Alonso brings \$21$21dollar sign, 21 to the market to buy eggs and avocados. He gets eggs that cost \$2.50$2.50dollar sign, 2, point, 50. Then, he notices that the store only sells avocados in bags of 333 for \$5$5dollar sign, 5. He wants to buy as many avocados as he can with his remaining money.


How do u get 3 bags of avacodes or 9 avacadoes ??

Answer:

  (c)  f(g(3)) > g(f(3))

Step-by-step explanation:

The relationship between the function values can be found by evaluating the functions.

The order of operations tells us we must first evaluate g(3).

  g(x) = -3x +15

  g(3) = -3(3) +15 = 6

Then we can evaluate f(x) for x=6:

  f(x) = 7x

  f(6) = 7(6) = 42

So, the composition is ...

  f(g(3)) = 42

As above, we must first evaluate f(3):

  f(3) = 7(3) = 21

Then we can evaluate g(x) for x=21:

  g(21) = -3(21) +15 = -63 +15 = -48

That means the composition is ...

  g(f(3)) = -48

The first is greater than the second.

  42 > -48

  f(g(3)) > g(f(3))

Considering the given graph, we have that:

The slope of a function, given two points, is given by the change in y divided by change in x.

When x = -3, y = -3, and while x = -2, y = -2, hence when x changes by 1, y also changes, hence the slope of the graph of the function is equal to 1 for x between x = -3 and x = -2.

When x = 3, y = 4, and when x = 4, y = 4, hence the slope of the graph is equal to 0 for x between x = 3 and x = 4.

Looking at the vertical axis:

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The total number of common tangents that can be drawn to the circles is 2.

A tangent serves as  line that touches the circle at a single point  whereby the  point where tangent meets the circle is the tangency.

A tangent to a circle can be described as the straight line  that touches the circle at only one point.

Therefore, from the definition, The total number of common tangents that can be drawn to the circles is 2.

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The true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B

The following are the properties of the sin trigonometric ratio of the function;

From the above listed deductions, we can see that the true statement about the function y = sin x is that the range which is always known as the maximum and minimum values of the function are 1 and - 1 respectively.

Thus, the true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B

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The values of b, h and k are (c) b = 2, h = -2 and k = -9

The logarithmic function is given as:

f(x) = log₂(x + 2) - 9

A logarithmic function is represented as:

f(x) = logb(x - h) + k

By comparing both equations, we have

b = 2

h = -2

k = -9

Hence, the values of b, h and k are (c) b = 2, h = -2 and k = -9

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Answer:

x=2

Step-by-step explanation:

2^x *2^4=2^3x

using law of indices

2^x+4=2^3x

x+4=3x

4=3x-x

4=2x

2=x

If you know the slope of the lines, you can also use these methods:

- see if the slopes multiplied by each other are -1 (should be if they're perpendicular)

- test if the slopes are opposite reciprocals (if they are, they are perpendicular)

Answer:

1.0954.

Step-by-step explanation:

Standard error  =  std dev / √n

=  6 / √30

= 1.0954.

Answer:

2/9 - 2/15

Solution

LCM = 45

45 ÷9 ×2 = 10

45÷ 15 ×2 = 6

10 - 6 = 4

ANSWER = 4/45

Answer:

l

Step-by-step explanation:

take the lcm of 9 and 15. it will be 45 . than continue

[tex]\sum^{\infty}_{n=1} (a/b)^n=5 \\ \\ =\frac{a/b}{1-\frac{a}{b}}=5 \\ \\ \frac{a}{b-a} =5 \\ \\ \frac{a}{b}=\frac{5}{6}[/tex]

So, we need to find

[tex]\sum^{\infty}_{n=1} n(5/6)^n

[/tex]

Let this sum be S.

Then,

[tex]S=(5/6)+2(5/6)^2 +3(5/6)^3+\cdots \\ \\ \frac{5}{6}S=(5/6)^2 + 2(5/6)^3+\cdots \\ \\ \implies \frac{1}{6}S=(5/6)+(5/6)^2+(5/6)^3+\cdots=5 \\ \\ \implies S=\boxed{30}[/tex]

The number set(s) that - 10 belong to are rational numbers, integers and real numbers. Option C, D and E

A rational number can be defined as a number expressed as the ratio of two integers, where the denominator is not be equal to zer0

- 10 can be written as = 1/ 10

Integers are whole number that could be positive, negative and even zero

- 10 is a negative whole number

Real numbers are numbers with continuous quantity that can represent  distance along a number line

-10 can represent distance along a number line.

Thus, the number set(s) that - 10 belong to are rational numbers, integers and real numbers. Option C, D and E

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The area of the shaded region in the given image is: 1,111.84 ft²

To find the area of the shaded region in the image given, find the areas of the unshaded region, then subtract it from the total area of the whole figure.

Area of the total figure = area of two semicircles + area of the rectangle.

Dimensions of the rectangle is given as, 18ft x 22ft.

Area of the rectangle = 18ft × 22ft = 396 ft²

The diameter of each of the semicircle = 7 + 7 + 18 = 32 ft

The radius of each of the semicircle = 1/2(32) = 16 ft

Area of the two semicircles = 2(1/2 × πr²) = 2(1/2 × 3.14 × 16²)

Area of the two semicircles = 803.84 ft²

Area of the rectangle = 32 × 22 = 704 ft²

The total area = 704 + 803.84

The total area = 1,507.84 ft²

The area of the shaded region = 1,507.84 - 396

The area of the shaded region = 1,111.84 ft²

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The velocity vector of the given path  r(t) = (9cos2(t), 3t - t^3, 2t) is [tex]v = 9sint\hat{i}+(3-3t^{2} )\hat{j} +2\hat{k}[/tex].

According to the given question.

We have a path

r(t) = (9cos2(t), 3t - t^3, 2t)

So, the vector form of the above vector form can be written as

[tex]r(t) = 9cos2(t)\hat{i}+ (3t - t^{3} )\hat{j} + 2t\hat{k}[/tex]

As, we know that the rate of change of position of an object is called velocity vector.

Therefore, the velocity vector of the given path r(t) = (9cos2(t), 3t - t^3, 2t) is given by

[tex]v = \frac{d(r(t))}{dt}[/tex]

[tex]\implies v = \frac{d(9cost\hat{i}+(3t-t^{3})\hat{j}+2t\hat{k} }{dt}[/tex]

[tex]\implies v = \frac{d(9cost\hat{i})}{dt} +\frac{d(3t-t^{3})\hat{j} }{dt} +\frac{d(2t)}{d(t)}[/tex]

[tex]\implies v = 9sint\hat{i}+(3-3t^{2} )\hat{j} +2\hat{k}[/tex]

Hence, the velocity vector of the given path  r(t) = (9cos2(t), 3t - t^3, 2t) is [tex]v = 9sint\hat{i}+(3-3t^{2} )\hat{j} +2\hat{k}[/tex].

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The vertex form of the equation y = -x^2 + 4x - 1 is y = -(x - 2)^2 + 3

The quadratic equation is given as:

y = -x^2 + 4x - 1

Differentiate the above quadratic equation.

This is done with respect to x by first derivative

So, we have:

y' = -2x + 4

Set the derivative to 0

-2x + 4 = 0

Subtract 4 from both sides of the equation

-2x + 4 - 4 = 0 - 4

Evaluate the difference in the above equation

-2x = -4

Divide both sides of the above equation by -2

x = 2

Rewrite as

h = 2

Substitute 2 for x in the equation y = -x^2 + 4x - 1

y = -2^2 + 4 *2 - 1

Evaluate the equation

y = 3

Rewrite as:

k = 3

A quadratic equation in vertex form is represented as:

y = a(x - h)^2 + k

So, we have:

y = a(x - 2)^2 + 3

In the equation y = -x^2 + 4x - 1, a = -1

So, we have:

y = -(x - 2)^2 + 3

Hence, the vertex form of the equation y = -x^2 + 4x - 1 is y = -(x - 2)^2 + 3

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Answer:

Step-by-step explanation:

This is a question about naming parts of a polynomial. The attached image has more on the subject.

The word "degree" refers to the number of times a variable is a factor in a term. When there is only one variable, the degree of the term is the exponent of the variable. A missing exponent is understood to be 1. A missing variable is understood to have a degree of 0.

When there are two or more variables, the degree of the term is the sum of their exponents.

In some cases, we're only interested in the degree associated with a particular variable. For example, 7x²y³ is a 5th-degree term that is 2nd degree in x and 3rd degree in y.

A "quadratic" term is one that has degree 2, or one in which the variable of interest has degree 2.

In the given function definition, the term -3x² is the quadratic term.

A "linear" term is one that has degree 1.

In the given function definition, there is no linear term.

If you must identify one, it would be 0x, a degree-1 term with a coefficient of 0.

A "constant" term is one that has no variables, or no variables of interest. It has degree zero.

For example, in the expression x² +2ax +a², when we are concerned with the variable x, the a² term is called the "constant" term because it does not contain the variable x. The same expression could be considered as a quadratic in 'a', in which case the x² term would be the "constant term."

In the given function definition, the term 1 is the constant term.

Answer: B

Step-by-step explanation:

First, find the sum of the bottles, which is 6,235,168,989 which is not an estimate.

Rounding it to the nearest billion, the answer is 6,000,000,000 or B)

The most general antiderivative of the given function g(t) is (8t + t³/3 + t²/2 + c).

The antiderivative of a function is the inverse function of a derivative.

This inverse function of the derivative is called integration.

Here the given function is: g(t) = 8 + t² + t

Therefore, the antiderivative of the given function is

∫g(t) dt

= ∫(8 + t² + t) dt

= ∫8 dt + ∫t² dt + ∫t dt

= [8t⁽⁰⁺¹⁾/(0+1) + t⁽²⁺¹⁾/(2+1) + t⁽¹⁺¹⁾/(1+1) + c]

= (8t + t³/3 + t²/2 + c)

Here 'c' is the constant.

Again, differentiating the result, we get:

d/dt(8t + t³/3 + t²/2 + c)

= [8 ˣ 1 ˣ t⁽¹⁻¹⁾ + 3 ˣ t⁽³⁻¹⁾/3 + 2 ˣ t⁽²⁻¹⁾/2 + 0]

= 8 + t² + t

= g(t)

The antiderivative of the given function g(t)is (8t + t³/3 + t²/2 + c).

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1) a) The volume of the sphere is 100 cubic centimeters.

b) The volume of the cylinder is 200 cubic centimeters.

2) The volume of the cone is 175 cubic centimeters.

Herein we have two case of submerging solids into recipients full of liquid, the volume of the objects is equal to the volume of the displaced liquid. Now we proceed to calculate the volume of each object:

Point 1 - Part A:

0.8 L - 0.5 L = 3 · x

0.3 = 3 · x

x = 0.1 L

x = 100 cm³

The volume of the sphere is 100 cubic centimeters.

Point 1 - Part B:

0.8 L - 0.5 L = x + y

0.3 = x + y

0.3 = 0.1 + y

y = 0.2 L

y = 200 cm³

The volume of the cylinder is 200 cubic centimeters.

Point 2:

350 mL = 2 · z

z = 175 mL

z = 175 cm³

The volume of the cone is 175 cubic centimeters.

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The trigonometric function that represents the curve seen in the picture is f(x) = 4.5 · sin (π · x / 2 - π) - 6.5.

In this problem we need to find a sinusoidal expression that models the curve seen in the picture. The most typical sinusoidal model is described below:

f(x) = a · sin (b · x + c) + d    (1)

Where:

Now we proceed to find the value of each variable:

Amplitude

a = - 2 - (-6.5)

a = 4.5

Angular frequency

b = 2π / T, where T is the period.

0.25 · T = 4 - 3

T = 4

b = 2π / 4

b = π / 2

Midpoint

d = - 6.5

Angular phase

- 2 = 4.5 · sin (π · 4/2 + c) - 6.5

4.5 = 4.5 · sin (π · 4/2 + c)

1 = sin (2π + c)

π = 2π + c

c = - π

The trigonometric function that represents the curve seen in the picture is f(x) = 4.5 · sin (π · x / 2 - π) - 6.5.

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Type of model best fits the given situation linear.  Since it has a constant of +3 everyday.

What is a linear equation in math?

the membership of the local pta increases by 3 members a day for each day during the month of September.

Since it has a constant of +3 everyday.

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Answer:7 21/100

Step-by-step explanation: We will covert 7.21 into a fraction. .21 = 21/100. Since 21 can only be divided by 3 and 7, the simplest form of 21/100 is 21/100. So, the mixed number is 7 and 21/100

Answer:

7 and 21/100

Step-by-step explanation:

Since .01 is 1/100, 7.21 will be 7 and 21/100. There is no way to further simplify this, therefore, it is our final answer. Hope this helps! :)

          Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.

[23] ABD = 42°, DBC = 35°

(4x - 2) + (3x + 2) = 77°

4x+ 3x + 2 - 2  = 77°

4x+ 3x= 77°

7x= 77°

x= 11°

-

ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°

DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°

[24] ABD = 62°, DBC = 78°

(4x - 8) + (4x + 8) = 140°

4x + 4x + 8 - 8 = 140°

4x + 4x = 140°

8x = 140°

8x = 140°

x = 17.5°

-

ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°

DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°

Answer:

3x + 16 + 30/x - 13

Step-by-step explanation:

The expression y = α · sin x + β · cos x is a solution of the ordinary differential equations if and only if (α, β) = (0, 0).

According to the statement, we must find in what conditions a given expression may be a solution of an ordinary differential equation. Then, first and second derivatives of the equation are:

y' = α · cos x - β · sin x                 (1)

y'' = - α · sin x - β · cos x              (2)

Then, we substitute on the ordinary differential equation:

(- α · sin x - β · cos x) + (α · cos x - β · sin x) = 0

And by algebraic handling we simplify the resulting expression:

- (α + β) · sin x + (α - β) · cos x = 0

Where each coefficient represents a constant of a linear combination:

α + β = 0

α - β = 0

Then, the solution of the system of linear equations is (α, β) = (0, 0). The expression y = α · sin x + β · cos x is a solution of the ordinary differential equations if and only if (α, β) = (0, 0).

The statement is incomplete and complete form cannot be found, then we decided to create a new statement:

Please prove that y = α · sin x + β · cos x is the solution of the differential equation d²y / dx² + dy /dx = 0 where the following condition is observed, if and only if α = β = 0.

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The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].

According to the statement

we have given that the function f(x) and we have to find the average value of that function.

So, For this purpose, we know that the

The given function f(x) is

[tex]f(x) = -x^{2} + 2x +1[/tex]

And now integrate this function with the limit 0 to a then

[tex]f_{avg} = \frac{1}{b - a} \int\limits^a_0 {f(x)} \, dx = -x^{2} + 2x +1[/tex]

Now integrate this then

[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-x^{2} + 2x +1} \, dx[/tex]

Then the value becomes according to the integration rules is:

[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-\frac{x^{3} }{3} + \frac{2x^{2} }{2} +x} \,[/tex]

Now put the limits then answer will become as output is:

[tex]f_{avg} = \frac{1}{a} [ {-\frac{a^{3} }{3} + \frac{2a^{2} }{2} +a} \,][/tex]

Now solve this equation then

[tex]f_{avg} = [ {-\frac{a^{2} }{3} + \frac{2a }{2} +1} \,][/tex]

Now

[tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex]

This is the value which represent the average of the given function in the statement.

So, The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].

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Answer: eleven equals five minus b

Step-by-step explanation:  11 = eleven. = equals equal. 5 = five.  - =  minus. b = b

Answer:

  p(x) = x² +30x -375

Step-by-step explanation:

When a quadratic has real rational coefficients, any irrational or complex roots come in conjugate pairs.

A root of p means (x -p) is a factor of the polynomial. Here, we have roots of -15+10√6 and -15-10√6, so the factored form can be written ...

  p(x) = (x -(-15 +10√6))(x -(-15 -10√6))

Using the factoring of the difference of squares, we can write this as ...

  p(x) = (x +15)² -(10√6)²

Expanding the factored form, we can write the polynomial as ...

  p(x) = x² +30x +225 -600

  p(x) = x² +30x -375

[tex]x = \frac{\sqrt{5} + 1}{2} \approx 1.618033989[/tex]

The tangent line has the largest slope at x = 3√2 and x = -3√2 on the curve y = 1 + 60x³ − 2x⁵.

First, let's find the derivative of the given function y = 1 + 60x³ − 2x⁵ using the power rule for differentiation:

dy/dx = 0 + 3(60)x² - 5(2)x⁴

= 180x² - 10x⁴

To find the critical points, we set the derivative equal to zero and solve for x:

180x² - 10x⁴ = 0

Factoring out common terms, we get:

10x²(18 - x²) = 0

Setting each factor equal to zero, we have:

10x² = 0 or 18 - x² = 0

From the first equation, we find x = 0.

From the second equation, we have:

18 - x² = 0

x² = 18

Taking the square root, we get:

x = ±√18

= ±3√2

So the critical points are x = 0, x = 3√2, and x = -3√2.

Now we need to evaluate the slope at these critical points. We can do this by plugging each x-value into the derivative:

When x = 0:

dy/dx = 180(0)² - 10(0)⁴ = 0

When x = 3√2:

dy/dx = 180(3√2)² - 10(3√2)⁴ = 180(18) - 10(216) = 3240 - 2160 = 1080

When x = -3√2:

dy/dx = 180(-3√2)² - 10(-3√2)⁴ = 180(18) - 10(216) = 3240 - 2160 = 1080

The slope is 0 when x = 0 and 1080 when x = 3√2 or x = -3√2.

Therefore, the tangent line has the largest slope at x = 3√2 and x = -3√2 on the curve y = 1 + 60x³ − 2x⁵.

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The complete question is as follows:

At which points on the curve y = 1 + 60x³ − 2x5⁵ does the tangent line have the largest slope?