An atom which an electron moves from the first to the third shell atom absorbs more energy.
An atoms may occupy different energy states . The energy states are discrete , that means they occur at specific values only. Therefore an atom can only move to a new energy level if it absorbs or emits an amount of energy that exactly corresponds to the difference between two energy levels.
The lowest possible energy levels that the atom can occupy is called ground state.The energy levels which is higher to the ground state is called excited state.
The more energy absorb when electron move from first to third because in this second energy level have to pass to reach at third energy level.
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Mannose (C6H12O6) is a simple sugar found in many fruits and vegetables. How many oxygen atoms are in 7. 15 x 10^23 molecules of mannose?
Number of oxygen atoms present in 7.15×10²³ molecules of mannose are 1.92≈2 a m u .
What is mannose sugar?D-mannose is a simple sugar found in many fruits. It is related to glucose. In some cells it occurs naturally in the body.
Mannose is a six-carbon sugar found in a variety of fruits and vegetables. This sugar is not found free in foods. It is a part of polysaccharide chains attached to a variety of proteins.
To calculate number of oxygen atoms present in 7.15×10²³ molecules of mannose-
Since,
1 molecule of oxygen=2.303×10²³ no. of atoms
Here, total number of molecules of oxygen is 6.
Therefore, 6 molecule of oxygen =6×2.303×10²³÷7.15×10²³
=1.92≈2 a m u .
Hence, the total number of oxygen atoms in 7.15×10²³ molecules of mannose is 1.92 ≈2 a m u.
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How many molecules of propane were in the erlenmeyer flask? Avogadro's number is 6. 022 × 10^23 molecules/mol
3.74×[tex]10^{21}[/tex]
3.74 ×[tex]10^{21}[/tex] molecules of propane were in the erlenmeyer flask.
number of moles of propane can be calculated as moles of propane.
mass of propane = 0.274 g
molar mass of propane = 44.1
So this gives us the value of 6.21×[tex]10^{-3}[/tex] moles of propane
No one mole of propane As a 6.0-2 × [tex]10^{23}[/tex]
so, 6.21 ×[tex]10^{-3}[/tex] × 6. 022 × 10^23
= 3.74 ×[tex]10^{21}[/tex]
Therefore, molecules of propane were in the erlenmeyer flask is found to be 3.74 ×[tex]10^{21}[/tex]
What is erlenmeyer flask?A laboratory flask with a flat bottom, a conical body, and a cylindrical neck is known as an Erlenmeyer flask, sometimes known as a conical flask or a titration flask. It bears the name Emil Erlenmeyer after the German chemist.What purpose does an Erlenmeyer flask serve?Liquids are contained in Erlenmeyer flasks, which are also used for mixing, heating, chilling, incubating, filtering, storing, and other liquid-handling procedures. For titrations and boiling liquids, their sloped sides and small necks make it possible to whirl the contents without worrying about spills.To learn more about calculating total molecules visit:
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Helium and methane gases are mixed together in a container. what is the ratio of their root-mean-square speeds, i. e. (vrms,helium) / (vrms,methane) ?
Root mean square speed is the estimation of the effect of temperature and weight on kinetic energy. The root means square speed for a mixture of helium and methane is 2. Thus, option d is correct.
What is the root mean square speed?Root mean square speed is the estimation of the square root of the mean value of the squared speeds of the individual gas particles in the mixture.
As it is known that,
Root mean square speed = √{3RT/M}
Where T is constant temperature and R is gas constant. The molecular mass of helium gas is 4 g/mol and of methane is 16 g/mol.
Vrms = √{3RT/M}
For helium, Vrms = √{3RT/4}
And, for methane = Vrms = √{3RT/16}
So, (Vrms,helium) / (Vrms,methane) = 4 / 2 = 2
Therefore, option d. 2 is the root-mean-square speed for the mixture.
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Your question is incomplete, but most probably your full question was, Helium and methane gases are mixed together in a container. what is the ratio of their root-mean-square speeds, i. e. (Vrms, helium) / (Vrms, methane)?
1/2102cannot tell41/4When the forecast calls for freezing rain, salt is often spread on the roads. Why is this done?
Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with water and water with octanol when measuring ow?
N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by [tex]K_{OW}[/tex] (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one, when it's more dissolved in water, the value is lower.
What is the partition coefficient?
The partition coefficient for the two-phase network comprising n-octanol and water is known as the [tex]K_{OW}[/tex] value. N-Octanol-Water Partition Ratio is another name for it.The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by [tex]K_{OW}[/tex]. The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique [tex]K_{OW}[/tex] ratio.So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.
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How many calories (not joules) are given off when 85 gram of steam condenses to liquid water?
45,849 calories are given off when 85 gram of steam condenses to liquid water.
Vaporization is always a highly endothermic (heat-absorbing) process because you must break all the intermolecular interactions present inside of the liquid phase.
So,
Q = mass × heat of vapourization
Q = m×ΔH[tex]_{vap}[/tex]
Q = 85 × 539.4
Q = 45,849 cal
Therefore, 45,849 calories are given off when 85 gram of steam condenses to liquid water.
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Sonam has a tank that holds 0.5L of air at a temperature of 300K and a pressure
of 880kPa.
What volume would the air occupy if it were released into the atmosphere, where
the pressure is 102kPa and the temperature is 327K?
Answer:
4.70 L
Explanation:
Use the basic relationship:
P1V1/T1 = P2V2/T2
Re-arrange to:
P1V1 T2 / (T1P2) = V2 To find the new volume
Sub in the values:
880 * .5 * 327 / ( 300*102) = 4.70 L
If a person wearing such a mask exhales 0. 65g of CO2 every minute. Calculate the number of grams of O2 that will be produced in 15 minutes.
If a person wearing such a mask exhales 0. 65g of [tex]CO_{2}[/tex] every minute then the number of grams of [tex]O_{2}[/tex] that will be produced in 15 minutes is 7.09 grams .
Calculation ,
Since number of moles of carbon dioxide exhale is equal to the number of moles of oxygen produce ,
Mass of carbon dioxide exhale per minute = 0.65 g
Mass of carbon dioxide exhale 15 minute = 0.65 g × 15 = 9.75 g
Number of moles of carbon dioxide = given mass / molar mass = 9.75 g/44
Number of moles of carbon dioxide = 0.221 moles
Number of moles of oxygen = 0.221 moles = given mass / molar mass
Number of moles of oxygen = 0.221 moles = given mass / 32
Mass of oxygen = 0.221 moles × 32 = 7.09 grams
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An aqueous solution has a molality of 3. 64 kcl. what is the the mass percent of kcl in the solution? enter your answer to three significant figures and in units of mass percent
The mass percentage of KCl solution is 21.34%
Calculation,
Given molality of KCl aqueous solution = 3. 64 m = 3. 64 mole/ Kg
It means 3. 64 mole of solute present in 1Kg of solvent
or , 3. 64 mole of solute present in 1000 g of solvent ( water )
Mass of solute ( KCl ) = 3. 64 mole×74.55 g/mole =271.3 g
The total mass of solution ( KCl + water ) = 271.3 g + 1000 g = 1271.3 g
Mass percentage is equal to percentage of mass of solute present in total mass of solution.
Mass percentage = 100×271.3 g/1271.3 g = 21.34%
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Extra was made by mixing different components together but it appears to have only one phase which term best describes categorizes make sure a
Solution is the term which best describes mixture A which was made by mixing different components together but has only one phase.
What is solution?Any mixture of one or more solutes that have been dissolved in a solvent is referred to as a solution.To create a homogenous mixture, a solute must dissolve in a solvent.The material known as a solute dissolves in a solvent to form a homogenous mixture.The material that is present in the highest concentration is called a solvent.A true solution won't spin apart in a centrifuge.It has a uniform distribution of particles.Example of homogenous mixture is the solution of salt and water.Learn more about solution here:
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Calculate the ph at the equivalence point for the titration of 0. 22 m hcn with 0. 22 m naoh. (ka = 4. 9 × 10^–10 for HCN).
The pH at the equivalence point for the titration of 0. 22 m HCN with 0. 22 m NaOH is 11.17
Calculation,
Concentration of NaCN = 0. 22 m/ 2 = 0.11 M ( at equal volumes of acid and base will be used).
The equilibrium is ,
HCN +[tex]H_{2} O[/tex] → [tex]H^{+} + CN^{-}[/tex]
C(1-x) Cx Cx
Where x , is the degree of hydrolysis and
[tex]K_{h}[/tex] = C[tex]x^{2}[/tex]/(1-x)
We know that [tex]K_{h}[/tex] = [tex]K_{w}/K_{a}[/tex] = 1 ×[tex]10^{-14}[/tex]/4. 9 ×[tex]10^{-10}[/tex] = 2.04×[tex]10^{-5}[/tex]
[tex]K_{h}[/tex] = C[tex]x^{2}[/tex] = 2.04×[tex]10^{-5}[/tex] = 0.11 M×[tex]x^{2}[/tex]
[tex]x^{2}[/tex] = 2.04×[tex]10^{-5}[/tex]/0.11 M
x = 1.36×[tex]10^{-2}[/tex]
[tex][OH^{-} ][/tex] = Cx = 1.36×[tex]10^{-2}[/tex] × 0.11 M = 0.15×[tex]10^{-2}[/tex]
[tex][H^{+} ][/tex] = 1 ×[tex]10^{-14}[/tex]/ 0.15×[tex]10^{-2}[/tex] = 6.66×[tex]10^{-12}[/tex]
pH = -㏒[tex][H^{+} ][/tex] = -㏒6.66×[tex]10^{-12}[/tex] = 11.17
The pH at the equivalence point for the titration is 11.17.
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Al+HCl=AlCl6+H6
is this balanced or unbalanced
Answer:
unbalanced
Explanation:
balanced: Al+HCl=AlCl+H
25. 22 the reaction of phenylmagnesium bromide with methyl benzoate followed by acidification produces triphenylcarbinol. what are the sources of phenyl groups in triphenylcarbinol?
Triphenylcarbinol( or triphenylmethanol) gets its phenyl groups from phenylmagnesium bromide.
Synthesis of triphenylcarbinol:
A typical laboratory experiment for demonstrating the Grignard reaction is the synthesis of triphenylmethanol using methyl benzoate, benzophenone, and phenylmagnesium bromide. Diethyl carbonate is a possible starting material.
Characteristics:
An organic substance is a triphenylmethanol. It is a white, crystalline substance that dissolves well in alcohol, diethyl ether, and benzene but not in water or petroleum ether. Due to the creation of a persistent "trityl" carbocation, it generates a bright yellow hue in very acidic solutions. Important dyes include several triphenylmethanol derivatives.Triphenylmethanol has a core tetrahedral carbon atom, three phenyls (Ph) rings, and an alcohol group attached to it. With lengths of around 1.47Å for all three C-Ph bonds and 1.42Å for the C-O link, these connections are characteristic of sp3-sp2 carbon-carbon bonds.Three neighboring phenyl groups give off specific qualities that are reflected in the alcohol's reactivity.Learn more about triphenylmethanol here:
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What would be the effect on the percentage recovery if not enough naoh were added in step 2 to react with both the unreacted hno3 and the cu2 present at the end of step 1?
The metallic cu⁺ will not be formed to calculate percentage recovery.
What is percentage recovery?
Most commonly "percent recovery" in chemistry refers to the quantity of recovered substance following a purifying procedure. This purification procedure could involve anything from completely separating a particular ingredient to removing a molecule totally.
If we do not completely react the HNO₃ in the reacion mixture, it will not fully reduce Cu ions which will not form all the metallic copper or if at all its formed the quantity will be very low that we will use to calculate the percentage recovey at the end.
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What is the mass of a 32.5-ml sample of ethanol? the density of ethanol is 0.789 g/ml.
Answer:
25.6 grams of ethanol in 32.5 ml of the substance.
Explanation:
The density of ethanol can be used as a conversion factor. We know that:
Ethanol is 0.789 g/ml. That becomes a conversion factor that we may write as (0.789 g/ml) and then convert either grams ethaanol or ml ethanol into the other unit. We are given volume of ethanol: 32.5 ml.
Note that when we multiply (0.789 g/ml) by (32.5 ml) the ml unit cancels, leaving just grams. That's what we want, so:
(0.789 g/ml)(32.5 ml) = 25.6 grams of ethanol in 32.5 ml of the substance.
Electric vehicles have less range they can drive compared to plug-in hybrid electric vehicles. true false
Answer is plug-in hybrid cars also offer advantages and disadvantages. The primary benefit is range. Plug-in hybrid vehicles include a gasoline engine in addition to an electric motor, whereas an electric car can only go as far as its batteries will allow. Plug-in drivers benefit from having the best of both worlds as a consequence.
what is a electric vehicle?
An electric car is fully electric. Instead of a petrol tank, it has a battery, and an electric motor rather than an internal combustion one. If your batteries run out, there isn't a backup motor like in a hybrid electric vehicle. Many versions, nevertheless, offer space for an extra battery. The Nissan Leaf, Tesla Model S, and Ford Focus Electric are a few examples.
what is a plug in hybrid electric vehicle?
A plug-in hybrid electric car combines (or, if you prefer, is a hybrid of) an electric and gasoline-powered vehicle. They have a gas tank, an internal combustion engine, an electric motor, and a battery. You could say they have everything. Gasoline and electricity are both used as fuel in plug-in hybrid electric vehicles. The Chevrolet Volt, Toyota Prius Plug-in, and Cadillac ELR are a few examples.
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Mike dissolves equal amounts of potassium chloride (KCl) and table sugar (C12H22O11) in the same container of water.
After both substances fully dissolve, what atoms or molecules remain in the water?
A. molecules of KCl and individual atoms of C, H, and molecules of KCl and individual atoms of C, H, and O , ,
B. individual atoms of K and Cl and molecules of C12 H22 O11 individual atoms of K and Cl and molecules of C12, H22, O11, , ,
C. molecules of KCl and C6 H12 O6 molecules of KCl and C6, H 12, O6, , ,
D. individual atoms of K, Cl, C, H, and O
Molecules of KCl and C6 H12 O6 molecules of KCl and C6, H 12, O6, will be present on dissolving equal amount of potassium chloride (KCl) and table sugar (C12H22O11) in the same container of water.
Dissolving the sugar within the water makes a homogenous aggregate and once dissolved an answer is made by the combination of a solute (sugar) and solvent. If a solute is a strong or liquid, growing the temperature will increase its solubility. as an example, greater sugar can dissolve in warm water than in cold water. If a solute is a gasoline, increasing the temperature decreases its solubility.
The solvent is the substance which commonly determines the physical state of the solution (stable, liquid or gas). The solute is the substance which is dissolved by means of the solvent. as an example, in an answer of salt and water, water is the solvent and salt is the solute.A supersaturated solution is an answer that contains greater than the maximum quantity of dissolved solute than a saturated solution below the identical conditions.
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Write the equation for the formation of ethyl acetate from ethanol and acetic acid
The equation for the formation of ethyl acetate from ethanol and acetic acid will be [tex]CH_{3} COOH (l) + C_{2} H_{5} OH(l)[/tex] ⇔ [tex]CH_{3} COOC_{2}H_{5} (aq) + H_{2}O (l)[/tex].
When ethanol reacts with acetic acid then it will form ethyl acetate.
Ethyl acetate was created through the esterification reaction between acetic acid and ethanol because once sulphuric acid would be present. Esterification is just the process by which a carboxylic acid reacts with an alcohol to create an ester.
In a chemical process known as acetoacetic ester synthesis, ethyl acetoacetate would be alkylated at the -carbon between both carbonyl groups before being transformed into a ketone, or more precisely, acetone with a -substituted carbon.
Therefore, the equation for the formation of ethyl acetate from ethanol and acetic acid will be [tex]CH_{3} COOH (l) + C_{2} H_{5} OH(l)[/tex] ⇔ [tex]CH_{3} COOC_{2}H_{5} (aq) + H_{2}O (l)[/tex].
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What is the ph of a 0. 10 m solution of NaCN at 25°C?(ka= 4. 9 x 10^-10for hcn at 25°C. )
The pH of a a 0. 10 m solution of NaCN at 25°C is 11.15
Calculation
The reaction in the solution is given below
[tex]CN^{-} + H_{2} O[/tex] → HCN + [tex]OH^{-}[/tex]
initial 0.1
change ( -x) (+x)
equilibrium ( 0.1 - x ) x
Kb = [HCN] [[tex]CN^{-}[/tex] ]/[[tex]CN^{-}[/tex] ]
Kb × Ka = Kw = 1.0 × [tex]10^{-14}[/tex]
Kb = 1.0 × [tex]10^{-14}[/tex] / 4.9 × [tex]10^{-10}[/tex] = [HCN] [[tex]CN^{-}[/tex] ]/[[tex]CN^{-}[/tex] ] = [tex]x^{2}[/tex]/ ( 0.1 - x )
Kb = 2.04× [tex]10^{-5}[/tex] = [tex]x^{2}[/tex]/ ( 0.1 - x )
Since , [NaCN] /Kb > 100 , we can simplify the above equation to
= 2.04× [tex]10^{-5}[/tex] = [tex]x^{2}[/tex]/ ( 0.1 )
x = 1.43 × [tex]10^{-3}[/tex] M = [HCN] = [ [tex]OH^{-}[/tex]]
Then pOH = 2.84
pH + pOH = 14
pH = 14- pOH = 14 - 2.84 = 11.15
Therefore , the pH is 11.15
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What would be the molecular formula of a monosaccharide characterized as an aldotetrose?
The molecular formula of a monosaccharide characterized as an aldotetrose is [tex]C_{5}H_{10} O_{5}[/tex].
What is monosaccharide?Any monosaccharide, often known as simple sugar, is one of the fundamental substances that forms the basis of carbohydrates.
Some features of monosaccharide are-
With some more than a hydroxyl group (OH) as well as a carbonyl group (C=O) either in the final carbon atom (aldose) or on the second carbon atom, monosaccharides constitute polyhydroxy aldehydes as well as ketones (ketose). A cyclic molecule is created when one hydroxyl group and the carbonyl group interact in an aqueous solution (hemi-acetal or hemi-ketal). A crystalline, water-soluble monosaccharide is the end product.Dioses, trioses, tetroses, pentoses, hexoses, and heptoses are the different types of monosaccharides according on the quantity of carbon atoms they contain. The majority have five or six.To know more about common monosaccharides, here
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If a saturated solution prepared by dissolving Ag2CO3 in pure water has [ag ] = 2. 56 x 10^-4m. What is the value of ksPfOR Ag2CO3?
The value of Ksp for Ag₂CO₃ in the saturated solution will be 8.39 × 10⁻¹².
A saturated solution is the one in which the maximum amount of solute that a solvent can dissolve in it has been dissolved. If more solute is tried to be dissolved than the crystals of the solute will be present in the solution as they won't dissolve.
According to the solution,
[Ag⁺] = 2.56 × 10⁻⁴ M
In saturated solution,
Ag₂CO₃ + H₂O ⇒ 2Ag⁺ + CO₃²⁻
Ksp = [Ag⁺]² [CO₃²⁻]
[CO₃²⁻] = 1/2 [Ag⁺]
[Ag⁺] = 2.56 × 10⁻⁴ M
Therefore, [CO₃²⁻] = 1.28 × 10⁻⁴ M
Hence, Ksp = (2.56 × 10⁻⁴ M)² × (1.28 × 10⁻⁴ M)
Therefore, Ksp = 8.39 × 10⁻¹²
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How does the mass per nucleon of an element change as the atomic number increases?
Answer:
Explanation: So, the atomic number is the number of protons present in an atom. For example, Helium's atomic number is 2, meaning it only has 2 protons. In most cases, the number of nuetrons and protons are equal, so Helium (usually) has 2 protons and 2 nuetrons - this is the nucleus. The atomic mass, or mass per nucleon is the proton and nuetron added together, so the atomic mass of Helium is about 4. Therefore, on the periodic table, as the atomic number increases by 1, the atomic mass increases by about 2 (the atomic mass is an average so it's not exact).
What are the spectator ions in the reaction between aqueous zncl2 and aqueous na2co3?(choose all that apply)
Sodium and chloride are the spectator ions in the reaction between aqueous zncl2 and aqueous na2co3.
Spectator ions are ions that are present on both sides of chemical reactions but do not take part in the reaction itself. The spectator ions on both sides of the equation are cancelled in the net chemical reaction. So, to "spectate" is to "see" the other ions in an aqueous solution interact with one another.
An ion known as a spectator is one that is present both before and after a chemical reaction but does not take part in it. Sodium is a spectator ion in an aqueous solution of sodium hypochlorite (NaOCl, bleach): Na+ + HOCl + OH or OCl- + H2O -
Cross out the spectator ions after comparing the reactant and product sides. Observer ions are any dissolved ions that exhibit the same form on both sides.
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Find the volume occupied by 22. 0 g of helium gas at 26. 0 ° C and 1. 20 atm of pressure.
The volume occupied by 22. 0 g of helium gas at 26. 0 ° C and 1. 20 atm of pressure is 112.37 L .
Calculation ,
According to ideal gas equation ,
PV = nRT ....(i)
where P is the pressure = 1. 20 atm
V is the volume of the helium gas = ?
R is the universal gas constant = 0.082 atm L /K mol
T is the temperature of the gas = 26. 0 ° C = 299 K
n is the number of moles
Number of miles (n) = given mass/ molar mass =22 g/4 = 5.5 moles
By putting the value of pressure , volume , temperature and universal gas constant in equation ( i) we get
1. 20 atm ×V = 5.5 moles × 0.082×299
V = 5.5 moles × 0.082×299/1. 20 atm = 112.37 L
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What is the molality of a nh₄no₃ solution of 125 g of nh₄no₃ (80.0434 g/mol) in 275 g of water (18.0153 g/mol)?
The molality of the given solution is 5.67 mol/kg
You may calculate the molality of a solution to find out how many moles of solute you obtain per kilogram of solvent. Mol/kg is a typical molality measurement unit in chemistry. One molal is another way to refer to a solution with a concentration of 1 mol/kg. Molar mass must be represented in kg/mol rather than the more common g/mol or kg/kmol when using the unit mol/kg. The formula is as follows:
Molality = [tex]\frac{moles of solute}{kilogram of solvent}[/tex]
First we need to find moles of solute ;
moles of solutes = [tex]\frac{given mass}{molecular mass}[/tex]
moles = 125 / 80.0434
moles of solute = 1.56
Now, molality is ;
molality = 1.56 / 0.275
molality = 5.67 mol/kg
Therefore, The molality of the given solution is 5.67 mol/kg
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2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)
2.0 moles C6H6 reacts with oxygen according to the reaction above. What volume of water vapor forms at STP?
Taking into account the reaction stoichiometry and STP conditions, Finally, a volume of H₂O of 134.4 L will be formed at STP.
Reaction stoichiometryIn first place, the balanced reaction is:
2 C₆H₆ + 15 O₂ → 12 CO₂ + 6 H₂O
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
C₆H₆: 2 molesO₂: 15 molesCO₂: 12 molesH₂O: 6 molesSTP conditionsStandard pressure and temperature conditions are a set of standard pressure and temperature conditions for laboratory experimental measurements that are established to allow comparisons between different sets of measured data.
Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Volume of H₂O formedBy reaction stoichiometry 2 moles of C₆H₆ form 6 moles of water or H₂O.
Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of H₂O occupies a volume of 22.4 liters, 6 moles occupies how much volume?
volume= (6 moles× 22.4 L) ÷ 1 mole
volume= 134.4 L
Finally, 134.4 L of H₂O will be formed.
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A 21. 2-l sample of nitrogen at 3. 65 atm and 22°c is simultaneously expanded to 62. 6 l and heated to 34°c. what is the new pressure of the gas?
a. a. 349 atm
b. 235 atm
c. 1. 19 atm
d. 1. 29 atm
e. 1. 91 atm
Then the new pressure of the sample of nitrogen is 1.28 atm
So, option D is correct one.
Calculation,
Formula used : [tex]P_{1} V_{1} /T_{1} =P_{2} V_{2}/T_{2}[/tex] (i)
Where , P is pressure and V is the volume
Given data,
[tex]P_{1}[/tex] = 3. 65 atm
[tex]V_{1}[/tex] = 21. 2 L
[tex]P_{2}[/tex] =
[tex]V_{2}[/tex] = 62. 6 L
[tex]T_{1}[/tex] = 22°C = 22+273 = 295 K
[tex]T_{2}[/tex] = 34°C = 34 +273 = 307 K
Putting the value of all data given in equation (i) we get,
3. 65 atm × 21. 2 L/295 K = [tex]P_{2}[/tex] × 62. 6 L / 307 K
[tex]P_{2}[/tex] = 3. 65 atm × 21. 2 L × 307 K/295 K × 62. 6 L = 1.28 atm
Then the new pressure the sample of nitrogen is 1.28 atm
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A substance decays so that the amount a of the substance left at time t is given by: a = a0 ∙ (0.8)t where a0 is the original amount of the substance. what is the half-life (the amount of time that it takes to decay to half the original amount) of this substance rounded to the nearest tenth of a year?
The half-life of the substance is 3.106 years.
What is the formula for exponential decay?The exponential decline, which is a rapid reduction over time, can be calculated with the use of the exponential decay formula. The exponential decay formula is used to determine population decay, half-life, radioactivity decay, and other phenomena. The general form is F(x) = a.Here,
a = the initial amount of substance
1-r is the decay rate
x = time span
The equation is given in its correct form as follows:
a = [tex]a_{0}[/tex]×[tex](0.8)^{t}[/tex]
As this is an exponential decay of a first order reaction, t is an exponent of 0.8.
Now let's figure out the half life. Since the amount left is half of the initial amount at time t, that is when:
a = 0.5 a0
Substituting this into the equation:0.5[tex]a_{0}[/tex] = [tex]a_{0}[/tex]×[tex](0.8)^{t}[/tex]
0.5 = [tex](0.8)^{t}[/tex]
taking log on both sides
t log 0.8 = log 0.5
t = log 0.5/log 0.8
t = 3.106 years
The half-life of the substance is 3.106 years.
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How do different glycosidic bonds contribute to the properties of different sugars?
When the hemiacetal of a saccharide (or a molecule made from a saccharide) combines with the hydroxyl group of another chemical, such as alcohol, a glycosidic bond, also known as a glycosidic linkage, is formed. Only sugars in cyclic forms, which have an anomeric carbon and can create a glycosidic bond, may do so.
The glucose units of glycogen, the main type of energy storage in animal cells, are connected by glycosidic linkages. They are the bonds that make up the strong exoskeletons of beetles, crabs, and lobsters as well as the cellulose that makes up the woody sections of plants and trees.
A sugar molecule connected to another molecule via an ether group is the outcome of a glycosidic connection. A chemical compound called an ether, which consists of an oxygen atom bound to two carbon atoms, is less reactive than other chemical compounds like alcohols. Glycosides are therefore typically more stable than free sugars.
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500. ml of a solution containing 1. 5 m nh4cl(aq) is mixed with 500. ml of a solution containing 0. 50m of naoh(aq). what is the ph of the final solution? (kb(nh3) = 1. 8 x 10-5)
The pH of the solution is determined by the hydrogen ion concentration. The pH of the solution with 1.5 M NH4Cl and 0.50 M NaOH is 8.77.
What is pH?
The potential of the hydrogen ion in the given solution is called pH which determines the acidity and basicity of the solution.
Given
The molar concentration of 500 mL NH4Cl = 1.5 M
The molar concentration of 500 mL NaOH= 0.50 M
Kb (NH3) = 1.8 × 10 -5
First pOH is calculated as,
pOH = pKB + log [NH4Cl][NaOH]
= - log 1.8 × 10-5 + log [1.5][0.50]
= - log 1.8 × 10-5 + log [3]
= 4.744 + 0.477
= 5.221
Now, pH is calculated from pOH as,
pH + pOH = 14
pH = 14 – pOH
= 14 – 5.221
= 8.77
Thus we found that, 8.77 is the pH of the solution with 1.5 M NH4Cl and 0.50 M NaOH.
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