Today, Stephen is three times as old as Gautham. Ten years ago Stephen turned 2. How old will Gautham be
in 8 years?

Answer:

35x71+71x65+51x23+23+49=8,345

Step-by-step explanation:

Answer:

8345

Is the correct answer

Step-by-step explanation:

hope it will help you

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The scoring guide assign points to special degrees of student performance. Instructors use them when a scholar's response can earn a number of the full possible factors, commonly for built-reaction items and performance responsibilities.

Rubrics and scoring guides were implemented into cutting-edge classrooms to offer college students higher know-how of what's being assessed, what standards grades are primarily based upon, and what clean and compelling product standards are addressed.

Even as scoring guides illustrate how college students can earn a certain amount of points for precise questions and responses, rubrics assign ratings primarily based on how well a pupil's reaction meets a degree of overall performance.

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Answer:

(0, -5/2).

Step-by-step explanation:

The coordinates of the mid point of (x1, y1) and (x2, y2) are

(x 1 + x2)/2 , (y1 + y2)/ 2

So here we have:

(-3 + 3)/ 2, (-4 + -1)/2

= 0/2, -5/2

= (0, -5/2).

The minimum and maximum values are (16/9)√3  and -(16/9)√3.

According to the statement

we have given that the function

First of all, since the constraint's graph is a circle, which is a closed loop, and f is continuous in [tex]R^2[/tex], there must exist a constrained global maximum and minimum value.

Lagrange Multipliers:

f(x,y) = xy^2

g(x,y) = x^2 + y^2

We want ∇f = λ∇g so we get the following system of equations

1. y^2 = 2λx

2. 2xy = 2λy

3. x^2 + y^2 = 4 ← The constraint.

Equation 2 implies that y = 0 or λ = x

We can ignore y = 0, since that will make f(x,y) = 0 and clearly f(x,y) takes on both positive and negative values subject to the constraint.

Plugging in the alternative, λ = x to equation 1 gives y^2 = 2x^2.

Plugging this into the constraint gives 3x^2 = 4 so that x^2 = 4/3 and y^2 = 8/3

Taking square roots gives

x = ±√(4/3) = ±(2/3)√3

y = ±√(8/3) = ±(2/3)√6

At the points < (2/3)√3 , ±(2/3)√6 >, f(x,y) = (16/9)√3 ← Maximum

At the points < -(2/3)√3 , ±(2/3)√6 >, f(x,y) = -(16/9)√3 ← Minimum

So, The minimum and maximum values are (16/9)√3  and -(16/9)√3.

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Answer:

The amount of unexplained variance in a relationship between two variables is called: coefficient of alienation also called coefficient of nondetermination. A positive correlation between two variables would be represented in a scatterplot as. line sloping upwards. .

Step-by-step explanation:

Answer:

(-4, -18).

Step-by-step explanation:

f(x = x^2 + 8x - 2         Completing the square on x^2 + 8x:-

     = (x + 4)^2 - 16 - 2

     = (x + 4)^2 - 18

- which is the vertex form of f(x)

The vertex of

(x - h)^2 + k  is at (h, k)

So the vertex of f(x) is at (-4, -18)

Answer: a = 24 units²

Step-by-step explanation:

      Let us graph the figure given. This shape appears to be a trapezoid. Now, we can solve for the area. This shape also has a height of 4, which I forgot to show in the picture.

       In the formula, h is the height, a is a base, and b is the other base.

            [tex]\displaystyle a=\frac{a+b}{2} h[/tex]

            [tex]\displaystyle a=\frac{4+8}{2} 4[/tex]

            [tex]\displaystyle a=\frac{12}{2} 4[/tex]

            [tex]\displaystyle a=(6)4[/tex]

            [tex]\displaystyle a=24\; \text{units}^{2}[/tex]

The second-order equation as its equivalent system of first-order equations is

[tex]\left[\begin{array}{ccc}u(1)\\\\v(1)\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}7.5\\\\9\end{array}\right][/tex]

An equivalent system that has the identical answer is known as an equivalent structure. Given a gadget of two equations, we can produce an equal system by way of replacing one equation by means of the sum of the 2 equations, or by way of changing an equation by means of a couple of of itself.

Systems of linear equations are equivalent if and handiest in the event that they have an equal set of solutions. In other phrases, two systems are equal if and only if each answer of one in all of them is likewise a solution of the opposite.

In the structures sciences, a machine equivalent system is the conduct of a parameter or thing of a machine in a way just like a parameter or component of a distinctive system. Similarity means that mathematically the parameters and additives will be indistinguishable from each different.

Taking v = u, we have:

u" + 4u' + 6u = 4sin(3t)

--> v' + 4v + 6u = 4sin(3t)

So the system of equations is:

u' = 0u + 1v

v' = -6u - 4v + 4sin(3t)

So we can write it as:

u(1) = 7.5

v(1) = u'(1) = 9

So the initial condition matrix is:

[tex]\left[\begin{array}{ccc}u(1)\\\\v(1)\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}7.5\\\\9\end{array}\right][/tex]

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Answer: Vertical: angles ABF and DBE. Adjacent: angles ABC and CBD

Step-by-step explanation:

vertical angles are angles that share a common point. they are right across from each other, and in this case, share point B. adjacent angles are angles that are directly next to each other, and share a line or segment. in this case, the two angles share the segment BC. hope this helps.

We are required to fill in the solution to the question that we have here.

this is done below

Six pyramids are shown inside of a cube. The height of the cube is h units. The lengths of the sides of the cube are b. The area of the base of the cube,

B, is (b)*(b) square units.

The volume of the cube is (b)*(b)*(b) cubic units.

The height of each pyramid, h, is  b/2

b = 2h.

There are 6 square pyramids with the same base and height that exactly fill the given cube.

Therefore, the volume of one pyramid is (1/6)(b)(b)(2h)

or One-third Bh.

This is the term that is used to refer to the shape that is known to have a square base and the base could also be triangular. The parts of the base are known to have a connection at the top of the pyramid.

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answer is in the attachment below :)

goodluck!!

This might help a bit, i hope

Values of c and d make the equation true are c=6, d=2

Equations

                                [tex]\sqrt[3]{162x^{c}y^{5} } = 3x^{2} y^{3} \sqrt[3]{6y^{d} }[/tex]

                               [tex](\sqrt[3]{162x^{c}y^{5} })^{3} = (3x^{2} y^{3} \sqrt[3]{6y^{d} })^{3}[/tex]

                                 [tex]{162x^{c}y^{5} } = (3x^{2} y^{3} \sqrt[3]{6y^{d} })^{3}[/tex]

                                  [tex]{162x^{c}y^{5} } = 27x^{6} y^{3} ({6y^{d})[/tex]

                                     [tex]{x^{c}y^{5} } = x^{6} y^{3} ({y^{d})[/tex]

                                     [tex]{x^{c}y^{5} } = x^{6} y^{3+d}[/tex]

                                   c = 6

                                   d = 2

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From the given options we can say that the only one that represents the area of the sector is; A = n/360 * πr²

In circles, a sector is said to be a part of a circle made of the arc of the circle together with its two radii. This means that it is a portion of the circle formed by a portion of the circumference (arc) and radii of the circle at both endpoints of the arc.

The formula for Area of a sector is given as;

θ/360 * πr²

where;

θ is the central angle of the sector

r is radius

Now, looking at the given options we can say that the only one that represents the area of the sector is;

A = n/360 * πr²

where n is the central angle of the sector

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Answer:

A!

Step-by-step explanation:

Answer:

=> Equilateral Triangle

Step-by-step explanation:

Equilateral Triangle is having 2-d shape with all equal sides and the sum of angles of any triangle is 180° .

Answer:

Step-by-step explanation:

a. d^2 - 7d + 6 = 0

(d - 1)(d - 6) = 0

d - 1 = 0,  d - 6 = 0 therefore:

d = 1,  6.

b, x^2 + 18x + 81 = 0

(x + 9)(x + 9) = 0

x = -9  multiplicity 2.

c   u^2 + 7u - 60 = 0

(u + 12)(u - 5) = 0

u = -12, 5.

The value of x from the given diagram is 20

According to theorem, the right triangle altitude theorem is a result in elementary geometry that describes a relation between the altitude on the hypotenuse in a right triangle and the two line segments it creates on the hypotenuse.

Using the theorem above;

RT^2 = 9 * 16

RT^2 = 144

R = 12 units

Determine the value of x using the Pythagoras theorem;

x² =12² + 16²

x² = 144 + 256

x² = 400

Take the square root of both sides

x = √400

x = 20

Hence the value of x from the given diagram is 20

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[tex]-2(-1+2w)[/tex]

distribute

[tex]2-4w[/tex]

put in standard form

[tex]-4w+2[/tex]

Answer:

x = 8

y = -3

Step-by-step explanation:

Multiply the first equation with (-2)

(-2) * (x - 4y) = 20

-2x + 8y = -40 now find the sum of it with second equation

2x + 5y - 2x + 8y = 1 - 40 add like terms (2x will eliminate -2x)

13y = -39 divide both sides by 13

y = -3

Now we can use this to find the value of x

x - 4y = 20 rewrite the equation using the value we found for y

x - 4(-3) = 20 multiply (-4) and (*3) (product will be positive because we are multiplying two negatives)

x + 12 = 20 subtract 12 from both sides

x = 8

Step-by-step explanation:

To find the Tth term of an arithmetic progression, you should use the formula: Tn: a + (n-1)d, whereby 'a' is the first term, you have to find 'n' and 'd' is the difference between the first 2 numbers to find out by how much the arithmetic progression is increasing or decreasing. Hence, 29/30 minus 4/5 equals to 1/6. 'a' is 4/5 and 'd' is 1/6.

Use the above formula by replace a and d then you'll get the answer. Hope this helps.

Her profit % was increased by 2.77%

Answer:

Solution Given:

discount =10%

profit =25%

S.P with 13% vat = Rs 5,085

S.P+Vat% of S.P= Rs 5,085

S.P(1+13%)=Rs 5,085

S.P=Rs 5,085/1.13

S.P =Rs 4,500

Again

M.P = S.P+discount% of M.P

M.P- discount% of M.P= Rs 4,500

M.P(1-10%)=Rs 4,500

M.P=Rs 4,500/0.9

M.P = Rs 5,000

Now

C.P= (S.P*100)/(1+profit%)

C.P=(4,500*100)/(100+25%)

C.P= Rs 3,600

Again

profit =S.P- C.P= Rs 4,500-Rs 3,600=Rs 900

Again

Due to the excessive demands of her items, she decreased the discount percent by 2%.

So,

New discount = 10%-2%=8%

New S.P= M.P -discount% of M.P

=M.P(1-discount%)

=Rs 5,000(1-8%)

=Rs 4,600

Again

Profit=S.P- C.P

New profit =Rs 4,600 - Rs 3,600=Rs 1,000

Profit% =profit/C.P*100%= 1000/3600*100=27.77%

Profit % increased =New profit%- profit%

=27.77-25

=2.77%

The true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

The complete question is added as an attachment

From the table, we have

Divisor = x^2 - 3x + 4

Quotient = 2x + 5

Dividend = -2x^3 + 11x^2 - 23x + 20

See that the signs of the leading coefficients of the dividend and the divisor are different

This means that the leading coefficient of the quotient must be negative

From the question, we have:

Quotient = 2x + 5

The expression 2x + 5 has a positive leading coefficient

Hence, the true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

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Answer:

Step-by-step explanatio

Step-by-step explanation:

i donot know

sorry about this

By the comparison test, the series converges.

We have

[tex]\dfrac1{k\sqrt{k+2}} \le \dfrac1{k \sqrt k} = \dfrac1{k^{3/2}}[/tex]

so we can compare to a convergent [tex]p[/tex]-series,

[tex]\displaystyle \sum_{k=1}^\infty \frac1{k\sqrt{k+2}} \le \sum_{k=1}^\infty \frac1{k^{3/2}} < \infty[/tex]

By the comparison test, the series converges.

What are convergence series and diverging series?

If the infinite series converges to a real number it is called converging if not then it is called diverging series.

If the larger series is convergent the smaller series must also be convergent. Likewise, if the smaller series is divergent then the larger series must also be divergent.

For this series to be converging it must follow the following :

⇒ [tex]| \frac{t_{n+1} }{t_{n} } | \leq 1[/tex]

⇒Putting n = 1

[tex]| \frac{t_{2} }{t_{1} } | \leq 1[/tex]

[tex]\t_{2} t_{1}[/tex] [tex]t_{2}[/tex]= 1/4

[tex]t_{1}[/tex]=1/[tex]\sqrt{2}[/tex]

[tex]\frac{t_{2} }{{t_{1} }}[/tex] = 1/2[tex]\sqrt{2[/tex]

⇒ t₂/t₁≤1

⇒ Hence it converges

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By the ratio test, the series converges for all [tex]x[/tex], since

[tex]\displaystyle \lim_{k\to\infty} \left|\frac{(k+1)^2 x^{k+4}}{(k+1)!} \cdot \frac{k!}{k^2 x^{k+3}}\right| = |x| \lim_{k\to\infty} \frac{(k+1)^2 k!}{k^2 (k+1)!} = |x| \lim_{k\to\infty} \frac1{k+1} = 0 < 1[/tex]

Then the radius of convergence is R = ∞, and the interval of convergence is the entire real line, -∞ < x < ∞.

The radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series. This can be obtained by using ratio test.  

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

[tex]\lim_{n \to \infty} | \frac{a_{n+1} }{a_{n} } |[/tex] = β

Here aₙ = (n²/n!) xⁿ⁺³  and  aₙ₊₁ = ((n+1)²/(n+1)!) xⁿ⁺¹⁺³ = ((n+1)²/(n+1)!) xⁿ⁺⁴

Now limit is taken,

[tex]\lim_{n \to \infty} | \frac{a_{n+1} }{a_{n} } |[/tex] = [tex]\lim_{n \to \infty} | \frac{((n+1)^{2} /(n+1)!) x^{n+4} }{(n^{2} /n!) x^{n+3} } |[/tex]

                      = [tex]\lim_{n \to \infty} | \frac{((n+1)^{2} ) n!x^{n+4} }{(n+1)!(n^{2} ) x^{n+3} } |[/tex]

                      = [tex]\lim_{n \to \infty} | \frac{((1+1/n)^{2} ) x }{(n+1)} |[/tex]  

                      =   [tex]\lim_{n \to \infty} | \frac{ x }{(n+1)} |[/tex]  = 0 < 1

Since the limit is less than 1 the series is converging.

We get that,

interval of convergence = (-∞, ∞)

radius of convergence R = ∞

Hence the radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series.

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Answer:

D) 14

Step-by-step explanation:

12+12+12 is 36 we don't know hold old the fourth sibling is so they are X

to get the average of 12.5 you need to add all the siblings ages then divide it by 4

(36+X)/4=14 so the other sibling is 14

Answer:

B

Step-by-step explanation:

12.5x3=37.5

37.5 +11.5 =49

49÷4 =12.25

The standard deviation exists as the positive square root of the variance.

So, the standard deviation = 6.819.

Given data set: 15, 17, 23, 5, 21, 19, 26, 4, 14

To calculate the mean of the data.

We know that mean exists as the average of the data values and exists estimated as:

Mean [tex]$=\frac{15+17+23+5+21+19+26+4+14}{9}[/tex]

Mean [tex]$=\frac{144}{9}[/tex]

Mean = 16

To estimate the difference of each data point from the mean as:

Deviation:

15 - 16 = -1

17 - 16 = 1

23 - 16 = 7

5 - 16 = -11

21 - 16 = 5

19 - 16 = 3

26 - 16 = 10

4 - 16 = -12

14 - 16 = -2

Now we have to square the above deviations we obtain:

1 , 1, 14, 121, 25, 9, 100, 144, 4

To estimate the variance of the above sets:

variance [tex]$=\frac{1+ 1+14+ 121+25+ 9+ 100+ 144+ 4}{9}[/tex]

Variance [tex]$=\frac{419}{9}[/tex]

Variance = 46.5

The standard deviation exists as the positive square root of the variance.

so, the standard deviation [tex]$\sqrt{46.5} =6.819[/tex] .

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If the pth term of an arithmetic progression is q and qth term is p then the (p+q) th term is 0.

Given that the p th term of an A.P is q aand q th term is p.

We are required to find the (p+q) th term of that A.P.

Arithmetic progression is a sequence in which all the terms have common difference between them.

N th term of an A.P.=a+(n-1)d

p th term=a+(p-1)d

q=a+(p-1)d-------1

q th term=a+(q-1)d

p=a+(q-1)d---------2

Subtract equation 2 by 1.

q-p==a+(p-1)d-a-(q-1)d

q-p=pd-qd-d+d

q-p=d(p-q)

d=(p-q)/(q-p)

d=-(p-q)/(p-q)

d=-1

Put the value of d in 1.

q=a+(p-1)(-1)

q=a-p+1

a=q+p-1

(p+q) th term=a+(n-1)d

=q+p-1+(p+q-1)(-1)

=q+p-1-p-q+1

=0

Hence if the pth term of an A.P is q and qth term is p then the (p+q) th term is 0.

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The value of x from the given diagram is -10

Two triangles are known to be similar if the ratio of their similar sides is equal. The diagram shown is similar to the required diagram.

Given the following parameters

<ABC = 2x

<BAC = 3x + 10

Equate the expression since both angles are equal. Substitute;

2x = 3x + 10

Subtract 3x from both sides

2x-3x = 3x-3x+10

-x = 10

x = -10

Hence the value of x from the given diagram is -10

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