Find the magnitude of this
vector:

The air pressure normally drops before a cold front passes and rises after a cold front passes.

When a warm, lighter air mass pushes under a cold, dense air mass, the warm air is forced to rise, forming a cold front. The warm air at the surface is replaced by the cold air as it moves forward. As the moisture in the warm air mass rises, cools, and condenses, rain and even thunderstorms might develop. The winds will often change direction during a cold frontal passage from the south to the west or north. It is probable that cold, fair weather will continue when the front passes.

The sort of air mass going in affects the temperature behind a cold front. During the winter, a polar air mass will bring in frigid air, and during other seasons, cool air. Bitter air from the Arctic will be present.

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Extrasolar planet mass can be ten times as that of earth and it's size can be twice as that of earth.

GJ 504b is the planet having lowest mass detected around sun.

HAT-O-67b is the planet having the highest mass with diameter twice as that of Jupiter.

Results show that there are more small planets than the large ones which indicates that small planets are dominant in the galaxy.

Earth-sized planets are common in the galaxy.

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After the collision the magnitude of the momentum of the system is Mv

Given:

mass of 1st object = M

speed of 1st object = v

mass of 2nd object = M

speed of 2nd object = 0

To Find:

magnitude of the momentum after collision

Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.

Applying conservation of linear momentum

Mv + M(0) = 2MV

Mv = 2MV

V = v/2

So, after collision momentum is

p = 2MV = 2xMxv/2 = Mv

So, after collision momentum is Mv

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Higher frequencies are present in more dramatic events and have thus been the first to be noticed, but the frequencies of ordinary gravitational waves are relatively low and considerably more difficult to detect.

A gamma-ray burst (GRB), which was discovered by the orbiting Fermi gamma-ray burst monitor on 2017 August 17 at 12:41:06 UTC, triggered an automatic notice throughout the world in addition to a merger of black holes. Six minutes later, a gravitational-wave observatory in Hanford, Washington, detected a gravitational-wave candidate that occurred 2 seconds before the gamma-ray explosion.

This collection of data supports the merger of two neutron stars, as shown by a multi-messenger transient event that was detected by gravitational waves as well as electromagnetic (gamma-ray burst, optical, and infrared) spectrum observations.

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The recommended range from which a temperature should be selected and maintained constantly to achieve targeted temperature manage is 32ºC-36ºC.

In most centers, the patient is actively cooled by using an induced hypothermia protocol for 24 hours to a goal temperature of 32ºC-36ºC. The goal is to achieve the target temperature as quickly as possible. In most cases, this can be achieved within 3-4 hours of initiating cooling.

Targeted temperature management (TTM), previously known as mild therapeutic hypothermia, in selected patients surviving out-of-hospital sudden cardiac arrest (OHCA) can significantly improve rates of long-term neurologically intact survival, [1] and it may prove to be one of the most important clinical advancements in the science of resuscitation.

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The radius is increasing at a rate of  0.31cm/sec.

We know the volume of the balloon is increasing at a rate of 3.3 [tex]ft^{3} min[/tex]

This is expressed as:

[tex]\frac{dV}{dT}[/tex] = 3.3

The volume of a sphere is given by:

V = [tex]\frac{4}{3}[/tex]π[tex]r^{3}[/tex]

The question asks to find the rate of which the radius is increasing when the radius is 0.65 feet.

We need to find:

[tex]\frac{dr}{dt}[/tex]

Since we don't have t in our equation, we will be differentiating implicitly. We can use the chain rule for this:

[tex]\frac{dV}{dT}[/tex] = [tex]\frac{dV}{dR}[/tex].[tex]\frac{dr}{dt}[/tex]

We already know  

[tex]\frac{dV}{dT}[/tex] = 3.3

∴

3.3 =  [tex]\frac{dV}{dR}[/tex].[tex]\frac{dr}{dt}[/tex]

To find [tex]\frac{dV}{dR}[/tex]  we differentiate  V = [tex]\frac{4}{3}[/tex]π[tex]r^{3}[/tex]

∴

3.3 = 4[tex]\frac{3.3}{5.30}[/tex][tex]r^{2}[/tex].[tex]\frac{dr}{dt}[/tex]

Dividing ,

[tex]\frac{3.3}{5.30}[/tex] = [tex]\frac{dr}{dt}[/tex] = 0.622 ft/min = 0.31 cm/sec

The radius is increasing at a rate of  0.31cm/sec.

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A stock tank heater rated at 1500 watts will use 1,29,600 kJ of energy in a 24 hour period.

Given :

We know that

Energy = Power x time

E = P * t

E = 1500 x 24 x 3600

E = 129600000 J ( or 129600 kJ)

Hence, a stock tank heater rated at 1500 watts will use 1,29,600 kJ of energy in a 24 hour period.

The formula that links energy and power is:

Energy = Power x Time.

The unit of energy is the joule, the unit of power is the watt, and the unit of time is the second.

If we know the power in watts of an appliance and how many seconds it is used we can calculate the number of joules of electrical energy which have been converted to sortie other form.

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As additional resistors are included lined up across a consistent voltage source, there are more ways for current to take.

So more current spills out of the source, and the all out current provided by the source increments.

The power supplied by the battery is (voltage) x (current).  So if the voltage is constant and the current increases, the power being supplied must also increase.

A resistor is an electrical part that cutoff points or manages the progression of electrical flow in an electronic circuit. Resistors can likewise be utilized to give a particular voltage to a functioning gadget like a semiconductor.

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The temperature corresponds to a length of 4cm is 80°C.

To find the answer, we need to know about the thermometers.

                          [tex]d=6cm-1cm=5cm[/tex]

                        [tex]1cm=\frac{100}{5}=20^0C[/tex]

                         [tex]T=4*20=80^0C[/tex]

Thus, we can conclude that the 4cm line corresponds to a temperature of 80°C.

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The fastest you could slow down before hitting a youngster who rushed into the road 60 to 65 feet in front of your car is 20 mph.

(Perception/Reaction Distance)

Speed 30 mph 40 mph 50 mph 60 mph 70 mph 80 mph

Distance 44 feet 59 feet 73 feet 88 feet 103 feet 117 feet

Braking Distance 45  feet 80  feet 125  feet 180  feet 245  feet 320 feet

Overall Stopping Distance 89 feet 139 feet 198 feet 268 feet 348 feet 439 feet

Equal to Approximate Number of Car Lengths 6 9 14 18 23 29

Take note that your total stopping distance triples when you double your speed, say from 30 mph to 60 mph or 40 mph to 80 mph.

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You could only brake down to 20 mph before hitting a child who dashed into the road 60 to 65 feet in front of your vehicle.

(Perception/Reaction Distance)

Speed 30, 40, 50, 60, 70, and 80 mph

Distance Braking Distance: 45 feet 80 feet 125 feet 180 feet 245 feet 320 feet 44 feet 59 feet 73 feet 88 feet 103 feet 117 feet

The total stopping distance is about equal to the number of car lengths: 89 feet, 139 feet, 198 feet, 268 feet, 348 feet, and 439 feet. 6 9 14 18 23 29

Be aware that as you double your speed, such as from 30 mph to 60 mph or 40 mph to 80 mph, your total stopping distance triples.

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Zinc metal (Zn) reacts with sulfur (S) to create zinc sulfide (ZnS), and the chemical reaction is: Zn (s) + S (s) = ZnS (s).

Importance of Zinc (Zn) and sulfur (S):

Chemical reaction -

In this experiment, heating a zinc(Zn) and sulfur(S) combination causes an interesting chemical reaction. A blinding flash of light, hot sparks, a hissing sound, and a cloud of white smoke in the shape of a mushroom are produced.

Therefore, the following chemical processes are taking place in the reaction: Zn (s) + S (s) = ZnS (s).

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Weight of the mass is the tension in the string if the turntable is held fixed, with the mass hanging from the pulley

Weight is a force that acts at all times on all objects near Earth. The Earth pulls on all objects with a force of gravity downward toward the center of the Earth. Weight (symbolized w ) is a quantity representing the force exerted on a particle or object by an acceleration field, particularly the gravitational field of the Earth at the surface.

The tension force is defined as the force that is transmitted through a rope, string or wire when pulled by forces acting from opposite sides. The tension force is directed over the length of the wire and pulls energy equally on the bodies at the ends.

The direction of tension is the pull which is given the name tension. Thus, the tension will point away from the mass in the direction of the string/rope. In case of the hanging mass, the string pulls it upwards, so the string/rope exerts an upper force on the mass and the tension will be in the upper side.

Tension will act opposite the the weight of the mass attached in order to maintain equilibrium .

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The unit of the quotient of inductance and resistance will be Henry and ohm

Inductance is the tendency of an electrical conductor to oppose a change in the electric current flowing through it. The flow of electric current creates a magnetic field around the conductor. The field strength depends on the magnitude of the current, and follows any changes in current.

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.

unit of quotient of inductance = henry (H)

unit of resistance = ohm

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In the the case above, if the consumption function is: C = $500 + 0.75 × YD, from the equation, the The marginal propensity to consume is option C) 0.75.

The marginal propensity to consume which is MPC is the aspect of each extra money that is dollar of a household's income that is said to be used, consumed or spent.

Note that Consumer behavior in regards to saving or spending has a very vital impact on the economy of a country.

From the formula given, the breakdown is:

YD = disposable income.

Autonomous consumption = $500.

The marginal propensity to consume  = 0.75.

Therefore, In the the case above, if the consumption function is: C = $500 + 0.75 × YD, from the equation, the The marginal propensity to consume is option C) 0.75.

See full question below

Suppose that the consumption function is: C = $500 + 0.75 × YD

(Scenario: Consumption Spending) The marginal propensity to consume is:

A) $500.

B) 0.

C) 0.75

D) 0.2.

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(1) The time taken by the cab to meet the bus is 18.96 seconds.

(2) The distance the cab has travelled to catch-up with the bus is 718.96 m.

The distance between the bus and the cab when the cab begins to move is calculated as follows;

D = speed x time

D = 30 m/s x 5 s

D = 150 m

The velocity of the cab when it begins to move is calculated as follows;

v = at

(v - 30)t = D

(at - 30)t = 150

(2t - 30)t = 150

2t² - 30t = 150

2t² - 30t - 150 = 0

solve the quadratic equation using formula method

t = 18.96 seconds

D =  vt

D = 2t²

D = 2(18.96²)

D = 718.96 m

Thus, the time taken by the cab to meet the bus is 18.96 seconds. The distance the cab has travelled to catch-up with the bus is 718.96 m.

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Answer:

2.59 ms^2

Explanation:

Radius, r= 17m

Velocity,v = 6.64m/s

Ac= V^2/r

Ac= (6.64)^2/17

Ac= 2.59 m/s^2

The wrong statement is that sound waves created vibration Option A.

Sound is a type of waves that moves in compressions and rare factions. This implies that sound is a mechanical wave. Recall that a mechanical wave is one that requires a material medium for propagation. Now we know that if we set the medium into vibration, that is when the sound waves begins to vibrate. That brings us to the idea that it is the vibration that causes the sound waves and not the sound waves that creates the vibration.

Thus, knowing that sound is a mechanical wave which moves through solids liquids and gas and that the vibration of the source of sound is what causes the air to vibrate, we conclude that the wrong statement is that sound waves created vibration Option A.

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Answer:

a

Explanation:

Answer:

The object with the greater mass will have the greater momentum

Explanation:

The momentum of an object with mass m, moving with velocity , is given by the formula

M = mv

Since both objects have the same velocity v, it is clear that the object with the bigger mass will have the greater momentum

9.87 seconds

The time required for this system to come to rest is equal to 9.87 seconds.

We have the following data:

Mass of gear A = 675 g to kg = 0.675 kg.

Radius of gear A = 40 mm to m = 0.04 m.

Mass of gear C = 3.6 kg.

Radius of gear C = 100 mm to m = 0.1 m.

How can I calculate the time needed?

We would need to figure out the moment of inertia for gears A and C in order to compute the time needed for this system to come to rest.

Mathematically, the following formula can be used to determine the moment of inertia for a gear:

I = mr²

Where:

m is the mass.

r is the radius.

We have, For gear A:

I = mr²

I = 0.675 × 0.04²

I = 0.675 × 0.0016

I = 1.08 × 10⁻³ kg·m².

We have, For gear C:

I = mr²

I = 3.6 × 0.1²

I = 3.6 × 0.01

I = 0.036 kg·m².

The initial angular velocity of gear C would therefore be converted as follows from rotations per minute (rpm) to radians per second (rad/s):

ωc₁ = 2000 × 2π/60

ωc₁ = 4000π/60

ωc₁ = 209.44 rad/s.

Also, the initial angular velocity of gears A and B is given by:

ωA₁ = ωB₁ = rc/rA × (ωc₁)

ωA₁ = ωB₁ = 0.15/0.06 × (209.44)

ωA₁ = ωB₁ = 2.5 × (209.44)

ωA₁ = ωB₁ = 523.60 rad/s.

Taking the moment about A, we have:

I_A·ωA₁ + rA∫F_{AC}dt - M(f)_A·t = 0

On Substituting the given parameters into the formula, we have;

(1.08 × 10⁻³)·(523.60) + 0.06∫F_{AC}dt - 0.15t = 0

0.15t - 0.06∫F_{AC}dt = 0.56549   ----->equation 1.

Similarly, the moment about B is given by:

0.15t - 0.06∫F_{BC}dt = 0.56549    ------>equation 2.

Note: Let x = ∫F_{BC}dt + ∫F_{AC}dt

Adding eqn. 1 & eqn. 2, we have:

0.3t - 0.06x = (0.56549) × 2

0.3t - 0.06x = 1.13098  ------>equation 3.

Taking the moment about A, we have:

Ic·ωc₁ - rC∫F_{AC}dt - rC∫F_{BC}dt - Mc(f)_A·t = 0

0.036(209.44) - 0.3t - 0.15(∫F_{BC}dt + ∫F_{AC}dt) = 0

0.3t + 0.15x = 7.5398    ------->equation 4.

Solving eqn. 3 and eqn. 4 simultaneously, we have:

x = 30.5 Ns.

Time, t = 9.87 seconds.

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The time taken by the light reflected from sun to reach on earth will be 8.4 minutes.

To find the answer, we need to know about the distance travelled by light.

         [tex]d=(1.5*10^8km)+2(3.8*10^5km)=1.51*10^8km=1.51*10^{11}m[/tex]

                      [tex]t=\frac{1.51*10^{11}}{3*10^8}=503.33 s\\t=\frac{503.33}{60}=8.4min[/tex]

Thus, the time it takes for the light from the Sun to reach Earth and be recognized as 8.4 minutes.

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The wavelengths of these signals is between  187.50m to 2.77 m.

Frequency describes the number of waves that skip a set region in a given quantity of time. There are two forms of frequency desk - Grouped Frequency Distribution and Ungrouped Frequency Distribution.

Wavelength is normally denoted with the aid of the Greek letter lambda (λ); it is identical to the velocity (v) of a wave train in a medium divided by means of its frequency (f)= λ = v/f.

Part A)

λ max = v / f

= 3 x 10^8 / 550x10^3 =545.45 m

λmin = 3 x 10^8 / 1600x10^3 = 187.50m

Part B)

λ max = v / f

= 3 x 10^8 / 88x10^6

 = 3.41 meters

λmin = 3 x 10^8 / 108x10^6 = 2.77 m

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A low partial pressure of oxygen promotes hemoglobin binding to carbon dioxide. This is an example of the  Haldane effect

The less saturated hemoglobin is and the lower the partial pressure of oxygen in the blood is, the more readily hemoglobin binds to carbon dioxide. This is an example of the Haldane effect.

The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.

The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.

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Only P-waves reach the side of Earth that is opposite the focus because P-waves option 4:  can travel through liquids and S-waves cannot.

A P wave is known to be a compressional wave. This is seen as  a kind of a seismic body wave that often moves or shakes the ground a lot in the same direction and also in its opposite direction as the  wave moving direction.

Note that the P waves can be able to move via liquid and solids and gases, but the S waves can only move through solids.

Hence, Only P-waves reach the side of Earth that is opposite the focus because P-waves option 4:  can travel through liquids and S-waves cannot.

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Answer:

Speed = distance traveled / time

Speed is a "scalar" quantity

Velocity = Vector Distance Traveled / time

Velocity is a vector quantity.

Example:

One can travel one lap around a track at some particular speed and his average speed will be (lap distance / time)

However, his vector velocity would be zero because he ended up where he started with zero displacement.

The angle of attack of airfoil with a 2m chord in an airstream with a velocity of 50m/s, and the lift per unit span is 1353n/m will be 4 degrees.

To find the answer, we have to know more about the dynamic pressure.

                        [tex]l=2m\\v=50m/s\\L=1353N/m\\d_{infinity}=1.233Kg/m^3[/tex]

                  [tex]P_d=\frac{1}{2} dv^2=\frac{1}{2}*1.233*50^2=1541.25 Pascals.[/tex]

                          [tex]k=\frac{L}{P*l} =\frac{1353}{1541.25*2}=0.438[/tex]

                                  [tex]\alpha =sin^{-1}(\frac{k}{2\pi } )\\\alpha =sin^{-1}(\frac{0.438}{2\pi } )\\\alpha =4.007 degrees.[/tex]

Thus, we can conclude that, the angle of attack of airfoil with a 2m chord in an airstream with a velocity of 50m/s, and the lift per unit span is 1353n/m will be 4 degrees.

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A car starts from rest and constantly accelerates at a rate of 10 [m/s2 ] during a 402 [m] race. At the finish line, the speed of the car is [tex]\mathbf{89}.\mathbf{6660}\ \mathbit{m}/\mathbit{s}[/tex].

The initial velocity of the car [tex]u = 0[/tex]

Constant acceleration [tex]a = 10~ m/s^2[/tex]

Distance of the Race [tex]d = 402~ m[/tex]

The car is accelerating with a constant acceleration [tex]a[/tex] , so the car's velocity will change with time as it approaches the finish point which is at a distance [tex]d[/tex] from the initial point.

Newton's equation is the backbone of Classical Mechanics. Let's say the velocity of the car at the finish line is [tex]v[/tex].  We know that displacement is the product of average velocity and time.

Or  [tex]s=\frac{u+v}{2}\times t[/tex]

Using Newton’s first equation [tex]v\ =\ u\ +\ at[/tex]

Newton's equation of motion turns out to be,

[tex]v^2 = u^2+2ad[/tex]

[tex]v^2 = 2\times 10 \times 402[/tex]

so, [tex]v = \sqrt{8040} = 89.6667 ~m/s[/tex]

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The Kinetic energy per unit volume appears in total energy equation of a flowing fluid, that does not appear in the total energy equation for a non-flowing fluid.

Kinetic Energy per unit volume is defined as the Kinetic energy of the flowing fluid per unit volume.

Bernoulli Equation is a equation that remains constant for a given fluid which comprises of Potential energy per volume, Kinetic energy per volume and Pressure.

It is given by:

P + ρgh + ρv²/2 = constant

where, P is the Pressure

            ρ is the density of fluid

            g is acceleration due to gravity

            h is the height

            v is the velocity

∴ ρgh is called as Potential energy per volume

∴ ρv²/2 is called as Kinetic energy per volume

In a Flowing Fluid:

In a Non-Flowing Fluid:

Hence, Kinetic Energy per unit volume does not appear in the total energy equation for a non-flowing fluid but appears in total energy equation for a flowing fluid.

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4.266 m is the radius of the circular path the electron follows.

Given

Speed of electron (v) = 7.5 × 10⁶ m/s

Earth's Magnetic Field (B) = 1 × 10⁻⁵ T

We already know that

Mass of electron (m) = 9.1 × 10⁻³¹ kg

Charge on electron (q) = 1.6 × 10⁻¹⁹ C

According to the formula

Radius of circular path(r) = mass on electron × speed/ Charge × Magnetic field

Radius of circular path(r) = m × v/q × B

Put the values into the formula

r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵

On solving, we get

r = 4.266 m

Hence, 4.266 m is the radius of the circular path the electron follows.

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The frequency of a photon is  1.06 * [tex]10^{18}[/tex] Hz.

The mass of a neutron is:

m = 1.67 * [tex]10^{-27}[/tex] kg

Since we know its speed, we can calculate the neutron's momentum:

p = mv = (1.67 * [tex]10^{-27}[/tex] kg)(1400 m/s) = 2.34 * [tex]10^{-24}[/tex] kg m /s

The problem says the photon has the same momentum of the neutron, p.  The photon momentum is given by

                                               p = h / λ              

where h is the Planck constant, and  λ  is the photon wavelength. If we re-arrange the equation and we use the momentum we found before, we can calculate the photon's wavelength:

p = h / λ =  [6.6 * [tex]10^{-34}[/tex] J/s]  /  [2.34 * [tex]10^{-24}[/tex] kg m /s ]

             = 2.82 * [tex]10^{-10}[/tex] m

And since we know the photon travels at speed of light c, we can now calculate the photon frequency:

f = c /  λ  =  [3 * [tex]10^{8}[/tex] m/s] / [ 2.82 * [tex]10^{-10}[/tex] m ]

              = 1.06 * [tex]10^{18}[/tex] Hz.

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The de Broglie wavelength of the particle is 1.578*10^-3nm.

To find the answer, we have to know about the de Broglie wavelength.

                          [tex]wavelength=\frac{h}{P} =\frac{h}{mv}[/tex]

where, h is the plank's constant, m is the mass and v is the velocity.

                               [tex]m=3.5*10^{-28}kg\\a=2.4*10^7m/s^2\\t=5s\\h=6.63*10^{-34}Js[/tex]

                           [tex]wavelength=\frac{6.63*10^{-34}}{3.5*10^{-28}*2.4*10^7*5}=1.578*10^{-14}m\\\\ wavelength=1.578*10^{-3}nm.[/tex]

Thus, we can conclude that, the de Broglie wavelength of the particle is 1.578*10^-3nm.

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