Find the distance between (-6, -12) and (4,8) using the distance formula.

Answer:

[tex]e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...[/tex]

[tex]\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n[/tex]

Step-by-step explanation:

Taylor series expansions of f(x) at the point x = a

[tex]\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...[/tex]

This expansion is valid only if [tex]\text{f}\:^{(n)}(a)[/tex] exists and is finite for all [tex]n \in \mathbb{N}[/tex], and for values of x for which the infinite series converges.

[tex]\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1[/tex]

[tex]\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...[/tex]

[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}[/tex]

[tex]\text{f}(x)=e^{4x} \implies \text{f}(1)=e^4[/tex]

[tex]\text{f}\:'(x)=4e^{4x} \implies \text{f}\:'(1)=4e^4[/tex]

[tex]\text{f}\:''(x)=16e^{4x} \implies \text{f}\:''(1)=16e^4[/tex]

Substituting the values in the series expansion gives:

[tex]e^{4x}=e^4+4e^4(x-1)+\dfrac{16e^4}{2}(x-1)^2+...[/tex]

Factoring out e⁴:

[tex]e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right][/tex]

Taylor Series summation notation:

[tex]\displaystyle \text{f}(x)=\sum^{\infty}_{n=0} \dfrac{\text{f}\:^{(n)}(a)}{n!}(x-a)^n[/tex]

Therefore:

[tex]\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n[/tex]

the surface area of the sphere is π/4 cm^3

It is important to know the formula for surface area and volume of a sphere

Surface area = [tex]\frac{4\pi }{r^2}[/tex]

Volume = [tex]\frac{4}{3} \pi r^3[/tex]

First, let's determine the value of radius, r

The value for volume was given as  256/3π cm3.

[tex]\frac{256}{3} \pi = \frac{4}{3} \pi r^3[/tex]

Pi cancels out and we have cross multiply to get the radius

[tex]256 * 3 = 4 * 3 r^3[/tex]

[tex]12r^3 = 768[/tex]

Make r the subject of the formula

[tex]r = \sqrt[3]{\frac{768}{12} }[/tex]

[tex]r = \sqrt[3]{64}[/tex]

r = 4

Let's substitute to find the surface area

Surface area = [tex]\frac{4\pi }{4^2}[/tex]

Surface area = π/4

Surface area = π/4 cm^3

Thus, the surface area of the sphere is π/4 cm^3

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The length of one edge of the cube exists 6 centimeters.

The lateral surface area of a cube exists

[tex]$A=4 a^{5}$[/tex]

where a stands the length of one edge of a cube.

It exists given that the lateral surface area of the square stands at 144 square centimeters.

Substitute A = 144 in the above formula.

[tex]$144=4 a^{2}[/tex]

Divide both sides by  4.

[tex]$36=a^{2}[/tex]

Taking square root on both sides.

[tex]$\sqrt{36}=\sqrt{a^{2}}[/tex]

6 = a

The length of one edge of the cube exists 6 centimeters.

Therefore, the correct answer is option c. 6 cm.

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Answer:

C

Step-by-step explanation:

Givens

r = 2 cm

h = 15 cm

pi = 3.14                                    The question does not expect a number for pi

Formula

V = (1/3) pi r^2 h                       Substitute givens into formula

Solution

V = 1/3 * pi * 2^2 * 15               Combine. Remember pi is left as it is

V = 1/3 * pi * 4 * 15                    

V = 1/3 pi * 60                         Divide 60 by 3

V = 20 pi

The correct unscrambling of whyrot is worthy.

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The vertex coefficient of the parabola with vertex (- 5, - 2) and the point (- 4, 2) is equal to 1.

In this question we must find the vertex coefficient of the equation of the parabola, which is the vertex form of the quadratic equation:

y - k = C · (x - h)²

If we know that (h, k) = (- 5, - 2) and (x, y) = (- 4, 2), then the vertex coefficient is:

2 - (- 2) = C · [- 4 - (- 2)]²

4 = C · (- 2)²

C = 1

The vertex coefficient of the parabola with vertex (- 5, - 2) and the point (- 4, 2) is equal to 1.

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Answer:

10,000

Step-by-step explanation:

Tbh this was pretty simple. If he makes twice the money as you, he pays twice as much too. Meaning he makes 40k a year and pays 10k for taxes

The result is [tex]5x-2y=-2[/tex].

Answer:

The mean absolute deviation (MAD) is 0

Step-by-step explanation:

20 + 16 + 21 + 16 + 22 + 16 + 15

= 126 ÷ 7 = 18

(20 - 18) + (16 - 18) + (21 - 18) + (16 - 18) + (22 - 18) + (16 - 18) + (15 - 18) =

2 +(-2) + 3 + (-2) + 4 + (-2) + (-3) = 0 ÷ 7= 0

The mean absolute deviation (MAD) is 0

Answer:

Option A is correct.

3x^2+6

Step-by-step explanation:

We have to find (f-g)(x):

We can write it f(x)-g(x), so substitute the values:

f(x)-g(x)=(4x^2+1)-(x^2-5)

=4x^2+1-x^2+5

=3x^2+6

Answer:

9

Step-by-step explanation:

We can tackle the individual parts and combine

1/5 of the sum of 9 and 6 means 1/5 * (9 + 6)

The quotient of 18 divided by the sum of 2 and 4 is 18 / (2 + 4)

Combing everything gives us (1/5 * (9 +6)) * (18 / (2 + 4)

(1/5 * 15) * 18/6

3 * 3 = 9

Answer:

8km  5mi

Step-by-step explanation:

20x400=8000meters a km = to 1000meters

8000/1000=8km

A mile is a kilometer/ 1.6  8/1.6=5 miles

Sanford ran approximately 8 kilometers and about 4.97 miles.

Given that a coach made someone run 20 laps on a 400 m track.

We need to find the number of mile he ran as well as number of kilometers he ran.

To find out how many kilometers Sanford ran, we can use the fact that 1 kilometer is equal to 1000 meters.

Similarly, to find out how many miles he ran, we'll use the conversion factor of 1 mile being equal to approximately 1609.34 meters.

Let's calculate it:

1 lap = 400 meters

20 laps = 20 x 400 = 8000 meters

Kilometers:

8000 meters ÷ 1000 meters/kilometer = 8 kilometers

Miles:

8000 meters ÷ 1609.34 meters/mile ≈ 4.97 miles

So, Sanford ran approximately 8 kilometers and about 4.97 miles.

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The company is considering the purchase of a new machine for $75,660 (based on the available data), and the payback period is 24 years.

The payback period is the time the company requires to recoup its investment for the new machine.

The payback period can be computed by dividing the investment cash outflows by the annual net cash inflows.

Initial investment in new machine = $75,660

Annual depreciation expense = $4,600

Investment period = 10 years

Annual sales revenue = $20,000

Annual expenses = $16,800

Ne annual cash inflow = $3,200 ($20,000 - $16,800)

Payback period = 24 years ($75,660/$3,200)

Thus, since the payback period is 24 years, while the investment period is 10 years, it sounds unwise for the company to continue the investment.

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Answer:

3 sqrt 5

Step-by-step explanation:

diameter talks about the center of the circle..and the middle of the circle lies between 3 and 5

Compounded continuously the balance grows at a continuous rate of 1.7%.

What is compound interest ?

The model used for continuous compounding is

 f(t) = Pe^(rt)

where P is the principal amount, and r is the interest rate being compounded. Assuming a typo in your given equation, you have

 f(t) = 1000·e^(0.017t)

Matching the various parts of the equation, we see that P = 1000 and r = 0.017 = 1.7%.

Therefore, the balance grows at a continuous rate of 1.7%.

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The slope-intercept form of given equation is y = 1/2x + 5/2.

According to the statement

we have given that the equation y-3 = 1/2(x-1) and the passing points are (–9, –2) and (1, 3).

And we have to find the slope-intercept form of the equation

slope-intercept form is the equation of a straight line in the form y = mx + b where m is the slope of the line and b is its y-intercept.

So, According to this

y-3 = 1/2(x-1)

convert this into y = mx +b form then

y-3 = 1/2x -1/2

here m is 1/2 and b is -1/2.

Then

y-3 = 1/2x -1/2

Add three on both sides then

y = 1/2x + 5/2

So, The slope-intercept form of given equation is y = 1/2x + 5/2.

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Answer:

its cccccccc

Step-by-step explanation:

Answer:

480

Step-by-step explanation:

Answer: If your opponent is winning 3:1 then they are probably better then you if they are winning more then you are. (or you are just having a bad day)

Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134

Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466

Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400

Let's denote the three possibilities as follows:

A: Equally talented, each player has a 0.5 probability of winning a game.

B: You are slightly better, with a 0.6 probability of winning a game.

C: Your opponent is slightly better, with a 0.6 probability of winning a game.

Given that you won the second game but lost the first, third, and fourth games, we want to find the probability of scenario C given this outcome. Let P(C) represent the prior probability of scenario C being true.

According to the given information, each of the three scenarios (A, B, and C) is equally likely, so P(A) = P(B) = P(C) = 1/3.

Now, let's update the probabilities based on the outcome of the match:

In scenario A:

The probability of winning the second game is 0.5, and the probability of losing the first, third, and fourth games is 0.5 each. Therefore, the overall probability of the observed outcome in scenario A is (0.5 * 0.5 * 0.5 * 0.5) = 0.0625.

In scenario B:

The probability of winning all three games (assuming you are slightly better) is (0.6 * 0.6 * 0.6) = 0.216.

In scenario C:

The probability of winning the second game (assuming your opponent is slightly better) is 0.4, and the probability of losing the first, third, and fourth games is 0.6 each. Therefore, the overall probability of the observed outcome in scenario C is (0.4 * 0.6 * 0.6 * 0.6) = 0.05184.

Now, we can update the probabilities based on Bayes' theorem:

Posterior probability of scenario A: P(A|data) = (P(data|A) * P(A)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

Posterior probability of scenario B: P(B|data) = (P(data|B) * P(B)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

Posterior probability of scenario C: P(C|data) = (P(data|C) * P(C)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

P(data|A) = 0.0625

P(data|B) = 0.216

P(data|C) = 0.05184

Plugging in the values, we get:

Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134

Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466

Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400

So, after the match, the posterior probability that your opponent is slightly better than you is approximately 0.400 or 40%.

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The probability of pulling a black or red card  = 3/10

Probability that a white card will be drawn, P(white) = 1/25

Probability that a blue card will be dealt, P(black)  = 1/5

Probability that a black card will be dealt, P(red) = 1/10

Probability that a pink card will be revealed, P(pink)  = 1/15

All of these occurrences are distinct from one another and do not relate to one another.

The likelihood that any one of any two events, A and B, with probability P(A) and P(B), will occur is:

                                        P( A ∪ B ) = P(A) + P(B)

Here, event A can be compared to getting a black card, and

incident B is comparable to receiving a red card.

So, P(black or red) = P(black) + P (red)

= (1/5) + (1/10)

= ( 2 + 1 )/10

= 3/10

So, the likelihood that a black or red card will be pulled from the hat:

= 3/10

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32 bottles are needed to poured 4 gallons of chocolate milk.

The correct option is D.

A closed surface's volume, which is expressed as a scalar quantity, measures how much three-dimensional space is enclosed. The area that a material or 3D object takes up or contains, for instance. The SI-derived cubic metre is a common unit for quantifying volume quantitatively.

Pints to Gallons Ratio: 1:8

Permit x bottles to be present.

There are x bottles required for 4 gallons of chocolate milk.

Because of the direct proportion

4/x = 1/8

x = 4 x 8

x = 32

As a result, 32 bottles are required.

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Answer:

range is 10

Step-by-step explanation:

highest number is 49

loweest number is 39

49 - 39 = 10

Answer:

10

Step-by-step explanation:

The range is found by taking the largest number and subtracting the smallest number

The largest number is 49

The smallest number is 39

The range is 49-39 = 10

Answer:

Number = 12

Step-by-step explanation:

2n-7=n+5 (+7 to both sides)

2n=n+12 (-n to both sides)

n=12

The equation of the line that passes through the points (-1, 2) and (6, 3) in slope-intercept form is,

[tex]y=\frac{x}{7} +\frac{15}{7}[/tex]

Given:  [tex](-1,2)[/tex] and [tex](6,3).[/tex]

The slope of the line passing through[tex](x1,y1)[/tex] [tex](x2,y2)[/tex] is [tex]\frac{y^{2} }{x^{2} } -\frac{y^{1} }{x^{1} }[/tex]

The slope of our line[tex]=\frac{(3-2)}{(6+1)} =\frac{1}{7}[/tex]

Slope intercept from the equation would be [tex]y= 1/7 x +C[/tex]

Find C:

Since [tex](-1,2)[/tex] lies on the line, substitute these in the line equation

[tex]2 = \frac{1}{7(-1)} +c[/tex]

[tex]C=2+\frac{1}{7} =\frac{15}{7}[/tex]

Therefore, the equation in slope intercept form is[tex]y=\frac{x}{7} +\frac{15}{7}[/tex]

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Answer:

5/52

Step-by-step explanation:

There are 52 cards in a deck, with 26 red and 26 black cards. There are 2 red ones, 2 black threes, and 1 six of hearts. The # of favorable outcomes is 2 + 2 + 1 = 5, so the answer is 5/52.

The expected payoff from rolling the die is 0 usd.

According to the given question.

A die is rolled.

So, the possiblbe outcomes for a dice = {1, 2, 3, 4, 5, 6}

⇒ Total number of outcomes = 6

Also, it is given that

If a die is roll to a 1 or 2, we win 2usd and if it rolls to 3, 4, 5, or 6 we lose 1 usd.

As, we know that "Probability denotes the possibility of the outcome of any random event". And probability of any event can be calculated as

P(E) = total number of favorable outcomes/ Total number of outcomes

So,

The probability that die rolls 1 or 2 = 1/6 + 1/6 = 2/6 = 1/3

And, the probability thet die rolls 3, 4, 5, or 6

= 1/6 +  1/6 + 1/6 + 1/6

= 4/6

= 2/3

Therefore, the excepted payoff from rolling this die

= [tex]2\times\frac{1}{3} - 1\times\frac{2}{3}[/tex]

[tex]= \frac{2}{3} - \frac{2}{3}[/tex]

= 0 usd

Hence, the expected payoff from rolling the die is 0 usd.

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The correct option regarding the outliers of the data-set is given by:

The greatest value, 78, is the only outlier.

The IQR for this problem is:

IQR = 37 - 13 = 24.

Hence the bounds for outliers are:

The options are:

Hence the correct option is that only 78 is an outlier.

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The probability that at least one of them will get scholarship is 0.93

The given parameters are:

P(Boy) = 0.75

P(Girl) = 0.72

The probability that at least one of them will get scholarship is calculated using

P = P(Boy only) or P(Girl only) or P(Both)

This is then calculated as:

P = 0.75 * (1 - 0.72) + 0.72 * (1 - 0.75) + 0.72 * 0.75

Evaluate the products

P = 0.21 + 0.18 + 0.54

Evaluate the sum

P = 0.93

Hence, the probability that at least one of them will get scholarship is 0.93

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The surface area of the cone exists as πr² + πrl

= (3.14)(6)² + (3.14)(6)(3)

= 169.56 cm²

Therefore, the surface area of the cone exists at 169.56 cm².

The surface of the cone consists of the lateral surface and the base area. So,

1. the lateral surface exists equal to πrs, where r exists the radius of the base and s exists the slant height of the cone.

2. the base area exists πr² (since the base exists a circle with radius r).

Then the surface area exists SA = πrs + πr²

The surface area of the cone exists as πr² + πrl

where "r" exists the radius, "l" exists the slant height

The radius of the cone exists at 6 cm

The slant height of the cone exists at 3 cm

To find the surface area of a cone

The surface area of a cone = πr² + πrl

= (3.14)(6)² + (3.14)(6)(3)

= 169.56 cm²

Therefore, the surface area of the cone exists at 169.56 cm².

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Answer:

2.571428

Step-by-step explanation:

The mean absolute deviation of a dataset is the average distance between each data point and the mean.