Drag the tiles to the correct boxes to compete the pairs. identify the types of chemical reactions occurring in the chemical equations. respiration photosynthesis combustion reaction of fossil fuels methane oxygen → water carbon dioxide heat arrowright glucose oxygen → carbon dioxide water energy arrowright water carbon dioxide sunlight → oxygen glucose arrowright

Answer:

19 hydrogen bonds

Explanation:

Between every thymine and adenine, there are 2 hydrogen bonds.

Between every guanine and cytosine, there are 3 hydrogen bonds.

Since there are 2 total thymines and adenines, they contribute 4 hydrogen bonds overall.

-----> 2 H bonds x 2 nucleotides = 4 H bonds

Since there are 5 total cytosines and guanines, they contribute 15 hydrogen bonds overall.

-----> 3 H bonds x 5 nucleotides = 15 H bonds

Therefore, there are 19 hydrogen bonds between the complementary strands.

The major product expected from the sequential reaction of cyclopentene with [tex]Br_{2} /H_{2} O[/tex] , followed by sodium hydroxide is cyclopentene epoxide.

The treatment of cyclopentene with  [tex]Br_{2} /H_{2} O[/tex]  which is known as bromine water is an electrophilic substitution reaction.

In the first step the bromine molecule and the water molecule reacts each other and leads to formation of the bromohydrines . After that bromohydrines  will break and we get halide anion i.e., bromine anion because bromine is more electronegativity and hydrin as a cation.

The cyclopentene will react with bromohydrin to give trans-2-bromopententanol and after reaction with base it give cyclopentane epoxide .

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There are 5 alpha and 5 beta particle  emit emission of thorium-232 nucleus into astatine-212.

A beta ray would be released from such an atomic nucleus during a radioactive decay process known as beta decay. The proton in the nucleus changes from a proton to a neutron throughout beta decay, and vice versa.

It is given that, The atomic mass of Th = 232

Atomic mass of astatine = 212

Atomic number of Th = 90.

Atomic number of  astatine = 85

Number of alpha particle = difference between atomic mass / 4

Number of alpha particle = 232-212 /4

Number of alpha particle = 20/4

Number of alpha particle = 5

Thus, the number of alpha particle will be 5.

Number of beta particle = difference between atomic number

Number of beta particle = 90-85

Number of beta particle = 5

Thus, the number of beta particle will be 5

Therefore, the number of alpha and beta particle will be 5 and 5.

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Chemical symbols that will complete the equation are 2NaCl + Br2

The balanced Chemical reaction is -

                                    [tex]2NaBr[/tex] + [tex]Cl_{2}[/tex] → [tex]2NaCl[/tex]  + [tex]Br_{2}[/tex]

Chlorine ([tex]Cl_{2}[/tex]) is more reactive than bromine([tex]Br_{2}[/tex]). So, chlorine  displaces  bromine  from its  compound.

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237.9 KJ/mol⁻¹ crystal-field splitting energy is found to absorb visible light.

The energy of the electron configuration in the ligand field less the energy of the electronic configuration in the isotropic field is known as the crystal field energy.

The core metal ion's d orbitals split into two groups with various energies in an octahedral complex. The energy of the electron transition, which is related to the wavelength of the emitted light, is equal to the energy of the crystal-field splitting.

Δ = E = ℎ c / λ

Where,

where ℎ is the Planck constant, 6.62*10⁻³⁴m²kg s⁻¹, and c is the speed of light, 3 x 10⁸m s⁻¹.

Δ = 6.62*10⁻³⁴m²kg s⁻¹ / 503 x 10⁻⁹

= 3.95 x 10⁻¹⁹

= 3.95 x 10⁻¹⁹

This value is the splitting energy per ion.

To convert it to J/mol, we should multiply it by Avogadro number,  6.022 x 10²³mol⁻¹

= 3.95 x 10⁻¹⁹ x 6.022 x 10²³mol⁻¹

= 237.9 KJ/mol⁻¹

Therefore, the crystal-field splitting energy is 237.9 KJ/mol⁻¹ .

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Answer:

Halogens are among the most active nonmetals due to their electron configuration and number of valence electrons.

Ammonium chloride is a white solid that breaks down when heated and produces ammonia and hydrogen chloride.

A reversible reaction is a reaction in which the conversion of reactants to products and products to reactants occur at the same time. In the above example, the chemical shows a reversible reaction because it moves both forward and backward direction. In reversible reaction, equal amount of reactant is converted into product and product into reactant.

So we can conclude that Ammonium chloride is a chemical that represents a reversible reaction.

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At constant temperature and pressure the gibbs free energy value is a measure of the spontaneity of a process.

At constant temperature and pressure the gibbs free energy value is zero and when gibbs free energy value is zero then the process is spontaneous . The meaning of spontaneous  is that the process is takes place smothly with any effect and itself .

The Gibbs free energy also known as Gibbs function , Gibbs energy or free enthapy . It is a quantity that is used to measure maximum amount of work done in a thermodynamic system when temperature and pressure is keep constant.

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The confocal microscope would you use to visualize a sample labeled with an antibody conjugated to a fluorescent tag.

Confocal microscopy, also known as laser light microscopy microscopy as well as confocal laser scanning microscopy, would be an optical imaging technique that employs a spatial aperture to block out-of-focus light during the image-formation process to increase the optical resolution as well as the contrast of a micrograph.

Confocal microscopy's fundamental tenet is that the lighting and detection lenses are concentrated at the same light scattering point, which would be traversed over the sample to create the entire image on the detector.

Therefore, The confocal microscope would you use to visualize a sample labeled with an antibody conjugated to a fluorescent tag.

Hence, option (a) will be correct answer.

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Answer:

[tex]\frac{g}{mL}[/tex]

Explanation:

You can determine the units in the final answer by identifying which of the units cancel out. Units are eliminated (cancelled out) when they are located both in the numerator and denominator of proportions being multiplied.

In this case, these units are cancelled out.....

-----> milligrams (mg) = (1st and 2nd proportions)

-----> decaliters (dL) = (1st and 3rd proportions)

-----> liters (L) = (3rd and 4th proportions)

As these units are not cancelled out, you are left with grams (g) in the numerator and milliliters (mL) in the denominator.

The final units should be represented by:

[tex]? \frac{g}{mL}[/tex]

Answer:

3 NaOH +  H₃PO₄ ----->  Na₃PO₄ + 3 H₂O

Explanation:

This appears to be a double-displacement reaction. In these reactions, the cation of one compound is swapped with the cation of another. Therefore, Na⁺ (from NaOH) is swapped with H⁺ (from H₃PO₄). When constructing the new compounds, you may need to alter the amount of each ion within a particular compound to to make it neutral.

New Product #1: Na₃PO₄

----------> Na⁺ and PO₄³⁻

----------> +1 + 1 + 1 + (-3) = 0

New Product #2: H₂O (or HOH)

----------> H⁺ and OH⁻

----------> +1 + (-1) = 0

Now that you know the products, you need to balance the chemical equation. An equation is balanced when there is an equal amount of each element on both sides. These amounts can be modified by adding coefficients.

The unbalanced equation:

NaOH + H₃PO₄ -----> Na₃PO₄ + H₂O

Reactants: 1 sodium, 5 oxygen, 4 hydrogen, 1 phosphorus

Products: 3 sodium, 5 oxygen, 2 hydrogen, 1 phosphorus

The balanced equation:

3 NaOH +  H₃PO₄ ----->  Na₃PO₄ + 3 H₂O

Reactants: 3 sodium, 7 oxygen, 6 hydrogen, 1 phosphorus

Products: 3 sodium, 7 oxygen, 6 hydrogen, 1 phosphorus

**I was having trouble balancing the equation with the reactant H₂PO₄⁻. From my experience, I believe this compound may have been mistyped. As such, I used H₃PO₄. Please let me know if the reactant was written properly**

Nitrogen fixation -

What is the organic form of nitrogen?

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The molar solubility of the substance is  1.2 × [tex]10^{-10}[/tex]  M if a substance x has a solubility of 2. 4 × [tex]10^{-5}[/tex]  mg/l, and a molar mass of 188 g/mol.

Calculation ,

The number of moles dissolve in one liter of solution is called molar solubility.

Given Solubility = 2.4 × [tex]10^{-5}[/tex] mg/L

Solubility = 2.4 × [tex]10^{-5}[/tex]  × [tex]10^{-3}[/tex]   g/L = 2.4 × [tex]10^{-8}[/tex]   g/L

Molar mass = 188 g/mol

Molar Solubility = 2.4 × [tex]10^{-8}[/tex]   g/L / 188 g/mol = 0.012 × [tex]10^{-8}[/tex]   mol/L

Molar Solubility = 1.2 × [tex]10^{-10}[/tex]  M

Therefore ,  the molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex]  M

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The mass of this ion is 1.16*10^-26kg.

To find the answer, we have to know about the force acting on a particle circulating in a uniform magnetic field.

                                  [tex]F_c=F_B\\\frac{mv^2}{r} =qvB\\[/tex]

                   [tex]m=\frac{qBr}{v} =\frac{2*1.67*10^{-19}*0.8*30*10^{-2}}{6.9*10^6} \\m=1.16*10^{-26}kg[/tex]

Thus, we can conclude that, the mass of this ion is 1.16*10^-26kg.

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0. 1-m  zinc sulfate - znso4 solution. is the solution acidic solution

Zinc sulfate is the inorganic compound with the formula ZnSO4 and historically known as "white vitriol". Zinc Sulfate is a prescription drug used to treat zinc deficiency. The body's healthy tissues grow and develop more quickly thanks to zinc sulfate.

Zinc sulfate inhalation can harm the respiratory system, bring on nausea, vomiting, stomach pain, disorientation, depression, and even death. Skin injury from exposure through skin contact can result in blisters, ulcers, and scars. In cases of mild to moderate acne, topical 5% zinc sulfate proved beneficial. In cases of moderate to severe acne, oral zinc gluconate and sulfate were helpful.

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There are 1157.14 milliliters of a 9. 0 M [tex]H_{2} SO_4}[/tex] solution are needed to make 0. 45 L of a 3. 5 M solution.

Calculation,

The formula for the dilution of a solution is given as:

[tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex]

Where M is molarity and V is the volume of the solution in liters ( L ).

Given data,

[tex]M_{1}[/tex] =  9. 0 M

[tex]V_{1}[/tex] = 0. 45 L

[tex]M_{2}[/tex] = 3. 5 M

[tex]V_{2}[/tex] = ?

9. 0 M ×0. 45 =  3. 5 M × [tex]V_{2}[/tex]

[tex]V_{2}[/tex] in Lit = 9. 0 M ×0. 45/ 3. 5 M = 1.15 L

[tex]V_{2}[/tex] in the ml = 1.15 × 1000ml = 1157.14 ml

Volume in milliliters is 1157.14 .

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A chemist reacted 0. 2 moles sodium benzoate with 0. 25 moles of hydrochloric acid. if she generated 22 g benzoic acid, the percent yield is 90%.

Reactant + HCl ------ Product

0.2 mol 0.25 22g

mol

Number of moles of reactant = 0.2mol

Molar mass of product = 122.12g

Number of moles of product = given mass/ molar mass

= 22g/ 122.12 g

= 0.180mol

Percent yield = (number of moles of product/ number of moles of reactant) × 100

= (0.180/0.2) × 100

= 90%

Thus we concluded that the percent yield of the given solution is 90%.

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Using the gas laws, the volume of nitrogen produced is 6.6 L.

We know that the product of a reaction is obtained from the balanced reaction equation. The reactants combine together to yield the products hence we have; N2 + 3H2 ----> 2NH3

We know that 1 mole of hydrogen occupies 22.4 L

x moles of hydrogen occupies 25500 L

x = 1 mole * 25500 L/ 22.4 L

x = 1138.4 moles

If 3 mole of hydrogen reacts with 1 mole of nitrogen

1138.4 moles  reacts with 1138.4 moles * 1 mole/ 3 moles = 379.5 moles

Mass of nitrogen = 379.5 moles * 28 g/mol = 10626 g

Now 3 moles of hydrogen produces 44.8 L of NH3

1138.4 moles  produces 1138.4 moles * 44.8 L/ 3 moles = 17000 L

Now;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 1 * 17000 * 848/5.5 * 273

V2 =9601 L

2) 2NH4NNO3(s) ---> 4H2O(g) + 2N2(g) + O2(g)

Number of moles = 12g/ 80 g/mol = 0.15 moles

Now;

2 moles of NH4NNO3 produced 2 moles of nitrogen hence 0.15 moles of N2 was produced.

1 mole of N2 occupies 22.4 L

0.15 moles of N2 occupies 0.15 moles  *  22.4 L/1 mole = 3.36 L

P1 = 760 torr

V1 = 3.36 L

T1 = 273 K

P2 = 745 torr

T2 = 527 degrees or 800 K

V2 = ?

V2 =  P1V1T2/P2T1

V2 =  760 *  3.36 * 527/745 * 273

V2 = 6.6 L

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Answer:1s2

Explanation:

The correct order of increasing dipole moment is as follows.

[tex]$B C l_{3} < B I F_{2} < B C l F_{2}$[/tex]

Thus, we can conclude that the correct order of increasing dipole moment is as follows.

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0.3147 concentration (in moles/l) of a saline (NaCl) solution will provide an isotonic eyedrop solution.

Isotonic eye drops

Because it might result in eye discomfort or tissue damage if it is not maintained, isotonicity is regarded as a crucial component of ophthalmic medicines. A few drops of blood are mixed with the test preparation before being examined and judged under a microscope at a magnification of 40. Isotonic solutions are those that have the same amount of water and other solutes in them as the cytoplasm of a cell. Since there is no net gain or loss of water, placing cells in an isotonic solution will not cause them to either shrink or swell.

We can calculate the osmotic pressure exerted by a solution using the following expression.

π = M . R . T

where,

π is the osmotic pressure

M is the molar concentration of the solution

R is the ideal gas constant

T is the absolute temperature

The absolute temperature is 37 + 273 = 310 K

π = M . R . T

8 = (X mol/L) . (0.082atm.L/mol.K) . 310 K = 0.3147 mol/L

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The major alkene  product that results when n,n-dimethylhexan-2-amine undergoes cope elimination is hexene or hex-1-ene.

The reaction in which an amine is oxidize to an intermediate called an N-oxide which , when heated , acts as base in an intramolecular elimination reaction. The oxidation of tertiary amine into N-oxide is called cope reaction.

This elimination gives the less substituted alkene along with more substituted alkene which is Zaitsev product.

Example: Cope elimination of  n,n-dimethylhexan-2-amine form hexene.

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The concentration in the next 3.9 years is obtained as 1.5 nM.

We know from first order kinetics that the relationship between the concentration and the time is exponential and leads to a straight line graph of the equation;

ln[A] = ln[A]o - kt

[A] = ?

[A]o = 419 nM

k =  1.45 yr¹

t  = 3.9 years

ln[A] = ln(419) - (1.45 * 3.9)

[A]  = e^ ln(419) - (1.45 * 3.9)

[A] = e^6.04 - 5.655

[A]  = 1.5 nM

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NaBH4 is blind + will reduce other functional groups.

Functional groups:

The aldehyde group in o-vanillin would be converted to alcohol if it had been added during step one (imine production). Because the carbon is not sufficiently nucleophilic, p-toluidine would not attack and imine would not form in the maximum yield.

Regardless of the other atoms in the molecule, a functional group is a collection of atoms that have specific chemical characteristics. Covalent bonds bind the atoms in a functional group to the other molecules in the molecule as well as to one another. Examples: Alcohol, Aldehyde, Ketone, Carboxylic acid, Halogens, Double & Triple covalent bonds.

A carbonyl in which the carbon atom is linked to at least one hydrogen atom is called an aldehyde. An R-group or a hydrogen atom could be the other group joined to the carbonyl. Aldehydes are a highly reactive form of carbonyl because of the tiny size of the hydrogen atom, which makes it relatively simple for other molecules to approach the partial positive charge on the carbonyl carbon. Aldehydes are adaptable reactants used in numerous different organic synthesis processes. Numerous aldehydes also have unique tastes and odors.

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For the sequential deprotonations of a polyprotic acid, the equilibrium constants will typically decrease with each successive ionization.

For explaining above statement let's take an example of polyprotic acid like phosphoric acid.

In the phospheric acid [tex]H_{3} PO_{4}[/tex], after deprotonation of one hydrogen results as [tex]H_{2} PO_{4}^{-}[/tex] and equilibrium constant as [tex]K_{1}[/tex] . [tex]H_{2} PO_{4}^{-}[/tex]  donate one hydrogen results as [tex]H_{} PO_{4}^{-2}[/tex] and equilibrium constant as [tex]K_{2}[/tex] . Similarly,  [tex]H_{} PO_{4}^{-2}[/tex]  donate one hydrogen results as [tex]PO_{4}^{-3}[/tex] and equilibrium constant as [tex]K_{3}[/tex] . The removing of hygen ion from nuetral molecule is easier than removal of hydrogen ion from ionic species So, the value of [tex]K_{1}[/tex] is greater than  [tex]K_{2}[/tex] and value of  [tex]K_{2}[/tex]  is greater than [tex]K_{3}[/tex].

So, the equilibrium constants of polyprotic acid will typically decrease with each successive ionization.

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The most likely reaction product when acetophenone was treated by one equivalent of LDA, followed by one equivalent of tert-butyl bromide.

The full form of LDA is the lithium diisopropyle amide. The enolates can acts as nucleophile in SN2 type reaction . Overall an alpha hydrogen is replaced with an alkyl group . This reaction is one of the more important for enolates because a carbon - carbon bond formed .

Example :  when acetophenone was treated by one equivalent of LDA, which is base and abstract alpha hydrogen followed by one equivalent of tert-butyl bromide which gives tert-butyl bromide which is alkyl and such reaction is called alkylation.

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400 BTU of wasted heat energy is present in the form of electricity.

So, when efficiency is 60%, energy is used 60% of the time and lost 40% of the time. Thus, according to question, the energy that is wasted is:

1000 BTUx (40/100) = 400 BTU

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A substance moving from an area of high concentration to an area in which it has a low concentration is moving btween two concentration gradient.

Diffusion can simply be defined as the movement of substances from a region of a high concentration to a region of lower concentration.

It is also the movement of substances from a region of a strong solution to a region of weak solution.

So therefore, a substance moving from an area of high concentration to an area in which it has a low concentration is moving btween two concentration gradient.

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The sensory neurons within the olfactory organ are stimulated by Chemicals in the air.

Sensory neurons are the neurons that take up the signal from the receptors to the Central Nervous system (CNS)

Olfactory organ is the organ which is capable to sense smell i.e. Olfaction.

The Chemicals present in the air stimulates the sensory neurons present withing the olfactory organ consisting of olfactory epithelium. The cilia present in the epithelium recognizes the chemical present.

The neurons form connections of neuron to the olfactory bulb.

It is a mass of tissue that is round in shape that comprises of several kinds of cells of neurons that are capable to sense smell. It is necessary to sense smell properly.

Odorants are the compound that consist of an odor which get detected by the sensory neurons to carry out olfaction. They activate olfactory receptors and send signals to olfactory bulb.

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A chemistry laboratory device is a clay triangle to support the crucible when heated to high temperatures. It consists of a three-sided triangle frame made of clay or ceramic material.

The heat can pass through the open sides and is evenly distributed throughout the crucible. Although the soil triangle is a common and commonly used piece of laboratory equipment, it is difficult to ascertain who actually invented it.

The design of the clay triangle probably changed over time as a result of diverse contributions from scientists and chemists working on building laboratory equipment. The soil triangle may not have had a clear beginning, as is the case with many scientific instruments, but it is considered an evolution in laboratory technology overall.

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