g. Hot water at 100 °C is added to 300 g of water at 0 °C until the final temperature is 40 °C. Find the mass of the hot water added. The specific heat capacity of water is 4200 Jkg-¹°C¹.​

Answers

Answer 1

Answer:

000

Explanation:

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God

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Related Questions

When hexan-1-ol is treated with conc. h2so4 at moderate temperatures, ________ is formed via a(n) ________ mechanism

Answers

When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed via SN₂ mechanism.

SN₂ Mechanism is mechanism involving the factors of steric hindrance following the order of 1° > 2° > 3°. It is a Nucleophilic substitution reaction.

Williamson Ether Synthesis is the synthesis of ether through SN₂ mechanism in which an ether is treated with conc. H₂SO₄ at moderate temperature.

When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed as below:

CH₃CH₂CH₂CH₂CH₂CH₂OH +Conc. H₂SO₄-->(CH₃CH₂CH₂CH₂CH₂CH₂)₂0

Hexan-1-ol                                                                 Di-n-hexyl ether

Williamson Ether Synthesis is a reaction involving a alcohol that is deprotonated to form an ether.

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How many grams of calcium phosphate are theoretically produced if we start with 3. 40 moles of calcium nitrate and 2. 40 moles of lithium phosphate?

Answers

There are 372 grams of calcium phosphate are theoretically produced if we start with 3. 40 moles of calcium nitrate and 2. 40 moles of lithium phosphate .

Calculation,

The reactant or reagent that produces the least moles of the products is called limiting reagents. When  limiting reagents used up , the reaction stops.

The balanced equation is given as,

[tex]3Ca(NO_{3} )_{2} + 2Li_{3} ( PO_{4} )[/tex] → [tex]3LiNO_{3} + Ca_{3}( PO_{4} )_{2}[/tex]

Multiply the moles of each reactant by the mole ratio between it and calcium phosphate in the balanced equation . so that the moles of the reactant cancel , leaving moles of calcium phosphate.

3.4 mol of calcium nitrate × 1 mol calcium phosphate / 3 mol calcium nitrate = 1.13 mol calcium phosphate

2.4 mol of  lithium phosphate× 1 mol calcium phosphate / 2 mol  lithium phosphate = 1.02 mol calcium phosphate

So, calcium nitrate  is limiting reactant .

Calculation of mass of 1.02 mol calcium phosphate.

Multiply the moles of  calcium phosphate by its molar mass.

molar mass of  calcium phosphate = 3×40.078 g/mol calcium ion+2×30.9 g/mol phosphorus + 8×15.99 g/mol calcium phosphate = 310.178 g/mol calcium phosphate

1.20 mol calcium phosphate × 310.178 g/mol = 372 gram

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HELP PLS important plsssssssssssssssss

Answers

Answer: All have something wrong with them!!!

Explanation: #1: He is using chemicals without using any goggles or protection

#2: She is unsupervised while around fire as well as no protection

#3:

#4: There are many flammable things around the fire especially since its paper it could start a major fire

#5: Again has no protection (goggles. gloves, e.t.c.) and putting chemicals close to your face is just a Don't in science

#6: They are "horseplaying" and also someone else is doing all the work

Which compound reacts third fastest with fuming sulfuric acid? a. Toluene b. Chlorobenzene d. Nitrobenzene e. Benzene c. Aniline.

Answers

Toluene compound reacts third fastest with fuming sulfuric acid.

The reaction is attached in figure -

When nitration of toluene is carried out in presence of fuming nitric acid and fuming sulfuric acid under 333 K temperature , 2, 4, 6-trinitro toluene is the final product .This 2, 4, 6-trinitro toluene is also called TNT. TNT is used as explosive.

What is toluene?

Toluene is a common ingredient in degreasers. It's a colorless liquid with a sweet smell and taste. It evaporates quickly. Toluene is found naturally in crude oil, and is used in oil refining and the manufacturing of paints, lacquers, explosives (TNT) and glues.

What is a toluene used for?

Toluene is found naturally in crude oil, and is used in oil refining and the manufacturing of paints, lacquers, explosives (TNT) and glues. In homes, toluene may be found in paint thinners, paintbrush cleaners, nail polish, glues, inks and stain removers.

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A mixture of three gases containing an equal number of moles of each gas has a total pressure of 12. 0 atm. What is the partial pressure of each gas?

Answers

A mixture of three gases containing an equal number of moles of each gas has a total pressure of 12. 0 atm then partial pressure of each gas is 4 atm .

Calculation ,

According to Dalton law the total gas of the container is equal to the sum of partial pressure of each gas .

[tex]P_{t}[/tex] = [tex]P_{1}[/tex] +[tex]P_{2}[/tex]+ [tex]P_{3}[/tex]

Partial pressure = total pressure × mole fraction

mole of each gas is equal . So, mole fraction is also equal for each gas.

Let the number of  mole = x

mole fraction = x/3x =1/3

[tex]P_{1}[/tex] = 12. 0 atm/3 = 4 atm

[tex]P_{2}[/tex] = 12. 0 atm/3 = 4 atm

[tex]P_{3}[/tex] = 12. 0 atm/3 = 4 atm

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What is the binding energy of the electron in kj/molkj/mol? [note that keke = 12mv212mv2 and 1 electron volt (evev) = 1. 602×10−19j. 1. 602×10−19j. ]

Answers

The binding energy of the electron is 1.237 ×10^(-16) kj/ mol.

The given parameter

wavelength of photon,

                       λ = 0.999nm

                          = 0.999x10⁻⁹ m

K.E of emitted photon,

                    K.E = 940 ev

The binding energy of electron is calculated as follows:

From Einstein's mass defect equation=

                    ΔE = Δmc²

Also, from Einstein's photo electric equation=

                       E = Ф + K.E

Where;

          Ф is binding energy of electron on metal surface.

The energy of on mole of electron, the emitted is calculated as:

                   

                       [tex]E = hf =h \frac{c}{λ} = (6.626×10^{-34} ) × \frac{{3×10^{8} }}{0.999×10^{-9} } \\\\E= 1.989×10^{-16}[/tex]

The K.E of emitted electron in Joules is

                 [tex]K.E = 940 × \frac{1}{2} ×1.602 ×\ 10^{-19} J\\\\ = 0.752 × 10^{-16} J[/tex]

The binding energy is electron is calculated as:

               [tex]Ф = E - K.E\\= (1.989 - 0.752) ×10^{-16}\\ =1.237 × 10^{-16} J[/tex]

Question: An X-ray photon of wavelength 0.999nm strikes a surface. The emitted electron has a kinetic energy of 940 eV. What isthe binding energy of the electron in kJ/mol? (KE=1/2mv2; 1 electron volt (eV) = 1.602 x10-19J)

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He fuel used in many disposable lighters is liquid butane, c4h10c4h10. butane has a molecular weight of 58. 1 grams in one mole. how many carbon atoms are in 2. 00 gg of butane?

Answers

Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.

Molecular weight of C4H10 is = 58.1 grams

Moles of butane = given mass/ molar mass

= 2/58.1

= 0.0344 mol

Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:

0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules

of butane

Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:

so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.

Thus the no. of carbon atom is 8.28×10^22.

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Identify the reactants and the products in this chemical equation. 2fe2o3 3c → 4fe 3co2

Answers

Answer:

Reactants: Fe₂O₃ and C

Products: Fe and CO₂

Explanation:

The reactants are the molecules that undergo changes in a reaction.

The products are the molecules which are made during a reaction.

The reactants are on the left side of the arrow and the products are on the right side of the arrow. Therefore.....

The chemical reaction:

2 Fe₂O₃ + 3 C -----> 4 Fe + 3 CO₃

Reactants: Fe₂O₃ and C

Products: Fe and CO₂


Use the Ideal Gal Law to calculate the following problem. How many moles of gas are contained in a 4.2 L container at 2.7 atm and 305 K?

Answers

Answer:

0.453 moles

Explanation:

The Ideal Gas Law equation looks like this:

PV = nRT

In this formula,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

To find the amount of moles of gas, you can plug the given values into the equation and then simplify.

P = 2.7 atm                                 R = 0.08206 atm*L/mol*K

V = 4.2 L                                     T = 305 K

n = ? moles

PV = nRT

(2.7 atm)(4.2 L) = n(0.08206 atm*L/mol*K)(305 K)

11.34 = n(25.0283)

0.453 = n

A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydrogen gas. A sample of hydrogen gas is collected over water in a eudiometer at 32. 0°c. The volume of collected gas is 43. 9 ml and the atmospheric pressure is 832 mmhg. Using the experimentally collected data, calculate r and the percent error.

Answers

The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.That is approximately 0.001758. Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas. The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter. Is it true that calculations made utilizing experimental and gathered data result in a percent error? Consequently, we are aware that magnesium and chloride react.We create 1 as the reaction ratio is 1:2. The hydrogen and 1 are more. Magnesium chloride is more. Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more. Among hydrogen, there is. \Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin. The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter. Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.So, in this instance, we are aware that p v = n r t. The r in this case equals p v over n t, thus we want to determine the r. So p is 110922.24. The temperature is 305.15 and the V is 0.04  over the n is 0.001758. Let's proceed with the calculations right now. In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

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What is the theoretical yield (mass of Al2O3 formed) for this reaction?
(answer is not 204)

Answers

Answer:

102 g Al₂O₃

Explanation:

The theoretical yield is the mass of product calculated via the molar masses and balanced chemical equation.

The limiting reagent is the reactant that is completely reacted before the other reactant(s) are used up. Since Al produces the smaller amount of product, it appears that Al is the limiting reactant. You can only make as much product as the limiting reactant allows. As such, the theoretical yield is 102 grams Al₂O₃.

pls help
complete the table below by writing the symbols for the cation and anion that make each ionic compound

Answers

Answer:

CrO₂ --------------------> Cr⁴⁺ and O²⁻

VCO₃ -------------------> V²⁺ and CO₃²⁻

Cr₂(SO₄)₃ -------------> Cr³⁺ and SO₄²⁻

(NH₄)₂S ----------------> NH₄⁺ and S²⁻

Explanation:

Within ionic compounds, the cation is listed first, followed by the anion. Some of the ions are polyatomic, meaning they are covalently bonded to other elements. Polyatomic ions always have a specific charge.

All of these ionic compounds have an overall charge of 0. As such, the charges of the cations and anions must balance out. In order to do so, there are some compounds which have more than one atom of each ion.

2.) CrO₂

------> Oxygen (O) always forms the anion, O²⁻.

------> Therefore, if there are 2 oxygen anions, the chromium (Cr) must have the cationic form of Cr⁴⁺.

------> +4 + (-2) + (-2) = 0

3.) VCO

------> Carbonate (CO₃), a polyatomic ion, always has the state CO²⁻.

------> If there is only one atom of each ion, the charges must perfectly balance, making vanadium (V) be the cation V²⁺.

------> +2 + (-2) = 0

4.) Cr₂(SO₄)

------> Sulfate (SO₄), a polyatomic ion, always has the state SO₄²⁻.

-------> The only way the charges could balance out is if the chromium (Cr) is in the cationic form Cr³.

------> +3 + 3 + (-2) + (-2) + (-2) = 0

5.) (NH₄)₂S

------> Ammonium (NH₄), a polyatomic ion, always has the state NH₄⁺.

------> Sulfur (S) always forms the anion S²⁻.

------> +1 + 1 + (-2) = 0

What is the boiling point of a solution consisting of cyclohexane (c6h12) dissolved in benzene if the freezing point of this solution is 0. 0°c?

Answers

The boiling point of a solution consisting of cyclohexane (c6h12) dissolved in benzene if the freezing point of this solution is 0. 0°c is 80.9°C.

When a solute and a solvent are combined to form a liquid homogeneous mixture or solution, the properties that result are different from those of the pure substances. As a result, we can find a freezing point depression, boiling point elevation, and a few other cooperative properties, but these two are the focus of this article.

Taking into account that the freezing point depression constant solely depends on the solvent (cyclohexane), we can begin by utilizing the freezing point depression to determine the molality of the solution:

[tex]T_{fsolution} - T_{fsolvent} = -m * {K_{fsolvent}[/tex]

0. 0°c - 5.5°c = -m * 20.0 °c

[tex]m = \frac{-5.5}{- 20.0 }[/tex]

m = 0.275 m

The boiling point elevation formula is then used to get the solution's boiling point, which is once more dependent on the solvent's boiling point elevation constant:

[tex]T_{b, solution} - T_{b, solute} = m * Kb_{solvent} \\\\T_{b, solution} - 80.1 = 0.275m + 2.79\\\\T_{b, solution} = 80.9[/tex]

Therefore, The boiling point of a solution is 80.9°C.

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What mass of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

Answers

91.4 grams

91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

C = mol/volume

2.45M=mol/0.5L

2.45M⋅0.5L = mol

mol = 1.225

Convert no. of moles to grams using the atomic mass of K + Cl

1.225mol * [tex]\frac{39.1+35.5}{mol}[/tex]

mol=1.225

=1.225 mol . [tex]\frac{74.6g}{mol}[/tex]

=1.225 . 74.6

=91.4g

therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

What is 1 molar solution?

In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.

58.44 g make up a 1M solution of NaCl.

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The value of the rate constant at 302°c is 2. 45 × 10-4 l/mol s and at 508°c the rate constant is 0. 0965 l/mol s. the value of r is 8. 3145 j/k mol. Calculate the activation energy for this reaction

Answers

The activation energy for this reaction is - 55.5 kJ/mol

Calculation,

Given data,

First temperature [tex]T_{1}[/tex] =  302°C = 302+273 = 575 K

Second temperature [tex]T_{2}[/tex] =  508°C =  508+273 = 781 K

rate constant at  302°C = 2. 45 × [tex]10^{-4}[/tex] lit/mol s

rate constant at 508°C =  0. 0965 lit/mol s.

Value of universal gas constant = 8.3145 J/k mol.

Apply Arrhenius equation,

㏒[tex]K_{1} /K_{2}[/tex] = [tex]E_{a}/2.203R[/tex] [1/ 575 K - 1/781 K]

㏒2. 45×[tex]10^{-4}[/tex] lit/mol s/0.0965 lit/mol s = [tex]E_{a}[/tex] /2.303×8.3145 J/k mol[781-575/575K×781 K]

[tex]E_{a}[/tex] = - 55.5 kJ/mol

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What will be the ph of a buffer solution with an acid (pka6. 1) that is exactly half as concentrated as its conjugate base?

Answers

The pH of a buffer solution with acid that (PKA 6. 1) is exactly half as concentrated as its conjugate base is 6.4.

What is a buffer solution?

A buffer solution is a solution that has a maintained pH, not basic or not acidic. Its pH changes when acid or base is added to the solution.

We had to figure out the acid's concentration, which is exactly half that of its potential base.

We know that pH = pH_log

We have less than 6.1 pH so this is a conjugated base.

This will equal to 6.1 + log2 = 6.4

Thus, the pH of a buffer solution with acid is 6.4.

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The oxygen consumption rate of a 100 kg seal is 1 ml/(g h). assuming that it has oxygen stores of 7 liters, how many minutes can it dive before running completely out of oxygen?

Answers

Oxygen is the crucial gas required for an organism to carry out the cellular process. The seal can dive for 4 minutes before it runs out of oxygen. Thus, option a is correct.

What is oxygen consumption?

Oxygen is the most vital element of the organism that is required by almost all cellular and metabolic activities. It is inhaled by the respiratory system and passed to cells and tissues through the circulatory system.

Given,

Mass of seal = 100 kg = 100000 gm

Rate of oxygen consumption (r) = 1 ml/ (gh)

The volume of the stored O₂ = 7000 mL

The time (t) is calculated as,

t = V ÷ mr

Substituting the values above,

t = 7000 ÷ 100000 × 1

= 0.07 hour

In minutes it will be given as,

0.07 × 60 = 4.2 minutes

Therefore, option a. 4 minutes is the time till the seal can remain underwater without oxygen.

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Your question is incomplete, but most probably your full question was, The oxygen consumption rate of a 100 kg seal is 1 ml/(g h). assuming that it has oxygen stores of 7 liters, how many minutes can it dive before running completely out of oxygen?

4 minutes45 minutes700 minutes4192 minutes

Rutherford's scattering experiment demonstrated that the mass of an atom was uniformly distributed throughout its volume.
a. true
b. false

Answers

Rutherford's scattering experiment demonstrated that the mass of an atom was uniformly distributed throughout its volume this statement is incorrect.

Hence, Option B is correct answer.  

What is Rutherford's Scattering Experiment ?

Rutherford's Alpha Scattering Experiment demonstrated that Rutherford bombarded most of the alpha particles passed straight through the gold foil. Rutherford observed that most part of the atom is empty.

What is Thomson Atomic Model ?

The mass of an atom was uniformly distributed throughout its volume this experiment was given by Thomson Model.

Thus from the above conclusion we can say that Rutherford's scattering experiment demonstrated that the mass of an atom was uniformly distributed throughout its volume this statement is incorrect.

Hence, Option B is correct answer.  

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Using this balance, can you estimate the mass to the nearest milligram?

Answers

Yes, we can use this balance to  estimate the mass to the nearest milligram.

What is the balance?

The weighing balance is the kind of scale that can be used to measure the mass of a body. We know that mass is the quantity of matter that is contained in a  body and the the SI unit of mass is the kilogram.

Looking at the balance as it is graduated in milligrams, we know that measurement to the nearest gram means measurement to the nearest whole number so we can say that the answer is yes. We can use this balance to  estimate the mass to the nearest milligram.

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How many moles of potassium hydroxide are contained in 750. ml of 5. 00 m potassium hydroxide solution?

Answers

Number of moles of KOH present in solution is 3.75.

What do you mean by mole concept?

The term "mole" refers to a mole's atomic mass, which is expressed in grams. A mole is an element's gram-atomic mass, or mass.

The mole idea equates the mass of a single atom or molecule (measured in a.m.u.) to the mass (measured in grams) of a large collection of equivalent molecules.

To calculate moles of potassium hydroxide in 750 ml of 5.00 m of KOH solution -

Mathematically molarity  is expressed as,

Molarity =no. of molecules of solute/volume of solution

Given: Molarity of solution = 5.00 M

Volume of solution = 750 ml = 0.750 l

∴ 5 = no. of moles/0.750

∴ number of moles = 3.75

Hence, number of moles of KOH present in solution is 3.75.

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What is observed when magnesium is reacted with hydrochloric acid? choose all that apply

Answers

It is observed that when magnesium reacts with hydrochloric acid, it produces visible bubbles of hydrogen gas.

A vigorous reaction will occur giving rise of heat as it is an exothermic reaction. If heat is applied then it should be more vigorous.

Reaction is as follows:

Mg(s) + HCl (aq) --> MgCl2 (aq) + H2(g)

Magnesium reacts easily with HCl to produce H2 gas and magnesium ions, Mg2+, and heat. The reaction is exothermic, so it heats up quickly.

Mg(s) + HCl (aq) --> MgCl2(aq) + H2(g)

The net ionic equation :

Mg(s) + 2H+ --> Mg2 + H2(g)

If water is removed from the solution then white crystals of Mgcl2 is obtained.

Or in simple words,

2Mg + 2HCl -> 2Mg+ + 2Cl- + H2(gas)

The magnesium is attacked by the hydrochloric acid resulting in the magnesium dissolving into the solution resulting in a solution of magnesium chloride in hydrochloric acid and the production of hydrogen gas.

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According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in which order?

Answers

According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.

What is IUPAC convention?

IUPAC convention of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).

The name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).

Types of IUPAC  Nomenclature of a few important aliphatic compounds:

AlkaneAlkeneAlkyne

Example :

Ethane, which has 2 carbon atoms and 6 hydrogen atoms, with the molecular formula of = C₂H₆

Formation of alkyl group:

Methane (CH₄)  Remove 1 hydrogen (H) convert to methyl (H₃-C-)

Example: Propyl (-CH₃ - CH₂ - CH₂ - )

According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.

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If 0.0309 mol CaCl2 is dissolved in water to make a 0.730 M solution, what is the volume of the solution

Answers

Answer:

0.0423 L

Explanation:

Molarity can be represented by the following ratio:

Molarity = moles / volume (L)

You can plug the given values into the equation and simplify to find the volume.

Molarity = moles / volume

0.730 M = 0.0309 moles / volume

(0.730 M) x volume = 0.0309 moles

volume = 0.0423 L

Write a balanced chemical equation for the standard formation reaction of liquid acetic acid hch3co2.

Answers

The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,

[tex]2C(gr) +2H_{2} (g) +O_{2} (g)[/tex]  → [tex]CH_{3} COOH(l)[/tex]

The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.

[tex]C(gr) +H_{2} (g) +O_{2} (g)[/tex] → [tex]CH_{3} COOH(l)[/tex]

The balanced chemical equation for the standard formation reaction of liquid acetic acid as,

[tex]2C(gr) +2H_{2} (g) +O_{2} (g)[/tex]  → [tex]CH_{3} COOH(l)[/tex]

The combustion of liquid acetic acid is given as,

[tex]CH_{3} COOH(l) + 2O(g)[/tex] → [tex]2CO_{2}((g) +2H_{2} O(l)[/tex]                    ΔH =-873

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In an experiment, 10.0 g of magnesium reacted with excess hydrochloric acid forming magnesium chloride. Mg(s) +2HCl(aq) → MgCl2(aq) +H2(g)
At the completion of the reaction, 29.5 g of magnesium chloride was produced. Calculate the percent yield. (Pls help)

Answers

Answer: 75.3%

Explanation:


Mg molar mass = 24

MgCl2 molar mass = 94

—> 94 x 10 / 24

29.5/1 x 24/94 x 10


= 29.5 x 24 / 94 x 10


since we are looking for percentage yield we multiply by 100


= 29.5 x 24 x 100 / 94 x 10 = 75.3%

A compound with chemical formula na2cx3 has formula mass 106 amu .. what is the atomic mass of element x

Answers

The element "X" is "O" (oxygen).

Calculation:

Given,

Chemical formula = Na₂CX₃

Formula mass = 106 amu

Molar mass of Na = 23 amu

Molar mass of C = 12 amu

To find,

Element X =?

We will equate the equation as follows,

2(23) + 12 + 3(y) = 106

46 + 12 + 3y =106

58 + 3y = 106

3y = 106 - 58

3y = 48

y = 48/3

y = 16

We know that Oxygen has molecular mass of 16. Therefore the element "X" is "O".

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What element of a contract refers to both parties receiving some measurable benefit?
a) consideration
b) capacity
c) consent
d) legality

Answers

The consideration element is the correct answer.

The exchange of the value is called consideration. The exchange of money is known as value for anything such as services/property, exchange of property, or services.

There are many types of considerations that are given below:

a promise.an act other than a promise,forbearance,money, a small change in a legal connection between the parties,other property.

The four important elements of a contract are given below:

Offer & Acceptance,Consideration,Legal Capacity,Legality.

If any of the given elements is missing then the contract is voided, and the parties released from the agreement.

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What was the oxygen consumption for a burmese python at 20 contractions per minute?

Answers

The oxygen consumption for a burmese python at 20 contractions per minute 5,30,35,10,15,20,25 contractions per minute.

Python

The Eastern Hemisphere's tropical and subtropical regions are home to the genus Python, a family of constricting snakes. For non-venomous flecked snakes, François Marie Daudin suggested the name "Python" in 1803. There are now 10 recognized python species. A new species has been established, and three previously recognized python subspecies have been elevated.

Ythons lack venom, and colubrids (rear-fanged snakes) either lack venom entirely or have a weak venom. It is important to take venomous elapid (front-fanged snake) bites seriously and treat them accordingly. Massive snakes called pythons have a brutal killing style. These snakes, like other strong constrictors like anacondas, will capture their victims with their mouths and wrap around them.

What was the oxygen consumption for a burmese python at 20 contractions per minute?

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Bombardment of uranium-238 nuclei by carbon-12 nuclei produces californium-246 and neutrons. Write a complete, balanced equation for this nuclear process

Answers

Bombardment of uranium-238 nuclei by carbon-12 nuclei produces californium-246 and neutrons then the complete, balanced equation for this nuclear process is given a ,

[tex]^{238} _{92}U + ^{12} _{6} C[/tex] → [tex]^{246} _{98} Cf + 4^{1} _{0} n[/tex]

Nuclear fusion reactions are defined as the reaction in which, two or more lighter atoms combine to form a heavier atom. The number of atoms formed in this reaction decreases from the given atoms. The nuclear process is also nuclear fusion.

Example : Bombardment  of uranium-238 nuclei

Chain reactions are defined as the reaction in which the neutrons that are released in the previous fission reaction act as the starting material in the next reaction. Thus, this process continues to many reactions.

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

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If the rock had originally 2400 atoms of u 235 and now has 440 left, how many atoms of pb 207 are there in the rock now?

Answers

436 atoms of Pb 207 are left in the rock.

Radioactive decay:

Alpha and beta decays are the mechanism through which uranium transforms into the lead. While 235U and its daughter nuclides only experience seven alpha and four beta decays, 238U and its daughter nuclides suffer eight alpha and six beta decays overall.

When there are too few neutrons in relation to protons, alpha decay occurs. There is the discharge of an alpha particle, which consists of two protons and two neutrons.

When there are more neutrons than protons, beta decay can happen. A high-speed electron is ejected from a proton that transforms spontaneously from a neutron.

Since gamma radiation is emitted as a wave rather than a particle, the atomic structure of an atom remains unaltered. Atomic fission is the primary cause of neutron emission. At one time, many neutrons can be released.

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