creating holes in the sand to fill the varied buckets is an example of an inverse relationship

true or false

Answers

Answer 1

Answer:

True

Step-by-step explanation:

You are taking away sand from the ground and adding sand to the bucket. There is less sand on the ground and more in the bucket making it inverse.


Related Questions

Find the length of the radius of a circle with a center at –7 2i and a point on the circle at 33 11i.

Answers

The length of the radius of a circle exists 41 units.

How to estimate the length of  the radius of a circle?

Given: The center exists at -7+2i and a point in the circle at 33+11i.

The radius of the circle exists given by the following formula;

The radius of the circle [tex]$=\sqrt{x^{2}+y^{2}}$[/tex]

The center exists at -7 + 2i and a point in the circle at 33 + 11i.

[tex]$&x(33-(-7)), y(2 \mathrm{i}-11 \mathrm{i}) \\[/tex]

simplifying the equation, we get

[tex]$&\mathrm{x}(33+7), \mathrm{y}(-9 \mathrm{i}) \\[/tex]

[tex]$&\mathrm{x}(40), \mathrm{y}(-9(-1)) \\[/tex]

[tex]$&\mathrm{x}(33+7), \mathrm{y}(9)[/tex]

The center of the circle exists at [tex]$&\mathrm{x}(33+7), \mathrm{y}(9)[/tex].

The length of the radius of a circle exists,

Radius [tex]$}=\sqrt{x^{2}+y^{2}} \\[/tex]

substituting the values of x and y, we get

Radius[tex]$}=\sqrt{40^{2}+9^{2}} \\[/tex]

Radius [tex]$}=\sqrt{1600+81} \\[/tex]

Radius [tex]$=\sqrt{1681} \\[/tex]

Radius = 41 unit

Therefore, the length of the radius of a circle exists 41 unit.

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Tina wrote a check for $35 on Monday. On Tuesday she made of withdrawal of $60 and on
Wednesday she deposited $75. What is the change in Tina's account after the three days?

Answers

The change in Tina's account after the three days; Monday, Tuesday and Wednesday is $-25

Deposit and withdrawal

Deposit is a sum of money or other asset given as an initial payment, to show good faith, or to reserve something for purchase.

Withdrawal on the other hand, is to extract money from an account.

Check = $35Withdrawal = $60Deposit = $75

Change in Tina's account after the three days = - 35 - 60 + 75

= -95 + 75

= $-20

Therefore, the change in Tina's account after the three days; Monday, Tuesday and Wednesday is $-25.

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Write an expression containing x2-terms, x-terms and constants. The
x2-terms should combine to −2x2 the x-terms should sum to 3x,
and the constants should sum to 3.

Answers

[tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression

Like terms are terms whose variables (and their exponents such as the 2 in [tex]x^{2}[/tex]) are the same. Like terms can easily be added and substracted. Such questions just need like terms to be bought together and simplified

Infinite number of equations or expressions can be written for the given question. So writing one possibility for the given question,

= [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex]

which sums up to

= [tex]-2x^{2} +3x+3[/tex]

Thus [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression

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The store has a 30% discount on every item in stock. how much is the 5% sales tax reduced on an item that regularly sells for $10?


i need help on this question

Answers

For the sale of a $ 10 item with a discount of 30 % has a sales tax of $ 0.35.

How much money should we pay in sales tax?

In this question we must determine the amount of money needed to pay in taxes by the purchase of an item with a discount. Sales taxes are an example of indirect taxes, this kind of indirect tax is usually calculated on the basis of total costs, including discounts. The amount of money need for the sales tax is described below:

t = (r / 100) · (1 - d / 100) · c     (1)

Where:

d - Discount rater - Sales tax ratec - Item pricet - Sales tax total

If we know that d = 30, r = 5 and c = 10, then the sales tax total is:

t = (5/ 100) · (1 - 30 / 100) · 10

t = 0.35

For the sale of a $ 10 item with a discount of 30 % has a sales tax of $ 0.35.

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divide $800 between kofi and kweku so that kofi gets three times what kweku gets

Answers

Answer:

600 and 200

Step-by-step explanation:

kofi  : kweku     is   3 :1

   so Kofi gets   3 out of ( 3 +1)  = 3/4 of 800  = 3/4 * 800 = 600

         kweku get s the rest   800- 600 = 200  

help me with this.
Calculate angles in a triangle

Answers

Step-by-step explanation:

Total Angle in a triangle is 180°

so D = 140 + 25 = 165°

D = 190° - 165° = 15°

Your answer is 15°.

Answer:

angle d = [tex]\boxed{15}^ {\circ}[/tex]

Step-by-step explanation:

The angles in a triangle add up to 180°.

∴ ∠d + 25° + 140° = 180°

⇒ ∠d + 165° = 180°

⇒ ∠d = 180° - 165°

⇒ ∠d = 15°

graph: g(x)=5cos((\pi )/(2)x-(3\pi )/(2))-2

Answers

[tex]g(x)=5cos((\pi )/(2)x-(3\pi )/(2))-2[/tex]

generate by:  Amplitude:5    Period:4

                      Phase shift:(3 to the right)    Vertical shift:-2

x=3,g(x)= 3

x=4,g(x)= -2

x=5,g(x)= -5

x=6,g(x)= -2

x=7,g(x)= 3

the graph is like cos(x)

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exponential growth and decay real-world word problems

Answers

The examples of exponential growth include bacteria population growth and compound interest and a real life example of exponential decay is radioactive decay.

What is exponential growth?

Exponential growth is the pattern of data that shows sharper increases over time. Savings accounts with a compounding interest rate can show exponential growth.

There are many real-life examples of exponential decay. An example, is thatsuppose that the population of a city was 100,000 in 1980. Then every year after that, the population has decreased by 3% as a result of heavy pollution. This is an example of exponential decay.

One of the best examples of exponential growth is the observed in bacteria. It takes bacteria roughly an hour to be able to reproduce through prokaryotic fission. In this case, if we placed 100 bacteria in an environment and recorded the population size each hour, we would observe an exponential growth.

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What is a31 of the
arithmetic sequence for
which a5 = 12.4 and
ag = : 22.4?

Answers

The value of a₃₁ of the arithmetic sequence exists 77.4.

How to find the value of a₃₁ of the arithmetic sequence?

Given: a₅ = 12.4 and a₉ = : 22.4

For the arithmetic sequence a₁, a₂, a₃, ..., the n-th term exists

where d = common difference

a₅ = 12.4,

a₁ + 4d = 12.4 .........(1)

Because a₉ = 22.4,

a₁ + 8d = 22.4 .........(2)

Subtract (1) from (2), we get

a₁ + 8d - (a₁ + 4d) = 22.4 - 12.4

4d = 10

Dividing throughout by 4, we get

d = 2.5

From (1), we get

a₁ = 12.4 - 4 [tex]*[/tex] 2.5 = 2.4

a₃₁ = 2.4 + 30 [tex]*[/tex] 2.5 = 77.4

Therefore, the correct answer is a₃₁ = 77.4

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50 pupils in a sports centre are surveyed. the pupils can only use the swimming pool and the gym. 31 pupils use the swimming pool. 28 pupils use the gym. 7 pupils use neither the swimming pool nor the gym. find the probability to select a pupil that uses the swimming pool but not the gym.

Answers

Using it's concept, it is found that there is a 0.3 = 30% probability to select a pupil that uses the swimming pool but not the gym.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that 50 - 7 = 43 pupils use at least one of the pool or the gym.

We use the following relation, considering the numbers of each:

Both = Pool + Gym - At least one

Hence:

Both = 31 + 28 - 43 = 16.

From this, we have that out of 50 pupils, there are 31 - 16 = 15 pupils who use the pool but not the gym, hence the probability is:

p = 15/50 = 0.3 = 30%.

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The first quartile of the dataset {1, 2, 3, 4, 5, 6} is _______. (give your answer as a whole number.

Answers

The first quartile of the dataset {1, 2, 3, 4, 5, 6} is 2.

Given data set: {1,2,3,4,5,6}

Median of the given data set =3.5

The data set can be split into 2 parts as, {1,2,3} and {4,5,6}. The first quartile is calculated by simply finding the median of the first part of the data set.

Thus, the first quartile is 2.

The quarter divides the distribution into four groups and calculates the range of values above and below the mean.

A quartile separates the dataset into four categories by dividing the data into three points: the lowest, median, and upper quartiles.

The interquartile range, a measurement of variation around the median, is calculated using quartiles.

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HELP PLS WHAT IS X
Darn

Answers

Answer:

x = 55°

Step-by-step explanation:

x , 35° , 90° lie on a straight line and sum to 180° , that is

x + 35° + 90° = 180°

x + 125° = 180° ( subtract 125° from both sides )

x = 55°

Please help and explain.

Answers

Answer:

B

Step-by-step explanation:

It's B

Answer:

Option B

Step-by-step explanation:

The equation is:

[tex]y=10-2x[/tex]

when x=2

[tex]y=10-2(2)010-4=6[/tex]

When x = 3

[tex]y=10-2(3)=10-6=4[/tex]

When x=4

[tex]y=10-2(4)=10-8=2[/tex]

Hope this helps

What is the area of the triangle shown below?

Answers

Answer: the area of the triangle is 5.

Step-by-step explanation:

[tex]A(0;0) \ \ \ \ B(1;3) \ \ \ \ C(4;2) \ \ \ \ S_{ABC}=?\\Use \ the\ formula:\\\displaystyle\\\boxed{S=\frac{1}{2}*|[(x_A-x_C)*(y_B-y_C)-(x_B-x_C)*(y_A-y_c)] |}\\x_A=0\ \ \ \ x_B=1\ \ \ \ x_C=4\ \ \ \ y_A=0\ \ \ \ \ y_B=3\ \ \ \ \ y_C=2.\\S=\frac{1}{2}*|[(0-4)*(3-2)-(1-4)*(0-2)]|\\S=\frac{1}{2}*| [(-4)*1-(-3)*(-2)]|=\\ S=\frac{1}{2}*| (-4-6)|\\S=\frac{1}{2}*|(-10)|\\S= \frac{1}{2} *10\\S=5.[/tex]

No matter what the value of s, 1s? is equal to the
value of s.

Answers

The complete statement is no matter what the value of s, √s² is equal to the absolute value of s?

How to complete the blank?

The statement is given as:

No matter what the value of s, √s² is equal to the ______ value of s?

The above statement can be split as follows:

No matter what the value of s, √s² is equal to the ______ value of s?

This means that, irrespective of the value of s, what would be the value of the square root of the square of s.

Assume that s is negative (say s = -2), the value of the square root of the square of s would be

√s² = √(-2)²

Evaluate the square

√s² = √4

Evaluate the square root

√s² = 2

See that s = 2 is the positive equivalent or absolute value of s = -2

Now, assume that s is positive (say s = 4), the value of the square root of the square of s would be

√s² = √4²

Evaluate the square

√s² = √16

Evaluate the square root

√s² = 4

See that s = 4 is the positive equivalent or absolute value of s = 4

Hence, the complete statement is no matter what the value of s, √s² is equal to the absolute value of s?

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Complete question

No matter what the value of s, √s² is equal to the ______ value of s?

A regular octagon has side lengths of 8 centimeters. what is the approximate area of the octagon?

Answers

Answer:309

Step-by-step explanation:

Figure A is a scalr image of figur B. Figure A maps to Figure B with scale factor of 2/3. what is tge value of x?​

Answers

Answer:

7

Step-by-step explanation:

You take the corresponding side that you know which is 10.5 and you multiply that by your scale factor of 2/3.

Another name for 10.5 is 10 [tex]\frac{1}{2}[/tex]  and that can be changed to [tex]\frac{21}{2}[/tex]

([tex]\frac{21}{2}[/tex])([tex]\frac{2}{3}[/tex])  The two's cancel out and we are left with [tex]\frac{21}{3}[/tex]  Which is the same as 7.

Estimate √50 to the hundredths place.

Answers

Answer:

7.07

Step-by-step explanation:

Answer:

7.07

Step-by-step explanation:

Hello!

Let's find two perfect square numbers that are directly before and after 50.

[tex]\sqrt{49} < \sqrt{50} < \sqrt{64}[/tex][tex]7 < \sqrt{50} < 8[/tex]

Since the square of 7 is the closest, we can use that as our whole number.

To find the decimal...

49 is 1 away from 50, and 64 is 14 away. Rewriting it as a fraction and we get  [tex]\frac{1}{14}[/tex].  The decimal is 0.07142857142.

Now, put 7 and 0.07142857142 together and we get 7.07142857142. Rounding that, we get 7.07.

The real value of Root 50 is 7.071067811865475, so the decimals were really close.

A boat heading out to sea starts out at Point A, at a horizontal distance of 1315 feet from a lighthouse/the shore. From that point, the boat’s crew measures the angle of elevation to the lighthouse’s beacon-light from that point to be 12^{\circ}. At some later time, the crew measures the angle of elevation from point B to be 8^{\circ}. Find the distance from point A to point B. Round your answer to the nearest foot if necessary.

Answers

Bearing is a topic that deals with distance and measure of the angle in locating the position of an object. The distance required in the question is 692 feet.

Bearing is a topic that relates the distance and measure of an angle so as to determine the accurate position of a given object. The angle with respect to the object is measured clockwise with respect to the North pole.

From the first part of the question, the height of the lighthouse, h, can be determined by applying the trigonometric function. So that;

Tan θ = [tex]\frac{Opposite}{Adjacent}[/tex]

Tan 12 = [tex]\frac{h}{1315}[/tex]

h = Tan 12 x 1315

  = 279.51

Thus the height of the lighthouse is approximately 280 feet.

Thus, let the distance between points A and B be represented by l. This implies that the distance from point B to the lighthouse is (l + 1315) ft.

So that;

Tan θ = [tex]\frac{Opposite}{Adjacent}[/tex]

Tan 8 = [tex]\frac{280}{(l+1315)}[/tex]

Tan 8 x (l + 1315) =  280

0.141l + 185.415 = 280

0.141 l = 280 - 185.415

          = 97.585

l = [tex]\frac{97.585}{0.141}[/tex]

 = 692.092

l = 692 feet

Therefore, the distance between points A and B is 692 feet.

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A newspaper started an online version of its paper 14 years ago. In a recent presentation to stockholders, the lead marketing executive states that the revenues for online ads have more than doubled that of the revenues for printed ads since starting the online version of the paper. Use the graph below to justify the lead executive’s statement and to determine the approximate year that the two ad revenues were equal.

Answers

The approximate year at which two revenues were equal is; 7.5 years

How to interpret Revenue Graphs?

From the graph attached, we see that in the year 10, the revenue for printed ads was 2 million dollars & 3 million dollars for printed ads and online ads revenue respectively.

Thus, printed ad. Revenue line equation is;

(y - 2) = (3 - 2)(x - 10)/(0 - 10)

y - 2 = (x - 10)/-10

x - 10 = -10(y - 2)

x - 10 = -10y + 20

x - 10 = -10y + 20

x  + 10y = 30   -----(1)

At x = 12 years from the graph, we have;

12 + 10y = 30

10y = 18

y = 1.8

Thus, online ad. Revenue line equation is;

(y - 0) = ((3 - 0)/(10 - 0))(x - 0)

y = 3x/10

10y = 3x

10y - 3x = 0 -----(2)

At x = 12, we have;

10y = 3*12

10y = 36

y = 3.6

In year '12' the online ad revenue got doubled as that of printed ad revenue and afterward more than doubled.

B) The approximate year at which two revenues were equal is gotten by solving equation 1 and 2 simultaneously to get;

x = 7.5

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Victor spent 1/2 of his salary on rent, 1/4 of the remainder on food and saved \mbox{Sh 1500). How much was his salary?​

Answers

Nag basa nito walang jõwa

Find the quotient.
18.)97.2

Answers

Answer:

540

Step-by-step explanation:

540 =18% of 97.2

Done please

it's quotient it's a synthax error..

I really need help ASAP! thx

Let f(z)=z-8 and g(z)=4z-9
Find (f+g)(2)

Answers

Answer:

  (f +g)(2) = -7

Step-by-step explanation:

Functions are added by adding their values.

Application

  (f +g)(2) = f(2) +g(2)

  = (2 -8) +(4(2) -9) . . . . . evaluate f and g with z=2

  = -6 +(-1)

  (f +g)(2) = -7

What is the slope?
What is the slope?
What is the slope?
What is the slope?
What is the slope?

Answers

Answer:

okay it's name is Muhammad Deco alfansia ( ◜‿◝ )

Answer:

Slope, sometimes referred to as gradient in mathematics, is a number that measures the steepness and direction of a line, or a section of a line connecting.

Step-by-step explanation: Hope this helps you!

suppose sin(A)=-0.78. use the trig identity sin^2(A)+cos^2(A)=1 and the trig identity tan(A) = sin(A)/cos(A) to find tan(A) in quadrant IV. round to the ten-thousandth.

a. -0.2039
b. 1.3941
c. 0.8671
d. -1.2464

Answers

In quadrant IV, [tex]\cos(A)[/tex] is positive. So

[tex]\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = \sqrt{1-\sin^2(A)} \approx 0.6258[/tex]

Then by the definition of tangent,

[tex]\tan(A) = \dfrac{\sin(A)}{\cos(A)} \approx \dfrac{-0.78}{0.6258} \approx \boxed{-1.2465}[/tex]

If p(x) = x² - 1 and g(x)= 5(x-1), which expression is equivalent to (p - q)(x)?
A.5(x-1)-x²-1
B.(5x-1)-(x² - 1)
C.(x²-1)-5(x - 1)
D.(x²-1)-5x - 1

Answers

The expression which is equivalent to the required expression (p - q)(x) is; Choice C; (x²-1)-5(x - 1).

Which expression is equivalent to (p - q)(x) given that p(x) = x² - 1 and g(x)= 5(x-1)?

It follows from the task content that the premise functions as given in the task content are;

p(x) = x² - 1

g(x)= 5(x-1).

Consequently, the required expression for the function operations; (p - q)(x) is simply;

p(x) - q(x) and is equivalent to;

(x² - 1) - 5(x - 1)

Therefore, the expression which is equivalent to the required expression (p - q)(x) is Choice C; (x²-1)-5(x - 1).

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QP=
Help please thanks so much

Answers

Answer:

QP = | a - d |

Step-by-step explanation:

since the y- coordinates of P and Q are equal , both b

then PQ is the absolute value of the difference of the x- coordinates, that is

QP = | a - d | = | d - a |

A construction worker is pouring concrete stairs. The first step requires 1.7 cubic feet of concrete, and the first 4 steps require a total of 17 cubic feet. If the steps follow an arithmetic series, how much concrete is required for the first 12 steps

Answers

Based on the given parameters of a = 1.7 cubic feet and concrete for first 4 steps as 17 cubic feet, the concrete is required for the first 12 steps is 132.6 cubic feet

Arithmetic progression

First term, a = 1.7 cubic feetSum of first four terms = 17 cubic feet

Sn = n/2 {2a + (n - 1) d}

17 = 4/2{2×1.7 + (4 - 1)d}

17 = 2{3.4 + (3)d}

17 = 2(3.4 + 3d)

17 = 6.8 + 6d

17 - 6.8 = 6d

10.2 = 6d

d = 10.2/6

Common difference, d = 1.7

Concrete required for first 12 steps;

Sn = n/2 {2a + (n - 1) d}

= 12/2{2×1.7 + (12-1)1.7}

= 6{3.4 + (11) 1.7}

= 6(3.4 + 18.7)

= 6(22.1)

= 132.6

Concrete required for first 12 steps = 132.6 cubic feet

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Answer:

132.6 cubic feet

Step-by-step explanation:

Line segment st is dilated to create line segment s't' using the dilation rule dq,2.25. point q is the center of dilation. line segment s t is dilated to create line segment s prime t prime. the length of q t is 1.2 and the length of q s is 2. the length of s s prime is x and the length of t t prime is 1.5. what is x, the distance between points s' and s?

Answers

The distance between points S' and S is 2.5 units.

What is proportionality theorem in triangles?

If a line is drawn parallel to any one side of a triangle so that it intersects the other two sides in two distinct points, then the other two sides of the triangle are divided in the same ratio.

Given that,

line segment ST is dilated to create line segment S'T' using the dilation rule DQ.

Also, SQ = 2 units, TQ = 1.2 units, TT'=1.5 units, SS' = x units.

We need to find the value of x, the distance between points S' and S.

Since the line ST is dilated to S'T' with center of dilation Q, so the triangles STQ and S'T'Q must be similar.

We know that the corresponding sides of two similar triangles are proportional.

So, from ΔSTQ and ΔS'T'Q, we get

[tex]\frac{SQ}{S'Q} =\frac{TQ}{T'Q}[/tex]

[tex]\frac{SQ}{SQ+S'S} =\frac{TQ}{TQ+T'Q}[/tex]

[tex]\frac{2}{2+x} =\frac{1.2}{1.2+1.5}[/tex]

[tex]\frac{2}{2+x} =\frac{1.2}{2.7}[/tex]

[tex]\frac{2}{2+x} =\frac{12}{27}[/tex]

[tex]\frac{1}{2+x} =\frac{6}{27}[/tex]

12+6x = 27

6x = 15

x = 2.5

Hence, Thus, the required value of x is 2.5 units.

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5 yd
5 yd
8 yd
5 yd
14 yd
3 yd
9 yd
6 yd
Pleasee help rn

Answers

What are you asking for? Conversions? or a statistical analysis (i.e. mean, median, etc.)?
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(3-4 sentences) Dontrell has asked Elolse to teach him about woodworking. Eloise and Dontrell work together on a project, and Elolse explains each step as thecomplete it. This is an example of what type of social learning? The reaction na 3po 4( aq) 3 agno3( aq) ag 3po 4( s) 3 nano 3( aq) is best classified as a(n):_____. What is the first action you should take if you witness someone being verbally abused? Find the measures of angles a and b when 0=47 Ramiya is using the quadratic formula to solve a quadratic equation. her equation is x = startfraction negative 3 plus or minus startroot 3 squared minus 4(1)(2) endroot over 2(1) endfraction after substituting the values of a, b, and c into the formula. which is ramiyas quadratic equation? Home depots return to a customer service culture included recognitions, bonuses, and buttons for employees orange aprons. hd advanced a culture change by:________ Casey at the Batby Ernest Lawrence ThayerA Ballad of the Republic, Sung in the Year 1888The outlook wasnt brilliant for the Mudville nine that day;The score stood four to two with but one inning more to play.And then when Cooney died at first, and Barrows did the same,A sickly silence fell upon the patrons of the game.A straggling few got up to go in deep despair. The restClung to that hope which springs eternal in the human breast;They thought if only Casey could but get a whack at thatWed put up even money now with Casey at the bat.But Flynn preceded Casey, as did also Jimmy Blake,And the former was a lulu and the latter was a cake;So upon that stricken multitude grim melancholy sat,For there seemed but little chance of Caseys getting to the bat.But Flynn let drive a single, to the wonderment of all,And Blake, the much despised, tore the cover off the ball;And when the dust had lifted, and men saw what had occurred,There was Jimmy safe at second and Flynn a-hugging third.Then from 5,000 throats and more there rose a lusty yell;It rumbled through the valley, it rattled in the dell;It knocked upon the mountain and recoiled upon the flat,For Casey, mighty Casey, was advancing to the bat.There was ease in Caseys manner as he stepped into his place;There was pride in Caseys bearing and a smile on Caseys face.And when, responding to the cheers, he lightly doffed his hat,No stranger in the crowd could doubt twas Casey at the bat.Ten thousand eyes were on him as he rubbed his hands with dirt;Five thousand tongues applauded when he wiped them on his shirt.Then while the writhing pitcher ground the ball into his hip,Defiance gleamed in Caseys eye, a sneer curled Caseys lip.And now the leather-covered sphere came hurtling through the air,And Casey stood a-watching it in haughty grandeur there.Close by the sturdy batsman the ball unheeded spedThat aint my style, said Casey. Strike one, the umpire said.From the benches, black with people, there went up a muffled roar,Like the beating of the storm-waves on a stern and distant shore.Kill him! Kill the umpire! shouted some one on the stand;And its likely theyd have killed him had not Casey raised his hand.With a smile of Christian charity great Caseys visage shone;He stilled the rising tumult; he bade the game go on;He signaled to the pitcher, and once more the spheroid flew;But Casey still ignored it, and the umpire said, Strike two.Fraud! cried the maddened thousands, and echo answered fraud;But one scornful look from Casey and the audience was awed.They saw his face grow stern and cold, they saw his muscles strain,And they knew that Casey wouldnt let that ball go by again.The sneer is gone from Caseys lip, his teeth are clinched in hate;He pounds with cruel violence his bat upon the plate.And now the pitcher holds the ball, and now he lets it go,And now the air is shattered by the force of Caseys blow.Oh, somewhere in this favored land the sun is shining bright;The band is playing somewhere, and somewhere hearts are light,And somewhere men are laughing, and somewhere children shout;But there is no joy in Mudvillemighty Casey has struck out.Source: Thayer, Ernest Lawrence. Casey at the Bat. Poetry Foundation. Poetry Foundation, n.d. Web. 24 June 2011. Mark the rhyme pattern and identify the meter. How would you classify this poem?