How much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km?

Answers

Answer 1

1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

What is Speed ?

Speed is the distance travelled per time taken. It is a scalar quantity. And the S.I unit is meter per second. That is, m/s

In the given question, we want to find how much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 10^5 km.

What are the parameters to consider ?

The parameters are;

The distance S = 3.85 × [tex]10^{5}[/tex] kmThe Speed of Light C = 3 × [tex]10^{8}[/tex] m/sThe time taken t = ?

Speed = distance S ÷ Time t

Convert kilometer to meter by multiplying it by 1000

C = S/t

3 × [tex]10^{8}[/tex] =  3.85 × [tex]10^{8}[/tex] / t

Make t the subject of formula

t = 3.85 × [tex]10^{8}[/tex] / 3 × [tex]10^{8}[/tex]

t = 1.2833

t = 1.3 s

Therefore, 1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

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Related Questions

A block and tackle pulley system has 3pulley wheels in the lower movable block. Determine the load that can be lifted by an effort of 350N if the efficiency of the system is 80%​

Answers

A block and tackle pulley design has a velocity ratio 3. <br> Draw a labelled diagram of this system. In your diagram, indicate absolutely the points of application and the directions of the load and effort

How to calculate  the load that can be lifted by an effort of 350N if the efficiency of the system is 80%​?

VR =3

VR = n=3

Efficiency of the system = 80%

Thus , Mechanical asvantage [tex]$=V R \times \eta=$[/tex]80/100×3 =2.4

Man can lift load with effort =350N

Thus,

Load= MA× effort = 2.4×350 = 840 N.

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A fisherman and his young son are in a boat on a small pond. Both are wearing life jackets. The son is holding a large helium filled balloon by a string, holding a significant part of his weight. Consider each action below independently and indicate whether the level of the water in the pond, Rises, Falls, is Unchanged or Cannot tell.
The son pops the helium balloon.
The fisherman knocks the tackle box overboard and it sinks to the bottom.
The son finds a cup and bails some water out of the bottom of the boat
The fisherman lowers himself in the water and floats on his back.
The fisherman lowers the anchor and it hangs one foot above the bottom of the pond. (the anchor is initially inside the boat)
The son gets in the water, looses his grip on the string, letting the balloon escape upwards.

Answers

(a) The son pops the helium balloon (unchanged)

(b) The fisherman knocks the tackle box overboard and it sinks to the bottom (rises)

(c) The son finds a cup and bails some water out of the bottom of the boat (falls)

(d) The fisherman lowers himself in the water and floats on his back (unchanged)

(e) The fisherman lowers the anchor and it hangs one foot above the bottom of the pond (rises)

(f) The son gets in the water, looses his grip on the string, letting the balloon escape upwards (rises).

Displaced volume of water in the pond

According to Archimedes principle, when a body is partially or completely immersed in a fluid, it experiences an upthrust which is equal to weight of to fluid displaced.

F = ρVg

V = F/ρg

where;

V is volume of water displacedρ is density of the immersed objectg is acceleration due to gravity

When an object with a significant weight is dropped into the pond, the level of water in the pond will rise and vice versa.

The son pops the helium balloon

The water level in the pond will be Unchanged, since the weight of the balloon is almost insignificant.

Fisherman knocks the tackle box overboard and it sinks to the bottom

The water level will rise because the weight of the tackle box is significant.

Son finds a cup and bails some water out of the bottom of the boat

The water level will fall since some volume of water is being removed.

Fisherman lowers himself in the water and floats on his back

The water level will be unchanged, since nothing new is added into the pond.

Fisherman lowers the anchor and it hangs one foot above the bottom of the pond

The water level will rise because the anchor will displace some volume of water upwards when it is dropped inside the pond.

Son gets in the water, looses his grip on the string, letting the balloon escape upwards.

The water level will rise, because the balloon will displace the water upwards when it escape upwards.

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Consider the f(x) = cos(x-C) function shown in the figure in blue color, where 0 ≤ C ≤ 2π. What is the value of parameter C for the function in the figure?
As a reference the g(x) = cos(x) function is shown in red color, and green tick marks are drawn at integer multiples of π.

Answers

The value of parameter C for the function in the figure is 2.

What is amplitude of a wave?

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

f(x) = Acos(x - C)

where;

A is amplitude of the waveC is phase difference of the wave

What is angular frequency of a wave?

Angular frequency is  the angular displacement of any element of the wave per unit time.

From the blue colored graph; at y = 1, x = -2 cm

1 = cos(2 - C)

(2 - C) = cos^(1)

(2 - C) = 0

C = 2

Thus, the value of parameter C for the function in the figure is 2.

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what is elecric field line​

Answers

A vector field and a starting position inside the field define the locus as a "field line." We have electric field lines for the electric fields.

What do you mean by electric field line?

In general, an electric field line is a curve drawn with each point's tangent pointing in the direction of that point's net field. An arrow on the curve is obviously required to designate the direction of the electric field from the two potential directions provided by a tangent to the curve. A field line is a space curve or a three-dimensional curve.The vector gets shorter as you move away from the origin and always points radially outward because the electric field varies as the inverse of the square of the distance that points from the charge.The density of the lines indicates the size of the field. This indicates that the location with a high density of field lines has a stronger electric field due to the charged substance. The electric field is weaker in the area where the density of these lines is low.The electric field can be depicted by joining these vectors to form a line.The direction of an imaginary line called an electric field line at any place must match the direction of the field there.In general, a field line is a curve drawn so that each point's tangent points in the direction of the net field.

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