How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane
with movements of only one unit right or one unit up? How many ways are there to do so that do not go above the line y = x?

Answers

Answer 1

The number of ways there are to move from (0, 0) to (7, 7) in the coordinate plane with movements of only one unit right or one unit up accordingly is; 49 while that such that y =x is; 7.

How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane with pmovements of only one unit right or one unit up?

It follows from the task content that the movement intended on the coordinate plane is; from (0, 0) to (7, 7).

The number of ways to move such that movements of only one unit right or one unit up is; 7 × 7 = 49.

The number of ways for which y= x is therefore is; 7 as the movement is diagonal.

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Related Questions

can someone help me with this?

Answers

Answer:

Step-by-step explanation:

Beatrice's conclusion is wrong

All of these points are not on the same line, because are different parallel lines

The slope between (-2,-1) and (1,0) is equal to 1/2

Answer:

Beatrice is incorrect. All of these points are not on the same line because the slope between (-2,-1) and (1,0) which are coordinates fr each of the pairs above, are equal to 1/2

Step-by-step explanation:

Let m1 be first slope

[tex]m1 \: = \frac{y2 - y1}{x2 - x1}= \frac{0 - ( - 2)}{4 - ( - 2)}= \frac{0 + 2}{4 + 2} \\ = \frac{2}{4} = \frac{1}{2} [/tex]

Let m2 be second slope

m2 = (y2 - y1)/ (x2 - x1)

= (2-(-1)) / (4-(-2)

= (2+1) / (4+2)

= 3/6 =1/2

Thus, the slopes are different parallel lines because m1 =m2

A locker combination consists of two non-zero digits. the digits in a combination are not repeated and range from 2 through 9. event a = the first digit is less than 5 event b = the second digit is less than 5 if a combination is picked at random, with each possible locker combination being equally likely, what is p(b|a) expressed in simplest form?

Answers

Answer:

1/3.

Step-by-step explanation:

P(event a occurs) = 3/9 = 1/3

P(event b occurs) = 3/9 = 1/3

P(a) ∩ P(b) = 1/3 * 1/3 = 1/9

P(b|a) = P(a) ∩ P(b) / P(a)

          =  1/9 / 1/3

          =  1/3.

Solve the equation the square root of the quantity x plus 4 minus 3 equals 1 for the variable.

Answers

Answer:

x = 12

Step-by-step explanation:

sqrt(x+4) - 3 = 1

First get the sqrt all by itself on one side of the equation. Add 3 to both sides of the equation.

sqrt(x+4) = 1 + 3

sqrt(x+4) = 4

To "fix" the sqrt, that is, "undo it" and get rid of it, you have to SQUARE both sides of the equation.

(sqrt(x+4))^2 = 4^2

x + 4 = 16

subtract 4 to finish up.

x = 12

Check:

sqrt(12 + 4) - 3 = 1

sqrt16 - 3 = 1

4 - 3 = 1

1 = 1 Check!

Solve for d.

5+d > 5−d

Answers

Answer:

d>0

Step by Step Explanation:

Let's solve your inequality step-by-step.

5+d>5−d

Step 1: Simplify both sides of the inequality.

d+5>−d+5

Step 2: Add d to both sides.

d+5+d>−d+5+d

2d+5>5

Step 3: Subtract 5 from both sides.

2d+5−5>5−5

2d>0

Step 4: Divide both sides by 2.

2d/2>0/2

d>0

Answer:

3

Step-by-step explanation:

You could put 3 because 5+3 is greater than 5-3.

Find the solution for the system of linear equations by substitution: 2x - y = 3 y − x = 1

Answers

The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5

What are linear equations?

Linear equations are equations that have constant average rates of change, slope or gradient

How to determine the solution to the system?

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2x- y = 3

y - x = 1

Make y the subject in the second equation, by adding x to both sides of the equation

y - x + x = x + 1

This gives

y = x + 1

Substitute y = x + 1 in 2x- y = 3

2x- x - 1 = 3

Evaluate the like terms

x = 4

Substitute x = 4 in y = x + 1

y = 4 + 1

Evaluate

y = 5

Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5

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Write the equation of straight line passing through (3,4). Does the point (4,3) lie on

your line​

Answers

Answer:

Is there more information?  There is not enough to find the slope of a line.  I'll answer with an equation that works, but I suspect it won't be correct.

Step-by-step explanation:

If the only requirement is to have a line that goes through (4,3).  Then one could simply say:

y = 4

This is a horizonal line that goes through (3,4), and will always produce a y value of 4 regardless of x.  No, it will not pass through (4,3) since y is aleways 4, regardless of x.

If you wanted to get fancier, we could write a needlessly more complex equation:

y = (4/3)x

When x = 3, y = 4, so (3,4) is on this line.  But (4,3) is not.  y = (4/3)(4) means y = (16/3), not 4.

Find the distance in nm between two slits that produces the first minimum for 405-nm violet light at an angle of 57. 5°

Answers

The distance between two slits is d =2.89*10^-7 m

Distance between slits,   d=2.89*10^-7 m

It is given that,

Wavelength, λ = 410nm= 410*10^-9 m

Angle, θ =45

We need to find the distance between two slits that produces first minimum. The equation for the destructive interference is given by :

dsinθ =(n+1/2) λ

For first minimum, n = 0

dsinθ =(1/2) λ

So, d is the distance between slits

d ={1/2 λ}sinθ

=2.89*10^-7 m

So, the distance between two slits is d =2.89*10^-7 m. Hence, this is the required solution.

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Consider the expressions shown below.
A. -8x^2 - 3x + 4
B. 8x^2 - 3x + 8
C. 8x^2 + 3x - 4

Complete each of the following statements with the letter that represents the expression.
(3x^2 - 7x + 14) + (5x^2 + 4x - 6) is equivalent to expression
(2x^2 - 5x - 3) + (-10x^2 + 2x + 7) is equivalent to expression
(12x^2 - 2x - 13) + (-4x^2 + 5x +9) is equivalent to expression

Answers

===> Exercise 1

(3x² - 7x + 14) + (5x² + 4x - 6)

Match 3x² and 5x² to get 8x².

8x² - 7x + 14 + 4x - 6

Combine −7x and 4x to get −3x.

8x² −3x + 14 − 6

Subtract 6 from 14 to get 8.

8x² - 3x + 8

Therefore, the expression (3x² - 7x + 14) + (5x² + 4x - 6), is equivalent to the expression "B".

===> Exercise 2

(2x² - 5x -3) + (-10x² + 2x + 7)

Combine 2x² and -10x² to get −8x².

−8x² −5x − 3 + 2x + 7

Combine −5x and 2x to get −3x.

-8x² − 3x − 3 + 7

Add −3 and 7 to get 4.

-8x² - 3x + 4

Therefore, the expression (2x² - 5x -3) + (-10x² + 2x + 7), is equivalent to the expression "A".

===> Exercise 3

(12x² - 2x - 13) + (-4x² + 5x +9)

Combine 12x² and -4x² to get 8x².

8x² − 2x −13 + 5x + 9

Combine −2x and 5x to get 3x.

8x² + 3x − 13 + 9

Add −13 and 9 to get −4.

8x² + 3x - 4

Therefore, the expression (12x² - 2x - 13) + (-4x² + 5x +9), is equivalent to the expression "C".

The following table represents a relation. X Y -3 0 0-2 5 -3 11-2 Does the table represent y as a function of c? Why or why not? No, because a number in the input is the same as a number in the output. Yes, because there are no x-values with more than one y-value. Yes, because every x-value has at least one y-value. No, because there are two inputs that have the same output.​

Answers

The table represent y as a function of c, Yes because every x-value has at least one y-value.

According to the question,

X       -3          0          5            11

Y        0           2          -3          -2

In order to find the table represent y as a function of c, When x = -3; y=0; x= 0 ;y=2; x= 0 y=2; x= 5 y=-3; x= 11 y=-2.

No, because a number in the input is the same as a number in the output.

⇒ Above option is wrong, because a number in the input is not same as a number in the output.

Yes, because there are no x-values with more than one y-value.

⇒ Above option is wrong, because there are many x-values with more than one y-value.

Yes, because every x-value has at least one y-value.

⇒ Above option is correct, because every x-value has at least one y-value.

No, because there are two inputs that have the same output.

⇒ Above option is wrong,  because there are not two inputs that have the same output

Hence, the table represent y as a function of c, Yes, because every x-value has at least one y-value. Above option is correct, because every x-value has at least one y-value.

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HELPPPP!!!!! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each given function with the description of its graph.

Answers

Answer:

y = 2(1/2)^x --> Second choice

y = (1/4)^x --> First choice

y = 3^x --> Third choice

Step-by-step explanation:

Take a look at the images uploaded for the reasons why.

y = 2(1/2)ˣ is y intercept (0,2) second choice, y = (1/4)ˣ is y intercept (0,1) first choice, y = 3ˣ is y intercept (0,1), fourth choice.

Let's break down each of the given exponential functions and understand their y-intercepts:

y = 2(1/2)ˣ :

When x = 0, the value of (1/2)ˣ  is 1, since any number raised to the power of 0 is 1. Therefore, y = 2 * 1 = 2 when x = 0. This gives us the y-intercept (0, 2).

y = (1/4)ˣ :

Similarly, when x = 0, the value of (1/4)ˣ  is 1, since any number raised to the power of 0 is 1. Therefore, y = 1 when x = 0. This gives us the y-intercept (0, 1).

y = 3ˣ :

Again, when x = 0, the value of 3ˣ  is 1. Therefore, y = 1 when x = 0. This gives us the y-intercept (0, 1).

The y-intercept is the point where the graph of the function intersects the y-axis, which occurs when x is zero. In all three cases, when x = 0, the exponent becomes zero, resulting in the base being raised to the power of zero, which is always equal to 1. The graph is given below.

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please give the right answer and i will mark you brainlyist

Answers

Considering the given box plots, we have that:

Class A has the higher IQR.Class A has the highest test score.Class B has the higher median.Class B has the smaller range.

What is a box plot?

It is a plot that focuses the interquartile range of the population, which is the difference between the third and the first quartile, but gives a five number summary of the population, composed by these following measures.

The smallest value.The first quartile.The median.The third quartile.The highest value.

Hence, for class A, we have that:

The smallest value is 62.The first quartile is 65.The median is of 70.The third quartile is 79.The highest value is of 86.

Then:

The IQR is of 79 - 65 = 14.The range is of 86 - 62 = 24.

Hence, for class B, we have that:

The smallest value is 68.The first quartile is 70.The median is of 74.The third quartile is 77.The highest value is of 79.

Then:

The IQR is of 77 - 70 = 7.The range is of 79 - 68 = 11.

Hence the correct options are given as follows:

Class A has the higher IQR.Class A has the highest test score.Class B has the higher median.Class B has the smaller range.

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There are different types of correlation one can use based on the types of variables being examined. When conducting an analysis, when do you need to use spearman’s rho instead of pearson’s r ?.

Answers

The correct option is A.

When the data are nominal or ordinal.

What are the Types of  correlation?

There are three types of correlation:

1. Positive and negative correlation

2. Linear and non-linear correlation

3. Simple, multiple, and partial correlation

According to the information:

There are different types of correlation one can use based on the types of variables being examined.

Spearman’s rho is a superb choice when you have nominal or ordinal data because Pearson’s isn't appropriate. Ordinal data have a minimum of three categories and the categories have a natural order. for instance , first, second, and third during a race are ordinal data.

Briefing:

Two variables can have some quite relationship, i.e., change in one may cause a change within the other.

If a change within the value of one variable causes a simultaneous change in the other variable in the same or opposite direction, then it’s termed as correlation, or these variables are said to be correlated. Keeping these in mind the answer to this question is When the data are nominal or ordinal

When the data are nominal or ordinal.

So the option no A is correct.

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I understand that the question you are looking for is:

There are different types of correlation one can use based on the types of variables being examined. When conducting an analysis, when do you need to use spearman’s rho instead of Pearson's r ?

A. When the data are nominal or ordinal.

B. When the data are ratio or interval.

C. When the data are random.

D. Spearman's rho should never be used for correlations.

Brass is an alloy made by melting and mixing copper and zinc. A metallurgist has two brass
alloys, one that is 65% copper and one that is 90% copper. He would like to combine a
portion of each alloy to produce 500 g of a new alloy that is 75% copper.

Write a system of equations for this problem

Answers

Answer:

x +y = 5000.65x +0.95y = 0.75(500)solution: (x, y) = (300, 200)

Step-by-step explanation:

A system of equations for the problem can be written using the two given relationships between quantities of brass alloys.

Setup

Let x and y represent the quantities in grams of the 65% and 90% alloys used, respectively. There are two relations given in the problem statement.

  x + y = 500 . . . . . . quantity of new alloy needed

  0.65x +0.90y = 0.75(500) . . . . . quantity of copper in the new alloy

These are the desired system of equations.

Solution

This problem does not ask for the solution, but it is easily found using substitution for x.

  x = 500 -y

  0.65(500 -y) +0.90y = 0.75(500)

  (0.90 -0.65)y = 500(0.75 -0.65) . . . . . . subtract 0.65(500)

  y = 500(0.10/0.25) = 200

  x = 500 -200 = 300

300 grams of 65% copper and 200 grams of 90% copper are needed.

Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4? f(n 1) = f(n) 99.4, n ≥ 1 f(n 1) = f(n) – 99.4, n ≥ 1 f(n 1) = 99.4f(n), n ≥ 1 f(n 1) = –99.4f(n), n ≥ 1

Answers

The recursive formula for the given sequence is [tex]f(n+1)=f(n)-99.4[/tex]

What is recursive formula?

Any term of a series can be defined by its preceding term in a recursive formula (s). For instance: An arithmetic series has the recursive formula [tex]a_n = a_{n-1} + d[/tex]. [tex]a_n = a_{n-1}r[/tex] is the recursive formula for a geometric sequence.

We are given a sequence as:

99.4,0,-99.4,-198.8, and so on

We can see that the sequence is constantly getting decreased by -99.4

i.e. f(1)=99.4

Then, f(2)=f(1)-99.4

               =99.4-99.4

               =0

f(3)=f(2)-99.4

   =0-99.4

   =-99.4

Therefore, the recursive formula of the given series is [tex]f(n+1)=f(n)-99.4[/tex]

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[tex]\frac{12}{20} =_____% = _____ hundredths

Answers

The percentage form of given fraction is 60% and the hundredths form is 0.60

According to the statement

we have given that the a fraction and we have to find the percentage of that fraction and write in the form hundredths.

So, For this purpose,

The given fraction is 12/20.

Then the definition of the percentage is that

The Percentage, a relative value indicating hundredth parts of any quantity.

so, the percentage of given fraction is :

Percentage fraction = 12/20 * 100

After solving it, The percentage fraction will become:

Percentage fraction = 60%

and Now convert into the hundredths form then

In the hundredths form it will become

from 60% to 0.60.

So, The percentage form of given fraction is 60% and the hundredths form is 0.60

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9 The cost of a mobile phone call is 30 cents plus 20 cents per minute.
a Find the possible cost of a call if it is:
i shorter than 5 minutes ii longer than 10 minutes
b For how many minutes can the phone be used if the cost per call is:
i less than $2.10 ii greater than or equal to $3.50

Answers

Using a linear function, we have that:

a) The costs are:

i. C(x) < $1.3.

ii. C(x) > $2.3.

b) The times are:

i. Less than 9 minutes.

ii. At least 16 minutes.

What is a linear function?

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, the y-intercept is of 0.3, while the slope is of 0.2, hence the cost for a call of x minutes is:

C(x) = 0.3 + 0.2x.

For calls shorter than 5 minutes, the costs are:

C(x) < 0.3 + 0.2 x 5

C(x) < $1.3.

For calls longer than 10 minutes, the costs are:

C(x) > 0.3 + 0.2 x 10

C(x) > $2.3.

The cost is less than $2.10 for calls of less than x minutes, found as follows:

0.3 + 0.2x < 2.1

0.2x < 1.8

x < 9.

The cost is greater or equal to $3.50 for calls of at least x minutes, found as follows:

0.3 + 0.2x >= 3.5

0.2x >= 3.2

x >= 16.

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QUICK!!!HELP!!!!!!!!!!!!!!!!!!

Answers

Using the normal distribution, the probability that a worker selected at random makes between $500 and $550 is: 2.15%.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean mu and standard deviation sigma is given by:

Z = (X - mu)/sigma

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given as follows:

mu = 400, sigma = 50

The probability is the p-value of Z when X = 550 subtracted by the p-value of Z when X = 500, hence:

X = 550:

Z = (X - mu)/sigma

Z = (550 - 400)/50

Z = 3

Z = 3 has a p-value of 0.9987.

X = 500:

Z = (X - mu)/sigma

Z = (500 - 400)/50

Z = 2

Z = 2 has a p-value of 0.9772.

0.9987 - 0.9772 = 0.0215 = 2.15% probability.

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Which of these expressions demonstrates the identity property? 25(0) = 25 25(1) = 25 25 + 0 = 25 25 + 1 = 25

Answers

The expressions which demonstrates the identity property of multiplication is; 25(1) = 25 option B

Identity Property

Identity Property of Multiplication states that any number multiplied by 1 does not change, that is, it is constant or remains the same

Check all options

25(0) = 25

0 = 25

Not true

25(1) = 25

25 = 25

True (identity property of multiplication holds)

25 + 0 = 25

25 = 25

True (Not identity property of multiplication)

25 + 1 = 25

26 = 25

Not true

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Identify the 7th term of the geometric sequence in which a2 = 324 and a4 = 36.

Answers

Answer:

a7=4/3 or a7=-4/3

Step-by-step explanation:

using the geometric sequences formula

an=ar^n-1

a2=ar

a4=ar³

when a2=324 and a4=36

324=ar...........(1)

36=ar³............(2)

from equation (1) a=324/r substitute in equation (2)

we have :

36=324/r *r³

36=324r²

r²=36/324

r²=1/9

r=±1/3

substitute when r=±1/3 in (1)

324=a(±1/3)

a=±972

so the 7th term is

when r=±1/3

we have

a7=ar^6

a7=±972(±1/3)^6

a7=972/729

a7=4/3 or a7=-4/3

John, Jim and Joe each went for a medical examination. Their combined height was 5.25 m. If John was 12 cm shorter than Jim and Jim was 0.09 m taller than Joe, how tall, in metres, was Joe?

Answers

The 5.25 m combined height of John, Jim, and Joe, the 12 cm height difference between John and Jim and the 0.09 m difference in height between Jim and Joe, indicates that solution to the word problem is Joe was 1.73  meters tall

What is a word problem?

A word problem is a presentation of a math problem using verbal description rather than numbers, variables and operators.

The combined height of John, Jim and Joe = 5.25 m

John's height = Jim's height - 12 cm = Jim's height - 0.12

Jim's height = Joe's height + 0.09 m

Let h represent Joe's height, we get;

Jim's height = h + 0.09

John's height = h + 0.09 - 0.12 = h - 0.03

John's height = h - 0.03

The sum of the heights is therefore; h + h + 0.09 + h - 0.03 = 3·h + 0.06

The sum of their heights = Their combined height = 5.25 meters

Therefore; 3·h + 0.06 = 5.25

h = (5.25 - 0.06)/3 = 1.73

Joe's height, h = 1.73 meters

Jim's height = 1.73 + 0.09 = 1.82

Jim's height = 1.82 meters

John's height = 1.73 - 0.03 = 1.7

John's height is 1.7 meters

Joe was 1,73 meters tall

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Using the digits below form the smallest number which is a multiple of 3
9,4,5​

Answers

This would be the least common multiple of 3, 4, 5, and 9. We can start by listing the multiples of the biggest number, 9, and seeing if each of the numbers can be divisible by the smaller numbers.

9: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, 117, 126, 135, 144, 153, 162, 171, 180

180 would be the answer because it is the first number in our list that is divisible by 3, 4, 5, and 9.

What number is the height changing by each minute?

Answers

The height is changing by 0.5 units per minute as evident in the given table.

By what number is the height changing?

It follows from the task content that the table given indicates that at, 0min, the height was 150.

While at 1 min, the height is 150.5. On this note, it follows that the height increases by 0.5 units for after every minute.

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In triangle r s t, angle r = 63 degrees, angle t = 90 degrees, side r s = 23 and side s t = 10.4. which ratios are correct?

Answers

The correct ratios are: cos 27=23/RT, sec 27= 23/10.4 and cot 63 = RT/10.4

What is trigonometry  ratio in tringle?

Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle. The basic trigonometric ratios are sin, cos, and tan, namely sine, cosine, and tangent ratios.

In triangle RST, angle T= 90° and angle R= 63°

As the total of all angle in any triangle is 180°, so the measure of the angle S = 180°- (90°+63°)

S= 180°- 153°

S= 27°

According to the rule of trigonometric ratios,

cos(θ) = [tex]\frac{hypotenuse}{opposite}[/tex]

sec(θ) = [tex]\frac{hypotenuse}{adjacent}[/tex]

cot(θ) = [tex]\frac{adjacent}{opposite}[/tex]

In respect of angle R (63°), side RS(23) is hypotenuse , ST(10.4) is opposite and RT is adjacent.

cos(63°) = [tex]\frac{23}{10.4}[/tex]

sec(63°) = [tex]\frac{23}{RT}[/tex]

cot(63°) = [tex]\frac{RT}{10.4}[/tex]

Now, in respect of angle S(27°), hypotenuse is RS(23), adjacent is ST(10.4) and opposite is RT.

So, cos(27°) = [tex]\frac{23}{RT}[/tex]

sec(27°) = [tex]\frac{23}{10.4}[/tex]

cot(27°) = [tex]\frac{10.4}{RT}[/tex]

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math help pleasee!!!!

Answers

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

Since this is an algebraic problem

  ⇒let's solve it like one

     [tex]2*3^{x+5} < 14\\3^{x+5} < 7\\ x+5 < log_37\\x < -5 + log_37\\x < -3.2288[/tex]

Answer: x < -3.2288

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pllllllllllllllllllllleasee one guys i neeed ur help one

Answers

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Let's solve ~

Calculate discriminant :

[tex]\qquad \sf  \dashrightarrow \: 3 {x}^{2} + 6x - 1[/tex]

a = 3b = 6c = 1

[tex]\qquad \sf  \dashrightarrow \: discriminant = {b}^{2} - 4ac[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = (6) {}^{2} - (4 \times 3 \times 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 36 - 12[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 24[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt {d} = 2 \sqrt{6} [/tex]

Now, let's calculate it's roots ( x - intercepts )

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - b \pm \sqrt{d} }{2a} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{2 \times 3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{6} [/tex]

So, the intercepts are :

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6 - 2 \sqrt{6} }{6} [/tex]

and

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6 + 2 \sqrt{6} }{6} [/tex]

Answer:

[tex]\left( \dfrac{ -3 + 2\sqrt{3}}{ 3}, \ 0\right), \ \left(\dfrac{ -3 - 2\sqrt{3}}{ 3}, \ 0\right)[/tex]

Explanation:

Given expression:

f(x) = 3x² + 6x - 1

To find x intercepts, set f(x) = 0

Use quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ where \ ax^2 + bx + c = 0[/tex]

Here after finding coefficients:

a = 3, b = 6, c = -1

Applying formula:

[tex]x = \dfrac{ -6 \pm \sqrt{6^2 - 4(3)(-1)}}{2(3)}[/tex]

[tex]x = \dfrac{ -6 \pm \sqrt{48}}{6}[/tex]

[tex]x = \dfrac{ -6 \pm 4\sqrt{3}}{6}[/tex]

[tex]x = \dfrac{ -6 \pm 4\sqrt{3}}{2 \cdot 3}[/tex]

[tex]x = \dfrac{ -3 \pm 2\sqrt{3}}{ 3}[/tex]

[tex]x = \dfrac{ -3 + 2\sqrt{3}}{ 3}, \ \dfrac{ -3 - 2\sqrt{3}}{ 3}[/tex]

A square of sides 6cm has been removed from regular pentagon of sides 12cm. Calculate the perimeter of the shape

Answers

The perimeter of the shape is 52 cm

How to determine the perimeter of the shape?

The shape is given as:

Regular pentagon

The length of the sides are

Length = 12 cm

So, the perimeter of the regular pentagon is

P = 5* Length

This gives

P = 5 * 12cm

Evaluate

P = 60 cm

When the square of sides 6cm is removed from the regular pentagon, the perimeter becomes

P = 60cm - 6cm

Evaluate the difference

P =52 cm

Hence, the perimeter of the shape is 52 cm

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Geometry: Use this illustration to calculate these values, ASAP!!!

Answers

Applying the same-side interior angles theorem,

7. m∠4 = 50°; m∠5 = 130°

8. m∠2 = 15°; m∠8 = 15°.

What is the Same-Side Interior Angles Theorem?

The same-side interior angles theorem holds that, two interior angles on a side of a transversal are supplementary, that is they add up to 180 degrees.

What is the Alternate Exterior Angles Theorem?

According to the alternate exterior angles theorem, exterior angles that alternate each other along a transversal are congruent, that is they have equal measures.

7. m∠4 + m∠5 = 180 [same-side interior angles theorem]

Substitute

y + 2y + 30 = 180

3y + 30 = 180

3y = 180 - 30

3y = 150

y = 50

m∠4 = y = 50°

m∠5 = 2y + 30 = 2(50) + 30

m∠5 = 130°

8. m∠2 = m∠8 [alternate exterior angles theorem]

Substitute

x - 30 = 3x - 120

x - 3x = 30 - 120

-2x = -90

x = 45

m∠2 = x - 30 = 45 - 30 = 15°

m∠8 = 3x - 120 = 3(45) - 120 = 15°

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Oscar corporation is planning to construct an elliptical gate at its headquarters. the width of the ellipse will be 5 feet across and its maximum height along the center will be 3 feet. the company wants to place two bright spots at the foci of the ellipse. how far from the center of the ellipse will the spots be located?

Answers

The distance from the center of the ellipse to where the spots are located will be 2 feet.

What is Distance?

Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.

The distance from the center of the ellipse to where the spots are located will be -

= 5 - 3

= 2 feet.

Therefore, the distance from the center of the ellipse is 2 feet.

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Which of the following scatter plots does not have a zero correlation?

Answers

The first scatter plot does not have a zero correlation.

Option(a) is correct.

A statistic called correlation gauges how much two variables change in connection to one another.

Correlation quantifies correlation but cannot determine whether x causes y or vice versa, or whether a third component is responsible for the association.

A scatterplot may make it easier to spot correlation, particularly when the variables have a non-linear but nevertheless significant association.

Zero means there is no correlation between the two variables under comparison.

A 0 correlation indicates that there is no relationship between the two variables according to the correlation statistic. This merely indicates that there isn't a linear relationship, not that there isn't any link at all. The first scatter plot does not represent a linear relationship, thus, it has zero correlation.

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How does the mean absolute deviation (mad) of the data in set 1 compare to the mean absolute deviation of the data in set 2? set 1: 12, 8, 10, 50 set 2: 13, 9, 8 the mad of set 1 is 13 less than the mad of set 2. the mad of set 1 is 13 more than the mad of set 2. the mad of set 1 is 2 more than the mad of set 2. the mad of set 1 is 2 less than the mad of set 2.

Answers

The Mean Absolute Deviation of Set 1 exists 13 more than the mean absolute deviation of Set 2.

How to estimate the Mean Absolute Deviation from the given data?

Set 1: 12, 8, 10, 50

Set 2: 13, 9,8

To determine the mean for each set

Mean = totality of elements/number of elements

Mean of Set 1:

[tex]$=\frac{12+8+10+50}{4}[/tex]

[tex]$=\frac{80}{4}=20$[/tex]

Mean of Set 2:

[tex]$=\frac{13+9+8}{3}[/tex]

[tex]$=\frac{30}{3}=10$[/tex]

To determine the mean absolute deviation (MAD) of the data in each set.

M.A.D of Set 1:

[tex]$=\frac{|12-20|+|8-20|+|10-20|+|50-20|}{4}[/tex]

[tex]$=\frac{8+12+10+30}{4}=\frac{60}{4}=15$$[/tex]

M.A.D of Set 2:

[tex]$=\frac{|13-10|+|9-10|+|8-10|}{3}[/tex]

[tex]$=\frac{3+1+2}{3}=\frac{6}{3}=2$[/tex]

The Mean Absolute Deviation of Set 1 exists 13 more than the mean absolute deviation of Set 2.

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