Answer:
6.4 L
Explanation:
When all other variables are held constant, you can use Boyle's Law to find the missing volume:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the theoretical volume by plugging the given values into the equation and simplifying.
P₁ = 3.2 atm P₂ = 1.0 atm
V₁ = 2.0 L V₂ = ? L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.2 atm)(2.0 L) = (1.0 atm)V₂ <----- Insert values
6.4 = (1.0 atm)V₂ <----- Simplify left side
6.4 = V₂ <----- Divide both sides by 1.0
Answer:
6.4L or C on Brainly.
Explanation:
What concentration of the barium ion, ba2 , must be exceeded to precipitate baf2 from a solution that is 1. 00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2. 45×10−5
The amount of barium ions that must be present in order for the salt to precipitate is 0.245 M.
A solution's solubility product is the result of raising each ion's concentration to the power of its stoichiometric ratio. It is portrayed as
A combination of 1 barium ion and 2 fluoride ions results in the ionic compound known as barium fluoride.
The following equation describes the equilibrium reaction for barium fluoride ionization:
BaF₂ → Ba²⁺ + 2F⁻
Ksp = [Ba²⁺] · [F⁻]²
2.45*[tex]10^{-5}[/tex]= [Ba²⁺] * [tex][1. 00*10^{-2} ]^{2}[/tex]
[Ba²⁺]=0.245 M
As a result, 0.245 M of barium ions must be present in order for the salt to precipitate.
SolubilitySolubility in chemistry refers to a chemical's capacity to dissolve in another substance, the solvent, to produce a solution. Inability of the solute to create such a solution is the opposite quality, or insolubility. A substance's degree of solubility in a given solvent is often determined by the amount of the solute present in a saturated solution, which is a solution in which no additional solute can be dissolved. The solubility equilibrium between the two compounds is considered to have been reached at this time. If there is no such restriction for a given solute and solvent, the two are referred to as being "miscible in any amounts."
What concentration of the barium ion, ba2 , must be exceeded to precipitate baf2 from a solution that is 1. 00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2. 45×10−5
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What is one of the most common uses of polyvinyl chloride? select one: a. 2-l soda bottles b. styrofoam cups c. plastic pipes d. plastic food bags e. plastic garbage cans
The correct answer choice which is the most common use of polyvinyl chloride is: plastic pipes. Option C
Below are some other uses of polyvinyl chloride:
It's pipes is used for fittingsIt's pipes is used for building infrastructure and structural materialIt is used for coatingsWhat is polyvinyl chloride?Polyvinyl Chloride (PVC) is polymer which is used in various applications including widespread use in building, transport, packaging, electrical and healthcare applications.
So therefore, the most common use of polyvinyl chloride is in the making of plastic pipes
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What are the products of hydrolysis when the polypeptide is treated with chymotrypsin?
The products of hydrolysis when the polypeptide is treated with chymotrypsin are endo-peptidases.
What is chymotrypsin?Chymotrypsin is a digestive enzyme that breaks down protein in the form of small intestine .This enzyme is a substance that speeds up certain chemical reactions in the body.
A digestive enzyme is a specialized protein that breaks down the substances in the digestive tract by catalyzing biochemical reactions.
The chymotrypsin active site consists of aspartic acid, serine, and histidine amino acid residues.
Chymotrypsin works primarily due to its hydrophobic pocket in the active site.
Products of hydrolysis when the polypeptide is treated with chymotrypsin are endo-peptidases.
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Write the chemical symbols for three different atoms or atomic cations with 25 electrons
Answer:
Three different atoms or atomic cations with 25 electrons = Mn ,Fe¹+ ,Co²+ ,Ni³+ ,Cu⁴+
Consider the reaction shown.
4 HCl(g) + O₂(g) → 2Cl₂(g) + 2 H₂O(g)
Calculate the number of grams of Cl2, formed when 0.125 mol HCl reacts with an excess of 0₂.
mass:
Answer:
4.43 g Cl₂
Explanation:
To find the mass of Cl₂, you need to (1) convert moles HCl to moles Cl₂ (via the mole-to-mole ratio from equation coefficients) and then (2) convert moles Cl₂ to grams (via the molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units. The final answer should have 3 significant figures like the given value.
4 HCl(g) + O₂(g) -----> 2 Cl₂(g) + 2 H₂O(g)
^ ^
Molar Mass (Cl₂): 2(35.453 g/mol)
Molar Mass (Cl₂): 70.906 g/mol
0.125 moles HCl 2 moles Cl₂ 70.906 g
-------------------------- x ---------------------- x ------------------- = 4.43 g Cl₂
4 moles HCl 1 mole
Which substance is a product of glycolysis, a precursor of gluconeogenesis and a precursor of the citric acid cycle?
Pyruvate substance is a product of glycolysis, a precursor of gluconeogenesis and a precursor of the citric acid cycle
A crucial node in the network of metabolic pathways is pyruvate. Pyruvate can be transformed into ethanol, the amino acid alanine, fatty acids or energy through acetyl-CoA, carbohydrates through gluconeogenesis, and fatty acids or energy. As a result, it combines numerous important metabolic activities.
Pyruvate's main job is to carry carbon atoms into the mitochondrion where they are fully oxidized into carbon dioxide.
The final byproduct of glycolysis, pyruvate, is crucial to cell metabolism. It is made in the cytosol and then oxidized in the mitochondria, where it activates oxidative phosphorylation and feeds the citric acid cycle.
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A 1. 7 m solution of the acid ha has a ph of 1. 0. what is the ka of the acid? the equation described by the ka value is ha(aq) h2o(l)⇌a−(aq) h3o (aq)
A 1. 7 m solution of the acid ha has a ph of 1. 0, then the ka of the acid is 6.25×10^(-3).
What is acid dissociation constant?The acid dissociation constant is defined as the value which is used to measure the strength of the specific acid in the solution.
Equation for general dissociation of strong or weak acid is
HA ----- (H+) + ( A-)
Ka can be expressed as
Ka = [H+] [A-]/[HA]
where [H+] is the concentration of H+ ions
Now, we will find the value of concentration of H+ ions
pH = -log [H+]
1 = -log[H+]
[H+] = antilog(-1)
[H+] = 0.1
By using ICE table, we find that the concentration of [HA] is
1.7-0.1
= 1.6
By substituting all the values we get,
Ka = 0.1 × 0.1/1.6
= 6.25×10^(-3)
Thus, we find that the Ka value of the given solution is 6.25×10^(-3).
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Consider the reaction below.
H O single bonded to C double bonded above to O and to the right to the bottom left of a benzene ring. The ring is bonded from the upper right to a C double bonded above to O and to the right to O H. H O bonded to C H Subscript 2 Baseline C H Subscript 2 Baseline bonded to O H. Arrow pointing with bond H Subscript 2 Baseline O beside it pointing down to H O bonded to C double bonded above to O and to the right to the bottom left of a benzene ring. The ring is bonded from the upper right to a C double bonded above to O and to the right to O bonded to C H Subscript 2 Baseline C H Subscript 2 Baseline bonded to O H.
This reaction eventually forms this product.
A bond from left to O single bonded to C double bonded above to O and to the right to the bottom left of a benzene ring. The ring is bonded from the upper right to a C double bonded above to O and to the right to O bonded to C H Subscript 2 Baseline C H Subscript 2 Baseline bonded to O bonded to C double bonded above to O and right to the upper left corner of a benzene ring. The ring is bonded from the lower left to C double bonded above to O and single bonded right to O bonded to CH Subscript 2 Baseline C H Subscript 2 Baseline bonded right to O bonded to C double bonded above to O and right to the lower left of a benzene ring, which is bonded from upper right to C double bonded above to O and single bonded right to O bonded to C H Subscript 2 Baseline C H Subscript 2 Baseline bonded to O.
Which type of reaction is represented by these diagrams?
elimination
substitution
addition polymerization
condensation polymerization
The type of reaction that is represented by these diagrams (attached) are given as: "condensation polymerization" (Option D)
What is condensation polymerization?Any type of polymer in polymer science that undergoes a condensation reaction during the polymerization process is referred to as a condensation polymer (i.e. a little molecules, methanol or water is derived as a metabolite).
The provided reaction is an example of condensation polymerization because it involves the combination of two monomers, which produces a big polymer and water as a byproduct.
Condensation polymers make significant contributions to the packaging, insulation, and textile sectors as far as real-world application of same is concerned.
Also examples of times that are condensation polymers and that have silicon rather than carbon as part of their molecular or structural make up are;
Silicone Oils and Rubbers.In conclusion, it is to be noted that The type of reaction that is represented by these diagrams (attached) are given as: "condensation polymerization"
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Answer:
condensation polymerization
Explanation:
The sp of pbbr2 is 6. 60×10−6. what is the molar solubility of pbbr2 in pure water?
Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.
Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.
Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.
Let the molar solubility be S upon dissociation.
PbBr₂ or Lead Bromide dissociates in pure water as follows:
PbBr₂ ----------> Pb⁺² + Br⁻
S 2S
Ksp = [Pb⁺²] [ Br⁻]
Ksp = (S) (2S)²
Ksp = 4S³
6.60 × 10⁻⁶ = 4S³
S = 0.0118M
Hence, the Molar solubility S is 0.0118M.
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A 400. 0 g sample of liquid water is at 30. 0 ºc. how many joules of energy are required to raise the temperature of the water to 45. 0 ºc?
Energy required to raise the temperature from 35°C - 45 °C= 25116 J.
specific heat, the quantity of warmth required to raise the temperature of one gram of a substance by means of one Celsius degree. The units of precise warmth are generally energy or joules consistent with gram according to Celsius diploma. for instance, the unique warmth of water is 1 calorie (or 4.186 joules) according to gram in step with Celsius degree.
solving,
Sample of liquid = 400. 0 g
temperature = 30. 0 ºc
joules of energy are required to raise the temperature of the water to 45. 0 ºc
therefore rise in temperature 45 - 30 = 15°C
Specific heat capacity = 4.186 J/g m °C
In kelvin = 273 + 15 = 288
= ∴ energy required = Q = m s ( t final - t initial)
= 400*4.186 * 15
= 25116 joule
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2CO(g) + O2(g) = 2CO2(g)
If 6.0 L of CO reacts at STP, how many liters of oxygen are required for the reaction?
Answer:
3.0 L O₂
Explanation:
If CO reacts at STP, it means that there are 1.0 moles of CO. To find the moles of O₂, you need to use the mole-to-mole ratio from the given equation.
1.0 moles CO 1 mole O₂
---------------------- x --------------------- = 0.5 moles O₂
2 moles CO
To calculate the liters of oxygen, you need to use Avogadro's Law:
V₁ / N₁ = V₂ / N₂
In this equation, "V₁" and "N₁" represent the volume and moles of the first molecule. "V₂" and "N₂" represent the volume and moles of the second molecule. You can plug the given and calculated values into the equation and simplify to isolate V₂.
V₁ = 6.0 L V₂ = ? L
N₁ = 1.0 moles N₂ = 0.5 moles
V₁ / N₁ = V₂ / N₂ <----- Avogadro's Law
(6.0 L) / (1.0 moles) = V₂ / (0.5 moles) <----- Insert values
6.0 = V₂ / (0.5 moles) <----- Simplify left side
3.0 = V₂ <----- Multiply both sides by 0.5
**I am not 100% confident on this answer. Please let me know if it is incorrect**
Answer:
2CO(g) + O2(g) → 2CO2(g)
If 9.0 L of O2 react at STP, how
many moles of CO2 form during the
reaction?
[?] mol CO2
Explanation:
What would it be if it was 9.0?
what do chemical and physical change have in common?
Explanation:
The similarities between chemical and physical changes include change in state of matter and both process involve change in energy.
Chemical changes of a substance results in the formation of entirely new substances. These changes are not reversible.
Physical changes results in the change of the state of the substance which can be reversed.
However, both chemical and physical changes results in change of state of matter and both process results in change in energy.
Thus, we can conclude that the similarities between chemical and physical changes include change in state of matter and both process involve change in energy.
(it's alre answered but here it again 'NOTE: not my answer')
The Enthalpy profile of chemical reaction is shown at the river. On the graph, indicate the magnitude of:
Energy was given out in the process as such the reaction must be exothermic given the loss of energy.
What is a reaction profile?The reaction profile shows the the interaction between substances. Now the vertical axes shows the energy while the horizontal axes shows the course of the reaction. The hump at the top of the profile shows the activation energy. The activation energy is the maximum energy that is required for reactants to cross the barrier and become products.
Now we know that the endothermic reaction is one in which energy is taken in while an exothermic reaction is one in which energy is given out.
As such we can see from the graph that the energy of the reactants is greater than that of the products. This implies that energy was given out in the process as such the reaction must be exothermic given the loss of energy.
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Determine the [oh−] , ph, and poh of a solution with a [h ] of 7. 2×10−8 m at 25 °c
The pH= 7.57 , pOH = 6.86, and [OH-] = 1.58 x 10⁻⁴ M M of the given solution.
What is pH?pH is a scale that measures the acidity and basicity of a solution. Its ranges from 1 to 14. Seven is neutral.
The H given is 7. 2 × 10⁻⁸ m
Calculating the pOH
[H⁺] = 10^(-7.20)
[H⁺] = 6.31 x 10⁻⁹ M
pOH = 14 - 7.2
pOH = 6.8
Calculating the [oh−]
[OH⁻] = 1 x 10⁻¹⁴ / 6.31 x 10⁻⁹
[OH⁻] = 1.58 x 10⁻⁴ M
Calculating the pH
pH = 14 - 6.43
pH = 7.57
Thus, the pH= 7.57 , pOH = 6.86, and [OH-] = 1.58 x 10⁻⁴ M.
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Draw the structure of the major organic product formed in the reaction of m‑cresol with sodium hydroxide. Ignore counterions.
The reaction between m-cresol and sodium hydroxide will create sodium m-cresolate and water.
What is organic creation?The structure of the organic creation (sodium m-cresolate) and the reaction is described in the attached picture.
In the late 1700s and earlier 1800s, organic biological products were isolated by Scheele, and Chevreuil dissolved carboxylic acids from the saponification of fats. Organic chemistry had formed. Lavoisier invented and Berzelius enhanced combustion research for the organic description. Organic Chemistry was first diagnosed as a branch of modern science in the earlier 1800s by Jon Jacob Berzelius. He compartmentalized chemical combinations into two groups-organic and inorganic, representing if they came from minerals or non-living significance.Organic chemistry is important because it is the study of life and all of the chemical responses related to life. Several professions apply an interpretation of organic chemistry, such as doctors, veterinarians, dentists, pharmacologists, chemical makers, and chemists.To learn more about organic creation, refer to:
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Calculate the ph of a solution formed by mixing 250. 0 ml of 0. 15 m nh4cl with 200. 0 ml of 0. 12 m nh3. the kb for nh3 is 1. 8 × 10-5.
i. 9. 45
ii. 4. 74
iii. 9. 06
iv. 04. 55
v. 9. 26
The potential of the hydrogen in water gives the pH of the acidity and basicity of the solution. The pH of the solution is 9.06. Thus, option iii is correct.
What is pH?The pH of a substance is given by the subtraction of the pOH from 14 which is the range of the pH scale.
The dissociation reaction for ammonia is given as,
NH₃ (aq) + H₂O (l) ⇄ NH₄⁺ (aq) + OH⁻ (aq)
Here, the concentration of ammonia is [NH₃] - x, ammonium ion is [NH₄⁺] + x, and hydroxide ion is x.
The molar concentration of ammonia is,
M = (0.12 M × 0.2 L) ÷ 0.45 L = 0.053 M
The molar concentration of ammonium ion is,
M = (0.15 M × 0.25 L) ÷ 0.45 L = 0.083 M
From the base dissociation constant and previous concentration from the reaction, the value of x or hydroxide ion is calculated as,
Kb = [NH₄⁺][OH⁻] ÷ [NH₃]
1.8 × 10⁻⁵ (0.053 - x) - (0.083 + x) × x = 0
x = [OH⁻] = 1.15 x 10⁻⁵
The pH from the hydroxide ion is calculated as,
pOH = - log [OH⁻]
= - log (1.15 x 10⁻⁵)
= 4.94
Further,
pH = 14 - pOH
= 14 - 4.94
= 9.06
Therefore, option iii. 9.06 is the pH of the solution.
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Which of the following statements statements expresses the following chemical equation with words?
2 K(s) + Cl₂(g) →> 2 KCI(S)
->
Select one:
O a. Four atoms of krypton react with two molecules of Cl₂
O b. Two atoms of potassium react with one molecule of chlorine to produce two molecules of potassium chloride.
O c. One atom of chromium reacts with 1 molecule of calcium to produce 1 molecule of chromium calcide.
O d. Two atoms of potassium react with potassium chloride to produce chlorine gas.
Answer:
option b is the answer of given statementtwo atoms of potassium react with one molecule of chlorine to produce two molecules of potassium chloride
How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?
430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
What is Molarity?The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity.Calculation of Required amount of AgClRemember that mol/L is the unit of molarity (M).
We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.
0.75L×4.0M=3.0mol
Then, using the periodic table's molar mass for AgCl, convert from moles to grams:
3.0mol×143.321gmol=429.963g
The final step is to round to the correct significant figure, which in this case is two: 430g.
Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
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Soil particles, soot, lead (pb), asbestos, sea salt, and sulfuric acid droplets are all types of?
Soil particles, soot, lead (pb), asbestos, sea salt, and sulfuric acid droplets are all types of particulate matter.
The atmosphere is dusty .The solid and liquid particles suspended in the atmosphere .
Examples : Soil particles, soot, lead (pb), asbestos, sea salt, and sulfuric acid droplets are all types of particulate matter
There are different categories of particulate matter. Such as mold spores , bacteria , dust , smoke and airborne viral paricles. The major sources of particulates matter are wildfires , dust storms , sea spray , volcanic eruption , and industrial process.
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how many grams of nacl ( 58.44 g/mol) are needed to make 250.0 ml of a 1.50 m solution of nacl?
Answer:
21.92 gm
Explanation:
A 1.5 M solution would have 1.5 * 58.44 = 87.66 gm per liter
you only need 1/4 of this (250 ml) = 21.92 gm
How many different products can be formed from a poorly planned crossed aldol addition?
a. 1
b. 2
c. 3
d. 4
e. 5
There are 4 different products will be formed from a poorly planned crossed aldol addition.
In a crossed aldol condensation, two distinct ketone and aldehyde reactants are used. Due to the possibility of several enolate nucleophiles as well as multiple carbonyl electrophiles, similar reactions typically result in a variety of distinct condensation products.
Ethanol and propanol undergo cross-aldol condensation, which results in two products:
one where ethanol serves as an enolate ion and the other where propanol serves as an enolate ion. 2-Methylbut-2-enal and Pent-2-enal are just the two cross-aldol derivatives.Therefore, the correct answer will be option (d)
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There are four different products can be formed from a poorly planned crossed aldol addition.
So the correct option is D
Two distinct ketone and aldehyde reactants are used in a crossed condensation reaction. Due to presence of distinct ketone and aldehyde reactants there are possibility of formation of several enolate ion nucleophiles as well as multiple carbonyl electrophile .
Example : Ethanal and propanone undergoes cross-aldol condensation reaction and give results in two products.
First case: ethanal acts as enolate ion
Second case: propanone acts as enolate ion
Third case: when self condensation is also a product.
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Please Help!
9/4Be + 4/2He = 12/6c + ?
a. 1/0n
b. 0/1e
c. 0/1H
d. 2/1H
Answer:
(1/0)n
See attached explanation.
A mixture of 10. 0 g of Ne and 10. 0 g ar have a total pressure of 1. 6 atm. What is the partial pressure of Ne?
Answer:
1.1 atm
Explanation:
moles of neon = 10.0g /20.2g/mole =.495 mole
moles of ar = 10.0 g /39.9 g/mole= .251 mole
the partial pressure of each is determined by their mole fractions of the entire mix
Ne .495 mole / (.495 + .251 mole) * 1.6 atm =
1.1 atm ( to two significant figures)
When the equation __no2 __h2o __o2 → __hno3 is balanced, the coefficient of hno3 is:_________
When the equation __[tex]NO_{2}[/tex] __[tex]H_{2} O[/tex] __[tex]O_{2}[/tex] → __[tex]HNO_{3}[/tex] is balanced, the coefficient of hno3 is 4.
An expression for a chemical reaction would be referred to as balanced if both the reactants as well as the products have an identical number of atoms with a total charge for each component of the reaction. In other words, two sides of the reaction have equal amounts of mass as well as charge.
The given unbalanced equation is __[tex]NO_{2}[/tex] __[tex]H_{2} O[/tex] __[tex]O_{2}[/tex] → __[tex]HNO_{3}[/tex] .
It can be seen that the count of hydrogen in reactant side 2 on the other hand the count of hydrogen atom is 1.
By multiplying by 4 as the coefficient of and [tex]NO_{2}[/tex] and by 2 as the coefficient of water then equation will be balanced.
The balanced chemical equation will be expressed as:
4 [tex]NO_{2}[/tex] + 2[tex]H_{2} O[/tex] +[tex]O_{2}[/tex] → 4[tex]HNO_{3}[/tex] .
Therefore, when the equation __[tex]NO_{2}[/tex] __[tex]H_{2} O[/tex] __[tex]O_{2}[/tex] → __[tex]HNO_{3}[/tex] is balanced, the coefficient of hno3 is 4.
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What is the molality of a solution prepared by dissolving 3. 41 g of c6h12o6 in 85 ml of water:__________
When 3. 41 g of C6H12O6 is dissolved in 85 ml of water the molality is 2.2m.
What is molality?Molality is the amount of a substance dissolved in a certain mass of solvent.
Molality = moles of solute/ mass of solvent (kg)
Given,
Mass of solute = 3.14g
Molar mass of solute = 180 g
Mole of solute= given mass/molar mass
= 3.14/180
= 0.0189 mol.
Volume of solvent = 85 ml
Density of water = 1 g/cm3
Density = mass/ volume
mass = density × volume
= 1× 85
= 85g
Molality = (0.0189/ 85) × 1000
= 2.2m
Thus we find that the molality of given solution is 2.2m.
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Explain why when an ion is formed, the mass of the atom does not change.
Answer:
Atoms are made up of protons, neutrons, and electrons. The mass of an atom is determined by the total number of neutrons and protons in the nucleus. The difference between an atom and an ion is the number of electrons. The change of electrons does not change the mass because electrons have a negligible mass. In other words, the mass of electrons is so small, it is considered insignificant.
When the reactants have less enthalpy than the products, then __________. A. heat energy is given out B. None of these C. heat energy is absorbed D. the reaction will be complete
When the reactants have less enthalpy than the products, then heat energy is given out. That is option A.
What is exothermic reaction?An exothermic reaction is a type of reaction in which the energy level of the reactants are higher than that of the product.
It is this discrepancy in the energy levels of both the reactants and products would lead to the generation and release of energy into the surrounding environment.
The enthalpy of exothermic reaction is gotten by the difference between the energy needed to break the bonds of reactants and the energy needed for the formation of products.
Therefore,when the reactants have less enthalpy than the products, then heat energy is given out.
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How many milliliters of an aqueous solution of 0. 195 m sodium sulfate is needed to obtain 4. 27 grams of the salt?
The volume of the aqueous solution of sodium sulfate required is 153.85 mL.
Number of moles of the saltThe number of moles of the salt in the given mass is calculated as follows;
moles = reacting mass / molar mass
molar mass of sodium sulfate = 142 g/mole
moles = (4.27) / (142)
moles = 0.03 mole
Volume of the aqueous solution of sodium sulfateConcentration = moles/volume in liters
0.195 = 0.03/V
V = 0.03/0.195
V = 0.15385 liters
V = 153.85 mL
Thus, the volume of the aqueous solution of sodium sulfate required is 153.85 mL.
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The resulting solution made from the combination of 50 ml of 1.0 m lioh with 50 ml of 1.0 m hbr will be identical in all respects to 100 ml of?
The resulting solution made from the combination of 50 ml of 1.0 M LiOH with 50 ml of 1.0 M HBr will be identical in all respects to 100 ml of 0.5 M LiBr.
What is Molarity ?Molarity (M) is defined as the number of moles of solutes dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I unit of Molarity is molar (M) or mol/L.
It is expressed as:
Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume (in L)}}[/tex]
Number of moles = Molarity × Volume
Moles of LiOH = 1.0 × 0.05 [1 ml = 0.001 L]
= 0.05 mol
Moles of HBr = 1.0 × 0.05 [1 ml = 0.001 L]
= 0.05 mol
Now put the values in above formula we get
Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume (in L)}}[/tex]
= [tex]\frac{0.05}{0.1}[/tex]
= 0.5 M LiBr
Thus from the above conclusion we can say that The resulting solution made from the combination of 50 ml of 1.0 M LiOH with 50 ml of 1.0 M HBr will be identical in all respects to 100 ml of 0.5 M LiBr.
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What is the molar absorptivity () of benzoic acid at 228 nm? assume that the path length is 1. 00 cm
The molar absorptivity () of benzoic acid at 228 nm? assume that the path length is 1. 00 cm is = 11178 M-1. cm-1
We are given, absorbance spectrum and from that the absorbance of benzoic acid at 228 nm
Absorbance = 0.8
Now we need to calculate the molar absorptivity of benzoic acid at 228 nm
We know at the 228 nm the A = 0.8 and C = 8.74 mg/L.
We also given the l = 1 cm
Moles of benzoic acid = 0.00874 g / 122.12 g.mol-1
= 7.16*10-5 moles
So, C of benzoic acid = 7.16*10-5 moles / L
We know the
ε = A/C*l
= 0.80 / 7.16*10-5 M. 1 cm
= 11178 M-1. cm-1
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