Consider the following reaction at 298K.
Pb2+ (aq) + Cu (s) Pb (s) + Cu2+ (aq)

Which of the following statements are correct?

Choose all that apply.
The reaction is product-favored.
delta G^o < 0
n = 4 mol electrons
K < 1
Eo cell < 0

The true statements are;

Now we can see that the reaction here is a redox reaction. Thus;

Eocell = cell potential = 0.54 - (-0.41) = 0.95 V

K = equilibrium constant = ?

n = number of moles of electrons = 2

ΔG = change in free energy = ?

Hence;

Eocell = 0.0592/n log K

0.95 = 0.0592/2 log K

K = 0.95 * 2/0.0592

K = 1.2 * 10^32

Now

ΔG = -nFEcell

ΔG = - (2 * 96500 *  0.95)

ΔG = -183.3kJ

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Answer:

A.) 4.0

Explanation:

The general equilibrium expression looks like this:

[tex]K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }[/tex]

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = molarity

-----> lowercase letters = balanced equation coefficients

In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.

[tex]K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }[/tex]                                       <----- Equilibrium expression

[tex]K = \frac{[2 M] [2 M]}{[1 M] [1 M] }[/tex]                                     <----- Insert molarities

[tex]K = \frac{4}{1 }[/tex]                                                <----- Multiply

[tex]K = 4[/tex]                                                <----- Divide

The new concentration of the lemonade solution, given the data from the question is 3.47 M

From the question given above, the following data were obtained:

The molarity of the new solution can be obtained by using the dilution formula as shown below:

M₁V₁ = M₂V₂

2.37 × 473 = M₂ × 323

1121.01 = M₂ × 323

Divide both side by 323

M₂ = 1121.01 / 323

M₂ = 3.47 M

Thus, the concentration of the new solution is 3.47 M

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The boiling point of plain water is less than the boiling point of both salt and sugar water.

Boiling point can be defined as the point when the pressure exerted by the surroundings upon a liquid is equal to the pressure exerted by the vapour of the liquid.

The boiling point of plain water is 100°C which increases upon addition of solute substances such as salt and sugar.

But salts are usually made up of ionic bonds while sugar are made up of covalent bonds. This means that more energy would be required to boil salt solution due to its ionic bonds.

Therefore, the boiling point of salt water is highest following sugar water before plain water which is the lowest.

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Taking into account the definition of pH and pOH, [H₃O⁺] will be 1×10⁻³ M.

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

In this case, you know that [OH⁻]= 1×10⁻¹¹ M.

Replacing in the definition of pOH, it is calculated as:

pOH= - log (1×10⁻¹¹ M)

Solving;

pOH= 11

Replacing in the relationship established between pH and pOH, the pH can be calculated as:

pH + 11= 14

Solving:

pH= 14 - 11

pOH= 3

Replacing in the definition of pH the concentration of H₃O⁺ ions is obtained:

- log [H₃O⁺]= 3

Solving:

[H₃O⁺]= 10⁻³

[H₃O⁺]= 1×10⁻³ M

In summary, [H₃O⁺] will be 1×10⁻³ M.

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Answer: e

Explanation: ima be real i searched it up lol

Answer:

See the image below for he circled and labeled functional groups.

*Keep in mind that all of the molecules technically contain alkanes.

The likely thing which will occur when an atom of this element 1s²2s²2p6 3s¹ comes near an atom having seven valence electrons is what is referred to as electrovalent bonding.

This is also referred to as ionic bonding and involves the transfer of atoms from one element to another. This is done so as to ensure that an octet configuration is achieved.

The element 1s²2s²2p6 3s¹  is Sodium and will undergo ionic bonding with the chlorine. One valence electron is transferred from the sodium to the chlorine which makes them stable.

This is therefore the reason why electrovalent bonding will most likely between the two elements.

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The product of the given reaction and the balanced form is as follows: Cu3(PO4)2 + 2Fe(OH)3 → 2FePO4 + 3Cu(OH)2 (option C).

A chemical reaction involves the formation of products from the combination of two or more reactants.

However, for the reaction to be balanced, the number of moles of each element on both sides of the equation must be equal.

According to this question, the following reaction is given: Cu3(PO4)2 + Fe(OH)3 → ?

The product of the given reaction and the balanced form is as follows: Cu3(PO4)2 + 2Fe(OH)3 → 2FePO4 + 3Cu(OH)2.

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The vapor pressure is obtained as 23.47 torr.

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp =  vapor pressure lowering

x2 = mole fraction of the  of the solute

Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp =  0.012 * 23.76 torr

Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

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answer = 9.96x10^-3

I hope that help you

Answer:

THERE IS NO  such compound

Explanation:

Potassium (K) has the greater tendency to be oxidized when compared to Lithium (Li).

Oxidation is a chemical process triggered by the reaction between an compound and an oxidizing agent. The agent is what gains electrons and undergoes reduction, causing what is called oxidation.

With that being said, as you go down the alkali metal group, the ionisation energy decreases. The tendency of an atom to give its electron (or get oxidised) increases. Therefore, potassium oxidises more easily than lithium or in other words, potassium has a lesser tendency to get reduced compared to lithium.

As lithium has a higher tendency to get reduced than potassium, lithium gets deposited instead of potassium.

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Answer:

D. Convert the 0.2 kg of NaCl to moles of NaCl

Explanation:

The molality equation looks like this:

Molality = moles of solute / mass (kg) of solvent

In this case, the solute is NaCl and the solution is water. So, if you have been given NaCl in kg, you need to convert it to grams and then to moles in order to plug it into the equation.

Answer:

C

Explanation:

For every action there is an equal but opposite reaction..... the forces are the same

Answer:

Disaccharide

Explanation:

When two monomers combine, a disaccharide is formed. Also, the prefix "di" is two therefore the answer must be a disaccharide

Answer:

C.) Fluorine

Explanation:

A period describes a row on the periodic table.

Halogens are located in the 17th column on the periodic table.

As such, the element located in the second row in the 17th column is fluorine.

The balanced redox reaction equation is 2Fe^2+  (aq) + H2O2 (aq)+2H + (aq) → 2Fe^3+ (aq)+2e + 2H2O(l).

A redox reaction equation is one in which there is a loss or gain of electrons. We can see that the oxidation number of some species is increased while the oxidation number of some species is reduced.

The oxidation half equation is written as; 2Fe^2+  (aq)→2Fe^3+ (aq)+2e

The reduction half equation is written as; H2O2 (aq)+2H + (aq)+2e  →2H2O(l).

Thus, the overall balanced redox reaction equation is written as;

2Fe^2+  (aq) + H2O2 (aq)+2H + (aq) → 2Fe^3+ (aq)+2e + 2H2O(l).

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Answer: D. They are slippery.

Explanation:

         Only one of the following is a property of bases. This is option D, they are slippery. Bases usually feel slippery, which can also be described as "soapy." Many soaps, shampoos, detergents, etc contain bases.

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Answer:

1.12 g CaCl₂

Explanation:

To find the mass of calcium chloride, you need to (1) convert grams KCl to moles KCl (via molar mass), then (2) convert moles KCl to moles CaCl₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CaCl₂ to grams CaCl₂ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (KCl): 39.098 g/mol + 35.453 g/mol

Molar Mass (KCl): 74.551 g/mol

Molar Mass (CaCl₂): 40.078 g/mol + 2(35.453 g/mol)

Molar Mass (CaCl₂): 110.984 g/mol

1 CaCl₂(aq) + K₂CO₃(aq) -----> 2 KCl(aq) + CaCO₃(aq)

1.50 g KCl            1 mole              1 mole CaCl₂           110.984 g
-----------------  x  -----------------  x  -----------------------  x  ------------------  =
                           74.551  g           2 moles KCl              1 mole

=  1.12 g CaCl₂

Taking into account the definition of calorimetry and latent heat, the heat needed to melt 100.0 grams of ice that is already at 0°C is 33,400 J (option A).

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you have to melt the ice into liquid water.Being the specific heat of melting of ice is 334 J/g, the heat needed to melt 100 grams of ice is calculated as:

Q= 100 grams× 334 J/g

Solving:

Q= 33,400 J

In summary, the heat needed to melt 100.0 grams of ice that is already at 0°C is 33,400 J (option A).

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Answer:

The amount of H2SO4 in 2 litres is 560gm.

Explanation:

Given,

mass of sulphuric acid / volume of solution =28%

Therefore, mass of sulphuric acid in 100 ml solution is 28 grams.

We know that,

volume of solution is 2000ml.

Thus,

mass of sulphuric acid in 2000ml is

(28/100) ×2000

=28×20

=560gm

Thus, the mass of sulphuric acid is 560gm.

The correct number of significant figures gotten from the result of (329.5/0.45)-23.2 is infinite because there is no uncertain digit as a result of the answer being 709.022222222 when calculated.

These refers to the digits which contributes to the degree of accuracy of a value and is usually counted starting from the non zero digits. In cases where the zero is between other numbers it is regarded as being significant such as 70.0111 in which the number of significant figures is six.

The result gotten from the expression (329.5/0.45)-23.2 is 709.022222222 which has a recurring decimal thereby making it difficult to calculate the number of recurring decimal.

Therefore it has infinitely many significant figures because there is no uncertain digit.

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Answer:

See below

Explanation:

2 Ag +   Cu(NO3)2 = Cu +  2 AgNO3​

The new pressure of the gas would be = 2.1 atm.

The initial temperature of the gas(T1) = 20°C

The final temperature of the gas(T2)= 35°C

The volume= constant

The Original pressure (P1) = 1.2atm

The new pressure (P2) =?

Using the gas law P1/T1 = P2/T2

Make P2 the subject of formula;

P2= P1×T2/T1

P2= 1.2 × 35/20

P2= 42/20

P2= 2.1 atm

Therefore, the new pressure of the gas would be = 2.1 atm.

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The average kinetic energy of the gas particles is greater in container B because it has a higher temperature.

The term temperature refers to a measure of the average kinetic energy of the molecules of  body. This means that molecules that are at high temperature tend to move faster than the molecules that are at low temperature.

As such, the higher temperature of the molecules of the gas in B shows that the molecules in B are faster than those in A thus the correct statement is; "the average kinetic energy of the gas particles is greater in container B because it has a higher temperature."

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Missing parts;

The picture shows two containers filled with a gas.

Two equally sized containers are shown with tight lids and each container has a thermometer. The container on the le is labeled A and the one on the right is labeled B. The thermometer inside container B shows a higher temperature than the thermometer inside container A.

Which statement is correct?

The average kinetic energy of the gas particles is greater in container A because it has a lower temperature.

The average kinetic energy of the gas particles is greater in container B because it has a higher temperature.

The gas particles in both containers have the same average kinetic energy because t have the same volume.

The gas particles in both containers have the same average kinetic energy because t have equal number of particles.

Answer:

0.15 M KCl

Explanation:

(Step 1)

Convert the original volume from mL to L. Calculate the moles of the original solution.

75.0 mL / 1,000 = 0.0750 L

Molarity = moles / volume (L)

0.200 M = moles / 0.0750 L

0.0150 = moles

(Step 2)

Convert the final volume from mL to L. Calculate the final molarity.

100. mL / 1,000 = 0.100 L

Molarity = moles / volume (L)

Molarity = 0.0150 moles / 0.100 L

Molarity = 0.15 M

The Molar enthalpy of combustion of methanol obtained from the practical is -31.02 kJ/mol.

The molar enthalpy of combustion from bond energies, ΔH is -543 kJ/mol

The differences in the values could be due to:

The actual enthalpy of combustion of methanol is calculated from the data obtained from the laboratory work.

The enthalpy of combustion is equal to the heat energy given off from the combustion of methanol.

Quantity of heat gained by water , q = -mcθ

where:

mass of water heated = 100 g

specific heat capacity of water = 4.18 J/g/°C

temperature change = 32.4°C - 21.5°C = 10.9°C

q = -(100 * 4.18 * 10.9) J

q = - 4556.2 J

moles of methanol reacted = mass/molar mass

mass of methanol = 80.6 - 75.9 = 4.7 g

molar mass of methanol = 32 g/mol

moles of methanol = 4.7/32 = 0.14687 moles

Molar enthalpy of combustion of methanol = -4556.2 J/0.14687 mole

Molar enthalpy of combustion of methanol = -31.02 kJ/mol

Calculating molar enthalpy of combustion from bond energies:

Sum of bond energies of bonds broken = (3 * 412) + 358 + 463 + (1.5 * 496) + 35 = 2836 kJ/mol

Sum of bond energies of bonds formed = (2 * 743) + 2(2 * 463) + 41 = 3379 kJ/mol

ΔH = 2836 kJ/mol - 3379 kJ/mol

ΔH = -543 kJ/mol

The value obtained from the practical is less than that from the bond energies

b. The possible reasons for the difference in value obtained from the practical is less than that from the bond energies include:

In conclusion, the molar enthalpy of combustion of methanol is negative since heat is given off during the reaction.

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Answer:

to launch aerials and also causes the explosions necessary for special effects like noise or colored light.

Explanation: