By 15% percent does the population of weeds decrease each day given that the function representing the number of weeds is W(d)=1650(0.85)^d. This can be obtained by using the function representing the exponential decay.
Find percent by which the population of weeds decrease each day:Number of weeds is represented by the function,
W(d)=1650(0.85)^d
⇒ W(d)=1650(1 - 0.15)^d
Here, d = number of days since application
Function representing the exponential decay is,
⇒ A(r) = A(1 - r)^t
where,
A = Initial value
r = Percentage decay
t = duration
By comparing the given function and function representing the exponential decay,
r = 0.15 ≈ 15/100
Or r = 15%
Therefore, population of weeds will decrease 15% each day.
Hence by 15% percent does the population of weeds decrease each day given that the function representing the number of weeds is W(d)=1650(0.85)^d.
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1. Ellie has 2/8 pound of cheese. She used 1/2 of the cheese to make tacos. Since there are 16 ounces in one pound, how many ounces of cheese does Ellie use to make tacos?
The ounces of cheese Ellie uses to make tacos is 2
What is a unitary method?
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Calculation :
1 pound = 16 ounces
Total cheese Ellie has = [tex]\frac{2}{8}[/tex] pound
Cheese required to make tacos = [tex]\frac{2}{8}[/tex]×[tex]\frac{1}{2}[/tex] = [tex]\frac{1}{8}[/tex] pounds
Ounces of cheese required to make cheese are [tex]\frac{1}{8}[/tex] × 16 = 2 ounces
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please help! find the distance of AG if A (4,4) and G (-1,-1)
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's solve ~
By using distance formula :
[tex]\qquad \sf \dashrightarrow \: \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{(4 - ( - 1)) {}^{2} + (4 - ( - 1)) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{(4 + 1) {}^{2} + (4 + 1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{2(5) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: 5 \sqrt{2 }\: \: units[/tex]
The distance between two points [tex]\rm{A(x_1,y_1)} [/tex] and [tex]\rm{B(x_2,y_2)}[/tex] is given by the formula,
[tex] \rm{AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }[/tex]
Proof:
[tex] \rm{Let \: X'OX \: and \: YOY' \: be \: the \: z-axis \: and \: y-axis \: respectively. Then, O \: is \: the \: origin.}[/tex]
[tex] \rm{Let \: A(x_1,y_1) \: and \: B(x_2,y_2) \: be \: the \: given \: points.}[/tex]
[tex] \rm{Draw \: AL \perp \: OX, BM \perp \: OX \: and \: AN \perp BM }[/tex]
Now,
[tex] \rm{OL=x_1,OM=x_2,AL=y_1 \: and \: BM=y_2}[/tex]
[tex]\rm\therefore{AN=LM=(OM-OL)=(x_2-x_1)}[/tex]
[tex] \: \: \: \: \rm{BN=(BM-NM)=(BM-AL)=(y_2-y_1)}[/tex]
[tex] \rm{In \: right \: angled \: \triangle ANB, by \: Pythagorean \: theorem,}[/tex]
We have,
[tex] \: \: \: \: \rm{AB^2=AN^2+BN^2}[/tex]
[tex] \rm{or,AB^2=(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex] \rm\therefore AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} [/tex]
The Given question,
Find the distance of AG if A (4,4) and G (-1,-1).
Solution,
The given points are A(4,4) and G(-1,-1).
Then,
[tex] \rm{(x_1=4,y_1=4) and (x_2=-1,y_2=-1)}[/tex]
We know that,
The distance formula,
[tex] \rm{AG= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }[/tex]
[tex] \: \: \: \: \: \: \: \: = \sqrt{ {( - 1 - 4)}^{2} + {( - 1 - 4)}^{2} } [/tex]
[tex] \: \: \: \: \: \: \: \: = \sqrt{ {( - 5)}^{2} + {( - 5)}^{2} } [/tex]
[tex] \: \: \: \: \: \: \: \: = \sqrt{25 + 25} [/tex]
[tex] \: \: \: \: \: \: \: \: = \sqrt{50} [/tex]
[tex] \: \: \: \: \: \: \: \: = \sqrt{(2)(25)} [/tex]
[tex] \: \: \: \: \: \: \: \: = \sqrt{(2)(5)(5)} [/tex]
[tex] \: \: \: \: \: \: \: \: = \sqrt{(2)( {5}^{2}) } [/tex]
[tex] \rm \: \: \: \: \: \: \: \: = 5 \sqrt{2} \: units[/tex]
Answered by:
[tex]\frak{\red{moonlight123429}}[/tex]
look at the graph below. what is the slope of the line a. -3 b.-1/3 c.1/3 d. 3
Answer:
-1/3
Step-by-step explanation:
Slope is rise over run. Every 3 units to the left, it rises 1 unit, so the slope is -1/3.
sariah has just begun training for a half-marathon, which is 13.1 miles. since she was on vacation, she started the training program later than the rest of her running club. There are 6 weeks of training runs remaining before the race.
In her first week of training, Sariah ran 3 miles. She ran 4.5 miles the second week and 6 miles the third week. If she continues to increase the length of her runs the same way, will there be enough time left in the train program for her to get up to half-marathon distance?
Describe how you would solve this problem using Polya’s four-step problem-solving method. Complete each task as part of your response. Be sure to number task 1-task 4 so that your instructor can tell which part you are answering.
1. understand the problem
task 1: read the problem and restate in your own words what the question asks.
2. formulate a plan
task 2: identify the model you would use to represent the problem and explain why you chose the model.
3. implement the plan
task 3: solve the problem and state your answer.
4. review the results
task 4: explain your problem-solving process and how you know your answer is correct.
There would not be enough time to reach the half marathon distance.
Would there be enough time to reach the half marathon distance?The distance run in a week can be represented with a linear equation. A linear equation is an equation that has a single variable raised to the power of 1.
The linear equation that would be used to represent the distance run would be in the form:
Miles run in a week = miles run the previous week - increase in miles
Increase in miles = 6 - 4.5 = 1.5 miles
Miles run in the fourth week = 1.5 + 6 = 7.5 miles
Miles run in the fifth week = 7.5 miles + 1.5 miles = 9 miles
Miles run in the sixth week = 9 + 1.5 = 10.5 miles
There would not be enough time to reach the half marathon distance because in the sixth week she would be able to run 10.50 miles
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What is the area of the shape?
The area of the shape is 35 square units
How to determine the area of the shape?The given shape is a trapezoid, and it has the following side lengths
Parallel bases = 6 and 8
Height = 5
The area of the shape is then calculated as:
A = 0.5 * (sum of parallel bases) * height
Substitute the known values in the above equation
A = 0.5 * (6 + 8) * 5
Evaluate the product
A = 35
Hence, the area of the shape is 35 square units
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The area of the given trapezoid is given as 35 square units
How to determine the area of a trapezoid?The given shape is quadrilateral known s a trapezoid. The formula for calculating the are of the trapezoid is expressed as;
A = 1/2(a+b)*h
where
a and b are parallel sides
h is the height of the trapezoid.
Given the following parameters
a =6units
b = 8 units
h - 5 units
Substitute to have:
A = 1/2(6 + 8) * 5
A = 1/2(14) *5
A = 7 * 5
A = 35 square units
Hence the area of the given trapezoid is given as 35 square units
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Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.
a. true
b. false
It is True that Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.
What is the use of flowcharts?A flowchart serves a picture consisting the separate steps of a process which is in sequential order and can be used to break large systems into subsystems during programing.
If a more cohesive module is needed, it can be formed into one unit, having the performance of multiple functions.
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A tire on sal's car makes 13 revolutions per second while traveling down the freeway. sal's tires are 2 ft in diameter, and there are 5,280 feet in 1 mile. how far does sal drive in 1 hour? round the answer to the nearest mile. a. 28 miles b. 56 miles c. 60 miles d. 111 miles
Compute the speed of the car:
[tex]\dfrac{2\pi\,\rm ft}{1\,\rm rev} \cdot \dfrac{13\,\rm rev}{1\,\rm s} \cdot \dfrac{1\,\rm mi}{5280\,\rm ft} \cdot \dfrac{3600\,\rm s}{1\,\rm h} = \dfrac{195\pi}{11} \dfrac{\rm mi}{\rm h} \approx 55.6919 \dfrac{\rm mi}{\rm h}[/tex]
So after 1 hour, Sal will have driven about 56 mi.
PLEASE HELP IM STUCK
Step-by-step explanation:
2 equations with 2 variables.
the most common approach is
1. use one equation to express one variable by the other.
2. use this expression in the second equation and solve for the second variable.
3. use that solution in the original first equation and solve for the first variable.
the end.
0.05N + 0.10D = 2.20
N + D = 23
1. N = 23 - D
2. 0.05(23 - D) + 0.10D = 2.20
1.15 - 0.05D + 0.10D = 2.20
0.05D = 1.05
D = 1.05/0.05 = 21
3. N = 23 - D = 23 - 21 = 2
2 Nickels, 21 Dimes
In the diagram below, EF || HG, EF = 5, HG = 12, FI = 1 4x + 3
and HI= 6.1x - 6.5.
What is the length of HI?
The length of HI in the similar triangles is: (4) 24.
What are Similar Triangles?The corresponding sides of triangles that are similar to each other have ratios that are equal to each other, thus, they are proportional.
Triangle EFI and triangle GHI are similar to each other. Therefore, their corresponding sides have ratios that are equal. Thus, we will have the following:
HI/FI = HG/EF
Given:
EF = 5,
HG = 12,
FI = 1.4x + 3
HI = 6.1x - 6.5
Plug in the values
6.1x - 6.5/1.4x + 3 = 12/5
Cross multiply
5(6.1x - 6.5) = 12(1.4x + 3)
Open the bracket
30.5x - 32.5 = 16.8x + 36
30.5x - 16.8x = 32.5 + 36
13.7x = 68.5
Divide both sides by 13/7
13.7x/13.7 = 68.5/13.7
x = 5
HI = 6.1x - 6.5
Plug in the value of x
HI = 6.1(5) - 6.5
HI = 30.5 - 6.5
HI = 24
The length of HI in the similar triangles is: (4) 24.
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Which of the following is equivalent to the quotient below?
√135/√3
A. 5√3
B. √45/3
C. 3√5
D. 3√15
The answer is C. 3√5.
√135/√3√45√3² × 53√5use the fact that there are 2pi radians in each circle to find another angle, smaller than 2pi, that is equivalent to 17pi/6. with detailed steps pleasee
The equivalent angle in the interval [0, 2pi] is 5pi/6.
How to find the equivalent angle?
Remember that for any given angle θ in radians, we define a family coterminal or equivalent angles as:
A = θ + n*(2pi)
Where n is a whole number.
Now we want to find an angle equivalent to 17pi/6 that is on the range between 0 and 2pi.
Then we can write:
A = 17pi/6 + n*(2pi)
If we use n = -1, then we get:
A = 17pi/6 - 2pi = 17pi/6 - 12pi/6 = 5pi/6
This is the equivalent angle in the desired range.
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Choose the equation that satisfies the data in the table.
-1 0 1
0
3
6
X
Y
OA. y = 3x +3
B.y = -x +9
Oc.y=x+9
OD. y=-3x +3
Answer:
A
Step-by-step explanation:
Based on the given table:
(x, y ) values are
(-1, 0)
(0, 3)
(1, 6)
A.
y = 3x+3, substitute each x and y pair in the equation to see if it checks
(x= -1, y= 0) (x= 0, y= 3) (x= 1, y= 6)
0 = -1·3+3 3 = 0·3 +3 6 = 1·3 + 3
0 = 0✅ 3 = 3✅ 6 = 6✅
Mr. jimenez deposited money into an account in which interest is compounded quarterly at a rate of 2.6%. how much did he deposit if the total amount in his account after 4 years was $7160.06, and he made no other deposits or withdrawals? $6455 $6455 $6798 $6798 $6887 $6887 $6977 $6977 skip to navigation
Answer:
$6455.
Step-by-step explanation:
The formula for this investment is:
A = P(1 + r/4)^4t where P = amount deposited , A amount after t years,
r = rate (as a decimal fraction).
So we have:
7160.06 = P(1 + 0.026/4)^16
7160.06 = P * 1.109227
P = 7160.06 / 1.109227
= $6455.
Identify the slope of a line perpendicular to the given line Y=2x-4
[tex]m = \frac{ - 1}{a} = \frac{ - 1}{2} \\ y = \frac{ - 1}{2} x + b[/tex]
The regression sum of squares (RSS) represents: a. The amount of variation in Y around its mean that the regression function can account for. b. The amount of variation in the dependent variable that is not explained by the regression function. c. The amount of variation in the independent variable that is not explained by the regression function. d. The amount of variation in the residuals that is explained by the regression function.
The regression sum of squares (RSS) represents: a. The amount of variation in Y around its mean that the regression function can account for.
What is regression sum of squares?
The regression sum of squares serves as the sum of the differences that exist between the predicted value and the mean of the variable.
The Sum of Squared Error however states the difference between the observed and the predictive value.
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What is the area of the following polygon?
I have tried 24, 25 and 26 and none of worked and I am at a loss.
The area of the polygon is 25.5 square units
How to determine the area of the polygon?From the figure, we have the following coordinates
A = (-2, 1)
B = (3, 2)
C = (5, -3)
D = (-1, -3)
The area of the polygon is then calculated as:
A = 0.5 * |(x1y2 - x2y1) + (x2y3 - x3y2) + (x3y4 - x4y3) + (x4y1 - x1y4)|
Substitute the known values in the above equation
Area = 0.5 * |(-2 * 2 - 3 * 1) + (3 * -3 - 5 * 2) + (5 * -3 + 1 * -3) + (-1 * 1 + 2 * -3)|
Evaluate the sum of products
Area = 0.5 * |-51|
Remove the absolute bracket
Area = 0.5 * 51
Evaluate the product
Area = 25.5
Hence, the area of the polygon is 25.5 square units
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if x^2 - 9 = 0 then x can only be equal to 3. true or false
Answer:
False
Step-by-step explanation:
The variable could also be -3, not just 3.
Answer:
False
Step-by-step explanation:
x^2 - 9 = 0
x^2 = 9
x = +- 3
creating holes in the sand to fill the varied buckets is an example of an inverse relationship
true or false
Answer:
True
Step-by-step explanation:
You are taking away sand from the ground and adding sand to the bucket. There is less sand on the ground and more in the bucket making it inverse.
Please help right away
Answer:
A: (4,7)
B: (2,1)
C: (6,1)
Step-by-step explanation:
To plot the points, go along the x-axis (the horizontal line with the x on the end) and stop where the dot is. Whatever number the dot is above is the x-coordinate. Then, however many numbers you go up by to reach the dot is your y-coordinate.
hope this helps :)
Find the Perimeter of the figure below, composed of a parallelogram and one
semicircle. Rounded to the nearest tenths place
4
14
The perimeter of the figure to the nearest tenth is 44.6 units
Perimeter of a figure?The perimeter of a figure is the sum of the whole sides.
Therefore,
A parallelogram has opposite sides equal to each other.
Therefore, the perimeter of the figure is as follows;
The figure combines a parallelogram and a semi circle.
Therefore,
perimeter of the figure = 4 + 14 + 14 + πr
perimeter of the figure = 32 + 3.14 × 4
perimeter of the figure = 32 + 12.56
perimeter of the figure = 44.56
perimeter of the figure ≈ 44.6 units
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11 points please help me
From the given sample data in the table on the backpack weight, we have;
(a) The means of the samples are;
First sample = 6.375Second sample = 6.375Third sample = 6.625(b) The range is 0.25
(c) The true statements are;
A single sample mean will tend to be a worse estimate than the mean of the sample meansThe farther the range of the sample means is from zero, the less confident they can be their estimate.How can the mean of the sample means be found?(a) The sample means of each of each of the three samples are found as follows;
[tex]Mean = \frac{ \sum \: x}{n} [/tex]
Where;
x = The value of a data point
[tex] \sum \: x = Sum of the data [/tex]
n = Sample size
The mean of the first sample, S1, data is therefore;
[tex]Mean \: S1 = \frac{3 + 7 + 8 + 3 + 7 + 9 + 6 + 8}{8} [/tex]
3+7+8+3+7+9+6+8 = 51
Which gives
[tex]Mean \: S1 = \frac{51}{8} = \mathbf{6.375\[/tex]
Mean of the first sample = 6.375Similarly, we have;
[tex]Mean \: S2 = \frac{8 + 6 + 4 + 7 + 9 + 4 + 6 + 7}{8} [/tex]
8 +6+4+7+9+4+6+7 = 51
Which gives;
[tex]Mean \: S2 = \mathbf{\frac{51}{8}} = 6.375 [/tex]
Mean of the second sample = 6.375
[tex]Mean \: S3 = \frac{9 + 4 + 5 + 8 + 7 + 5 + 9 + 6}{8} [/tex]
9+4+5+8+7+5+9+6 = 53
Which gives;
[tex]Mean \: S3 = \frac{53}{8} = \mathbf{6.625} [/tex]
Mean of the third sample = 6.625(b) The range of the means of the sample means is found as follows;
Range = Largest value - Smallest value
Which gives;
Range of the sample means = 6.625 - 6.375 = 0.25(c) The population mean is given by the mean of the sample means. That is, a very good estimate of the sample mean is given by the mean of the sample means.
The true statements are therefore;
A single sample mean will tend to be a worse estimate than the mean of the sample meansThe farther the range of the sample means is from zero, the less confident they can be their estimate.Learn more about the mean of the sample means of a collection of data here:
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If you are choosing a single card from a standard deck of playing cards, what is
the probability that you draw a face card or a heart?
Your answer should be in the form of a fraction. Type it like this: 15/52.
Just to review:
• There are 52 cards in a deck.
• There are 4 suits with 13 cards each.
o 2 red suits - hearts and diamonds
o 2 black suites - clubs (look like clovers) and spades
• Each suit has an Ace, numbered cards 2-10, and 3 "face" cards--a Jack, Queen, and King.
Step-by-step explanation:
there are 4 suit with 13 cards each
I need help with this
Example 1 Find 6 – 9. 6 – 9 = 6 + ( – 9) To subtract 9, add – 9. = – 3 Simplify
Answer:
Step-by-step explanation: This example is saying that adding a negative number is the same as subtracting a positive number. For example 2-3 = 2 + (-3).
We can fill a certain barrel with water if we use water from 6 small pitchers, 3 medium pitchers, and one large pitcher, or from 2 small pitchers, 1 medium pitcher, and 3 large pitchers. If we use only large pitchers of water, how many of them do we need to fill the barrel?
Answer:
Solution Given:
let pitcher which is small be S medium be M and large be L and barrel be B.
By question
6S+3M+1L= 1B...... eq. 1
2S+1M+3L=1B.......eq. 2
The difference in 2L from the first to the second is 4S and 2M
Therefore, each L=2S+M
In equation 2
2S+1M+3L=1B
replacing 2S +1M by L,we get
L+3L=1B
4L=1B
Therefore, 4 large pitcher is required
Answer:
4 large pitchers
Step-by-step explanation:
Define the variables:
Let x = volume of a small pitcherLet y = volume of a medium pitcherLet z = volume of a large pitcherLet b = volume of a barrelCreate two equations with the given information and the defined variables.
Equation 1
If the barrel can be filled with 6 small pitchers, 3 medium pitchers and 1 large pitchers:
⇒ 6x + 3y + z = b
Equation 2
If the barrel can be filled with 2 small pitchers, 1 medium pitcher and 3 large pitchers:
⇒ 2x + y + 3z = b
Substitute Equation 2 into Equation 1
⇒ 6x + 3y + z = 2x + y + 3z
Subtract 6x from both sides:
⇒ 3y + z = -4x + y + 3z
Subtract y from both sides:
⇒ 2y + z = -4x + 3z
Subtract z from both sides:
⇒ 2y = -4x + 2z
Divide both sides by 2:
⇒ y = -2x + z
Substitute the found expression for y into Equation 1:
⇒ 6x + 3(-2x + z) + z = b
⇒ 6x - 6x + 3z + z = b
⇒ 4z = b
Therefore, 4 large pitchers are needed to fill the barrel.
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Choose the correct simplification of the expression (8x − 5)(2x2 − 5x − 6). 16x3 − 50x2 − 23x − 30 16x3 − 50x2 − 23x 30 16x3 − 30x2 − 23x 30 16x3 50x2 − 23x 30
The correct simplification of the given expression is (B) [tex]16x^{3} -50x^{2} -23x+30[/tex].
What is an expression?An expression or mathematical expression is a finite combination of symbols that is well-formed according to context-dependent norms.To find the correct simplification of the given expression:
The easiest terms to check are the first (8x)(2x²) = 16x³ and the last (-5)(-6) = 30. This check eliminates the first choice. The remaining choices differ only in the sign and coefficient of the squared term, so that is the one we need to find.The squared term will be the sum of the products of factors whose degrees total 2:[tex](8x)(-5x)+(-5)(2x^{2} )=-40x^{2} -10x^{2} =-50x^{2} =16x^{3} -50x^{2} -23x+30[/tex]Therefore, the correct simplification of the given expression is (B) [tex]16x^{3} -50x^{2} -23x+30[/tex].
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The correct question is given below:
Choose the correct simplification of the expression (8x − 5)(2x2 − 5x − 6). (1 point)
(A) 16x3 − 50x2 − 23x − 30
(B) 16x3 − 50x2 − 23x + 30
(C) 16x3 − 30x2 − 23x + 30
(D) 16x3 + 50x2 − 23x + 30
How many different license plates can be made if each license plate is to consist of 3 letters, followed by 2 digits, and no letters or digits may repeat
Explanation: The alphabet consists of 26 letters, and if each license plate has 3 letters we can make 8 plates. It may be followed by 2 digits but there is a plenty amount of different 2 digit numbers so we don't have to worry about that.
Answer: 8 License plates
Hope this helped! :D
find the square roots of each of the following number
1: 81
2: 100
Multiply 9 with 9, and we get:
9 × 9 = 81
Multiply 10 with 10, and we get:
10 × 10 = 100
We get the final result as:
9²10²Hope this helps :)
Sketch The Graphs:
y = -1/3x -2
Answer:
Step-by-step explanation:
The graph of the straight line [tex]y = -\frac{1}{3}x -2[/tex] is plotted. The graph is shown below.
A straight line is of the form y = mx + c, where m is the slope and c is the y-intercept.
To plot the given straight line [tex]y = -\frac{1}{3}x -2[/tex], follow the following steps:
Step 1: Substitute x = 0 in the given equation to obtain the point where the line intersects the y-axis.
y = 0 - 2
y = -2
The point at the y-axis is (0, -2).
Step 2: Substitute y = 0 in the given equation to obtain the point where the line intersects the x-axis.
[tex]0 = -\frac{1}{3}x -2\\x = -6[/tex]
The point at the x-axis is (-6, 0).
Step 3: Draw a straight line passing through both points.
Thus, the straight line [tex]y = -\frac{1}{3}x -2[/tex] is plotted.
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5. The grid shows how many eggs Ms. Benton bought.
The shaded boxes represent the number of eggs she
used to make the cookies. What percent and fraction
of the eggs bought were not used to make the cookies?
Show your work in the space below. Remember to
check your solution.
Answer:
You can count how many boxes that are not shaded to find how many eggs were not used, but that's to find out the fraction
Step-by-step explanation:
Count the boxes total in the grid. then count the number of boxes were not shaded. the number of total boxes is your denominator, and the number of boxes thar aren't shaded is your numerator.
I think...
HELPP!!!!! PLSSSS!!!!
Consider functions f and g. Select the correct answer.
f(x)=(x^4)+9x²-3
g(x)=(1/2)^(x-2)
Using a table of values, what are the approximate solutions to the equation f(x)=g(x) to the nearest quarter of a unit?
A.) x congruent to -0.25 and x congruent to 2.5
B.) x congruent to -1 and x congruent to 0.75
C.) x congruent to -0.5 and x congruent to 0.5
D.) x congruent to -0.25 and x congruent to 1.5