The temperature of boiling liquid will be 78°C.
To find the correct answer, we need to know about the upper and lower fixed points of the thermometer.
How to find the temperature of boiling liquid?The lower fixed point is measured by the melting temperature of pure water.Given that, the fundamental interval is 25cm, which is the separation between the upper and lower fixed points.We have the equation for the temperature as,[tex]T=\frac{x-x_0}{x_{100}-x_0} *100[/tex]
where,
[tex]x=[/tex] length of liquid at T temperature = 19.5cm.
[tex]x_0=[/tex] length of liquid thread at ice point = 0°C
[tex]x_{100}=[/tex] length of liquid thread at steam point = 25 cm.
Substituting values, we get,[tex]T=\frac{19.5-0}{25-0}*100\\ T=0.78*100=78^0C[/tex]
Thus, we can conclude that, the temperature of boiling liquid will be 78°C.
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What angle (in degrees) is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value?
The 60 degrees is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
It is given that axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
It is required to find the angle between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
What is the angle between the direction of polarized light and the axis of a polarizing filter?Suppose the angle between the polarizer and the axis of filter is θ.
The intensity of light that is passing after the filter is 0.2 l₀.
From the law of Malus, we have
I = I₀ [tex]cos^{2}[/tex]θ
0.2I₀= I₀ [tex]cos^{2}[/tex]θ
0.2 = [tex]cos^{2}[/tex]θ
[tex]cos\\[/tex]θ = 0.447
θ = 60°
Thus the angle between the direction of polarized light and the axis of a polarizing filter is 60 degree.
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A mass m is attached to an ideal massless spring with spring constant k. In experiment 1 the mass oscillates with amplitude a, and period t. A student grabs the mass and brings it to rest before starting experiment 2. In experiment 2, the mass is set to oscillate with a larger amplitude of 3a. What is the period of the oscillation in experiment 2?.
Time period remains the same in both the experiment as change in amplitude does not affect time period.
What are the factors on which time period depends in SHM?Time period is given by:
[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]
where,
T = time period
m = mass
k = spring constant
From the given formula, we find that the time period is only dependent on mass of the object and spring constant in a simple harmonic motion (SHM). If there is any change in mass of the object or the spring constant, the time period will change accordingly.
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An electric dipole consists of a particle with a charge of 6 x 10–6 c at the origin and a particle with a charge of –6 x 10–6 c on the x axis at x = 3 x 10–3 m. its dipole moment is:______.
An electric dipole consists of a particle with a charge of 6 x 10⁻⁶ c at the origin and a particle with a charge of –6 x 10⁻⁶ c on the x axis at x = 3 x 10⁻³ m. Its dipole moment is 18 x 10⁻⁹ Cm
Dipole moment of a dipole is dependent on the charge of the dipole and the distance between the two charges.
Electric Dipole consists of two charges which are equal and opposite in charge i.e. positive and negative charges.
Given,
Dipole moment, p = ?
Charge, q = 6 x 10⁻⁶C
Distance between charges, d = 3 x 10⁻³ m
Dipole moment (p) is given by:
p = charge x distance between the two charges
p = 6 x 10⁻⁶ x 3 x 10⁻³ Cm
p = 18 x 10⁻⁹ Cm
The dipole moment for the given charge configuration is 18 x 10⁻⁹ Cm
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what is the definition of laws of conservation
Answer:
conservation law, also called law of conservation, in physics, a principle that states that a certain physical property (i.e., a measurable quantity) does not change in the course of time within an isolated physical system.
Explanation:
The definition of a conservation law in physics asserts that a certain observable attribute of an isolated physical system doesn't change over time.
Part a a calorimeter consists of an aluminum cup inside of an insulated container. The cup is weighed on a top-loading balance and is found to have a mass of 31. 91 g. A reaction is conducted in the calorimeter, raising the temperature from 21. 2 c to 26. 1 c what is the change in heat q for the aluminum cup in units of j? aluminum has a specific heat of 0. 903 j 1 ? 1 write your answer to the correct number of significant figures.
The change in heat q for the aluminum cup is 141 J.
What is Specific heat?A substance's heat capacity is the amount of heat needed to increase its overall temperature by one degree. The heat capacity is known as the specific heat capacity or the specific heat if the substance's mass is unity.
change in heat -
The amount of heat Q that is transported to create a temperature shift depends on the substance and phase involved, the mass of the system, and the magnitude of the temperature change. (A) The temperature change and the amount of heat transported are directly inversely related.
The answer's sign dig is determined by a calculation's lowest sign digits.
The solution will need 3 digits because the temperatures are provided with 3 significant digits and the specified heat has 3 significant digits (the mass has 4 significant digits).
31.91 g * 0.903 J/g-C * (26.1 - 21.2 C) = 141 J
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→e pointing up and the magnetic field →b pointing west. what is the direction of wave propagation?
When the magnetic field is heading west and the electric field is pointing up, the wave propagation will be in the north.
How do we find out the direction of wave propagation?
Electromagnetic waves (EM-waves), as we are aware, are transverse. Electric and magnetic fields are both perpendicular to one another in EM waves (E⊥B).
Transverse waves are waves in which the propagation direction is opposite the direction of amplitude. for instance, gravitational waves, light waves, and water waves.
In this instance, the magnetic field is heading west while the electric current is pointing up towards the screen's layout.
∴ E x B = κ
where E= the direction of the electric field,
B = the direction of the magnetic field,
κ = at a particular point, the direction of propagation
The aforementioned equation is right-handed. When we put our finger towards ourselves (away from the screen) and curl it to the west, and the thumb will indicate the wave propagation direction ( north side ).
The propagation of waves in our instance is in the north direction.
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A river is flowing south at a constant speed of 1.20 m/s. The river is 45 meters wide.
Alice swims in the direction perpendicular to the river.
In order to target the spot 90 meters south of the starting point on the bank of the other side, what should be Alice’s speed relative to the water?
Alice's speed relative to the water should be 0.6 m/s in order to target the spot 90 meters south of the starting point on the bank of the other side.
What is relative velocity?Relative velocity refers to the velocity of an object with respect to another observer.
Velocity is speed in a given direction and is a vector quantity.
Velocity = displacement/timeThere is relative velocity between Alice and the water.
Let Alice's velocity relative to the river be x
Time it will take her to cross the river = 45/x
The displacement of the river in that time is given below as;
Displacement = velocity * time
Velocity of river = 1.20 m/s
time, t = 45/x
d = 90 m
90 = 1.2 * 45/x
90x = 54
x = 54/90
x = 0.6 m/s
Therefore, Alice's speed relative to the water should be 0.6 m/s.
In conclusion, relative velocity is the velocity of one object from the reference point of another object.
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If fuel consumption is 80 pounds per hour and groundspeed is 180 knots, how much fuel is required for an airplane to travel 477 nm?
Answer:
212 pounds
Explanation:
477 nm / 180 nm/hr * 80 #/hr = 212 #
How could a man be severely injured beig hut by some tomatoes?
Answer:
he can fall down
Explanation:
he could fall down because of the tomatoes and do notice he has fallen down because of them
HELP PLS I WILL MARK U BRAINLIEST!!
Answer:
D
Explanation:
I would say much too small as there is a significant portion of the plant that is UNDER water.....
( Really depends on how deep the water is...if it is shallow water it would be just a little too small)
A solenoid with 500 turns is 0. 10 m long and carries a current of 4. 0. What strength of magnetic field will it have at its center?
A solenoid with 500 turns is 0. 10 m long and carries a current of 4. 0. The strength of magnetic field at its center will be 2.5 * [tex]10^{-2}[/tex] H
Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.
A coil of wire which is designed to generate a strong magnetic field within the coil is called a solenoid. Wrapping the same wire many times around a cylinder creates a strong magnetic field when an electric current is passed through it. N denotes the number of turns the solenoid has.
Magnetic field at the center of the solenoid = mu0 * I * N / L
I = current in the solenoid
N = number of turns in the solenoid
L = length of the coil
B = 4π * [tex]10^{-7}[/tex] * 4 * 500 / 0.10
= 251200 * [tex]10^{-7}[/tex] H
= 2.5 * [tex]10^{-2}[/tex] H
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On a frictionless, horizontal air track. the glider has a head-on collision with a 0. 300-kg glider that is moving to the left with a speed of 2. 20 m>s. Find the final velocity?
The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s
Given data,
Mass of glider A (M[tex]_{1}[/tex]) = 0.15 kg
Mass of glider B (M[tex]_{2}[/tex]) = 0.3 kg
Initial velocity of A (u[tex]_{1}[/tex]) = 0.80ms-1
Initial velocity of B ( u[tex]_{2}[/tex]) = -2.2m/s
Momentum and kinetic energy are conserved in elastic collision . So,
M[tex]_{1}[/tex]u[tex]_{1}[/tex]+M[tex]_{2}[/tex]u[tex]_{2}[/tex] = M[tex]_{1}[/tex]v[tex]_{1}[/tex]+M[tex]_{2}[/tex]v[tex]_{2}[/tex]
0.15×0.8+0.3x(-2.2) = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]
-0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]
Again if,
u[tex]_{1}[/tex]+v[tex]_{1}[/tex] =u[tex]_{2}[/tex]+v[tex]_{2}[/tex]
0.8 +v[tex]_{1}[/tex] =-2.2+v[tex]_{2}[/tex]
v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3
Solving for -0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex] and v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3 , we get
v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s
Therefore,The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s
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A solid sphere of radius r rotates about a diameter with an angular speed w. the sphere then collapses under the action of internal forces to a final radius r/2. what is the final angular speed of the sphere
The final angular speed of the sphere is 4ω.
Calculation:Angular momentum will remain conserved.
What is conservation of angular momentum?A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; in other words, the rotation's speed will not change as long as the net torque is zero.
Angular momentum is given by,
L = Iω
where,
L = angular momentum
I = moment of inertia
ω = angular speed
The moment of inertia of a solid sphere is,
I = [tex]\frac{2}{5} MR^{2}[/tex]
For the question,
L₁ = L₂
I₁ω₁ = I₂ω₂
Given,
R₁ = R
R₂ = R/2
ω₁ = ω
To find,
ω₂ =?
Substituting the values in the equation,
I₁ω₁ = I₂ω₂
[tex]\frac{2}{5}[/tex](MR²)ω = [tex]\frac{2}{5}[/tex] M(R/2)²ω₂
R²ω = (R²/4)ω₂
ω = (1/4)ω₂
ω₂ = 4ω
Hence, the final angular speed of the sphere is 4ω.
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4ω is the final angular speed of the sphere.
When a solid sphere of radius r rotates about a diameter with an angular speed w, the sphere then collapses under the action of internal forces to a final radius r/2, 4ω is the final angular speed of the sphere.
Angular momentum will remain conserved.
Angular momentum is given by,
L = Iω
where,
L = angular momentum
I = moment of inertia
ω = angular speed
The moment of inertia of a solid sphere is,
I = [tex]\frac{2}{5}[/tex][tex]MR^{2}[/tex]
For the given problem,
L₁ = L₂
I₁ω₁ = I₂ω₂
We are given,
R₁ = R
R₂ = R/2
ω₁ = ω
To find,
ω₂ =?
On substitution of the values in the equation,
I₁ω₁ = I₂ω₂
[tex]\frac{2}{5}[/tex](MR²)ω = [tex]\frac{2}{5}[/tex] M(R/2)²ω₂
R²ω = (R²/4)ω₂
ω = (1/4)ω₂
ω₂ = 4ω
Hence, we can conclude that the final angular speed of the sphere is 4ω.
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An fm radio station broadcasts at 98. 6 mhz. What is the wavelength of the radiowaves?.
The wavelength of radiowaves is 3.042 m.
What is radiowaves?The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below.
Frequency given, f = 98.6 MHz = 98.6 x [tex]10^{6}[/tex] cycles/second
Electromagnetic waves including radiowaves also travel at the speed of light.
Therefore, c = 3.0 x [tex]10^{8}[/tex] m/sec
Wavelength = speed/frequency
wavelength of 98.6 MHz = 3.0 x [tex]10^{8}[/tex]/98.6 x [tex]10^{6}[/tex] meters
=3.042 meters
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Find the magnitude of this
vector:
Answer: = 25. 5 m
Explanation:
2-D vectors can be solved using the Pythagorean theorem: [tex]a^{2} +b^{2} =c^{2}[/tex]The hypotenuse, or longest side is not given and that is what must be solved forDirection can be omitted as the question only asks for magnitudeMagnitude: is the distance or quantity in which an object moves during motionSolve for C using Pythagorean theorem:
1. [tex]\sqrt{a^{2}+b^{2} }=c[/tex]
2. [tex]\sqrt{22.2 m ^{2} +12.6m^{2} } =c[/tex]
3. [tex]25.52646 m= c[/tex]
round to lowest number of significant digits when dividing and multiplyingrounded to 3 significant digits∴ Magnitude of the vector is 25.5 m
the cullinan diamond weighs 621.35g and is estimated to have a value for 400 million. how many dollars per ounce do this equal
The value is equal to 18.26*10^6 dollars/ounces.
To find the answer, we have to know about the Cullinan diamond.
What is Cullinan diamond?The Cullinan Diamond, weighing 3,106.75 carats (621.35 g) (21.9 ounces), (1.37 pounds), was found at the Premier No.2 mine in Cullinan, South Africa, on January 26, 1905. It is the largest gem-quality rough diamond ever found.We have to find the dollars per ounce do this diamond equal,It is given that the diamond weighs 621.35g and is estimated to have a value for 400 million dollars. 621.35g means 21.9 ounces. Thus, for 1 ounce,[tex]21.9 Ounce= 621.35g=400*10^6 dollars\\\\value=\frac{400}{21.9} *10^6dollars/ounce=18.26*10^6dollars/ounce[/tex]
Thus, we can conclude that, the value is equal to 18.26*10^6dollars/ounces.
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Transformers: an ideal step-up transformer doubles a primary voltage of 110 v. what is the ratio of the number of turns in its primary coil to the number of turns in the secondary coil?
The ratio of the number of turns in the primary and the secondary coil of a step-up transformer is 1 : 200.
The formula for calculating the secondary voltage in a transformer is: N = V = Where No and N are the primary and secondary coils' respective turn counts; V and V are the RMS voltages across the primary and secondary coils, and I and Is are the primary and secondary currents.
Calculation: Due to this:
The coil's N2 to Ns turn ratio is 1/20.
We understand that N=1/20 = 4/LP: Is = 20:1.
The transformer uses the following principles: A wire's magnetic field moves as a result of a changing current flowing through it. A wire exposed to a moving magnetic field will create a changing current.One of the coils produces a magnetic field that grows and contracts in response to the changing voltage of the AC when an AC source is connected to it.
In other words, the coil generates a growing magnetic field as the voltage across it rises. The magnetic field generated around the capacitor increases when the voltage reaches its maximum and starts to decline.
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Newton's Third Law of Motion relates to action and reaction. Which of the following scenarios accurately names the correct action and reaction pair to apply to Newton's Third Law?
An extraterrestrial astronomer surveying our solar system with the doppler method could discover the existence of jupiter with just a few days of observation. True or false?.
False; finding it would require much more than a few days of observation.
What is the Doppler method?The Doppler approach is a reliable way to find exoplanets. It examines the velocity and characteristics of the star and planet using the Doppler effect. The star and the planet both revolve around the same mass.
What is measured by the Doppler technique?The periodic velocity change of the stellar spectrum brought on by an orbiting massive planet is discovered using Doppler spectroscopy.
How does the Doppler technique function?Doppler spectroscopy tracks changes in the host star's light's hue to find periodic shifts in radial velocity. A star's spectrum is redshifted when it moves away from us and blueshifted when it moves toward us.
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A vector of magnitude 20 is added to a vector of magnitude 25. the magnitude of this sum can be?
The sum of vectors lie between 5 - 45
We all know that Vector is a quantity of Magnitude and Direction.
Couple of examples of Vector quantity are Acceleration, Displacement, Force, Momentum, Velocity
Let's solve the problem:
I A I is given as 20
I B I is given as 25
The sum of vectors lie between their maximum and minimum
Hence,
MIn < Sum of Vectors < Max
I A-B I < Sum of Vectors < I A + B I
I 20 - 25 I < Sum of Vectors < I A + B I
5 < Sum of Vectors < 45
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What magnitude net force is required to accelerate a 1200-kg car uniformly from 0 m/s to 27.0 m/s in ?
Magnitude of Net force Required to accelerate a 1200kg car uniformly from 0m/s to 27m/s in 10s is 3240N.
Force can be found out using the relation of Force, mass and acceleration.
The relation of Force, mass and acceleration is as follows:
∴ Force = Mass × Acceleration
⇒ Force = 1200kg × Acceleration
Given:
Mass = 1200kg
Final Velocity = 27m/s
Initial Velocity = 0m/s
time = 10s
Now, to find out the acceleration we can use the first equation of motion:
∴ Final Velocity = Initial Velocity + Acceleration × time
⇒ 27 = 0 + 10a
⇒ a = 2.7m/s²
Putting acceleration in the above mentioned equation,
∴ Force = 1200kg × Acceleration
⇒ Force = 1200kg × 2.7
⇒ Force = 3240N
Hence, the net force required to accelerate the car uniformly is 3240N.
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The answer is 3240 N.
Intial velocity [tex]$\mathrm{u}=0 \mathrm{~m} / \mathrm{s}$[/tex]
final velocity [tex]$\mathrm{v}=27 \mathrm{~m} / \mathrm{s}$[/tex]
time [tex]$t=10$[/tex] sec.
Newton's first equation of motion
[tex]$v=u+a t$[/tex], here a = acceleration
[tex]$\mathrm{so}_{0}=(v-u) / t$[/tex]
[tex]$a=(27.0-0) / 10$[/tex]
[tex]$a=2.7 \mathrm{~m} / \mathrm{sec}^{2}$[/tex]
Force [tex]$F=m a$[/tex]
Mass [tex]$\mathrm{m}=1200 \mathrm{~kg}$[/tex]
[tex]$F=1200 \times 2.7$[/tex]
[tex]$F=3240 N$[/tex]
What is acceleration?
Acceleration is the rate at which velocity varies over time, both in terms of speed and direction. A point or object travelling in a straight path is accelerated if it accelerates or decelerates.To learn more about Acceleration visit:
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What is the function of a diaphragm in a camera?
It controls the speed of the shutter.
It focuses incoming light rays.
It controls the amount of light.
It directs the image to the viewfinder.
0.7-kg of r-134a is expanded isentropically from 800 kpa and 50°c to 140 kpa. determine the total heat transfer and work production for this expansion.
There will be no heat transmission, and the system's work is 25.27 Kj.
The calculation for total heat transfer and work production:
Provided,
The mass of r-134a = 0.7 kg
Initial pressure of the system, P₁ = 800 kpa
Initial temperature of r-134a, T₁ = 50°C = 273+ 50 = 323 K
Final pressure of the system, P₂ = 140 kpa
From the superheated refrigerant r-134a
P₁ = 800 kpa & T₁ = 50°C
the internal energy, u₁ = 263.87 Kj/kg &
the entropy, s₁ = 0.9803 Kj/kg .K
There won't be any heat transmission because the process is isentropic.
So, Q = 0 KJ
Due to the isentropic nature of the operation, the ultimate entropy is determined by
s₂ = s₁ = 0.9803 Kj/kg .K
From the r-134a superheated refrigerant
at P₂ = 140 kpa & entropy s₂ = 0.9803 Kj/kg .K
the internal energy,u₂ = 227.77 K/kg
The work on the system is provided by
W = m x (u₂-u₁)
W = 0.7 x(227.77 - 263.87)
W = 0.7 x (-36.1)
W = -25.27 KJ
A negative number means the system is doing the task.
As a result, there won't be any heat transfer, and the system will only have used 25.27 KJ of energy.
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Question 1 of 28
Which sentence is generally true of red stars?
OA. They are the oldest stars.
OB. They are the hottest stars.
OC. They are the youngest stars.
D. They are the coldest stars.
Answer: D. They are the coldest stars.
Explanation:
how to find out the heat capacity of a material?
[tex]\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}[/tex]
The heat capacity is given by the expression:
[tex]\longrightarrow \sf{\triangle Q= m \triangle C \triangle T}[/tex]
[tex]\longrightarrow \sf{Q= \: Heat}[/tex]
[tex]\longrightarrow \sf{M= \: Mass}[/tex]
[tex]\longrightarrow \sf{C= \: Specific \: Heat}[/tex]
[tex]\longrightarrow \sf{T= \: Temperature}[/tex]
[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]
[tex] \leadsto[/tex] When the [tex] \bm{heat}[/tex] is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in [tex] \bm{temperature}[/tex] , we can then determine the specific heat "C" by simply remplazing in the expression.
The heat capacity of a material is its ability to absorb heat energy. There are different methods to determine the heat capacity of a material, depending on the specific conditions and resources available. Here are some common approaches:
Differential Scanning Calorimetry (DSC): DSC is a technique used to measure heat flow into or out of a material as a function of temperature. By subjecting the material to controlled heating or cooling, the heat capacity can be determined from the measured heat flow data.Specific Heat Capacity Measurement: The specific heat capacity of a material is the amount of heat energy required to raise the temperature of a unit mass of the material by one degree Celsius (or Kelvin). This can be determined through calorimetry experiments, where the material is heated or cooled while its temperature changes and heat transfer amount are measured. The specific heat capacity can then be calculated using the equation: Q = mcΔT, where Q is the heat energy transferred, m is the mass of the material, c is the specific heat capacity, and ΔT is the temperature change.Tabulated Data: The heat capacity of some commonly used materials is available in reference books, handbooks, or online databases. These values are often given as average or estimated values based on previous measurements. By referencing such data, you can obtain an approximate heat capacity value for a specific material.Statistical Data: The heat capacity of some commonly used materials is available in reference books, handbooks, or online databases. These values are often given as averages or estimates based on previous measurements. By referencing such data, you can obtain an approximate heat capacity value for a specific material.It's imperative to note that heat capacity can vary with temperature, pressure, and other factors. Therefore, measurements or data should ideally be conducted or referenced within the appropriate range of conditions relevant to the specific application or analysis.
What are the similarities between the compass needle (magnetism) and a charge to probe the electric field (electricity)?
Similarities between the compass needle (magnetism) and a charge to probe the electric field (electricity) is that Electric fields are produced by two kinds of charges, positive and negative similarly Magnetic fields are associated with two magnetic poles
Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts. A pictorial representation of the magnetic field which describes how a magnetic force is distributed within and around a magnetic material.
Electric field, an electric property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.
Electric fields are produced by two kinds of charges, positive and negative. Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges (but moving charges).
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Four point charges, each of charge 2. 5 x 10-5 c, are located on the x- and y-axes, one at each of the locations (0, 2. 0 m), (0, -2. 0 m), (2. 0 m, 0), and (-2. 0 m, 0). the potential at the origin is__________.
The Potential at the origin due to the four point charges located at (0, 2), (0, -2), (2 , 0), and (-2 , 0) will be - [tex]45\times10^{4}[/tex] volts.
We have four point charges, each of charge [tex]2.5\times10^{-5}[/tex] C, are located on the x - axis and y - axis, one at each of the locations (0, 2), (0, -2), (2 , 0), and (-2 , 0).
We have to calculate the potential at the origin O(0,0).
What is the formula to calculate the Electric potential at a point ' r ' meters away from a point charge ' q ' ?The Electric field potential due to point charge ' q ' at a distance ' r ' meters apart is -
[tex]V(r) = \frac{1}{4\pi\epsilon_{o} } \frac{q}{r}[/tex]
Now, in the question given to us -
q = [tex]2.5\times10^{-5}[/tex]
Let us label the four points as - A (0, 2), B (0, -2), C (2 , 0), and D (-2 , 0).
Now, the potential due to charge located at point A will be -
[tex]V_{A} = \frac{1}{4\pi\epsilon_{o} } \frac{q}{r}\\V_{A} = \frac{1}{4\pi\epsilon_{o} } \frac{q}{r}\\V_{A} = 9\times10^{9}\times\frac{2.5\times10^{-5} }{2} \\V_{A} = 11.25\times10^{4}[/tex]
Now, the distance of the center from each point will be same = 2 m.
Hence, the potential due to each charge at the origin will be -
[tex]V_{A} =V_{B} =V_{C} =V_{D} = 11.25\times10^{4}[/tex]
Since, the potential is a scalar quantity, we can add the potential due to each charge using simple addition -
[tex]V_{A} +V_{B} +V_{C} +V_{D} = 4\times11.25\times= 45\times10^{4}[/tex] Volts
Hence, the potential at the center will be - [tex]45\times10^{4}[/tex] volts.
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what kind of energy is stored when you squeeze a mattress
Answer:
elastic energy
Explanation:
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When charging a system with vapor refrigerant from a refrigerant cylinder the cylinder will become:_________
When charging a system with vapor refrigerant from a refrigerant cylinder the cylinder will become cold .
When refrigerant is added in the vapor state, the refrigerant cylinder will lose pressure as the vapor is pushed out of the cylinder.The volume of the refrigerant changes with the ambient air so the graduated cylinder must be calibrated before each use.What is a refrigerant charging cylinder used for?
A cylinder used to transfer refrigerant from the transportation cylinder into the system during the charging process. It has several scales on the exterior that indicate various refrigerant charges.What type of refrigerant can be added as a liquid or a vapor?
Blends like R410a or 404a must be added to a system as a liquid. Pure refrigerants like R22 can be added in liquid or vapor states.
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What is the speed of a transverse wave in a rope of length 3. 1 m and mass 86 g under a tension of 380 n?
117 m/sec is the speed of a transverse wave in a rope of length 3. 1 m and mass 86 g under a tension of 380 n.
The wave speed v is given by
v= √τ/μ
where τ is the tension in the rope and μ is the linear mass density of the rope.
The linear mass density is the mass per unit length of rope :
μ= m / L = (0.086 kg)/(3.1 m)=0.0277 kg/m.
v= [tex]\sqrt{ \frac{380 N}{0.0277 kg/m}}[/tex] = 117.125 m/sec (approx. 117 m/sec
In physics, a transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations. Water waves are an example of transverse wave.
Transverse waves commonly occur in elastic solids due to the shear stress generated; the oscillations in this case are the displacement of the solid particles away from their relaxed position, in directions perpendicular to the propagation of the wave. These displacements correspond to a local shear deformation of the material. Hence a transverse wave of this nature is called a shear wave. Since fluids cannot resist shear forces while at rest, propagation of transverse waves inside the bulk of fluids is not possible.
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