which graph below shows the solutions for the linear inequality y>- 1/3x + 1

¹³C₈ + ¹³C₉ as a single term from Pascal's Triangle is ¹⁴C₉

Pascal's triangle is a triangle written in such a way that it forms the coefficients of a binomial expansion. The coefficients of the terms are gotten through combination.

Combination is the number of ways r in which n objects can be selected. It is given by ⁿCₓ = n!/x!(n - x)!

Since we have ¹³C₈ + ¹³C₉ and we want to write it as a single term, we have that

So,  ¹³C₈ + ¹³C₉ =  13!/8!5! +  13!/9!4!

= 13!/(8! × 5 × 4!) +  13!/(9 × 8! × 4!)

= 13!/8!4![1/5 + 1/9]

= 13!/8!4! × [(9 + 5)/45]

= 13!/8!4! × 14/45]

= 13!/8!4! × 14/(9 × 5)]

= 14 × 13!/8! × 9 × 4! × 5)]

= 14!/9!5!

= 14!/9!(14 - 9)!

= ¹⁴C₉

So,  ¹³C₈ + ¹³C₉ as a single term from Pascal's Triangle is ¹⁴C₉

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[tex]x+\frac{b}{2a}=\pm \frac{\sqrt{b^2 -4ac}}{2a}[/tex]

i really hate how we actually have to type something.

Volume of prism = [tex]\frac{1}{2x^{3} } + x^{2}[/tex]

Given that:

The oblique prism below has an isosceles right triangle base and the length of the base is x

=> the area of the base: [tex]\frac{1}{2}[/tex] × x × x = [tex]\frac{1}{2}[/tex]

The vertical height of the prism is (x + 2)

=> The volume of the oblique prism is:

                    V = the base area * the vertical height

<=> V = [tex]\frac{1}{2}[/tex] [tex]x^{2}[/tex] (x + 2)

<=> V =  [tex]\frac{1}{2x^{3} } + x^{2}[/tex]

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The amount of water that will serve the entire container exists 3/10 gallons.

An expression exists a sentence with a minimum of two numbers or

variables and at least one math function.

Given: 1 over 5 gallons of water serve 2 over 3 of the container.

(1/5) gallon / (2/3) container = x gallons / 1 container

cross-multiplying the above equation, we get

1/5 = (2/3)x

multiply both sides by the reciprocal of 2/3 = 3/2

(3/2) (1/5) = x = 3/10 gallons serve the total container

Each 1/10 of a gallon serve 1/3 of the container

So 3(1/10) gallons serve 3(1/3)bins

3/10 gallons serve a whole container.

The amount of water that will serve the entire bin container exists 3/10 gallons.

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Answer: 120

Step-by-step explanation:

Answer:

B. 60°

Step-by-step explanation:

Angle 4 and angle 8 are equal. Find the measure of angle 4 to know the measure of angle 8.

∠4=∠8

180-120=60

∠4=60°

Since angle 4 equals 60 degrees, angle 8 also equals 60 degrees.

Hope this helps!

The inverse function of f(x) = 1/2x + 1/4 is f-1(x) = 2x - 1/2

The function is given as:

f(x) = 1/2x + 1/4

Rewrite the function as

y = 1/2x + 1/4

Swap the positions of x and y

x = 1/2y + 1/4

Multiply through by 4

4x = 2y + 1

Subtract 1 from both sides

2y = 4x - 1

Divide by 2

y = 2x - 1/2

Rewrite as an inverse function

f-1(x) = 2x - 1/2

Hence, the inverse function of f(x) = 1/2x + 1/4 is f-1(x) = 2x - 1/2

See attachment for the graph of the inverse function

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Answer:

Step-by-step explanation:

e graph opens upward, and it has a vertex of (0,0)

What is vertex?

The vertex of an equation is the minimum or the maximum point on the graph of the equation

The equation of the graph is given as:

The above equation represents an absolute value function

An absolute value function is represented as:

So, by comparison, we have:

This means that the graph opens upward, and it has a vertex of (0,0)

See attachment for the graph of

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The ratio illustrates that the values will be 3146.7945 gram, 9440.3835 gram, and 3968.93 grams.

It should be noted that 1 ounce is equivalent to 28.3495 gram.

Therefore, 111 ounces will be:

= 111 × 28.3495 gram

= 3146.7945 gram

333 ounces will be:

= 333 × 28.3495 gram

= 9440.3835 gram

140 ounces will be:

= 140 × 28.3495 gram

= 3968.93 grams

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2x4=8

8x2=16

the answer is 16

The table of values for y=1/2x-1 is completed as follows:

x               y

-2             -2

-1            -3/2

0               -1

1             -1/2

2                0

3              1/2

Exactly one value from the set of second components of the ordered pair is connected with each value from the set of first components of the ordered pairs in a relation known as a function.

Given function:  y=1/2x-1

For x = -2

Value of y = -2

For x = -1

Value of y = 1/2(-1)-1 = -3/2

For x = 0

Value of y = 1/2(0)-1 =-1

For x = 1

Value of y = 1/2(1)-1 = -1/2

For x = 2

Value of y = 0

For x = 3

Value of y = 1/2(3)-1 = 1/2

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the expression that represents the volume of the prism is  14x² + 7x cubic centimeters. Option 2

The  volume of a pentagonal prism is determined using the formula;

V = 5/2abh

where

Now, let's substitute the values given

Let the base be 'x'

The apothem is 2. 8 centimeters

height is 2x + 1

Volume = 5/ 2 × 2. 8 × x × (2x + 1)

Volume = 14/ 2 × x(2x + 1)

Volume = 7x(2x + 1)

Volume = 14x² + 7x

Thus, the expression that represents the volume of the prism is  14x² + 7x cubic centimeters. Option 2

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Answer:

[tex]\textsf{A. } y=3x^2+10x-8[/tex]

Step-by-step explanation:

We are given the information that a function has zeros at x = ⅔ and x = -4. In order to find the function that has those zeros, we can substitute the value of the zeros into each function. If the value of a function equates to zero with both values, then that is the function we are looking for.

..................................................................................................................................................

Standard Form of a Quadratic: ax² + bx + c = 0.

..................................................................................................................................................

[tex]\large \text{$y = 3x^2+10x-8 \implies 0=3x^2+10x-8$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{24}{3}-8\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2+10(-4)-8\\\\\implies 0=3(16)-40-8\\\\\implies 0=48-48\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]

..................................................................................................................................................

[tex]\large \text{$y = 2x^2-5x-12 \implies 0=2x^2-5x-12$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2-5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=2\left(\dfrac{4}{9}\right)-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}-\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=-\dfrac{22}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{130}{9}\ \textsf{X}\end {minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2-5(-4)-12\\\\\implies 0=2(16)+20-12\\\\\implies 0=32+20-12\\\\\implies 0=40\ \textsf{X}\end{minipage}}[/tex]

..................................................................................................................................................

[tex]\large \text{$y = 2x^2+5x-12 \implies 0=2x^2+5x-12$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2+5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}+\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=\dfrac{38}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{70}{9}\ \textsf{X}\end{minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2+5(-4)-12\\\\\implies 0=2(16)-20-12\\\\\implies 0=32-32\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]

..................................................................................................................................................

[tex]\large \text{$y = 3x^2-10x-8 \implies 0=3x^2-10x-8$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2-10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)-\dfrac{20}{3}-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)-\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}-\dfrac{20}{3}-\dfrac{8\times3}{3}\\\\\implies 0=-\dfrac{16}{3}-\dfrac{24}{3}\\\\\implies 0=-\dfrac{40}{3}\ \textsf{X}\end{minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2-10(-4)-8\\\\\implies 0=3(16)+40-8\\\\\implies 0=48+40-8\\\\\implies 0=80\ \textsf{X}\end{minipage}}[/tex]

..................................................................................................................................................

Therefore, the function whose zeros are ⅔ and -4 is [tex]y=3x^2+10x-8[/tex].

The descriptive statistics for the above data is given as follows:
X = 12.5

A set of concise descriptive coefficients that describe a particular data set indicative of a whole or sample population is known as descriptive statistics.

For X (mean) = [tex]{\displaystyle X={\frac {1}{n}}\sum _{i=1}^{n}X_{i}[/tex]

= 300/24

= 12.5

For sample variance = [tex]s^2 = \frac{1}{n-1}\biggl[\, \sum_{i=1}^n X_i^2 - \frac{\Bigl(\,\sum\limits_{i=1}^n X_i\Bigr)^{\!2}}{n} \biggr][/tex]

= (1/(24-1) (4,900 - (300²/24)

= 50

Standard deviation s = √s²

= √50

= 7.0711

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The stock's current price  is  53.413455.

What is CAPM ?

The capital asset pricing model (CAPM) to know the value of the stock

[tex]Ke = rf + \beta ( r_{m} - r_{f} )[/tex]

risk free = 0.085

premium market =(market rate - risk free) = 0.045

beta(non diversifiable risk) 1.3

Ke = 0.085 + 1.3(0.045)

Ke = 0.14350

Now we need to know the present value of the future dividends:

D0 = 2.8

D1 = D0 × ( 1 +g ) = 2.8  = 2.8 * 1.23 = 3.444

D2 3.444 x 1.23 = 4.2361200

The next dividends, which are at perpetuity will we solve using the dividned grow model

[tex]\frac{divends}{return - growth} = Intrinsic value[/tex]

In this case dividends will be:

4.23612 x 1.07 = 4.5326484

return will be how return given by CAPM and g = 7%

plug this into the Dividend grow model.

[tex]\frac{4.5326484}{0.1435 - 0.07} = Intrinsic value[/tex]

value of the dividends at perpetity: 61.6686857

Finally is important to note this values are calculate in their current year. We must bring them to present day using the present value of a lump sum:

[tex]\frac{principal}{(1 + rate)^{time} } = PV[/tex]

[tex]\frac{3.444}{(1 + 1. 1435)^{1} } =PV[/tex]

3.011805859

[tex]\frac{4.23612}{( 1 + 0.1435)^{2} } = PV[/tex]

3.239633762

[tex]\frac{61.6686857}{(1 + 0.1435)^{2} } = PV[/tex]

47.16201531

We add them and get the value of the stock  is 53.413455.

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Answer: 12x squared + 2x + 96

Step-by-step explanation: We first simplify the parentheses. 8x2 = 16 - 4x - 8 = 16-8-4x = 8-4x. 2x2 = 4 +3x+2 = 4+2+3x = 6+3x. So, we are left with (16-4x)(6+3x).  We rearrange the problem so it looks like this: (-4x + 16)(3x + 6). -4x(3x+6)  + 16(3x+6). Now we just multiply. And, we get 12 x squared + 2x + 96

Answer: y ≥ [tex]\frac{3}{2}[/tex]x + 3

Step-by-step explanation:

       Since the shaded area is above the line, we will use either > or ≥ for our inequality.

       Next, since this is a solid line we will use the ≥ symbol for our inequality. This means the answer is the first option.

Answer:

23 is the answer

Answer:

Step-by-step explanation:

Refer to attached diagram with added details.

Circle O with:

Since r = OC + CD, the radius is 4 cm.

Consider right triangles OAC or OBC:

Recall the property of 30°x60°x90° triangle:

It means OC: OA = 1 : 2, so angles AOC and BOC are both 60° as adjacent to short legs.

In order to find the shaded area we need to find the area of sector OADB and subtract the area of triangle OAB.

Area of sector:

Area of triangle AOB:

The shaded area is:

Answer:

336

Step-by-step explanation:

They can place 1 of 8 frags on the bottom.

Now they have 7 flags left.

They can place 1 of 7 flags in the middle.

Now they have 6 flags left.

The can place 1 of 6 flags on top.

8 × 7 × 6 = 336

The p-value that would be given as the evidence would be given as p-value = 0.00002 and also P value = 0.00003

The sample size of the first sample = 100

x1 = success 0f 86%

We have to find the proportion of this = 0.86

The sample size of the second sample n2 = 100

x12 = success 0f 60%

We have to find the proportion of this = 60/100

= 0.6

The difference = 0.86-0.6= 0.26

Next we have to find the pooled proportion. This is taken given as p = (x1+x2)/(n1+n2) this gives us 0.73

Next we have to find the standard error

= √(p*(1-p)*(1/n1+ 1/n2)= 0.06279

Z stat = (0.26-0)/0.0628= 4.1411

From here the p value would have to be

p-value = 0.00002 and also

P value = 0.00003

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The first four partial sums of the sequence are S₁ = 0.3010, S₂ = 0.9999, S₃ = 2.447, S₄ = 4.8569.

In this question,

A sequence is a set of things (usually numbers) that are in order. A partial sum is the sum of part of the sequence.

The sequence is [tex]a_{n} =log(n^{n}+1 )[/tex]

The first four partial sum S₁, S₂, S₃, S₄ can be calculated by substituting n = 1,2,3,4 in the sequence.

S₁ can be calculated as

S₁ = a₁

⇒ [tex]a_{1} =log(1^{1}+1 )[/tex]

⇒ [tex]a_{1} =log(1+1 )[/tex]

⇒ [tex]a_{1} =log(2 )[/tex]

⇒ [tex]a_{1} =0.3010[/tex]

Now, S₁ = 0.3010

S₂ can be calculated as

S₂ = a₁ + a₂

⇒ [tex]a_{2} =log(2^{2}+1 )[/tex]

⇒ [tex]a_{2} =log(4+1 )[/tex]

⇒ [tex]a_{2} =log(5 )[/tex]

⇒ [tex]a_{2} =0.6989[/tex]

Now, S₂ = 0.3010 + 0.6989

⇒ S₂ = 0.9999

S₃ can be calculated as

S₃ = a₁ + a₂ + a₃

⇒ [tex]a_{3} =log(3^{3}+1 )[/tex]

⇒ [tex]a_{3} =log(27+1 )[/tex]

⇒ [tex]a_{3} =log(28)[/tex]

⇒ [tex]a_{3} =1.4471[/tex]

Now, S₃ = 0.3010 + 0.6989 + 1.4471

⇒ S₃ = 2.447

S₄ can be calculated as

S₄ = a₁ + a₂ + a₃ + a₄

⇒ [tex]a_{4} =log(4^{4}+1 )[/tex]

⇒ [tex]a_{4} =log(256+1 )[/tex]

⇒ [tex]a_{4} =log(257 )[/tex]

⇒ [tex]a_{4} =2.4099[/tex]

Now, S₄ = 0.3010 + 0.6989 + 1.4471 + 2.4099

⇒ S₄ = 4.8569

Hence we can conclude that the first four partial sums of the sequence are S₁ = 0.3010, S₂ = 0.9999, S₃ = 2.447, S₄ = 4.8569.

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Answer:

y is equal to -16

Answer:

y = 8

Step-by-step explanation:

We can use proportions for this question since y varies directly with x. This means that if x changes, y changes along with the x, and vice versa.

When y = -8, x = 4, so the proportion will be -8 : 4.

We need to find the y when x is 4, so our equation will be:

-8 : 4 = y : -4

Since the proportion will be the same.

Next, we multiply the inner two numbers, and the outer two numbers, saying that the values are the same.

4y = 32

y = 8

So y = 8 will be our answer!

Answer:

See below

Step-by-step explanation:

Using triangle side rule :  The sum of any two sides must be greater than the third side

.5<x<16.5

The range of possible sizes for side x for given triangle is 0.5<x<16.5.

In the given triangle, one side measures 8.5 units, other side is 8.0 units and third side is x units.

The length of one side of a triangle must be greater than the difference and less than the sum of the lengths of the other two sides.

Here, the range of x is 8.5-8.0<x<8.5+8.0

0.5<x<16.5

Therefore, the range of possible sizes for side x for given triangle is 0.5<x<16.5.

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Answer:

8.57.

Step-by-step explanation:

that would be 360/42

= 8.5714

Answer:

D

Step-by-step explanation:

Pq=opp/hyp

(135+12)=180

Answer:

m=-4

y-intercept=8

x-intercept=2

Step-by-step explanation:

Please see attachment.

y-intercept=8

The y-intercept is where the line crosses the y-axis.

x-intercept=2

The x-intercept is where the line crosses the x-axis.

m=-4

If you do not know how to find slope by looking at graph, use slope formula.

(y2-y1)/(x2-x1)

Choose 2 points. You may use the x and y intercepts.

(2,0) and (0,8)

(8-0)/(0-2)=8/-2=-4

Hope this helps!

The given set of functions are not linearly independent.

Given,

[tex]f_{1} (x) = x\\f_{2} (x) = x^{2} \\f_{3} (x) = 6x-2x^{2}[/tex]

We need,

[tex]c_{1} f_{1} (x)+c_{2} f_{2} (x)+c_{3} f_{3}(x)=0[/tex]

Substituting the values in equation we get,

[tex]c_{1} x+c_{2} x^{2} +c_{3} (6x-2x^{2} )=0\\[/tex]

Computing the equation we get,

[tex]c_{1} x+c_{2} x^{2} +c_{3} 6x-c_{3} 2x^{2}=0[/tex]

[tex](c_{1} +6c_{3} )x+(c_{2} -2c_{3} x^{2} =0[/tex]

This resolves to two equations

[tex](c_{1} +6c_{3})x =0\\(c_{2} -2c_{3} )x^{2} =0[/tex]

These will have an infinite set of solutions:

[tex]c_{1} =-6c_{3} \\c_{2} =2c_{3}[/tex]

Two functions are said to be linearly independent if neither function is a constant multiple of the other.

Here, it is clear that the given functions are not linearly independent.

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The system of the linear systems of equation using substitution is;

3x-y=4

x+2y=6

from (2)

x = 6 - 2y

substitute into (1)

3x-y=4

3(6 - 2y) - y = 4

18 - 6y - y = 4

- 6y - y = 4 - 18

-7y = -14

y = 2

Substitute into

x+2y=6

x + 2(2) = 6

x + 4 = 6

x = 6 - 4

x = 2

2. 2x-y= -39

x+y= -21

From (2)

x = -21 - y

substitute into

2x-y= -39

2(-21 - y) - y = -39

-42 - 2y - y = -39

- 2y - y = -39 + 42

- 3y = 3

y = 3/-3

y = -1

substitute into

x+y= -21

x + (-1) = -21

x - 1 = -21

x = -21 + 1

x = -20

3. 2x+y =11

6x-5y =9

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