C. The heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
What is Specific heat capacity?
Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass.
Heat released when the aluminum is cooledThe heat released when the aluminum is cooled from 70°C to 50°C is calculated as follows;
Q = mcΔθ
where;
m is mass of the aluminum c is specific heat capacityΔθ is change in temperatureQ = (10)(0.9)(50 - 70)
Q = -180 J
Thus, the heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
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Difference between jaanto and panighatta..
Answer:
they're both completely different games
Explanation:
Answer: uh.. tricky
Explanation:
Calculate the molality of a 5.51 M ethanol (C2H5OH) solution whose density is 0.9349 g/mL
Molality of C2H5OH is 1.1.27m.
What is Molality?
Molality is no.of moles present in One Kg solution .
Molality is represented by m
m= no.of moles/ weigt of solution in kg
Given is Molarity= 51.30M
molar mass of C2H5OH is 46g / mol , Density =0.9349g/ ml
Density=m/V
V = 107 ml
Molarity= no of moles/ Volume
51.5×46×107= x × 1000
weight of C2H5OH = 27.7g
molality = 27.7/1000××46
m= 1.27m
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Compare how entropy changes for the following two systems
System A: Solid particles are dissolved in water
System B: Vapor from a gas is condensed
Remember the fact
Randomness follows the order
Gas>Liquid>Solid#System A
As solid particles are dissolved in water their randomness increases so entropy increases
#System B
Gas is converted to liquid so entropy decreases as randomness decreases
Help me asap please !
Answer:
15 is not a correct scientific measurement.
Explanation:
Is this helpful for You
A 34.4 L sample of oxygen gas at 229°C and 752 torr is cooled to 34°C at 668 torr. The volume of the sample is now
L.
Answer:
23.55 L
Explanation:
USe the following 'identity' of gs laws
P1 V 1 / T1 = P2 V2 / T2 ( T must be in Kelvin)
re arrange to
P1 V 1 T2 / (T1 P2) = V2 NOW SUB IN THE VALUES
752 * 34.2 * ( 34 + 273.15) / [( 229 + 273.15) * 668] = V2 = 23.55 L
In Boston elevation 20 feet, your mass is 75 kg. On top of Mt. Everestt (elevation 29,029 feet) you mass would be
Answer:
75 kg or 75,000 g
Explanation:
Mass is a measurement that describes the amount of matter within an object. This is a constant measurement that does not change regardless of the object's location.
As such, a person's mass would be the same at both elevations.
**Their weight, however, may change.
** 1 kg = 1,000 g
the weak ionization constant (Ka) for HNO2 is equal to:
Answer:
the answer is A
Explanation:
The weak ionization constant (Ka) for HNO₂ is:
[tex]\displaystyle K_a = \frac{[H^+][NO_2^-]}{HNO_2}[/tex]
What is the ionization constant?Acid-ionization constant Ka can be described as a quantitative measure of the strength of an acid in solution. It can be represented as the equilibrium constant for a chemical reaction:
[tex]{\displaystyle {\ce {HA \longrightarrow A^- + H^+}}}[/tex]
The chemical species HA can dissociate into A⁻ the conjugate base of the acid and a hydrogen ion, H⁺. In equilibrium, when the concentrations will not change over time, because both forward and backward reactions have the same rate.
The ionization constant can be described as the ratio of products and reactants raised to stoichiometric powers.
The dissociation constant is defined as:
[tex]{\displaystyle K_{\text{a}}=\mathrm {\frac {[A^{-}][H^{+}]}{[HA]}} }[/tex]
Given the dissociation of the HNO₂ as follows:
HNO₂ ⇄ H⁺ + NO₂⁻
The weak ionization constant (Ka) for HNO₂ is equal to:
[tex]\displaystyle K_a = \frac{[H^+][NO_2^-]}{[HNO_2]}[/tex]
Therefore, option A is correct.
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Determine the concentration of a solution (M) made by dissolving 18.8 g of sodium chloride (NaCl) in 750.0 mL of solution.
Answer:
0.429 M
Explanation:
To find the molarity, you need to (1) convert grams to moles (using the molar mass), then (2) convert mL to L, and then (3) calculate the molarity (using the molarity ratio).
(Step 1)
Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol
Molar Mass (NaCl): 58.443 g/mol
18.8 grams NaCl 1 mole
-------------------------- x ------------------------ = 0.322 moles NaCl
58.443 grams
(Step 2)
1,000 mL = L
750.0 mL 1 L
------------------ x ----------------- = 0.7500 L
1,000 mL
(Step 3)
Molarity (M) = moles / volume (L)
Molarity = 0.332 moles / 0.7500 L
Molarity = 0.429 M
Given the following reaction: 2 NO(g) + O2(g) <--> 2 NO2(g), what is the equilibrium constant (K), if the concentrations at equilibrium are [NO] = 0.0542 M, [O2] = 0.127 M, and [NO2] = 15.5 M?
Group of answer choices
A. K = 2.35 x 102
B. K = 2.54 x 10-1
C. K = 6.44 x 105
D. K = 3.4 x 103
The equilibrium constant of a reaction, [tex]K_{c}[/tex] = 6.44 * 10⁵; option C.
What is equilibrium constant of a reaction?Equilibrium constant, [tex]K_{c}[/tex] of a reaction is a measure of the ratio of the equilibrium concentration of the products of a reaction, to the equilibrium concentration of the reactants; with each concentration raised to the exponent corresponding to the coefficient in the balanced equation of the reaction.
[tex]K_{c} = \frac{(products)^{a}}{(reactants)^{b}}[/tex]
The balanced equation of the given reaction is as follows:
2 NO (g) + O₂ (g) ⇄ 2 NO₂ (g)The concentrations at equilibrium of the species are as follows:
[NO] = 0.0542 M,
[O₂] = 0.127 M, and
[NO₂] = 15.5 M
Equilibrium constant, [tex]K_{c}[/tex] = (15.5)²/(0.127) * (0.0542)²
[tex]K_{c}[/tex] = 6.44 * 10⁵
In conclusion, the equilibrium constant of a reaction, tells on in which direction, the reaction is favored at equilibrium.
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on 1: A piece of unknown metal weighs 348 g. When the metal piece absorbs 6.64 kJ of heat, its temperature increases from 22.4 °C to 43.6 °C.
Answer:
.900 J / g-C°
Explanation:
I assume you are looking for the specific heat of the metal
Specific heat = J / g-C
= 6640 J / 348 g[ (43.6 - 22.4) ] = .900 J / g-C
The specific heat of the unknown metal is approximately [tex]\rm \( 0.90 \, \text{kJ/kg\°C} \)[/tex].
To find the specific heat of the unknown metal, we can use the formula:
[tex]\rm \[ q = m \cdot c \cdot \Delta T \][/tex]
where:
[tex]\rm \( q \)[/tex] = heat absorbed by the metal (in kJ)
[tex]\rm \( m \)[/tex] = mass of the metal (in g)
[tex]\rm \( c \)[/tex] = specific heat of the metal (in kJ/kg·°C)
[tex]\rm \( \Delta T \)[/tex] = change in temperature (in °C)
Given data:
[tex]\( m = 348 \, \text{g} \)\\\( \Delta T = 43.6°C \\\\- 22.4°C = 21.2°C \)\\\( q = 6.64 \, \text{kJ} \)[/tex]
Now, let's rearrange the formula to solve for [tex]\rm \( c \)[/tex]:
[tex]\rm \[ c = \frac{q}{m \cdot \Delta T} \][/tex]
Substitute the values:
[tex]\rm \[ c = \frac{6.64 \, \text{kJ}}{348 \, \text{g} \times 21.2°C} \][/tex]
Convert the mass to kg and temperature to °C:
[tex]\rm \[ c = \frac{6.64 \, \text{kJ}}{0.348 \, \text{kg} \times 21.2\°C} \]\\\\\ c \approx 0.90 \, \text{kJ/kg\°C} \][/tex]
The specific heat of the unknown metal is approximately [tex]\rm \( 0.90 \, \text{kJ/kg\°C} \)[/tex].
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Your question is incomplete, but most probably your full question was,
A piece of unknown metal weighs 348 g. When the metal piece absorbs 6.64 kJ of heat its temperature increases from 22.4°C to 43.6°C. Determine the specific heat of this metal. What is your unknown metal?
Which of these have the highest volume
A. - 1kg of lead
B. - 1kg of iron
C. - 1kg of gold
D. - 1kg of aluminum
Answer:
D. 1kg Aluminium
Explanation:
First of all, you have to know that you were given two quantities, volume and mass.
The relationship between both quantities is given by the formula of density which is:
Density = Mass / Volume
Volume = Mass / Density
Since mass is constant, it means that the volume is inversely proportional to the density.
Volume = k / Density where k is a constant.
This means that the substance with the lowest density would have the highest volume and the one with the highest density would have the highest lowest.
The density of the substances are given as:
Lead = 11.2
Iron = 7.874
Gold = 19.3
Aluminium = 2.7
This means that Aluminium would have the highest volume as its the least dense.
How many molecules of H₂S are required to form 79.0 g of sulfur according to the following reaction? Assume excess SO2.
2 H₂S(g) + SO2(g) → 3 S(s) + 2H₂O(1)
Answer:
9.89 x 10²³ molecules H₂S
Explanation:
To find the molecules of H₂S, you need to (1) convert grams S to moles S (via the atomic mass of sulfur), then (2) convert moles S to moles H₂S (via the mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂S to molecules H₂S (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Atomic Mass (S): 32.065 g/mol
2 H₂S(s) + SO₂(g) -----> 3 S(s) + 2 H₂O(l)
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
79.0 g S 1 mole 2 moles H₂S 6.022 x 10²³ molecules
--------------- x --------------- x ---------------------- x ------------------------------------- =
32.065 g 3 moles S 1 mole
= 9.89 x 10²³ molecules H₂S
Magnesium metal burns with a bright white light . At the end of the reaction , white magnesium oxide powder is produced . Suggest why magnesium is often found in fireworks . Your answer should include a word equation .
The element magnesium is often in fireworks because it burns with bright white light. It adds white sparks and hence, improves the overall brilliance of a firework.
Properties of Magnesium Magnesium metal and its alloys are explosive in nature. They are highly flammable in pure form, powder form, or ribbon formMagnesium reacts violently with waterWhen magnesium metal is burned it reacts with the oxygen present in the air. Magnesium and oxygen react with each other to form magnesium oxide which is a white powder. Magnesium gives its 2 electrons to the oxygen to form this powdered product.The reaction is as follows:
[tex]2Mg (s) + O_2 (g) \rightarrow 2MgO(s) + energy[/tex]
The reaction is exothermic in nature.
It can also reduce water to H₂ gas[tex]Mg(s)+ 2H_2O \rightarrow Mg(OH)_2(s) + H_2 (g)[/tex]
Magnesium reacts with carbon dioxide to form carbon[tex]Mg(s)+CO_2 \rightarrow 2MgO(s)+ C(s)[/tex]
As magnesium is highly flammable and burns with white bright light, hence it is used in fireworks to improve its overall experience.
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What would the hydroxide ion concentration be if the hydrogen ion concentration was 1 x 10-3 M?
Answer:
1 x 10⁻¹¹ M
Explanation:
(Step 1)
Determine the pH.
pH = -log[H⁺]
pH = -log[1 x 10⁻³ M]
pH = 3
(Step 2)
Determine the pOH.
pH + pOH = 14
3 + pOH = 14
pOH = 11
(Step 3)
Determine the hydroxide (OH⁻) concentration.
[OH⁻] = 10^-pOH
[OH⁻] = 10⁻¹¹
[OH⁻] = 1 x 10⁻¹¹ M
What is the component concentration ratio, [CH3COO−]/[CH3COOH], of a buffer that has a pH of 4.650? (Ka of CH3COOH = 1.8 × 10−5)
Answer:
Refer to the attached page,
I've done the calculation over there
what does it mean Emphasis on object vs woman
Emphasis on object vs woman simply means s- e- x- ual objectification
This goes to say that it emphasizes seeing women as objects of se- xu- al pleasure
What is objectification?Objectification simply refers to the act of treating or viewing a person as an object, devoid of thought or feeling.
Most of the time, objectification is targeted at women and reduces them to objects of se- xu- al pleasure
So therefore, emphasis on object vs woman simply means se- xu- al objectification
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Using the periodic table, choose the more reactive non-metal.
S or As
Answer:
Sulfur
Explanation:
In general, elements are more reactive the more electronegative they are. The most electronegative elements are at the top-right of the periodic table. Since sulfur (S) is one unit up and one unit to the right of arsenic (As), it is considered more electronegative, and therefore more reactive, than arsenic.
How many moles of NaOH are in a 356 mL solution that has a concentration of 7.2 M?
Answer:
2.56 moles
Explanation:
7.2 M is 7.2 moles/L
356 mL = .356 Liters
x moles / .356 Liters = 7.2 M (moles/L)
x = .356 * 7.2 = 2.5632 moles
Which would be the best way to represent the concentration of a 1.75 M K2CrO4 solution?
O 1.75% K2CrO4
O [K2CRO4]
(K2CrO4)
K2CRO4, [M] = 1.75
The best way to represent the concentration of a 1.75 M K2CrO4 solution is 1.75% K2CrO4 (option A).
What is molarity?Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.
The molarity is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.
The molarity is measured in mol/L or M, hence, it can be said that the molarity of a solution is 0.1M.
However, the concentration of a solution is best represented by using %. In accordance with this question, the best way to represent the concentration of a 1.75 M K2CrO4 solution is 1.75% K2CrO4.
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[Ir(NH3)₂CI(CO)] draw cis and trans isomers
The IUPAC name of this compound is diamminecarbonylchloroIridium ..
What are Isomers?Isomers are structure of compund in different forms but they have same molecular mass .
The cis and trans form are given in the picture
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2Al(s)+Fe2O3(s) → Al2O(s)+2Fe(s) with a delta H=-847 KJ.
Railroad maintenance initiates a thermite reaction of 4.0 mol Al to connect two lengths of rail using the reaction above. How much heat is released during the reaction?
∆H for given reaction -847kJ
As it's negative reaction is exothermicSo
2 mol of Al releases 847KJ heat
4 mol Al releases
2(847)1694KJ∆H=-1694KJ
It is given that the energy released during the reaction of 2 moles of Al metal is - 847 KJ. The n the heat energy released by 4 moles of Al will be - 1694 KJ.
What is reaction enthalpy?The enthalpy change of a reaction is the heat energy absorbed or released by a reaction. For an endothermic reaction, the heat energy is absorbed and the enthalpy change is positive. For an exothermic reaction, where the energy is released, the enthalpy change will be negative.
The heat energy change during a reaction is equal to the product of mass, specific heat and temperature difference of the substanc eunder reaction or phase transition.
Given that, the heat evolved by 2 moles of Al is - 847 kJ. Then, the heat evolved when 4 moles of Al reacted is calculated as follows:
(4 × - 847) / 2 = - 1694 KJ.
Therefore, the heat energy released is - 1694 KJ.
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Prform the following operation and express the answer in scientific notation 6.0 x 10^3-2.310^3
The value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.
What is scientific notation?Scientific notation is a way to write very large or very small numbers so that they are easier to read and work with.
You express a number as the product of a number greater than or equal to 1 but less than 10 and an integral power of 10 .
Why it is used?There are two reasons to use scientific notation.
The first is to reveal honest uncertainty in experimental measurements. The second is to express very large or very small numbers so they are easier to read.Given,
= 6.0 x 10^3- 2.3 × 10^3
= (6.0 - 2.3) × 10^3
= 3.7 × 10^3
Thus, we find that the value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.
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write three disadvantages of hard water.
The three disadvantages of hard water are:
1. Hard water is unsuitable for washing because soap does not readily create a lather in it.
2. Soap may react and produce, wasting the soap.
3. Due to the development of calcium and magnesium carbonates, tea kettles will get furred.
Hard waterWater that contains a lot of minerals is referred to as hard water. In limestone, chalk, or gypsum deposits, which are mostly composed of calcium and magnesium carbonates, bicarbonates, and sulphates, hard water is created as a result of percolation. A moderate health advantage from drinking hard water is possible. In industrial settings where water hardness is regulated to prevent expensive breakdowns in boilers, cooling towers, and other water-handling equipment, it can present serious issues. Hard water is frequently detected in home settings by the build-up of lime scale in kettles and water heaters as well as by the absence of foam when soap is agitated in water. Wherever there is a worry about water hardness, water softening is frequently employed to lessen the negative impacts of hard water.
write three disadvantages of hard water.
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Question 2 of 10
What button on a scientific calculator is used to enter a number in scientific
notation?
Answer:
It's the button with the x, and a blank box above it.
Explanation:
Check the attachments, you'll see what it looks like. It will probably look different on your calculator, but the icon should be the same or similar.
The average energy consumption for a new Samsung refrigerator is 5.47 × 10 2 kWh/ye ar. What is the average energy consumption of this refrigerator in gigajoules per day? (Given 1 GJ = 277.8 kWh ) show work.
Answer:
Explanation:
'nsofikldng[ousgafi'fjsngds[sbuofdia
What is the isotopic symbols for
Beryllium atom that contains 9 nucleon?
Answer:
Beryllium-9 is the isotope of beryllium with relative atomic mass 9.
A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 35°C is 42.2 torr, what is the volume of the gas sample at standard pressure?
Answer:
The volume of the gas sample at standard pressure is 819.5ml
Explanation:
Solution Given:
let volume be V and temperature be T and pressure be P.
[tex] V_1=250ml[/tex]
[tex] V_2=?[/tex]
[tex] P_{total}=735 mmhg[/tex]
1 torr= 1 mmhg
42.2 torr=42.2 mmhg
so,
[tex] P_{water}=42.2mmhg[/tex]
[tex] T_1=35°C=35+273=308 K[/tex]
Now
firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.
[tex] P_{gas}=P_{total}-P_{water} [/tex]
=735-42.2=692.8 mmhg
Now
By using combined gas law equation:
[tex]\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}[/tex]
[tex]V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1[/tex]
[tex]V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1[/tex]
Here [tex]P_2 \:and\: T_2[/tex] are standard pressure and temperature respectively.
we have
[tex]P_2=750mmhg \:and\: T_2=273K[/tex]
Substituting value, we get
[tex]V_2=\frac{692.8}{750}*\frac{273}{308} *250[/tex]
[tex]V_2= 819.51 ml[/tex]
Which of the following best describes the interaction between water molecules?
Group of answer choices
A. Hydrogen Bonding
B. London Dispersion Forces
C. Dipole-Dipole Forces
D. Van der Waals Forces
Answer:
hydrogen bonding
Explanation:
I just think it is I am not sure
Answer: C. Dipole-dipole interactions.
1. Consider the unbalanced equation:
Al4C3 (s) + H2O (l) ---> Al(OH)3 (s) + CH4 (g)
How many moles of H2O are needed to react with 1.48 moles of Al4C3 ?
Hint: Write the balanced equation first
2.
Consider the balanced equation:
2 CH4 (g) + 3 O2 (g) + 2 NH3 ---> 2 HCN (g) + 6 H2O (g)
If 203.6 g of NH3 is reacted with excess CH4 and O2, what mass in grams of HCN is produced?
Answer:
1.) 17.76 moles H₂O
2.) 323.1 g HCN
Explanation:
1.) An equation is balanced when there is an equal amount of each element on both sides of the reaction. The quantities can be modified by adding coefficients in front of the molecules.
The unbalanced equation:
Al₄C₃(s) + H₂O -----> Al(OH)₃(s) + CH₄(g)
Reactants: 4 aluminum, 3 carbon, 2 hydrogen, 1 oxygen
Products: 1 aluminum, 1 carbon, 7 hydrogen, 3 oxygen
The balanced equation:
Al₄C₃(s) + 12 H₂O -----> 4 Al(OH)₃(s) + 3 CH₄(g)
Reactants: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen
Products: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen
Now that the equation is balanced, you can use the relevant coefficients to construct a mole-to-mole ratio. This will allow you to convert between moles Al₄C₃ to moles H₂O.
1.48 moles Al₄C₃ 12 moles H₂O
---------------------------- x ------------------------ = 17.76 moles H₂O
1 mole Al₄C₃
2.) To find the mass of HCN, you need to (1) convert grams NH₃ to moles NH₃ (via molar mass), then (2) convert moles NH₃ to moles HCN (via mole-to-mole from equation coefficients), and then (3) convert moles HCN to grams HCN (via molar mass). It is important to arrange the coefficients in a way that allows for the cancellation of units.
Molar Mass (NH₃): 14.009 g/mol + 3(1.008 g/mol)
Molar Mass (NH₃): 17.033 g/mol
Molar Mass (HCN): 1.008 g/mol + 12.011 g/mol + 14.009 g/mol
Molar Mass (HCN): 27.028 g/mol
2 CH₄(g) + 3 O₂(g) + 2 NH₃(g) ------> 2 HCN(g) + 6 H₂O(g)
203.6 g NH₃ 1 mole 2 moles HCN 27.028 g
--------------------- x ---------------- x ------------------------ x ----------------- =
17.033 g 2 moles NH₃ 1 mole
= 323.1 g HCN
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
C2H4(g) + H2O(g) ------> CH3CH2OH(g)
The enthalpy change of the reaction is -44.79 kJ/mol.
What is the enthalpy change?We can define the enthalpy change as the energy that is given out or taken in in a reaction. it can be calculated from the enthalpies of formation of species by the use of the relation;
ΔH = ∑Enthalpy of formation of products - ∑Enthalpy of formation of reactants
ΔHfC2H4(g) = +52kJ/mol
ΔHf H2O(g) = - 241.82 kJ/mol
ΔHf CH3CH2OH(g)= -234.61 kJ/mol
ΔHrxn = (-234.61) - [52 + (- 241.82 )]
ΔHrxn = (-234.61) - (-189.82)
ΔHrxn = -44.79 kJ/mol
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