Answer:i am not sure
Step-by-step explanation:
This question is very hard to answer
Answer: I think your brain needs cheese but..............................................
Step-by-step explanation:
Don't know
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Service Department Charges and Activity Bases
Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.
CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:
• The sector has 5,200 employees, of whom 25% are office employees.
• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.
• One hundred percent of the employees with a computer also have an e-mail account.
• The average number of help desk calls for October was 1.5 calls per individual with a computer.
• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.
a. Determine the service charge rate for the four CCS service categories for October.
CCS Service Category Service Charge Rate
Help desk $fill in the blank 1
Per call
Network center $fill in the blank 3
Per device monitored
Electronic mail $fill in the blank 5
Per user or e-mail account
Smartphone support $fill in the blank 7
Per smartphone issued
b. Determine the charges to the COMM sector for the four CCS service categories for October.
October charges to the COMM sector
Help desk charge $fill in the blank 9
Network center charge $fill in the blank 10
Electronic mail charge $fill in the blank 11
Smartphone support charge $fill in the blank 12
Feedback Area
Feedback
a. Divide the budgeted cost by the budgeted activity base quantity for each category.
b. Determine the Help desk charge by multiplying the rate from (a) by the number of employees times the percentage of office employees times the percentage with a computer times the number of calls. Follow a similar process for each of the other three categories.
Learning Objective 3.
The service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.
Service charge ratea. Service charge rate
Service charge rate=Budgeted cost/ Budgeted activity base quantity
Help desks:
Service charge rate=$160,000/3,200 calls
Service charge rate=$50 per call
Network center:
Service charge rate=$735,000/9,800 devices
Service charge rate=$75 per device monitored
Electronic mail:
Service charge rate=$100,000/10,000 accounts
Service charge rate=$10 per user or per e-mail account
Local voice support:
Service charge rate=$124,600/8,900 phone extensions
Service charge rate=$14 per phone extension
b. Help desk charge
Help desk charge =(Number of employees times × Percentage of office employees× Percentage with a computer ×Number of calls)× Service charge rate
Help desk charge:
(5,200 employee×25%×96%×1.5)× $50 per call
=$93,600
Network center charge:
[(5,200 employee×25%×96%)+ 600]× $75 per device
=$138,600
Electronic mail:
(5,200 employee×25%×96%×100)×$10 per user or per e-mail account
=$12,480
Local voice support:
(5,200 employee×25%)× $14 per phone extension
=$18,200
Therefore the service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.
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Solve the inequality and enter your solution as an inequality in the box below.
Do not use spaces in your answer.
2+ x>-8
Answer:
x > -10
Step-by-step explanation:
2 + x > -8
x > -8 - 2
x > -10
Answer:
x>-10
Step-by-step explanation:
2+x-2>-8-2
x>-10
cual es el valor de x+5=7
Answer: x = 2
Work Shown:
x+5 = 7
x+5-5 = 7-5
x = 2
Subtract 5 from both sides to isolate x. This is to undo the plus 5.
HELP ME WITH THIS QUESTION AS SOON AS POSSIBLE
Answer:
the answer is 2880
Step-by-step explanation:
because you would use the formula (n - 2) x 180 which equals the sum interior angles of any polygon .
The letter n stands for number of sides so in this case you would do (18 - 2) x 180 so 16 × 180 = 2880
hope this helped :) pls ask if you need any more explanation .
pls give brainliest if you like my answer :)
Line A passes through the points (-8, 5) and (-5, 4). Line B passes through the points (0, 1) and (4, -1). Which of the following describes the relationship between line A an line B?
1. Lines A and B are parallel, because they have opposite reciprocal slopes.
2. Lines A and B are parallel, because they have the same slope
3. Lines A and B intersect, because their slopes have no relationship.
4. Lines A and B are perpendicular, because they have opposite reciprocal slopes.
[tex]\stackrel{\textit{\LARGE Line A}}{(\stackrel{x_1}{-8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{4})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{4 -5}{-5 +8}\implies -\cfrac{1}{3} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{\textit{\LARGE Line B}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{0}}} \implies \cfrac{-1 -1}{4 +0}\implies -\cfrac{1}{2}[/tex]
keeping in mind that perpendicular lines have negative reciprocal slopes, and that parallel lines have equal slopes, well, those two slopes above aren't either, so since they're neither, and they're different, that means that lines A and B intersect.
It takes 3 liters of paint to cover an area of 24 square meters. What percentage increase in the quantity of paint would be required to cover an area of 50.4 square meters?
Answer:
110 [%].
Step-by-step explanation:
if the initial area is 24 m² and final area 50.4 m², then the required percentage can be calculated as:
[tex]\frac{50.4}{24}*100-100=110[/tex] ,
where 50.4/24*100 - the final percentage.
P.S. It means, the final value of the paint is 3*2.1=6.3 [liters].
round 00.963.785 to the nearest. hundredth
find the length of a segment in the coordinate plane with endpoints (5, -2) and (2, 2)
Answer: 5
Step-by-step explanation:
[tex]\sqrt{(5-2)^2 +(-2-2)^2}=5[/tex]
Please help me with this question <3 ASAP!
Answer:
54°
Step-by-step explanation:
Opposite angles of a parallelogram are congruent, so;
[tex]9x+9=8x+14 \\ \\ x=5 \\ \\ m\angle S=9(5)+9=54^{\circ}[/tex]
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
Angle S = 54°[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
In a Parallelogram, opposite angles are equal, so we infer that :
[tex] \qquad❖ \: \sf \:9x + 9 = 8x + 14 [/tex]
[tex] \qquad❖ \: \sf \:9x - 8x = 14 - 9[/tex]
[tex] \qquad❖ \: \sf \:x = 5 \degree[/tex]
Next,
Measure of Angle S is :
[tex] \qquad❖ \: \sf \:9x + 9[/tex]
[tex] \qquad❖ \: \sf \:9(5) + 9[/tex]
[tex] \qquad❖ \: \sf \:45 + 9[/tex]
[tex] \qquad❖ \: \sf \:54 \degree[/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
Angle S = 54°flying against the jet stream, a jet travels 3000 in 3 hours. Flying with the jet-stream, the same jet travels 5360 miles in 4 hours. What is the rate of the jet in still air and what is the rate of the jet stream?
Based on the time taken by the jet when flying with the wind versus against it, the rate of the jet and jet streams are:
In still air = 1,170 mphRate of wind = 170 mphWhat is the speed of the jet?The speed of the jet flying against the wind is:
= 3,000 / 3
= 1,000 mph
The speed with the jet stream is:
= 5,360 / 4
= 1,340 mph
Assuming the speed of the jet is x and the rate of wind is y, the formulas are:
x - y = 1,000
x + y = 1,340
Solving gives:
2x = 2,340
x = 1,170 mph
The rate of jet stream is:
x - y = 1,000
1,170 - y = 1,000
y = 170 mph
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Pls answer before 8:00 pm
Answer:225 jeans.
Step-by-step explanation: What we need to do here is convert the number of jeans to a percentage. There were 25 jeans when 50 customers were surveyed and 25 is half of 50 or 50%. This means that if 450 pairs of pants are ordered half of them should be jeans. 450/2 = 225.
Calcular el valor del ángulo que falta de un triangulo rectangulo si uno de sus lados mide 25 grados.
Considerando la definición de triángulo rectángulo y sus propiedades, el valor del ángulo que falta de un triángulo rectángulo es 65°.
Definición de triánguloUn triángulo es un polígono conformado por tres lados, así como por tres vértices y tres ángulos interiores.
Una de las propiedades de cualquier triángulo indica que la suma de los ángulos interiores es igual a 180°.
Definición de triángulo rectánguloEl triángulo rectángulo es una figura geométrica que se considera como un polígono formado por tres lados que forman un ángulo interior recto (es decir, mide 90°) y dos ángulos interiores agudos.
Valor del ángulo faltante en este casoEn este caso, sabes que:
Al ser un triángulo rectángulo, un ángulo interior mide 90°.Otro ángulo interior mide 25°.La suma de los ángulos interiores es igual a 180°.Entonces, el valor del ángulo faltante se puede calcular mediante:
90° + 25° + ángulo faltante= 180°
Resolviendo:
115° + ángulo faltante= 180°
ángulo faltante= 180° - 115°
ángulo faltante= 65°
Finalmente, el valor del ángulo que falta de un triángulo rectángulo es 65°.
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PLEASE HELP ME WITH THIS PROBLEM!!!
Answer: Moderate negative association
Step-by-step explanation:
a negative association or in other terms correlation, suggests that while one variable increases the other decreases and vice versawhen looking at the graph, the data shows a negative correlationas the x variable increases the y variable decreasesthis not a perfect correlation as the the change in value of variable x is not directly proportional to the change in value of yWhat does it mean for the volume of a solid object to be 10 in.³ rely on the meaning of volume by phone to 1“ x 1“ x 1“ cubes in your answer
The insinuation of calling the volume of a solid 3-dimentional shape 10in³ is that the product of all of its dimensions as measured in units is; 10 in.³.
What is the meaning of volume as used in the task content?It follows from the task content that the shape in discuss is a solid shape and consequently, one of it's measures is its volume which describes the space it occupies.
On this note, the meaning of a solid having a volume of 10in³ as indicated is that it's volume is; 10 times as large as the volume occupied by an object with unit dimensions 1“ x 1“ x 1“ in which case, the volume is; 1 in³.
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Scores on a test are normally distributed with a mean of 63 and a standard deviation of 9.3. Find P81, which separates the bottom 81% from the top 19%.
We want to find [tex]x[/tex] such that
[tex]\mathrm{Pr}(X \le x) = 0.81[/tex]
where [tex]X[/tex] is the random variable for test scores, and [tex]X\sim\mathrm{Normal}(63,9.3^2)[/tex].
Transform [tex]X[/tex] to [tex]Z\sim\mathrm{Normal}(0,1)[/tex] using the relation
[tex]X = \mu + \sigma Z \implies Z = \drac{X-63}{9.3}[/tex]
so that
[tex]\mathrm{Pr}(X \le x) = \mathrm{Pr}\left(\dfrac{X-63}{9.3} \le \dfrac{x-63}{9.3}\right) = \mathrm{Pr}\left(Z \le \dfrac{x-63}{9.3}\right) = 0.81[/tex]
Applying the inverse CDF of [tex]Z[/tex] (denoted by [tex]\Phi^{-1}[/tex]), we have
[tex]\dfrac{x-63}{9.3} = \Phi^{-1}(0.81) \approx 0.8779[/tex]
Solve for [tex]x[/tex].
[tex]\dfrac{x-63}{9.3} \approx 0.8779[/tex]
[tex]x-63 \approx 8.1644[/tex]
[tex]x \approx 76.1644[/tex]
Then the cutoff test score for the 81% percentile is [tex]P_{81} \approx \boxed{76}[/tex].
I'm trying to figure this out for extra credit but I don't know what to do can someone step by step take me through it with the answer?
Answer:
2800
Step-by-step explanation:
The choice at any node (except the edges) is to go right or go down.
A to BTo get from A to B requires a total of 4 choices to go down, and 4 choices to go right. Those can occur in any order. Locating the "right" choices in the list of "all" choices is effectively choosing 4 of 8. The number of ways those choices can be made is ...
C(8, 4) = 8!/(4!(8-4)!) = 8·7·6·5/(4·3·2) = 70
B to CSimilarly a total of 2 choices must be made, 1 of which is a "right" choice. The number of ways those can be ordered is ...
C(2, 1) = 2 . . . . . . . that is: (right, down) or (down, right)
C to DA total of 6 choices must be made, of which 3 are "right." The number of possible orderings is ...
C(6, 3) = 6·5·4/(3·2·1) = 20
Total pathsEach set of choices is independent of the others, so the total possible number is the product of the numbers of choices on the subpaths:
total paths = (70)(2)(20) = 2800
There are 2800 possible paths from A to D.
Graph the polar equation r=1-3 sin 0
No graph for the polar equation because here sin 0 is 0.
According to the statement
we have given that a polar equation and we have to represent in the graph.
So, For this purpose, we know that the
The expression of a point as an ordered pair. is known as polar notation, the equation of a curve expressed in polar coordinates is known as a polar equation.
The given polar equation is
r = 1-3 sin 0
here the value of r is 0.
so, No graph is possible for the given statement
because here the value of r is 0 and for zero value there is a no graph possible.
So, No graph for the polar equation because here sin 0 is 0.
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here is another one that i need help on What number represents the same amount as 8 hundreds + 10 tens + 0 ones
Answer:
810 is the number that represents the same amount.
Hope this helps :)
PLEASE HELP AS SOON AS POSSIBLE
A quadrilateral PQRS is a parallelogram. PQ and RS are opposite sides then the answer of this particular question is , x = 4, the parallelogram PQRS is a rhombus, QR = 31, The opposite angles are congruent. Thus, more than one answer is correct.
According to the question,
PQ = 7x+12; RS = 5x -20 and QR = 31
Solving PQ and RS we get x = 4. Thus, PQ = 40 and RS = 40.
A quadrilateral is a parallelogram if a pair of its opposite sides is parallel and congruent. A quadrilateral that has all sides equal and opposite sides parallel is called Rhombus.
Thus, the parallelogram PQRS is a rhombus.
Hence, a quadrilateral PQRS is a parallelogram. PQ and RS are opposite sides then the answer of this particular question is , x = 4, the parallelogram PQRS is a rhombus, QR = 31, The opposite angles are congruent. Thus, more than one answer is correct.
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HELP PLEASE
What is the area of the kite below?
Answer:
Area = 33 inches squared
Step-by-step explanation:
The formula for the area of a kite is:
Area = ½ × (d)1 × (d)2
To find the first diagonal (d1):
d1 = 7 in + 4 in = 11 in
To find the second diagonal (d2):
The triangles on the right of the kite must be 3 4 5 triangle since it is a right triangle with a hypotenuse of 5 and a side of 4, we know half of a diagonal would be 3 inches.
d2 = 3 in + 3 in = 6 in
Now we can plug the diagonals into the area formula.
Area = ½ × 11 × 6 = 33 inches squared
Answer: A = 33 in²
Step-by-step explanation:
Given information:
Longer side = 7 in
Shorter side = 4 in
Shorter Hypotenuse = 5 in
Given formula:
A = (1/2) × (d₁) × (d₂)
A = aread₁ = The longer line (horizontal)d₂ = The shorter line (vertical)Please refer to the attachment below for a graphical understanding
Determine the length of the shorter side (vertical) through the Pythagorean theorem
a² + b² = c² (Pythagorean theorem)
(4)² + b² = (5)² (Substitute values into the equation)
16 + b² = 25
b² = 25 - 16
b² = 9
b = 3 or b = -3 (rej)
Substitute values into the given formula
A = (1/2) × d₁ × d₂
A = (1/2) × (7 + 4) × (3 + 3)
Simplify values in the parenthesis
A = (1/2) × 11 × 6
Simplify by multiplication
A = (11/2) × 6
[tex]\Large\boxed{A=33}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Joey owns a small bakery and today Phoebe has ordered 100 cookies. If Joey boxes the cookies by the dozen, which of the following equations describes how many boxes of cookies Phoebe will have? Let b represent the number of boxes. (HINT: All of the cookie boxes are not necessarily full.)
Answer:
Joey needs 9 boxes.
Step-by-step explanation:
You will use the fact that a dozen is 12 cookies. You're trying to find how many dozen are in 100.
Something like:
12b = 100
or if you're studying inequalities:
12b >= 100
Divide by 12 to solve. See image. Interpret the results. See image.
Hava Racquets Company manufactures pickleball racquets in four different models.
For the year, the SoftNet line had a net loss of AED 40,000 from sales of AED 250,000,
variable costs of AED 180,000 and fixed costs of AED 110,000. If the Softnet is
eliminated, AED 30,000 of fixed cost will remain. What would be the incremental
effect to the Company if the Softnet would be eliminated?
Based on the AED 40,000 net loss that the SoftNet line brings to Hava Racquets company, the incremental effect if the Softnet line is eliminated is that the company would save AED 10,000.
What is the incremental effect?If Hava Racquets Company decides to scrap the Softnet line, then it means that they will no longer be incurring the AED 40,000 net loss that the line had brought to them.
They would instead incur a fixed cost of AED 30,000 which they can apply to their other operations.
This means that in exchange for a AED 40,000 loss, they would instead get a AED 30,000 loss.
The savings on these losses is:
= 40,000 - 30,000
= AED 10,000
This means that Hava Racquets Company will make a saving of AED 10,000 if they eliminate the line.
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Which graph shows a system with no solutions?
Graph A
Graph B
y
201
OA. Graph B
OB. Graph C
OC. Graph A
5
5
Graph C
Y
5
5+
y=2x-1
5
2y=4x-2
Answer:
i belive its graph B
4x-9y=36 find the missing y-coordinate
The y-intercept of the function is given as (0, -4). This also shows that the value of y missing from the coordinate is -4
How to find the y-intercept of a function?The y-intercept of a function is the point where the value of x is zero. Given the function below;
4x-9y=36
when the value of x is zero, hence;
4(0) - 9y = 36
Simplify to have:
0 - 9y = 36
-9y = 36
Divide both sides by -9 to have:
-9y/-9 = 36/-9
y = -4
Hence the y-intercept of the function is given as (0, -4). This also shows that the value of y missing from the coordinate is -4
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For the function p defined by p(m) = 2m^-4m+3, find p(1/3).
Determine three numbers a , b , c
such that a , b , c are three consecutive terms of a geometric sequence and an arithmetic sequence at the same time.
Note: i do not want the answer
d=0 and r=1, as in 2 , 2 , 2 , 2 , 2...
Given also:
abc=27 or a.b.c=27
Since [tex]a,b,c[/tex] are in geometric progression, if [tex]r[/tex] is the common ratio between consecutive terms, then
[tex]a=a[/tex]
[tex]b = ar[/tex]
[tex]c=ar^2[/tex]
Since [tex]a,b,c[/tex] are also in arithmetic progression, if [tex]d[/tex] is the common difference between consecutive terms, then
[tex]a = a[/tex]
[tex]b = a + d \implies d = b-a[/tex]
[tex]c = b + d = a + 2d \implies c = a + 2(b-a) = 2b-a[/tex]
Given that [tex]abc=27[/tex], we have
[tex]abc = a\cdot ar\cdot ar^2 = (ar)^3 = 27 \implies ar = 3 \implies a = \dfrac3r[/tex]
[tex]b = \dfrac3r \cdot r = 3[/tex]
[tex]c = \dfrac3r \cdot r^2 = 3r[/tex]
It follows that
[tex]c = 2b-a \iff 3r = 6 - \dfrac3r[/tex]
Solve for [tex]r[/tex].
[tex]3r - 6 + \dfrac3r = 0[/tex]
[tex]3r^2 - 6r + 3 = 0[/tex]
[tex]r^2 - 2r + 1 = 0[/tex]
[tex](r-1)^2 = 0[/tex]
[tex]\implies r=1 \implies a=b=c=3[/tex]
so the only possible sequence is {3, 3, 3, …}.
Assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard deviation 15. Find the probability that a randomly selected adult has an IQ less than 123.
The probability that a randomly selected adult has an IQ less than 123 is ____.
Answer:
.8849 or 88.49% have score ess than 123
Step-by-step explanation:
Answer:
88.49 % have less than 123 (or .8849)
Step-by-step explanation:
123 is 18/15 = 1.2 S.D. ABOVE the mean z-score +1.2
from z- score table +1.2 this is .8849 or 88.49 %
A rectangular park had a dirt path across its diagonal that was yards long. The diagonal and the long side of the park formed an angle that measured . A person walked along the sidewalks outside the park, from the start to the end of the path, as shown by the arrows. The diagonal dirt path that cuts across the rectangular park and the sidewalks outside the park form a right triangle. The dirt path is the hypotenuse and it is labeled 100 yards. The start of the sidewalk is adjacent to the 30-degree angle, and it is labeled X. The end of the path is opposite the 30-degree angle, and it is labeled Y. Which expression shows the distance that he walked?
Trigonometry functions are functions that relate two sides of a given triangle with one of its included angles.
The expression that shows the distance that he walked = x + y + 100
= 87 + 50 + 100
= 237 yards
Trigonometry functions are functions that relate two sides of a given triangle with one of its included angles. The required function may be a sine function, a cosine function, or a tangent function.
Such that;
Sin θ = [tex]\frac{Opposite}{Hypotenuse}[/tex]Cos θ = [tex]\frac{Adjacent}{Hypotenuse}[/tex]Tan θ = [tex]\frac{Opposite}{Adjacent}[/tex]The given question can be solved by applying the appropriate trigonometric function.
So that to determine the value of x, we have:
Cos θ = [tex]\frac{Adjacent}{Hypotenuse}[/tex]
Cos 30 = [tex]\frac{x}{100}[/tex]
⇒ x = 100 cos 30
= 100 x 0.866
x = 86.60
Thus, the start of the sidewalk is approximately 87 yards.
To determine the value of sidewalk y, we have:
Sin θ = [tex]\frac{Opposite}{Hypotenuse}[/tex]
Sin 30 = [tex]\frac{y}{100}[/tex]
⇒ y = 100 x Sin 30
= 100 x 0.5
y = 50
Thus the sidewalk which represents the end of the path is 50 yards.
Therefore, the total distance that he walked = 100 + 87 + 50
= 237 yards
The expression that shows the distance that he walked = x + y + 100
= 87 + 50 + 100
= 237 yards
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Find the first five terms of the recursive sequence. Show all work.
The first five terms of the recursive sequence are 5, 12, 19, 26 and 33.
How to use recursive equations to generate a series
In this question we have a linear recursive equation that requires the value of the immediately previous element to generate the next one. Then, we need to evaluate the expression for the first five elements:
i = 1
a₁ = 5
i = 2
a₁ = 5, a₂ = a₁ + 7
a₂ = 5 + 7
a₂ = 12
i = 3
a₂ = 12, a₃ = a₂ + 7
a₃ = 12 + 7
a₃ = 19
i = 4
a₃ = 19, a₄ = a₃ + 7
a₄ = 19 + 7
a₄ = 26
i = 5
a₄ = 26, a₅ = a₄ + 7
a₅ = 26 + 7
a₅ = 33
The first five terms of the recursive sequence are 5, 12, 19, 26 and 33.
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Evaluate the limits
[tex]x > \ln(x)[/tex] for all [tex]x[/tex], so
[tex]\displaystyle \lim_{x\to\infty} (\ln(x) - x) = - \lim_{x\to\infty} x = \boxed{-\infty}[/tex]
Similarly, [tex]\displaystyle \lim_{x\to\infty} (x-e^x) = - \lim_{x\to\infty} e^x = \boxed{-\infty}[/tex]
We can of course see the limits are identical by replacing [tex]x\mapsto e^x[/tex], so that
[tex]\displaystyle \lim_{x\to\infty} (\ln(x) - x) = \lim_{x\to\infty} (\ln(e^x) - e^x) = \lim_{x\to\infty} (x - e^x)[/tex]
You can also rewrite the limands to accommodate the application of l'Hôpital's rule. For instance,
[tex]\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\exp\left(\lim_{x\to\infty} (x - e^x)\right)\right) = \ln\left(\lim_{x\to\infty} e^{x-e^x}\right) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right)[/tex]
Using the rule, the limit here is
[tex]\displaystyle \lim_{x\to\infty} \frac{(e^x)'}{\left(e^{e^x}\right)'} = \lim_{x\to\infty} \frac{e^x}{e^x e^{e^x}} = \lim_{x\to\infty} \frac1{e^{e^x}} = 0[/tex]
so the overall limit is
[tex]\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right) = \ln(0) = \lim_{x\to0^+} \ln(x) = -\infty[/tex]