Will mark brainliest

Will Mark Brainliest

Answers

Answer 1

[tex]x^3[/tex] is strictly increasing on [0, 5], so

[tex]\max\{x^3 \mid 0\le x\le5\} = 5^3 = 125[/tex]

and

[tex]\min\{x^3 \mid 0 \le x\le5\} = 0^3 = 0[/tex]

so the integral is bounded between

[tex]\displaystyle \boxed{0} \le \int_0^5x^3\,dx \le \boxed{125}[/tex]


Related Questions

PLEASE HELP ME THANK U

Answers

Answer:

2700 degrees

Step-by-step explanation:

The number of sides minus 2 times.

n = number of sides

(n-2)= 180

(17-2)(180)

(15)(180) = 2700

how much would you need to deposit in an account now in order to have 6000 in the account in 8 years. assume the account earns 6% interest compounded monthly

Answers

Answer:

$3,717.14

Step-by-step explanation:

Compound interest is the interest on the principal funding as well as the interest itself.

Compound Interest Formula

Compound interest can be solved by plugging known values into a formula.

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

In this formula, the variables stand for different values.

A = total amountP = principal amountr = rate as a decimaln = times compounded per time periodt = time

So, for this question, we can plug in the values we are given and solve for P.

Identifying Known Values

First, let's find the exact numbers we are going to plug in.

6000 is the final amount we want, so A = 6000.6%, the rate, is 0.06 as a decimal, so r = 0.06.Since interest is compounded each month per year, n = 12.The total time is 8 years, so t = 8.

Solving For P

Now we can plug all of these values in.

[tex]6000=P(1+\frac{0.06}{12})^{12*8}[/tex]

First, simplify the values within the parentheses and in the exponent through arithmetic.

[tex]6000 = P(1.005)^{96}[/tex]

Next, divide both sides by [tex]1.005^{96}[/tex]

3717.14 ≈ P

*Note that the answer has been rounded to the nearest hundredth.

This means that you would need to deposit $3,717.14 into the account to have $6,000 in 8 years.

|m² + n²|
When m = -5and n
=
3, the value of the expression is

Answers

Answer:

  34

Step-by-step explanation:

You want the value of |m² +n²| for m = -5 and n = 3.

Evaluation

Put the values where the variables are in the expression and do the arithmetic.

  |m² +n²| = |(-5)² +3²| = |25 +9| = |34| = 34

The value of the expression is 34.

__

Additional comment

Here, the absolute value bars don't do anything, because the value between them is positive. If it were negative, they would remove the minus sign.

<95141404393>

which statements are true

Answers

The true statements are;

-Both graphs are logarithmic functions

-Both graphs have been shifted and flipped (B and D).

What is a graph?

A graph is a plot of information on the cartesian coordinates. The function is plotted on an x - y cartesian plane. Given the nature of function, we can understand the shape of the graph as shown.

In this case, the graph shows a flipped logarithmic function. As such, the following are true about the function;

-Both graphs are logarithmic functions

-Both graphs have been shifted and flipped

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Which expression correctly represents "six more than the quotient of three and a number, decreased by eight"?
6+3/n-8
6+n/3-8
6+3/n+8
6+n/3+8

Answers

The option A is correct because the value of the statement is 6+3/n-8.

According to the statement

we have given that the statement and we have to write the statement in the numerical form.

So, For this purpose

we know that the given statement is

"Six more than the quotient of three and a number, decreased by eight".

In this statement "Six more than" indicates the sum between the quotient and 6.

And "The quotient of three and a number" indicates a fraction where the numerator is 3 and the denominator is , a number.

"Decreased by eight" indicates a subtraction between the quotient an 8 units".

If we unit all parts of the statements, we would have

6+3/n-8

So, From the given statement, The option A is correct because the value of the statement is 6+3/n-8.

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Below, the two-way table is given for a class
of students.
Sophomore
Freshmen
4
3
6
4
Juniors Seniors Total
2
6
Male
Female
Total
If a male student is selected at random, what is the
probability the student is a freshman.
2
3
P (Freshman | Male) = [?]%
Round to the nearest whole percent.
Enter

Answers

Answer:

2/7 = 29% (nearest percent)

Step-by-step explanation:

Calculate the totals and add them to the table:

[tex]\begin{array}{| c | c | c | c | c | c |}\cline{1-6} & \sf Freshman & \sf Sophmore & \sf Juniors & \sf Seniors & \sf Total \\\cline{1-6} \sf Male & 4 & 6 & 2 & 2 & 14\\\cline{1-6} \sf Female & 3 & 4 & 6 & 3 & 16\\\cline{1-6} \sf Total & 7 & 10 & 8 & 5 & 30\\\cline{1-6}\end{array}[/tex]

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Let P(A) = probability that the student is a freshman

Let P(B) = probability that the student is male

Use the given table to calculate the probability that the student is male:

[tex]\sf \implies P(B)=\dfrac{14}{30}[/tex]

And the probability that the student is a freshman and male:

[tex]\implies \sf P(A \cap B)=\dfrac{4}{30}[/tex]

To find the probability that the student owns a credit card given that the they are a freshman, use the conditional probability formula:

Conditional Probability Formula

The probability of A given B is:

[tex]\sf P(A|B)=\dfrac{P(A \cap B)}{P(B)}[/tex]

Substitute the found values into the formula:

[tex]\implies \sf P(Freshman|Male)=\dfrac{\dfrac{4}{30}}{\dfrac{14}{30}}=\dfrac{4}{14}=\dfrac{2}{7}=0.28571...=29\%[/tex]

Therefore, the probability that the student is a freshman given they are male is 29% (nearest percent).

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DJ Larissa is making a playlist for a friend; she is trying to decide what 10 songs to play and in what order they should be played .
Step 2. If she has her choices narrowed down to 7 blues, 3 hip-hop, 5 reggae, and 7 rock songs, and she wants to play no more 4 blues songs, how many different playlist or possible? Express your answer in scientific notation rounding to the hundredths place

Answers

The total number of ways are formed is 4.43 x 10^10 by rounding to the hundredths place.

According to the statement

we have given that the some numbers of the songs which are added by the larrisa in her playlist.

And we have to tell the ways which are formed with the help of the combination and permutations.

So, For this purpose we know that the

The first condition we have given that the

"play no more than 4 blues songs" - indicates playlist can contain 0, 1, 2, 3, or 4 blues songs. You need to analyze five different cases and add them up together in the end. From 7 blues songs, you can either "pick" 0, 1, 2, 3, or 4. Since order matters, it's a permutation, not a combination.

Afterwards, it gets tricky. Consider the first case, where we have 0 blues songs. This means that there are 10 spaces for the remaining (3+5+7 = 15) songs, which means that they can be arranged in (7P0 ∙ 15P10) ways.

For the next case, where we have 1 blues songs, it means that there are 9 spaces for the remaining 15 songs, which means that they can be arranged in (7P1 ∙ 15P9) ways. Continue doing this for the cases of 2, 3, and 4 blues songs and add up all the cases together.

And from this way we get the all combinations which are formed.

So, For this purpose

n = (7P0 ∙ 15P10) + (7P1 ∙ 15P9) + (7P2 ∙ 15P8) + (7P3 ∙ 15P7) + (7P4 ∙ 15P6) = 4.43459016×1010,

which rounded to the hundredths place, is 4.43 x 10^10 possible playlists.

So, The total number of ways are formed is 4.43 x 10^10 by rounding to the hundredths place.

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Answer:

Step-by-step explanation:

How many three-digit positive integers have three different digits and at least one prime digit?

Answers

The number of three-digit positive integers that have three different digits and at least one prime digit are 7960.

What are prime numbers?

The definition of a prime number is a natural number larger than 1 that is not the sum of two lesser natural numbers. A composite number is any natural number that is more than 1 but not a prime.

The only two components in prime numbers are 1 and the number itself.

Any whole number greater than one is a prime number.

It has exactly two factors—1 and the actual number.

There is just one 2-digit even prime number.

Every pair of prime numbers is always a co-prime.

The product of prime numbers can be used to represent any number.

Three-digit positive integers that have three different digits and at least one prime digit = 3!*4!*10*9 = 7960

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Find the area and the circumference of a circle with radius .
Use the value 3.14 for , and do not round your answers. Be sure to include the correct units in your answers.

Answers

The area of the circle is 78.5 square yards and the circumference of the circle is 31.4  yards

How to determine the area?

The radius of the circle is given as:

r = 5 yard

The area is calculated using

A = pi r^2

Substitute the known values in the above equation

A =3.14 * 5^2

Evaluate the exponent

A =3.14 * 25

Evaluate the product

A =78.5

Hence, the area of the circle is 78.5 square yards

How to determine the circumference?

The radius of the circle is given as:

r = 5 yard

The circumference is calculated using

C = 2pi r

Substitute the known values in the above equation

C =2 * 3.14 * 5

Evaluate the product

C = 31.4

Hence, the circumference of the circle is 31.4  yards

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Maths Questions box 51.The function f: R→ R is twice differentiable and for any x ER we have g(x) = f(4-x²), if f'(1) = -5 and f" (1) = -1 than what is g" (√3)?






Answers

By the chain rule,

[tex]g(x) = f(4 - x^2) \\\\ \implies g'(x) = -2x f'(4 - x^2) \\\\ \implies g''(x) = -2 f'(4 - x^2) + 4x^2 f''(4 - x^2)[/tex]

Observe that

[tex]4 - x^2 = 1 \implies x^2 = 3 \implies x = \pm\sqrt3[/tex]

Then

[tex]g''(\sqrt3) = -2 f'(1) + 4\left(\sqrt3\right)^2 f''(1) = -2(-5) + 4(3)(-1) = \boxed{-2}[/tex]

Find the measure of c.

Answers

Answer:

100°

Step-by-step explanation:

basically, in this situation, whatever number or angle you're given, and the number diagonally across from it are supposed to add up to 180°.

(i think its called a cyclic quadrilateral, so do with that what you will.)

What are the excluded values? –4 and –1 -1/2, 1, and 4 1 1 and 4

Answers

The excluded values are x = 4 and x - 1

How to determine the excluded values?

The complete question is added as an attachment

The function is given as:

(2x^2 - 7x - 4)/(x^2 - 5x + 4)

Set the denominator to 0

x^2 - 5x + 4 = 0

Expand

x^2 - x - 4x + 4 = 0

Factorize the equation

x(x -1) - 4(x - 1) = 0

This gives

(x - 4)(x - 1) = 0

Solve for x

x = 4 and x - 1

Hence, the excluded values are x = 4 and x - 1

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Answer: Its D 1 and 4

Step-by-step explanation:

I took the assignment

What is the General form of the zero of a first degree polynomial? Explained answered please​

Answers

Answer:

for normalian is a function of the form FX is equal to a and x n + a n - 1 x n - 1 + ax2 into X + A1 is equal to A2 is degree per normal highest power of X is

An isosceles trapezoid has a perimeter of 108 metres. Its shorter base measures 11.5 metres and its longer base measures 28.1 metres. The two remaining sides have the same length; what is that length?

Answers

The length of one of the remaining sides is 34.20 meters.

What is the length?

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Perimeter of an isosceles trapezoid =  sum of lengths of sides of a trapezoid

length of shorter base + length of longer base + (2 x legs)

108 = 11.5 + 28.1 + (2 x legs)

108 = 39.60 + (2 x legs)

108 - 39.60 =  (2 x legs)

68.40 =  (2 x legs)

leg = 68.40 / 2

= 34.20 meters

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Fraction how do you make 0.475 a simple fraction

Answers

Answer: 19/40

Step-by-step explanation:

First Write 0.475 as 0.4751Multiply both numerator and denominator by 10 for every number after the decimal point0.475 × 10001 × 1000 = 4751000. Reducing the fraction gives The answer

i believe the correct answer should be19/40

Pls help me with this calculus question

Answers

Answer:

5

Step-by-step explanation:

Gradient (slope) of the curve can be found by deriving a curve function.

In this scenario, the given function is a polynomial function which we can use Power Rules to derive it.

Power Rules

[tex]\displaystyle{y=ax^n \to y' = nax^{n-1}}[/tex]

Thus, using the power rules, we will have:

[tex]\displaystyle{y'=3x^2-4x+5}[/tex]

Note that deriving a constant will always result in 0.

Then the problem gives us that we want to find the slope or gradient at where the curve crosses y-axis.

The curve crosses y-axis at x = 0 only. Therefore, we substitute x = 0 in a derived function.

[tex]\displaystyle{y'(0) = 3(0)^2-4(0)+5}\\\\\displaystyle{y'(0) = 5}[/tex]

Therefore, the slope at the point where a curve crosses y-axis will be 5.

The half-life of iron-52 is approximately 8.3 hours.How much of a 13 gram sample of iron-52 would remain after 8 hours? Round to three decimal places.

Answers

6.665 grams of the 13 grams remain after 8 hours.

How much of a 13 gram sample of iron-52 would remain after 8 hours?

The decay equation for the 13 grams of iron-52 is:

[tex]N(t) = 13g*e^{(-ln(2)/8.3h)*t}}[/tex]

Where N is the amount of iron-52, and t is the time in years.

Where we used the fact that the half-life is exactly 8.3 hours.

Now, the amount that is left is given by N(8h), so we just need to replace the variable t by by 8 hours, so we get:

[tex]N(8h) = 13g*e^{(-ln(2)/8.3h)*8h}} = 6.665g[/tex]

So 6.665 grams of the 13 grams remain after 8 hours.

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Whole page of geometry stuff for 50 points only do 2,3 and 4 ( serious answers only or 1 star and report )

Answers

See below for the distance between the points and the lines

How to determine the distance between the lines and the points?

Question 2

The line and the points are given as:

x = y

P = (4, -2)

Rewrite the equation as:

y = x

The slope of the above equation is

m = 1

The slope of a line perpendicular to it is

m = -1

A linear equation is represented as:

y = mx + b

Substitute m = -1

y = -x + b

Substitute (4, -2) in y = -x + b

-2 = -4 + b

Solve for b

b = 2

Substitute b = 2 in y = -x + b

y = -x + 2

So, we have:

x = y and y = -x + 2

Substitute x for y

x = -x + 2

Solve for x

x = 1

Substitute x = 1 in y = x

y = 1

So, we have the following points

(1, 1) and (4, -2)

The distance between the above points is

d = √(x2 - x1)² + (y2 - y1)²

So, we have:

d = √(1 - 4)² + (1 + 2)²

Evaluate

d = 3√2

Hence, the distance between x = y and P = (4, -2) is 3√2 units

Question 3

The line and the points are given as:

y = 2x + 1

Q = (2, 10)

The slope of the above equation is

m = 2

The slope of a line perpendicular to it is

m = -1/2

A linear equation is represented as:

y = mx + b

Substitute m = -1/2

y = -1/2x + b

Substitute (2, 10) in y = -1/2x + b

10 = -1/2 * 2 + b

Solve for b

b = 11

Substitute b = 11 in y = -1/2x + b

y = -1/2x + 11

So, we have:

y = 2x + 1 and y = -1/2x + 11

Substitute 2x + 1 for y

2x + 1 = -1/2x + 11

Solve for x

x = 4

Substitute x = 4 in y = 2x + 1

y = 9

So, we have the following points

(4, 9) and (2, 10)

The distance between the above points is

d = √(x2 - x1)² + (y2 - y1)²

So, we have:

d = √(4 - 2)² + (9 - 10)²

Evaluate

d = √5

Hence, the distance between the line and the point is √5 units

Question 4

The line and the points are given as:

y = -x + 3

R = (-5, 0)

The slope of the above equation is

m = -1

The slope of a line perpendicular to it is

m = 1

A linear equation is represented as:

y = mx + b

Substitute m = 1

y = x + b

Substitute (-5, 0) in y = x + b

0 = 5 + b

Solve for b

b = -5

Substitute b = 5 in y = x + b

y = x + 5

So, we have:

y = x + 5 and y = -x + 3

Substitute x + 5 for y

x + 5 = -x + 3

Solve for x

x = -1

Substitute x = -1 in y = x + 3

y = 2

So, we have the following points

(-1, 2) and (-5, 0)

The distance between the above points is

d = √(x2 - x1)² + (y2 - y1)²

So, we have:

d = √(-1 + 5)² + (2 - 0)²

Evaluate

d = 2√5

Hence, the distance between the line and the point is 2√5 units

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finish this whole thing and ill give you five stars thanks and brainliest

Which statement is true?


The value of 8,590 − 4,586 is half the value of 2 x (8,590 − 4,586).

The value of 2,674 x 5,480 + 5 is 5 times the value of 2,674 + 5,480.

The value of 6,432 x (1,860 − 6) is 6 less than the value of 6,432 x 1,860.

The value of 2,876 x (9,280 + 8) is 8 more than the value of 2,876 x 9,280.

Answers

The value of 8,590 − 4,586 is half the value of 2 x (8,590 − 4,586).

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables. The basic operations performed on an equation are addition, subtraction, multiplication and division.

The value of 8,590 − 4,586 = 4004

Half the value of 2 x (8,590 − 4,586) = (1/2) of 2 x (8,590 − 4,586) = 4004

The value of 8,590 − 4,586 is half the value of 2 x (8,590 − 4,586).

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3(q+ 4/3 )=2 solve for Q

Answers

Answer: q = -2/3

Step-by-step explanation:

First, we need to apply the Distributive Law in order to proceed with the problem.

3(q + 4/3) = 2

3q + 3(4/3) = 2

We already know that 3(4/3) = 4, since the 3's cancel out. Or, 3(4/3) = 12/3 = 4.

Our new equation is,

3q + 4 = 2

Through transposition and isolation of variables, we get,

3q = -2

Dividing by 3 on both sides...

q = -2/3

what is the difference between d and 7?

Answers

Answer:

d - 7

Step-by-step explanation:

The word "difference" tells us that we will be using subtraction. Also, subtraction is not the same if you reverse the terms like, x - 2 and 2 - x are not the same. In your question it say "d and 7" so that's the order we use in the algebraic expression.

evaluate b-(-1/8)+c where b=2 and c=-7/4

Answers

Answer: [tex]\Large\boxed{\dfrac{3}{8} }[/tex]

Step-by-step explanation:

Given information

[tex]b=2[/tex]

[tex]c=-\dfrac{7}{4}[/tex]

Given expression

[tex]b-(-\dfrac{1}{8}) +c[/tex]

Substitute values into the expression

[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{7}{4} )[/tex]

Convert the fractions into the common denominator

Least Common Multiple (LCM) of 8 and 4 = 8

[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{7\times2}{4\times2} )[/tex]

[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{14}{8} )[/tex]

Simplify the parenthesis

[tex]=2+\dfrac{1}{8} -\dfrac{14}{8}[/tex]

Simplify by addition

[tex]=\dfrac{16}{8} +\dfrac{1}{8} -\dfrac{14}{8}[/tex]

[tex]=\dfrac{17}{8} -\dfrac{14}{8}[/tex]

Simplify by subtraction

[tex]\Large\boxed{=\dfrac{3}{8} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

A triangle with a base of 16 cm and a height of 9 cm.

Answers

Answer: 288

Step-by-step explanation:

(16x9)x2

The controller of MingWare Ceramics Inc. wishes to prepare a cost of goods sold budget for September. The controller assembled the following information for constructing the cost of goods sold budget: Direct materials: Enamel Paint Porcelain Total Total direct materials purchases budgeted for September $35,870 $7,530 $139,890 $183,290 Estimated inventory, September 1 1,730 4,150 6,920 12,800 Desired inventory, September 30 2,980 2,710 7,150 12,840 Direct labor cost: Kiln Department Decorating Department Total Total direct labor cost budgeted for September $51,550 $149,500 $201,050 Finished goods inventories: Dish Bowl Figurine Total Estimated inventory, September 1 $5,810 $3,310 $2,730 $11,850 Desired inventory, September 30 3,720 4,590 4,360 12,670 Work in process inventories: Estimated inventory, September 1 $3,540 Desired inventory, September 30 1,980 Budgeted factory overhead costs for September: Indirect factory wages $80,400 Depreciation of plant and equipment 10,550 Power and light 5,110 Indirect materials 3,390 Total 99,450 Use the preceding information to prepare a cost of goods sold budget for September. For those boxes in which you must enter subtracted or negative numbers use a minus sign. MingWare Ceramics Inc. Cost of Goods Sold Budget For the Month Ending September 30 Finished goods inventory, September 1 $Finished goods inventory, September 1 Direct labor $Direct labor Direct materials: $- Select - - Select - $- Select - - Select - $- Select - Direct labor fill in the blank 15 - Select - - Select - $- Select - Work in process inventory, September 30 fill in the blank 22 - Select - $- Select - - Select - $- Select - 4,100

Answers

The preparation of the Cost of Goods Sold Budget for MingWare Ceramics Inc. in September is as follows:

Cost of Goods Sold Budget:

Beginning inventory of finished goods $11,850

Cost of goods manufactured                485,310

Ending inventory of finished goods      (12,670)

Cost of Goods Sold                           $484,490

What is the cost of goods sold budget?

The cost of goods sold budget sums the costs of the beginning inventory of finished goods with the cost of goods manufactured and subtracts the ending inventory of finished goods.

The cost of goods sold budget is based on the cost of goods manufactured budget.

Data and Calculations:

Direct materials:                            Enamel        Paint     Porcelain      Total    

Total direct materials purchases

budgeted for September            $35,870    $7,530    $139,890  $183,290

Estimated inventory, September 1   1,730        4,150          6,920      12,800 Desired inventory, September 30 (2,980)      (2,710)         (7,150)    (12,840)

Materials used in production                                                          $183,250

Direct labor cost:           Kiln Department    Decorating Department   Total

Total direct labor cost

budgeted for September    $51,550                   $149,500        $201,050

Finished goods inventories:             Dish       Bowl     Figurine             Total

Estimated inventory, September 1  $5,810   $3,310     $2,730        $11,850

Desired inventory, September 30    3,720    4,590       4,360         12,670

Cost of goods manufactured budget:

Work in process inventories:

Estimated inventory, September 1      $3,540

Direct materials used in production $183,250

Direct labor costs                              $201,050

Total factory overhead costs             $99,450

Desired inventory, September 30       (1,980)

Cost of goods manufactured           $485,310

Budgeted factory overhead costs for September:

Indirect factory wages $80,400

Depreciation of plant and equipment 10,550

Power and light 5,110

Indirect materials 3,390

Total 99,450

Thus, to prepare the cost of goods sold, as above, MingWare Ceramics, requires to determine the cost of goods manufactured for September.

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Solve for the value of w.
(4W-8)°
(3w+6)°

Answers

Step-by-step explanation:

4W-8=3W+6

4W-3W=6+8

W=14°

lets find the value of W in this straight line

4W-8°=180°(angle on a straight line)

collect like terms

4W=180°+8°

4W=188°

divide both sides by the coefficient of W which is 4

W=47°

if i am correct pls rate it

By selling a TV for Rs 6900, a shopkeeper loses 8%. Find his cost price. What must be the price so as to make a profit of 12%?​

Answers

Answer:

The selling price must be ₹8400 to make a profit of 12%

======================

Given

Selling price of a TV is ₹6900,With this price the loss is 8%.

To find

SP to make a profit of 12%

Solution

Find the cost, x:

x - 8% of x = 6900x - 0.08x = 69000.92x = 6900x = 6900/0.92x = 7500

Find the price to get 12% profit:

7500 + 12% = 7500*1.12 = 8400

What is the length of the transverse axis (y-2)^2/16 - (x+1)^2/144= 1

Answers

The length of the transverse axis is 8.

What is transverse axis length?The transverse axis of the hyperbola is the straight line connecting vertices A and A'. The line segment connecting the vertices of a hyperbola is referred to as the transverse axis or AA'.The hyperbola's equation is expressed as (yk)2b2(xh)2a2=1). The center is (h,k), b defines the transverse axis, and a defines the conjugate axis. The section of a line where a hyperbola's vertices form.

Given the equation of hyperbola:[tex]\frac{(y-2)^{2} }{16}[/tex][tex]-\frac{(x+1)^{2} }{144 }[/tex][tex]=1[/tex]

Rewrite this equation as [tex]\frac{(y-2)^{2} }{4^{2} }[/tex][tex]-\frac{(x+1)^{2} }{12^{2} }[/tex][tex]=1[/tex]

When comparing this equation to the common hyperbola equation with a vertical transverse axis is [tex]\frac{(y-k)^{2} }{a^{2} }[/tex][tex]-\frac{(x+h)^{2} }{b^{2} }[/tex][tex]=1[/tex]

[tex]h = -1[/tex]

[tex]k= -2[/tex]

[tex]a = 4[/tex]

[tex]b = 12[/tex]

The length of the transverse axis is[tex]2a = 2*4[/tex]

                                                               [tex]=8.[/tex]

The length of the transverse axis is 8.

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Rachel is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove to get to the safe zone at 242424 meters per second. After 444 seconds of driving, she was 707070 meters away from the safe zone.
Let yyy represent the distance (in meters) from the safe zone after xxx seconds.
Complete the equation for the relationship between the distance and number of seconds.

Answers

The distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone. This can be obtained by converting the conditions to equations.

Find the equation for the relationship between the distance and number of seconds:

A linear function containing one dependent and one independent variable.

It can be represented using the equation,

y = mx + c

where m is the slope

It is given in the question that,

Rachel is a stunt driver and one time during a gig where she escaped from a building about to explode she drove to get to the safe zone at 24 meters per second.

After 4 seconds of driving, she was 70 meters away from the safe zone.

Let, D(t) be the distance to the safe zone (measured in meters) and t be the  time (measured in seconds)

After 4 seconds of driving, she was 70 meters away from the safe zone.

⇒ This means that at t = 4 seconds, D(4) = 70 meters

Rachel's rate is the slope of the function D(t). Since the distance is decreasing when the time is increasing, the slope must be negative

m = - 24

y = mx + c

⇒ D(t) = (-24)t + c

Put t = 4,

D(4) = (-24)4 + c

70 = -96 + c ⇒ c = 166

D(t) = 166 - 24t

Hence the distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone.

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Find X:
J:58
K:70
L:111
M:121

Answers

Answer:

L

Step-by-step explanation:

interior angle formula so

(number of sides - 2)*180

2*180 = 360

you can also just take an example from a square 4*90 = 360

360-121-58-70 = 111

I need help with the questions in this photo

Answers

Part I: The correct formula is D. ((x₁ + x₂)/2, (y₁ + y₂)/2)

Part II: The midpoint of the segment with endpoints (-2, -1) and (0, 9) is (-1, 4)

Calculating the midpoint of a line segment

From the question, we are to determine the formula for calculating the midpoint of a segment

The midpoint of a segment can be determined by using the formula,

Midpoint = ((x₁ + x₂)/2, (y₁ + y₂)/2)

The correct formula is D. ((x₁ + x₂)/2, (y₁ + y₂)/2)

II. To determine the midpoint of the segment with endpoints (-2, -1) and (0, 9)

x₁ = -2

y₁ = -1

x₂ = 0

y₂ = 9

Putting the parameters into the formula,

Midpoint of the segment = ((-2 + 0)/2, (-1 + 9)/2)

Midpoint of the segment = (-2/2, 8/2)

Midpoint of the segment = (-1, 4)

Hence, the midpoint of the segment with endpoints (-2, -1) and (0, 9) is (-1, 4)

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