Before a site begins recruitment, a protocol monitor will conduct
a visit to review the data the research site has collected from
study participants.

Answers

Answer 1

Initiation visits occur before a study site begins participant recruitment for protocol participation and after the necessary IRB permissions are obtained. During a site initiation visit, study monitors review trial records to ensure that they are complete and in order.

What is Protocol Monitor?

The experimental Protocol Monitor displays the underlying requests and reactions happening over the DevTools protocol. For example, when considering some JavaScript via DevTools, observe the following notes on the protocol: Runtime.

How do I turn off Developer Tools on my phone?

You can disable the Developer options and hide the menu by opening Locations, and then tapping Developer options. Tap the switch at the top of the net to turn off Developer options.

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Related Questions

Consider an experiment of tossing two fair dice and noting the outcome on each die. The whole sample space consists of 36 elements. Now, with each of these 36 elements associate values of two random variables, X and Y, such that X≡ sum of the outcomes on the two dice, Y ≡ |difference of the outcomes on the two dice|. Construct joint probability mass function.

Answers

The joint probability mass function based on the given experiment is as seen in the attached file.

How to construct a joint probability mass function?

The whole sample space consists of 36 elements, i.e.,

Ω = {ω_ij = (i, j) : i, j = 1, ....6}

Now, with each of these 36 elements associate values of two random variables, X₁ and X₂, such that;

X₁ ≡ sum of the outcomes on the two dice.

X₂ ≡ |difference of the outcomes on the two dice|

That is;

X(ω_ij) = X₁(ω_ij) + X₂(ω_ij) = (i + j, |i - j|) i, j = 1, 2, ...., 6

Then, the bivariate rv X = (X₁, X₂) has the following joint probability mass

function (empty cells mean that the pmf is equal to zero at the relevant values of the rvs).

The joint probability mass function is seen in the attached file.

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Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetrically distributed around the mean. Roughly 68% of the patients had serum cholesterol level between 175 mg/dl and 205 mg/dl. a. Calculate the standard error b. What will be the range of 95% confidence interval?

Answers

The standard error is 1.5.

The range of 95% confidence interval is 160 mg/dL and 220 mg/dL

What is the standard error of the distribution?

The standard error of the distribution is calculated as follows:

Standard error = standard deviation/√N

where N is the number of participants = 100

From the empirical rule of a normal or symmetrical distribution;

68% of the data lies within one standard deviation95% percent within two standard deviations, and99.7% within three standard deviations from the mean.

Therefore,  175 mg/dl and 205 mg/dl lie one standard deviation from the mean.

One standard deviation = 175 - 190 or 205 - 190 = ±15

Standard deviation = 15

a. Solving for the standard error using the equation above;

Standard error = 15/√100

Standard error = 1.5

b. The range of 95% confidence interval is two standard deviations away from the mean.

Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)

Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL

Therefore, the range of 95% confidence interval is 160 mg/dL and 220 mg/dL

In conclusion, the standard error is calculated from the standard deviation and the sample size.

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All the actresses brought (her, their) scripts

Answers

Answer:

their

Explanation:

Lets highlight the keywords in this sentence.

All the actresses brought (her, their) scripts.

The words all and actresses are telling you that there are more than 1 actress, so we will refer to them as 'their'.

Astronauts in space can travel around the earth in about:

Answers

Astronauts in space can travel around the earth in about 12 hours.

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 426 gram setting. Based on a 13 bag sample where the mean is 433 grams and the standard deviation is 29, is there sufficient evidence at the 0.05 level that the bags are overfilled? Assume the population distribution is approximately normal.

Answers

The conclusion of the research is that we reject the null hypothesis and we conclude that the bag filling machine does not work correctly at the 426 gram setting.

How to solve hypothesis testing?

We are given;

Population Mean; μ = 426

Sample mean; x' = 433

Sample size; n = 13

Standard deviation; s = 29

significance level; α = 0.05

Let us define the hypotheses;

Null Hypothesis; H₀: μ = 426 g

Alternative Hypothesis; H_a: μ < 426 g

Formula for the z-score here is;

z = (x' - μ)/(s/√n)

z = (433 - 426)/(29/√13)

z = 0.87

From online p-value from z-score calculator, we have;

p-value =  0.1922

This p-value is greater than the significance value and as such we reject the null hypothesis and we conclude that the bag filling machine does not work correctly at the 426 gram setting.

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1. A box contains six identical balls, numbered from 1 to 6. One ball is randomly selected from the box. What is the probability that the ball will show a 5?​

Answers

Answer:

The probability of ball 5=1/6

Explanation:

This is because in 1 to 6, there is only one 5 numbered ball out of the total number of balls which is 6.

Which of the following is the best way to improve human capital?

Answers

You've asked an incomplete question. However, one of the best ways to improve human capital is often linked to increasing access to education.

What is human capital?

The term human capital is often used to describe valuable skills or talents that can be acquired or possessed by people which if utilized properly can help improve workplace efficiency. Hence increased access to education can go a long way to improve human capital. For example, providing access to receive technical training in software engineering, has often been ranked as one of the best ways to improve human capital.

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The sum of three numbers is 100. The second number is 2 times the third. The third number is 8 less than the first. What are the numbers?

Answers

Answer:

19, 54 and 27

Explanation:

54 is 2 times of 27 and 27-8=19

19+54+27=100

Part A: Explain the meaning of these terms and how each relates to the scientific method.
1. Variables
2. Demand characteristic
3. Theory
4. Experiment
5. Data
6. Hypothesis
7. Case study
8. Dependent variable
9. Survey
10. Naturalistic
11. Design
12. Stimulus
13. Independent variable
14. Control group
15. Conclusion
16. random
ont describes part of the design, theory, variable or a hypothesis of

Answers

Below is the meaning of each term and how each relates to the scientific method:

Variables can be understood as a concept that expresses a value, classification or measure in scientific research.Demand characteristics relate to the needs and interest in scientific research.Theory is the set of untested arguments that justify information.Experiment is a systematic way of exploring data and information, for the accomplishment of the scientific study.Data is a set of research records that serve as the basis for a scientific study.Hypothesis is an assertion about a research question, proposing an expected result.Case study is the explanation of real phenomena through the collection and demonstration of qualitative data.Dependent variable is the factor that changes in relation to the manipulation of the independent variable.Survey is a research method to collect qualitative and quantitative data and information that will inform the research.Naturalistic is a theory about the knowledge of the world and its phenomena explained through the scientific method.Design is the scientific method whose purpose is the development of products and services to enhance the human experience.Stimulus are items of different natures used to promote a reaction of the components of a scientific study.Independent variable is the variable manipulated in a scientific study for the purposes of analysis and observation.Control group are groups that serve as parameters for the results of a research, not being manipulated, only compared.Conclusion the final part of the work, the synthesis of the considerations found through the testing of the theory and hypothesis.Random a choice from a representative sample of a larger population in a study.What is scientific methodology?

It is a set of methods and techniques structured and organized in a complex way to test a theory, find new concepts and knowledge through research, study, experimentation and analysis.

Therefore, the scientific methodology helps the development of society through the production of reliable and tested knowledge in order to assist in social and technological progress.

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To receive credit fWhich of the following can you use during a quiz?

Question 4 options:

a)

Notes

b)

Textbook

c)

Both A or B

d)

You cannot use the textbook or notes on a quiz.or a course, your overall average must be above?

Answers

Answer:

D

Explanation:

you can't use textbook or note on a quiz

I delined one of my high school offeres, and accepted to go to discovery program, and fail the discovery program what can I do?

Answers

Answer:

I don't know

Explanation:

I don't know

sorry for it ;

I am really sorry

bona has a stated reaction to a sound of a loud < >. immediately before the loud pop, a light flashes. after several times. Bona has started reaction to the flash of lighy. What is UCS? What is CR? What is NS? What is UCR?

Answers

The UCS is known to be the loud pop

What is CR?

The CR is known to be  a light flashes

What is NS?

The NS is the reaction  of bona

What is UCR?

The UCR  flash of light.

What is an unconditioned response?

In classical conditioning, an unconditioned response is known to be that behavior that is said to be unlearned response that takes place as a sort of natural  reaction to the unconditioned stimulus.

Hence, The UCS is known to be the loud pop.

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Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Find the values of d and s.. In general, what does
represent?
Temperature (°F) at 8 AM 98.4 98.7 97.5 97.3
97.1
Temperature (°F) at 12 AM 99.0 99.3 97.9 96.9 97.5
Let the temperature at 8 AM be the first sample, and the temperature at 12 AM be the second sample. Find the values of d and s..
d=
(Type an integer or a decimal. Do not round.)

Answers

The mean of the temperature based on the information given is -3.2.

How to calculate the mean?

The difference in the temperature based on the information will be:

98.4 - 99.0 = -0.6

98.7 - 99.3 = -0.6

97.5 - 97.9 = -0.4

97.3 - 96.9 = 0.4

97.1 - 97.5 = -0.4

Total = -1.6

The mean will be:

= -1.6/5

= -3.2

Also, the standard deviation is 2.8. This simony illustrates how spread the numbers are in the information given.

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in a clinical trial, 28 out of 888 patients taking a prescription drug daily complained of flulike symptoms. suppose that it is known that 2.8% of the patients taking competing drugs complain of flulike symptoms. is there sufficient evidence to conclude that more than 2.8% of this drug's user experience flulike symptoms as a side effect at the aplha 0.05 level of significance

Answers

The p-value (0.0001) is less than α = 0.05. Based on this, we should reject the null hypothesis.

What is a null hypothesis?

A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.

How to calculate value of the test statistic?

The test statistic can be calculated by using this formula:

[tex]t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }[/tex]

Where:

x is the sample mean.u is the mean.is the standard deviation.n is the number of hours.

For this clinical trial (study), we should use a t-test and the null and alternative hypotheses would be given by:

H₀: p = 0.028

H₁: p > 0.028

For the sample proportion, we have:

Sample proportion, P = 28/888

Sample proportion, P = 0.032.

Next, we would calculate the t-test as follows:

[tex]t=\frac{0.032\;-\;0.028}{\frac{0.02 \times 0.028}{888 } }\\\\t=\frac{0.004}{\sqrt{\frac{0.00056}{888 } }}[/tex]

t = 0.004/0.00079

t-test, t = 5.06.

For the p-value, we have:

P-value = P(t > 5.06)

P-value = 1 - P(t < 5.06)

P-value = 1 - 0.9999

P-value = 0.0001.

Therefore, the p-value (0.0001) is less than α = 0.05. Based on this, we should reject the null hypothesis.

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