Answer:
Is [h] really [H]? What characteristics are mentioned?
Explanation:
A high [H} means high acid concentration.
What are the atomic number and atomic mass number of fluorine atoms with nine protons and ten neutrons
Answer:
Atomic Number = 9
Mass Number = 19
Explanation:
The atomic number is the total amount of protons in an atom's nucleus. Therefore, if a fluorine atom has 9 protons, the atomic number is 9.
The mass number is the total amount of protons and neutrons in an atom's nucleus. Therefore, if a fluorine atom has 9 protons and 10 neutrons, the mass number is 19 (9 + 10 = 19).
How many minutes would be required to produce a mass of 6. 38 g al using a current of 12. 50 amps?
To produce a mass of 6. 38 g al using a current of 12. 50 amps the time required would be 7207.4 minutes.
What is faraday law?It states that the chemical which is getting decomposed because of the flow of current within an electrolyte is directly proportional to the quantity of electricity passing through it.
W= Z × I × t Z = 1 coulomb
I = current
t = time
substituting the values
Z= 96500/Eq.wt
Al 3+ +3e − →Al n= 3
so, Eq= 27 / 3 = 9
t = W × Z / I
t = 9 × 96500 / 12.50
t = 7207.4 minutes.
Therefore the time required would be, 7207.4 minutes.
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As a whole, plants tend to release more oxygen than carbon dioxide into the environment, but the ratios of gases differ at various times of the day. plants tend to take in more carbon dioxide during the day and release more oxygen. at night, they tend to take in more oxygen and excrete more carbon dioxide. how does the model support this phenomenon?
During the day, due to the existence of sunlight, the procedure of photosynthesis elevations over that of respiration. Photosynthesis uses carbon dioxide to produce carbohydrates removing oxygen as a byproduct. During the night, because there is no sunlight, the rate of photosynthesis decreases. This, therefore, drives the rate of respiration to surpass the speed of photosynthesis. In respiration, oxygen is consumed and carbon dioxide is dismissed.
What is photosynthesis?Photosynthesis is the process by which manufacturers use sunlight, water, and carbon dioxide to produce oxygen and energy in the form of sugar.The primary position of photosynthesis is to transform solar energy into chemical energy and then reserve that chemical energy for prospective use. For the most part, the planet's living designs are powered by this process.An illustration of photosynthesis is how plants convert sugar and significance from water, air, and sunlight into energy to grow. Description of photosynthesis is the procedure through which plants use water and carbon dioxide to assemble their food, grow and remove excess oxygen into the air.To learn more about photosynthesis, refer to:
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Calculate the kf of ag(nh3)2 from ag (aq) e- ⇋ ag(s) e0= 0. 81 v ag(nh3)2 (aq) e- ⇋ ag(s) 2nh3(aq) e0= 0. 39 v enter number as e notation (e. g. 2. 34e6 or 4. 56e-4)
The kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
What is kf value?kf value can be calculated by dividing the molal concentration with the freezing point of depression.
The reaction are given:
Ag+(aq) + e- ⇋ Ag(s) E0= 0.81 V
Ag(NH₃)₂ +(aq) + e- ⇋ Ag(s) + 2NH₃(aq) E0= 0.37 V
To get Kf of Ag(NH₃)₂ we will rearrange the above written equations
a. Ag +(aq) + e- ⇋ Ag(s) E0= 0.81 V
b. Ag(s) + 2NH₃(aq) ⇋ Ag(NH₃)₂ +(aq) + e- E0= - 0.37 V
Adding equation (a) and equation (b) we will get
Ag +(aq) + 2NH₃(aq) ⇋ Ag(NH₃)₂ + (aq) Eo = 0.81 -0.37 = 0.44 V
By the Ernst equation,
E = E° - 0.0591 logkf
Now Kf is calculated at equilibrium and at equilibrium E = 0,
The number of transfer of electron is 1 ( 1 e-) , n=1
E° = 0.44 V
Substituting all the values in Ernst equation
0 - 0.44 - 0.0591/ 1 logkf
logkf = 0.44/ 0.0591
kf = 10 (0.44/ 0.0591)
Kf = 2.786 x 10⁷
Hence, Kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
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Discuss potential advantages and disadvantages of using water as a solvent in organic chemistry.
Potential advantages of using water as a solvent in organic chemistry are:
Natural resource, easy to obtain, lower cost.Avoiding biomass drying step.Facilitating recovery of inorganics contained in biomass.Disadvantages of using water as a solvent in organic chemistry
Higher critical point, severe reaction conditions.Lower yields of water insoluble bio-oil.The bio-oil with higher oxygen content and lower calorific value.What is the most widely used liquefaction solvent?Water is the most common liquefaction solvent. Not only is water an environmentally friendly solvent that is inexpensive and does not pollute the environment, but it also facilitates the recovery and recycling of inorganic matter contained in biomass in ionic form for eventual use as fertilizers.
Why is water called a universal solvent?Water dissolves many substances and is known as a universal solvent. We learned that, despite being a universal solvent, it can only dissolve polar molecules and that nonpolar molecules, even when mixed with water, form a separate layer.Many researchers around the world have studied the effect of liquefaction solvent type on the liquefaction behaviors of various biomasses, including lignocelluloses, algae, and sewage sludge.Learn more about water as a solvent:
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The use of phenol (carbolic acid) as a surgical wound disinfectant was first practiced by?
The use of phenol (carbolic acid) as a surgical wound disinfectant was first practiced by Joseph Lister.
Who was Joseph Lister?
Joseph Lister was a surgeon, scientist, pathologist, etc. He was famous for the discovery of the prevention of infection in wounds. He first used phenol as a disinfectant agent for wounds.
Phenol is an inorganic compound, it is white crystalline and solid. It was used by Joseph Lister as an agent for a disinfectant agent. He discovered the safer medical procedure.
Thus, Joseph Lister was the first to utilize phenol (carbolic acid) to sterilize surgical wounds.
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9.0 mol Na2S can from 9.0 mol CuS and 8.0 mol CuSO4 can form 8.0 mol Cus.
What mass of Cus forms during the reaction?
Cus; 95.62 g/mol
Answer:
765.0 grams CuS
Explanation:
The limiting reagent is the reactant which completely reacts before the other reactant(s) is used up. When 9.0 moles Na₂S and 8.0 moles CuSO₄ react, it appears that CuSO₄ is the limiting reagent. You can tell because it results in the production of less product.
You can determine the mass of CuS by multiplying the moles by the molar mass. It is important to arrange the ratio in a way that allows for the cancellation of units.
Molar Mass (CuS): 95.62 g/mol
8.0 moles CuS 95.62 g
------------------------- x ----------------------- = 765.0 grams CuS
1 mole
The materials in the flux covering on an electrode determine the electrical characteristics of the electrode.
a. true
b. false
Answer:
a. true
Explanation:
It is true that, the materials in the flux covering on an electrode determine the electrical characteristics of the electrode.
What substance is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(l)cabr2(l), and molten magnesium iodide, mgi2(l)mgi2(l)? assume standard conditions
Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).
What is Anode and cathode ?The anode in the cell has been the negative electrode and attracts the positive ions in the solution. The cathode has been the positive electrode, and attract negative ions.
What is Electrolysis of Calcium Bromide ?In electrolysis of Calcium bromide, Calcium will form at the cathode and Bromine will form at the anode.
The reaction is as follows:
2Br⁻ (aq) → Br₂ (g) + 2e⁻
What is Electrolysis of Magnesium Iodide ?In electrolysis of magnesium Iodide, Magnesium will form at the anode Iodine will form at the cathode.
The reaction is as follows:
2I⁻ (aq) → I₂ (g) + 2e⁻
Thus from the above conclusion we can say that Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).
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number of oxygen atoms in 16 g of So2??
Now , we know that one mole of SO² Contains 2 Moles ( two ) of atoms of oxygen . Hence , 16 Grams of SO² Contains 0.5 Mole(s) of Oxygen
0.5
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Butane reacts with oxygen gas to form carbon dioxide and water vapor as shown below:
2C₂H₁o + 130₂-8CO₂ + 10H₂O
a. If 20 g of butane were used in the experiment how many litres of water would be produced at SATP?
b. How many litres of oxygen would be consumed in this experiment?
c. If conditions were converted from SATP to STP, how many litres of water would now be produced?
A. The volume of water (in litres) produced at SATP is 42.73 L
B. The volume of oxygen consumed in the experiment is 55.55 L
C. If the conditions were converted from SATP to STP, the volume of water (in litres) produced is 38.64 L
How to determine the mole of C₂H₁₀ Mass of C₂H₁₀ = 20 gMolar mass of C₂H₁₀ = (12×4) + (10×1) = 58 g/molMole of C₂H₁₀ = ?Mole = mass / molar mass
Mole of C₂H₁₀ = 20 / 58
Mole of C₂H₁₀ = 0.3448 mole
A. How to determine the volume of water (in litres) produced at SATPBalanced equation
2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O
From the balanced equation above,
2 moles of C₄H₁₀ reacted to produce 10 moles of water.
Therefore,
0.3448 mole of C₄H₁₀ will react to produce = (0.3448 × 10) / 2 = 1.724 mole of water
Thus, the volume of water (in litres) produced at SATP can be obtained by using the ideal gas equation as follow:
Number of mole of water (n) = 1.724 molePressure (P) = SATP = 0.987 atm Temperature (T) = SATP = 298 KGas constant (R) = 0.0821 atm.L/Kmol Volume of water produced (V) =?PV = nRT
Divide both sides by P
V = nRT / P
V = (1.724 × 0.0821 × 298) / 0.987
Volume of water produced at SATP = 42.73 L
B. How to determine the volume of oxygen consumedBalanced equation
2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O
From the balanced equation above,
2 moles of C₄H₁₀ reacted with 13 moles of O₂
Therefore,
0.3448 mole of C₄H₁₀ will react with = (0.3448 × 13) / 2 = 2.2412 moles of O₂
Thus, the volume of O₂ (in litres) consumed at SATP can be obtained by using the ideal gas equation as follow:
Number of mole of O₂ (n) = 2.2412 molesPressure (P) = SATP = 0.987 atm Temperature (T) = SATP = 298 KGas constant (R) = 0.0821 atm.L/Kmol Volume of O₂ consumed (V) =?PV = nRT
Divide both sides by P
V = nRT / P
V = (2.2412 × 0.0821 × 298) / 0.987
Volume of O₂ consumed = 55.55 L
C. How to determine the volume of water (in litres) produced at STPNumber of mole of water (n) = 1.724 molePressure (P) = STP = 1 atm Temperature (T) = STP = 273 KGas constant (R) = 0.0821 atm.L/Kmol Volume of water produced (V) =?PV = nRT
Divide both sides by P
V = nRT / P
V = (1.724 × 0.0821 × 273) / 1
Volume of water produced at STP = 38.64 L
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If 160 grams of a 200-gram sample of gold-198 decay in 6.25 days, what is the half-life of gold-198?
The half-life of gold-198 is 2.77 days
Given:
mass of gold sample = 200-gram
mass of decay sample = 160 grams
time taken to decay = 6.25 days
To Find:
the half-life of gold-198
Solution: The amount of time it takes to disintegrate by half an initial amount. For a given reaction, a reactant's half-life t1/2 is the time it takes for its concentration to reach a value which is the arithmetic mean of its initial and final (equilibrium) value.
Since Au-198 is 200 g originally and it decays to 160 g, so 40g left
the fraction decay is 40/200 = 0.2
the time base is 6.25 days
ln0.2/6.25 = -0.25
k=ln2/half life therefore half-life = ln2/k = ln2/0.25
half life = 2.77 days
So, half life of gold is 2.77 days
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Two molecules of mercury oxide decompose into 2 molecules of mercury and 1 molecule of oxygen gas. Which of the following
equations correctly describes this reaction?
(A) Pro(s)-> Pr(s) + O(g)
(B) Mc₂O(s)-> 2 Mc(s) + O(g)
(C) 2 MnO(s)-> 2 Mn(s) + 20(g)
(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)
Select one:
O a. A
O b. B
OC. C
O d. D
Answer:
D
Explanation:
Mercury is Hg. Most of these reaction do not involve Hg. Only D correctly shows a balanced equation with mercury (Hg).
(A) Pro(s)-> Pr(s) + O(g)
(B) Mc₂O(s)-> 2 Mc(s) + O(g)
(C) 2 MnO(s)-> 2 Mn(s) + 20(g)
(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)
A current of 5. 68 a is passed through a Fe(NO3)2 solution. How long, in hours, would this current have to be applied to plate out 7. 20 g of iron?
There are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
Calculation ,
Given ; Current ( I ) = 5. 68 A
In [tex]Fe(NO_{3} )_{2}[/tex] , the valancy of Fe is +2 .
2 moles of [tex]e^{-}[/tex] are required for the decomposition of 1 mole of Fe .
7. 20 g of Fe in moles = 7. 20 g /55.845 g/mol =0.12 mole
x moles of [tex]e^{-}[/tex] are required for the decomposition of 0.128 mole of Fe .
moles of [tex]e^{-}[/tex] are required = 0.256 moles
Charge on 1 mole of [tex]e^{-}[/tex] = 96500 C
Charge on 0.256 mole of [tex]e^{-}[/tex] = 24704 C
Current ( I )= Q/t
t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr
Therefore , there are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
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A solution is made by dissolving 6.93 grams of lead(II) nitrate into about 50 mL of water. The volume is then precisely brought up to 100 mL and the solution is saved as stock solution. A 50.0 mL aliquot* of this stock solution is then titrated with 0.222 M sodium phosphate. What would be the minimum number of milliliters (mL) of the the phosphate solution that are needed to completely precipitate (knock out) all the lead in this aliquot? (tolerance is ±0.1 mL)
6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.
What is a neutralization reaction?A neutralization reaction is defined as the reaction between an strong acid and strong base to produce a salt and water.
The process of the reacting given volume of acids or bases for the determination of the concentration or volume of the acid or base which is required for neutralization is known as titration in volumetric analysis.
The formula used to determine the volume of the acid is given below:
(Ca × Va) /(Cb × Vb) = Na/Nb
where,
where Ca is the concentration of lead nitrate
Cb is the concentration of sodium phosphate
Va is the volume of lead nitrate
Vb is the volume of sodium phosphate
Na is the moles of lead nitrate
Nb is the moles of sodium phosphate
Concentration of lead nitrate = m/V
= 6.931/(0.1 × 331.2)
= 0.0281 M
Ca = 0.222M
Cb = 0.0281M
Na = Nb = 1
Va = ( 0.0281 × 50) /0.222
= 6.32 mL.
Thus, 6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.
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To use the gas law constant r = 0.0821, the unit for temperature should be kelvin and the unit for pressure should be atmospheres. true false
The given statement "To use the gas law constant R=0.0821 the unit for temperature should be kelvin and the unit for pressure should be atmospheres" is -----true.
What is the ideal gas law?
The ideal gas law tells us about behavior of ideal gas through a equation and postulates.The ideal gas law is considered as ideal gas equation.
The ideal gas equation is given as.
PV = nRT
where,
P is pressure of the gasV is volume occupied by the gasn is number of moles of ideal gasT is temperatureR is constant known as universal gas constant.The value of R depends upon units of temperature, pressure and volume.
Why is Kelvin used in gas laws?
The Kelvin scale is used in gas law problems because the pressure and volume of a gas depend on the kinetic energy or motion of the particles.
How are pressure and Kelvin temperature related?
It states that, at a constant volume, the pressure of a given amount of a particular gas is directly proportional to its Kelvin temperature. It can be written as: P ∝ T, or. P/T = k where k is a constant,
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Which one of these molecules can be a reactant in a friedel-crafts reaction? a) aniline b) benzenesulfonic acid c) chloroethene d) bromobenzene e) p-bromonitrobenzen
The molecules can be a reactant in a Friedel-crafts reaction will be aniline .
The Lewis acid as well as the chlorine atom of such acid chloride form a complex during the Friedel-Crafts acylation reaction. Cleaving the complex's C-Cl link produces an acylium ion. The acylium ion undergoes resonance stabilized but also has a positive electrical charge upon that carbon atom.
The Friedel-Crafts alkylation reaction, an electrophilic aromatic substitution process, may add an alkyl to a benzene molecule. One illustration is the insertion of a methyl group into a benzene ring.
Therefore, the molecules can be a reactant in a Friedel-crafts reaction will be aniline .
Hence, the correct answer will be option (a)
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Given the following reaction: 2O3---->3O2. DeltaH of reaction=-286kJ/mol
What is the Delta H reaction of the reaction 3O2----->2O3
The enthalpy of reaction (ΔH) of the above chemical reaction is equal to -143 kJ/mol.
What is a chemical reaction?A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.
What is a balanced equation?A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.
Next, we would write the properly balanced chemical equation for this chemical reaction:
3/2O₂ -----> 2/2O₃
Therefore, the enthalpy of reaction (ΔH) of the above chemical reaction is half the enthalpy of reaction (ΔH) of the initial chemical reaction:
Enthalpy of reaction (ΔH) = ½ × -286 kJ/mol
Enthalpy of reaction (ΔH) = -143 kJ/mol.
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How many particles are there in 5 grams of sodium carbonate?
3.01× 1024 particles are the number of particles are there in 5 grams of sodium carbonate.
How many particles are there in 5 grams of sodium carbonate?There are 6.022 × 1023 particles in one gram of a substance according to Avogadro's number. So when we find out for 5 grams, then we multiply 5 with 6.022 × 1023, we get 3.01 × 1024 particles. For one gram atomic weight of hydrogen, one mole of hydrogen contains 6.022 × 1023 hydrogen atoms.
So we can conclude that 3.01× 1024 particles are the number of particles are there in 5 grams of sodium carbonate.
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A solution of naf is added dropwise to a solution that is 0.0122 m in ba2 . when the concentration of f- exceeds ________ m, will precipitate. neglect volume changes. for , ksp = 1.7 x 10-6. 4. calculate the ph of a solution prepared by dissolving 0.270 mol of weak acid ha (ka = 1.77 x 10-4) and 0.260 mol of its conjugate base in water sufficient to yield 1.00 l of solution.
A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 m, BaF₂ will precipitate.
Let's consider the solution of BaF₂.
BaF₂(s) ⇄ Ba²⁺(aq) + 2 F⁻(aq)
We can use the solubility product constant (Ksp) to find the equilibrium concentration of F⁻ when [Ba²⁺] is 0.0144 M.
When [F⁻] exceeds 0.011 M, BaF₂ will precipitate.
A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 M, BaF₂ will precipitate.
What is BaF₂.?
BaF2 crystallizes in the cubic Fm3m space group and has a fluorite structural makeup. Eight comparable F1 atoms and Ba2+ are joined in a cubic shape with the body in the middle. The average Ba-F bond length is 2.72. Four comparable Ba2+ atoms are joined with F1 to create a mixture of corner- and edge-sharing FBa4 tetrahedra.Learn more about BaF2 crystallizes
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what type of solution do you have if you dissolve 20.2 g of potassium chlorate in 0.300 L
solution of potassium chlorate,
K
C
I
O
3
, has 20 grams of the salt dissolved in 100 grams of water at 70 C. Approximately how many more grams of the salt can be added to the solution before reaching the saturation point?
3) During a chemical reaction, atoms are ________. A) destroyed B) created C) rearranged D) destroyed and created
Answer: C- rearranged
Explanation:
Answer:
C
Explanation:
15. conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that ___ are likely intermediates during these reactions
Conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that electrophilic reagents are likely intermediates during these reactions.
Two double bonds and one single bond divide a conjugated diene into two halves. Nonconjugated (Isolated) Dienes have more than one single bond separating two double bonds. Two double bonds are joined to the same atom to form cumulated dienes.
Reagents that function by acquiring electrons or sharing electrons that once belonged to a foreign molecule are referred to as electrophilic reagents, or electrophiles, in some cases. Electrophiles are molecules with a positive charge and a lack of electrons that can react by exchanging electron pairs with nucleophiles, which have many electrons. Epoxides, hydroxy amines, nitroso and azoxy derivatives, nitrenium ions, and elemental sulfur are significant electrophiles.
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Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2). calculate the concentration of solute s in hexane if [s]water is 0. 011 m.
Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2), then the concentration of solute s in hexane if [s]water is 0. 011 m is 0.055m.
What is partition Coefficent?It is defined as the ratio of the concentration of solute in two immiscible ( or slightly miscible liquid) in two solids, when they are in equilibrium across the interface between them.
What is concentration?It is defined as the ratio of number of moles of compound to the volume of compound.
Solute S has a partition coefficient of 5 between water and hexane
Partition coefficient Kd = 5.0
Now we calculate the concentration of S in hexane
[hexane]/[water] = Kd
[Hexane]= 5.0 × (water)
[Hexane] = 5 × (0. 011)
[Hexane] = 0.055 m
Thus, we found that the concentration of solute of hexane if water is 0.011m is 0.055m.
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Please help.. I'm Giving Brainliest :)
Answer:
i think its -91.6
Explanation:
2 ( - 950.8) - (( - 1130.7) + ( - 393.5) + ( - 285.8))
The standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.
The heat produced during a chemical reaction under specific conditions is known as the standard enthalpy change, abbreviated as H° (zero delta H). Standard conditions often refer to all reactants and products in their standard states, which are their most stable forms at 298 K and 1 bar (or 1 atm) pressure.
Hess's law, which states that the total enthalpy change of a reaction is equal to the sum of the enthalpy changes of its component phases, is used to calculate the standard enthalpy change of the reaction.
The following reaction is given:
[tex]\rm 2 NaHCO_3(s)--- > Na_2CO_3(s)+ CO_2(g) + H_2O(l)[/tex]
The relevant enthalpy changes of formation are:
ΔH°[NaHCO3(s)] = -950.8 kJ mol⁻¹
ΔH°[Na2CO3(s)] = -1130.7 kJ mol⁻¹
ΔH°[CO2(g)] = -393.5 kJ mol⁻¹
ΔH°[H2O(l)] = -285.8 kJ mol⁻¹
By using Hess's Law, the standard enthalpy change (ΔH°) for the reaction can be calculated as follows:
ΔH° = Σ (products) - Σ (reactants)
ΔH° = [ΔH°[[tex]\rm Na_2CO_3[/tex](s)] + ΔH°[[tex]\rm CO_2[/tex](g)] + ΔH°[H2O(l)]] - [2 × ΔH°[[tex]\rm NaHCO_3[/tex](s)]]
ΔH° = [-1130.7 kJ mol⁻¹ + (-393.5 kJ mol⁻¹) + (-285.8 kJ mol⁻¹)] - [2 × (-950.8 kJ mol⁻¹)]
ΔH° = [-1809.7 kJ mol⁻¹] - [-1901.6 kJ mol⁻¹]
ΔH° ≈ -1809.7 kJ mol⁻¹ + 1901.6 kJ mol⁻¹
ΔH° ≈ 91.9 kJ mol⁻¹
Hence, the standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.
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How many grams of silver may be formed by the passage of 9,604 c through an electrolytic cell that contains a molten silver salt?
The grams of silver formed by the passage of 9,604 c through an electrolytic cell that contains a molten silver salt is 10.7g.
Acc. Faraday’s law of electrolysis,
W=(I×t×M) /nF
W=Faraday’s constant=96500
F=time M=molar mass
N=no. Of el.
It=9604C
Given,
Molar mass of silver=108g/mol.
n=1.
Then weight of silver deposited can be given as
W=(9604×108)/(96500×1)
= 10.7g
Thus we concluded that the silver deposited is 10.7g
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The energy of the ground state in the bohr model is -13. 6 ev. the energy of the n = 2 is:_______
Bohr's model explained the position of the electron, proton, and neutron in the atom of the element. The energy at the n = 2 level of the atom will be - 3.40 eV.
What is the principal quantum number (n)?The principal quantum number (n) has been the distance of the electron of that atom in the nucleus and its energy in the structure. It can also be said to define the size of the atomic orbit.
n = 2 is the first excited state whose energy is calculated as:
Eₙ = − 13.6 ÷ n² eV
E₂ = - 13.6 eV ÷ 2²
= -3.40 eV
Therefore, -3.40 eV is the energy of electron at n = 2.
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What products are formed in the following reaction
The correct product from this reaction is the structure in option D.
What is a secondary amine?An amine is a compound that contains an alkyl group and an amino group. We know that we can obtain an amine from ammonia by replacing one or more hydrogen atoms with alkyl groups.
The compound as shown here is a secondary amine because two hydrogen atoms have been replaced with alkyl groups. We know that the reaction between the HCl and the amine produces an ionic compound owing to the fact that the nitrogen and the hydrogen from HCl are involved in a Dative bond.
As such, the correct product from this reaction is the structure in option D.
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Risk premiums on corporate bonds tend to ________ during business cycle expansions and ________ during recessions, everything else held constant.
Risk premiums on corporate bonds tend to decreases during business cycle expansions and increases during recessions, everything else held constant.
A bond that is sold for more than it is worth. when the prevailing interest rate is lower than the coupon rate.
Corporate bond risk premiums have become typically anticyclical, meaning they rise during recessions as well as fall throughout expansions of the business cycle.
Bonds that trade above their face value or cost more than their face value are referred to as premium bonds. Since its interest rate has been higher than those of the current market, a bond may trade at a premium. The bond's price may also increase as a result of the company's as well as the bond's credit ratings.
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Simon measured the density of a piece of metal
to be 11.70 g/cm³. However, the manufacturer
claims it has a density of 12.00 g/cm³. What is
the percent error of Simon's measurement?
From the question we know that 12 - 11.70 = 0.3 so 0.3 / 12 = 0.025 therefore Simon's percent error is 2.5%.
Percent error compares an estimate to an accurate value and expresses the difference among them as a percent. This statistic lets analysts recognize the scale of the mistake relative to the true cost. it's also referred to as percentage error as well as % mistakes.
Percentage errors Calculation Steps :
Subtract one cost from another.Divide the mistake by the exact or ideal price (not your experimental or measured value).Convert the decimal variety into a percentage by multiplying it by using 100.Add a percent or % symbol to record your percentage mistakes value.Percentage error tells you the way huge your mistakes are when you degree something in an experiment. Smaller values suggest that you are close to the accepted or actual value. for instance, a 1% blunder means that you obtain very near the accepted value, whilst 45% means that you were pretty a long way off from the real value.
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