Calculate the kf of ag(nh3)2 from ag (aq) e- ⇋ ag(s) e0= 0. 81 v ag(nh3)2 (aq) e- ⇋ ag(s) 2nh3(aq) e0= 0. 39 v enter number as e notation (e. g. 2. 34e6 or 4. 56e-4)

The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.

The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.

It can be found using the formula,

m = Z I t

where, m = mass of metal deposited = 75.8g

            Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001

             I is the current passed

              t is the time taken = 75hour = 75 × 60 = 4500s

On subsituting in above formula,

75.8 = E I t / F

⇒ 75.8 = 0.0001 × I × 4500

⇒ I = 168.4 Ampere (A)

Hence, amount of current required to deposit a metal is 168.4A.

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A single slit with a width of 2019 * 109 m creates its initial minimal for 624 nm light at an angle of 18°.

How does diffraction work?

Waves spreading outward around obstructions are known as diffraction. Diffraction happens with sound, electromagnetic radiation like light, X-rays, and gamma rays, as well as with incredibly minuscule moving particles like atoms, neutrons, and electrons that exhibit wavelike qualities. Diffraction prevents the creation of sharp shadows as one of its effects. In order to spread out and illuminate regions at which a shadow is anticipated, light must be bent around corners, which is known as diffraction.

Calculation:

Provided for a single slit, m=1

λ = 624 *10⁻⁹

sinθ = sin 18⁰

Therefore,

asinθ=mλ

a = [tex]\frac{1 * 624 *10^{-9} }{sin 18}[/tex]

⇒a = 2019 *10⁻⁹ m

Therefore the width of a single slit is 2019 *10⁻⁹ m.

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Na -k pumps couple atp hydrolysis with the transport of Na and k.

Both ions are used for active transport.

d. K+ and Na+ both diffuse into the cell along their concentration gradients and drive the transport of glucose.

Na/K pump is a pump located on the plasma membrane which uses ATP to move 3 Na ions out the cell and brings in 2 K ions into the cell. It is an example of primary active transport. As a consequence, concentration of Na is higher outside the cell, while K concentration is higher inside the cell.

Glucose is transported in the cell against its gradient, together with Na ions (symport) which move down their concentration gradient.

This is an example of secondary active transport because it uses the energy from the primary active transport to move other substances such as glucose against their own gradients.

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Urea get decomposed during autoclaving, because it is volatile. It is filter sterilized and added aseptically to your autoclave media.

Can urea be autoclaved?

What is autoclave sterilization?

What is filter sterilization?

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Nitrogen (N2) and hydrogen (H2) gases react to form ammonia, which requires -99.4 J/K of standard entropy (ΔS°).

What is standard entropy?

The difference between the total standard entropies of the reaction mixture and the summation of the standard entropies of the outputs is the standard entropy change. Each entropy in the balanced equation needs to be compounded by its coefficient, as shown by the letter "n."

Calculation:

Balancing the given reaction following-

1/2 N₂(g) + 3/2 H₂ (g)→ NH₃ (g)

ΔS° = [1 mol x S° (NH₃)g] - [1/2 mol x S° (N₂)g] - [3/2 mol x S°(H₂)g]

Here S° = standard entropy of the system

Insert into the aforementioned equation all the typical entropy values found in the literature:

ΔS° = [1 mol x 192.45 J/mol.K] - [1/2 mol x 191.61 J/mol.K] - [3/2 mol x 130.684 J/mol.K]

⇒ΔS° = - 99.4 J/K

Therefore, the standard entropy, ΔS° is -99.4 J/K.

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Answer:

See below

Explanation:

Temperature is basically a measure of the average kinetic energy of the particles in the sample ....so as  temp goes up, kinetic energy increases

The given example is a chemical reaction.

The contents (separated as reactants and products) :

[tex]\begin{tabular}{c | l}Reactants & Products \\\cline{1-2}Chlorine & Sulfuric Acid \\Water & Hydrochloric Acid \\Sulfur Dioxide & \\\end{tabular}[/tex]

The written reaction is :

[tex]\boxed {Cl + SO_{2} + H_{2}O \implies HCl + H_{2}SO{4}}[/tex]

I hope it helped you solve the problem.

Good luck on your studies!

Answer:

1 mole of H2SO4 contains 2 x 6.023 x 10²³ So, 0.1 mole of H2SO4 contains =2 x 6.023 x 10²³ x 0.1

= 1.2 x 10²³atoms of hydrogen

hello there !!

In the Question it's asked that total atoms present in 0.1 mol of H2So4.

so , in the question number of moles is given as 0.1 mole

=> n = 0.1 mole

and total atoms present are = ???

So , in H2So4 molecule there are two hydrogen atoms

=> H2So4 → 2 hydrogen atoms

one mole of H2So4 consist of ;

=> 2 × 6.022 × 10²³

1 mol = 6.022 × 10 ²³ atoms

Therefore, 0.1 mole of H2So4

=> 0.1 × 2 × 6.022 × 10²³ Atoms

=> 0.1 × 2 × 6.022 × 10²³ Atoms=> 12.004 × 10²² Atoms

x2=x+2 at x=−1 and x=2 so we have no need to worry about the end-points

f(x)=x+2−x^2

df/dx=1–2x

and that is zero (indicating a maximum) at x=1/2

So the maximum distance is f(1/2)=2.5–0.25=2.25

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If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,

In dehydration reaction of alcohol (  O-H and  C-O bond ) contain , the water molecule ( [tex]H_{2}O[/tex] ) is release from the reactant and C-C double bond is form which is known as alkene in the product .

The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of  dehydration reaction of an alcohol. It means  O-H band is disappear from stating material.

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144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Presure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = temperature in Kelvin

Here,

P = 1 atm  [At STP]

R = 0.0821 atm.L/mol.K

T = 273 K  [At STP]

Now first find the number of moles

F₂  +  CaBr₂  →  CaF₂  +  Br₂

Here 1 mole of F₂ reacts with 1 mole of CaBr₂.

So,  199.89 g CaBr₂ reacts with  = 1 mole of F₂

1.28 g of CaBr₂ will react with = n mole of F₂

[tex]n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}[/tex]

n = 0.0064 mole

Now put the value in above equation we get

PV = nRT

1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K

V = 0.1434 L

V ≈ 144 mL

Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

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Rusting of Iron is the formation of rust which is characterized by formation of layer of red colour. Formula of Rust is Ferric Oxide (Fe₂O₃) where iron exhibits oxidation state of +3.

Following are the indicators of rusting:

Even if the Reddish brown rust is not visible on the iron surface, then also Ferroxyl Indicator turns blue in presence of Iron ions.

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The process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".

The biological process of nitrification turns ammonia into nitrite and nitrite into nitrate. The technique of denitrification, which turns nitrate into nitrogen gas, is such treatment option if requirements demand that the resultant nitrate be eliminated.

A surplus of nitrogen compounds could result in pollutants like ammonia and ozone that can affect plant growth, visibility, and human capacity to breathe. Excess nitrogen from the atmosphere that returns to earth could be damaging to the health of forests, soils, including streams.

Therefore, the process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".

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A symmetrical acid anhydride will undergo a reaction with an alcohol to give an ester and a carboxylic acid. An asymmetrical acid anhydride will undergo a reaction with an alcohol to give two esters and two carboxylic acids.

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a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

The molar mass is the mass in grams of 1 mole of particles, that is, the mass in grams of 6.02 × 10²³ particles. The units are g/mol.

We want to calculate the number of moles represented by different masses of different substances. In each case, the conversion factor between mass and moles is the molar mass.

The molar mass of silver is 107.87 g/mol.

2.00 × 10² g × (1 mol/107.87 g) = 1.85 mol

The molar mass of silicon dioxide is 60.08 g/mol.

37.1 g × (1 mol/60.08 g) = 0.618 mol

a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

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The molarity of the solution is 0.528 mol/l.

What is molarity?

The molarity of any solution is the number of moles per liter of the solution.

Given,

The molality of the solution is 0.0480 m Lif

The density of the solution is 1.10 g/ml

Step 1: 0.0480 moles of LiF were present in 1 kg solvent.

Mass of 0.0480 moles of LiF = 0.0480 mol × 26 g/mol = 1.248 g

Mass of the solution (m)=  1 kg (solvent) + 1.248 g(solute)

m = 1000 g + 1.248 g = 1001.248 g

Step 2: Find the volume of the solution

Step 3: Calculating the molarity

Thus, the molarity of the solution is 0.528 mol/l.

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In a solution, when the concentrations of a weak acid and its conjugate base are equal: 1. the -log of the concentration of H+ and the -log of the Ka are equal.

Any acid that entirely ionises in solutions is considered a strong acid. When positioned, it emits the most hydrogen ions or protons.

Acids that don't entirely dissociate in solution are referred to as weak acids. In other words, any acid that is not a strong acid qualifies as a weak acid. The amount of dissociation determines how strong an acid is; the more dissociation, the stronger the acid.

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The  Cm of the Microsand concentration in the tanks when expressed in grams of Microsand per liter (g/L) is known to be 3.8 g/L.

This is known to be a kind of  aggregate, that is said to be exempted from clay and shale and it is one that can rightly fine to pass via a No. 100 (that is 150 µm) sieve.

Note that from the question:

The Average of six samples = 30mg/L.

Then one need to Multiply:

30 by 300gpm x 1 Train x 1700 ( this is the use of the bulk density conversion factor).

Then one need to also Divide by (4000 gpm x 2000 mL) =  1.8 g/L.

Lastly you then multiply by 2,

1.8 g/L x 2  = 3.8 g/L.

Therefore, looking at the solution above, the Cm of the Microsand concentration in the tanks  is seen to be 3.8 g/L.

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If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)

This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.

A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states as follow:

If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

From the principle given above, we can see that volume does not affect equilirium position.

However, from Boyle's law, we understood that pressure and volume are in invest relationship.

Thus, increasing volume simply means decreasing pressure.

A decrease in pressure will favors the side where there is an increase in volume.

Let us consider the equation from the question:

N₂(g) + 3H₂(g) <=> 2NH₃(g)

Thus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.

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Mass of CH₄ is 10.591 g.

The molar mass is a crucial characteristic of the material that is independent of sample size. The coherent unit of molar mass in the International System of Units (SI) is kg/mol. However, molar masses are usually generally given in g/mol due to historical considerations.

A chemical compound's molar mass is calculated by dividing its mass by the number of moles of the substance that make up the sample.

Δg = 587.9 KJ

CH₄ Molar mass = 16.05 g/mol

mol CH₄ = Δg / ΔH°

              = 587.9 / 890.3 KJ/ mol

              = 0.6603 mol CH₄

Mass CH₄ = 0.6603 × 16.05 g/mol

                = 10.591 g

Therefore, the mass of  CH₄ is 10.591 g.

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10

For every one NADH molecule oxidized at complex i ,  10 total hydrogen ions are pumped across all of the complexes from the mitochondrial matrix to the inner membrane space.

4 proteins

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Epimerization and Enediol rearrangement are the two most common unwanted side reactions which can occur when monosaccharides are treated with base.

Epimerization is a process in stereochemistry in which there is a change in the configuration of only one chiral centre. As a result, a diastereomer is formed. The classical example of this in medicine is tetracycline. In acidic conditions around pH 4, tetracycline readily undergoes epimerization at position 4, and an inactive 4-epitetracycline is produced, which on dehydration forms 4-epianhydrotetracycyline, a highly toxic product. This toxic compound can also be formed from acid catalysed (at lower pH) dehydration of tetracycline via anhydrotetracycline.

Enediol rearrangement is a  transformation which occurs at basic medium and allows the conversion of epimers, defined as isomeric forms that differ in the position of the hydroxyl group at C-2. In this way it is possible to transform through the enediol intermediate glucose to mannose and vice versa.

Another important isomerization process through the enediol rearrangement is the interconversion of glucose and fructose. Thus, the enolization proceeds by migration of proton at position 2, to carbon at 1.

Monosaccharides contain both alcohol and carbonyl functional groups. This allows monosaccharides to undergo many of the reactions typical for these functional groups. In particular, alcohols can be converted to esters, converted to ethers, converted to acetals, or oxidized. Carbonyls can be reacted with nucleophiles, be reduced to form alcohols, or be oxidized to form carboxylic acids.

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Answer:

Density = 0.27 decagrams/cm³

Explanation:

From conversion tables, we know that;

1 g/cm³ = 0.1 decagrams/cm³

We are given;

Density of aluminium = 2.7 g/cm³

Thus;

Density = 2.7 * 0.1

Density = 0.27 decagrams/cm³

Answer:

270000 decagrams/m³

Explanation:

1.

Density=mass/Volume

=2.7g/1cm3

=(2.7/1000)/(1/1000000)

=2.7x1000

Density=2700kg/ m3

= 270000 decagrams/m³

2.

1000g=1kg

1g=1/1000kg

1cm3= ? m3

100cm=1m

1cm=1/100 m

1cm3=1/1000000 m3

The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;

P1V1/T1 = P2V2/T2

Where;

According to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.

However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:

2 × 12.3/300 = 2 × V2/900

0.082 = 2V2/900

73.8 = 2V2

V2 = 73.8 ÷ 2

V2 = 36.9L

Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

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Answer:

Explanation:

it's 18.45, my sister just got the guestion right! hope it helps :)

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

[SO₄²⁻] = 0.037 M;

[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid.  HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R   [tex]HSO_4^-[/tex]    ⇄  [tex]H^+ + SO_4^2^-[/tex]

I    [tex]0.14[/tex]

C   [tex]- x[/tex]               [tex]+x[/tex]       [tex]+x[/tex]

E   [tex]0.14-x[/tex]        [tex]x[/tex]         [tex]x[/tex]

[tex]K_a = 1.3[/tex] × [tex]10^-^2[/tex] for [tex]HSO^-_4[/tex] . As a result,

[tex]\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a[/tex]

[tex]K_a[/tex] is large. It is no longer valid to approximate that [tex][HSO^-_4][/tex] at equilibrium is the same as its initial value.

[tex]\frac{x^2}{0.14-y} = 1.3 * 10^-^2[/tex]

[tex]x^2+1.3*10^-^2x - 0.14[/tex] × [tex]1.3[/tex] × [tex]10^-^2= 0[/tex]

Solving the quadratic equation for [tex]x , x \geq 0[/tex] since [tex]x[/tex] represents a concentration;

                             [tex]x=0.0366538[/tex]

Then, round the results to 2 significant figure;

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The balanced overall reaction from these unbalanced half-reactions is given  in following steps ,

Step 1 : [tex]Sn[/tex] → [tex]Sn^{+2}+ 2e^{-}[/tex]  

Step 2 : [tex]Ag^{+}[/tex] + [tex]e^{-}[/tex] →  [tex]Ag[/tex]

 [tex]2Ag^{+} + 2e^{-}[/tex] → [tex]2Ag[/tex]

Overall reaction : [tex]Sn[/tex] + [tex]2Ag^{+}[/tex] → [tex]Sn^{+2}[/tex] + [tex]2Ag[/tex]

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

This step is oxidation half-reaction in which loss of electron is takes place .

Second steps is reduction reaction in which fain of electrons is takes place. We multiple second  half-reaction by two to make equal number of electrons in both steps to cancel out the electrons from the equation.

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Answer:

Atom

Explanation:

That describes an ATOM

Explanation:

(e)the heat is absorbed into the reaction .