (height of the circle at the top)

g = 9.8 m/s²

Putting these values in the above equation,

v = √(9.8 × 0.6) = 3.4 m/s

The free-body diagram for the yo-yo at the top of the circular path is given below:

b) The speed of the yo-yo at the bottom of the circular path is given by:

v² = gr [r - h]

Where, v = velocity

g = acceleration due to gravity

r = radius

h = height

Here, r = 0.30m (length of the string)

h = r

  = 0.30m (height of the circle at the bottom)

g = 9.8 m/s²

Putting these values in the above equation,

v = √(9.8 × 0.0)

  = 0 m/s

The free-body diagram for the yo-yo at the bottom of the circular path is given below:

c) The maximum tension in the string occurs when the yo-yo is at the bottom of the circular path. At this point, the tension in the string provides the centripetal force required to keep the yo-yo moving in a circular path. The maximum tension in the string is given by:

T = mg + mv² / r

Where, T = tension in the string

m = mass of the yo-yo

v = velocity

r = radius

g = acceleration due to gravity

At the slowest speed, v = 0 and hence, the maximum tension in the string is given by:

T = mg + 0

  = mg

  = 0.050 × 9.8

  = 0.49 N

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how to tell which light is out on christmas lights

Answers

To determine which light is out on a string of Christmas lights, you can follow these steps  are  Ensure Safety,   Inspect the Bulbs, Replace Bulbs,Check the Light Set,    Wiggle and Inspect, Use a Light Tester.

The following steps are :

   Ensure Safety: Make sure the Christmas lights are unplugged from the power source before attempting any inspection or repair.    Inspect the Bulbs: Carefully examine each bulb in the string of lights. Look for any bulbs that appear darker or have a broken filament. A darkened or blackened bulb is often an indicator that it has burned out.    Replace Bulbs: Once you identify a potentially faulty bulb, you can try replacing it with a new one of the same type and rating. Gently remove the defective bulb from its socket and insert the new one securely.    Check the Light Set: After replacing the suspected faulty bulb, plug in the lights to see if they are working properly. If they are still not functioning, move on to the next step.    Wiggle and Inspect: Sometimes a loose or improperly seated bulb can cause the entire string of lights to go out. Carefully wiggle each bulb in its socket while the lights are plugged in to see if any faulty connection causes the lights to flicker or come back on temporarily. Additionally, visually inspect the sockets for any signs of damage or corrosion.    Use a Light Tester: If you are having difficulty identifying the problematic bulb, you can utilize a Christmas light tester, which is a handheld device specifically designed to help locate faulty bulbs in a string of lights. Simply follow the instructions provided with the light tester to identify the defective bulb.

By systematically inspecting and replacing bulbs, checking for loose connections, and utilizing a light tester if needed, you can identify and replace the faulty light, allowing your Christmas lights to shine brightly once again.

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Question 13 0.1 pts In a two-slit experiment, monochromatic coherent light of wavelength 600 nm passes through a pair of slits separated by 2.20 105 m. At what angle away from the centerline does the second dark fringe occur? ○ 4.70° O 2.34° O 3.94⁰ 3.51 O 1.17 0.1 pts Question 14 A two-slit arrangement with 60.3 um separation between the slits is illuminated with 537.0-nm wavelength light. If a viewing screen is located 2.14 m from the slits find the distance on the screen from the first dark fringe on one side of the central maximum to the second dark fringe on the other

Answers

In a two-slit experiment, when monochromatic coherent light passes through a pair of slits, an interference pattern is formed on a screen located at a certain distance away from the slits. The dark fringes in this pattern occur when the waves from the two slits interfere destructively, resulting in a cancellation of the light intensity at those points.

To find the angle at which the second dark fringe occurs in the given scenario, we can use the formula for the position of dark fringes in a two-slit experiment:

y = (m * λ * L) / d

where:

y is the distance from the centerline to the fringe,

m is the order of the fringe (m = 1 for the first dark fringe, m = 2 for the second dark fringe, and so on),

λ is the wavelength of light,

L is the distance between the slits and the screen, and

d is the separation between the slits.

Given:

λ = 600 nm = 600 * 10^(-9) m

d = 2.20 * 10^(-5) m

m = 2

L is not given.

Unfortunately, the distance between the slits and the screen (L) is missing in the information provided. Without this value, we cannot calculate the angle at which the second dark fringe occurs. Therefore, the correct answer cannot be determined with the given information.

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The position of a particle is expression as r= 2t i + t²j+ t³ k, where r is in meters and t in seconds. a) Find the scalar tangential components of the acceleration at t=1s. b) Find the scalar normal components of the acceleration at t = 18.

Answers

Given that the position of a particle is expression as

r= 2t i + t²j+ t³ k,

where r is in meters and t in seconds.  We need to find the scalar tangential components of the acceleration at t=1s and scalar normal components of the acceleration at t = 18.

a) Scalar tangential components of the acceleration at t=1s:We know that, Velocity of the particle is given by the differentiation of the given position of the particle.

r = 2ti + t²j + t³k

Differentiating r with respect to time t, we get

v = dr/dt = 2i + 2tj + 3t²k

Differentiating v with respect to time t, we get

a = dv/dt = 0i + 2j + 6tkAt t = 1s

The acceleration of the particle is given by,Substituting t = 1s in the above equation, we get

a = 0i + 2j + 6k

Therefore, the scalar tangential components of the acceleration at t=1s is given by the dot product of the acceleration vector and the unit tangent vector at t=1s. The unit tangent vector at t=1s is given by,The magnitude of the acceleration is,So, the scalar tangential components of the acceleration at t=1s is given by

aT = a . T= (2.449j + 0.588k).(0.554i + 0.832j)= 1.358

b) Scalar normal components of the acceleration at t = 18:

We know that, Velocity of the particle is given by the differentiation of the given position of the particle.

r = 2ti + t²j + t³k

Differentiating r with respect to time t, we get,

v = dr/dt = 2i + 2tj + 3t²k

Differentiating v with respect to time t, we get

a = dv/dt = 0i + 2j + 6tkAt t = 18s,

The acceleration of the particle is given by,Substituting t = 18s in the above equation, we get

a = 0i + 2j + 6(18)k= 0i + 2j + 108k

Therefore, the scalar normal components of the acceleration at t = 18 is given by the dot product of the acceleration vector and the unit normal vector at t = 18. The unit normal vector at t=18 is given by,The magnitude of the acceleration is,So, the scalar normal components of the acceleration at t = 18 is given by

aT = a . N= (1.928j + 0.296k).(0.830i - 0.558j)= -0.515

Therefore, the scalar normal components of the acceleration at t = 18 is -0.515.

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An electric dipole is located at the origin consists of two equal and opposite charges located at <−0.01,0,0>m and <0.01,0,0>m. The electric field at <0,1,0>m has a magnitude of 1 N/C. What is the approximate magnitude of the electric field at <0,2,0>m

×


1.00 N/C
0.13 N/C
0.50 N/C
0.25 N/C

None of the above

Answers

The approximate magnitude of the electric field at point Q(<0,2,0>) is 0.015 N/C. The correct option is (B) 0.13 N/C.

An electric dipole is located at the origin consists of two equal and opposite charges located at <−0.01,0,0>m and <0.01,0,0>m.

The electric field at <0,1,0>m has a magnitude of 1 N/C.

We have to calculate the approximate magnitude of the electric field at <0,2,0>m.

Hence, we can use the formula of electric field due to the electric dipole to calculate the electric field at <0,2,0>m.

Electric field due to an electric dipole is given as

E = 1 / 4πε₀ * p / r³

Where, E is the electric field at a point p is the magnitude of electric dipoler is the distance between the point and the midpoint of the dipole 4πε₀ is the permittivity of free space

Putting the values in the above formula, we get

E = 1 / 4πε₀ * 2q * d / r³Where,2q is the magnitude of electric dipoled is the distance between the point and the midpoint of the dipole 4πε₀ is the permittivity of free space

Thus, the distance of point P(<0,1,0>) from the midpoint of the dipole is

r = √(0.01)² + 1²

r = √(0.0001 + 1)

≈ √(1)

= 1 m

And the distance of point Q(<0,2,0>) from the midpoint of the dipole is

r' = √(0.01)² + 2²r'

= √(0.0001 + 4)

≈ √(4)

= 2 m

We know that the magnitude of electric dipole (p) is given by

p = 2qa

Where, q is the magnitude of the charge and a is the distance between the two charges

Putting the values of q and a in the above formula, we get

p = 2 * 1 * 0.01

p = 0.02 C-m

Thus, the electric field at point P(<0,1,0>) is given by

E = 1 / 4πε₀ * p / r³Putting the values in the above formula, we get

E = 1 / 4πε₀ * 0.02 / 1³

E = 1 / 4πε₀ * 0.02

E = 0.14 N/C

Similarly, the electric field at point Q(<0,2,0>) is given by

E' = 1 / 4πε₀ * p / r'³

Putting the values in the above formula, we get

E' = 1 / 4πε₀ * 0.02 / 2³

E' = 1 / 4πε₀ * 0.02 / 8

E' = 1 / 4πε₀ * 0.0025

E' = 0.015 N/C

The correct option is (B) 0.13 N/C.

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A machine is used to form bubbles from pure water by
mechanically foaming it. The surface tension of water is 0:070 N
m-1. What is the gauge pressure inside bubbles of radius 10 m?

Answers

The gauge pressure inside the bubble is 14,000 N/m² or 14,000 Pa. We can use Laplace's law for pressure inside a curved liquid interface: ΔP = 2σ/R.

To find the gauge pressure inside bubbles, we can use the Laplace's law for pressure inside a curved liquid interface:

ΔP = 2σ/R

where ΔP is the pressure difference across the curved interface, σ is the surface tension of water, and R is the radius of the bubble.

Given:

Surface tension of water (σ) = 0.070 N/m

Radius of the bubble (R) = 10 μm = 10 × 10^(-6) m

Substituting the values into the equation, we have:

ΔP = 2σ/R

= 2 * 0.070 / (10 × 10^(-6))

= 14,000 N/m²

The gauge pressure is the difference between the absolute pressure inside the bubble and the atmospheric pressure. Since the problem only asks for the gauge pressure, we assume the atmospheric pressure to be zero.

Therefore, the gauge pressure inside the bubble is 14,000 N/m² or 14,000 Pa.

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Other Questions
An aeroplane has 30 seats. 95% of people show up for their journey. You have been hired by the travel company to recommend how many tickets they sell for the aeroplane. Stating your assumptions clearly and explaining the risk to the company of having a passenger who can't get on the plane show how many tickets you would sell. The financial statement that reports revenues and expenses is the O A. Statement of changes in equity OB. Statement of financial position O C. Statement of income D. Statement of cash flow What is the Phase constant? Express your answer in radians to three significant figures. I know the phase constant is 3pi/2 but I don't how to convert it to three sig figs. Please help! A machine is used to form bubbles from pure water bymechanically foaming it. The surface tension of water is 0:070 Nm-1. What is the gauge pressure inside bubbles of radius 10 m? In December 2020, following an investigation by the Competition and Markets Authority (CMA), 2 UK-based companies who supply groundworks products to some of the nations largest construction firms, have been fined 15m for colluding illegally to reduce competition and maintain or increase prices for over 2 years. This involved sharing confidential information on future pricing and commercial strategy and monitoring each others prices.a) Use economic theory to explain how firms can sustain collusion in the market when they interact repeatedly.b) When does economic theory suggest that collusion is more likely to be successful?c) How does information sharing and monitoring help sustain the collusion in the above case? what instrument is jack teagarden most famous for playing? One of the core job characteristics in the Job Characteristics Model of job enrichment is: O a. affiliation. O b. task division. O c. power. O d. skill variety. A politician is speaking in a public debate and employs make-up artists, fashion advisors, and speech trainers to improve her presentation and credibility. Her approach emphasises which component of persuasion? O a. The message O b. The source O c. The context O d. The recipient Which of the following situations is best analysed using equity theory? O a. Cindy likes the people she works withO b. Karen gets a good salary considering her needs O c. Beth gets more money than Liz even though their jobs are essentially the same and both work equally hard O d. Liz is happy with her job because it is challenging Intrinsic work rewards: O a. result directly from task accomplishment. O b. are controlled externally by supervisors.O c. are controlled by co-workers. O d. result directly from pay. Which of the following is a MBTI orientation? O a. Locus of control O b. Thinking verses feeling O c. Conscientiousness O d. Openness to experience Expresses similar traits to psychopathy but individuals develop these traits as a result of poor parenting and other environmental factors. O a. Sadism O b. Sociopathy O c. Masochism O d. Crimonopathy Bias (in relation to cognitive ability testing): O a. Is none of the above. O b. Is a statistical term relating to errors of prediction. O c. Is a value judgement. O d. Relates to the extent to which the test taker has had the opportunity to become familiar with the subject matter. Which does not describe someone with a Type A personality?O a. Impatience with anything that interferes with goal attainment O b. Workaholic tendenciesO c. Unlikely to react in a hostile or aggressive manner O d. Constant feeling of time urgency Tele Ltd has a beta of 1.4 and is trying to calculate its cost of equity capital. If the risk-free rate of return is 5 percent and the market risk premium (market return minus risk-free rate) is 6 percent, then what is the rate of market return? A. 15.14% B. 10.60% C. 11.00% D. 11.20% Required information [The following information applies to the questions displayed below.] Shadee Corp. expects to sell 650 sun visors in May and 350 in June. Each visor sells for $18. Shadee's beginning and ending finished goods inventories for May are 75 and 40 units, respectively, Ending finished goods inventory for June will be 60 units. Each visor requires a total of $3.50 in direct materials that includes an adjustable closure that the company purchases from a supplier at a cost of $2.00 each. Shadee wants to have 29 closures on hand on May 1,18 closures on May 31 , and 23 closures on June 30 and variable manufacturing overhead is $2.00 per unit produced. Suppose that each visor takes 0.20 direct labor hours to produce and Shadee pays its workers $11 per hour. Required: 1. Determine Shadee's budgeted manufacturing cost per visor. (Note: Assume that fixed overhead per unit is \$4) 2. Compute the Shadee's budgeted cost of goods sold for May and June. Complete this question by entering your answers in the tabs below. Compute the Shadees budgeted cost of goods sold for May and June. (Round your intermediate calculations to 2 decimal places. Round your answers to 2 decimal places.) Cazenovia is in the midst of a bad recession, and its Congress has placed economic recovery at the top of its political agenda. Different expansionary and will not accept any proposal that increases the deficit by more than $5 million. After lengthy discussions, these are the final proposals: Plan A: Spend $5 million on highways Plan B: Reduce taxes by $5 million Assume the economy of Cazenovia is characterized by the following four equations in the short run: YC=C+1+G+NX=C 0 +C Y (YT)1NX=I 0 (a constant) =0 where C 0 =50 and C Y =0.8. Using the government expenditure multiplier from the simple model presented in the chapter, the plan Y spend $5 million on highways (GDP) by $ million. (click the following icon for help answering this question)2. Using the government taxation multiplier from the simple model presented in the chapter, the plan to reduce taxes by $5 million will increase Y (GDP) by $enter your response here million. (click the following icon for help answering thisquestion)3. The plan that appears to be the most effective in achievingCongress's goal is to ____________.A.spend $5 million on highways.B.reduce taxes by $5 million.C.both are equally effective.D.neither achieves the goal of Congress. Question 13 0.1 pts In a two-slit experiment, monochromatic coherent light of wavelength 600 nm passes through a pair of slits separated by 2.20 105 m. At what angle away from the centerline does the second dark fringe occur? 4.70 O 2.34 O 3.94 3.51 O 1.17 0.1 pts Question 14 A two-slit arrangement with 60.3 um separation between the slits is illuminated with 537.0-nm wavelength light. If a viewing screen is located 2.14 m from the slits find the distance on the screen from the first dark fringe on one side of the central maximum to the second dark fringe on the other Since his spouse passed away three years ago, Bill has been the sole provider for his fifteen year old son, Chad. Bill earns a very modest income. He wants his son to have enough money to get through university and become independent by age of twenty five. What type of life insurance policy would be the best solution for Bill's situation? Select one: a, A 10 year term life insurance policy on Bill's life. b. A 10 year term joint first to die life insurance policy. c. A permanent life insurance policy on Bill's life. d. A 10 year term life insurance policy on Chad's life. True or False: Horizontal communication flows within and between work units. True False True or False: The grapevine is the unofficial communication system of the informal organization, a network of in-person and online gossip and rumor. True False True or False: Controlling is monitoring performance, comparing it with goals, and taking corrective action as needed. True False True or False: The classical viewpoint applied the scientific study of work methods to improving the productivity of groups of workers. True False An electric dipole is located at the origin consists of two equal and opposite charges located at m and m. The electric field at m has a magnitude of 1 N/C. What is the approximate magnitude of the electric field at m 1.00 N/C 0.13 N/C 0.50 N/C 0.25 N/C None of the above What is the medium for propagation of sound What treatments have been shown to help to improve a patientsoptimism? The scenario is designed to help you determine and evaluate thepayment amount of a car loan and a mortgage, based on theassumption that your household income is $36,000 per year or $3,000per month. Night Shades, Incorporated, manufactures biotech sunglasses. The variable materials cost is $12.14 per unit, and the variable labor cost is $6.89 per unit. O points a. What is the variable cost per unit? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) b. Suppose the company incurs fixed costs of $845,000 during a year in which total production is 210,000 units. What are the total costs for the year? (Do not round intermediate calculations.) c. If the selling price is $49.99 per unit, does the company break even on a cash basis? If depreciation is $450,000 per year, what is the accounting break-even point? (Do not round intermediate calculations and round your answers to 2 decimal places, e.g., 32.16.) Skipped Print a. Variable cost b. Total cost c. Cash break-even point c. Accounting break-even point units units Choose the pair of terms that corrrrctly completes their sentence :Nucleotides are to.... as.... are to proteinsA nucliec acid and aminoacidB amino acid polypeptidesC glycosidic linkage polypeptide linkagesD polymers polypeptides A company has a fiscal year-end of December 31: (1) on October 1, $19,000 was paid for a one-year fire insurance policy; (2) on June 30 the company advanced its chief financial officer $17,000; principal and interest at 7% on the note are due in one year; and (3) equipment costing $67,000 was purchased at the beginning of the year for cash. Depreciation on the equipment is $13,400 per year. Prepare the necessary adjusting entries at December 31 for each of the above items. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field.)