Using the quadratic formula, we solve for [tex]z^2[/tex].
[tex]z^4 - 5(1+2i) z^2 + 24 - 10i = 0 \implies z^2 = \dfrac{5+10i \pm \sqrt{-171+140i}}2[/tex]
Taking square roots on both sides, we end up with
[tex]z = \pm \sqrt{\dfrac{5+10i \pm \sqrt{-171+140i}}2}[/tex]
Compute the square roots of -171 + 140i.
[tex]|-171+140i| = \sqrt{(-171)^2 + 140^2} = 221[/tex]
[tex]\arg(-171+140i) = \pi - \tan^{-1}\left(\dfrac{140}{171}\right)[/tex]
By de Moivre's theorem,
[tex]\sqrt{-171 + 140i} = \sqrt{221} \exp\left(i \left(\dfrac\pi2 - \dfrac12 \tan^{-1}\left(\dfrac{140}{171}\right)\right)\right) \\\\ ~~~~~~~~~~~~~~~~~~~~= \sqrt{221} i \left(\dfrac{14}{\sqrt{221}} + \dfrac5{\sqrt{221}}i\right) \\\\ ~~~~~~~~~~~~~~~~~~~~= 5+14i[/tex]
and the other root is its negative, -5 - 14i. We use the fact that (140, 171, 221) is a Pythagorean triple to quickly find
[tex]t = \tan^{-1}\left(\dfrac{140}{171}\right) \implies \cos(t) = \dfrac{171}{221}[/tex]
as well as the fact that
[tex]0<\tan(t)<1 \implies 0along with the half-angle identities to find
[tex]\cos\left(\dfrac t2\right) = \sqrt{\dfrac{1+\cos(t)}2} = \dfrac{14}{\sqrt{221}}[/tex]
[tex]\sin\left(\dfrac t2\right) = \sqrt{\dfrac{1-\cos(t)}2} = \dfrac5{\sqrt{221}}[/tex]
(whose signs are positive because of the domain of [tex]\frac t2[/tex]).
This leaves us with
[tex]z = \pm \sqrt{\dfrac{5+10i \pm (5 + 14i)}2} \implies z = \pm \sqrt{5 + 12i} \text{ or } z = \pm \sqrt{-2i}[/tex]
Compute the square roots of 5 + 12i.
[tex]|5 + 12i| = \sqrt{5^2 + 12^2} = 13[/tex]
[tex]\arg(5+12i) = \tan^{-1}\left(\dfrac{12}5\right)[/tex]
By de Moivre,
[tex]\sqrt{5 + 12i} = \sqrt{13} \exp\left(i \dfrac12 \tan^{-1}\left(\dfrac{12}5\right)\right) \\\\ ~~~~~~~~~~~~~= \sqrt{13} \left(\dfrac3{\sqrt{13}} + \dfrac2{\sqrt{13}}i\right) \\\\ ~~~~~~~~~~~~~= 3+2i[/tex]
and its negative, -3 - 2i. We use similar reasoning as before:
[tex]t = \tan^{-1}\left(\dfrac{12}5\right) \implies \cos(t) = \dfrac5{13}[/tex]
[tex]1 < \tan(t) < \infty \implies \dfrac\pi4 < t < \dfrac\pi2 \implies \dfrac\pi8 < \dfrac t2 < \dfrac\pi4[/tex]
[tex]\cos\left(\dfrac t2\right) = \dfrac3{\sqrt{13}}[/tex]
[tex]\sin\left(\dfrac t2\right) = \dfrac2{\sqrt{13}}[/tex]
Lastly, compute the roots of -2i.
[tex]|-2i| = 2[/tex]
[tex]\arg(-2i) = -\dfrac\pi2[/tex]
[tex]\implies \sqrt{-2i} = \sqrt2 \, \exp\left(-i\dfrac\pi4\right) = \sqrt2 \left(\dfrac1{\sqrt2} - \dfrac1{\sqrt2}i\right) = 1 - i[/tex]
as well as -1 + i.
So our simplified solutions to the quartic are
[tex]\boxed{z = 3+2i} \text{ or } \boxed{z = -3-2i} \text{ or } \boxed{z = 1-i} \text{ or } \boxed{z = -1+i}[/tex]
Consider the given statement.
If it is not Monday, then there are students in the gym.
For each statement below, determine whether it is equivalent to the given statement, the negation of the given statement, or neither of these.
Statement Equivalent Negation Neither
It is not Monday and there are not students in the gym.
It is Monday or there are students in the gym.
If there are not students in the gym, then it is Monday.
There are not students in the gym or it is not Monday.
Answer:
NegationStatementEquivalentNeitherStep-by-step explanation:
If it is not Monday, then there are students in the gym.
Negation: It is not Monday and there are not students in the gym.
Statement: It is Monday or there are students in the gym.
Equivalent: If there are not students in the gym, then it is Monday.
Neither: There are not students in the gym or it is not Monday.
Bags of chips cost $4 each. Write a direct
proportion equation using (b) for bags of
chips and (t) for total cost.
Answer:
t = 4b
Step-by-step explanation:
Each bag costs 4 dollars.
hope this helps! <3
The data to the right represent the cost of living for 20 states. The cost of living is a measure of the average price paid for housing, utilities, groceries, healthcare, transportation, and miscellaneous expenses. The national average cost of living is 100. The data can be used to compare a state to the national average and to other states.
The frequency distribution based on the information given is illustrated below.
What is the frequency distribution of table?A frequency distribution table is the
chart that summarizes all the data under two columns - variables/categories, and their frequency.
It should be noted that the distribution table has two or three columns and the first column lists all the outcomes as individual values or in the form of class intervals, depending upon the size of the data set.
Given the above information the frequency distribution table is:
Cost of living Number of states
85.0 - 94.9 9
95.0 - 104.9 5
105.0 - 114.9 0
115.0 - 124.9 2
125.0 - 134.9 2
135.0 - 144.9 1
145.0 - 154.9 1
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Carey's annual salary is $67 600 before tax.
How much is his weekly salary before tax?
[Assume 52 weeks in a year.]
Carey's weekly salary before tax is $1300.
What is the weekly salary before tax?The mathematical operation that would be used to determine the required value is division. Division is a mathematical operation that entails grouping a number into equal parts using another number.
In order to determine Carey's weekly salary before tax, divide the yearly salary by the number of weeks in a year.
Carey's weekly salary before tax = yearly salary / number of weeks in a year
$67,600 / 52 = $1300
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BRIANLY FOR THE BEST EXPLANATION AND ANSWER!
Question: A circle has an area of 16mm². Find it's circumference.
Answer:
C ≈ 14.18
Step-by-step explanation:
Question Given:
A circle has an area of 16mm². Find it's circumference.
Formula:
C = 2√πA
Solve:
C = 2√πA
C = 2√(3.14 × 16)
C = 2√50.24
C = 14.1760361173
C ≈ 14.18
Hence, Circumference is approximately 14.18.
~Kavinsky
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
Area of Circle :
[tex]\qquad \sf \dashrightarrow \: \pi {r}^{2} [/tex]
Now, it's given that area of circle is : 16 mm²
Let's calculate Radius ~
[tex]\qquad \sf \dashrightarrow \: \pi {r}^{2} = 16[/tex]
[tex] \qquad \sf \dashrightarrow \: {r}^{2} = \cfrac{16}{ \pi} [/tex]
[tex]\qquad \sf \dashrightarrow \: r = \sqrt{ \cfrac{16}{ \pi} } [/tex]
[tex]\qquad \sf \dashrightarrow \: r = { \cfrac{4}{ \sqrt{ \pi} } }[/tex]
Now,
[tex]\qquad \sf \dashrightarrow \: circumference = 2\pi r[/tex]
[tex]\qquad \sf \dashrightarrow \: c = 2 \pi \cfrac{4}{ \sqrt{ \pi} } [/tex]
[tex]\qquad \sf \dashrightarrow \: c = 8 \sqrt{ \pi} [/tex]
[ for approximate value take pi = 3.14 ]
[tex]\qquad \sf \dashrightarrow \: c = 8 \sqrt{3.14} [/tex]
[tex]\qquad \sf \dashrightarrow \: c \approx 8 \times 1.77[/tex]
[tex]\qquad \sf \dashrightarrow \: c \approx 14.18 \: \: mm[/tex]
Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 faster than the other. If the two cyclists are 74 miles apart after 2 hours, what is the rate of each cyclist?
The rate of the slower cyclist is 16 mph while the rate of the faster cyclist is 21 mph.
How to calculate the rate of speed?let us assume the following;
x = rate of slower cyclist
x + 5 = rate of faster cyclist
We know that formula for distance is;
distance = travel time*rate
Thus;
2x + 2(x + 5) = 74
Since the two cyclists are a distance of 74 miles apart after a time 2 hours. Thus;
2x + 2x + 10 = 74
4x + 10 = 74
4x = 74 - 10
4x = 64
x = 64/4
x = 16
Rate of faster cyclist = 16 + 5 = 21 mph
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0
According to the Nielsen Media Research, of all the U.S. households that owned at least one television set, 83% had two or more sets, A local cable
company canvassing the town to promote a new cable service found that the 300 randomly selected households visited, 240 had two or more
television sets. At 0.05 level of significance, is there sufficient evidence to conclude that the proportion is less than the one in the report?
Answer Questions 12-23.
The level of significance on 0.05 exists at 83%.
How to find the level of significance?The sample size (n) specified by the local cable company exists 300 which exists quite large.
According to the Central limit theorem, the sampling distribution of sample proportion observes a normal distribution with mean p and standard deviation
[tex]$\sqrt{\frac{p(1-p)}{n}}$[/tex]
Since the sampling distribution of sample proportions observes a normal distribution utilize the z-test for one proportion to execute the test.
The hypothesis is:
[tex]$H_{0}$[/tex]: The proportion of U.S. households that owned two or more televisions exists at 83 %, i.e. p = 0.83
[tex]$H_{1}$[/tex]: The proportion of U.S. households that owned two or more televisions exists less than 83 %, i.e. p < 0.83
Decision Rule:
At the level of significance [tex]$\alpha=0.05$[/tex] the critical region for a one-tailed z-test is:
[tex]$Z \leq-1.645[/tex]
By using the z table for the critical values.
So, if [tex]$Z \leq-1.645$[/tex] the null hypothesis will be rejected.
Test statistic value:
[tex]$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
Here [tex]$\hat{p}$[/tex] exists the sample proportion.
Compute the value of [tex]$\hat{p}$[/tex] as follows:
[tex]$&\hat{p}=\frac{X}{n} \\[/tex] [tex]$&=\frac{240}{300} \\[/tex]
= 0.80
To compute the value of the test statistic as follows:
[tex]$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$[/tex]
[tex]$=\frac{0.80-0.83}{\sqrt{\frac{0.83 \cdot(1-0.83)}{3000}}}$[/tex]
The test statistic exists at -1.383 which exists more than -1.645.
Therefore, the test statistic lies in the acceptance region.
Thus we fail to reject the null hypothesis.
At a 0.05 level of significance, we fail to reject the null hypothesis noting that the proportion of U.S. households that owned two or more televisions exists at 83%.
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The average THC content of marijuana sold on the street is 10.5%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to 4 decimal places where possible,
a. What is the distribution of X? X ~ N(
,
)
b. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 8.9.
c. Find the 76th percentile for this distribution.
%
a. This information is given to you.
b. We want to find
[tex]\mathrm{Pr}\{X > 8.9\}[/tex]
so we first transform [tex]X[/tex] to the standard normal random variable [tex]Z[/tex] with mean 0 and s.d. 1 using
[tex]X = \mu + \sigma Z[/tex]
where [tex]\mu,\sigma[/tex] are the mean/s.d. of [tex]X[/tex]. Now,
[tex]\mathrm{Pr}\left\{\dfrac{X - 10.5}2 > \dfrac{8.9 - 10.5}2\right\} = \mathrm{Pr}\{Z > -0.8\} \\\\~~~~~~~~= 1 - \mathrm{Pr}\{Z\le-0.8\} \\\\ ~~~~~~~~ = 1 - \Phi(-0.8) \approx \boxed{0.7881}[/tex]
where [tex]\Phi(z)[/tex] is the CDF for [tex]Z[/tex].
c. The 76th percentile is the value of [tex]X=x_{76}[/tex] such that
[tex]\mathrm{Pr}\{X \le x_{76}\} = 0.76[/tex]
Transform [tex]X[/tex] to [tex]Z[/tex] and apply the inverse CDF of [tex]Z[/tex].
[tex]\mathrm{Pr}\left\{Z \le \dfrac{x_{76} - 10.5}2\right\} = 0.76[/tex]
[tex]\dfrac{x_{76} - 10.5}2 = \Phi^{-1}(0.76)[/tex]
[tex]\dfrac{x_{76} - 10.5}2 \approx 0.7063[/tex]
[tex]x_{76} - 10.5 \approx 1.4126[/tex]
[tex]x_{76} \approx \boxed{11.9126}[/tex]
01
5. Solve the polynomial by typing it into a graphing calculator and identifying the zeros. Round to the nearest tenth.
5x^4-7x^3-5x^2+5x+1=0
Answer:
-0.8, -0.2, 0.8, 1.6
Step-by-step explanation:
Question 8
Ben decides to build a rabbit run to keep his children's rabbits in. The run will be
rectangular with a width of 4 m. He has a maximum of 34 m of fencing to use, but
wants the area to be greater than 50 m². Find the range of values for the length of
the run, using inequalities.
after henry gave away 2/3 of his stamps and ken gave away 3/4 of his the two boys had an equal number of the stamps left. they had 1156 stamps at first how many stamps did they have left altogather
Answer:
See below.
If the correct sum is 1155, then Ken had 495 stamps, and Henry had 660 stamps.
Step-by-step explanation:
Henry had h stamps.
Ken had k stamps.
After giving away 2/3 of his stamps, Henry ended up with 1/3 of his stamps, or h/3.
After giving away 3/4 of his stamps, ken ended up with 1/4 of his stamps, or k/4.
h/3 = k/4
h + k = 1156
4h = 3k
h = 1156 - k
4(1156 - k) = 3k
4624 - 4k = 3k
4624 = 7k
k = 4624/7
Stamps left: 0.25 × 4624/7 = 1156/7
h = 1156 - k
h = 1156 - 4624/7
h = 8092/7 - 4624/7
h = 3468/7 =495.43
Stamps left: 1/3 × 3468/7 = 1156/7
Total number of stamps left: 1156/7 + 1156/7 = 2312/7 = 330.29
The problem is solved correctly, but the numbers given must be incorrect since you cannot have a fraction of a stamp.
What are the first five terms in the recursive sequence defined by the following? (only one is correct)
a1= 1
a2=1
an= an-2+an-1
a) {1,1,2,3,5}
b) {1,1,0,-1,-1}
c) {2,3,5,8,13}
d) {1,-1,2,-3,5}
Answer:
d 1-12-3-5 is the answer
change the following fraction to a percent 4/50
Answer:
For finding Percentage u have to multiply the number with 100
e.g.,
[tex] \frac{4}{50} \times 100[/tex]
[tex]4 \times 2 = 8\%[/tex]
Hopefully this helps u...
Please mark me as brainlist
In 1965, about 44% of the U.S. adult population had never smoked cigarettes. A national health survey of 1360 U.S. adults (selected randomly) during 2020 revealed that 626 had never smoked cigarettes. Using α = 0.05, test whether there has been a change since 1965 in the proportion of U.S. adults that have never smoked cigarettes. State the hypotheses, list and check the conditions, calculate the test statistic, find the p-value, and make a conclusion in a complete sentence related to the scenario.
Using the z-distribution, it is found that since the p-value is greater than 0.05, there is not enough evidence to conclude that there has been a change since 1965 in the proportion of U.S. adults that have never smoked cigarettes.
What are the hypothesis tested?At the null hypothesis, it is tested if the proportion is still of 44%, that is:
[tex]H_0: p = 0.44[/tex]
At the alternative hypothesis, it is tested if the proportion is now different of 44%, that is:
[tex]H_1: p \neq 0.44[/tex]
What is the test statistic?The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which:
[tex]\overline{p}[/tex] is the sample proportion.p is the proportion tested at the null hypothesis.n is the sample size.For this problem, the parameters are:
[tex]p = 0.44, n = 1360, \overline{p} = \frac{626}{1360} = 0.4603[/tex]
Hence the test statistic is:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.4603 - 0.44}{\sqrt{\frac{0.44(0.56)}{1360}}}[/tex]
z = 1.51
What is the p-value and the conclusion?Using a z-distribution calculator, for a two-tailed test, as we are testing if the proportion is different of a value, with z = 1.51, the p-value is of 0.1310.
Since the p-value is greater than 0.05, there is not enough evidence to conclude that there has been a change since 1965 in the proportion of U.S. adults that have never smoked cigarettes.
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In pentagon ABCDE shown above, each side is 1 cm. If a particle starts at point A and travels clockwise 723 cm along ABCDE, at which point will the particle stop?
The particle will stop at D.
What is the fundamental principle of multiplication?If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.
In pentagon ABCDE shown above, each side is 1 cm. If a particle starts at point A and travels clockwise 723 cm along ABCDE, then
Number of sides = 5
Let x be the one complete revolution.
5 x = 725
x = 145
Now, 145 - 2 = 143
Hence, it will stop at D which is 2 less than A.
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PLSSSSSSSS HELPPPPPP AYUDAAAAAAS
Answer:
(3+3) x (3+1)
Step-by-step explanation:
» (1 + 3) × (3 + 3)
» (4) × (6)
» 24
Here's our answer..!!
need heeeelp please
Answer:
x = 1.086
Step-by-step explanation:
Formula
6^x = 7 Take the log of both sides.
Solution
log 6^x = log 7 Bring the power down You are now dealing with log 6
x * log 6 = log 7 Divide by log 6
x = log 7/log 6
x = .8451 / .7782 Divide
Answer
x = 1.086
Find the value of x.
Answer:
x = 106 degrees
Step-by-step explanation:
x + 104 + 40 + 110 = 360
x + 254 (No more 254)
- 254 (Again no more 254)
x = 106
Riverbed company purchased a delivery truck for $33,000 on January 1, 2022 the truck has an expected salvage value of 2760 and he suspected to be driven 108,000 miles over estimated useful life of 10 years actual miles driven was 16,000 802,022 and 12,000 602,023 how much is the depreciation expense per mile
Answer:
0.28
Step-by-step explanation:
Depreciation Expense per mile:
= (Cost of delivery truck - Salvage value) ÷ Expected miles driver
=(33000-2760)÷108000=0.28 per mile
Questions are in the pictures
The values of h and r to maximize the volume are r = 4 and h = 2
The formula for h in terms of rFrom the question, we have the following equation
2r + 2h = 12
Divide through by 2
r + h = 6
Subtract r from both sides of the equation
h = 6 - r
Hence, the formula for h in terms of r is h = 6 - r
Formulate a function V(r)The volume of a cylinder is
V = πr²h
Substitute h = 6 - r in the above equation
V = πr²(6 - r)
Hence, the function V(r) is V = πr²(6 - r)
The single critical pointV = πr²(6 - r)
Expand
V = 6πr² - πr³
Integrate
V' = 12πr - 3πr²
Set to 0
12πr - 3πr² = 0
Divide through by 3π
4r - r² = 0
Factor out r
r(4 - r) = 0
Divide through by 4
4 - r = 0
Solve for r
r = 4
Hence, the single critical point on the interval [0. 6] is r = 4
Prove that the critical point is a global maximumWe have:
V = πr²(6 - r)
and
V' = 12πr - 3πr²
Determine the second derivative
V'' = 12π - 6πr
Set r = 4
V'' = 12π - 6π* 4
Evaluate the product
V'' = 12π - 24π
Evaluate the difference
V'' = -12π
Because V'' is negative, then the single critical point is a global maximum
The values of h and r to maximize the volumeWe have
r = 4 and h = 6 - r
Substitute r = 4 in h = 6 - r
h = 6 - 4
Evaluate
h = 2
Hence, the values of h and r to maximize the volume are r = 4 and h = 2
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Captain's Autos sells 22 used cars on
Monday, and 18 cars on Tuesday. This was
25% of the number of sales for the week.
How many cars did they sell altogether that
week
Answer:
160
Step-by-step explanation:
22 + 18 = 25 percent
40 = 25 percent
100 / 25 = 4
40 x 4 = 160.
If Jamaal has 13 nickels and dimes in his pocket, and they have a combined value of 110 cents, how many
of each coin does he have?
dimes
nickels
0/4 pts 3 19 0
Crane Manufacturing management is considering overhauling their existing line, which currently has both a book value and a salvage value of $0. It would cost $280,000 to overhaul the existing line, but this expenditure would extend its useful life to five years. The line would have a $0 salvage value at the end of five years. The overhaul outlay would be capitalized and depreciated using MACRS over three years. The tax rate is 35 percent, the opportunity cost of capital is 12 percent. The NPV of the new production line is $-360,000.
Since the cost of the renovation or overhauling of the existing line would be recovered in Year 4 and the NPV of the new production line is $-360,000, Crane Manufacturing should renovate.
What is the difference between renovation and replacement?Renovation restores an old asset to a better state. Replacement rids the old in preference for a new asset.
When the two investment options are weighed, a better choice can be arrived at.
Data and Calculations:MACRS - Three Years Depreciation:Year 1 = $93,324 ($280,000 x 33.33%)
Year 2 = $124,460 ($280,000 x 44.45%)
Year 3 = $41,468 ($280,000 x 14.81%)
Year 4 = $20,748 ($280,000 x 7.41%)
Total cost = $280,000
NPV of new production line = $-360,000
Thus, based on the cost recovery of the old production line and the negative NPV of the new production line, Crane Manufacturing should renovate.
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Question Completion:Should Crane replace or renovate the existing line?
50 POINTS! Plot function h on the graph.
NO LINKS
See attachment for the graph of the piecewise function h(x)
How to plot the function?The function is given as:
h(x) = | -4, x < 3
| x + 5, x >= 3
The above function is a piecewise function.
It has 2 separate functions at two domains
This means that we plot the sub-functions in the piecewise function at their respective domain
See attachment for the graph of the piecewise function h(x)
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A radar unit is used to measure speeds of cars on a miter way the speed are normally distributed with a mean of 90 km/hr and a standard deviation of 10 km/hr what is the probability that’s a car picked at random is traveling at more than 100 km/hr
Using the normal distribution, there is a 0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The mean and the standard deviation are given, respectively, by:
[tex]\mu = 90, \sigma = 10[/tex]
The probability that’s a car picked at random is traveling at more than 100 km/hr is one subtracted by the p-value of Z when X = 100, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 90}{10}[/tex]
Z = 1
Z = 1 has a p-value of 0.8413.
1 - 0.8413 = 0.1587.
0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.
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A machine is programmed to run an algorithm for 972 hours starting at 9 A.M. on Monday. When will the machine stop running the algorithm.
A) 9 A.M. on Saturday
B) 9 P.M. on Saturday
C) 9 A.M. on Sunday
D) 9 P.M. on Sunday
Using proportions, it is found that the correct option for when the machine will stop running the algorithm is:
B) 9 P.M. on Saturday.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
The algorithm runs for 972 hours. Each day has 24 hours, hence we apply the proportion to find the number of days as follows:
972/24 = 40.5 days.
The remainder of the division of 40.5 by 7, as a week has 7 days, is of 5.5, which means that the code will finish running 5.5 days after the 9 A. M. Monday, that is at 9 P. M. on a Saturday, which means that option B is correct.
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Find the volume of the figure
h=9.5', r=1.8'
Answer:
Volume=96.7
Step-by-step explanation:
V=πr^2h=
V=π·1.8^2·9.5=
96.69822
pLEASE answer as fast as possible REALLY URGENT
Using proportions, it is found that you would expected the white counter to be chosen 128 times.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
From the table, the proportion of the white counter is given as follows:
p = 32/(32 + 18) = 32/50 = 0.64.
Hence, out of 200 trials, the number of trials in which the white counter is expected to be chosen is given by:
0.64 x 200 = 128 times.
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7
O x-3
O x-1
O x + 1
O x + 3
3
2-
What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?
3
N
3
I NEED HELP !!!!!
Answer:
x-1 gave ggs is it correct
please help with question
Applying precedence of operations, the result of the expression is of 161.
What is the precedence of operations?Power operations are done before multiplication/division, which are also done before addition/subtraction.
Operations inside brackets or parenthesis also take precedence.
In this problem, the operation is:
[3 x 2^5 + 13 x (-2)] + 7[8 - (4 - 9)]
First the power:
[3 x 32 + 13 x (-2)] + 7[8 - (4 - 9)]
Now the multiplications on the first bracket, and the subtraction on the second:
[96 - 26] + 7[8 - (-5)]
Then, applying the parenthesis to the negative number, we have that:
[96 - 26] + 7[8 - (-5)] = 70 + 7 x 13 = 161.
More can be learned about precedence of operations at https://brainly.com/question/550188
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[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{3 \times 2^5 + 13(-2)] + 7[8 - (4 - 9)]}[/tex]
[tex]\mathsf{= 3\times32 + 13\times -2 + 7[8 - (4 - 9)] }[/tex]
[tex]\mathsf{= 96 + 13\times -2 + 7(8 - (4 - 9))}[/tex]
[tex]\mathsf{= 96 - 26 + 7(8 - (4 - 9))}[/tex]
[tex]\mathsf{= 70 + 7(8 - (4 - 9))}[/tex]
[tex]\mathsf{= 70 + 7(8 - (-5))}[/tex]
[tex]\mathsf{= 70 + 7\times13}[/tex]
[tex]\mathsf{= 70 + 91}[/tex]
[tex]\mathsf{= 161}[/tex]
[tex]\huge\text{Therefore, your answer should be: }[/tex]
[tex]\huge\boxed{\frak{161}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]