Can someone please help me with this?

The vertical asymptote of f(x) is (A) x = 0, –9.

To find the vertical asymptote of f(x):

The vertical asymptotes of a function are the zeroes of the denominator of a rational function

The function is given as: [tex]f(x) = \frac{(x-9)}{(x^{3} -81x)}[/tex]

Set the denominator to 0:

Factor out x:

Express 81 as 9^2:

Express the difference between the two squares:

Split, [tex]x=0[/tex] or [tex]x=-9[/tex] or [tex]x+9=0[/tex].

Solve for x:

Therefore, the vertical asymptote of f(x) is (A) x = 0, –9.

(See attachment for the graph of f(x))

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The complete question is given below:

Consider the function f(x)=(x-9)/(x^3-81x) . find the vertical asymptote(s) of f(x).

A) x = 0, –9

B) x = –9

C) x = 0, 9

D) x = 9

The value of the vector will be -53. The correct option is C.

In mathematics and physics, the term "vector" is used informally to describe certain quantities that cannot be described by a single number or by a set of vector space elements.

The dot product, also known as the scalar product, is an algebraic operation that takes two sequences of integers of equal length and outputs a single number.

The given vectors are u=2i-9j and v=-5i+7j, the dot product of the vectors will be calculated as below:-

u.v = ( 2i-9j ).( -5i+7j)

u.v = -10i² + 17 (i.j) -45(i.j) -63j²

Substitute i² = 1, j² = 1 and (i.j) = 0 in the above equation.

u.v = -10 + 63

u.v = 53

Therefore, the value of the vector will be -53. The correct option is C.

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Answer:

6

Step-by-step explanation:

Given an isosceles triangle the two sides opposite of congruent angles are equal to eachother, so you can create an equation setting the two sides equal to eachother and solve for x.

[tex]x+4=3x-8\\x=3x-12\\-2x=-12\\x=6[/tex]

The length of AC is simply x, therefore 6

331.5 inches²  is the area of the octagon, rounded to the nearest square inch.

What is octagonal in shape?

Solving for an area of a regular octagon, we can make use of the formula shown below:

Area = 1/2 × apothem × perimeter

In this problem, the following values were given such as:

Apothem = 10 inches

Perimeter = 66.3 inches

Put the values in the formula

Area = 1/2 × 10 × 66.3

Area = 331.5 inches²  

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Answer: C). 332 in.2

Step-by-step explanation:

on edg

There are 59 integer solutions

Such questions are best solved by writing cases and calculating the total number of cases. So beginning with

1)  x = -3. The possible combinations are as follows:-

-3 2 13

-3 3 12

-3 4 11

-3 5 10

-3 6 9

-3 7 8

-3 8 7

-3 9 6

-3 10 5

-3 11 4

10 combinations

2) x = -2

-2 2 12

through

-2 11 3

10 combinations

3) x = -1

-1 2 11

through

-1 10 3

9 combinations

4) x = 0

0 2 10

through

0 9 3

8 combinations

as we can see from the pattern at x =1  we get 7 combinations, at x =2  we get 6 combinations, at x=3 we get 5 combinations and at x =4  we get 5 combinations.

Thus total number of combinations 4+5+6+7+8+9+10+10 = 59 integer solution.

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[tex]m = m \\ \frac{97 - 68}{2 - 1} = \frac{134 - 97}{3 - 2} \\ 29 = 37 \\ this \: function \: is \: non \: linear[/tex]

[tex]f(1) = 68 \: \: \: f(2) = 97 \: \: \: \: f(3) = 134 \\ f(x) = ax {}^{2} + bx + c[/tex]

[tex]f(1) = 68 \\ 7.8(1) {}^{2} - 2.9(1) + 67.1 = 68 \\ 7.8 - 2.9 + 67.1 = 68 \\ 72 = 68 \\ this \: is \: false[/tex]

Answer:

division

Step-by-step explanation:

ratio compares 2 numbers by dividing them

example

2 out of 3 dentists like gum

2 ÷ 3 = .67 = 67%

so you can say

67% of dentists like gum

A ratio can be defined as the relationship or comparison between two numbers of the same unit to check how bigger is one number than the other one. For example, if the number of marks scored in a test is 7 out of 10, then the ratio of marks obtained to the total number of marks is written as 7:10.

Answer:

no solution

Step-by-step explanation: because if it has no variables that are the same it has no solution.

Answer:

5 line of symmetry

Step-by-step explanation:

Answer:

7+21+15+19+.....+79

Here 21 be replaced by 11.

Now., common diffrence btw terms , d = 11-7 = 4

first term , a = 7

Last term , l = 79

number of terms = ( a + l ) ÷ d

=( 7 + 79 ) ÷ 4 = 86 ÷ 4 = 21.5 { It cannot be in decimal }

There's some mistake in the terms you provided please check your question again...

Answer:

14cm.

Step-by-step explanation:

X is the hypotenus, 7√3 is the opposite and the other side is the adjacent. Choose sin from (soh, cah, toa) because you have to find 'H' (hyp) and opposite is given. Hence, sin 60= 7√3 over x. Cross multiply and you'll get x * sin 60= 7√3. Make x the subject of formula and 14 will be the answer.

Answer:

10 shelves

Step-by-step explanation:

out of the other choices, 10 is most suitable to divide with 80

Considering the graph of the velocity of the car, it is found that the interval in which it was stopped at a traffic light was:

Between 3 and 4 minutes.

When a car is stopped at a traffic light, the car is not moving, that is, it's velocity is of zero.

In this problem, the graph gives the velocity as a function of time, and it is at zero between 3 and 4 minutes, hence the interval in which it was stopped at a traffic light was:

Between 3 and 4 minutes.

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Answer:

A. (3x + 4)(x-7)

Step-by-step explanation:

3x times x = 3x^2

3x times -7 = -21x

4 times x = 4x

4 times -7 = -28

-21x + 4x = -17x

3x^2 - 17x - 28

The addition equation to represent how their charges combine to make the overall charge of the atom is + 1 + - 1 = 0

A hydrogen atom has one positively charged proton and one negatively charged electron.

An atom of every elements has an electron(negatively charged) and positively charge(proton) part.

An atom as a whole is electrically neutral if the number of proton and electron are equal. They will cancel each other to make the atom neutral.

Therefore, the addition equation to represent how their charges combine to make the overall charge of the atom is as follows;

+ 1 + - 1 = 0

1 positively charged proton plus single negatively charged electron  = zero(neutral)

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Answer:

the answer to "2 times what equals 25?" is 12.5.

Step-by-step explanation:

proof from r.h.s to l.h.s

(cot(a)-tan(a))(cot(a)+tan(a))

cot(a)=cos(a)/sin(a)

tan(a)=sin(a)/cos(a)

(cot(a)-tan(a))=cos(a)/sin(a) - sin(a)/cos(a)

=cos²(a)-sin²(a)/sin(a)cos(a)

from trigonometry identity cos²(a)-sin²(a)=cos2(a)

so we have cos2(a)/sin(a)cos(a)

(cot(a)+tan(a))=cos(a)/sin(a) +sin(a)/cos(a)

=cos²(a)+sin²(a)/cos(a)sin(a)

from trigonometry identity cos²(a)+sin²(a)=so we have 1/cos(a)sin(a)

(cot(a)-tan(a)) ÷(cot(a)+tan(a))

=cos2(a)/cos(a)sin(a) ÷ 1/cos(a)sin(a)

=cos2(a)/cos(a)sin(a) * cos(a)sin(a)

=cos2(a)

proved

Answer:

Step-by-step explanation:

Given functions:

[tex]\begin{cases}f(x)=-4^x+5\\g(x)=x^3+x^2-4x+5 \end{cases}[/tex]

This is an exponential function.

An exponential function includes a real number with an exponent containing a variable.

x-intercept (when y = 0):

[tex]\begin{aligned}f(x) & = 0\\\implies -4^x+5 & =0\\ 4^x &=5\\\ln 4^x &= \ln 5\\x \ln 4 &= \ln 5\\x&=\dfrac{ \ln 5}{\ln 4}\\x&=1.16\:\: \sf(2\:d.p.)\end{aligned}[/tex]

Therefore, the x-intercept of f(x) is (1.16, 0).

y-intercept (when x = 0):

[tex]\begin{aligned}f(0) & = -4^{0}+5\\& = 1+5\\& = 6\end{aligned}[/tex]

Therefore, the y-intercept of f(x) is (0, 6).

End behavior

[tex]\textsf{As }x \rightarrow \infty, \: f(x) \rightarrow \infty[/tex]

[tex]\textsf{As }x \rightarrow -\infty, \: f(x) \rightarrow 5[/tex]

Therefore, there is a horizontal asymptote at y = 5 which means the curve gets close to y = 5 but never touches it.  Therefore:

This is a polynomial function of degree 3 (since the greatest exponent of the function is 3).

A polynomial function is made up of variables, constants and exponents that are combined using mathematical operations.

x-intercept (when y = 0):

There is only one x-intercept of function g(x).  It can be found algebraically using the Newton Raphson numerical method, or by using a calculator.

From a calculator, the x-intercept of g(x) is (-2.94, 0) to 2 decimal places.

y-intercept (when x = 0):

[tex]\begin{aligned}g(0) & = (0)^3+(0)^2-4(0)+5\\& = 0+0+0+5\\& = 5 \end{aligned}[/tex]

Therefore, the y-intercept of g(x) is (0, 5).

End behavior

[tex]\textsf{As }x \rightarrow \infty, \: f(x) \rightarrow \infty[/tex]

[tex]\textsf{As }x \rightarrow -\infty, \: f(x) \rightarrow - \infty[/tex]

Therefore:

Conclusion

Key features both functions have in common:

Answer:

Week 4

Step-by-step explanation:

Victoria has $250 and saves $150 each week, hence have increments $150 each week

250+150 (first week)

= 400

second week = 400 + 150 = 550

third week = 550 + 150 = 700

fourth week = 700 + 150 = $850

Felicia on the other hand has $1,650 and spends $200 each week, hence has decrements of $200 each week.

1650+200 (first week)

= 1450

second week = 1450 - 200 = 1250

third week = 1250 - 200 = 1050

fourth week = 1050 + 200 = $850

Answer: 77 - 10 = 67, and the additive inverse of 77 - 10 is 77 + 10. 77 + 10 = 87.

Hope this helps! This question was kind of confusing for me, because I didn’t understand why you said to add 77 - 10… is this is the incorrect answer sorry your question was worded weird

Using it's concept, the probability a person tests positive who does not actually have Tuberculosis is:

c. 49/148.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there are 198 + 98 = 296 people who test positive, which is the number of total outcomes, and of those, 98 do not have the disease, which is the number of desired outcomes. Hence the probability is given by:

p = 98/296 = 49/148.

Which means that option c is correct.

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The probability a person tests positive who does not actually have Tuberculosis is 1/100

The probability is given as:

The probability a person tests positive who does not actually have Tuberculosis.

This is a conditional probability, and it can be calculated using

P = n(Tests positive | Does not have Tuberculosis)/n(Does not have Tuberculosis)

Using the given table of values, we have:

P = 98/9800

Evaluate the quotient

P = 1/100

Hence, the probability a person tests positive who does not actually have Tuberculosis is 1/100

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One can prove congruence through transformation if they have the same shape and size.

The congruency postulates include:

In geometry, it should be noted that two figures are congruent if they have the same shape and size.

In this case, if two angles and a non-included side of one triangle are equal to two angles and a non-included side of another triangle, then the triangles are congruent.

One can prove triangle congruence using congruency postulates by using the SSS theorem( side side side theorem).

It should be noted that the congruence postulate is used to illustrate that the triangles are equal.

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Answer:

x=3

y = -2

Step-by-step explanation:

2x+5y = -4

y = x-5

We want to use substitution

In the first equation, every time we see y, substitute x-5

2x + 5( x-5) = -4

Distribute

2x + 5x -25 = -4

Combine like terms

7x -25 = -4

Add 25 to each side

7x -25+25 = -5+25

7x = 21

Divide each side by 7

7x/7 = 21/7

x=3

Now we can find y

y = x-5

y = 3-5

y = -2

The answer is x = 3, y = -2 or (3, -2).

We are given that :

Let us substitute the 2nd equation's value of y in the 1st equation.

Now, substitute for x in the 2nd equation.

5. m∠C = 95°

6. m∠C = 70°

7. The other acute angle in the right triangle = 70°

8. m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 110°

11. m∠B = 70°

12. m∠Z = 70°

A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:

5. m∠C = 180 - 50 - 35 [triangle sum theorem]

m∠C = 95°

6. m∠C = 180 - 25 - 85 [triangle sum theorem]

m∠C = 70°

7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]

The other acute angle = 70°

8.  m∠C = 180 - 55 - 55 [isosceles triangle]

m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 50 + 60

Measure of the exterior angle at ∠C = 110°

11. m∠B = 115 - 45

m∠B = 70°

12. m∠Z = 180 - 35 - 75

m∠Z = 70°

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The quantity of the radioactive material which would remain 2 years from now is; 4 grams.

Since, it follows from the task content that after two year, the quantity of the radioactive substance decrease by 1 gram. Consequently, it follows from proportion that the quantity remaining in 2 years from now is; 5-1 = 4 grams.

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Two or more equations using the same variable are referred to mathematically as a "system of linear equations." These equations' solutions serve as a representation of the intersection of the lines.

Two equations are presented here:

1) x + 3y = 7

2) 2x + 4y = 8

First, in the first equation, we want to isolate x:

x + 3y = 7

x = 7 -3y

In order to create an equation that depends just on the variable y, we must now b) swap it out in the second equation.

2x + 4y = 8

2(7 - 3y) + 4y = 8

The value of y is now determined by solving this equation in step (c).

14 - 6y + 4y = 8

14 - 2y = 8

-2y = 8 - 14 = -6

y= 6/2= 3

d) With the value of y now available, we can change the equation we obtained in step a) by substituting it.

x = 7 - 3y

x = 7 - 3*3 = 7 - 9 = -2

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I understand that the question you are looking for is:

Find the solution to the system of equations, x + 3y = 7 and 2x + 4y = 8.

1. Isolate x in the first equation: x = 7 − 3y

2. Substitute the value for x into the second equation: 2(7 − 3y) + 4y = 8

3. Solve for y:

14 − 6y + 4y = 8

14 − 2y = 8

−2y = −6

y = 3

4. Substitute y into either original equation: x = 7 − 3(3)

5. Write the solution as an ordered pair:

Answer:

[tex]\dfrac{8y-43}{(y-1)(y-8)}[/tex]

Explanation:

[tex]\rightarrow \dfrac{5}{y-1} +\dfrac{3}{y-8}[/tex]

make the denominators similar

[tex]\rightarrow \dfrac{5(y-8)}{(y-1)(y-8)} +\dfrac{3(y-1)}{(y-8)(y-1)}[/tex]

Join both the fraction

[tex]\rightarrow \dfrac{5(y-8)+3(y-1)}{(y-1)(y-8)}[/tex]

simplify the expression

[tex]\rightarrow \dfrac{5y-40+3y-3}{(y-1)(y-8)}[/tex]

[tex]\rightarrow \dfrac{8y-43}{(y-1)(y-8)}[/tex]

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's simplify ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{5}{y - 1} + \cfrac{3}{y - 8} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{5(y - 8) + 3(y - 1)}{(y - 1)(y - 8)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{5y -40 + 3y - 3}{y {}^{2} - y - 8y + 8} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{8y -43}{y {}^{2} - 9y + 8} [/tex]

Pick 2 coordinates:

I choose first & last one (0,15) & (8-9)

Change in y is 24

(15--9 = 24)

Change in x is 8

(0 - 8) = - 8

24/-8 = - 3

So, slope = - 3

Hope this helps!

Answer:

-3

Step-by-step explanation:

The formula to find the slope is (change in y)/(change in x). In other words, rise over run.

If we look at the data, we can see that the x and y value changes.

x value: 0 --> 2 --> 4 --> 6 --> 8

y value: 15 --> 9 --> 3 --> -3 --> -9

When y changed from 15 to 9, the x changed from 0 to 2.

y: 15 --> 9

x: 0 --> 2

There was a difference of -6 in the y and a difference of 2 in the x.

At the top, I wrote that the slope was (change in y)/(change in x)

With -6 and 2 we found, we can say that the slope is -6/2.

If we simplify this answer, we end up with -3.

So -3 is the slope of the data.