Given 8 different toppings to choose from, how many 3-topping pizzas are possible?

Answers

Answer 1

Answer:

336 ways

Step-by-step explanation:

Use nPk which is [tex]\frac{n!}{(n-k)!}[/tex]. This is [tex]\frac{8!}{5!}[/tex]. This becomes 8×7×6 as the 8! and 5! cancel out. 8×7×6 is 336.

Answer 2

Total number of possible 3-topping pizzas are 336 ways.

How do you calculate the number of possible ways something can be arranged?

In more general terms, if we have n items total and want to pick k in a certain order, we get: n! / (n – k)! And this is the permutation formula: The number of ways k items can be ordered from n items: P(n,k) = n (n – k)!

Given that,

Total number of items n = 8

number of picking item k = 3

Now,

p(n,k) = [tex]\frac{n!}{(n -k)!}[/tex]

p(8,5) =  [tex]\frac{8!}{(8 -3)!}[/tex]

         = [tex]\frac{8!}{5!}[/tex]

         = [tex]\frac{8.7.6.5! }{5! }[/tex]

         = 8 × 7 ×6

p(8,5) = 336 ways

Hence, Total number of possible 3-topping pizzas are 336 ways.

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Related Questions

Lori was paid a 15 percent commission for the home audio system that she sold. The electronics store had marked up the price of the system by 60 percent over the wholesale price of $264. How much did Lori earn for the sale of the home audio system? $15.84 $23.76 $39.60 $63.36

Answers

Answer:

$63.36

Step-by-step explanation:

The home audio system costs $264 wholesale.

The system's price had been increased by 60 percent at the electronics retailer.

Consequently, the increased cost is 60/100x264=$158.40.

The audio system's total cost is now $422.40 (264 + 158.40).

Given that Lori received a commission of = 15% on $422.40, her commission is now (15/100) x 422.40

= $63.36

Determine and state the coordinates of the center and the length of the radius of the
circle whose equation is x2 + y2 + 6x = 6y + 63

Answers

we can see that the center is (-3, 3) and the radius is 9 units.

How to find the center and radius of the circle?

The general circle equation, for a circle with a center (a, b) and radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Here we have the equation:

x^2 + y^2 + 6x = 6y + 63

Let's complete squares:

x^2 + y^2 + 6x - 6y =  63

(x^2 + 6x) + (y^2 - 6y) = 63

(x^2 + 2*3x) + (y^2 - 2*3y) = 63

Now we can add and subtract 9, (two times) so we get:

(x^2 + 2*3x + 9) - 9 + (x^2 - 2*3x + 9) - 9 = 63

(x + 3)^2 + (y - 3)^2 = 63 + 9 + 9 = 81 = 9^2

(x + 3)^2 + (y - 3)^2 = 9^2

Comparing with the general circle equation, we can see that the center is (-3, 3) and the radius is 9 units.

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What is the solution to 3/2b + 5 < 17? Explain How.
(1) b < 8

(2) b > 8

(3) b < 18

(3) b > 18

Answers

3/2b + 5 < 17

We subtract 5 from both sides of the inequality.

3/2b + 5 - 5 < 17 - 53/2 b < 12

Multiply both sides by 2/3.

( 2/3) * (3/2b) < (2/3) * 12b < 8

Therefore, the correct option is alternative "A".

We would think that it is option B, but the only difference is that it changes the direction of the sign.

Answer:  [A]: " b < 8 " .
_____

Step-by-step explanation:

Given:
Find the solution to:   " 3/2b + 5 < 17 " ; and choose from the answer choices.

So; we have:  

 (3/2)b + 5 < 17  ;

 Now, subtract "5" from each side of this inequality:
 (3/2)b + 5 − 5  <  17 − 5  ;

   To get:
  (3/2)b  <  12 ;

Now, let's multiply Each Side of this inequality by "2" ;

 to get rid of the fraction:

    "  2*(3/2)b  <   12*2 "  ;

{Note: " [tex]2 *\frac{3}{2}=\frac{2}{1}*\frac{3}{2}[/tex] " } ;

Note:  To simplify:  " [tex]\frac{2}{1} * \frac{3}{2}[/tex] " ;
   Note the "2" in the denominator in the "first term" ;  

   And:  The "2" in the denominator in the "second term" ;

      Both "cancel out" to "1" ;  since:  "[ 2 / 2 = 2÷2 = 1 ]" ;

   And:  we have:  " [tex]\frac{1}{1}*\frac{3}{1}= 1 *3 = 3[/tex] " };

_____
and rewrite:
   " 3b < 24 "  ;

Now, divide Each side of the inequality by "3" ;

 to isolate "b" on one side of the inequality;

and to solve for "x" ;
_____
 " 3b/3 < 24/3 " ;

 to get:

_____

   " b < 8 " ; which corresponds to the correct answer:

Answer choice:  [A]:  " b < 8 " .
_____

Hope this is helpful to you! Best wishes!
_____

The diagonal is a of a rectangular field is 169m. If the ratio of the length to the width is 12:5 find the dimensions

Answers

Based on the calculations, the dimensions of the rectangle are

Length, L = 156 meters.Width, w = 65 meters.

What is a diagonal?

The diagonal of a rectangle can be defined as a line segment that connects any two (2) of its non-adjacent vertices together while dividing the rectangle into two (2) equal parts.

Mathematically, the length of diagonals of a rectangle can be calculated by using this formula:

d = √(l² + w²)

Where:

d is the diagonal of a rectangle.l is the length of a rectangle.w is the width of a rectangle.

Since the ratio of the length to the width is 12:5, we have:

Width, w = 5l/12

Substituting the given parameters into the formula, we have;

169 = √(l² + (5l/12)²)

169² = l² + (5l/12)²

169² = l² + (25l²/144)

Length, L = 156 meters.

For the width, we have:

Width, w = 5l/12

Width, w = 5(156)/12

Width, w = 65 meters.

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Make a list of 4 different numbers whose average works up to 50

Answers

Answer is numbers 10, 30, 70, 90

The 4 numbers must be different and added up and divided by 4 must equal 50.

Four such numbers are 10, 30, 70, 90

We all know that Average = Sum / total of numbers in sum

Addition of these different 4 numbers = 200.
Average = 200 / 4 = 50, the required average.
Problem solved!

11/6 + -2/5 +-13/10?

Answers

Answer:

2/15

Step-by-step explanation:

11/6 + -2/5 +-13/10?

11/6 + (-2/5) + (-13/10)

43/30 - 13/10

2/15

What is the end behavior of the function f of x equals 3 times the cube root of x? as x → –[infinity], f(x) → –[infinity], and as x → [infinity], f(x) → [infinity]. as x → –[infinity], f(x) → [infinity], and as x → [infinity], f(x) → –[infinity]. as x → –[infinity], f(x) → 0, and as x → [infinity], f(x) → 0. as x → 0, f(x) → –[infinity], and as x → [infinity], f(x) → 0.

Answers

The function [tex]f(x)=4\sqrt[3]{x}[/tex] is a cube root function and the function end behavior is: [tex]x[/tex] → [tex]+[/tex] ∞, [tex]f(x)[/tex] → [tex]+[/tex] ∞, and as [tex]x[/tex] → - ∞, [tex]f(x)[/tex] → [tex]+[/tex] ∞

What is end behavior?The end behavior of a function f defines the behavior of the function's graph at the "ends" of the x-axis. In other words, the end behavior of a function explains the graph's trend when we look at the right end of the x-axis (as x approaches +) and the left end of the x-axis (as x approaches ).

To determine the end behavior:

The equation of the function is given as: [tex]f(x)=4\sqrt[3]{x}[/tex]To determine the end behavior, we plot the graph of the function f(x).We can see from the accompanying graph of the function:As x approaches infinity, so does the function f(x), and vice versa.As a result, the function end behavior is:  

[tex]x[/tex] → [tex]+[/tex] ∞, [tex]f(x)[/tex] → [tex]+[/tex] ∞, and as [tex]x[/tex] → - ∞, [tex]f(x)[/tex] → [tex]+[/tex] ∞

Therefore, the function [tex]f(x)=4\sqrt[3]{x}[/tex] is a cube root function and the function end behavior is: [tex]x[/tex] → [tex]+[/tex] ∞, [tex]f(x)[/tex] → [tex]+[/tex] ∞, and as [tex]x[/tex] → - ∞, [tex]f(x)[/tex] → [tex]+[/tex] ∞

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The complete question is given below:

What is the end behavior of the function f of x equals negative 4 times the cube root of x?

As x → –∞, f(x) → –∞, and as x → ∞, f(x) → ∞.

As x → –∞, f(x) → ∞, and as x → ∞, f(x) → –∞.

As x → –∞, f(x) → 0, and as x → ∞, f(x) → 0.

As x → 0, f(x) → –∞, and as x → ∞, f(x) → 0.

Answer:

As x → –∞, f(x) → –∞, and as x → ∞, f(x) → ∞.

Step-by-step explanation:

I got it right on the test.

The time allotted for the Math test for 2 3/4 hours. Emma completed the test 1/2 of an hour earlier. How long did it take Emma to complete the test?

Answers

2 3/4h=2.75h
1/2h=0.5h
2.75h-0.5h=2.25
2.25h=2 1/4h


Or


1/2h•2=2/4h
2 3/4h-2/4h=2 1/4h

It took Emma 2 1/4 hours to complete the test.

Russell has $38 and is saving $2 per day. cornelius has $64 and is spending $2 per day. after how many days will russell have more money than cornelius?

Answers

The equation be 38 + 2x - (64 - 2x) = 0 then the value of x = 6.5.

How to find the value of x?

To estimate the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.

Let the day be x

38 + 2x - (64 - 2x) = 0

Subtract 38 from both sides

38 + 2x - (64 - 2x) - 38 = 0 - 38

Simplifying the above equation, we get

2x - (64 - 2 x) = -38

Expanding the above equation, 2x - (64 - 2x) = 4x - 64

4x - 64 = -38

Add 64 to both sides

4x - 64 + 64 = -38 + 64

Simplify

4x = 26

Divide both sides by 4

[tex]$\frac{4 x}{4}=\frac{26}{4}[/tex]

Simplifying the equation

[tex]$x=\frac{13}{2}[/tex]

The value of x = 6.5.

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Find the terms through degree four of the maclaurin series for f(x) = sin(x) 1−x.

Answers

The terms through degree four of the Maclaurin series is [tex]f(x)=x+x^{2} +\frac{5x^{3} }{6} +\frac{5x^{4} }{6} +.....[/tex].

In this question,

The function is f(x) = [tex]\frac{sin(x)}{1-x}[/tex]

The general form of Maclaurin series is

[tex]\sum \limits^\infty_{k:0} \frac{f^{k}(0) }{k!}(x-0)^{k} = f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} +\frac{f'''(0)}{3!}x^{3}+......[/tex]

To find the Maclaurin series, let us split the terms as

[tex]f(x)=sin(x)(\frac{1}{1-x} )[/tex] ------- (1)

Now, consider f(x) =  sin(x)

Then, the derivatives of f(x) with respect to x, we get

f'(x) = cos(x), f'(0) = 1

f''(x) = -sin(x), f'(0) = 0

f'''(x) = -cos(x), f'(0) = -1

[tex]f^{iv}(x)[/tex] = cos(x), f'(0) = 0

Maclaurin series for sin(x) becomes,

[tex]f(x) = 0 +\frac{1}{1!}x +0+(-\frac{1}{3!} )x^{3} +....[/tex]

⇒ [tex]f(x)=x-\frac{x^{3} }{3!} +\frac{x^{5} }{5!}+.....[/tex]

Now, consider [tex]f(x) = (1-x)^{-1}[/tex]

Then, the derivatives of f(x) with respect to x, we get

[tex]f'(x) = (1-x)^{-2}, f'(0) = 1[/tex]

[tex]f''(x) = 2(1-x)^{-3}, f''(0) = 2[/tex]

[tex]f'''(x) = 6(1-x)^{-4}, f'''(0) = 6[/tex]

[tex]f^{iv} (x) = 24(1-x)^{-5}, f^{iv}(0) = 24[/tex]

Maclaurin series for (1-x)^-1 becomes,

[tex]f(x) = 1 +\frac{1}{1!}x +\frac{2}{2!}x^{2} +(\frac{6}{3!} )x^{3} +....[/tex]

⇒ [tex]f(x)=1+x+x^{2} +x^{3} +......[/tex]

Thus the Maclaurin series for [tex]f(x)=sin(x)(\frac{1}{1-x} )[/tex] is

⇒ [tex]f(x)=(x-\frac{x^{3} }{3!} +\frac{x^{5} }{5!}+..... )(1+x+x^{2} +x^{3} +......)[/tex]

⇒ [tex]f(x)=x+x^{2} +x^{3} - \frac{x^{3} }{6} +x^{4}-\frac{x^{4} }{6} +.....[/tex]

⇒ [tex]f(x)=x+x^{2} +\frac{5x^{3} }{6} +\frac{5x^{4} }{6} +.....[/tex]

Hence we can conclude that the terms through degree four of the Maclaurin series is [tex]f(x)=x+x^{2} +\frac{5x^{3} }{6} +\frac{5x^{4} }{6} +.....[/tex].

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Someone please explain.50 points available.Thankyou so much!

Answers

Answers:

a) 49 square tiles - did the work on paper.

b) 83 circular tiles - did the work on paper.

c) C: could be even or odd - all patterns had both even and odd amounts of square and circular tiles.

Step-by-step explanation:

I did all the work on paper it took a while to do it. pls mark brainliest

if you rolled two dice what is the probability that you would roll a 4 or a 5

Answers

Hello there! Given that normal dice are numbered 1-6, individually rolling a 4 or a 5 would give a 1/6 probability. That converts to about 17% as a percentage because we can multiply 1 by 100 to get 100/6, then divide 100 by 6 to get 16.6666. When rounding, that gives approximately 17%. However, if we combined probabilities, we would find that rolling a 4 or a 5 collectively gives a 2/6 probability, which is approximately 33% as a decimal.

In terms of individual probabilities, you would be 17% likely to roll one of them. In terms of collectiveness, the likelihood of rolling a 4 or 5 would render 33% on each die. If you need additional help, let me know and I will gladly assist you.

The marked price of a mobile set is Rs 9,600 and 40% discount is allowed to make 20% profit. By what percent is the discount to be reduced to increase the profit by 10%?​

Answers

Answer:

5%

Step-by-step explanation:

price after discount :

9 600 - 9 600×40%

= 5760

Original price (price without profit) :

let x be the original price of the device.

x + x × 20% = 5760

Then

x = (5 760×100)÷120

  = 4 800

Original price increased by 30% :

4 800 + 4 800×30%

= 6 240

the discount needed to increase the profit by 10% :

[(9 600-6 240)÷9 600]×100

= 35%

Then

to increase the profit by 10% ,we have to reduce

the percent of discount to :

40% - 35%

= 5%

For a pair of sample​ x- and​ y-values, the​ ______________ is the difference between the observed sample value of y and the​ y-value that is predicted by using the regression equation.

Answers

For a pair of sample x and y values, the residual exists as the distinction between the observed sample value of y and the y value that exists indicated by utilizing the regression equation.

What is the difference between the observed sample value of Y and the Y value that exists as predicted by utilizing the regression equation?

In regression analysis, the distinction between the observed value of the dependent variable and the predicted value exists named the residual.

A regression equation exists utilized in stats to estimate what relationship if any, exists between sets of data.

For a pair of sample x and y values, the residual exists as the distinction between the observed sample value of y and the y value that exists indicated by utilizing the regression equation.

Residual = observed y - predicted y.

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q=sqrt (c+d)/(c-d) solve for c

Answers

The equation for the variable 'c' is c = d(q² + 1)/(q² - 1). By using simple arithmetic operations on the original equation, the required equation can be obtained.

What is an equation?

An equation is a relationship between two expressions given by a mathematical statement.

There are different types of equations. They are linear equations, quadratic, polynomial, etc.

Solving for c in the given equation:

The given equation is

q = √((c + d)/(c - d))

Squaring on both, root gets canceled out

⇒ q² = (c + d)/(c - d)

⇒ q²(c - d) = (c + d)

⇒ cq² - dq² = c + d

Separating like terms  aside,

cq² - c = d + dq²

⇒ c(q² - 1) = d(q² + 1)

⇒ c = d(q² + 1)/(q² - 1)

Therefore, the required equation is c = d(q² + 1)/(q² - 1).

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Which function has a vertex at the origin?
f(x) = (x + 4)²2
f(x) = x(x-4)
f(x) = (x-4)(x + 4)
f(x) = -x²

Answers

Answer:

f(x) = -x²

Step-by-step explanation:

Writing f(x) = -x² in vertex form gives f(x)=-(x-0)^2+0 which shows that the vertex (h,k) is at (0,0)

The other equations written in vertex form do not have (h,k) = (0,0)

Jack and Serena can write a lab report together in 12 hours. If all people work at the same rate, how many hours would it take to write a lab report if Kay joins Jack and Serena?

Answers

The answer would be 4 hours because 12/3 is 4

Which of the following is a monomial? O A. 11x-9 OB. 20x9 OC. 20x⁹ - 7x O D.9/x

Answers

Answer:

B. 20x⁹

Step-by-step explanation:

A monomial is a polynomial with just one term.

Example: 3x²

A. 11x - 9

INCORRECT, this has two terms 11x and 9

B. 20x⁹

CORRECT, this only has one term!

C. 20x⁹ - 7x

INCORRECT, this has two terms 20x⁹ and 7x

D.9/x

INCORRECT, this is not a polynomial

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What must be true in order to find a sum for an infinite geometric series?

Answers

Answer:

0 < r < 1

Step-by-step explanation:

That every sequence gets multiplied by a number less than 1 but more than 0

The law is

Common ratio or r must lies in between 0 and 1

It means

r is in (0,1)

r is greater than 0 but less than 1

The formula is

[tex]\boxed{\sf S_{\infty}=\dfrac{a}{1-r}}[/tex]

Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​

Answers

Step-by-step explanation:

log 6 = log (2×3) = log 2 + log 3 = 0.3010+0.4771

=0.7781

Answer:

[tex]\sf \log_{10}6=0.7781[/tex]

Step-by-step explanation:

Given:

[tex]\sf \log_{10} 2 = 0.3010[/tex]

[tex]\sf \log_{10} 3 = 0.4771[/tex]

To find log₁₀ 6, first rewrite 6 as 3 · 2:

[tex]\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)[/tex]

[tex]\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay[/tex]

[tex]\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2[/tex]

Substituting the given values for log₁₀ 3 and log₁₀ 2:

[tex]\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}[/tex]

Therefore:

[tex]\sf \log_{10}6=0.7781[/tex]

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One positive integer is 2 times another positive integer and their product is 50. what are the positive integers?

Answers

The first integer is 5.

The second integer  is 10.

What is Positive integer ?

If an integer is higher than zero, it is positive; if it is lower than zero, it is negative. Zero can be either positive or negative. Since a b and c d, then a + c b + d, the ordering of integers is consistent with algebraic operations.

According to the information:

One integer is twice the other

so,

If one integer is x then

The other will be 2x.

Their product :

2x * x = 50

2x² = 50

x² = 50/2

x² = 25

x = √25

x = 5

the first integer is 5.

the second integer is 2x = 2 x 5

                                        = 10.

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How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane
with movements of only one unit right or one unit up? How many ways are there to do so that do not go above the line y = x?

Answers

The number of ways there are to move from (0, 0) to (7, 7) in the coordinate plane with movements of only one unit right or one unit up accordingly is; 49 while that such that y =x is; 7.

How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane with pmovements of only one unit right or one unit up?

It follows from the task content that the movement intended on the coordinate plane is; from (0, 0) to (7, 7).

The number of ways to move such that movements of only one unit right or one unit up is; 7 × 7 = 49.

The number of ways for which y= x is therefore is; 7 as the movement is diagonal.

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How is a circumference related to an arc

Answers

Answer:

An arc of a circumference or of a circle mostly is a portion of the circumference. The length of an arc for all intents and purposes is simply the length of this portion of the circumference in a definitely major way. The circumference itself can particularly be considered an arc that goes around the circle in a fairly major way.

(a) if x is the sample mean young's modulus for a random sample of n = 64 sheets, where is the sampling distribution of x centered, and what is the standard deviation of the x distribution?

Answers

The standard deviation of the x distribution is 0.2.

According to the statement

we have given that the the sample n is 64 and we have to find the standard deviation of the given sample.

So, For this purpose, we know that the

The standard deviation of the sample is the standard deviation of population divided by the square root of the length of the sample.

In this problem, we have that the value of alpha is

[tex]\alpha = 1.6[/tex]

Suppose that for aluminum alloy sheets of a particular type,

If X is the sample mean Young's modulus for a random sample of n = 64 sheets, and the standard deviation of the X distribution is given by

[tex]s = \frac{\alpha}{\sqrt{64} }[/tex]

then solve it then the standard deviation

s =  {1.6} / {8 }

s = 0.2

So, The standard deviation of the x distribution is 0.2.

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Given that Young's modulus is a quantitative measure of stiffness of an elastic material. Suppose that for aluminum alloy sheets of a particular type, its mean value and standard deviation are 70 GPa and 1.6 GPa, respectively.

a. If X is the sample mean Young's modulus for a random sample of n = 64 sheets, the sampling distribution of X centered at 70 GPa, and the standard deviation of the X distribution is given by

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Determine the seating capacity of an auditorium with 15 rows of seats if there are 25 seats in the first row, 29 seats in the second row, 33 seats in the third row, 37 seats in the forth row, and so on

Answers

Answer:

Step-by-step explanation:

15 rows adding 4 additional seats to each. Once at end add all seats in rows together for the final answer.

1-25

2-29

3-33

4-37

5-41

6-45

7-49

8-53

9-57

10-61

11-65

12-69

13-73

14-77

15-81

Add all togther. 25+29+33+37+41+45+49+53+57+61+65+69+73+77+81=795

So there are 795 seating capacity.

O Yes
O No
2. (02.01 LC)
Is the following relation a function? (1 point)
{(3,-2), (1, 2), (-1,-4), (-1, 2)}

Answers

Answer:

no

Step-by-step explanation:

In a function, each "x" value [input] must have only one corresponding "y" value.

We know that points are written as (x, y)

Our points: {(3,-2), (1, 2), (-1,-4), (-1, 2)}

We can see that the x-input of -1 has two y-outputs, so this is therefore not a function

hope this helps! have a lovely day :)

Question 9 of 25 a bookstore costs $105 a day to keep open, and it spends $12 for each book that it sells. if each book sells for $15, what is the break-even point for this bookstore?

Answers

The store will break even after selling 35 books.

What is the break-even point?The break-even point is the moment at which total cost and total revenue are equal, implying that your small firm has no loss or benefit. In other words, you've reached the point where the costs of production equal the revenues for a product.

To find  what is the break-even point for this bookstore:

Given:

The cost required per day to keep the store open = $105Amount spent on each book = $12

Let, n be the number of books.

Total costs = 12n + 105

The selling price of each book = $15

Total revenue = 15n

For breaking even, costs = revenue.

12n + 105 = 15n105 = 15n - 12n105 = 3n3n = 105Dividing both sides by 3:3n/3 = 105/3n = 35

Therefore, the store will break even after selling 35 books.

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find the length of MN​

Answers

Answer:

The length of MN is 5 cm

Step-by-step explanation:

Add the segment LX, parallel to QP.

Recall the properties of midsegment:

Midsegment is parallel to side,Midsegment is half the length of the parallel side.

We have:

Since QL = LR, the point L is midpoint of Q,Since PN = NL, the point N is midpoint of PL,Since LX is parallel to QP, LX is midsegment of ΔPRQ.

Find the length of LX:

LX = QP/2 = 20/2 = 10 cm

Since QP ║ LX ║ NM, the segment NM is the midsegment of ΔPLX.

Find the length of NM:

NM = LX/2 = 10/2 = 5 cm

Factorise 10xy-12+15x-8y

Answers

Answer: 10xy-12+15x-8y=(5x-4)*(2y+3).

Step-by-step explanation:

[tex]10xy-12+15x-8y=(10xy-8y)+(15x-12)=\\=2y*(5x-4)+3*(5x-4)=(5x-4)*(2y+3).[/tex]

If p(x,3) Q(7,1) and pQ(15) unit find the possible value of x

Answers

Answer:

Step-by-step explanation: P(x 3), Q(7, -1) and PQ= 5 .

To Find :

The possible value of x.​

Solution :

We know, distance between two points in coordinate plane is given by :

Therefore, the possible value of x are 10 and 4.

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