Taking into account the definition of pH and pOH, the hydroxide ion concentration will be 6.61×10⁻⁵ M.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
Hydroxide ion concentrationIn this case you know that the hydrogen ion concentration is 1.5×10⁻¹⁰ M, this is, [H⁺]= 1.5×10⁻¹⁰ M.
Replacing in the definition of pH:
pH= - log (1.5×10⁻¹⁰ M)
Solving:
pH= 9.82
Replacing in the relationship established between pH and pOH, the pOH can be calculated as:
pOH + 9.82= 14
Solving:
pOH= 14 - 9.82
pOH= 4.18
Replacing in the definition of pOH, the concentration of hydroxide ion is obtained:
- log [OH⁻]= 4.18
Solving:
[OH⁻]= 10⁻⁴ ¹⁸
[OH⁻]= 6.61×10⁻⁵ M
In summary, the hydroxide ion concentration will be 6.61×10⁻⁵ M.
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HELP NOW pls will give points due soon
Sorry for the sloppy writing I tried my best.
If you can't read the words in my photo it says
Evaporation
condensation precipitation and runoff
definition of these words
evaporation: The process of turning liquid into vapor
Condensation:water which collects as droplets on a cold surface when humid air is in contact with
Precipitation: the action or process of precipitating a substance from a solution
runoff: liquid, especially water or rainwater, that flows off or drains away
I hope this is helpful
Sincerely- Your Brainly Bestfriend
In the reaction between CO and Fe3O4 , the theoretical yield in an experiment is calculated to be 47.2 g Fe.
When a chemistry student carries out the experiment, their actual yield is 34.1 g Fe.
Calculate the percent yield (% yield) of Fe
Answer:
Explanation:
34.1 / 47.2 x 100% = 0.07%
The percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.
How to calculate percent yield?The percent yield is the percent ratio of the weight of the product obtained to the theoretical yield.
The percent yield can be calculated by dividing the experimental yield by the theoretical yield and multiplying the result by 100 then express the final answer in %.
According to this question, the experimental yield is 34.1g and the theoretical yield is 47.2g. The percent yield can be calculated as follows:
Percent yield = 34.1/47.2 × 100
Percent yield = 72.25%
Therefore, the percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.
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Given similar concentrations, the stronger acid corresponds to the lower pH. Comment on the relative strengths of the acids H3PO4, H2PO4^– and H2PO4^2–
Answer:
H3PO4 is stronger than H2PO4- because
H3PO4 dissociation constant is 6.9×10^-3
H2PO4^- dissociation constant is 6.2×10^-8
If the value for ΔS is postive, and the value for ΔH is negative, thr reaction will be
Group of answer choices
A. spontaneous at high temperatures.
B. spontaneous at all temperatures.
C. spontaneous at low temperatures.
D. Δnot spontaneous at all temperatures.
It follows that the reaction is spontaneous at high temperatures Option A.
What is ΔS ?The term ΔS is referred to as the change in the entropy of the system. Now recall that entropy is defined as the degree of disorderliness in a system. If a system is highly disorderly then it means that it has a high entropy. Also, ΔH has to do with the heat change that accompanies a reaction.
We know that both the entropy and the heat change can both either be positive or negative. Now we know that the equation ΔG = ΔH - TΔS can be used to ascertain whether or not a reaction will be spontaneous. If the result is negative, then the reaction will be spontaneous.
As such, when then it follows that the reaction is spontaneous at high temperatures Option A.
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What is the oxidation number of nitrogen in nitrogen gas?
Group of answer choices
A. -2
B. -1
C. -3
D. 0
Consider the following reaction at 298K.
I2 (s) + H2 (g) 2 I- (aq) + 2 H+ (aq)
Which of the following statements are correct?
From the forgoing, we can conclude that the the correct statements are;
n = 2 mol of electronsK < 1What are the redox reaction?The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;
E°cell = 0.0592/n log K
E°cell = cell potential
n = number of electrons
K = equilibrium constant
E°cell = -0.403 - 0.535 = -0.938 V
n = 2 electrons
Thus;
-0.938 = 0.0592/2 logK
-0.938 * 2/ 0.0592 = log K
K = 2 * 10^-31
Also;
ΔG = - nFE°cell
ΔG = - (2 * 96500 * -0.938)
ΔG = 181kJ/mol
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Consider this reaction: 6 CO2 + 6 H2O + light equation C6H12O6 + 6 O2 If there were 2.38 x 102 g of H2O, 18.6 moles of CO2, and plenty of light, which reactant would be the limiting reactant?
H₂O would be the limiting reactant.
Balanced chemical equation:
6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂
The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).
Given
No. of moles of CO₂ = 18.6
Mass of H₂O = 2.38 × 10² g = 238g
No. of moles of H₂O = Given mass/ Molar mass
= 238 / 18 = 13.22 moles
Moles of H₂O = 13.22
According to the balanced chemical equation
6 moles of CO₂ react with 6 moles of H₂O
So the reactant that has less number of moles will be consumed first.
As the No. of moles of H₂O < No. of moles of CO₂
So, H₂O is the limiting reactant with 13.22 moles.
Hence, H₂O would be the limiting reactant.
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Oliver and Mike put some ice into a container and heat it .
Answer:
See below
Explanation:
From the graph: initial temp = -10 ° C
melting occurs at 0 ° C (constant temp process)
at '2' the ice is melting.....going from a solid to a liquid at a constant temperature