y = 3x + 15
3x + 3y = 9

Answers

Answer 1

Answer:

[tex]\Large\boxed{x=-3}[/tex][tex]\Large\boxed{y=6}[/tex]

Step-by-step explanation:

Given the system of equations

[tex]1)~y=3x+15[/tex]

[tex]2)~3x+3y=9[/tex]

Divide 3 on both sides of the 2) equation

[tex]3x+3y=9[/tex]

[tex]3x\div3+3y\div3=9\div3[/tex]

[tex]x+y=3[/tex]

Current system

[tex]1)~y=3x+15[/tex]

[tex]2)~x+y=3[/tex]

Substitute 1) equation into the 2) equation

[tex]x+(3x+15)=3[/tex]

Combine like terms

[tex]x+3x+15=3[/tex]

[tex]4x+15=3[/tex]

Subtract 15 on both sides

[tex]4x+15-15=3-15[/tex]

[tex]4x=-12[/tex]

Divide 4 on both sides

[tex]4x\div4=-12\div4[/tex]

[tex]\Large\boxed{x=-3}[/tex]

Substitute the x value into one of the equations to find the y value

[tex]y=3x+15[/tex]

[tex]y=3(-3)+15[/tex]

[tex]y=-9+15[/tex]

[tex]\Large\boxed{y=6}[/tex]

Hope this helps!! :)

Please let me know if you have any questions


Related Questions

Express 60 as a product of its prime factors

Answers

Answer:

The actual prime factors of 60 are 2, 3, and 5.

Step-by-step explanation:

Greetings !

Use a factor tree to express 60 as a product of prime factors. So the prime factorization of 60 is 2 × 2 × 3 × 5, which can be written as 2² × 3 × 5.

A friend of mine believes that the average GPA at KSU is equal to 3.0. In order to test whether he/she is right, I collect some information from the data. Specifically, I use 100 KSU students to form a sample and find that their sample average GPA is equal to 3.3. In addition, suppose that I also know the population standard deviation of GPA at KSU is 1.5. I decide to use 0.05 as the level of significance for my hypothesis testing. Could you help me with Q1-Q10 below? Q1: What should be my null hypothesis? What should be my alternative hypothesis? Q2: Is this a lower-tailed, upper-tailed or two-tailed case? Q3: Show me how to calculate my test statistic.
Q4: If I use the critical value approach, explain how to derive my critical value(s). Q5: If I use the p-value approach, explain how to derive my p-value. Q6: If I use the confidence interval approach, show me how to derive the confidence interval. Q7: How to make my decision, if I use the critical value approach? Q8: How to make my decision, if I use the p-value approach? Q9: How to make my decision, if I use the confidence interval approach? Q10: Are the decisions in Q7, Q8, and Q9 the same?

Answers

The solution of the questions is given as

a)

The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)

b)

This is a case with two separate arguments. (This is a two-tailed case)

c)

Test Statistic is given by:

z= 2.00

d)

Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.

e)

, p-value = 0.0455

f)

CI= (3.006, 3.594)

g)

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

h)

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

i) Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.

j)

The choices you choose in Questions 7, 8, and 9 are identical.

What is the null hypothesis?

a)

The null hypothesis states that mu equals 3.0. ( the average GPA at KSU is equal to 3.0) (Claim)

The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)

b)

This is a case with two separate arguments.

c)

Test Statistic is given by:

[tex]z=\frac{\barx-u^0}{σ/Vn}\\\\z=33 - 3.0/1.5/V100[/tex]

z= 2.00

d)

[tex]\alpha = 0.05[/tex]

Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.

e)

Z Score = 2.00

reading from table, p-value = 0.0455

f)

Confidence Interval:

[tex]CI= \barx \pm \frac{ZX\sigma }{\sqrt((n)}[/tex]

[tex]CI =3.3 \pm 1.96 x 1.5 / \sqrt{100}[/tex]

CI= (3.006, 3.594)

g)

The disparity is noteworthy given that the computed value of Z = 2.00 is higher than the crucial value of z = 1.96. Cast doubt on the null hypothesis.

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

h)

The difference may be considered statistically significant since the p-value of 0.0455 is lower than the alpha threshold of 0.05. Cast doubt on the null hypothesis.

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

i)

The difference is statistically significant since the value of 3.0 is not included in the confidence range (3.006 - 3.594). Cast doubt on the null hypothesis.

Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.

j)

The choices you choose in Questions 7, 8, and 9 are identical.

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Hey so I’m stuck on this. What is the solution to the equation 2= -8 -x?

Answers

Answer:

X = -10

Step-by-step explanation:

2 = -8 -X

2+X = -8

X = -10

Answer:

x = - 10

Step-by-step explanation:

Comment

The trick to any equation like this one is to get the numbers on one side and the term with an unknown on the other side. That way, your last step is to divide by the number in front of the letter into a number on the other side.

Solution

2 = - 8 - x                                 Add 8 to both sides

2 + 8 = -8 + 8 - x                      Combine

10 = - x                                     The number in front of x is - 1. Divide.

10/-1 = -x/-1                        

-10 =x

The letter usually has to be expressed as a number greater than 0. In other words x is positive for this question

Haley and tyler are on the cross country team. tyler can run 1 mile (ata constant speed) in 8 minutes and 20 seconds. haley's distances and times for a training run are given by the equation y=8x where x represent distanse and times in miles and y represents time in minutes. who ran farther in 10 minutes how much farther

Answers

Haler ran farther than Tyler in 10 minutes. She covered an extra 0.05 miles compared to Tyler.

What is an equation?

An equation is an expression that shows the relationship between two numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.

Tyler can run 1 mile in 8 minutes and 20 seconds.

Time taken = 8 mins + 20 sec (0.33 min) = 8.33 minutes

Speed = distance / time = 1 mile / 8.33 = 0.12 mile per min

In 10 minutes, distance = 0.12 mile per min * 10 min = 1.2 mile

Haler is given by:

y = 8x; where y is time and x is distance.

In 10 minutes, distance = y/8 = 10/8 = 1.25 miles

Haler ran farther than Tyler in 10 minutes. She covered an extra 0.05 miles compared to Tyler.

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A 164 ft^2
B 1233 ft^2
C 1395 ft^2
D 1557 ft^2

Answers

B I can explain if you want just ask

Answer:

B 1233 ft^2

Step-by-step explanation:

I hope this is right

Nuber 17 pls (question on quadratics)​

Answers

Considering the equation of the parabola, the coefficients are given as follows: p = 5, q = -20, r = 19.

The graph is the one given at the side of the question.

What is the equation of a parabola given it’s vertex?

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

In this problem, the turning point is (2,-1), hence h = 2, k = -1, and the equation has the following format:

y = a(x - 2)² - 1

The curve passes through (3,4), that is, when x = 3, y = 4, and we use it to find a.

y = a(x - 2)² - 1

4 = a(3 - 2)² - 1

a = 5.

Hence the equation is:

y = 5(x - 2)² - 1

Placing it into standard form, we have that:

y = 5(x² - 4x + 4) - 1

y = 5x² - 20x + 19

Hence the coefficients are:

p = 5, q = -20, r = 19.

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(50 POINTS PLEASE HELP!!!)

!!!THE QUESTION THAT I NEED TO BE ANSWERED IS THE PICTURE ATTACHED!!! BELOW IS JUST THE REQUIREMENTS AND EXAMPLE!!!

He has hired you as their new production manager. Your job is to look at four different figures and determine which would best suit the needs of the company for packaging the candy. You will choose one of the four options shown below. The candy is animal gummies. The package must hold between 80 and 100 cubic inches (roughly 5-7 cups of space). The cost of the plastic for the packaging is $0.004 per square inch. When finding cost you would multiply the Total Surface Area by $0.004.
For example:
Total Surface Area = 86 sq. in
Cost per sq in = $0.004
86 * .004 = .344 when rounded to nearest penny = $0.34

Your project should include the volume, total surface area, and materials cost for each figure given below, including the formulas you used and each step of your work. Be sure to find all measures for each figure, even if the figure does not meet the restraints that the company has given. Make sure to use the formulas given in your lessons, round your volume and area to the nearest hundredth, and round your cost to the nearest penny.

Answers

The figure in the question is a box with dimensions of 6 in. by 2 in. by 9 in., which gives;

Surface area of the packaging = 168 in.²

Package volume = 108 in.³

Cost of packaging = $0.672

Which method can be used to provide the packaging estimates for the company?

The dimensions of the box in the given figure are;

Length, L = 9 in.

Width, W = 2 in.

Height, H = 6 in.

The surface area, A, of a box is found using the following formula;

A = 2•L•W + 2•L•H + 2•H•W

Therefore;

A = 2×9×2 + 2×9×6 + 2×2×6 = 168

The surface area of the figure, A = 168 in.²

The volume of a box, V, is calculated as follows;

V = L•W•H

For the given figure, therefore;

V = 9 × 2 × 6 = 108

The volume of the given figure, V = 108 in.³

Cost of packaging per square inch, c = $0.004

Cost to package the figure, C, is therefore;

C = c × A

Which gives;

C = $0.004/in.² × 168 in.² = $0.672

Packaging cost, C = $0.672

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The figure shows a square, a regular pentagon and a regular hexagon put together. What is the measure of ∠BAC

Answers

Answer:

42

Step-by-step explanation:

One angle of a regular pentagon = 108°

One angle of a regular hexagon = 120°.

One angle of a square = 90°

∴ ∠BAC = 360 – (108 + 20 + 90) 360 – 318 = 42°

Find the results of the given vector subtractions for u = <-8, 4> and v = <2, 7>.

Answers

The resultant of subtractions of u = <-8, 4> and v = <2, 7> are

-u-v = <6, -11>,

u-v = <-10, -3>,

and v-u= <10,3>.

What is a vector in simple definition?

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. The term also denotes the mathematical or geometrical representation of such a quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

The resultant of subtractions of u = <-8, 4> and v = <2, 7> are

-u-v = <6, -11>,

u-v = <-10, -3>,

and v-u= <10,3>.

Given that,

The results of the given vector subtractions for u = <-8, 4> and v = <2, 7>.

We have to determine,

The value of -u-v, u-v, and v-u.

According to the question,

The results of the given vector subtractions for u = <-8, 4> and v = <2, 7>.

The value of -u-v is,

-u -v = - < -8 ,4 > - <2,7>

-u -v = <8, -4> - < 2, 7 >

-u - v = < 8 - 2 , -4 - 7 >

-u -v =  < 6 , - 11 >

The value of u-v is,

u -v = < -8 ,4 > - < 2,7 >

u - v = < - 8  - 2, 4 - 7 >

u - v = < 10 ,3>

The value of v - u is,

v - u = < 2 , 7>  - < - 8,4 >

v - u = <  2 + 8 ,  7 - 4 >

v - 4 = <  10 , 3 >

Hence, The resultant of subtractions of u = <-8, 4> and v = <2, 7> are

-u-v = <6, -11>,

u-v = <-10, -3>,

and v-u= <10,3>.

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This pattern follows the rule add 14. What other features do you observe?

13, 27, 41, 55
please help meeeeee

Answers

The above pattern follows an arithmetic sequence with a common difference of 14 and first term of 13

How to solve a pattern?

The pattern can be represented as follows:

13, 27, 41, 55

The first term of the sequence is 13 and the common difference is 14.

The above pattern is an arithmetic sequence.

Therefore, the following can be used to find the nth term.

nth term = a + (n - 1)d

where

n = number of termd = common differencea = first term

Therefore,

a = 13

d = 27 - 13 = 14

Let's find the next term

5th term = 13 + (5 - 1)14

5th term = 13 +(4)14

5th term = 13 + 56

5th term = 69

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determine what type of model best fits the given situation: An Internet phone company presently provides service to 5,000 customers at a monthly rate of $20 per month. After a market survey, it was determined that for each $1 decrease in the monthly rate an increase of 500 new customers would result.
A. none of these
B. quadratic
C. linear
D. exponential

Answers

The option c is correct. The linear representation model is best for this situation out of the exponential, quadratic model.

According to the statement

we have given that:

Monthly Rate = $20, Number of customers = 5000

If there is a decrease of $1 in the monthly rate, the number of customers increase by 500.

And we have to find that The type of model that best fits the given situation.

So, according to the linear representation model

Monthly Rate = $20, Number of customers = 5000

Let us decrease the monthly rate by $1.

Monthly Rate = $20 - $1  = $19, Number of customers = 5000 + 500 = 5500

Let us decrease the monthly rate by $1 more.

Monthly Rate = $19 - $1  = $18, Number of customers = 5500 + 500 = 6000

Here, we can see that there is a linear change in the number of customers whenever there is decrease in the monthly rate.

We have 2 pair of values here,

x = 20, y = 5000

x = 19, y = 5500

Let us write the equation in slope intercept form:

y = mx + c

And Slope of a function is

m = y₂ - y₁ / x₂ - x₁

Then

m = 5500 - 5000 / 19 - 20

m = -500

So, the equation become

y = -500x +c

And find the value of by putting the values.

So, c = 15000

And the equation become

y = -500x + 15000.

According to this linear model is perfect for this situation.

So, The linear representation model is best for this situation.

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In regression, the difference between the confidence interval and prediction interval formulas is ________

Answers

In regression, the difference between the confidence interval and the prediction interval formula is "The addition of 1 to the quantity under the radical sign i.e., standard error".

What are the formulas for the confidence interval and prediction interval?

The formula for the confidence interval is

[tex]y_h[/tex] ± [tex]t_{(1-\alpha /2,n-2)[/tex] × √(MSE([tex]\frac{1}{n}[/tex] + ([tex]x_h[/tex] - μ)²/∑([tex]x_i[/tex] - μ)²))

The formula for prediction interval is

Prediction interval = Sample estimate ± (t multiplier × standard error)

[tex]y_{new}[/tex] = [tex]y_h[/tex] ± [tex]t_{(1-\alpha /2,n-2)[/tex] × √(MSE(1 + [tex]\frac{1}{n}[/tex] + ([tex]x_h[/tex] - μ)²/∑([tex]x_i[/tex] - μ)²))

Where μ = x bar.

What is the difference between the confidence interval and the prediction interval?

From the above, the prediction interval has one additional MSE term in the standard error calculation. But in the confidence interval, only one term is used.

So, the difference between them occurs in the standard error value.

The formula shows it by adding 1 to the quantity under the radical sign.

Thus, the difference is in the standard error.

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Find the area of quadrilateral abcd. [hint: the diagonal divides the quadrilateral into two triangles.]

Answers

The area of quadrilateral ABCD exists equivalent to the area of triangle ABD plus the area of triangle ADC

Heron's Formula exists a technique for estimating the area of a triangle when you know the lengths of all three sides.

Therefore, the total area of  quadrilateral abcd exists 28.53 [tex]$$units^2[/tex].

How to find the area of quadrilateral abcd?

Let a, b, and c be the lengths of the sides of a triangle.

The area is given by:

[tex]$$A = \sqrt{p(p-a)(p-b)(p-c)}[/tex]

where p exists half the perimeter

[tex]$p = \frac{a+b+c}{2}[/tex]

To estimate the area of triangle ABD

we have

a = AB = 2.89 units

b = BD = 8.59 units

c = DA = 8.6 units

To estimate the perimeter

[tex]$p = \frac{2.89+8.59+8.6}{2}[/tex]

= 10.4 units

To estimate the area

[tex]$A = \sqrt{10.04(10.04-2.89)(10.04-8.59)(10.04-8.6)}[/tex]

[tex]$A = \sqrt{10.04(7.15)(1.45)(1.44)}[/tex]

[tex]$A = \sqrt{149.89}[/tex]

A = 12.24 [tex]$$units^2[/tex]

To estimate the area of the triangle ADC

we have

a = AC = 4.3 units

b = AD = 8.6 units

c = DC = 7.58 units

To estimate the half perimeter p

[tex]$p = \frac{4.3+8.6+7.58}{2}[/tex]

= 10.24 units

To estimate the area

[tex]$A = \sqrt{10.24(10.24-4.3)(10.24-8.6)(10.24-7.58)}[/tex]

[tex]$A = \sqrt{10.24(5.94)(1.64)(2.66)}[/tex]

[tex]$A = \sqrt{265.35}[/tex]

A = 16.29 [tex]$$units^2[/tex]

To estimate the total area

A = 12.24+16.29 = 28.53 [tex]$$units^2[/tex].

Therefore, the total area of  quadrilateral abcd exists 28.53 [tex]$$units^2[/tex].

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Into how many equal parts can the same cake be cut if the cuts can only be made along the gridlines? cake can be cut into equal parts.

Answers

Into how many equal parts can the same cake be cut if the cuts can only be made along the gridlines, cake can be cut into 20 equal parts.

This is further explained below.

What are gridlines?

Generally, In spreadsheet software, gridlines are the light gray lines that divide the cells, rows, and columns. Gridlines are often used to maintain track of data. Gridlines are widely used in popular spreadsheet programs like Spreadsheet.

In conclusion, If the cuts can only be done along the gridlines, the cake may be divided into 20 equal pieces when cutting along the lines.

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If a sum of money amounts to Rs. 2175 in 3 years and to Rs. 2625 in 5 years.Find the rate of interestsl

Answers

The rate of interest applied on the amount is 15%.

According to the statement

we have given that the sum of money amounts to Rs. 2175 in 3 years and to Rs. 2625 in 5 years.

And we have to find the rate of interest on this money.

So, For this purpose,

The given equation is:

Money in 3 years = 2175

Money in 5 years = 2625

Amount increased in 2 years = 2625-2175

Amount increased in 2 years = 450

And amount increased per year = 450/2

Amount increased per year = 225.

SI in 3 years=450/2 *3=Rs. 675

Principal amount= 2175-675=1500

so again,

R=(I*100)/(P*T)

R=15%

So, The rate of interest applied on the amount is 15%.

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1)Find the L.C.Mof the following set of numbers by prime factorization method:
a)6 and 9
b)16 and 24
c)24,48 and 64

2)Find L.C.M of the following set of numbers by division method:
a)6 and 15
b)25,30 and 75

Note: Answer must have proper explanation ​

Answers

Answer:

a) 18

b) 48

c) 192

a) 30

b) 150

Step-by-step explanation:

Answer:

1

a ) 18

b ) 48

c ) 144

2

a ) 30

b ) 150..

[tex]...[/tex]


The sum of three numbers is 134. The second number is 8 less than the first. The third number is 4 times the second. What are the numbers?

Answers

Answer:

29, 21, 84

Step-by-step explanation:

Let the first number be x.

The second number is x - 8.

The third number is 4(x - 8).

Their sum is 134.

x + (x - 8) + 4(x - 8) = 134

x + 5(x - 8) = 134

x + 5x - 40 = 134

6x = 174

x = 29

x - 8 = 29 - 8 = 21

4(x - 8) = 4(29 - 8) = 4(21) = 84

question down below about linear equations and grapghing.

Answers

The system of equations is -x + y = 4 and -2x + y = 0

How to create the system of linear equations?

To do this, we make use of the following ordered pairs

(4, 8)

The above point represents April 2008.

Let the system of equations be

mx + ny = 4

2mx + ny = 0

Substitute (4, 8) for x and y in the above equations.

4m + 8n = 4

8m + 8n = 0

Subtract both equations

4m - 8m = 4

This gives

-4m = 4

Divide by 4

m = -1

Substitute m = -1 in 8m + 8n = 0

-8 + 8n = 0

This gives

8n = 8

Divide by 8

n = 1

So, the system of equations is -x + y = 4 and -2x + y = 0

The graph of the system of equations

The system of equations is -x + y = 4 and -2x + y = 0

See attachment for the graph of the system of equation

Prove that the solution is (4, 8)

The above is represented in the (a) part of this solution

Verify that the solution is (4, 8)

We have:

-x + y = 4 and -2x + y = 0

Substitute (4, 8) for x and y in the above equations.

-4 + 8 = 4 --- true

-2*4 + 8 = 0 --- true

Both equations are true

Hence, the system of equations have been verified

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Simplify[tex](\frac{16}{81}x^{16}\right))^{\frac{1}{2}}[/tex]

Answers

The answer is = 4x^8/9

Answer:

[tex]\sf \dfrac{4}{9}x^8[/tex]

Step-by-step explanation:

Law of exponents:

       [tex]\sf (a*b)^m = a^m *b^m\\\\(a^m)^n =a^{m*n}[/tex]

  16 = 4 *4 = 4²

 81  = 9 *9 = 9²

[tex]\sf\left (\dfrac{16}{81}x^{16}\right)^{\frac{1}{2}}= \left(\dfrac{4^2}{9^2}x^{16}\right)^{\frac{1}{2}}[/tex]

                [tex]\sf =\dfrac{4^{2*\frac{1}{2}}}{9^{2*\frac{1}{2}}}*x^{16*\frac{1}{2}}\\\\=\dfrac{4}{9}x^8[/tex]

Find the most general antiderivative of the function. (check your answer by differentiation. use c for the constant of the antiderivative. ) f(x) = x(18x 4)

Answers

Answer:

Below in bold.

Step-by-step explanation:

f(x) = x(18x + 4)

f(x) = 18x^2 + 4x

Antiderivative = 18 * (x^2+1)/(2 + 1) -+4x(1+1) / (1+1) + C

                        =  18x^3 / 3 + 4x^2 / 2 + C

                         = 6x^3 + 2x^2 + C.

Checking by differentiating:

f'(x) = 6*3 x^(3-1) + 2*2x^(2-1)

      =  18x^2 + 4x

      =  x(18 -+4)

               

Hazing has been reported all across america. What percentage of students say they have witnessed hazing and did not report it?.

Answers

percentage of students say they have witnessed hazing and did not report it are  = 95%

What is Hazing?

No matter how voluntarily a person is to take part, hazing, initiation or deposition are all actions that are demanded of someone when they join or participate in a group and which humiliate, degrade, abuse, or imperil them.

involves humiliating a person or group. involves making fun of someone or something. involves or includes the deliberate destruction of or removal of private or public property for the purpose of affiliation with, initiation into, or as a requirement for continuing membership in an organization.

What is an example of hazing?

Paddling, beating, or other types of attack. Branding. consumption of disgusting substances or mixtures under duress or force.

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Find the surface area of the composite figure.
4 cm
13 cm
3 cm
4 cm
SA =
12 cm
[?] cm²
5 cm
3 cm

Answers

With the help of the area formulae of rectangles and triangles and the concept of surface area, the surface area of the composite figure is equal to 276 square centimeters.

What is the surface area of a truncated prism?

The surface area of the truncated prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and right triangles. Then, we proceed to determine the surface area:

A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)

A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²

A = 276 cm²

With the help of the area formulae of rectangles and triangles and the concept of surface area, the surface area of the composite figure is equal to 276 square centimeters.

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What are the restricted values for x2−3x−2−4y⋅2x−2−xy2+2y2?

Answers

The restricted values in (x^2 - 3x - 2)/-4y * (2x - 2)/(-xy^2 + 2y^2) are x ≠2 and y ≠ 0

How to determine the restricted values for the function?

The complete question is added as an attachment

The equation is given as:

(x^2 - 3x - 2)/-4y * (2x - 2)/(-xy^2 + 2y^2)

Set the products of the denominators to 0

-4y * (-xy^2 + 2y^2) = 0

Split the equation

-4y = 0 or (-xy^2 + 2y^2) = 0

Remove the bracket

-4y = 0 or -xy^2 + 2y^2 = 0

Divide both sides by -4 in -4y = 0

y = 0

Factor out y^2 in -xy^2 + 2y^2 = 0

y^2(-x + 2) = 0

This means that y^2 = 0 or -x + 2= 0

This gives y = 0 or -x + 2 = 0

Solve for x in -x + 2 = 0

x = 2

Hence, the restricted values in (x^2 - 3x - 2)/-4y * (2x - 2)/(-xy^2 + 2y^2) are x ≠2 and y ≠ 0

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Algebra 3, in the excercise size the graphs to determine the functions domain and range, x and y intercepts if any, and the functions values indicated below the graphs

Answers

Answer:

Read Explanation

Step-by-step explanation:

The domain is a list of all possible x-values, this graph starts at 0 and proceeds to positive infinity, making the domain:

[0,∞)

The range is a list of all possible y-values, this graph starts at -1 and proceeds to positive infinity, making the range:

[-1,∞)

x-intercepts Are where the line crosses the x-axis, in this graph the line only crosses the x-axis at x of 2. Making its only x-intercept 2.

y-intercepts Are where the line crosses the y-axis, in this graph the line only crosses the y-axis at y of -1. Therefore its y-intercept is -1.

In function notation when a question asks for f(x) its asking for the y values at the given x-values. At x of 3 the y value equals 1.

Find the output, y, when the input, x, is -5.

Answers

The output, y, when the input, x, is -5 is -2

How to determine the value of the output y?

The input is given as:

-5

This means that

x = -5

This is so because x represents the input

From the graph, we have the following highlight

The line of the graph passes through the point x = -5

On the graph;

When x = -5, the value of y is -2

This means that the output, y, when the input, x, is -5 is -2

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A football is kicked toward the goal. the height of the ball is modeled by the function h(t) = −16t2 64t, where t equals the time in seconds and h(t) represents the height of the ball at time t seconds. what is the axis of symmetry, and how does it relate to the time the ball is in the air? t = 2; it takes the ball 2 seconds to reach the maximum height and 2 more seconds to fall back to the ground. t = 2; it takes the ball 2 seconds to reach the maximum height and 4 more seconds to fall back to the ground. t = 4; it takes the ball 4 seconds to reach the maximum height and 4 more seconds to fall back to the ground. t = 4; it takes the ball 4 seconds to reach the maximum height and 8 more seconds to fall back to the ground.

Answers

The function [tex]H(t) = -16t^2 + 64t[/tex] exists in a parabola.

The axis of symmetry of a parabola exists at the midpoint between the two real roots.

The roots exist the solutions of H(t) = 0

To estimate the roots equation exists [tex]-16t^2 + 64t = 0[/tex]

Factor t(-16t + 64) = 0

t = 0 and -16t + 64 =0

-16t + 64 = 0

t = 64 / 16 = 4

t = 4

Then the two roots are t = 0 and t = 4, and the axis of symmetry exists

t = (0+4)/2 = 4/2 = 2

How to estimate the axis of symmetry?

The axis of symmetry exists at t = 2.

It represents the time at which the ball is at the higher point, the maximum height.

You can find the maximum height replacing t = 2 in the function H(t)

[tex]H(t) = -16(2^2) + 64(2)[/tex]

= 64 feet.

And you can also deduce that the second part of the flight will take 2 seconds, for a total flight time of 4 seconds.

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Answer:

answer is a

Step-by-step explanation:

it takes 2 seconds for the ball to reach maximum height and 2 seconds to fall on the ground.


t = 2; it takes the ball 2 seconds to reach the maximum height and 2 more seconds to fall back to the ground

Took the FLVS test!

Can someone help pls

Answers

Answer:

x = 0, x = 5

Step-by-step explanation:

x² - 5x = 0 ← factor out x from each term

x(x - 5) = 0

equate each factor to zero and solve for x

x = 0

x - 5 = 0 ⇒ x = 5

B
23. Find the EXACT circumference of the circle
if AB = 2in and BC = 11in.
A
C
a. √117 in
b.
5√5π in
c.
35.1 in
d. 5√5 in

Answers

Answer:

C. 35.1

Step-by-step explanation:

First get the length of AC by using the Pythagorean Theorem, that ends up being about 11.18. Then you need to get the radius of the circle so you divide 11.18 by 2 and get 5.59. Then plug 5.59 for r into 2(pi)(r). 2(pi)(5.59) = 5.123

Answer:

Answer B is correct

Step-by-step explanation:

First, let us find the diameter (AC) of the circle using the Phythogerem theorem.

AC² = AB² + BC²

AC² = 2² + 11²

AC² = 4 + 121

AC² = 125

AC = √ 125

AC = 5√5

And now let us find the circumference of the circle.

C = π × d

C = π × 5√5

C = 5√5π in

Find the equation of the plane through the points p(0, 1, 1), q(1, 0, 1), and r(1, 1, 0).

Answers

The equation of the plane through the points p(0, 1, 1), q(1, 0, 1), and

r(1, 1, 0) is x + y + z = 2  .

According to the question

Let the points

p(0, 1, 1) = (x1,y1,z1)

q(1, 0, 1)= (x2,y2,z2)

r(1, 1, 0)= (x3,y3,z3)

now,

The equation of the plane through the points

i.e

The formula of equation of a plane passing through three non collinear points

[tex]\left[\begin{array}{ccc}x-x1&y-y1&z-z1\\x2-x1&y2-y1&z2-z1\\x3-x1&y3-y1&z3-z1\end{array}\right] = 0[/tex]

by substituting the values in the formula of equation of a plane

[tex]\left[\begin{array}{ccc}x-0&y-1&z-1\\1-0&0-1&1-1\\1-0&1-1&0-1\end{array}\right] = 0[/tex]

[tex]\left[\begin{array}{ccc}x&y-1&z-1\\1&-1&0\\1&0&-1\end{array}\right] = 0[/tex]  

x(1) - (y-1)(-1) + (z-1)(1) = 0

x + y - 1 + z - 1 = 0

x + y + z = 2

Hence, the equation of the plane through the points p(0, 1, 1), q(1, 0, 1), and r(1, 1, 0) is x + y + z = 2  .

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construct a quadrilateral
AB=6cm , BC = 5cm, AD = 4CM CD =7cm and BD = 6cm​

Answers

If a quadrilateral exists as a parallelogram, then opposite sides exist congruent and parallel.

What is quadrilateral?

If a quadrilateral exists as a parallelogram, then opposite sides exist congruent and parallel.

Given: AB = 6cm , BC = 5cm, AD = 4cm, CD = 7cm and BD = 6cm​

Draw a line AB with 6cm with A as the center draw an arc of radius 4 cm. And draw another arc of 6cm to cut the previous arc at D with B as the center draw an arc of radius 5cm. And with D draw another arc of 7cm to cut the previous arc at C. Join the lines of the quadrilateral.

Now ABCD exists as a required quadrilateral.

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