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Answer:

c. 3  

yes you are right, good job!!

Step-by-step explanation:

18 divided by what equals 2?

18 / 2 = 9 so 18 / 9 = 2

so 27 / 9 = y which y = 3

check: 9 x 3 = 27

Answer:

Yes, C

Step-by-step explanation:

18/2 = 9 so you need to divide 27 by 9 to get 3

Using it's concept, the domain of the function is given as follows:

{x| –2 ≤ x <= 5}

The domain of a function is the set that contains all possible input values for the function.

The function described is defined for x between -2 and 5, hence the domain is given by the following interval:

{x| –2 ≤ x <= 5}

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Answer:

{x| –2 ≤ x < 5}

Step-by-step explanation:

Answer: $4.50

Step-by-step explanation:

Original Price: $6

Discount: 25%

Discounted Price: 6*25%= $1.5

                              $6-$1.5= $4.5

The term that must be added to the equation x2+4x=1 to make it into a perfect square is 4.

Any equation that can be rewritten in standard form as where x represents an unknown, a, b, and c represent known numbers, and where a 0 is true is a quadratic equation. Since there is no ax2 term, the equation is linear if a = 0, not quadratic.

This is true because the Latin word quadratum, which means "square," plus the fact that the area of a square with side length x is equal to x2, make up what is known as the quadratic (or "square-like") definition of a polynomial equation with exponent two.

x²+4x=1

as, the x has coefficient 4.

so,

half the coefficient of x and add and subtract the square of the remaining.

x²+4x + 2 ² - 2² =1

Now,

make the whole square term

x²+4x + 2 ² - 4 - 1=0

( x + 2)² -5= 0

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Answer:

  s = -24

Step-by-step explanation:

This is a 2-step linear equation, so can be solved the way all 2-step equations are solved.

Step 1

Identify the constant term on the side of the equation with the variable term, and add its opposite to both sides.

  [tex]7 = \dfrac{1}{6}s+11\qquad\text{given}\\\\7-11=\dfrac{1}{6}s+11-11\qquad\text{add $-11$ to both sides}\\\\-4=\dfrac{1}{6}s\qquad\text{simplify}[/tex]

Step 2

Multiply both sides by the inverse of the coefficient of the variable.

  [tex](6)(-4)=(6)\left(\dfrac{1}{6}s\right)\qquad\text{multiply both sides by 6}\\\\\boxed{-24=s}\qquad\text{simplify}[/tex]

Often, when equations contain fractions, you are advised to "eliminate fractions" as a first step. That generally means you multiply both sides of the equation by a suitable common denominator.

Here, the only denominator is 6, so the fraction can be eliminated by multiplying both sides of the equation by 6.

  [tex]7=\dfrac{1}{6}s+11\qquad\text{given}\\\\6(7)=6\left(\dfrac{1}{6}s+11\right)\qquad\text{multiply both sides by 6}\\\\42=s+66\qquad\text{simplify}\\\\42-66=s+66-66\qquad\text{add the opposite of 66 to both sides}\\\\\boxed{-24=s}\qquad\text{simplify}[/tex]

You will note this requires the same number of steps, but you don't have to mess with fractions after the first step.

The value we found for the variable can be checked in the original equation.

  [tex]7=\dfrac{1}{6}(-24)+11\\\\7=-4+11\qquad\text{true}[/tex]

The periodic time, t, of a pendulum range directly as the square root of its length, l. t = 6 when l = 9. If l = 25 then the periodic time, T exists at 10.

The period, or periodic time, of a periodic variation of a quantity, exists described as the time interval between two consecutive repetitions.

Given: The periodic time, t, of a pendulum goes directly as the square root of its length, l if t = 6 when l = 9.

If [tex]T \alpha\ l^2[/tex] then [tex]T^2[/tex] α [tex]\sqrt{l}[/tex]

[tex]T^2 = l[/tex]

Let, [tex]T^2 = kl,[/tex] where k exists constant

t = 6 when l = 9.

So, [tex]6^2 = k*9[/tex]

[tex]k = 6^2/9 = 4[/tex]

[tex]T^2 = 4*l[/tex]

If l = 25

[tex]T^2 = 4 * 25 = 100[/tex]

[tex]T = \sqrt{100}[/tex]

T = 10

Therefore, the periodic time, T exists 10.

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Answer:

$50

Step-by-step explanation:

x is distance and y is cost because the cost is dependent on the distance which makes the distance the independent variable. you can always use y=mx+b for these problems!!

Intercepts with the axes are where your line touches the x or y axis. An example is a straight line, say, y=4x+2. In this case, the y-intercept is 2 because the line touches the y-axis at (0, 2). With y=mx+b format, the y-intercept is b. To find the x-intercept of an equation in y=mx+b format, set y to zero and solve for x. In a parabola, the x-intercepts would be the roots. An example of this is x^2 - 5x + 4 = 0. The roots here are (4,0) and (1,0). Hopefully this helped.

Answer:

The graph of g(x) has a y-intercept at (0,0) and a slope of -2.

The corresponding angles are ∠2 and ∠6 i.e., ∠2≅∠6 according to the corresponding angles theorem. So, option 2 is correct.

The theorem states that,

The lines 'AB' and 'CD' are parallel and cut by a transverse 'EF' if and only if their corresponding angles are congruent.

The corresponding angles are those which lie on the same side of the transverse one is interior and the other is an exterior angle.

From the diagram,

Lines 'AB' and 'CD' are parallel and line 'EF' cuts these parallel lines.

So, the corresponding angles formed are:

(∠1, ∠5), (∠2, ∠6), (∠3, ∠7), and (∠4, ∠8)

According to the theorem, they are congruent. I.e.,

∠1 ≅ ∠5

∠2 ≅ ∠6

∠3 ≅ ∠7

∠4 ≅ ∠8

So, option 2 is correct.

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Disclaimer: The given question is incorrect. Here is the correct question.

Question: Lines 'c' and 'd' are parallel lines cut by the transversal 'p'. Which must be true by the corresponding angles theorem?

1) ∠1 = ∠7

2) ∠2 = ∠6

3) ∠3 = ∠5

4) ∠5 = ∠7

C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride. This can be obtained by converting the statements to algebraic equation with variables and constants.

Here in the question it is given that,

The total cost charged for a day of fun at Aussie World consists of

We have to find a rule for the total cost, C, where r rides are taken.

For one ride the rate is 3 ⇒ therefore for r rides the rate is 3r

We can convert the statements to algebraic equation so that we get the required rule,

⇒ The total cost consists of entry fee and rate of rides

⇒ The total cost = entry fee + rate of rides

⇒ C = 15 + 3r (from the given information)

⇒ C = 3r + 15

Hence C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride.

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Answer:

option c

Step-by-step explanation:

option c is a correct answer

The lower and the upper class limit are as follows

interval  lower limit  upper limit

10-14          10                14

15-19          15                19

20-24         20              24

25-29           25            29

This is further explained below.

Generally, The lower class limit and the upper-class limits are just the minima and maximum values that are allowed in each class, respectively: The gap that exists between the upper-class limit and the lower class limit is referred to as the class interval.

In conclusion, The lower and the upper class limit are as follows

interval  lower limit  upper limit

10-14          10                14

15-19          15                19

20-24         20              24

25-29           25            29

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Just me:

? I will just explain what I understand

Answer:

(Think hard) If you cut a snake in half you get 1/2 but if you cut it into 4's 1/5

I tried.

These are some of the ways you can make 15 by adding three numbers together.

The first way is doing  6+6+3.There are some more ways to do it too.

2nd way is 6+4+5.

3.   1+6+6

4.   5+5+5

Answer:

1178 because 31 dollars an hour for 38 hours you would multiply or times 31 and 38 and get 1178 for total money earned

The directrix of the parabola with equation (y + 3)² = 8 · (x - 3) is equal to y = - 5. (Correct choice: B)

According to the given statement, we have a parabola of the form (y - k)² = 4 · p · (x - h), whose axis of symmetry is parallel to the x-axis. The directrix is always perpendicular to the axis of symmetry and therefore the equation of the directrix is equivalent to x = h - p, where p is the distance from the vertex to the focus.  

If we know that the equation of the parabola (y + 3)² = 8 · (x - 3), the equation of the directrix is:

y = - 3 - 2

y = - 5

The directrix of the parabola with equation (y + 3)² = 8 · (x - 3) is equal to y = - 5. (Correct choice: B)

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Answer:

4.378 MPH

Step-by-step explanation:

          Distance in Miles

MPH= -------------------------

           Time in Hours

19.7/4.5 = 4.378 MPH

The image of the point P(-3, 2) under the translation T<2,1> is (-1, 3)

The coordinate point is given as:

P = (-3, 2)

The translation is given as

T<2,1>

The translation can be represented as:

(x, y) = (x + 2, y + 1)

So, we have the following equation

P' = (-3 + 2, 2 + 1)

Evaluate the sum

P' = (-1, 3)

Hence, the image of the point P(-3, 2) under the translation T<2,1> is (-1, 3)

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Answer:

75%

Step-by-step explanation:

3/4 ie 75/100. .........edge

Answer:

-6

Step-by-step explanation:

Additive inverse is the number that when added to A gives a result of zero

A + inverse = 0

6 + inverse = 0

inverse = -6

Answer:

figure A = 3 units

figure B = 9 x 3 = 27 units

scale factor =

[tex] \frac{3}{27 } = \frac{1}{9} [/tex]

so the scale factor = 9

By simplifying the fraction 10/28 ÷ 32/49 exists 35/64.

The first stage of dividing fractions exists to estimate the reciprocal (reverse the numerator and denominator) of the second fraction. Subsequently, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if required.

To find the reciprocal of the divisor

Reciprocal of 32/49 = 49/32

Now, multiply it by the dividend, then we get

So, 1028 ÷ 3249 = 10/28 × 49/32

= (10 × 49)/(28 × 32) = 490/896

After decreasing the fraction, the answer exists at 35/64.

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The value of the mean absolute percentage error of the forecast for march found by the exponential smoothing method with a smoothing constant of 0. 3 is  16.94%

The equation is given as

∝At + (1-∝) Ft

The value for Alpha = 0.7

1 - ∝ = 1 - 0.7

= 0.3

Forecast in match = 62

Ft = 51. 5

the difference = 62 - 51.5

= 10.5

The error = 10.5/62 * 100

= 16.94%

Hence the value of the  mean absolute percentage error of the forecast for march found by the exponential smoothing method with a smoothing constant of 0. 3 is  16.94%

The past demand data shown below can be regarded as stationary.

Month Demand

January

50

February

55

March

62

April

45

What is the mean absolute percentage error of the forecast for March found by the exponential smoothing method with a smoothing constant of 0.3?

O a. 14.68%

Ob. 16.94%

O c. 12.57%

Od. 11.33%

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Answer:

Step-by-step explanation:

To find the x intercepts, substitute in 0 for y and solve for x

So,

2x^2+2x-4 = 0

2(x^2+x-4) = 0

2/2(x^2+x-4) = 0/2

x^2+x-4 = 0

(x-1) (x+2) = 0

now,

x-1 = 0

x = 1

or

x+2 = 0

x = -2

The x intercepts for the parabola (1,0), (-2,0)

Answer: A. V: x = –4; H: y = 4

Step-by-step explanation:

Answer:

Step-by-step explanation:

part A:   when you graph both y=7x-9 and y=3x-1 the two lines will intersect this is how you solve the graphing part of the system of equations.

Both of these lines are in slope form (y=mx+b) where m is the slope which is 7 and 3 and b is the y-intercept which is -1 and -9.

part B

7x-9=3x-1

subtract 3x from both sides

4x-9=-1  

add 9 to both sides

4x=8  

divide both sides by 4

x=2,

making y=3x-1 become:

y=3(2)-1=6-1=5,  

the answer is (2,5)

The p-value from the information about the recently televised broadcast is B. 0.9999.

From the information given, n = 5000 and the level of significance is 0.01.

The computed z value is -8.84.

From the z table, the probability value is the value corresponding to the row 8.8 and column 0.04.

This will give a value of 0.9999.

In conclusion, the correct option is B.

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Answer:

Step-by-step explanation:

Convert 2y=-3x+2 into y=mx+b form

[tex]\frac{2y}{2} =\frac{-3x+2}{2}[/tex]

[tex]y=\frac{-3x}{2} +1[/tex]

Y intercept is 1, slope is -3/2

Graph looks like this: