Have my equation written out but struggling to solve. Can someone help me solve!

Answer:

an open fracture contains some sort of water which if it comes in contact with electrons could result to a shock

The value of parameter B (angular frequency) for this function is 2.7.

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

f(x) = Acos(Bx)

where;

Angular frequency is  the angular displacement of any element of the wave per unit time.

From the blue color; at y = -0.9, x = -7.5 cm

-0.9 = cos(-7.5B)

7.5B = arc cos (0.9)

7.5B = 2.7

B = 7.5/2.7

B = 2.7

Thus, the value of parameter B (angular frequency) for this function is 2.7.

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The time it takes for the ball to hit the ground from the platform is determined as 1.56 seconds.

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 12 / 9.8)

t = 1.56 seconds

Thus, the time it takes for the ball to hit the ground from the platform is determined as 1.56 seconds.

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Answer:

No because a pot plant system must interact with its surroundings (air, water, etc) and these are not closed systems.

Only if the pot plant were completely enclosed, say in a large glass jar would the system be closed.

Answer:

B. 2.5 Ω

Explanation:

[tex]\frac{1}{5} +\frac{1}{5}=0.4[/tex]

Put a one on top of the 0.4

[tex]\frac{1}{0.4} =2.5[/tex]

Answer:

X component= 46 N

Y component= 80 N

Magnitude =( 46 ^2 + 80^2 )^0.5 = 92.3 N

Answer:

Astrobiologists have put in tremendous efforts till now in the search for extra-terrestrial life. They are searching not only for tremendously developed life forms like humans, but also for microbes that are found to inhabit even the harshest of environments on Earth. Due to the tremendous development in technology, the odds of finding life beyond Earth are increasing day by day. Nasa's Kepler mission was launched to hunt for Earth like planets beyond our Solar System, and till now this mission has established the presence of 2,337 exoplanets, along with 1,284 new planets. This hugely increases the chances of finding another Earth like planet outside the limits of our Solar system. NASA's Astrobiology researchers are presently studying the most severe environments on Earth for improved understanding of the kind of conditions that would be able to support life in every part of the universe. Moreover, programs for instance SETI are keeping an eye on the galaxy for electromagnetic communications occurring or situated between stars from the societies on new worlds.

There is still a tremendous possibility to find life in our solar system. By the discovery of life forms in the extreme environments here on Earth, scientists have realized that the presence of solar energy is not an absolute necessity for the subsistence of life. Energy from chemical reactions can also trigger the organic elements to interact and start the formation of life. In the Solar system, Jupiter's moons Io and Europa and Saturn's moons Enceladus and Titan have been realized to the very strong candidates for the presence of microscopic life forms.

Explanation:

I hold a very optimistic view on the presence of life beyond Earth. It is highly probable that life on Earth is not an exceptional case but it should be a general one in the Universe. While we are always excited to imagine that we might encounter species as much developed or more highly developed than us, there is very good chance that the Universe is teeming with microscopic life forms. Also, to discover another intelligent life form would also be highly welcome.

The period of the oscillations.T = 1.2042s

Opposition is the process of any quantity or measure fluctuating repeatedly about its equilibrium value throughout time. This process is referred to as oscillation. Oscillation, a periodic fluctuation of a substance, can also be described as alternating between two values or rotating around a central value.

Typically, the mathematical formula for the moment of inertia is

T = 2 π √(I / mgd)

Therefore, a moment of inertia

I = 9.00×10-3 + md^2 ;

I=9.00*10^{-3}+ 0.5 * 0.3^2

I=0.054

T=2[tex]\pi \sqrt{0.5*9.8*0.3}[/tex]

T=1.2042s

The period of the oscillations.T = 1.2042s

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Answer: 1.348 meters

Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point  c . Adding the four moments together, we get:

(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0

6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0

11.5c=15.50

c=  1.348 metres

The center of mass is on the y axis at  y  = 1.348 metres.

The oxygen–hemoglobin dissociation curve depicts the relationship between the partial pressure of oxygen (pao2) and the arterial oxygen.

The oxygen-hemoglobin dissociation curve (OHDC) indicates the relationship between the oxygen saturation of hemoglobin and the partial pressure of arterial oxygen. This curve can change its position or shifted to another level depending on various factors.

So we can conclude that the oxygen–hemoglobin dissociation curve depicts the relationship between the partial pressure of oxygen (pao2) and the arterial oxygen.

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B. As the resistance increases, the slope on the current vs voltage graph gets flatter.

Resistance is the opposition to the follow of current in electrical material.

The mathematical relationship between resistance, current and voltage is given by Ohm's law.

R = V/I

where;

From the equation above, increase in resistance means an increase in voltage or decrease in current.

In Current vs voltage graph, the following will occur;

Thus, as the resistance increases, the slope on the current vs voltage graph gets flatter.

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Hi there!

Drum #2 will have a greater center of mass speed and reach the bottom of the hill first.

The moment of inertia can be thought of as inertia for rotation.

If mass is concentrated at the rim, the drum has a GREATER moment of inertia compared to if the mass is more concentrated towards the center.

Using the Rotational Equivalent of Newton's Second Law:
[tex]\Sigma \tau = I\alpha[/tex]

**Sum of torques = Moment of inertia * angular acceleration

From this equation, we know that if 'I' increases, 'α' decreases, and thus, the speed of the object's center of mass decreases and it will reach the bottom later.

Therefore, drum #2 with the smaller moment of inertia (mass concentrated at the center) will have a greater angular acceleration ⇒ greater center of mass speed ⇒ read the bottom first.

Answer:

an instrument measuring atmospheric pressure, used especially in forecasting the weather and determining altitude.

Explanation:

hope it helps ya

The resultant force of the three professional wrestlers on the championship belt is 98.35 N.

The component of the forces in x -direction is calculated as follows;

Fx = 40 N  +  60(cos 36.9)

Fx = 40 N + 47.98 N

Fx = 87.98 N

The component of the forces in y -direction is calculated as follows;

Fy = -80 N + 60(sin 36.9)

Fy = -43.95 N

R = √Fx² + Fy²

R = √( 87.98²  + 43.95²)

R = 98.35 N

Thus, the resultant force of the three professional wrestlers on the championship belt is 98.35 N.

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Answer:

v

f=90km/h=25m/s

v_{_{i}}=0v

i=0

t=10\;\mathrm{s}t=10s

m=1000\;\mathrm{kg}m=1000kg

The acceleration of the car is 2.5 m/s². The net force acting on the car is 2500 Newtons (N). The correct answers are  2.5 m/s², 2500 Newtons (N).

Given:

Mass of the car (m) = 1000 kg

Acceleration (a) = 2.5 m/s²

a) The acceleration of the car is:

Acceleration (a) = Change in velocity / Time taken

Final velocity (v(f)) = 90 × 0.27778  = 25 m/s

Acceleration (a) = (Final velocity - Initial velocity) / Time taken

Acceleration (a) = (25 - 0 ) / 10

Acceleration (a) = 2.5 m/s²

Therefore, The acceleration of the car is 2.5 m/s².

b) Newton's second law of motion:

F = m × a

F = 1000 × 2.5

F = 2500 N

The net force acting on the car is 2500 Newtons (N).

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The minimum necessary height of the IV bag above the position of the needle is 0.37 m.

The minimum necessary height of the IV bag above the position of the needle is calculated as follows;

P = ρgh

where;

Substitute the given parameters and solve for minimum height

h = P/ρg

h = (4759.609) / (9.8 x 1308)

h = 0.37 m

Thus, the minimum necessary height of the IV bag above the position of the needle is 0.37 m.

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Answer:[tex]\sqrt{65} m/s[/tex]

Explanation:

The maximum rate at which energy can be added to the circuit element mathematically given as

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

Generally, the equation for P is  mathematically given as

[tex]P=\ln s \frac{\Delta T}{\Delta t}[/tex]

Therefore

[tex]Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}[/tex]

[tex]\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}[/tex]

[tex]\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}[/tex]

Max temp Change

[tex]MaxT=5.6^{\circ} \mathrm{C}[/tex]

[tex]\text { time }=3 \times 60[/tex]

t=180s

In conclusion, Max Energy Rate

[tex]MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}[/tex]

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

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Answer:

Explanation:

yes

Answer:

Warm weather may be found in the tropical zone since the sun's heat is concentrated in regions close to the equator. At 23.5 degrees north of the equator and 23.5 degrees south of the equator, this area is nearly in the middle of the world. It has a monthly average temperature of 18 degrees Celsius or higher.

Explanation:

Answer:

[tex]V = 900\; {\rm V}[/tex] for a resistor where [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex].

Explanation:

By Ohm's Law, if the electric resistance of a resistor is [tex]R[/tex] and the current going through that resistor is [tex]I[/tex], the voltage across that resistor would be [tex]V = I\, R[/tex].

Note that electric resistance is typically measured in Ohms, where [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex].

Given that [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex] for the resistor in this question, apply the formula [tex]V = I\, R[/tex] to find the voltage [tex]V[/tex] across this resistor:

[tex]\begin{aligned} V &= I\, R \\ &= 30\; {\rm A} \times 30\; {\rm \Omega} \\ &= 30\; {\rm A} \times 30\; {\rm V \cdot A^{-1}} \\ &= 900\; {\rm V} \end{aligned}[/tex].

Answer:

23.562

Explanation:

First it is good to work out the circumference:

2 pi r

2 pi .75

circumference = 4.7124

Next we need half of this because it is half a resolution. This will be our distance travelled.

half = 2.3562

word done = force x distance

work done = 10 x 2.3562

work done = 23.562

(I didn't see the need for mass...)

The average density of the material from which the coin is made is 9.67 g/cm³.

The volume of the coin at the given diameter is calculated as follows;

V = Ah

where;

V = πd²/4 x h

V = π(2.8)²/4  x (0.21 cm)

V = 1.293 cm³

The average density of the material from which the coin is made is calculated as follows;

density = mass/volume

density = 12.5 g / (1.293 cm³)

density = 9.67 g/cm³

Thus, the average density of the material from which the coin is made is 9.67 g/cm³.

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Answer:

water at 4°c that's abnormal stage of water

(1) If the ship moves upward with a constant velocity, the period increases, false.

(2) If the length of the pendulum is doubled, the new period will be: square root of 2 times T₀. true.

(3) If the ship accelerates upward, the period increases, true.

(4) If the ship accelerates downward at 9.81 m/s² , the pendulum will no longer oscillate, false.

(5) If the mass of the pendulum is halved, the period decreases, false.

The period of a simple pendulum is given as;

T = 2π√(L/g)    ------- (1)

where;

When the ship moves upward with a constant velocity, the period will not change.

T ∝√L

when, L = 2L₀

T = T₀√2

Thus, if the length of the pendulum is doubled, the new period will be: square root of 2 times T₀.

t = √2h/g

T = √I/mgd

where;

when the mass is halved, the period increases.

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Answer:

because he's fast and speedy

Explanation:

Explanation:

Distance traveled by motorist =(15.0m/s)t

Distance traveled by policeman =1/2(2.00m/s2)t2

(a) Intercept occurs when 15.0t =t2or t=15.0s.

(b) x(officer)=1/2(2.00m/s2)t2= 225m