An aircraft which is located 30 miles from a vor station and shows a 1/2 scale deflection on the cdi would be how far from the selected course centerline?

Answer:

Explanation:

Formula

Voltage_p * Current_p = Voltage_s * Current_s

Comment

What the formula means is the voltage multiplied by the current in the primary = voltage multiplied by the current in the secondary.

Givens

Vp =100 v

Ip = 6 amps

Vs = x

Is = 0.75 amps

Solution

100 * 6 = 0.75* x

600 = 0.75 x                  Divide both sides by 0.75

600/0,75 = 0.75x/0.75

800v = x

What you have here is a step up transformer. It has a relatively small voltage (100 volts ) on the primary which the transformer changes to 800 volts in the secondary.

Answer

800 volts.

The differential equation x · y' + y² = 0 in differential form is x · dy + y² · dx = 0.

The standard form of the differential equation (y')² - 5 · (y') + 6 = (x + y) · (y' - 2) is the equation y' - y - 3 = x.

In the first part of this problem we have a nonlinear diferential equation of the form f(x, y, y') = 0, which has to be changed into diferential form, defined below:

M(x, y) dx + N(x, y) dy = 0, where y' = dy / dx.      (1)

Now we proceed to work on the ordinary differential equation:

x · y' + y² = 0

x · y' = - y²

x · (dy / dx) = - y²

x · dy = - y² · dx

x · dy + y² · dx = 0

The differential equation x · y' + y² = 0 in differential form is x · dy + y² · dx = 0.

The second part of the problem involves another nonlinear differential equation, of which we must find its standard form, also defined below:

f(y', y) = g(x)         (2)

Finally, we proceed to modify the equation:

(y')² - 5 · (y') + 6 = (x + y) · (y' - 2)

(y' - 3) · (y' - 2) = (x + y) · (y' - 2)

y' - 3 = x + y

y' - y - 3 = x

The standard form of the differential equation (y')² - 5 · (y') + 6 = (x + y) · (y' - 2) is the equation y' - y - 3 = x.

The statement presents typing mistakes, correct form is shown below:

3. Write the differential equation x · y' + y² = 0 in differential form. Write the differential equation (y')² - 5 · y' + 6 = (x + y) · (y' - 2).

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Answer:

Between 35°– 45°

Explanation:

In the vertical position, Point the flame in the direction of travel. Keep the flame tip at the correct height above the base metal. An angle of 35°–45° should be maintained between the torch tip and the base metal. This angle may be varied up or down to heat or cool the weld pool if it is too narrow or too wide

a. The maximum thickness of the copper nozzle is 0.33 cm

b. The maximum thickness of the steel nozzle is 0.054 cm

c. The material preferred is steel

The is a heat transfer question

Heat transfer is the movement of thermal energy from one body to the other.

We know that the rate of heat loss by the gas equals rate of heat gain by the metal.

The rate of heat loss by gas is P₁ = -hA(T₂ - T₁) where

The rate of heat gain by metal is P₂ = kA(T₂ - T₃)/d where

Given that P₁ = P₂, we can write

-hA(T - T') =  kA(T - T")/d

So we make d subject of the formula, thus

t = -k(T₂ - T₃)/h(T₂ - T₁)

We know that for copper

Substituting the values of the variables into d, we have

d = -k(T₂ - T₃)/h(T₂ - T₁)

d = -378 W/m-K(540°C - 150°C)/[2 × 10⁴ W/m²-K(540°C - 2750°C)]

d = -378 W/m-K(390°C)/[2 × 10⁴ W/m²-K(-2210°C)]

d = -147420 W/m/-4420 × 10⁴ W/m²

d = 147420 W/m/44200000 W/m²

d = 0.0033 m

d = 0.33 cm

So, the maximum thickness of the copper nozzle is 0.33 cm

We know that for steel

Substituting the values of the variables into d, we have

d = -k(T₂ - T₃)/h(T₂ - T₁)

d = -23.2 W/m-K(980°C - 150°C)/[2 × 10⁴ W/m²-K(980°C - 2750°C)]

d = -23.2 W/m-K(830°C)/[2 × 10⁴ W/m²-K(-1770°C)]

d = -19256 W/m/-3540 × 10⁴ W/m²

d = 19256 W/m/35400000 W/m²

d = 0.00054 m

d = 0.054 cm

So, the maximum thickness of the steel nozzle is 0.054 cm

Since the steel nozzle has a thickness of 0.054 cm while the copper nozzle has a thickness of 0.33 cm, we see that the thickness of the steel nozzle is less. So, the steel is preffered.

So, the material preferred is steel

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The phase of the engineering design process which should be completed next is to test their work and is denoted as option C.

These are the series of steps and techniques which are done by individuals in the making of functional product and services.This employs the use of scientific methods and also ensures an easier living for different individuals.

The first stage involves identifying the problem and then building a prototype through the use of different materials. This is then tested before the final finishing work is done to ensure the parts are properly placed before they are moved for evaluation by other people.

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The cooling system removes and reduces the heat caused by friction between the moving engine parts and the explosion of fuel in the cylinders. The correct option is d)

The cooling system is a system that works on engines of machines and cars. It prevents friction for the parts of the engine that are moving and runs a smooth machine.

It also prevents the heating of the machines. Furthermore, it is like a liquid coolant that cools the machines and prevents overheating.

Thus, the correct option is d) cooling.

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The question is incomplete. Your most probably complete question is given below:

a) steering

b) brake

c) suspension

d) cooling

Answer:

After 5 minutes, set the indicator to the magnetic heading of the aircraft and check for proper alignment after taxi turns.

Explanation:

The pretakeoff check is that;

After 5 minutes, set the indicator to the magnetic heading of the aircraft and check for proper alignment after taxi turns.

Perform pre-flight checks on the vacuum-driven heading indicator, including the power source, zero setting, gyro drift, and accurate operation before an IFR flight.

We have,

Before a flight, especially for IFR (Instrument Flight Rules) operations, it's crucial to conduct a thorough pre-flight check of the vacuum-driven heading indicator, also known as the directional gyro or DG.

The heading indicator is a crucial instrument for maintaining proper heading during flight. Here are the key checks to perform:

- Power and Vacuum Source:

Ensure that the aircraft's vacuum system is functioning correctly and providing adequate suction to power the heading indicator.

Verify that the vacuum system pressure is within the manufacturer's specified range.

- Instrument and Case Inspection:

Visually inspect the heading indicator and its case for any signs of damage, cracks, or loose fittings.

Make sure the instrument's glass is clean and clear for easy readability.

- Zero Setting:

Set the heading indicator to the correct heading using the aircraft's magnetic compass or another reliable heading reference. This process is known as "synchronizing" the heading indicator.

- Gyro Drift Check:

- Operation Check:

Thus,

Perform pre-flight checks on the vacuum-driven heading indicator, including the power source, zero setting, gyro drift, and accurate operation before an IFR flight.

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The maximum cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors is 10 cubic inches.

A current-carrying conductor is a conductor that experience a force when it is in a magnetic field, due to the interaction between the magnetic field & the field (magnetic) produced by moving charges in the wire.

The HHN stands for High Heat-resistant Nylon-coated.

The maximum cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors is calculated as follows;

cubic inch space = 4 x 2.5 in³

cubic inch space = 10 in³

Thus, the maximum cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors is 10 cubic inches.

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The design speed was used for the freeway exit ramp is 11 mph.

The design speed used in the exit ramp is calculated as follows;

f = v²/15R - 0.01e

where;

v = ωr

v = (θ/t) r

θ = 90⁰ = 1.57 rad

v = (1.57 x 19.4)/2.5 s

v = 12.18 ft/s = 8.3 mph

f = v²/15R - 0.01e

let the maximum superelevation, e = 1%

f = (8.3)²/(15 x 19.4) - 0.01

f = 0.22

0.22 is less than value of f which is 0.4

f = (10)²/(15 x 19.4) - 0.01

f = 0.33

0.33 is less than 0.4

f = (11)²/(15 x 19.4) - 0.01

f = 0.4

Thus, the design speed was used for the freeway exit ramp is 11 mph.

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Engineering ethics is not without abstraction, but in contrast with computing, it is animated by a robust and active movement concerned with the seamless identification of ethics with practice.

This is a branch of science and technology concerned with the design, building, and use of engines, machines, and structures that uses scientific principles.

Comparing ethics in engineering and ethics in computing:

Some practical examples in the computing field:

Some practical examples in the engineering field:

Hence, Engineering ethics is the field of system of moral principles that apply to the practice of engineering and following them is important to the profession.

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Answer: Dampness or moisture introduces hydrogen into the weld, which causes cracking when some metals are welded.

Explanation:

This moisture (hydrogen) is a major cause of weld cracking and porosity.

When a room becomes so hot that everything in it ignites simultaneously it is termed a flashover.

In a confined space, a flashover occurs when the majority of the directly exposed flammable material ignites almost simultaneously. Certain organic compounds go through thermal decomposition when heated and emit combustible gases as a result.

Every flammable surface exposed to thermal radiation in a compartment or confined space ignites quickly and simultaneously during a flashover, a thermally driven event. For typical combustibles, flashover typically happens when the upper section of the compartment achieves a temperature of about 1,100 °F.

Flashover circumstances are more likely to occur in buildings with hidden compartments, lower ceiling heights, room partitions, and energy-efficient or hurricane windows.

Therefore, the sudden ignition of everything in the room is called a flashover.

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Since you notified the company that they were out of compliance with MS licensing requirement, and got no got no response. one can:

The Microsoft Services Provider License Agreement ("SPLA") is known to be a kind of a program that is made to target a lot of service providers and also those of Independent Software Vendors ("ISVs").

This is known to be the v that is given to their partners to give their software services and that of their hosted applications to the end customers.

Based on the above, Since you notified the company that they were out of compliance with MS licensing requirement, and got no got no response. one can:

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Answer:open circuit

short circuit

voc

Explanation:

One of the simple ways to create a run chart is:

This refers to the line chart that is plotted over time and displays observed data in a time sequence.

Hence, we can see that the simple tutorial on how to create a run chart with the use of an Excel Spreadsheet is given above.

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Answer:

Direct Control Electrode Negative) (DCEN)

Explanation:

The type of current that flows from the electrode across the arc to the work is called direct current electrode is called DCEN.

Answer:if power factor =1 is possible for that.

Explanation:when pf is unity. means 1.

Answer:

multimeter

Explanation: in parallel

Answer:2.88 ohms

Explanation:

R= V^2 / P

12^2/50

144/50

2.88 ohms

Answer:

faster

Explanation:

because in a big grinder you ca only grind bigger things but not Small things , some parts of your things that will

remain as they were in the beginning, so it will take more time to grind Small things .

Answer:

A: True

Explanation:

The given statement is true.

During welding in the vertical position, the torch angle is not typically varied to control sagging. This statement is False.

Sagging, also known as downward distortion, occurs when the molten metal in the weld pool pulls downward due to gravity.

To control sagging, the primary method is to adjust the welding parameters, such as the welding current, travel speed, and electrode angle, rather than the torch angle.

Maintaining a proper travel speed and using appropriate welding techniques, such as weaving, can also help to manage sagging.

Ensuring proper joint preparation and fit-up, as well as using suitable welding procedures, are crucial in minimizing sagging and achieving high-quality vertical welds.

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Answer:

Electrode Holder

Explanation:

Shielded metal arc welding (SMAW), also known as manual metal arc welding, is a manual arc welding process that uses a consumable and protected electrode. As the electrode melts, a cover that protects the electrode melts and protects the weld area from oxygen and other atmospheric gases

Using the knowledge in computational language in python it is possible to write a code that was fixed;

from random import randint

class Character:

   def __init__(self):

       self.name = ""

       self.health = 1

       self.health_max = 1

   def do_damage(self, enemy):

       damage = min(

           max(randint(0, self.health) - randint(0, enemy.health), 0),

           enemy.health)

       enemy.health = enemy.health - damage

       if damage == 0:

           print("%s evades %s's attack." % (enemy.name, self.name))

       else:

           print("%s hurts %s!" % (self.name, enemy.name))

       return enemy.health <= 0

class Enemy(Character):

   def __init__(self, player):

       Character.__init__(self)

       self.name = 'a goblin'

       self.health = randint(1, player.health)

class Player(Character):

   def __init__(self):

       Character.__init__(self)

       self.state = 'normal'

       self.health = 10

       self.health_max = 10

   def quit(self):

       print(

           "%s can't find the way back home, and dies of starvation.\nR.I.P." % self.name)

       self.health = 0

   def help(self): print(Commands.keys())

   def status(self): print("%s's health: %d/%d" %

                           (self.name, self.health, self.health_max))

   def tired(self):

       print("%s feels tired." % self.name)

       self.health = max(1, self.health - 1)

   def rest(self):

       if self.state != 'normal':

           print("%s can't rest now!" % self.name)

           self.enemy_attacks()

       else:

           print("%s rests." % self.name)

           if randint(0, 1):

               self.enemy = Enemy(self)

               print("%s is rudely awakened by %s!" %

                     (self.name, self.enemy.name))

               self.state = 'fight'

               self.enemy_attacks()

           else:

               if self.health < self.health_max:

                   self.health = self.health + 1

               else:

                   print("%s slept too much." % self.name)

                   self.health = self.health - 1

   def explore(self):

       if self.state != 'normal':

           print("%s is too busy right now!" % self.name)

           self.enemy_attacks()

       else:

           print("%s explores a twisty passage." % self.name)

           if randint(0, 1):

               self.enemy = Enemy(self)

               print("%s encounters %s!" % (self.name, self.enemy.name))

               self.state = 'fight'

           else:

               if randint(0, 1):

                   self.tired()

   def flee(self):

       if self.state != 'fight':

           print("%s runs in circles for a while." % self.name)

           self.tired()

       else:

           if randint(1, self.health + 5) > randint(1, self.enemy.health):

               print("%s flees from %s." % (self.name, self.enemy.name))

               self.enemy = None

               self.state = 'normal'

           else:

               print("%s couldn't escape from %s!" %

                     (self.name, self.enemy.name))

               self.enemy_attacks()

   def attack(self):

       if self.state != 'fight':

           print("%s swats the air, without notable results." % self.name)

           self.tired()

       else:

           if self.do_damage(self.enemy):

               print("%s executes %s!" % (self.name, self.enemy.name))

               self.enemy = None

               self.state = 'normal'

               if randint(0, self.health) < 10:

                   self.health = self.health + 1

                   self.health_max = self.health_max + 1

                   print("%s feels stronger!" % self.name)

           else:

               self.enemy_attacks()

   def enemy_attacks(self):

       if self.enemy.do_damage(self):

           print("%s was slaughtered by %s!!!\nR.I.P." %

                 (self.name, self.enemy.name))

Commands = {

   'quit': Player.quit,

   'help': Player.help,

   'status': Player.status,

   'rest': Player.rest,

   'explore': Player.explore,

   'flee': Player.flee,

   'attack': Player.attack,

}

p = Player()

p.name = input("What is your character's name? ")

print("(type help to get a list of actions)\n")

print("%s enters a dark cave, searching for adventure." % p.name)

while(p.health > 0):

   line = input("> ")

   args = line.split()

   if len(args) > 0:

       commandFound = False

       for c in Commands.keys():

           if args[0] == c[:len(args[0])]:

               Commands[c](p)

               commandFound = True

               break

       if not commandFound:

           print("%s doesn't understand the suggestion." % p.name)

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Answer:

pf=kw/kvar

Explanation: voltage p=vi

The regulator is closed when the adjusting screw is turned in (clockwise), this statement is false.

Monitoring adherence to other legal and regulatory standards as well as contractual responsibilities to the government and users. establishing technical, safety, and quality requirements and ensuring that they are followed (if not already specified in the contract agreements). levying fines in the event of non-compliance.

The principal oversight organization for a bank or other financial institution is known as a primary regulator. Primary regulators are state or federal regulatory organizations, which are frequently the same organization that granted the financial institution's operating permit with a charter.

Hence, The regulator is closed when the adjusting screw is turned in (clockwise), it is turned Anticlockwise.

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A pilot reports that when the hydraulic pump is running, the pressure is normal. However, when the pump is stopped, no hydraulic pressure is available. This is an indication of a leaking accumulator air valve

This is further explained below.

Generally, An accumulator of the bladder type is a metal tank that houses a rubber bladder that is filled with compressed gas. This form of the accumulator is also sometimes referred to as a hydro-pneumatic accumulator. In addition, the discharge port has a poppet valve, and the gas valve that is used to precharge the bladder has its own separate valve.

In conclusion, When the hydraulic pump is operating normally, according to the report of a pilot, the pressure is normal. On the other hand, there is no hydraulic pressure available when the pump is turned off. The presence of this symptom is evidence of a leaky accumulator air valve.

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Answer:

the answer to this is 6 times.

Answer: Compact Disc

Answer:

Put on your right turn signal