Find the third order maclaurin polynomial. Use it to estimate the value of sqrt1.3
Answers
You can use the well-known binomial series,
[tex]\displaystyle (1+x)^\alpha = \sum_{k=0}^\infty \binom \alpha k x^k[/tex]
where
[tex]\dbinom \alpha k = \dfrac{\alpha(\alpha-1)(\alpha-2)\cdots(\alpha-(k-1))}{k!} \text{ and } \dbinom \alpha0 = 1[/tex]
Let [tex]\alpha=\frac12[/tex] and replace [tex]x[/tex] with [tex]3x[/tex]; then the series expansion is
[tex]\displaystyle (1+3x)^{1/2} = \sum_{k=0}^\infty \binom{\frac12}k (3x)^k[/tex]
and the first 4 terms in the expansion are
[tex]\sqrt{1+3x} \approx 1 + \dfrac{\frac12}{1!}(3x) + \dfrac{\frac12\cdot\left(-\frac12\right)}{2!}(3x)^2 + \dfrac{\frac12\cdot\left(-\frac12\right)\cdot\left(-\frac32\right)}{3!}(3x)^3[/tex]
which simplify to
[tex]\sqrt{1+3x} \approx \boxed{1 + \dfrac32 x - \dfrac98 x^2 + \dfrac{27}{16} x^3}[/tex]
You can also use the standard Maclaurin coefficient derivation by differentiating [tex]f[/tex] a few times.
[tex]f(x) = (1+3x)^{1/2} \implies f(0) = 1[/tex]
[tex]f'(x) = \dfrac32 (1+3x)^{-1/2} \implies f'(0) = \dfrac32[/tex]
[tex]f''(x) = -\dfrac94 (1+3x)^{-3/2} \implies f''(0) = -\dfrac94[/tex]
[tex]f'''(x) = \dfrac{81}8 (1+3x)^{-5/2} \implies f'''(0) = \dfrac{81}8[/tex]
Then the 3rd order Maclaurin polynomial is the same as before,
[tex]\sqrt{1+3x} \approx f(0) + \dfrac{f'(0)}{1!} x + \dfrac{f''(0)}{2!} x^2 + \dfrac{f'''(0)}{3!} x^3 = 1 + \dfrac32 x - \dfrac98 x^2 + \dfrac{27}{16} x^3[/tex]
Now,
[tex]\sqrt{1.3} = \sqrt{1+3x} \bigg|_{x=\frac1{10}} \\\\ ~~~~~~~~ \approx 1 + \dfrac32 \left(\dfrac1{10}\right) - \dfrac98 \left(\dfrac1{10}\right)^2 + \dfrac{27}{16} \left(\dfrac1{10}\right)^3 \\\\ ~~~~~~~~ = \dfrac{18,247}{16,000} \approx \boxed{1.14044}[/tex]
Compare to the actual value which is closer to 1.14018.
[tex]\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}[/tex] is the maclaurin polynomial and estimate value of [tex]\sqrt{1.3}[/tex] is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.
Find the third order maclaurin polynomial:Given the polynomial,
[tex]f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }[/tex]
The formula to find the maclaurin polynomial,
[tex]f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}[/tex]
Next we have to find f'(x), f''(x) and f'''(x),
[tex]f'(x) = \frac{3}{2}(1+3x)^{-\frac{1}{2} }[/tex] [tex]f''(x) =-\frac{9}{4}(1+3x)^{-\frac{3}{2} }[/tex][tex]f'''(x) = \frac{81}{8}(1+3x)^{-\frac{5}{2} }[/tex]By putting x = 0 , we get,
[tex]f(0)=(1+3(0))^{\frac{1}{2} }=1[/tex] [tex]f'(0) = \frac{3}{2}(1+3(0))^{-\frac{1}{2} }=\frac{3}{2}[/tex][tex]f''(0) =-\frac{9}{4}(1+3(0))^{-\frac{3}{2} }=-\frac{9}{4}[/tex][tex]f'''(0) = \frac{81}{8}(1+3(0))^{-\frac{5}{2} }=\frac{81}{8}[/tex]Therefore the maclaurin polynomial by using the formula will be,
[tex]\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}[/tex]
[tex]\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}[/tex]
To find the value of [tex]\sqrt{1.3}[/tex] we can use the maclaurin polynomial,
[tex]\sqrt{1.3}[/tex] is [tex]\sqrt{1+3x}[/tex] with x = 1/10,
[tex]\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}[/tex]
[tex]\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14[/tex]
Hence [tex]\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}[/tex] is the maclaurin polynomial and estimate value of [tex]\sqrt{1.3}[/tex] is 1.14.
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Related Questions
The surface areas of two similar cylinders are 6cm² and 54cm².
i. Find the scale factor for the enlargement.
ii. If the larger cylinder has height 12cm, how high is the smaller one?
iii. What is the ratio of their volumes?
Answers
Answer:
3, 4, 27
Step-by-step explanation:
1) Area scale factor = 9
Length scale factor = 3 because √9
2) 12/3 = 4
3) 3³ = 27
Find two consecutive numbers such that the sum of four times the first and triple the second is 157. (linear function)
Answers
So, 22, 23 are the two numbers.
What is linear and polynomial function?There are two distinct but related ideas that are referred to as linear functions: A polynomial function of degree 0 or 1 is referred to as a linear function in calculus and related fields if its graph is a straight line.
Consecutive numbers are preceding and following, hence we need two numbers so that
X+1=Y
or
X- Y = -1
In addition, we are aware of
4x + 3y = 157
Let's increase the top equation by 3 times.
We get
3x - 3y = -3
Then we combine that with the bottom equation.
4x + 3y = 157
7x= 154
x = 22
Afterward, we substitute x into the initial equation,
22+1 = 23
So, 22, 23 are the two numbers.
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The given decimal is 0.571
Convert the decimal into fraction :
Write down the decimal divided by1
:
0.571
1
Multiply both top and bottom by1000
:
0.571
1
×1000
1000
=571
1000
Answers
PLEASE ANSWER QUICKLY
Answers
Answer:
1st option
Step-by-step explanation:
to find f(g(x)) substitute x = g(x) into f(x) , that is
f(g(x))
= f(4x - 5)
= 2(4x - 5) + 1 ← distribute parenthesis
= 8x - 10 + 1
= 8x - 9
Alan is arranging 3 different stuffed toys in a row on a shelf. create a sample space for the arrangement of a teddy bear (t), a kitten (k), and an elephant (e).
Answers
The sample space for the arrangement of a teddy bear (t), a kitten (k), and an elephant (e) is tke, tek, kte, ket, etk and ekt
How to create the sample space?The given parameters are
Stuffed toys, n = 3
Toys to arrange, r = 3 i.e. teddy bear (t), a kitten (k), and an elephant (e).
The number of arrangement is calculated as;
Ways = nPr
Substitute the known values in the above equation
Ways = 3Pr
Apply the permutation formula
Ways = 3!/0!
0! =1
So, we have
Ways = 3!/1
This gives
Ways = 3!
Expand
Ways = 3 * 2 * 1
Evaluate
Ways = 6
This means that the sample size is 6
Hence, the sample space for the arrangement of a teddy bear (t), a kitten (k), and an elephant (e) is tke, tek, kte, ket, etk and ekt
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A lighthouse is located at (1, 2) in a coordinate system measured in miles. a sailboat starts at (–7, 8) and sails in a positive x-direction along a path that can be modeled by a quadratic function with a vertex at (2, –6). which system of equations can be used to determine whether the boat comes within 5 miles of the lighthouse? startlayout enlarged left-brace 1st row (x minus 1) squared (y minus 2) squared = 5 2nd row y = startfraction 14 over 81 endfraction (x minus 2) squared minus 6 endlayout startlayout enlarged left-brace 1st row (x minus 1) squared (y minus 2) squared = 25 2nd row y = startfraction 14 over 81 endfraction (x minus 2) squared minus 6 endlayout startlayout enlarged left-brace 1st row (x minus 1) squared (y minus 2) squared = 5 2nd row y = negative startfraction 14 over 81 endfraction (x 7) squared 8 endlayout startlayout enlarged left-brace 1st row (x minus 1) squared (y minus 2) squared = 25 2nd row y = negative startfraction 14 over 81 endfraction (x 7) squared 8 endlayout
Answers
The system of equations that can be used to determine whether the boat comes within 5 miles of the lighthouse is:
y = (2/7)(x - 2)^2 - 6(x - 1)^2 + (y - 2)^2 = 5^2What are equations?The equation is described as the state of being equal and is commonly represented as a math expression with equal values on either side, or it refers to an issue in which many factors must be considered. 2+2 = 3+1 is an example of an equation.To find the system of equations that can be used to determine whether the boat comes within 5 miles of the lighthouse:
The vertex form of a quadratic function is given by: f(x) = a(x - h)^2 + k
Where (h, k) is the vertex of the parabola, a is constant.
For the sailboat we have vertex: (h, k) = (2, -6) and one point: (-7, 8) that is f(-7) = 8.
f(x) = a(x - 2)^2 - 6We will find a using f(-7) = 8:
f(-7) = a(-7-2)^2 - 6f(-7) = 49a - 649a - 6 = 849a = 14a = 14/49a = 2/7The quadratic function for the sailboat is given by:
f(x) = (2/7)(x - 2)^2 - 6 or y = (2/7)(x - 2)^2 - 6The equation for a circle with a radius of 5 and center (1, 2) is:
(x - 1)^2 + (y - 2)^2 = 5^2Therefore, the system of equations that can be used to determine whether the boat comes within 5 miles of the lighthouse is:
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The correct form of the question is given below:
A lighthouse is located at (1, 2) in a coordinate system measured in miles. a sailboat starts at (–7, 8) and sails in a positive x-direction along a path that can be modeled by a quadratic function with a vertex at (2, –6). which system of equations can be used to determine whether the boat comes within 5 miles of the lighthouse?
Don't answer this.
A, B, and C are equal in length; each one is 4.47 units long. ABC is an isosceles triangle since two of its sides are congruent.
Answers
The information given that A, B, and C are equal in length; each one is 4.47 units long illustrates that the angle is an equilateral triangle.
Secondly, when two of its sides are congruent, then the triangle is an isosceles triangle.
How to illustrate the information?It should be noted that an equilateral triangle simply means the triangle tht had equal shape and angles. Here, since A, B, and C are equal in length; each one is 4.47 units long illustrates that the angle is an equilateral triangle.
Secondly, when two of its sides are congruent, then the triangle is an isosceles triangle. On such triangle, two out of the three sides are equal.
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For each of the number lines, write an absolute value equation that has the following solution set. 26 and m
Answers
On a number line, an absolute value equation that has the given solution set is |m - 4| = 2.
How to write the absolute value equation?By critically observing the given question, we can infer and logically deduce that the solution sets for this absolute value equation is given by:
m = {2, 6}
Next, we would calculate the mean of the solution sets as follows:
m₁ = (2 + 6)/2
m₁ = 8/2
m₁ = 4.
Also, we would calculate the difference in the solution sets as follows:
m₂ = (6 - 2)/2
m₂ = 4/2
m₂ = 2.
Mathematically, the absolute value equation is given by:
|m - m₁| - m₂ = 0
|m - 4| - 2 = 0
|m - 4| = 2.
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Consider this quadratic equation. x2 3 = 4x which expression correctly sets up the quadratic formula to solve the equation?
Answers
The expression which correctly sets up the quadratic formula to solve the equation is (A) [tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex].
What is an expression?
In mathematics, an expression is a combination of numbers, variables, and functions (such as addition, subtraction, multiplication or division, etc.) Expressions are similar to phrases. A phrase in language may comprise an action on its own, but it does not constitute a complete sentence.To find which expression correctly sets up the quadratic formula to solve the equation:
Theory of quadratic equation - A quadratic equation is defined as any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power.
An example of a quadratic equation in x is [tex]-4x^{2} +4=9x[/tex].
How to solve any quadratic equation using the Sridharacharya formula?
Let us represent a general quadratic equation in x, [tex]ax^{2} +bx+c=0[/tex] where a, b and c are coefficients of the terms.
According to the Sridharacharya formula, the value of x or the roots of the quadratic equation is -
[tex]x=\frac{-b+-\sqrt{(b)^{2}-4(a)(c) } }{2a}[/tex]
The given equation is [tex]x^{2} -4x+3=0[/tex]
Comparing with the general equation of quadratic equation, we get a = 1, b = -4 , c = 3.
Putting the values of coefficients in the Sridharacharya formula,
[tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex] which is (A).
Therefore, the expression which correctly sets up the quadratic formula to solve the equation is (A) [tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex].
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The complete question is shown below:
Consider this quadratic equation. x^2+3=4x. Which expression correctly sets up the quadratic formula to solve the equation?
find the value of n:
[tex]\frac{n}{11} = \frac{3.5}{7}[/tex]
Answers
The value of n from the given expression is 5.5
Solution to linear equation and fractionsFractions are expression written as a ratio of two integers. The linear equation on the other hand has a leading degree of 1.
Given the equation below;
n/11 = 3.5/7
Simplify to have
n/11 = 1/2
Cross multiply the given result to have:
11 = 2n
Swap
2n = 11
Divide both sides by 2 to have;
2n/2 = 11/2
n = 5.5
Hence the value of n from the given expression is 5.5
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i need help with my algebra assignment
Answers
Answer:
[tex]Question 1\\1+i\\-1-i\\Question 2\\\\-1+i\\1-i[/tex]
Step-by-step explanation:
Complex Numbers:
Complex numbers can generally be expressed in the form: [tex]a+bi[/tex] where a and b are both real numbers, with the a part representing the real part of the complex number, and the bi representing the imaginary part.
We can also graph these numbers using the complex plane. The complex plane has the real axis where the x-axis would normally be, and the imaginary axis where the y-axis would normally be. So by this definition the "a" is what determines the horizontal position or the position on the real axis and the "b" is what determines the vertical position or the position on the imaginary axis.
I attached a diagram of the complex plane, and it's essentially the same as a normal graph, with a=x, and b=y.
Question 1:
So when a complex number lies above the real-axis, that means the imaginary part is greater than 0. When a complex numbers lies to the right of the imaginary axis, that means the real part is greater than 0.
This means we have the form: [tex]a+bi \text { where } a > 0 \text{ and } b > 0[/tex]. You can literally plug in any number for a and b, so long as it fits this. For example we can just do: [tex]1+i[/tex]
So when a complex number lies below the real-axis, that means the imaginary part is less than 0. when a complex numbers lies to the left of the imaginary axis, the real part is less than 0.
This means we have the form: [tex]a+bi \text { where } a < 0\text{ and }b < 0[/tex]. You can plug in any real number that lies within this restriction. An example would be:
[tex]-1-i[/tex]
Question 2:
Above real axis and to the left of the imaginary axis means: b>0 and a<0. So we can plug in any number into the standard form that fits this restriction. an example would be: [tex]-1+i[/tex]
Below real axis and to the right of the imaginary axis means: b<0 and a>0. So we can plug in any number into the standard form that fits this restriction. An example would be: [tex]1-i[/tex]
(6+q)-xy pllease help this question turn in words
Answers
In words (6 + q) - xy is six added to a number subtracted from the product of two numbers
The problem is a algebraic expression
What is an algebraic expression?A algebraic expression a mathematical expression containing one or more variables used to express a word problem
We want to convert the algebraic expression (6 + q) - xy into a word problem.
First, we have 6 + q which is six added to a number.Next, we have xy which is the product of two numbersSince (6 + q) is subtracted from xy, we have (6 + q) - xy as six added to a number subtracted from the product of two numbersSo, (6 + q) - xy in words is six added to a number subtracted from the product of two numbers
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Write the equation for a circle centered at the origin with x-intercepts of (-9,0) and (9,0).use ^2 for squared, ^3 for cubed,
Answers
The equation of the circle can be shown as, x² + y² = 9², or, x² + y² = 81.
The equation of a circle, with the center at the origin and the radius r units, is given as x² + y² = r².
In the question, we are asked to write the equation for a circle centered at the origin with x-intercepts of (-9, 0) and (9, 0).
We can find the radius of the circle using the distance formula,
D = √((x₂ - x₁)² + (y₂ - y₁)²), where (x₁, y₁) and (x₂, y₂) are the endpoints of a line segment.
Radius is the distance between the center and any point on the circle.
Thus, taking (x₁, y₁) as (0, 0), the origin, for the center, and (x₂, y₂) as (9, 0), for any point on the circle, we get the radius as:
r = √((9 - 0)² + (0 - 0)²),
or, r = √(9² + 0²),
or, r = √9² = 9.
Thus, the radius of the circle is r = 9 units.
Thus, the equation of the circle can be shown as, x² + y² = 9², or, x² + y² = 81.
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Given the linear regression equation, y^=134. 63−2. 79x. What is the predicted value of y^ when x=45? (round answer to two decimal places, example: 3. 45)
Answers
Answer:
9.08
Step-by-step explanation:
To find the predicted value of y, put the x-value where x is in the equation and do the arithmetic.
Substitution[tex]\hat{y}=134.63-2.79x\qquad\text{given}\\\\\hat{y}=134.63-2.79(45) = 134.63-125.55\qquad\text{use 45 for x}\\\\\boxed{\hat{y}=9.08}\qquad\text{simplify}[/tex]
Evaluate the expression under the given conditions. tan(2); cos() = 5 13 , in quadrant i
Answers
The solution to given expression tan(2θ) is 22.615°
For given question,
We have been given an expression tan(2θ)
Given that cos(θ) = 5/13, and θ is in quadrant 1.
We know that the trigonometric identity
sin²θ + cos²θ = 1
⇒ cos²θ = (5/13)²
⇒ sin²θ = 1 - 25/169
⇒ sin²θ = 169 - (25/169)
⇒ sin²θ = 144/169
⇒ sin(θ) = 12/13
We know that the identity cos(2x) = cos²x - sin²x
⇒ cos(2θ) = cos²θ - sin²θ
⇒ cos(2θ) = 25/169 - 144/169
⇒ cos(2θ) = -119/169
And sin(2x) = 2sin(x)cos(x)
⇒ sin(2θ) = 2sin(θ)cos(θ)
⇒ sin(2θ) = 2 × 12/13 × 5/13
⇒ sin(2θ) = 120/169
We know that, tan(x) = sin(x)/cos(x)
⇒ tan(2θ) = sin(2θ)/cos(2θ)
⇒ tan(2θ) = (120/169) / (-119/169)
⇒ tan(2θ) = 120 / (-119)
⇒ tan(2θ) = -1.008
Since θ is in quadrant 1, tan(2θ) = 1.008
⇒ 2θ = arctan(1.008)
⇒ 2θ = 45.23
⇒ θ = 22.615°
Therefore, the solution to given expression tan(2θ) is 22.615°
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Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. the mirror is 2 feet wide and 3 feet long. which quadratic equation can be used to determine the thickness of the frame, x? square with an inner frame with height of 2 ft on the left frame and width of 3 ft on the top. arrow on the bottom frame with an x and an arrow on the right frame with an x. x2 14x − 2 = 0 2x2 10x − 7 = 0 3x2 12x − 7 = 0 4x2 10x − 1 = 0
Answers
The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.
The correct option is D.
What is a quadratic equation ?A quadratic equation is an algebraic equation of the second degree in x.. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.
According to the given information:Total area = 7 square feet
and,
Total area = Length x Width
So,
7 = (2x + 3)(2x + 2)
7 = 4x2 + 4x + 6x + 6
7 = 4x2 + 10x + 6
4x2 + 10x + 6 - 7 = 0
4x2 + 10x - 1 = 0
Hence,
The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.
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I understand that the question you are looking for is:
Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and 3 feet long. Square with an inner frame with height of 2 ft on the left frame and width of 3 ft on the top. Arrow on the bottom frame with an x and an arrow on the right frame with an x. Which quadratic equation can be used to determine the thickness of the frame, x?
A. x² + 14x - 2 = 0
B. 2x² + 10x - 7 = 0
C. 3x² + 12x - 7 = 0
D. 4x² + 10x - 1 = 0
the value of digit 7 in 906.7
Answers
The answer is tenths
Step-by-step explanation:
According to the place value chart of decimals,the first number after the decimal point starts from tenths and continues.so the answer is tenths
Hi :)
Remember Place value in decimal numbers
———————————[tex]\large\boldsymbol{\hfill\stackrel{hundreds}{9}~\hfill\stackrel{tenths}0~\hfill\stackrel{ones}6.\hfill\stackrel{tenths}{7}}[/tex]
Then
The place-value of [tex]\boldsymbol{7}[/tex] is [tex]\boldsymbol{tenths}[/tex].
[tex]\tt{Learn~More;Work~Harder}[/tex]
:)
what do I check off
Answers
Answer:
E. >
Because 65 is greater than 56.
Tickets to the movies cost $24 for 1 adult. The price of 1 child was 2/3 of that price. How much did a family with 2 adults and 2 children have to pay?
Answers
Two thirds of 24 will be the price of 1 child. Divide 24 by 3 and you get 8. Since 8 is 1/3 of 24, 16 would be 2/3 of 24.
So the price for 1 child is 16$.
2 adults and 2 children is 24+24+16+16
The family had to pay a total of $80
Find the area of this triangle. Round to the nearest tenth.
Answers
The area of the triangle rounded to the nearest tenth is 33.3 squared inches.
What is the area of the triangle?
Given the data in the diagram;
Angle B = 133°Side a = 7Side c = 13Side b = ?Angle C = ?First we find the dimension of side b.
From the rule of cosines.
b = √[ a² + c² - 2acCosB ]
We substitute into the formula.
b = √[ 7² + 13² - ( 2 × 7 × 13 × cos( 133° ) ]
b = √[ 49 + 169 - ( 182 × cos( 133° ) ) ]
b = √[ 218 - 182×cos( 133° ) ]
b = √[ 342.1237 ]
b = 18.5
Next, we find angle C.
From rule of cosines.
cosC = [ b² + a² - c² ] / 2ba
cosC = [ 18.5² + 7² - 13² ] / [ 2 × 18.5 × 7 ]
cosC = [ 342.25 + 49 - 169 ] / [ 259 ]
cosC = [ 222.25 ] / [ 259 ]
cosC = [ 0.8581 ]
C = cos⁻¹[ 0.8581 ]
C = 30.9°
Now, we can find the area of the triangle.
Area = [ ab × sinC ] / 2
Area = [ 7 × 18.5 × sin( 30.9 ) ] / 2
Area = [ 129.5 × 0.51354 ] / 2
Area = 66.5 / 2
Area = 33.3 in²
The area of the triangle rounded to the nearest tenth is 33.3 squared inches.
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If two marbles are selected at random with replacing between draws, what is the probability that the outcome is red then yellow? (round your answer to four decimal places. )
Answers
The probability that the outcome is red then yellow is 0.036.
Given that in a jar there are 8 red marbles, 1 yellow marble and 6 green marbles.
We are required to find the probability of obtaining a red then yelow marble if two marbles are drawn and replacement is used.
Probability is the calculation of finding the chance of happening a event among all the events possible. It lies between 0 and 1.
Probability=Number of items/ Total items.
Number of red marbles=8
Number of yellow marble=1
Number of green marbles=6
Total marbles=15
Probability of obtaining red marble=8/15
Probability of obtaining yellow marble=1/15 (Because replacing is there so the number of total marbles do not decrease)
Required probability=8/15*1/15
=8/225
=0.035555
After rounding off we will get 0.036.
Hence the probability that the outcome is red then yellow is 0.036.
Question is incomplete. The following line should be included in question:
A jar contains 8 red marbles , a yellow marble and 6 green marbles.
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how do you calculate this
Answers
Answer:
y = - 2x - 1
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 1, 1) and (x₂, y₂ ) = (0, - 1) ← 2 points on the line
m = [tex]\frac{-1-1}{0-(-1)}[/tex] = [tex]\frac{-2}{0+1}[/tex] = [tex]\frac{-2}{1}[/tex] = - 2
the line crosses the y- axis at (0, - 1 ) ⇒ c = - 1
y = - 2x - 1 ← equation of line
In the regular octagon below, if AP = 12 cm. and BC = 19 cm, find its area.
Answers
First symmetrically cut the octagon to get 8 pieces. (So that you will get the idea that this polygon is divided into 8 triangles)
Then find the area of one of the triangles:
Area of Triangle = [tex]\frac{1}{2} * b* h[/tex]
A = [tex]\frac{1}{2}[/tex] × 12 × 19
A = 114 cm²
To find the area of the whole octagon shape:
A = 114 × 8 = 912 cm²
Hope it helps!
Answer:
Step-by-step explanation:
You cannot do this unless you are certain that P is the center of the octagon. I don't know if that's solvable from the information given. So I will make the assumption that P is the center.
Determine the midpoint of BC. Call it E. Draw a line from P to E. By symmetry EP = AP. BE = 1/2 * BC = 19/2 = 9.5 by construction
You have a trapezoid witch is 1/4 the area of the octagon. Three more trapezoids can fit into the octagon.
Formula
Area = (AP + BE)*PE / 2
Givens
AP = 12
BE = 9.5
PE = 12
Solution
Put the givens and constructions into the formula
Area = (12 + 9.5)*12/2
Area = 21.5 * 12/2
Area = 21.5 * 6
Area = 129
That's the area of one of the trapezoids. Multiply the area here by 4.
You get 516.
Determine what type of model best fits the given situation: water leaking from a local reservior at the rate of 500 gallons per hour.
Answers
The type of model that best fits the given situation is; A linear equation Model
What is the model of the equation?Right inside the local reservoir we will have an initial amount of water A.
Now, for every hour that passes by, the amount of water in the reservoir decreases by 500 gals.
Thus, after t hours, the amount of water in the reservoir is expressed as:
W = A - 500gal * t
This is clearly a linear equation model and so we can conclude that the model that fits best in the given situation is a linear model.
The domain of this model is restricted because we can't have a negative amount of water in the reservoir, and as such the maximum value of t accepted is: W = 0 = A - 500gal*t
t = A/500 hours
Therefore, the domain of this linear relation is: t ∈ {0h, A/500 }
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QUICK!!!
The total arm and blade of a windshield wiper is 12 in. long and rotates back and forth through an angle of 90 degrees. The shaded region in the figure is the portion of the windshield cleaned by the 9-in. wiper blade. What is the area of the region cleaned?
answer with the last three decimal places (no rounding)
Answers
The area of the region is: 63.585 square inches.
What is the area of the region cleaned?If we have a circle of radius R, the area of said circle is:
A = pi*R^2
Particularly, if we have a section of the circle defined by an angle θ, the area of that region is:
A = (θ/2pi)*pi*R^2 = (θ/2)*R^2
In this case we have:
θ = 90° = pi/2
R = 9in
Replacing that we get:
A = (pi/4)*(9in)^2 = (3.14/4)*(9in)^2 = 63.585 in^2
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If BD = 16 yd and the area of rhombus ABCD is 72 yd^2, what is AC?
Answers
Formula for finding area of rhombus: [tex]\frac{d1 * d2}{2}[/tex]
d₁ = 16 yd
Area = 72 yd²
Rhombus Area =>
[tex]\frac{16 * d2}{2} = 72[/tex]
16*d₂ = 144
d₂ = 9
AC = 9 yd
Hope it helps!
A particle starts from rest at a fixed point A and moves in a straight line with an acceleration which, t seconds after leaving A, is given by a = 4t. After 2 seconds the particle reaches a point B and the acceleration then ceases. Find:
i) the velocity when the particle reaches B
ii) the distance AB
The particle moves on immediately with acceleration given by -3t, where t seconds is the time after the particle leaves A, until it comes to rest at a point C. Find:
iii) the value of t when the particle reaches C
(iv) the distance AC
Answers
(a) The velocity when the particle reaches B is 8 m/s.
(b) The distance between point A and B is 5.33 m.
(c) The value of t when the particle reaches C is 1.63 seconds.
(d) The distance AC is 8.7 m.
Velocity when the particle reaches BThe velocity when the particle reaches B is calculated as follows;
v = ∫a. dt
where;
v is velocitya is acceleration of the particlev = ∫(4t . dt)
v = 4t²/2
v = 2t²
v(2) = 2(2)²
v(2) = 8 m/s
Thus, the velocity when the particle reaches B is 8 m/s.
Distance ABx = ∫v
where;
x is the distance between A and Bx = ∫2t². dx
x = ²/₃t³
x(2) = ²/₃(2)³
x(2) = 5.33 m
Thus, the distance between point A and B is 5.33 m.
value of t when the particle reaches Cwhen the particle reaches point C, final velocity, vf = 0
vf = v + at
where;
v is the velocity at point0 = 8 - 3t(t)
0 = 8 - 3t²
3t² = 8
t² = 8/3
t² = 2.67
t = √(2.67)
t = 1.63 seconds
Distance between A and Cx = ∫vf
x = ∫(8 - 3t²)
x = 8t - t³
x(1.63) = 8(1.63) - (1.63)³
x(1.63) = 8.7 m
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Select the correct answer. which of these organizations provides help to the friends and families of an alcoholic? a. national clearing house for alcohol and drug information b. american council on alcoholism c. alateen
Answers
Alateen, also called Al-Anon, provides meetings and services for young people age 13 to 18 who’ve been affected by the drinking of other people.
Answer: C
Step-by-step explanation:
Sami cuts out a rectangle that has a perimeter of 48 inches and a length of 13 inches. they cut out another rectangle that is the same length and twice as wide. what is the perimeter of the new rectangle?
Answers
Answer:
70 inches
Step-by-step explanation:
the width of the original rectangle:
48/2 - 13 = 24 - 13 = 11
the new rectangle:
length: 13
width: 2(11) = 22
perimeter: 2(13+22) = 2(35) = 70
The perimeter of the new rectangle is 70 inches.
What is Area of Rectangle?The area of Rectangle is length times of width.
The perimeter of a rectangle is given by the formula P = 2(l + w)
where P is the perimeter, l is the length, and w is the width.
The first rectangle has a perimeter of 48 inches and a length of 13 inches.
48 = 2(13 + w)
24 = 13 + w
w = 11
So the first rectangle has a length of 13 inches and a width of 11 inches.
The second rectangle has the same length of 13 inches and twice the width of the first rectangle, which means it has a width of 22 inches.
P = 2(13 + 22)
= 2(35)
= 70
Therefore, the perimeter of the new rectangle is 70 inches.
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Given the triangle ABC at points A=(1,6) B=(-3,5) C=(7,1), and if the triangle is first reflected over the
y axis, and then over the x axis, find the new point A".
Select one:
O a. (1,-6)
Ob. (3,5)
Oc. (-1,-6)
O d. (1,6)
Answers
After reflected over the triangle the point a become A = (-1,-6). The option c is correct.
According to the statement
we have given that the a triangle ABC at the points A=(1,6) B=(-3,5) C=(7,1), and we have to find the points of a when the triangle is first reflected over the y axis.
So, For this purpose
we know that the when the triangle is at the x axis then the point A is A=(1,6).
But when the triangles reflected over the y - axis then the point A goes to the negative side of the graph. In other words whole of the triangle shift to the negative side of the graph. That's why the point become negative.
So, The option c is correct. After reflected over the triangle the point a become A = (-1,-6)
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