distance between −42 and −78

His body temperature in the evening is 102.6 °F

The given parameters are:

Temperature in the morning = 99.2°F.

Temperature increase = 3.4°F.

His body temperature in the evening is calculated as:

New = Temperature in the morning + Temperature increase

So, we have

New = 99.2°F +  3.4°F

Evaluate the sum

New = 102.6 °F

Hence, his body temperature in the evening is 102.6 °F

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The estimated standard error for the sample is 6

Given,

Sample size, n = 36

Sample variance, [tex]s^{2}[/tex] = 1296

Standard deviation, s = √1296

                                   = 36

Standard error, SE = [tex]\frac{s}{\sqrt{n} }[/tex]

                              = [tex]\frac{36}{\sqrt{36} }[/tex]

                              = [tex]\frac{36}{6}[/tex]

                              = 6

Concept

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Answer:

Step-by-step explanation:

Answer: 16.8°C

Correct match for the quadratic equation are:

A. {-4, 4}

B.  {-5, 5}

C.  {-8, 8}

D.  {-11, 11}

E.  {3,-3}

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.

2x² - 32 = 0

Adding thirty-two to both sides of the equation:

2x² = 32

Dividing between two on both sides of the equation:

x² = 322

x² = 16

Applying square root to eliminate the exponent:

x =  ±√16

x =  ±4

4x² - 100 = 0

Adding hundred to both sides of the equation:

4x² = 100

Dividing between four on both sides of the equation:

x² = 100/4

x² = 25

Applying square root to eliminate the exponent:

x = ±√25

x = ±5

x² - 55 = 9

Adding fifty-five to both sides of the equation:

x² = 9 + 55

x² = 64

Applying square root to eliminate the exponent:

x = ±√64

x =  ±8

x² - 140 = -19

Adding one- fourty to both sides of the equation:

x² = -19 + 140

x² = 121

Applying square root to eliminate the exponent:

x = ±√121

x = ±11

2x² - 18 = 0

Adding eighteen to both sides of the equation:

2x² = 18

Dividing between two on both sides of the equation:

x² = 182

x² = 9

Applying square root to eliminate the exponent:

x = ±√9

x = ±3

Correct match for the quadratic equation are: A. {-4, 4},B.  {-5, 5},

C. {-8, 8},D.  {-11, 11},E.  {3,-3}

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I understand that the question you are looking for is:

Match each quadratic equation with its solution set.

A. 2x2 - 32 = 0  {-8, 8}

B. 4x2 - 100 = 0  {-4, 4}

C. x2 - 55 = 9          {-5, 5}

D. x2 - 140 = -19         {-11, 11}

E. 2x2 - 18 = 0  {3,-3}

Answer:

x=1.08 (3SF)

Step-by-step explanation:

hope it helps!!!!

The factors of the trinomial are:

Options C and E

This is further explained below.

Generally, A trinomial is a kind of polynomial that is used in basic mathematics. It is composed of three components, also known as monomials.

In conclusion, The following expressions are the components of the trinomial: x - 7, x + 2

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Answer:

13. Two real solutions.

14. No real solutions.

Step-by-step explanation:

Given quadratic equations:

13. [tex]x^2+7x+10=0[/tex]

14. [tex]4x^2-3x+4=0[/tex]

[tex]{\large \textsf{Quadratic Formula: }} x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\ \Bigg{\|}\ \textsf{when }ax^2+bx+c=0[/tex]

What is the discriminant?

The discriminant (Δ) is b² - 4ac, which is under the square root in the quadratic formula. It is used to determine the number of real solutions (roots) of a quadratic:

13. x² + 7x + 10 = 0

[tex]\implies a=\textsf{1},b=\textsf{7},c=\textsf{10}[/tex]

Find the discriminant value.

[tex]\implies \Delta = b^2 - 4ac[/tex]

[tex]\implies \Delta=(7)^2 - 4(1)(10)[/tex]

[tex]\implies \Delta=49 - 40[/tex]

[tex]\implies \Delta=9[/tex]

As [tex]9[/tex] > 0, this quadratic has two real solutions.

14. 4x² - 3x + 4 = 0

[tex]\implies a=\textsf{4},b=\textsf{-3},c=\textsf{4}[/tex]

Find the discriminant value.

[tex]\implies \Delta = b^2 - 4ac[/tex]

[tex]\implies \Delta = (-3)^2 - 4(4)(4)[/tex]

[tex]\implies \Delta = 9 - 64[/tex]

[tex]\implies \Delta = -55[/tex]

As [tex]-55[/tex] < 0, this quadratic has no real solutions.

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Answer:

-4

Step-by-step explanation:

We are going to substitute 0 in for x and solve for y.  

-2(0)+ 8y = -32  Anything times zero is zero

0 + 8 y = -32  Anything plus zero is itself.

8y = -32 Divide both sides by 8

y = -4

First symmetrically cut the pentagon to get 5 pieces. (So that you will get the idea that this polygon is divided into 5 triangles)

Then find the area of one of the triangles:

Area of Triangle = [tex]\frac{1}{2} bh[/tex]

A = [tex]\frac{1}{2}[/tex] × 4 × 10

A = 20 m²

To find the area of the whole pentagon shape:

A = 20 × 5 = 100 m²

Hope it helps!

Answer:(a) 50% (b)5%

Step-by-step explanation:

For a, it's not really difficult  because the price of a jacket is 1/2 more than jeans. So it's 50%.

For b, it's similar to no. (a) because the price of the jean is 1/2 less than a jacket. So u need to divide 250 by 500 and u will get 0.5 so if u want to put in % u need to multiply with 10, so u will get 5%.

Answer:

Below in bold,

Step-by-step explanation:

a. There's is only one card that fits this description so

Probability = 1/52.

b. There are 2 black Kings so

Probability = 2/52 = 1/26.

c. There are 2 of these - 7 of diamonds and 7 of hearts

so

Probability = 2/52 = 1/26.

d.  There 13 diamonds and 13 hearts so

Probability = 26/52 = 1/2.

e.  There  26 black cards

Probability = 26/52 = 1/2.

Answer:

  (c)  2

Step-by-step explanation:

The dilation scale factor multiplies the distance from the center of dilation.

We are given that QA = 1.25, and that AA' = 1.25. By the segment sum theorem, we have ...

  QA' = QA +AA'

  QA' = 1.25 +1.25 = 2.50

The scale factor multiplies the original distance:

  QA' = k·QA . . . . . . . . . . where k is the dilation scale factor

  2.50 = k·1.25 . . . . . . . . using the known lengths

  2.50/1.25 = k = 2 . . . . divide by the coefficient of k

The scale factor is 2.

Answer:

m = F / a is the answer

Step-by-step explanation:

F = ma

m = F / a

Answer:

  (a)  (f +g)(x) = √(x-2) +√(x)

Step-by-step explanation:

The sum of two functions is the sum of their definitions.

  (f +g)(x) = f(x) +g(x)

  (f +g)(x) = √(x -2) +√(x)

Note: the radicals can only be combined if they can be reduced to a form that has the same expression under the radical. Here, that is not the case, so there is no way to simplify the sum.

Answer:

2, 0, 2, 3, 5

1, 2, 4, 0, 5

Step-by-step explanation:

(ax + b)(cx² + dx + e)

acx³ + adx² + aex + bcx² + bdx + be

2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0

4x³ + 6x² + 10x

a = 2

b = 0

c = 2

d = 3

e = 5

1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10

4x³ + 8x² + 10x + 10

a = 1

b = 2

c = 4

d = 0

e = 5

If Mary measures the angle of elevation from a point A, to be 10°. She then walks 100m directly towards the tower, and finds the angle of elevation from the new point B to be 20°, the height of the tower comes out to be 37 meters.

Given Information and Formula Used:

The angle of elevation of the tower from point A (a in figure) = 10°

The angle of elevation of the tower from point B (b in figure) = 20°

The distance AB (ab n figure) = 100m

In right triangle adc, tan 10° = cd / ad ....... (1)

In right triangle bdc, tan 20° = cd / bd ......... (2)

Here, cd is the height of the tower.

Let the distance bd be x, then the ad = x + 100

Substituting this value of of ad in equation (1), we get,

tan 10° = cd / (x+100)

x+100 = cd / tan 10°

x+100 = cd / 0.18

x+100 = 5.6 cd ....... (3)

From equation (2),

tan 20° = cd / x

x = cd / tan 20°

x = cd / 0.34

x = 2.9 cd

Putting this value of x in equation (3), we obtain the height cd (or CD) as,

2.9 cd + 100 = 5.6 cd

(5.6 - 2.9)cd = 100

2.7cd = 100

cd = 100/2.7

cd ≈ 37m (To the nearest tenth of a meter)

Therefore, the height of the tower is calculated to be 37 meters.

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Answer:

1. Given.

2. Alternate Interior Angles Theorem.

3. m<2 + m<7 = 180 by definition of supplementary angles. By definition of congruent angles, m<2 = m<4 and m<5 = m<7, therefore m<4 + m<5 = 180 by substitution property of equality. By definition of supplementary angles, <4 is supplementary to <5.

4. Converse of Consecutive Angles Theorem.

It is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

To find the domain and range:

Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

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The complete question is given below:

What are the domain and range of g of x equals the square root of the quantity x plus 4?

(A) D: [4, ∞) and R: [0, ∞)

(B) D: (–4, ∞) and R: (–∞, 0)

(C) D: [–4, ∞) and R: [0, ∞)

(D) D: (4, ∞) and R: (–∞, 0)

The probability of getting a reading between 1.50 and 2.25 is; 0.00546

We are given the following information in the question:

Mean; μ = 0 °C

Standard Deviation; σ = 1 °C

We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.

Formula for z-score is;

z = (x' - μ)/σ

P(Between 1.50 degrees and 2.25 degrees) is expressed as;

P(1.5 ≤ x ≤ 2.25)

= P((1.5 - 0)/1 ≤ z ≤ (2.25 - 0)/1))

= P(z ≤ 2.25) -  P(z < 1.5)

= 0.0546 = 5.46%

The graph that correctly describes this is the first graph

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The shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet

The given parameter is

Perimeter, P = 520 feet

Represent the shorter side with x and the longer side with y

One side of the garden is bordered by a river:

So the perimeter is:

P = 2x + y

Substitute P = 520

2x + y = 520

Make y the subject

y = 520 - 2x

The area is

A = xy

Substitute y = 520 - 2x in A = xy

A = x(520 - 2x)

Expand

A = 520x - 2x^2

Differentiate

A' = 520 - 4x

Set to 0

520 - 4x = 0

Rewrite as:

4x= 520

Divide by 4

x= 130

Substitute x= 130 in y = 520 - 2x

y = 520 - 2 *130

Evaluate

y = 260

The area is then calculated as:

A = xy

This gives

A = 130 * 260

Evaluate

A = 33800

Hence, the shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet

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Answer:

y=1

Step-by-step explanation:

Since you already found x,

We will only be needing one equation to find y..

I will take equation two: 3(2)+2y=8

Step Two: 6+2y=8 (then you minus 6 on each side)

Step Three: 2y=2 (divide)

y=1

Add 8 to both sides.

Add 7 and 8 to get 15.

Divide both sides by 3.

Divide 15 by 3 to get 5.

Subtract 9 from both sides.

Subtract 9 from −15 to get −24.

Divide both sides by 8.

Divide −24 entre 8 para obtener −3.

Swap the sides so that all the terms of the variables are on the left side.

Add 13 to both sides.

Add 8 and 13 to get 21.

Divide both sides by 3.

Divide 21 by 3 to get 7.

Subtract 22 from both sides.

Subtract 22 from 4 to get −18.

Divide both sides by 6.

Divide −18 entre 6 para obtener −3.

Swap the sides so that all the terms of the variables are on the left side.

Subtract 51 from both sides.

Subtract 51 from 84 to get 33.

Divide both sides by 11.

Divide 33 by 11 to get 3.

Solution 1 :-

>> 3k - 8 = 7

>> 3k = 7 + 8

>> 3k = 15

>> k = 15 / 3

>> k = 5

Solution 2 :-

>> 8b + 9 = -15

>> 8b = -15 - 9

>> 8b = -24

>> b = -24 / 8

>> b = -3

Solution 3 :-

>> 8 = 3x - 13

>> 3x = 13 + 8

>> 3x = 21

>> x = 21 / 3

>> x = 7

Solution 4 :-

>> 6p + 22 = 4

>> 6p = 4 - 22

>> 6p = -18

>> p = -18 / 6

>> p = -3

Solution 5 :-

>> 84 = 51 + 11c

>> 11c = 84 - 51

>> 11c = 33

>> c = 33 / 11

>> c = 3

[tex]1+\frac{1}{6}+\frac{1}{11}+\cdots=\sum^{\infty}_{n=1} \frac{1}{5n-4} \\ \\ \frac{1}{4}+\frac{1}{9}+\cdots=\sum^{\infty}_{n=1} \frac{1}{5n-1} \\ \\ S=\sum^{\infty}_{n=1} \left(\frac{1}{5n-4} -\frac{1}{5n-1} \right) \\ \\ =\frac{\pi}{5} \sqrt{\frac{1}{5} (5+2\sqrt{5})}[/tex]

Answer:

No real solutions.

Step-by-step explanation:

To solve this, we need to use Quadratic Formula.

Quadratic Formula:

[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ [/tex]

in the form of:

[tex]a {x}^{2} + bx + c[/tex]

Given information from the question, we can deduce:

a = -1

b = -2

c = 5

Let's substitute these values into the formula.

[tex]x = \frac{ - ( - 2) + - \sqrt{ {( - 2)}^{2} - 4( - 1)( -5)} }{2( - 1)} \\ = no \: real \: solutions[/tex]

if you punch these into the calculator.

Considering the angle of the arc, it is found that the value of x is of x = 12º.

It is twice the inside angle.

In this problem, the angle of the arc is of 102º, hence the inside angle is of 51º, which means that we can solve for x as follows:

4x + 3 = 51

4x = 48

x = 12º.

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[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies \begin{array}{llll} y+4=4(x-3)\implies y-(\stackrel{y_1}{-4})=\stackrel{m}{4}(x-\stackrel{x_1}{3})\\\\ ~\hfill (\stackrel{x_1}{3}~~,~~\stackrel{y_1}{-4}) \end{array}[/tex]

The data set in discuss which contains three points and two of the residuals are 7 and -3 would have its third residual as; -4.

According.tinthe task content, the data set in discuss has three points and consequently should have three residuals.

Additionally, two of the three residuals have been given and on this note, it follows that the third residual must have a value such that the algebraic sum of all residuals is 0.

Hence, we have; -3 + 7 +x = 0;

x = 3-7 = 4.

Ultimately, the third residual is; -4.

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100–pound earthling's weight on Saturn using the proportion is (B)

15/4 = 100/x.

To find the 100–pound earthling's weight on Saturn using the proportion:

Therefore, 100–a pound earthling's weight on Saturn using the proportion is (B) 15/4 = 100/x.

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The correct question is given below:
A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet Saturn. you could determine a 100–pound earthling's weight on Saturn using the proportion:

a. start fraction 15 over 4 end fraction = start fraction x over 100 end fraction

b. startfraction 15 over 4 endfraction = 100 over x endfraction

c. startfraction 4 over 15 endfraction = startfraction 100 over x endfraction

d. either a or c